Answers
Answer:
39.7 kJ
Explanation:
The kinetic energy formula applies:
KE = (1/2)mv^2 = (1/2)(633.0 kg)(11.2 m/s)^2 = 39,701.76 J
The kinetic energy is about 39.7 kJ.
Related Questions
You are at the edge of a diving board that is 9 meters above the water. If you weigh 500 Newtons, what is your potential energy?
Answers
Answer:
4500 J
Explanation:
First, let's define some equations and derivations.
Our potential energy formula is:
\(\displaystyle U = mgh\)Where m is mass (in kg), g is the gravitational constant (in m/s²), and h is height (in m).
We also know that mg is equal to the weight of an object (in N), from Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration).
Therefore, we can simply substitute force into the equation:
\(\displaystyle U = Fh\)Where F is the force (in N) and h is still height (in m).
Now we can calculate the amount of potential energy in our system, measured in joules.
Substitute in the given variables, F = 500 N and h = 9 m:
\(\displaystyle U = (500 \ N)(9 \ m)\)Using simple Pre-Algebra rules, we find that:
\(\displaystyle U = 4500 \ J\)This tells us that the we have 4500 joules of potential energy when I am 9 meters above the water on the edge of the diving board.
Answer:
4500 J
Explanation:
First, let's define some equations and derivations.
Our potential energy formula is:
Where m is mass (in kg), g is the gravitational constant (in m/s²), and h is height (in m).
We also know that mg is equal to the weight of an object (in N), from Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration).
Therefore, we can simply substitute force into the equation:
Where F is the force (in N) and h is still height (in m).
Now we can calculate the amount of potential energy in our system, measured in joules.
Substitute in the given variables, F = 500 N and h = 9 m:
Using simple Pre-Algebra rules, we find that:
This tells us that the we have 4500 joules of potential energy when I am 9 meters above the water on the edge of the diving board.
A runner begins a race from the starting line and accelerates to a speed of 8.9 m/s. If it takes the runner 3 seconds to reach his maximum speed, what was his acceleration?
Answers
Answer:
it will be 8.9 over 3 m/s/s or m/s square
Explanation:
acceleration equal to speed over time
An 80- quarterback jumps straight up in the air right before throwing a 0.43- football horizontally at 15 . How fast will he be moving backward just after releasing the ball? Suppose that the quarterback takes 0.30 to return to the ground after throwing the ball. How far d will he move horizontally, assuming his speed is constant?
Answers
Answer:
a)
the quarterback will be moving back at speed of 0.080625 m/s
b)
the distance moved horizontally by the quarterback is 0.0241875 m or 2.41875 cm
Explanation:
Given the data in the question;
a)
How fast will he be moving backward just after releasing the ball?
using conservation of momentum;
m₁v₁ = m₂v₂
v₂ = m₁v₁ / m₂
where m₁ is initial mass ( 0.43 kg )
m₂ is the final mass ( 80 kg )
v₁ is the initial velocity ( 15 m/s )
v₂ is the final velocity
so we substitute
v₂ = ( 0.43 × 15 ) / 80
v₂ = 6.45 / 80
v₂ = 0.080625 m/s
Therefore, the quarterback will be moving back at speed of 0.080625 m/s
b) Suppose that the quarterback takes 0.30 to return to the ground after throwing the ball. How far d will he move horizontally, assuming his speed is constant?
we make use of the relation between time, distance and speed;
s = d/t
d = st
where s is the speed ( 0.080625 m/s )
t is time ( 0.30 s )
so we substitute
d = 0.080625 × 0.30
d = 0.0241875 m or 2.41875 cm
Therefore, the distance moved horizontally by the quarterback is 0.0241875 m or 2.41875 cm
A force of x Newtons is applied at an angle of x degrees above the horizontal to
a mass of x kg which sits on an incline of angle x degrees. The coefficient
of friction between the mass and the incline is x. For a sufficient applied force so
that the mass moves upward , the net force is given by the expression
F_net = F * cos(α + β) - m * g * sin(β) - u * N
Note:
F_net = net force
F = applied force
α = angle of the applied force
β = angle that the mass sits on
m = mass
g = gravity
u = coefficient of friction between the mass and the incline
N = normal force of the object
Determine the expression to find the angle of the applied force (α).
Show all work/steps.
Answers
Hello,
I hope you and your family are doing well!
To find the angle of the applied force (α), you can rearrange the equation for the net force to solve for α. The equation for the net force is:
F_net = F * cos(α + β) - m * g * sin(β) - u * N
To solve for α, you can start by isolating the term containing α. You can do this by subtracting the other terms from both sides of the equation, which gives you:
F_net - F * cos(β) + m * g * sin(β) + u * N = F * cos(α + β)
Then, you can divide both sides of the equation by F * cos(β) to get:
[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α + β)
Next, you can use the identity cos(a + b) = cos(a)cos(b) - sin(a)sin(b) to rewrite the right side of the equation:
[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α)cos(β) - sin(α)sin(β)
Finally, you can rearrange this equation to solve for α:
α = atan2(sin(α) * cos(β) + cos(α) * sin(β), cos(α) * cos(β) - sin(α) * sin(β))
This equation gives the angle of the applied force (α) in terms of the other variables in the equation for the net force.
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Happy Holidays!
TRUE OR FALSE: Increasing the time of impact during a collision increases the force experienced by the object.
Answers
Answer: True
Explanation:
areaAgNO3 + ___Response area_Li →_____Response areaLiNO3 +____Response areaAg
Answers
Answer:
1 is 3 -1
Explanation:
yan po ang tamang sagot thank you four gave thise answer thise if iam rong sorry i dont gate thinking
How many oxygen atom has protein
Answers
Answer:
1 or 2
Explanation:
Compared to RNA and DNA backbone, protein backbone has a relatively simple chemical structure - a nitrogen atom, two carbon atoms, one or two oxygen atoms, and a few hydrogens.
Define the term dimension
Answers
Answer:
Q1. A measurable extent of a particular kind, such as length, breadth, depth, or height.
Q2. A dimensional constant is a physical quantity that has dimensions and has a fixed value. Some of the examples of the dimensional constant are Planck's constant, gravitational constant, and so on.
Q3. Physical quantities which posses dimensions and have variable are called dimensional variables. Examples are length, velocity, and acceleration etc.
Q4. Dimensionless variables are the quantities which doesn't have any dimensions the the value is a variable. Eg: angle = arc/ radius. Dimensions = L/L. = 1. So angle does not have any dimensions and the value can vary.
Q5. Principle of Homogeneity states that dimensions of each of the terms of a dimensional equation on both sides should be the same. This principle is helpful because it helps us convert the units from one form to another.
Q6. Dimensional analysis has been around a long time, Newton called it the "Great principle of Similitude", but the modern form can be traced back to James Clerk Maxwell. It was Maxwell who distinguished mass [A/], length [£], and time [7"] as the independent dimensions from which others could be derived.
Q7. Mass, length, time, temperature, electric current, amount of light, and amount of matter.
Q8. Dimensional analysis is used to convert the value of a physical quantity from one system of units to another system of units. Dimensional analysis is used to represent the nature of physical quantity. The expressions of dimensions can be manipulated as algebraic quantities.
Hope that helps. x
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
Answers
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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A motorcycle rider loses control while making a sharp turn on a wet road through the mountains. Dude skids off the road at 30.7 m/s and lands in the valley, 191 m below the road. How long does it take him to hit the valley floor
Answers
Answer:
The time taken for the rider to hit the valley floor is 6.22 seconds
Explanation:
The formula to be used here is that of speed
Speed = distance ÷ time
where speed is 30.7 m/s and distance is 191 m, time taken to hit the valley floor is the unknown; thus we solve for time (in seconds).
time = distance ÷ speed
time = 191 ÷ 30.7
time = 6.22 secs
The time taken for the rider to hit the valley floor is 6.22 seconds
Confirm that the force field F is conservative in some open connected region containing the points P and Q, and then find the work done by the force field on a particle moving along an arbitrary smooth curve in the region from to P and Q.
F(x,y)= 2xy^3i + 3x^2y^2 j; P(-9,4), Q(10,5)
Answers
Answer:
Explanation:
From the information:
\(F(x,y) = 2xy^3i+3x^2y^2j;P(-9,4), B(10,5)\)
\(W = \int ^{10,5}_{-9,4} f .dn \\ \\ W = \int ^{10,5}_{-9,4} (2xy^3i) + 3x^2y^2j) *(dxi+dyj) \\ \\ f = 2xy^3\ \ ,\ \ g = 3x^2y^2 \\ \\ \dfrac{\partial f}{\partial y} = \dfrac{\partial g}{\partial x} \\ \\ \text{We wil realize that f is conservative; as a result, there is a potential function } \phi ;\\\\ \dfrac{\partial \phi}{dx}= 2xy^3 \\ \\ \phi= \dfrac{2x^2}{2}y^3+f(y) \\ \\ \phi = x^2y^3 + f(y) \\ \\ \dfrac{\partial \phi}{\partial y } = 3x^2y^2 + f'(y) \\ \\\)
\(\dfrac{\partial \phi}{\partial y } = 3x^2y^2 + f'(y) = 3x^2y^2 \\ \\ f'(y) = 0 \\ \ f(y) = k \\ \\ \phi = x^2y^3 + k \\ \\ Recall: \int^{10,5}_{-9,4 } \ F* dn = W = \phi(10,5) - \phi (-9,4) \\ \\ = (10)^2(5)^3 + k - (-9)^2(4)^3 - k \\ \\ = (100*125) - (81*64) \\ \\ = 12500 - 5184 \\ \\ =7316\)
An experiment is set up as follows:
A mass m = 9.4kg is sent down a frictionless ramp with an initial velocity of 2.5m/s. The ramp is 87cm
long and has an angle of 36°above the horizontal. At the bottom of the ramp is a horizontal surface with a
kinetic friction coefficient of μk = 0.27. At the far side of the horizontal surface, 48cm away, is a spring with
k-constant ks = 3,413.7N
m that will be compressed as the mass collides with the spring. The experiment
ends as the spring is fully compressed and the mass is at rest.
Note: The distance that the spring is compressed is in addition to the 48cm.
7) Find the initial energy of the mass. (10pts)
8) How far will the spring compress if there is no surface friction under the spring? (10pts)
9) How far will the spring compress if the surface friction continues under the spring? (20pts)
Answers
(a) The initial energy of the mass is 76.485 J.
(b) The compression of the spring in the absence of friction is 21.2 cm.
(c) The compression of the spring in the presence of friction is 19.4 cm.
Initial energy of the massThe initial energy of the mass is determined as follows;
E = K.E + P.E
E = ¹/₂mv² + mgh
where;
h is the height of the rampE = ¹/₂mv² + mg x Lsinθ
P.E = ¹/₂(9.4)(2.5)² + (9.4)(9.8)(0.87)(sin36)
P.E = 76.485 J
Compression of the spring when there is no surface tensionThe compression of the spring in the absence of friction is calculated as follows;
Ux = E
¹/₂kx² = 76.485
kx² = 2(76.485)
x² = (2 x 76.485)/k
x = √(2 x 76.485)/k
x = √(2 x 76.485 / 3413.7)
x = 0.212 m
x = 21.2 cm
Compression of the spring in presence of frictionThe compression of the spring in the presence of friction is determined by applying the principle of conservation of energy.
E - Fd = Ux
E - μmgd = ¹/₂kx²
76.11 - (0.27 x 9.4 x 9.8 x 0.48) = ¹/₂(3413)x²
64.17 = 1706.5x²
x² = 0.0376
x = √0.0376
x = 0.194
x = 19.4 cm
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define the term work in physics
Answers
Answer:
W = F · x
Work is the product of force and distance
The vector equation listed above can be written
W = F S cos θ where θ is the angle between the force vector and the displacement vector
Which of the following fields can only exist in one direction?
Answers
the figures below represent positively charged particles moving in the same uniform magnetic field. the field is directed from left to right. all of the particles have the same charge and the same speed v. rank these situations according to the magnitudes of the force exerted by the field on the moving charge, from greatest to least.
Answers
1 > 2 > 3, These are the rankings, from largest to least, of the amounts of the force the field applied to the moving charge. Because the images below show positively charged particles.
The total of all forces exerted on an object is referred to as the magnitude of the force. A crucial physics measurement is calculating the magnitudes of forces. Regardless of the direction in which it works, a force's "magnitude" is its "size" or "strength." A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force.
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A man walks 30 m to the west, then 5 m to the east in 45 seconds. What is his average speed?
Answers
The average speed is 0.55 m/s
What was his displacement?Displacement is defined as the change in position of an object.
Mathematically,
D = Initial value - Final Value
D = 30 - 5 = 25m
Now , We have to find the average velocity,
Average velocity is calculated by the formula V = D/t,
where V equals the average velocity, D equals total displacement and t equals total time.
V = D/t
V = 25 m / 45s
V = 0.55 m/s
So , The average speed is o.55 m/s
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Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a magnitude of 305 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s²)? m/s² (b) The electron is initially at rest. What is its speed (in m/s) after 1.10 x 10 s? m/s
Answers
a. The magnitude of the acceleration of the electron is 5.37 x \(10^{11\) m/s².
b. The speed of the electron after 1.10 x \(10^{-10\) s is 0.591 m/s.
(a) To find the magnitude of the acceleration of the electron, we can use Newton's second law of motion:
F = m * a
In this case, the force is due to the electric field, given by:
F = q * E
where
q = charge of the electron
E = magnitude of the electric field.
Given:
The magnitude of the electric field (E) = 305 N/C
Charge of the electron (q) = -1.6 x \(10^{-19\) C (negative since it's an electron)
Substituting the values into the equation for force:
q * E = m * a
(-1.6 x \(10^{-19\) C) * (305 N/C) = (mass of the electron) * a
Rearranging the equation, we can solve for the acceleration (a):
a = (-1.6 x \(10^{-19\) C * 305 N/C) / (mass of the electron)
The mass of an electron is approximately 9.1 x \(10^{-31\) kg.
Plugging in the values, we get:
a = (-1.6 x \(10^{-19\) C * 305 N/C) / (9.1 x \(10^{-31\) kg)
≈ -5.37 x \(10^{11\) m/s²
Therefore, the magnitude of the acceleration of the electron is approximately 5.37 x \(10^{11\) m/s².
(b) To find the speed of the electron after a certain time, we can use the equations of motion. Since the electron starts at rest, its initial velocity (u) is 0 m/s, and we can use the equation:
v = u + at
where
v = final velocity
u = initial velocity
a = acceleration
t = time.
Given:
Acceleration (a) =-5.37 x \(10^{11\) m/s²
Time (t) = 1.10 x \(10^{-10\)s
Plugging in the values, we get:
v = 0 m/s + (-5.37 x \(10^{11\) m/s²) * (1.10 x \(10^{-10\) s)
≈ -5.91 x \(10^{-1\) m/s
The negative sign indicates that the electron is moving in the opposite direction of the electric field.
Therefore, the speed of the electron after 1.10 x \(10^{-10\) s is approximately 0.591 m/s.
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The position
Of a body is described by S= t^3-2t + 5 find v in m/s when t=3s
Answers
To find the velocity at a particular time, we need to take the derivative of the position function with respect to time and then evaluate the result at that time.
The derivative of the position function, S = t^3 - 2t + 5, with respect to time is:
dS/dt = 3t^2 - 2
Therefore, the velocity at t = 3s is:
v = 3 * 3^2 - 2 = 3 * 9 - 2 = 27 - 2 = 25 m/s.
For most of human history, to be fully human has meant to be??
Answers
Answer:
become fully human is to let down the barriers, to open up. And to discover that every person is beautiful. Under all the jobs they're doing, their responsibilities, there is you.
Explanation:
So to be fully human is the development of the heart and the head, and then we can become one.
The sketch below shows cross sections of equipotential surfaces between two charged conductors that are shown in solid grey. Various points on the equipotential surfaces near the conductors are labeled A, B, C, ..., I.
At which of the labeled points will the electric field have the greatest magnitude?
A) G
B) I
C) A
D) H
E) D
Answers
The answer is B) I. The electric field will have the greatest magnitude at point I because it is the closest point to the charged conductors. The closer to the conductors, the greater the electric field magnitude.
What is electric field?Electric field is an invisible force field that surrounds any object that has an electric charge. It is measured in terms of volts per meter (V/m) and is responsible for the attraction or repulsion of two objects with different electric charges. The force of the electric field is determined by the amount of charge on the objects and the distance between them. Any changes in the electric field will cause a corresponding change in the force felt by the objects. Electric fields can be created by moving charges, such as those found in electric currents, or by static charges, such as those found on a charged object. Electric fields are essential for the transmission of electrical signals and are used in many applications, from telecommunications to medical imaging.
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A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically.
Answers
The value of spring constant (k) is 25 N/m.
Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.
To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.
Formula apply
U=mgh
U=1/2kx^2
putting the value of K ,x ,mass and g then
k is 25N/m
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A horizontal spring with a constant of 3000 N/m is compressed 4.0 cm from equilibrium. A 2.0 kg mass is placed on front of the compressed spring and then is released. The object drags on a flat surface with a coefficient of friction equal to .23 and eventually comes to rest. How far from the spring does the mass travel?
Answers
Regarding a spring-mass system's duration, the square root of the mass and the spring constant have opposing correlations. The length of spring will be longer and vice versa as the mass grows. Therefore, the mass influences spring.
What far from the spring does the mass travel?They swing back and forth around a stationary point. Classic examples of this type of vibrating motion are a simple pendulum and a mass on a spring.
Therefore, The use of motion detectors demonstrates that the vibrations of these objects have a sinusoidal nature, even if this is not obvious from plain viewing.
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For a certain experiment, Juan must measure the concentration of a certain substance in a solution over time. He needs to collect a measurement every 0.05 seconds. He then needs to display his data in a graph and place that graph in a text document. Select the best tools to use for this experiment. Check all that apply.
Answers
Answer:
Probeware and computer
Explanation:
Computers are more powerful and better than a graphing calculator for this situation.
are the tools he must use.
A path for the flow of current:A. is called an electrical circuit.B. allows accumulation of excess charge.C. must always have just one branchD. offers no resistance to current at room temperature.
Answers
An electrical circuit is defined as a path for transmitting electric current.
Therefore the answer is A.
Which is the closeness of measured values to an accepted value of data?
O reproducibility
O significance
O accuracy
O precision
Answers
Answer:
O accuracy
Explanation:
Accuracy is the closeness of measured values to an accepted value of data. The accepted value of data is the true value.
The difference between the measured value and the true value is the error.
Precision is the ability to reproduce a given set of readings from an experiment. The nearness of results or measurements to on another is the precision. But the nearness of the measured value to the standard true value is a measure of its accuracy.yes or no
1.the ink of a pen that is used for writing is not a colloid
2.the blood consists of solid particles and plasma are considered a kind of colloid.
Answers
Answer:
1. No, it is a colloid
2. Yes
Explanation:
An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
Answers
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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What is the magnitude of the velocity after it hits the
ground?
9.3 m/s
12 m/s
41 m/s
73 m/s
Answers
Answer: 9.3m/s
Explanation:
Your question isn't complete but let me help out:
A 0.060 kg ball hits the ground with a speed of –32 m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a +55 N force on the ball. What is the magnitude of the velocity after it hits the ground?
We would use Newton's law of motion to solve this which goes thus:
F = ma
f = m(v-u)/t
Cross multiply
ft = m(v-u)
where,
f = 55
t = 45/1000 = 0.045
m = 0.0060
u = -32
v = Unknown
Therefore,
55 × 45/1000 = 0.060(v - -32)
55 × 0.045 = 0.060(v + 32)
2.475 = 0.06(v + 32)
2.475 = 0.06v + 1.92
0.06v = 2.475 - 1.92
0.06v = 0.555
v = 0.555/0.06
v = 9.25m/s
v = 9.3m/s Approximately
Answer:
A.9.3 m/s
Explanation:
A catcher catches a baseball (m = 145 g) traveling at a speed of 42.5 m/s. How much work was done on the baseball to bring it to rest?
Answers
The net work done on the baseball to bring it to rest is -130.953 J or approximately 131 J. The negative sign indicates that the force has been applied opposite to the direction of motion of the baseball.
What is the work-kinetic energy theorem ?The work-kinetic energy theorem states that an object's change in kinetic energy is equivalent to the work that has been done on it.
\(W_{net} = KE_{f} -KE_{i}\)
Here,
\(W_{net}\) = Net work done
\(KE_{f}\) = Final Kinetic Energy
\(KE_{i}\) = Initial Kinetic Energy
We know,
\(KE = \frac{1}{2} mv^{2}\)
Here, m = Mass of the object
v = velocity of the object
Now,
\(W_{net} = KE_{f} -KE_{i}\\W_{net}= \frac{1}{2} mv^{2}_{f} - \frac{1}{2} mv^{2}_{i}\)
Given,
Mass of baseball (m) = 145g = 0.145 kg
Initial velocity (\(v_{i}\)) = 42.5 m/s
Final velocity (\(v_{f}\)) = 0 m/s (since, the baseball comes to rest.)
Inserting these values in the above equation we get,
\(W_{net}= \frac{1}{2} mv^{2}_{f} - \frac{1}{2} mv^{2}_{i}\\ = 0- \frac{1}{2} *0.145*42.5*42.5 \\= -130.953\)
Hence, the net work done on the baseball to bring it to rest is -130.953 J or approximately 131 J.
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