What is the value of x if 3x+2=8?
F. -2
G. 0
H. 2
J. 6

The type of variable for,

a. The number of counties in California: Quantitative discrete.

b. The stages of childhood: Qualitative ordinal.

c. In the scenario above, 23 minutes is a statistic, because 28 students is a sample.

d. Between 6 minutes and 8 minutes: Approximately 68% of the athlete's mile times are expected to be between 6 and 8 minutes, according to the empirical rule.

e. Between 4 minutes and 7 minutes: Approximately 68% of the athlete's mile times are expected to be between 4 and 10 minutes, according to the empirical rule.

f. Less than 9 minutes: Approximately 84% of the athlete's mile times are expected to be less than 9 minutes, according to the empirical rule.

In statistics, variables can be categorized into two types: qualitative and quantitative.

Qualitative variables describe characteristics or qualities that cannot be measured numerically, such as gender or hair color.

Quantitative variables, on the other hand, represent numerical values that can be measured or counted.

There are two types of quantitative variables: continuous and discrete. Continuous variables can take any numerical value within a range, such as age or weight.

Learn more about the type of a variable at

https://brainly.com/question/14501374

#SPJ4

We can see that the statement is not always true for any vectors u and v in V3.

The statement is not always true.

The cross product of vectors u and v in V3 is a vector that is orthogonal to both u and v. That is,

u x v ⊥ u and u x v ⊥ v

However, this does not necessarily mean that (u x v) * u = 0 for all u and v in V3.

For example, let u = <1, 0, 0> and v = <0, 1, 0>. Then,

u x v = <0, 0, 1>

(u x v) * u = <0, 0, 1> * <1, 0, 0> = 0

So in this case, the statement is true. However, consider the vectors u = <1, 1, 0> and v = <0, 1, 1>. Then,

u x v = <1, -1, 1>

(u x v) * u = <1, -1, 1> * <1, 1, 0> = 0

So in this case, the statement is also true. However, if we take the vector u = <1, 0, 0> and v = <0, 0, 1>, then

u x v = <0, 1, 0>

(u x v) * u = <0, 1, 0> * <1, 0, 0> = 0

So in this case, the statement is true as well.

However, if we take the vector u = <1, 1, 1> and v = <0, 1, 0>, then

u x v = <1, 0, 1>

(u x v) * u = <1, 0, 1> * <1, 1, 1> = 2

So in this case, the statement is not true.

Therefore, we can see that the statement is not always true for any vectors u and v in V3.

Learn more about vectors

brainly.com/question/29740341

#SPJ11

Answer:

Answer:

(0,2) + (-6,6) =

Step-by-step explanation:

pls mark me as brainliest

Answer:

look at the picture, i wrote in french but o think yoi could understand

Answer:

90

Step-by-step explanation:

Answer:2.51

Step-by-step explanation:

Answer:

orthocentre

Step-by-step explanation:

A triangle's three altitudes intersect at the orthocentre

For confidence interval: support of the association rule A to B is 0.5 and the confidence of the association rule A to B is 0.5.

For Support and confidence of the association rule A - B

To determine the support and the confidence of the association rule A → B, where A = {1, }, B = {1}, we use the formulas given below:

Support(A → B) = frequency of (A, B) / N

Confidence(A → B) = frequency of (A, B) / frequency of A

where N is the number of transactions in the database.

To find the frequency of (A, B) and the frequency of A.

Thus Frequency of (A, B) = 1

Since there is only one transaction in the database where both A and B occur, the frequency of (A, B) is 1.

Frequency of A = 2

The itemset {1, } occurs in two transactions T₁ and T₂.

Hence, the frequency of A is 2.

Learn more about confidence here:

brainly.com/question/30589291

#SPJ4

Answer:

The 2D Pythagorean theorem can be applied twice to calculate the longest diagonal inside a rectangular prism.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

I HOPE THIS HELPS

Since the other Hexagon has a side length of 6 and a perimeter of 36, when you divide 36 by 6, you get 6. That's also how many sides there are. So then you also multiply the side length of 3 by 6 (sides) and the perimeter you get is 18.

Answer:

8 inches is left in the pool

The mode is the most appropriate measure of center to represent the data in the graph because it reflects the most common value(s) observed in the dataset. In this case, the mode is 3.

The most appropriate measure of center to represent the data in the given line plot is the mode.

The mode is the value or values that occur most frequently in a dataset. In this case, we can observe the frequencies of the data points on the line plot:

There is one dot above 2, 4, 8, and 9.

There are two dots above 6 and 7.

There are three dots above 3.

Based on this information, the mode(s) of the dataset would be the values that have the highest frequency. In this case, the mode is 3 because it appears most frequently with a frequency of three. The other data points have frequencies of one or two.

The mode is particularly appropriate in this scenario because it represents the most common or frequently occurring value(s) in the dataset. It is useful for identifying the central tendency when the data is discrete and there are distinct peaks or clusters.

While the median and mean are also measures of center, they may not be the most appropriate in this case. The median represents the middle value and is useful when the data is ordered. However, the given line plot does not provide an ordered arrangement of the data points. The mean, on the other hand, can be affected by outliers and extreme values, which may not accurately represent the central tendency of the dataset in this scenario.

Therefore, the mode is the most appropriate measure of center to represent the data in the graph because it reflects the most common value(s) observed in the dataset. In this case, the mode is 3.

for such more question on measure of center

https://brainly.com/question/25716982

#SPJ8

Given:

Number of green peas = 475

Number of yellow peas = 193

Let's find the 94% confidence interval to estimate the percentage of yellow peas.

Where:

Total number of peas = 475 + 193 = 668

For the sample proportion, we have:

For a 94% confidence interval, the significance level will be:

1 - 0.94 = 0.06

For the critical value, using the z-table, we have:

Now, to find the 94% confidence interval, apply the formula::

Where:

To find the margin of error E, we have:

Thus, we have:

Hence the confidence interval will be:

Lower limit = 0.2559 ==> 25.59%

Upper limit = 0.3219 ==> 32.19 %

The confidence interval does not contain 0.25, hence we can say that the true results contradicts the expectations.

ANSWER:

The confidence interval does not contain the expectation of 25%, hence, the true results contradicts the expectation.

Answer: Line BC and Line DE

Step-by-step explanation:

In geometry terms, we can say that for any set of two points, we always can find a line that passes through them.

For example, in the image, we can see two lines (but actually we could make more with those points)

We can see a line that connects points B and C, and we can call that line as:

Line BC

We also can see a line that connects the points D and E, we can call this line as:

Line DE

So the two lines are: Line BC and Line DE

Answer:

1. f(n+1) = f(n) + 0.09

2. The correct answer is 403 = x. The student’s error is that she did not cancel out properly the constant by the inverse add ended to find the answer of the variable.

3. B

4. D 34 + 6(25.3)

Given:

Degree of a polynomial = 3

Zeros of the polynomial = 0,5,8

f(10)=17

To find:

The polynomial function.

Solution:

The general form of a polynomial is

\(P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}\)

Where, a is a constant, \(c_1,c_2,...,c_n\) are zeros with multiplicity \(m_1,m_2,...,m_n\) respectively.

Since, 0,5,8 are zeros of the polynomial, therefore, (x-0),(x-5), (x-8) are the factors of required polynomial.

\(f(x)=a(x)(x-5)(x-8)\)           ...(i)

Putting x=10, we get

\(f(10)=a(10)(10-5)(10-8)\)

We have f(10)=17.

\(17=a(10)(5)(2)\)

\(17=a(100)\)

\(\dfrac{17}{100}=a\)

\(0.17=a\)

Putting a=0.17 in (i).

\(f(x)=0.17(x)(x-5)(x-8)\)

Therefore, the required polynomial is \(f(x)=0.17(x)(x-5)(x-8)\).

Answer:

620

Explanation:

When the sample is given, the number of elk are likely to be infected is to be considered as the 620.

Calculation of the number of elk:

Since the population is 7,750.

The random sample is 50.

So here be like

= 620

hence, When the sample is given, the number of elk are likely to be infected is to be considered as the 620.

1.644 gml⁻¹ is is the new volume of the water .

What is density, ?

density = mass/volume

     ρ  = 12.5/7.6

      ρ = 1.644 gml⁻¹

Learn more about density

brainly.com/question/15164682

#SPJ4

Answer:

is there a picture to this? we dont know how many marbles there are or how big the marbles are

Step-by-step explanation:

im guessing that each marble is one inch so sorry if this is wrong.

if its a square box (or cube) it would be 8 by 8 but id.k im sorry for wasting your time, feel free to report me.

The average rate of change of f is less than the average rate of change of g.

What is average rate ?

This expression represents the average rate of change of the function f over the range a≤x≤b is less than or equal to x, and is less than or equal to b:

f(b)−f(a) / b - a

It is the average amount by which the function changed per unit throughout that time period.

Here, in Average rate of change in function g over [-3, 0]

=> a = -3, b = 0

=> f(a) = 5 , f(b) = 14

Average rate of change = (14 - 5) / (0 - (-3))

                                        = 3

​

Now, in Average rate of change in function f over [-3, 0]

=> a = -3, b = 0

=> f(a) = -3, f(b) = 0

Average rate of change = (0 - (-3)) / (0 - (-3))

                                        = 1

Therefore, The average rate of change of f is less than the average rate of change of g.

To read more about Average rate.

https://brainly.com/question/26425956

#SPJ13

The diagonal matrix A' for T relative to the basis \(\(B'\)\) is:

\(\[A' = \left[ \begin{array}{ccc} 3 & -4 & 0 \\ -2 & -1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

To find the diagonal matrix A' for the linear transformation T relative to the basis B', we need to perform a change of basis using the given matrix A and basis B'.

Let's denote the standard basis as \(\(B = \{(1, 0, 0), (0, 1, 0), (0, 0, 1)\}\).\)

To perform the change of basis, we need to find the matrix P such that P[B'] = B.

We can write the vectors in B' as column vectors:

\(\[B' = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

To find \(P\), we solve the equation P[B'] = B for P:

\(\[P \cdot B' = B\]\\\\\P = B \cdot (B')^{-1}\]\)

Calculating the inverse of \(\(B'\)\):

\(\[B'^{-1} = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]^{-1} = \left[ \begin{array}{ccc} -1 & 1 & 0 \\ \frac{1}{2} & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Now we can calculate \(\(P\)\):

\(\[P = B \cdot B'^{-1} = \left[ \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right] \cdot \left[ \begin{array}{ccc} -1 & 1 & 0 \\ \frac{1}{2} & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right] = \left[ \begin{array}{ccc} -1 & 1 & 0 \\ \frac{1}{2} & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Now, the diagonal matrix A' for T relative to the basis B' can be calculated as:

\(\[A' = P^{-1} \cdot A \cdot P\]\)

Calculating\(\(P^{-1}\):\)

\(\[P^{-1} = \left[ \begin{array}{ccc} -1 & 1 & 0 \\ \frac{1}{2} & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right]^{-1} = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Substituting the values into the equation for \(\(A'\)\):

\(\[A' = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]^{-1} \cdot \left[ \begin{array}{ccc} -1 & -2 & 0 \\ -1 & 0 & 0 \\ 0 & 0 & 1 \end{array} \right] \cdot \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Performing the matrix multiplication:

\(\[A' = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right] \cdot \left[ \begin{array}{ccc} -1 & -2 & 0 \\ -1 & 0 & 0 \\ 0 & 0 & 1 \end{array} \right] \cdot \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Calculating the matrix multiplication, we get:

\(\[A' = \left[ \begin{array}{ccc} 3 & -4 & 0 \\ -2 & -1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Therefore, the diagonal matrix A' for T relative to the basis B' is:

\(\[A' = \left[ \begin{array}{ccc} 3 & -4 & 0 \\ -2 & -1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Learn more about matrix at https://brainly.com/question/1279486

#SPJ4

Answer:

10

Step-by-step explanation:

t= 24-14 = 10

Do the opposite of the question to get the answer

The definite integral that represents the area of the region enclosed by the polar curve r = 1 sin θ is ∫[a, b] 1/2 r^2 dθ

To determine the definite integral that represents the area of the region, we integrate the expression 1/2 r^2 with respect to θ over the interval [a, b], where a and b are the limits of the region.

In this case, the polar curve r = 1 sin θ represents a circle with radius 1 centered at the origin. As θ varies from 0 to π, the curve traces half of the circle in the positive direction. To find the area of the region enclosed by this curve, we integrate the expression 1/2 r^2 over this interval.

The expression 1/2 r^2 represents the area of a sector of the circle with radius r and central angle θ. Integrating this expression with respect to θ gives us the total area enclosed by the curve.

By evaluating the definite integral over the interval [a, b], we can find the area of the region enclosed by the polar curve r = 1 sin θ.

To know more about area click here

brainly.com/question/13194650

#SPJ11

The area of cardboard needed to make a box with dimensions 25 cm x 15 cm x 8 cm is 1390 cm².

To find the surface area of the box, we first need to determine the area of each individual side and then sum them up. The box has six sides: a top, a bottom, a front, a back, a left side, and a right side. Let's calculate the area of each side.

The area of the top and bottom sides is equal to the length multiplied by the width. In this case, the dimensions are 25 cm x 15 cm, so the area of each of these sides is:

Area of top/bottom = length x width = 25 cm x 15 cm = 375 cm²

The area of the front and back sides is equal to the length multiplied by the height. In this case, the dimensions are 25 cm x 8 cm, so the area of each of these sides is:

Area of front/back = length x height = 25 cm x 8 cm = 200 cm²

The area of the left and right sides is equal to the width multiplied by the height. In this case, the dimensions are 15 cm x 8 cm, so the area of each of these sides is:

Area of left/right = width x height = 15 cm x 8 cm = 120 cm²

Now, let's sum up the areas of all six sides to find the total surface area of the box:

Total surface area = 2(Area of top/bottom) + 2(Area of front/back) + 2(Area of left/right)

= 2(375 cm²) + 2(200 cm²) + 2(120 cm²)

= 750 cm² + 400 cm² + 240 cm²

= 1390 cm²

To know more about area here

https://brainly.com/question/14994710

#SPJ4

Complete Question:

The area of the cardboard needed to make a box of size 25 cm×15 cm×8 cm will be

Answer:

A,C,D are triangles, B is not.

Step-by-step explanation:

Let 3 sides of a triangle be a,b,c.

A triangle have the sum of 3 angles = 180 degree

and

a-b<c<a+b (similar for a and b)

a. three sides measuring 6 cm, 8 cm, and 10 cm

Satisfied the a-b<c<a+b property -> triangle

b. three angles measuring 40 degrees, 70 degrees, and 65 degrees

Total of 3 angles = 40+70+65 = 175 > 180

-> not triangle

c. three angles measuring 10 degrees, 25 degrees, and 145 degrees

Total of 3 angles = 10+25+145 = 180

-> triangle

d. three sides measuring 9 m, 15 m, and 9 m

Satisfied the a-b<c<a+b property -> triangle

Answer:

C

All triangle must equal 180, 40 + 70 + 65 = 175

Answer:

C. 0

Step-by-step explanation:

0 / 7 = 0 ÷ 7

recall that zero divided by any number is zero

hence 0 ÷ 7 = 0

Step-by-step explanation:

-6s2+12s-8-3s2-8s+6

=-9s2+4s-2

Answer:

second part is

2a^2 + 9ab + (-7b^2)

on edge

Step-by-step explanation:

The number of medium and large pieces of pizza Mr Brown ordered is 3 and 6 respectively.

Let

number of medium pieces = x

number of large pizzas = y

Number of slices in a medium pizza = 6

Number of slices in a large pizza = 8

Total pizzas ordered = 9

Total number of slices = 66

The simultaneous equation can be written as follows;

x + y = 9

6x + 8y = 66

From (1)

x = 9 - y

Substitute into (2)

6x + 8y = 66

6(9 - y) + 8y = 66

54 - 6y + 8y = 66

2y = 66 - 54

2y = 12

divide both sides by 2

y = 12/2

y = 6

Substitute y = 6 into (1)

x + y = 9

x + 6 = 9

x = 9 - 6

x = 3

In conclusion, Mr Brown ordered 3 pieces of medium and 6 pieces of large pizza.

Read more on Simultaneous equation:

https://brainly.com/question/16863577

#SPJ1