The value of the rate constant at 820.0 K is 0.2 s^-1
Applying the Arrhenius equation, which is...
k = Ae-Ea/RT
Applying the formula, we get
lnk2 = lnk1 - (Ea/R)(1/T2 - 1/T1)
Applying the values, we get
ln k2 = ln 6.1x10^-8 - (2.62x10^3/8.314)(1/820 - 1/600)
Calculating the value, we get...
ln k2 = -0.31
Taking power e, we get
k2 = 0.2 s^-1
Arrhenius equation relates the temperature and activation energy of a reaction.It is helpful in studying the different parameters related to reaction.Activation energy is the minimum required to attain to form the product.To learn more about the activation energy visit:
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1. What is a huge ball of super-heated gases?
O planet
star
solar system
galaxy
Answer:
star
Explanation:
Nayla grew skin in a lab by adding cells to a synthetic material. The skin functioned normally for 12 days. Then Nayla separated some
of the skin cells into cell membranes, cytoplasm, and vacuoles to studythem. WhichofthefollowingwerealiveduringNayla’s experiment?
a. The skin and the cytoplasm
b. The skin and the skin cells
c. The cell membranes and the skin cells
d. The cell membranes and the cytoplasm
Answer:B) The Skin and The Skin cells
Explanation:
Hope this helped
A cube of iron and a cube of wood, each having a volume of V = 3.25 10-4 m3, are each placed in a large beaker of water. The density of the wood is rhowood = 3.73 102 kg/m3 and the density of the iron is rhoiron = 7.86 103 kg/m3. Calculate the buoyant force on each. (The cube of wood is allowed to float at the surface.)
Answer:
anor277
Nov 17, 2017
Well, by definition,
Molarity
≡
Moles of solute
Volume of solution
Explanation:
And thus...
moles of solute
=
molarity
×
volume
We use a molar quantity of
80.3
⋅
g
174.01
⋅
g
⋅
m
o
l
−
1
=
0.461
⋅
m
o
l
with respect to
potassium sulfate
And thus
volume
=
moles of solute
molarity
80.3
⋅
g
174.01
⋅
g
⋅
m
o
l
−
1
3.12
⋅
m
o
l
⋅
L
−
1
=
0.148
⋅
L
.
The buoyant force is one that acts against the weight of an object suspended in a fluid. The value of the buoyant force on each are:
i. Buoyant force on the cube of iron = 25.0 N
ii. Buoyant force on the cube of wood = 1.20 N
Upthrust is a force which acts against the direction of the weight of an object when suspended in a fluid. It acts majorly upwards against gravity, and it can be referred to as a buoyant force.
The amount of upthrust on object in a fluid sometimes depends on the density, volume and gravity acting on the object.
So that;
Upthrust = density x volume x gravity
Thus from the given question;
i. The buoyant force on the cube of iron can be determined by:
Upthrust = 7.86 x \(10^{3}\) * 3.25 x \(10^{-4}\) * 9.8
= 25.034
Upthrust = 25.0 N
Therefore, the buoyant force on the cube of iron is 25.0 N.
ii. The buoyant force on the cube of wood can be determined by:
Upthrust = 3.73 x \(10^{2}\) * 3.25 x \(10^{-4}\) * 9.8
= 1.1880
Upthrust = 1.20 N
Therefore, the buoyant force on the cube of wood is 1.20 N.
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The volume of a sample of hydrogen gas was decreased from 10.89 L
to 4.18 L
at constant temperature. If the final pressure exerted by the hydrogen gas sample was 8.95 atm,
what pressure did the hydrogen gas exert before its volume was decreased?
Answer:
3.44 atm
Explanation:
boyles law
p1v1=p2v2
p1*10.89 L=4.18 L*8.95 atm
p1*10.89=4.18*8.95
p1*10.89 = 37.411
p1 = 37.411/10.89
p1 = 3.43535353535
Applying a force can make an electron shift from one atom to another causing what?
Describe at least 3 biotic and 3 abiotic factors found in that ecosystem and do not tell which ecosystem you chose
gravity sample work connection’s academy
PLEASE HELP AS SOON AS POSSIBLE WILL MARK BRAINIEST
Answer:
search on YT Khan academy work done by gravity
Explanation:
you will get it for sure with best explanation
mark me please on brainlest
Difference between heavy chemicals and fine chemicals
Answer:
Fine chemicals are used as starting materials for specialty chemicals, particularly pharmaceuticals, biopharmaceuticals and agrochemicals. ... The term "fine chemicals" is used in distinction to "heavy chemicals", which are produced and handled in large lots and are often in a crude state.
Explanation:
What volume of 12 M NaOH and 2 M NaOH should be mixed to get 2 litres of 9 M NaOH solution?
Which of the following would likely be a non -conductor of electricity?a) An aqueous solution of magnesium sulfate (Epsom salts)b) Gasolinec) An aqueous solute of sodium carbonate (washing powder)d) Carbonated soft drinksExplain your answer.
This would be the Gasoline, letter B, since gasoline is a hydrocarbon and these compounds are formed with covalent bonds, they share electrons and not gain or lose, forming ions and then conducting electricity, as we can see in the other 3 options, they all form ions.
please help me out, am trying to solve it but its hard
Answer:
A
Explanation:
A
from le chatelier's principle, we know that as the concentration of one reactant or product changes, the equilibrium is shifted. If the concentration of a gaseous or aqueous product increases, the equilibrium is shifted to the left. Iodine is added, which means that the equilibrium is shifted to the left. Iodine increases, and HI increases. Since HI has increased, there must have been some iodine and hydrogen consumed. Since iodine was added, there is a net increase of iodine. However, since hydrogen was consumed and no new hydrogen was added, the concentration of hydrogen decreases
Give an excited state electron configuration for Kr
24) Which ionization process requires the most energy? A) W(g) → W+(g) + e-
B)W+ (g)→ W2+ (g)+e-
C)W2+ (g)→ W3+ (g)+e-
D)W3+ (g)→ W4+ (g)+e-
E) All the above reactions require the same amount of energy.
Option D, W3+ (g) → W4+ (g) + e-, requires the most energy for the ionization process.
The ionization interaction that requires the most energy is choice D, where W3+ (g) is ionized to W4+ (g) by the deficiency of one electron. This is on the grounds that the energy expected to eliminate an electron from a particle increments as the particle turns out to be all the more decidedly charged. Hence, it takes more energy to eliminate an electron from W3+ (g) than it does from W+(g), W2+ (g), or W3+ (g).
Choice An includes the expulsion of one electron from an impartial tungsten iota, and choice B includes eliminating an electron from W+. Choice C includes eliminating an electron from W2+. These ionization processes require less energy than choice D in light of the fact that the ionization energy increments as the particle turns out to be all the more emphatically charged. Hence, the ionization energy expected to eliminate an electron from W3+ is more prominent than that expected to eliminate an electron from any of the past particles.
Subsequently, choice D, W3+ (g) → W4+ (g) + e-, requires the most energy for the ionization interaction.
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Why is scientific notation used?
to round numbers to the nearest whole number
to promote reproducibility of data
to increase the validity of data
to express very large or very small numbers
The correct option is (d) To express very large or very small number.
What is the Scientific Notation?
Scientific notation is a way to present numbers that are too large or too small to be easily written in decimal form. The three components of scientific notation are coefficient, base and exponent. The proper format to write a scientific notation is a x 10^b, where a is a number or decimal number and b is the power of 10 to make scientific notation equivalent to original number. When a number between 1 and 10 is multiplied by a power of 10 then the number is expressed in scientific notation. For example, 10000000 can be written as 10⁷, which is the scientific notation and the exponent is positive here. Similarly, for the negative exponent 0.000001 can be can be represented as 10-⁷. Hence, the scientific notation is used to express very large or very small numbers.
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Draw the structure(s) of all of the possible monochloro derivatives of 2,6-dimethylheptane, C9H19Cl.
Answer:
The monochloro derivatives of 2,6-dimethylheptane are 1-chloro-2,6-dimethylheptane, 2-chloro-2,6-dimethylheptane, 3-chloro-2,6-dimethylheptane, and 4-chloro-2,6-dimethylheptane
Explanation:
The structures of all of the possible monochloro derivatives of 2,6-dimethylheptane, C₉H₁₉Cl are shown in the attachments below.
The monochloro derivatives of 2,6-dimethylheptane are
1. 1-chloro-2,6-dimethylheptane
2. 2-chloro-2,6-dimethylheptane
3. 3-chloro-2,6-dimethylheptane
4. 4-chloro-2,6-dimethylheptane
Explain what an ion is.
An ion is an atom or a group of atoms that carries an electric charge.
What is an ion?An atom becomes an ion when it gains or loses one or more electrons, resulting in an unequal number of protons and electrons. This imbalance of positive and negative charges gives the ion a net charge, either positive or negative.
When an atom loses one or more electrons, it becomes a positively charged ion, called a cation. Cations have fewer electrons than protons, resulting in a net positive charge.
When an atom gains one or more electrons, it becomes a negatively charged ion, called an anion. Anions have more electrons than protons, resulting in a net negative charge.
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KCIO3 -> KCI + 02
How many moles of KCI are produced if 6743 grams of KCIO3 decomposes?
55.03 moles of KCI are produced when 6743 grams of \(KClO_{3}\) decomposes
To determine the number of moles of KCl produced when 6743 grams of \(KClO_{3}\) decomposes, we need to use the concept of molar mass and the balanced chemical equation.
First, let's calculate the molar mass of \(KClO_{3}\)
The molar mass of potassium (K) is approximately 39.10 g/mol.
The molar mass of chlorine (Cl) is approximately 35.45 g/mol.
The molar mass of oxygen (O) is approximately 16.00 g/mol.
So, the molar mass of \(KClO_{3}\) is:
(39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol) = 122.55 g/mol.
Now, we need to calculate the number of moles of \(KClO_{3}\):
Number of moles = Mass / Molar mass
Number of moles = 6743 g / 122.55 g/mol = 55.03 mol.
According to the balanced chemical equation:
2\(KClO_{3}\) -> 2 KCl + 3 O2,
we can see that for every 2 moles of \(KClO_{3}\), we obtain 2 moles of KCl.
Therefore, the number of moles of KCl produced will be equal to the number of moles of \(KClO_{3}\) since the ratio is 1:1. Thus, 55.03 moles of KCl will be produced.
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What is TRUE about the precipitin test?
A.
It determines if blood is type A, B, or O.
B.
It uses hydrogen peroxide to make a chemical reaction.
C.
It requires a very small amount of blood.
D.
It can only be used on blood that is still wet.
Precipitin test is used to determine antigens and human blood from other sources. It is widely used in forensic laboratories. Thus we can determine the blood groups such as A, B,O etc.
What is precipitin?Precipitin is an antibody which precipitates when other antigens binds with it. Thus, antigens from other source can be easily determined using precipitin reaction.
Precipitin reaction involves a specific serological precipitation of an antigen . Varying amounts of the antigen is added to the serum source where each antigen molecule extensively bound to the antibody excess zone.
A small antibody - antigen complex is formed there with crosslinking reaction. The advantages of this test is that very small amount of test sample is needed and about fifty specimens can be easily tested within few minutes.
Therefore, the precipitin test can used to determine the antigen type of blood A, B or O. Hence, option A is correct.
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Answer: A
Explanation:
7. The picture below shows a girl with a widow's peak. Widow's peak She has a widow's peak because of her -
Answer:
genes (c)
Explanation:
since traits are passed down genetically, so her mother or father must have one (or even one of her grandparents)
hope this helps!:)
Answer: D.
Explanation:looks right to me it’s for sure not A hope did helped
When you are finished with the experiment, complete the following data analysis and record your answers in the Essay box
below.
1. Determine the volume of the box and the block
2. Determine the ratio of the block to the box
volume of block (L)(W) (H)
volume of box L(
WH)
a. Multiply this number by 100 to turn it into a percent
b. Complete this statement: The volume of the block is
percent of the volume of the box.
0
3. Determine the ratio of the number of hits to the number of shots:
number of hits
100 shots
a. Multiply this number by 100 to turn it into a percent
b. Complete this statement: The block was hit percent of the time.
4. Compare the results of step 2 to the results of step 3. Are the percentages similar?
5. Write a conclusion discussing the following items:
a. Based on your findings, do you think Rutherford's hypothesis was reasonable?
b. Restate Rutherford's hypothesis and describe how you tested it
c. State whether your results support the hypothesis. If they do not, can you suggest some error in experimental
procedure (other than general human error) that might explain it?
d. Finally, explain how this experiment confirms the nuclear model of the atom and the idea that most of the atom is
empty space
Answer:
lol id help u if i could
Explanation:
Volume of the block (V_block) = Length (L) x Width (W) x Height (H)
Volume of the box (V_box) = Length (L) x Width (W) x Height (H)
Ratio of the block to the box:
Volume of the block / Volume of the box = (V_block / V_box) x 100%
Ratio of the number of hits to the number of shots:
Number of hits / 100 shots = (Number of hits / 100) x 100%
Comparing the percentages from step 2 and step 3, we can determine if they are similar.
Conclusion:
a. Based on the findings, we can evaluate whether Rutherford's hypothesis was reasonable.
b. Restate Rutherford's hypothesis: Rutherford proposed that the atom has a small, dense, and positively charged nucleus at its center, with electrons moving around the nucleus in empty space.
c. How the hypothesis was tested: The experiment involved shooting alpha particles at a gold foil to observe their behavior, specifically to see how many alpha particles were deflected and how many passed through.
d. Results supporting the hypothesis: If the percentages from step 2 and step 3 are similar, it indicates that a significant portion of the atom is empty space since most of the alpha particles passed through the foil without being deflected. This supports the nuclear model of the atom, with a small and dense nucleus surrounded by mostly empty space.
e. Possible errors in the experimental procedure: Some errors that might explain discrepancies in the results include experimental setup issues, calibration errors, or variations in the alpha particle source.
f. Confirmation of the nuclear model of the atom: The experiment confirmed that most of the alpha particles passed through the gold foil without significant deflection, implying that atoms have a lot of empty space. This supported Rutherford's hypothesis of a small, positively charged nucleus surrounded by electron orbits, confirming the nuclear model of the atom.
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a. You have a stock solution of 14.8 M NH3. How many milliliters of this solution should you dilute to make 1000.0 mL of 0.250 M NH3?
b. If you take a 10.0 mL portion of the stock solution and dilute it to a total volume of 0.500 L, what will be the concentration of the final solution?
Answer:A) V = 16.892 ml
Explanation:
M1 * V1 = M2 * V2
14.8 M * V1 =0.250 M * 1000 ml
V1 = 16.892 ml
a. The volume of 16.89 milliliters of the stock solution of 14.8 M should be diluted to make 1000.0 mL of 0.250 M.
b. The concentration of the final solution is 0.296 M.
What is the dilution law?The concentration or the volume of the concentrated or dilute solution can be calculated by using the equation:
M₁V₁ = M₂V₂
where M₁ and V₁ are the concentration and volume of the concentrated solution respectively and M₂ and V₂ are the concentration and volume of the dilute solution.
A stock solution is a solution that has a high concentration and that will be diluted to a low concentration by the addition of water in it.
Given, a stock solution of concentration, M₁ = 14.8 M
The concentration of the diluted solution, M₂ = 0.250 M
The volume of diluted solution, V₂ = 1000ml
Substitute the value of the molarity and volume in equation (1):
(14.8)× (V₁) = (1000) × (0.250)
V₁ = 16.89 ml
Similarly, for part (b): M₁ = 14.8 M, V₁ = 10 ml and V₂ = 0.5L = 500 ml
(14.8)× (10) = (500) × (M₂)
M₂ = 0.296 M
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How many grams of CCl4 are needed to make a 1.20 m solution in 450g of octane?
There 83.2g of CCl4 are needed to make a 1.20 m solution in 450g of octane.
An octane score, or octane wide variety, is a popular measure of a gasoline's potential to face up to compression in an internal combustion engine without detonating. The higher the octane variety, the greater compression the gas can withstand before detonating. Octane rating is the measure of a fuel's ability to face up to knocking or pinging all through combustion, as a result of the air and fuel combination detonating prematurely in the engine.
Octane's legs are made from platinum, stated by using Octane whilst you reach Platinum IV in ranked announcing, Platinum rank to suit my legs Octane will be addicted to his Stim, together with his regular twitching within the in-game lobby and his use of the stim without apparent usage in trailers and teasers. considering Octane was envisioned with a mask, there's not anything beneath there that can make exceptional faces. Parra explained that because of this, he could have a clean expression for the whole thing.
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Rank each of the following gases in order of increasing Urms assuming equivalent amounts and all gases are at the same temperature and pressure where 1 is the lowest Urms Gas 1: H2S Gas 2: He Gas 3: NF3 Gas 4: H20
Answer:
NF3< H2S< H2O< He
Explanation:
The average speed of a gas depends on the relative molecular mass of the gas. Lighter gases have a greater average speed and move faster than heavier gases.
Hence, we need to arrange these gases listed in the question in order of decreasing molecular mass in order to obtain the order of increasing Urms assuming equivalent amounts and all gases are at the same temperature and pressure.
Hence; NF3< H2S< H2O< He
what is normality and molarity of the concentration of solution?
Answer:
Normality is the number of gram equivalents of solute divided by the volume in liters.
The molarity is the amount of moles in solute divided by the volume in liters.
Moles are the molar mass times grams if you're curious
I hope this helps and good luck!
Answer:
Molarity and normality describe the numbers (moles) of reactants or products dissolved in one liter of solution. Molarity: M = moles of solute contained in one liter of solution. ... Normality is always a multiple of molarity. It describes the “equivalent” moles of reactants involved in chemical reactions.
Explanation:
Normality is a measure of concentration equal to the gram equivalent weight per litre of solution. Gram equivalent weight is the measure of the reactive capacity of a molecule. The solute's role in the reaction determines the solution's normality. Normality is also known as the equivalent concentration of a solution.
Molar concentration is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.
Formula for Molar: M = \(\frac{n}{v}\)
How does the electric force vary with distance
Answer:
increasing the separation distance between objects decreases the force of attraction
Explanation:
Determine the mass in grams of CO, that is produced by the complete reaction of
0.2038 moles of CH₁ (xylene) according to the following combustion reaction:
C_H,,(I)+ 10.5 O,(9)– 8 |CO,(g)+ 5 \H,O(g)
Taking into account the reaction stoichiometry, 71.7376 grams of CO₂ is produced by the complete reaction of 0.2038 moles of xylene.
Reaction stoichiometryIn first place, the balanced reaction is:
C₈H₁₀ + 10.5 O₂ → 8 CO₂ + 5 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₈H₁₀: 1 moleO₂: 10.5 molesCO₂: 8 molesH₂O: 2 molesThe molar mass of the compounds is:
C₈H₁₀: 106 g/moleO₂: 32 g/moleCO₂: 44 g/moleH₂O: 18 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
C₈H₁₀: 1 mole ×106 g/mole= 106 gramsO₂: 10.5 moles ×32 g/mole= 336 gramsCO₂: 8 moles ×44 g/mole= 352 gramsH₂O: 5 moles× 18 g/mole= 90 gramsMass of CO₂ formedIt can be applied the following rules of three: if by reaction stoichiometry 1 mole of C₈H₁₀ form 352 grams of CO₂, 0.2038 moles of C₈H₁₀ form how much mass of CO₂?
mass of CO₂= (0.2038 moles of C₈H₁₀× 352 grams of CO₂)÷1 mole of C₈H₁₀
mass of CO₂= 71.7376 grams
Finally, 71.7376 grams of CO₂ are formed.
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How can knowledge of separating mixtures help you in daily life and within society? Answer below.
Answer:
I can say that knowledge of separating mixtures can help us in daily life and within society in the following ways:
1. Purification of water: Separation techniques are used to purify water for drinking and industrial purposes. It is essential to remove impurities from water to prevent diseases.
2. Recycling: Separation techniques are used to separate materials for recycling. This helps reduce the amount of waste in landfills and helps conserve resources.
3. Food industry: Separation techniques are used in the food industry to separate unwanted particles from food products. This helps ensure that the food we eat is safe and free from contaminants.
4. Medicine: Separation techniques are used in the pharmaceutical industry to separate and purify chemicals for use in medicine. This helps ensure that medicines are safe and effective.
5. Environmental protection: Separation techniques are used to remove pollutants from the environment. This helps protect our natural resources and prevent pollution-related health problems.
6. Oil and gas industry: Separation techniques are used to separate crude oil and natural gas into their various components. This helps in the production of energy and other useful products.
In summary, knowledge of separating mixtures is essential in our daily lives and within society. It helps ensure that we have access to safe and clean water, food, medicine, and energy, and also helps protect the environment.
Explanation:
How can you use titration to determine an unknown concentration?
Answer:
You will use the volume and known concentration of the titrant to calculate the number of moles needed to titrate a sample of unknown concentration
HELP PLEASE ILL GIBE BRANLIEST TO WHOEVER CAN SOLVE THIS WITH NO LINKS!!!!!! If 4.00 moles of a gas at a pressure of 5.40 atmospheres have a
volume of 120 liters, what is the temperature of this gas? (R = .0821
L. atm L. atm
K mol K.
komol)
F. 190 K
G. 234 K
H. 1973 K
J. 2280 K
C.9.A-R/C.2.G-P
Answer:
Option H
Explanation:
We can get the temperature of the gas by applying ideal gas law,
PV = nRT
Here, P = Pressure of the gas
V = Volume of the gas
n = Number of moles
R = Gas constant
T = Temperature
By substituting the values in the given equation,
5.40 × 120 = 4 × 0.0821 × T
648 = 0.3284T
T = \(\frac{648}{0.3284}\)
T = 1973.20
≈ 1973 K
Therefore, temperature of the gas is 1973 °K
Option H will be the answer.
Identify the fact that is FALSE about the law of conservation of energy?
Answer:
What are the options?
Explanation:
......