Write an algebraic expression that represents each verbal expression: 6 times a number plus 3
\(\huge \text{Hello there! :)}\)
Answer:
The algebraic expression is as followed:
➛ \(\huge \text{6(n+3)}\)Step-by-step explanation:
Given the following question:
➛ 6 × a number➛6 × n➛plus 3 ➛ equals6(n+3)what is a algebraic expression?It's an equation built up by integers, variables, and many different operations like addition and subtraction.In this case 6 and 3 are the integersn is the variable6 times and + 3 are the operationsAll form together to make a algebraic expression.Hope this Helps! :)If you have any doubts about my answer please let me know.
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Consider the Autoregressive model AR(1) below 1.05+0.9Y+&+1, t=0,1,..., where E1, E2... are independent normal random variables with mean 0 and variance 0.01, (a) Compute the unconditional mean E(Y) a
The unconditional mean E(Y) of the autoregressive model AR(1) is 10.5.
To compute the unconditional mean E(Y) of the autoregressive model AR(1) given by 1.05 + 0.9Y + ε, we can use the property of linearity in expectation and solve for the mean value.
The model can be rewritten as:
Y = (1.05 + ε) / (1 - 0.9)
Since ε follows a normal distribution with mean 0 and variance 0.01, we know that E(ε) = 0.
Using the linearity of expectation, we can compute the unconditional mean E(Y) as follows:
E(Y) = E((1.05 + ε) / (1 - 0.9))
= (1.05 + E(ε)) / (1 - 0.9)
= 1.05 / (1 - 0.9)
= 1.05 / 0.1
= 10.5
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(b) Given the matrix D = k 0 0 3 k² k³ 0 kª k³ kº k k k 0 0 0 k¹⁰ Find all possible value(s) of k if det(D) = 1024."
To find the possible values of k, we need to calculate the determinant of matrix D and set it equal to 1024.
Given matrix D:
D = | k 0 0 |
| 3 k² k³ |
| 0 kª k³ kº |
| k k k |
| 0 0 0 |
| k¹⁰ |
The determinant of D can be calculated by expanding along the first row or the first column. Let's expand along the first row:
det(D) = k(det | k³ k k |
| 0 k³ kº |
| 0 0 k¹⁰ |)
- 0(det | 3 k² k³ |
| 0 kª k³ |
| k k k |)
+ 0(det | 3 k² k³ |
| k k k |
| k k k |)
Simplifying further, we have:
det(D) = k(det | k³ k k |
| 0 k³ kº |
| 0 0 k¹⁰ |)
Now, we can calculate the determinant of the 3x3 submatrix:
det | k³ k k |
| 0 k³ kº |
| 0 0 k¹⁰ |
This determinant can be found by expanding along the first row or the first column. Expanding along the first row gives us:
det = k(k³(kº) - 0(k)) - 0(0(k¹⁰)) = k⁴kº = k⁴+kº
Now, we can set det(D) equal to 1024 and solve for k:
k⁴+kº = 1024
Since we are looking for all possible values of k, we need to solve this equation for k. However, solving this equation may require numerical methods or approximations, as it is a quartic equation.
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what are the coordinates of the x intercept of the graph with the rule y = 6x - 90
Answer: (15 , 0)
Step-by-step explanation:
find x-intercept
give y = 0
0 = 6x - 90
90 = 6x
x = 15
coordinates of the x-intercept is (15 , 0)
please give me a brainliest answer
Use inverse trigonometric measures to find the measure of the indicated angle to the nearest degree.
value of angle in the triangle is 19.5°
Define triangleA triangle is a closed, 2-dimensional geometric shape that consists of three line segments connected end-to-end to form three sides. The three sides of a triangle enclose a region of space, and the interior angles between these sides sum to 180 degrees. The side opposite to the largest angle is the longest side and is called the hypotenuse in a right-angled triangle.
In the given triangle,
Hypotenuse, h=18
Base, p=6
To find value of angle x
Using trigonometric function
Sinx=p/h
Sinx=6/18
x=Sin⁻¹1/3
x=19.47≈19.5°
Hence, value of angle in the triangle is 19.5°
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N is the centriod of triangle. Find XN if XG = 33
Answer:
22
Step-by-step explanation:
The centroid divides a median in two parts that have this ratio = 1/3 and 2/3
In particular the part between the vertex and the centroid is 2/3 of the median.
So we have:
XN = (33 * 2)/3 = 22
Joe's triangle hut is having a sale. All triangles are priced at $0.68
Joe's Bamboo Hut Kitchen and Seafood, Patong: See 5 unbiased reviews of Joe's Bamboo Hut Kitchen and ... Traditional Thai food with an amazing variety including fresh seafood all at an extremely affordable price and .
Suppose that the demand curve in the market for VCRs can be represented by the following demand and supply equation: Qd = 1,000 - 6P = Qs = = 4P The government decides to impose a tax of $30 per unit sold on VCRs. 1. Find the equilibrium quantity with the tax. 2. Find the price paid by buyers 3. Find the price paid by sellers. 4. Illustrate your answer in (a) with a diagram 5. Calculate the Dead Weight Loss due to the tax 6. Calculate the consumer surplus due to the tax.
Demand refers to the quantity of a product or service that buyers are willing and able to purchase at a certain price level. A demand curve is a graphical representation of the relationship between the quantity of a good or service that buyers are willing to purchase at different price levels.
In the market for VCRs, the demand and supply equations are Qd = 1,000 - 6P and Qs = 4P respectively. The government decides to impose a tax of $30 per unit sold on VCRs. This will lead to a shift in the supply curve upwards by $30, resulting in a new equilibrium point.
1. To find the new equilibrium quantity with the tax, we set Qd = Qs + tax. Thus, 1,000 - 6P = 4P + 30. Solving for P, we get P = $105. The equilibrium quantity is therefore Q = 1,000 - 6($105) = 370.
2. The price paid by buyers is the same as the equilibrium price, which is $105.
3. The price paid by sellers is the equilibrium price minus the tax, which is $75.
4. The diagram below illustrates the impact of the tax on the market for VCRs. The original equilibrium point is E0, with a price of $70 and a quantity of 400. With the tax, the new equilibrium point is E1, with a higher price of $105 and a lower quantity of 370. The tax creates a vertical distance between the two equilibrium points, which represents the tax revenue collected by the government.
[Insert Diagram Here]
5. The deadweight loss due to the tax is the reduction in total surplus (consumer surplus + producer surplus) that results from the tax. Using the original equilibrium as a benchmark, the total surplus is (1/2)($70)(400) = $14,000. With the tax, the total surplus is (1/2)($75)(340) = $6,375. Thus, the deadweight loss is $7,625.
6. To calculate the consumer surplus due to the tax, we need to compare the original consumer surplus with the new consumer surplus. Using the original equilibrium as a benchmark, the consumer surplus is (1/2)($70)(400 - 70) = $5,950. With the tax, the consumer surplus is (1/2)($105)(370 - 105) = $12,145. Thus, the consumer surplus due to the tax is $6,195.
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4➗64
4 divided by 64
Answer:
The answer for your problem will be 0.0625
Scores on an test follow an approximately Normal distribution with a mean of 76.4 and a standard deviation of 6.1 points. What is the minimum score you would need to be in the top 5%? 1.645 88.6 66.37 86.43
The minimum score you would need to be in the top 5% is 86.
To find the minimum score you would need to be in the top 5%, we can use the properties of the standard normal distribution. Since the scores on the test follow an approximately normal distribution, we can convert the problem into a standard normal distribution by standardizing the scores.
The z-score formula is given by:
z = (x - μ) / σ
where x is the observed value, μ is the mean, and σ is the standard deviation.
In this case, we want to find the z-score corresponding to the top 5% of the distribution. The z-score associated with the top 5% can be found using a standard normal distribution table or a calculator. The z-score corresponding to the top 5% is approximately 1.645.
Now, we can use the z-score formula to find the minimum score (x) needed to be in the top 5%:
1.645 = (x - 76.4) / 6.1
Solving for x:
x - 76.4 = 1.645 * 6.1
x - 76.4 = 10.0345
x = 86.4345
Rounding to the nearest whole number, the minimum score you would need to be in the top 5% is 86.
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Please Help ASAP! Find X.
The measure of angle x is 70°.
How to find the value of angle x?Here we have the image of some triangles, and we want to find the value of the interior angle x in the left triangle.
What you need to remember here is that the sum of the interior angles of any triangle is always equal to 180°.
Then, for the left triangle, we can write:
30° + 80° + x° = 180°
Now we can solve that equation for x, then we will get:
x° = 180° - 80° - 30°
x = 70°
That is the measure of angle x.
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The probability that a marksman will hit a target each time he shoots is 0. 89. If he fires 15 times, what is the probability that he hits the target at most 13 times?.
Answer:
Step-by-step explanation:
Correct option is A)
Specifications cul for the thickness of steel sheet to average 0.83 mm. A quality control engineer samples 4 steel si from a large batch and measures the thickness of each in mm. The repilts are: It is of interest to determine whether there is evidence to support a claim that the mean thickness is equal to 0.83 mm. Compute the test statistic to perform a hypothesis test. 0.22 2.13 −5.12 −1.11 −139 1.42
The test statistic is -1.459. This value represents how many standard errors the sample mean is away from the hypothesized mean under the null hypothesis.
To perform a hypothesis test to determine whether there is evidence to support a claim that the mean thickness of the steel sheets is equal to 0.83 mm, we need to calculate the test statistic.
The first step is to set up the hypotheses:
Null hypothesis (H₀): The mean thickness of the steel sheets is equal to 0.83 mm.
Alternative hypothesis (H₁): The mean thickness of the steel sheets is not equal to 0.83 mm.
Part 2: Steps to follow:
Calculate the sample mean (x) of the thickness measurements. In this case, the sample mean is the average of the reported thickness measurements: x = (0.22 + 2.13 - 5.12 - 1.11) / 4 = -0.97 mm.
Calculate the sample standard deviation (s) of the thickness measurements. In this case, you can use the sample standard deviation formula: s = sqrt((Σ(x - x)²) / (n - 1)), where x is each individual measurement and n is the sample size. In this case, s ≈ 3.536 mm.
Calculate the standard error (SE), which is the standard deviation of the sample mean. The standard error is calculated by dividing the sample standard deviation by the square root of the sample size: SE = s / sqrt(n) ≈ 3.536 / sqrt(4) = 1.768 mm.
Calculate the test statistic (t-value) using the formula: t = (x - μ₀) / SE, where μ₀ is the hypothesized mean under the null hypothesis. In this case, μ₀ = 0.83 mm. Plugging in the values, we get t ≈ (-0.97 - 0.83) / 1.768 = -1.459.
The test statistic is -1.459. This value represents how many standard errors the sample mean is away from the hypothesized mean under the null hypothesis. It provides a measure of the evidence against the null hypothesis.
Remember to interpret the test statistic in the context of the problem and use it to make a decision regarding the hypotheses.
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Please help with problem ASAP. Thank you!
Find the consumers' surplus at a price level of p = $120 for the price-demand equation below. p=D(x) = 500 -0.05x What is the consumer surplus? $
To find the consumer surplus at a price level of $120 for the price-demand equation p = D(x) = 500 - 0.05x, we need to calculate the area of the region between the demand curve and the price level.
The consumer surplus represents the monetary gain or benefit that consumers receive when purchasing a good at a price lower than their willingness to pay. It is determined by finding the area between the demand curve and the price line up to the quantity demanded at the given price level.
In this case, the demand equation is p = 500 - 0.05x, where p represents the price and x represents the quantity demanded. To find the quantity demanded at a price of $120, we can substitute p = 120 into the demand equation and solve for x. Rearranging the equation, we have 120 = 500 - 0.05x, which yields x = (500 - 120) / 0.05 = 7600.
Next, we integrate the demand curve equation from x = 0 to x = 7600 with respect to x. The integral represents the area under the demand curve, which gives us the consumer surplus. By evaluating the integral and subtracting the cost of the goods purchased at the given price level, we can determine the consumer surplus in dollars.
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writing fractions with common denominators to add or subtract(Aleks)
Answer:
3/5+1/3= 9/15+5/15= 14/15
Step-by-step explanation:
Hi there!
To make fractions have a common denominator, multiply both the numerator and the denominator by a number. In this case, 3/5= 9/15, because both the numerator and denominator are multiplied by 3. 1/3= 5/15, using the same rule. 9/15+5/15=14/15
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Simplify.
8 · 3 · x plzzzzzzzz answer fast
Answer:
24x
Step-by-step explanation:
hope this helps
Help Please!!!!
1) Find the local maximum and minimum values and saddle points of the furction \[ f(x, y)=\left(x^{2}+y\right) e^{y / 2} \] 2) Use Lagrange multipliers to find the maximum and minimum values of \[ f(x
The local maximum and minimum values and saddle points of the function \(f(x, y) = (x^2+ y) * e^{y/2}\)
The partial derivatives of the function with respect to x and y are given by:
\(f_x(x,y) = e^(y/2) * (2x + y + 2x²)y_x(x,y) = e^(y/2) * (1 + y/2 + x)\)
We equate them to zero and get:
\(e^(y/2) * (2x + y + 2x²) = 0\) ...(i)
\(e^(y/2) * (1 + y/2 + x) = 0\) ...(ii)
Equation (i) gives the following three cases:
If \(e^(y/2)\) = 0, then y = - infinity
If 2x + y + 2x² = 0, then y = - 2x - 2x²
Putting y = - 2x - 2x² in equation (ii), we get 0 = \(e^(-x²) * (1 - x)\)
Therefore, the critical points are (0, 0), (1, - 4), and (-1, - 2)
Now we have to use the second derivative test to determine the nature of the critical points.
The second partial derivatives of \(f_x(x,y) = e^(y/2) * (2x + 4)y_x(x,y) = e^(y/2) * (1/2) * (2x + y + 4)\) and
\(f_xx(x,y) = e^(y/2) * 2\\f_xy(x,y) = e^(y/2) * (1/2) * (2x + y + 4)\\f_yy(x,y) = e^(y/2) * (1/4) * (y + 4)\\Therefore,f_xx(0,0) = 2f_xy(0,0) = 0\)
\(f_yy(0,0) = 1\\f_xx(1,-4) = - 8e^{-2}\\f_xy(1,-4) = (1/4)e^{-2}\\f_yy(1,-4) = e^{-2}\)
Therefore, (1,-4) is a local maximum of the function
Similarly, f_xx(-1,-2) = 2f_xy(-1,-2) = 0f_yy(-1,-2) = (1/4)\(f_xx(-1,-2) = 2f_xy(-1,-2) = 0f_yy(-1,-2) = (1/4)\)
Therefore, (-1, -2) is a saddle point of the function.
In conclusion, the critical points of the function are (0,0), (1,-4), and (-1,-2). The second derivative test is applied to find the nature of the critical points. (1,-4) is a local maximum of the function, and (-1,-2) is a saddle point of the function.
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Is the correlation between the heights of husbands and wives in the U.S. around -0.9, -0.3, 0.3, or 0.9? Explain briefly.
The correct correlation between the heights of husbands and wives in the U.S. is around -0.3. The correlation between the heights of husbands and wives in the U.S. is not as strong as some might assume. It is about -0.3.
This is not a strong negative correlation, but it is still a negative one, indicating that as the height of one partner increases, the height of the other partner decreases. This relationship may be seen in married partners of all ages. It's important to note that the correlation may not be consistent among various populations, and it may vary in different places. The correlation between husbands and wives' heights is -0.3, which is a weak negative correlation.
It indicates that as the height of one partner increases, the height of the other partner decreases. When there is a weak negative correlation, the two variables are inversely related. That is, when one variable increases, the other variable decreases, albeit only slightly. The correlation is not consistent across all populations, and it may differ depending on where you are. Nonetheless, when compared to other correlations, such as a correlation of -0.9 or 0.9, the correlation between husbands and wives' heights is a weak negative one.
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When Maria Acosta bought a car 2 1/2 years ago, she borrowed 10,000 for 48 months at 7. 8% compounded monthly. Her monthly payments are 243. 19 but she’d like to pay off the loan early. How much will she owe just after her payment at the 2 1/2 year mark?
Just after her payment at the 2 1/2 year mark, Maria will owe approximately $7,722.63 on her loan.
To calculate the amount Maria will owe just after her payment at the 2 1/2 year mark, we need to determine the remaining balance on her loan.
First, we convert the loan duration to months:
2 1/2 years = 2.5 * 12 = 30 months.
Next, we use the formula for the remaining balance on a loan:
Remaining balance = Principal * (1 + monthly interest rate)^remaining months - Monthly payment * [(1 + monthly interest rate)^remaining months - 1] / monthly interest rate.
Principal = $10,000
Monthly interest rate = 7.8% / 12 = 0.065
Remaining months = 48 - 30 = 18
Plugging in the values, we have:
Remaining balance = $10,000 * (1 + 0.065)^18 - $243.19 * [(1 + 0.065)^18 - 1] / 0.065
Calculating this expression step by step:
Remaining balance = $10,000 * (1.065)^18 - $243.19 * [(1.065)^18 - 1] / 0.065
≈ $7,722.63
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I need help with this. Please don't rush and take your time.
Answer:
The correct answer is B.
A bank loan processing system has three components with individual reliabilities as shown: R 1 = 0.82 R 2 = 0.991 R 3 = 0.98 What would be the reliability of the bank system above if each of the three components had a backup with a reliability of 0.80? How would the total reliability be different?
To calculate the reliability of the bank loan processing system with backup components, we can use the concept of series-parallel system reliability.
In the original system, the three components are connected in series. To calculate the overall reliability of the system, we multiply the reliabilities of the individual components:
R_system = R_1 * R_2 * R_3 = 0.82 * 0.991 * 0.98 ≈ 0.801
So, the reliability of the bank loan processing system without backup components is approximately 0.801.
Now, if each of the three components has a backup with a reliability of 0.80, we have a parallel configuration between the original components and their backups. In a parallel system, the overall reliability is calculated as 1 minus the product of the complement of individual reliabilities.
Let's calculate the reliability of each component with the backup:
R_1_with_backup = 1 - (1 - R_1) * (1 - 0.80) = 1 - (1 - 0.82) * (1 - 0.80) ≈ 0.984
R_2_with_backup = 1 - (1 - R_2) * (1 - 0.80) = 1 - (1 - 0.991) * (1 - 0.80) ≈ 0.9988
R_3_with_backup = 1 - (1 - R_3) * (1 - 0.80) = 1 - (1 - 0.98) * (1 - 0.80) ≈ 0.9992
Now, we calculate the overall reliability of the system with the backups:
R_system_with_backup = R_1_with_backup * R_2_with_backup * R_3_with_backup ≈ 0.984 * 0.9988 * 0.9992 ≈ 0.981
Therefore, the reliability of the bank loan processing system with backup components is approximately 0.981.
Comparing the two scenarios, we can see that introducing backup components with a reliability of 0.80 has improved the overall reliability of the system. The total reliability increased from 0.801 (without backups) to 0.981 (with backups). Having backup components in a parallel configuration provides redundancy and increases the system's ability to withstand failures, resulting in higher reliability.
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Someone help and plz make sure it’s right
Answer:
80 degree angle is the right answer
can anyone help ? No links please worth a lot of points! I also need a explaination and the answer for Z
Answer:
11.66
Step-by-step explanation:
10^2 + 6^2 = Z^2
100 + 36 = Z^2
136 = Z^2
sqrt(136) = Z
sqrt 136 = 11.66
Explain the errors in the process. Then correct the errors, and solve the equation
The quadratic equation is solved as;
2x² + 5x - 12 = 0
2x² + 8x - 3x - 12 = 0
2x(x + 4) - 3(x + 4) = 0
x: -4 and 3/2
How to determine the processFrom the information given, we have that the quadratic equation is;
2x² + 5x = 12
Equate the quadratic equation to zero, we have;
2x² + 5x - 12 = 0
Now, find the product of the coefficient of x² and -12. Then, find the pair factors of the value that sum up to 5, we have;
-8 and 3
Substitute the values
2x² + 8x - 3x - 12 = 0
Factorize the expressions in pairs, we get;
2x(x + 4) - 3(x + 4) = 0
Then, we have;
2x - 3 = 0
x = 3/2
and
x + 4 = 0
x = -4
x: -4 and 3/2
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4. John is packing books into boxes. Each box can hold either 15 small books or 8
large books. He needs to pack at least 35 boxes and at least 350 books, Write a
system of linear inequalities to represent the situation
Answer:
Your system of inequalities is:
x + y ≥ 35
15x + 8y ≥ 350
Step-by-step explanation:
Let x = number of boxes of small books and let y = number of boxes of large books.
Since John needs to pack at least 35 boxes:
(number of boxes of small books) + (number of boxes of large books) (is at least) 35
x + y ≥ 35
Since John needs to pack at least 350 books:
(number of small books packed) + (number of large books packed) (is at least) 350
(number of small books per box)(number of boxes of small books) + (number of large books per box)(number of boxes of small books) ≥ 350
15x + 8y ≥ 350
suppose that the value of a stock varies each day from $8.82 to $16.17 with a uniform distribution. find the third quartile, i.e., 75% of all days the stock is below what value?
The third quartile is $10.6575, which means that 75% of all days the stock is below this value.
The range of the stock price is from $8.82 to $16.17, and the distribution is uniform, which means that the probability of the stock price being any value between the minimum and maximum is the same.
To find the third quartile, we need to find the value x such that 75% of the observations are less than or equal to x, and 25% of the observations are greater than or equal to x.
Since the distribution is uniform, we can find x by finding the value that separates the bottom 25% of the distribution from the top 75% of the distribution.
The bottom 25% of the distribution spans from $8.82 to some value x. Since the distribution is uniform, we can find x by setting the probability of the stock price being less than or equal to x to 0.25, which gives:
(x - 8.82) / (16.17 - 8.82) = 0.25
Solving for x, we get:
x - 8.82 = 0.25 * (16.17 - 8.82)
x - 8.82 = 1.8375
x = 10.6575
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Find the volume of the triangular prism
Answer:
V = 22
Step-by-step explanation:
V= 1/2 b*h*l
V= 0.5 * 4 * 3 * 11
V= 22
An ordered pair is a(n) ________ of an equation in two variables if replacing the variables by the coordinates of the ordered pair results in a true statement.
An ordered pair is a solution of an equation in two variables if replacing the variables by the coordinates of the ordered pair results in a true statement.
In mathematics, an equation in two variables represents a relationship between two quantities. An ordered pair consists of two values, typically denoted as (x, y), that represent the coordinates of a point in a two-dimensional plane.
When these values are substituted into the equation, if the equation holds true, then the ordered pair is considered a solution or a solution set to the equation. This means that the relationship described by the equation is satisfied by the values of the ordered pair. In other words, the equation is true when evaluated with the values of the ordered pair.
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do you need to perform a post hoc on an anova that has three levels and has significant findings for that factor?
Yes, a post hoc test should be performed after an ANOVA with three or more levels if the ANOVA finds a significant result.
Post hoc tests are used to determine which specific levels within the factor are responsible for the significant result.
1. An ANOVA is performed to test if there is a significant difference between the means of three or more levels of a factor.
2. If the ANOVA finds a significant result, then a post hoc test should be performed to determine which specific levels within the factor are responsible for the significant result.
3. Post hoc tests compare the means of each level of the factor to determine which levels are significantly different from each other and which are not.
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If trapezoid
EFGH is
reflected over
the x-axis, what
will be the
coordinates of
the new image?
Answer:
e (2,-1)
f (4,-1)
g (5,-4)
h (1,-4)