Answer:
58.8J
Explanation:
Given parameters;
Mass of ball = 4kg
Height above the floor = 1.5m
g = 9.8n/kg
Unknown:
Potential energy = ?
Solution:
The potential energy of a body is the energy due to the position of the body.
It is mathematically expressed as:
Potential energy = mass x acceleration due to gravity x height
Potential energy = 4 x 9.8 x 1.5 = 58.8J
Find the magnitude of the force F exerted by the leg on the small pulley. (By Newton's third law, the small pulley exerts an equal and opposite force on the leg.) Let the mass m be 2.27 kg.
The magnitude of the force F exerted by the leg on the small pulley is, F = 38.53 N
We can calvulate the magnitude of the force by a mathematical calculation, which is as follows. As the small pulley and mass are not moving, they are stationary.
t2=t1 = mg = (2.27)(9.8)
= 22.246 N
Now resolve the force in the opposite direction.
F = 2Tcos30°
F = (2)(22.246)(cos30°)
F = 38.53 N
Therefore, the magnitude of the force is 38.53 N.
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A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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A rocket has been fired upward to launch a stellite in its orbit name two forces acting on the rocket immediately after leaving the launching pad
Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.
1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.
This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.
2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.
The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.
Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.
However, the thrust force continues to be the dominant force propelling the rocket upward.
It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.
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which produces wave particles that move and displace one another
Answer:
a guitar?
Explanation:
Which of the following is most likely the caption for the illustration that was scratched out of the textbook?
A. An electrically-charged object can attract an uncharged object with magnetic properties.
B. An electrically-charged object is stronger than a magnet.
C. A dry cell battery has magnetic properties.
D. An electric circuit can only have one dry cell battery.
IMAGE DOWN BELOW OR UP
The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.
A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.
The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.
So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.
Therefore, The correct answer is option C.
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Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
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2. In peas, gray seed color is dominant to white. In the following ex
with known phenotypes but unknown genotypes produced the listed
Parents
a. gray x white
b. gray x gray
c. white x white
d. gray x white
e. gray x gray
Gray
82
118
74
90
Progeny
White
78
39
50
0
the letter G for the gray gene and g for white, give the most probable genotype
of each parent.
Us
The most probable genotype of each parent is:
Gg (gray) x gg (white)GG (gray) x GG (gray)gg (white) x gg (white)Gg (gray) x gg (white)GG (gray) x GG (gray)Genotype determinationTo determine the most probable genotype of each parent, we need to use the principles of Mendelian genetics and the observed phenotypes of the parents and offspring. We can use the letter G for the gray gene and g for the white gene.
For parent a (gray x white), we can write the genotypes as Gg (gray) x gg (white). All of the offspring are white, so they must have received a g allele from each parent. Therefore, the genotypes of the offspring are all gg. Using a Punnett square, we can see that the most probable genotype of the gray parent is Gg, and the white parent is gg.
For parent b (gray x gray), we can write the genotypes as GG (gray) x GG (gray). All of the offspring are gray, so they must have received a G allele from each parent. Therefore, the genotypes of the offspring are all GG. Since both parents are gray, they must both have the GG genotype.
For parent c (white x white), we can write the genotypes as gg (white) x gg (white). All of the offspring are white, so they must have received a g allele from each parent. Therefore, the genotypes of the offspring are all gg. Since both parents are white, they must both have the gg genotype.
For parent d (gray x white), we already determined the genotypes in parent a. Therefore, the most probable genotype of the gray parent is Gg, and the white parent is gg.
For parent e (gray x gray), we already determined the genotypes in parent b. Therefore, both parents must have the GG genotype.
In summary, the most probable genotype of each parent is:
a. Gg (gray) x gg (white)
b. GG (gray) x GG (gray)
c. gg (white) x gg (white)
d. Gg (gray) x gg (white)
e. GG (gray) x GG (gray)
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It takes a force of 150 newtons to move a 300 newton object up a ramp to a height of 3 meters. How could you reduce the amount of force needed to move an object?Select one:a. Make the ramp higher.b. Make the ramp longer.c. Make the ramp shorter.d. Lift the object without the ramp.
Explanation
Step 1
Diagram:
Step 2
the work done by an object is defined as:
the product of the displacement of an object and the component of the applied force which is in the direction of the object's displacement:
\(Work=force*distance*cos(angle)\)so,let
\(\begin{gathered} displacement\text{ =}3m \\ force=\text{ 150 N} \end{gathered}\)therefore,l to reduce the amount of force needed , we need to affect the distnace or the angle
Step 3
let's check every option
A)Make the ramp higher.
as the distnace becomes greater the force must increase too, so this is not the rigth option,in other words , a higher distnace will neeed a stronger force
B)making the ramp longer will make the angle becomes smaller, and this makes the distance becomes greater,
C) when yuo make the ramp shorter ,you will need the same force because the displacementis vertical
when the angle becomes smaller, the work will be the same, but the distnace and force, change, cos
\(\begin{gathered} Work=force*distance*cos(angle) \\ cos\text{ \lparen angle}\Rightarrow0)=1 \\ so,\text{ } \end{gathered}\)when the angle goes to 0° degrees the required force becomes smaller, so
the answer is
b. Make the ramp longer.
D)finally, if yuo lift the object witouth the ramp ( vertically) , the distnace becomes smaller, ( only 3 m),but the force is the total weigth of the object ( 300 N)
I hope this helps you
A refrigerator using 1005 W runs one-third of the time. How much does the electricity cost to run the refrigerator each month (30 days) at 19¢ per kWh?answer in:____$
We are asked to calculate the cost to run a 1005 W refrigerator over one-third of 30 days.
To do that we will first convert the 1005W into kW using the following conversion factor:
\(1kW=1000W\)Multiplying by the conversion factor we get:
\(1005W\times\frac{1kW}{1000W}=1.005kW\)Now, we multiply the kW by the number of hours. Since the refrigerator operates one-third of the time during a 30 days period, this means that the time of operation is 10 days. We convert days into hours using the following conversion factor:
\(24h=1day\)Multiplying by the conversion factor we get:
\(10days\times\frac{24h}{1day}=240h\)Multiplying by the power we get:
\(E=(1.005kW)(240h)=241.2kWh\)Now, to determine the cost we multiply by the cost per kWh:
\(C=(241.2kWh)(0.19\frac{dollars}{kWh})=45.83\)Therefore, the cost is $45.83
Two runners race each other around a circular track. The track is 500 meters long and 159 m across (the diameter of the circle). Runner A trips at the half- way mark and doesn't get up Runner B finishes the race. Is there a difference? Explain with a diagram: Which runner has the greater displacement? Which ran the greatest distance?is there a difference?explain with a diagram
The higher displacement [highest increase in bare ground from the start position] is caused by Runner A. Runner B traveled the furthest, covering the entire track.
Simply put, what is displacement?The verb "to displace" refers to the movement or removal of anything. The location of an object is changed, which is the definition of displacement.
What is a displacement example?Change in quite an object's location in relation to an image plane is known as displacement. For instance, a billiards ball travels from one spot to another because a player strikes it. It is alleged to have moved. A vector quantity with both speed and phase is displacement.
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5. How does a jack make changing a tire easier?
Answer: An jack makes changing a tire easier because it lifts up the car to get the tire off of the ground.
Explanation:
1)What is the pressure at point D in kPa ?
2)Temperature at point D
3)What is the net work done on the gas as it is taken through four cycles?
4)What is the internal energy of the gas when it is at point A?
5)What is the total change in internal energy of this gas during four complete cycles?
The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.
The total change in internal energy of this gas during four complete cycles is zero. The given diagram represents the Carnot cycle involving four stages. The four stages of the Carnot cycle are reversible and follow an ideal gas that is placed in a cylinder with a movable piston.Let's solve each question asked one by one.1) From the graph, it can be observed that the pressure at point D is 0.08 M Pa, which is equal to 80 kPa. Hence, the pressure at point D in kPa is 80 kPa.2) Temperature at point D The isotherm at point D is about 800 K. Hence, the temperature at point D is 800 K.3) The net work done on the gas as it is taken through four cycles is zero because the Carnot cycle is a cycle that has four stages. In each cycle, the net work done is the area enclosed by the cycle. Therefore, for a complete cycle, the net work done is zero because the area enclosed is a loop.4) The internal energy of the gas when it is at point A is 100 J because the internal energy of the gas is directly proportional to the temperature and volume. Here, at point A, the temperature is 500 K, and the volume is 2 m³, so the internal energy of the gas when it is at point A is 100 J.5) The Carnot cycle is a reversible cycle that is used to determine the efficiency of heat engines. It is a closed cycle that does not involve any net energy exchange with the surroundings. Therefore, the total change in internal energy of this gas during four complete cycles is zero since the initial and final states are the same. Hence, the total change in internal energy of this gas during four complete cycles is zero.For more questions on the Carnot cycle, click on:
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1(a) At night, bats emit pulses of sound to detect obstacles and prey. The speed of sound in air is
340 m/s.
(i) A bat emits a pulse of sound of wavelength 8.5 mm. Calculate the frequency of the sound.
frequency
The frequency of the sound wave emitted by the bat is approximately 40,353 Hz.
Bats are one of the animals that emit pulses of sound to detect obstacles and prey at night. The frequency of a sound is a measure of how many waves of a sound wave pass a given point in a given period of time, and it is measured in hertz (Hz).Sound waves travel at a certain speed through a given medium.
The speed of sound is a property of a medium that determines how quickly sound waves travel through it. In air at room temperature, the speed of sound is approximately 343 meters per second. The wavelength of a sound wave is the distance between two adjacent points on the wave that are in phase, such as the distance between two consecutive crests or troughs.
The wavelength of a sound wave is inversely proportional to its frequency, so the shorter the wavelength, the higher the frequency, and vice versa.The formula to calculate the frequency of a sound wave is given by:f = v/λ,where f is the frequency, v is the speed of sound in air, and λ is the wavelength of the sound wave.
Using the given information, the frequency of the sound wave emitted by the bat can be calculated as follows:f = v/λ = 343 m/s / (8.5 mm/1000) = 40,353 Hz.
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Suppose a ball is thrown vertically upward (positive direction) from an initial height LaTeX: h_0 with initial velocity LaTeX: v_0. Find the position function LaTeX: s(t) of the ball after LaTeX: t seconds assuming the gravitational acceleration LaTeX: g is a positive constant pointing downward (negative direction).
After time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)
The given parameters;
initial velocity of the ball, = \(v_0\)initial position of the ball, = \(h_0\)acceleration due to gravity, = gThe position function of the ball after time t, is calculated as follows;
\(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)
The negative sign of acceleration of due to gravity is because the ball is moving upward against gravity.
Thus, after time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)
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A bicycle has wheels of radius 0.330 m. Each wheel has a rotational inertia of 0.0800 kg⋅m2 about its axle. The total mass of the bicycle including the wheels and the rider is 72.0 kg. When coasting at constant speed, what fraction of the total kinetic energy of the bicycle (including rider) is the rotational kinetic energy of the wheels?
The ratio of the rotational kinetic energy of the rider and the bicycle is 0.0205.
What is Rotational kinetic energy?
Rotational energy or the angular kinetic energy is the kinetic energy which is due to the rotation of an object and is also a part of the total kinetic energy.
We know that Rotational Kinetic Energy is given by,
KE(rid) = 1/2 Iω²
KE(rid) = 1/2 I (v/r)²
KE(rid) = 1/2 I (v²/r²)
where, I is the inertia and ω is the angular velocity.
That equation are perfect for the 4 wheel, however we need a similar expression for the cycle
KE (bicycle) = 1/2 mv²
The total energy can be expressed as follow,
Kt = K(rid) + K(bicycle)
Kt = 1/2 I (v²/r²) + 1/2 mv²
K(rid)/ K(bicycle) = 2I/ (2I + mr²)
(You only need to put the previous values and simplify)
Substituting , I = 0.0800, m = 72kg, and r = 0.330 m
We have,
K(rid)/ K(cycle) = 2I/ (2I + mr²)
K(rid)/ K(cycle) = 2 × 0.080/ (2 × 0.080 + 72×(0.330)²)
K(rid)/ K(cycle) = 0.16/ (0.16 + 72 × 0.108)
K(rid)/ K(cycle) = 0.16/ (0.16 + 7.776)
K(rid)/ K(cycle) = 0.16/ 7.936
K(rid)/ K(cycle) = 0.0205
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The force of gravity on a person or object on the surface of a planet is called
A. gravity
ОВ.
B. free fall
OC
c. terminal velocity
D. weight
Answer:
D. Weight
Explanation:
Hope that helps:)
A golfer shoots a ball horizontally off a cliff with a speed of 80.0 m/s, and it lands 471m from the base of the cliff.
1. How long is the golf ball in the air?
2. What is the height of the cliff?
3. What is the golf ball/s speed when it lands?
Answer:
1. t = 5.89 s
2. h = 170 m
3. Vf = 57.8 m/s
Explanation:
1.
First, we analyze the horizontal motion of the golf ball. Assuming the air friction to be negligible, the horizontal motion will be uniform. So, e can use the following equation:
\(s = vt\)
where,
s = horizontal distance covered by the golf ball = 471 m
v = horizontal speed of golf ball = 80 m/s
t = time taken by the golf ball in air = ?
Therefore,
\(471\ m = (80\ m/s)t\\\\t = \frac{471\ m}{80\ m/s}\\\\\)
t = 5.89 s
2.
Now, we analyze the vertical motion. Using 2nd equation of motion:
\(h = v_{i}t + \frac{1}{2}gt^2\)
where,
h = height of cliff = ?
vi = vertical component of initial speed of ball = 0 m/s(ball was shot horizontally)
g = acceleration due to gravity = 9.81 m/s²
t = time of flight = 5.89 s
Therefore,
\(h = (0\ m/s)(5.89\ s) + \frac{1}{2}(9.81\ m/s^2)(5.89\ s)^2\)
h = 170 m
3.
Now, we can use 1st equation of motion:
\(v_{f} = v_{i} + gt\\v_{f} = 0 m/s + (9.81\ m/s^2)(5.89\ s)\\\)
Vf = 57.8 m/s
Image shows question, please help
Jonathan needs to maintain a separation of 0.543 mm between the plates to get the desired charge, and a dielectric constant of 92.6 to achieve a separation of 5 mm with a dielectric.
(a) Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can solve for the capacitance: C = Q/V =\((8.15 x 10^-9 C) / (50 V) = 1.63 x 10^-10 F.\)
Then, using the formula for capacitance of parallel plate capacitors: C = ε0A/d, where ε0 is the permittivity of free space, A is the area of the plates, and d is the separation distance, we can solve for the separation distance: d =\(_{3}OA/C = (8.85 x 10^-12 F/m) x (0.01 m^2) / (1.63 x 10^-10 F) = 0.543 mm.\)
(b) To find the dielectric constant, we can use the formula for capacitance of a parallel plate capacitor with a dielectric: C = εrε0A/d, where εr is the relative permittivity or dielectric constant of the material. Solving for εr, we get: εr = Cd / ε0A = \((1.63 x 10^-10 F)\) x (0.005 m) / \((8.85 x 10^-12 F/m)\) x \((0.01 m^2)\) = 92.6.
Therefore, Jonathan should use a dielectric with a relative permittivity of 92.6 to achieve a separation of 5 mm.
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Examine the image and assess the relationship of the atoms shown by
The reactants in the given chemical equation are methane (CH₄) and oxygen (O₂), while the products are carbon dioxide (CO₂) and water (H₂O).
During a chemical reaction, the atoms of the reactants reorganize to form new compounds in the products. A chemical change is this atomic rearrangement.
What is a change in chemistry?A chemical change is the transformation of one or more substances into new ones with distinct chemical and physical properties. New substances are created when the original substances' atoms are rearranged and new chemical bonds are formed during a chemical change.
Typically, a transfer of energy in the form of heat, light, or sound occurs in conjunction with this kind of change. Reactions like combustion, oxidation, decomposition, and synthesis are all examples of chemical changes. Physical changes, on the other hand, involve alterations in a substance's physical properties without altering its chemical composition.
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a child holds a 10N toy car for 30 seconds. what is the net work done on the toy car?
If the child is holding the toy car still for 30 seconds, then net work done on the car is zero.
What is meant by work done?Work is defined as the product of force and displacement in the direction of force. In this case, the force and displacement are perpendicular to each other, so no work is being done. Therefore, net work done on the toy car is zero.
If the child is holding the toy car still, then net work done on the car is zero. This is because the force exerted by the child is equal in magnitude and opposite in direction to the force of gravity acting on the car and car is not moving, so there is no displacement.
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PLEASE HELP!!!!
Suppose a tractor was moving forward at 6.0 m/s. It runs into a pile of hay and is
brought to a stop in 1.1 s. If the tractor had a mass of 2550 kg, with what force did
the pile of hay stop the tractor?
A. -5.5N
B. -14000N
C. 15000N
D. -15000N
E. -0.0021N
F. -0.000072
Answer:
B )-14000N
Explanation:
F=mv-mu
t
F =2550(0)-2550(6)
1.1
F = -13909.09
approximately -14000N
Suppose a tractor was moving forward at 6.0 m/s. It runs into a pile of hay and is brought to a stop in 1.1 s. If the tractor had a mass of 2550 kg, the force did the pile of hay stop the tractor 14000N
What are the types of force ?Force can be a unit of pushing or pulling of any object which result from the object’s interaction or movement, without applying force the objects can not be moved, can be stopped or change the direction.
Force is a quantitative parameter between two physical bodies, means an object and its environment, there are various types of forces in nature.
If an object present in its moving state will be either static or motion, the position of the object will be changed if it is pushed or pulled and The external push or pull upon the object is mainly called as Force.
The contact force that occurs when we apply some effort on an object such as Spring Force, Applied Force, Air Resistance Force, Normal Force, Tension Force, Frictional Force
Non-Contact forces are the type of forces that occur from a distance such as Electromagnetic Force, Gravitational Force, Nuclear Force
F=mv-mu
t
F =2550(0)-2550(6)
1.1
F = -13909.09
approximately -14000N
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A 30.0 kg cart travelling at 5.00 m/s collides with a 50.0 kg cart. Both carts immediately come to rest after the collision. What was the velocity of the 50.0 kg cart
Answer:
30m/s
Explanation:
From the principle of conservation of momentum; it implies momentum before collision is same after collision hence
M1U1 +M2U2= M1V1 +M2V1
Since both objects comes to rest after collision it means the final velocity is 0 and this has been represented as V1; hence the right side of the equation evaluates to zero.
We can then rewrite the equation as;M1U1 +M2U2=0
Let U1 and U2 be the respective velocity for M1 =30kg and M2= 50kg respectively.
Hence the equation becomes on substituting M1,M2 and U1.
We have;
30×5 + 50×U2 = 0
150 +50U2=0
50U2 = -150
U2= -150/50 = -30m/s
Ignore the -ve sign which shows the direction of the 50kg mass was opposite that of 30kg
The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.
The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.
The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
Learn more about earthquakes from the given link.
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A monochromatic beam of light is sent through each of the following six optical slides.
Rank these scenarios on the basis of the angle of the first interference maximum.
Rank from largest to smallest. To rank items as equivalent, overlap them.
a.) difraction grating with 1000 lines/cm
b.)single slit slide with width .04mm
c.)single slit slide with width .01mm
d.) double slit slide with spacing .08mm
e.)diffraction grating with 500 lines/cm
f.)double slit slide with spacing .02mm
c>a>f=e>b>d is the rank from largest to smallest, which scenarios on basis of the angle of interference.
single-slit slide with width 0.01 mm> diffraction grating with 1000 lines/cm> double-slit slide with spacing 0.02 mm=diffraction grating with 500 lines/cm> single-slit slide with width 0.04 mm> double-slit slide with spacing 0.08 mm
Monochromatic lights are called single-wavelength light, where mono refers to a single, and chroma means color which is essentially electromagnetic radiation derived from photon emissions from atoms.
A sodium lamp is one example of monochromatic light. There are some applications like:
It is used in crime detection to scan specific and delicate evidence. It also helps to recognize hidden bloodstains, fingerprints, fibers, and lesions under the skin.To know more About Monochromatic beams:
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For a given substance, the molecules
move fastest when the substance is
Answer:GAS
Explanation:
what are some ways that electric fields are simular to magnetic fields
Answer:
Obey inverse square law obey superposition principlelong range forces.linear current source Idl produces magnetic field just as linear charge source produces electric field.pls mrk me brainliest
give 2 reasons why a person should move away from "isolating muscles"
Answer:
1) - They should move away because its cold
2) - You can get hypothermia......
Explanation:
What is electronegativity
If a person was interested how light passes through clear substances, what field of science would be the best course of study?
A. thermodynamics
B. quantum mechanics
C. optics
D. electromagnetism
Answer:
C. Optics
Explanation:
We need to understand each of the fields first.
A. Thermodynamics: Thermodynamics is the branch of science the deals with the transfer of heat as it is clear from the name. Thermo means Heat and Dynamics means motion,
B. Quantum Mechanics: It is the study of the physical laws and properties in nature, at atomic or even sub-atomic level.
C. Optics: Optics is the branch of physics that deals with the nature of light light and the phenomena related to the light.
D. Electromagnetism: It is the branch of physics that deals with the interaction of electricity and magnetism.
Since, optics deals with the phenomena of light. Hence, person interested in how light passes through clear substances, should study:
C. Optics