Butadiene (right) is a colorless gas used to make synthetic rubber and many other compounds.
(b) Are cis-trans arrangements about the double bonds possible? Explain.

Answer:

In very simple words ,

As the weight increases the gravitational force acting on the ball increases and thus it effects the change in the distance of the ball as the ball will fall very close to its initial distance if it has more mass and shall go far if the mass is less .

The enthalpy change for the process MgSO₄ + NaOH → Mg(OH) + Na₂SO₄ is 132.065 J/mol.

Total volume of the solution:

= 50 + 50

= 100mL

Mass of the solution (water) = 100mL × 1gm/mL = 100gm

Heat absorbed by the solution

= 100gm ×  4.18 J/°C/gm ×  (29.3-23.2)

=2549.8 J

Heat absorbed by the calorimeter:

= 15J/°C ×  (29.3-23.2) = 91.5 J

Total heat absorbed:

= 2549.8 J + 91.5 J

= 2641.3 J

Moles of MgSO4 =1.00M/0.05 L = 20mol

Enthalpy of reaction per mole of MgSo4 reacted = 2641.3 J ÷ 20mole

= 132.065 J/mol

Thus, enthalpy change for the process  MgSO₄ + NaOH → Mg(OH) + Na₂SO₄ is 132.065 J/mol.

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The type of light that can be broken into its individual wavelengths by a prism is Ultraviolet. The correct answer is Option B.

Ultraviolet (UV) light is a form of electromagnetic radiation that is invisible to the eye. Ultraviolet radiation has a wavelength that is shorter than visible light but longer than X-rays. This is the type of light that can be broken down into its individual wavelengths by a prism.

A prism is a piece of glass or other transparent material with a specific shape that can split white light into its component colors. The process of bending and separating light is known as dispersion. The index of refraction of the glass, as well as the angle of incidence, determines the amount of refraction that occurs.

In conclusion, ultraviolet light is the type of light that can be broken down into its individual wavelengths by a prism.

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Answer:

The maximum number of electrons present in a particular shell is calculated by the formula 2n2, where “n” represents the shell number. For instance, K shell is the first shell and it can hold up to 2(1)2 = 2 electrons. Similarly, L shell is the second shell and it can hold up to 2(2).

Answer:

the oil spreads to cover the water

Answer:

I think it is ; The oil floats to the surface of the water

Explanation:

I don't know about the other one.

Answer:

Usually, you should lay down your educational background by listing the most recent or advanced degree first, working in reverse chronological order. But there are exceptions. Say you earned a degree in geography, but are now working in the field of online marketing. If you more recently completed coursework specific to social media or digital marketing, list that first to grab the reviewer’s attention.

Explanation:

Answer:

Start with the most recent  or advanced degree first, working in reverse chronological order.

Explanation:

15.80 oz of gold contains approximately 3.29 x 10²³ atoms.

The ounce/oz is any of the several different units of mass, weight or volume and is derived almost unchanged from the uncia.

In order to convert 15.80 oz to atoms, we need to know the identity of substance we are dealing with. The number of atoms in a given mass of a substance depends on atomic mass and Avogadro's number.

To convert ounces to grams, we can use the following conversion factor:

1 oz = 28.35 g

15.80 oz * (28.35 g/oz) * (1 mol/196.97 g) * (6.022 x 10²³ atoms/mol) = 3.29 x 10²³ atoms

Therefore, 15.80 oz of gold contains approximately 3.29 x 10²³ atoms.

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The substitution product that is suppose to be favoured is The product with retention of configuration is expected to predominate slightly, because the leaving group blocks the nucleophile.

Substitution product is a product that is gotten from a reaction in which a group of reactant is replaced by another group in the reaction.

Therefore,The substitution product that is suppose to be favoured is The product with retention of configuration is expected to predominate slightly, because the leaving group blocks the nucleophile.

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Answer:

666.6 pounds

Explanation:

Answer:

105.98844 g/mol

Explanation:

Answer:

Covalent bonds are much more common in organic chemistry than ionic bonds. A covalent bond consists of the simultaneous attraction of two nuclei for one or more pairs of electrons. The electrons located between the two nuclei are bonding electrons.

...

Answer:

pH = 1.522

Explanation:

HCl + H20 -> Cl^(-) + H30^(+)

0.03M ____ ____

____ 0.03M 0.03M

[H30^(+)] = 0.03M

pH = - log([H30^(+)])

pH = - log( 0.03)

pH = 2 - log3

pH = 2- 0.47

pH = 1.522

The pH of the hydrogen chloride, HCl solution having a concentration of 0.03 M is 1.52

This is simply a measure of the acidity / alkalinity of a solution.

The pH measures the hydrogen ion concentration while the pOH measures the hydroxide ion concentration

Dissociation equation

HCl(aq) —> H⁺(aq) + Cl¯(aq)

From the balanced equation above,

1 mole of HCl contains 1 mole of H⁺.

Therefore,

0.03 M HCl will also contain 0.03 M H⁺

pH = –Log H⁺

pH = –Log 0.03

pH = 1.52

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The change in temperature for the silicon is approximately -2.21°C. Note that the negative sign indicates a decrease in temperature.

Using the formula q = m * c * ΔT, we can rearrange it to solve for c, giving c = q / (m * ΔT). Plugging in the given values, we get c = -125 J / (25.0 g * -5.0 degrees Celsius) = 1.00 J/(g*C).

To calculate the change in temperature of silicon, we need to use the specific heat capacity of silicon (0.71 J/g°C) and the equation:

q = m × c × ΔT

where q is the energy released (-125 J), m is the mass of silicon (25.0 g), c is the specific heat capacity of silicon (0.71 J/g°C), and ΔT is the change in temperature we want to calculate.

Rearranging the equation, we get:

ΔT = q / (m × c)

Substituting the values, we get:

ΔT = -125 J / (25.0 g × 0.71 J/g°C) ≈ -2.21°C

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Answer:-29.4

Explanation:

Part 1: Carbon dioxide is most likely the molecule represented by C. Part 2: Cellular respiration is one mechanism that might cause carbon dioxide to be released into the atmosphere.

Since it is continually recycled between living things and the environment, carbon is saved during the carbon cycle. Plants absorb atmospheric carbon dioxide during the photosynthetic process to create organic compounds like glucose.

Many health impacts from CO2 exposure might be experienced. These symptoms can include a coma, hypoxia, convulsions, sweating, a tingling or pins-and-needles sensation, headaches, disorientation, restlessness, a tingly or pins-and-needles feeling, and trouble breathing.

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Answer:

than what can i do lol

Answer:

The reactants are on the left of the arrow, the products are on the right.

Explanation:

Reactants are the substances that exist before the chemical reaction takes place. When writing a chemical reaction or equation, they are found on the left of the arrow. They react to form new substances, which are known as the products. The products are found to the right of the arrow in the reaction.

Answer:1. How many moles is 400.0 g of Al 2(SO4)3?

Mol = mass/molar mass

Mol = 400.0g/342g/mol = 1.169 mol

2. Which is the percent composition of bromine in the compound NaBr?

% Br = (mass Br/mass NaBr) x 100

% Br = (79.90g/102.88g) x 100 = 77.7%

3.How many molecules are in 3.6 grams of NaCl?

Molecules NaCl = 3.6g NaCl x 6.02 x 1023 NaCl molecules = 3.7 x 1022 molecules

58.43g NaCl

4.How many grams are in 1.946 moles of NaCl?

From Mol = mass/molar mass,

Mass = mol x molar mass

Mass NaCl = 1.946 mol x 58.43 g = 113.7 g

Explanation:

The given information refers to a scientific article titled "A CCSD(T) Investigation of Carbonyl Oxide and Dioxirane" authored by Cremer, D., Gauss, J., Kraka, E., Stanton, J. F., and Bartlett, R. J., published in the journal Chemical Physics Letters in 1993, with the volume number 209 and pages 547-556.

The mentioned article focuses on a computational study using the CCSD(T) method to investigate carbonyl oxide and dioxirane. The authors explore various aspects such as equilibrium geometries, dipole moments, infrared spectra, heats of formation, and isomerization energies associated with these compounds. By employing advanced computational techniques, they aim to provide insights into the molecular properties and behavior of carbonyl oxide and dioxirane, which have relevance in the field of chemical physics.

The CCSD(T) method is a high-level quantum mechanical approach used to accurately describe the electronic structure and properties of molecules. Through this study, the authors aim to contribute to the understanding of the structures, properties, and reactivity of carbonyl oxide and dioxirane. The investigation of these compounds is important for gaining insights into their potential applications in various chemical processes and reactions.

Overall, the article by Cremer, Gauss, Kraka, Stanton, and Bartlett provides valuable information about the theoretical investigation of carbonyl oxide and dioxirane, shedding light on their characteristics and behavior at the molecular level.

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Answer:

CH³–C=CH——CH³–CH=CH²

Explanation:

THIS IS PROPYNE TO PROPENE

Answer:

k(+)

NH4(+)

Al3(+)

Explanation:

cations are those elements who donate their electrons and we put a positive charge on it and receivers get negative charge and they are called anion.....Thank you so,much Please let me know how you feel and is helps you or not....

The partial pressure of He in the tank, given that the tank contains 1.47 mole of O₂ and 5.53 moles of He is 9.56 atm

To obatin the partial pressure of He in the tank, we'll begin by obtaining the mole fraction of He in the tank. This is illustrated below:

Mole fraction of He = Mole of He / total mole

Mole fraction of He = 5.53 / 7

Mole fraction of He = 0.79

Finally, we shall determne the partial pressure of He in the tank. Details below

Partial pressure of He = mole fraction of He × total pressure

Partial pressure of He = 0.79 × 12.1

Partial pressure of He = 9.56 atm

Thus, we can conclude that the partial pressure of He is 9.56 atm

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When 101 grams of copper is used to form copper (II) oxide according to the equation 2Cu + \(O_2\) → 2CuO, approximately 1.85 miles of copper (II) oxide will be formed. To determine the amount of copper (II) oxide formed, we need to calculate the number of moles of copper used and then use the stoichiometry of the balanced equation to find the number of moles of copper (II) oxide produced.

Finally, we can convert the moles of copper (II) oxide to grams and then to miles.

First, we calculate the number of moles of copper used. The molar mass of copper (Cu) is 63.55 g/mol. Therefore, the number of moles of copper used can be calculated as follows:

\(\[\text{Moles of Cu} = \frac{\text{Mass of Cu}}{\text{Molar mass of Cu}} = \frac{101 \, \text{g}}{63.55 \, \text{g/mol}} \approx 1.59 \, \text{mol}\]\)

According to the balanced equation, 2 moles of copper react to form 2 moles of copper (II) oxide. Therefore, the number of moles of copper (II) oxide formed is also 1.59 mol.

Next, we convert the moles of copper (II) oxide to grams. The molar mass of copper (II) oxide (CuO) is 79.55 g/mol. Thus, the mass of copper (II) oxide can be calculated as follows:

\(\[\text{Mass of CuO} = \text{Moles of CuO} \times \text{Molar mass of CuO} = 1.59 \, \text{mol} \times 79.55 \, \text{g/mol} \approx 126.44 \, \text{g}\]\)

Finally, we convert the mass of copper (II) oxide to miles. Assuming an average diameter of 0.1 inches for a copper (II) oxide wire, we can calculate the length in miles using the equation:

\(\[\text{Length (miles)} = \frac{\text{Mass (g)}}{\text{Density (g/cm}^3\text{)}} \times \frac{1 \, \text{cm}^3}{0.1 \, \text{in} \times 2.54 \, \text{cm/in}} \times \frac{1 \, \text{ft}}{12 \, \text{in}} \times \frac{1 \, \text{mi}}{5280 \, \text{ft}}\]\)

The density of copper (II) oxide is approximately 6.31 g/cm³. Substituting the values, we find:

\(\[\text{Length (miles)} = \frac{126.44 \, \text{g}}{6.31 \, \text{g/cm}^3} \times \frac{1 \, \text{cm}^3}{0.1 \, \text{in} \times 2.54 \, \text{cm/in}} \times \frac{1 \, \text{ft}}{12 \, \text{in}} \times \frac{1 \, \text{mi}}{5280 \, \text{ft}} \approx 1.85 \, \text{miles}\]\)

Therefore, approximately 1.85 miles of copper (II) oxide will be formed when 101 grams of copper is used.

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Two different beakers A and B with the same single-replacement reaction are being run at two different temperatures. The first beaker is heated to 75°C and the second beaker is heated to 100°C.

For a chemical reaction, temperature is a crucial factor. The speed of a chemical reaction increases with temperature. As a result, we can assume that the reaction in Beaker B will proceed more quickly than the reaction in Beaker A, resulting in more product formation.

As a result, we may anticipate that the product in Beaker B will be more in quantity than in Beaker A. We can assume that the reaction in Beaker B will proceed more quickly than the reaction in Beaker A, resulting in more product formation.

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Answer:

thanks for the pointthanks for the pointthanks for the point

Explanation:

Answer:

Explanation:

Titration: titrate twice, the first time with an indicator to determine how much sodium hydroxide is needed to completely react with hydrochloric acid, and the second time without an indicator to prevent the contamination of the sodium chloride salt produced

Answer:

Glass A has a greater mass than glass B

Answer:

Glass A has a greater mass than Glass B

hope this helped :>

The compound is named 2,3-dibromo-2,4-hexadienedioic acid, which consists of a six-membered ring with alternating single and double bonds.

The line-angle formula describes a six-membered ring with alternating single and double bonds. To name the compound, we need to consider the functional groups and substituents present.

The carboxylic acid group, -COOH, is attached to the first vertex of the ring. This group is named as "hexanedioic acid" because it contains six carbon atoms in a linear chain. The prefix "hexa-" indicates the presence of six carbons, and the suffix "-dioic acid" denotes the presence of two carboxylic acid groups.

The bromine atom, represented by "Br," is attached to the third vertex in a clockwise direction. Since there are two bromine atoms present, the prefix "di-" is used. Thus, the compound is named "dibromo-hexanedioic acid."

To specify the positions of the bromine atoms, we start numbering the ring from the vertex where the carboxylic acid group is attached, which is the first vertex. Moving clockwise, the second vertex has a double bond, the third vertex has a bromine atom, and the fourth vertex has a double bond. Therefore, the compound is named as "2,3-dibromo-2,4-hexadienedioic acid." The numbers indicate the positions of the substituents in the ring.

In summary, the compound is named 2,3-dibromo-2,4-hexadienedioic acid, which represents a six-membered ring with alternating single and double bonds, a carboxylic acid group attached to the first vertex, and a bromine atom attached to the third vertex in a clockwise direction.

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To make a 0.250 m potassium sulfide solution using 15.8 grams of potassium sulfide, you should add 250 mL of water. To calculate this, use the formula:

Molarity (M) = moles of solute / liters of solution

Given that molar mass of potassium sulfide is 110.23 g/mol, the amount of moles of potassium sulfide is 15.8 g / 110.23 g/mol = 0.1432 mol.

Then, the liters of solution is 0.250 M x liters of solution = 0.1432 mol, so liters of solution = 0.1432 mol / 0.250 M = 0.5728 L

Therefore, you should add 0.5728 L x 1000 mL/L = 572.8 mL of water.

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