Bond formed when electrons are shared between atoms.

Option D. The result of a chemical change is a different chemical composition, In a physical change the chemical composition remain the same.

A chemical change happens when one chemical substance is transformed into one or more special materials, which includes when iron will become rust. Chemical changes occur thru the system of chemical reactions, and the resulting materials have extraordinary houses because their atoms and molecules are arranged in a different ways.

Physical changes are adjustments affecting the shape of a chemical substance, but not its chemical composition. physical modifications are used to split combos into their factor compounds, however, can not generally be used to separate compounds into chemical factors or less difficult compounds

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The answer is the result of a chemical change is different chemical composition, in physical change the chemical composition remains the same.

Physical change is a temporary change. A chemical change is a permanent change. A physical change impacts simplest bodily residences i.e. shape, size, etc. Chemical change each physical and chemical residences of the substance including its composition. A bodily change entails very little to no absorption of electricity.

A chemical change is a trade of materials into another, new materials with distinctive properties and one or a couple of new materials are fashioned. It outcomes when a substance combines with another to form a new substance.

Changes in the length or shape of count are examples of physical change. Physical changes include transitions from one nation to every other, consisting of from strong to liquid or liquid to gasoline. Cutting, bending, dissolving, freezing, boiling, and melting are a number of the tactics that create physical adjustments.

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The volume occupied by a 21.8 g sample of osmium is approximately \(0.964 cm^3\).

The volume (in \(cm^3\)) occupied by a 21.8 g sample of osmium can be calculated using its density of \(22.6 g/cm^3\).

To find the volume, we can use the formula:

Volume = Mass / Density.

Plugging in the values, we have:

Volume = 21.8 g / \(22.6 g/cm^3\)

Now, dividing 21.8 g by \(22.6 g/cm^3\) gives us the volume in cm^3.

Calculating this, we get:

Volume = \(0.964 cm^3\)

So, a 21.8 g sample of osmium would occupy a volume of approximately \(0.964 cm^3\)

In conclusion, the volume occupied by a 21.8 g sample of osmium is approximately \(0.964 cm^3\)

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1) Groups of elements in the periodic table.

On the left, there are several types of metals and on the right, there are nonmetals, halogens, and noble gases.

There is a group that is between those mentioned above, the semi-metals also known as Metalloids.

.

Answer:

mu answer is A

Explanation:

i think it is a popular opinion because its the opinion of a country

The quantity (moles) of naoh must be added to 1.0 l of 2.0 m hc2h3o2 to produce a solution buffered at each pH is determined by the calculations given below.

To determine the quantity (moles) of NaOH that must be added to 1.0 L of 2.0 M HC2H3O2 to produce a solution buffered at each pH, we can use the Henderson-Hasselbalch equation. Here are the steps to follow:

1. Write down the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA])

2. Determine the pKa of HC2H3O2 (acetic acid). Acetic acid has a pKa value of 4.74.

3. Plug in the desired pH value and the pKa value into the equation:
  pH = 4.74 + log([A-]/[HA])

4. Solve for the ratio [A-]/[HA] using the given pH value:
  [A-]/[HA] = 10^(pH - 4.74)

5. Calculate the initial moles of acetic acid (HA) in the solution:
  Moles of HA = 2.0 M * 1.0 L = 2.0 moles

6. Calculate the moles of A- (acetate) and NaOH required:
  Moles of A- = ([A-]/[HA]) * moles of HA
  Moles of NaOH = moles of A- (since NaOH reacts with acetic acid in a 1:1 ratio)

By following these steps, you can determine the quantity (moles) of NaOH needed to be added to 1.0 L of 2.0 M HC2H3O2 to produce a solution buffered at a specific pH value.

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The proton NMR confirms that there are 2 different proton habitats. The downfield septet signal shows that there are 6 equivalent nearby hydrogens for one type of hydrogen. 2  hydrogen atoms are represented by the downfield signal. The upfield signal appears as a doublet because it relates two hydrogens that each have one neighbor. 12 hydrogens are represented by the upfield signal.

The nuclei of some atoms start to act like tiny magnets when molecules are exposed to a strong magnetic field. If the sample is exposed to a wide range of radio frequency waves, the nuclei will start to vibrate at their own distinct frequencies.

Spectra of proton-decoupled ions

A proton-decoupled NMR spectrum is the name given to the resulting spectrum. A high-intensity radio frequency source that can detect protons is utilized to irradiate the sample while the spectrum of 13C is being acquired over at one magnetic field strength and frequency.

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A magnesium ribbon is cleaned to remove the protective layer of basic magnesium carbonate from its surface, so that it may readily combine with the oxygen in air (on heating).

Answer:

Magnesium gets covered with a layer of magnesium oxide when kept in air for a long time. This layer hinders the burning of magnesium. Hence, it is to be cleaned before burning.

Answer:

It can’t displace any more than its volume, assuming there is no external force pushing downwards.

To determine the enthalpy change in a coffee cup calorimetry experiment, the following data or information is needed: initial and final temperatures (T1, T2), heat capacity of the calorimeter (Cp), and mass of the reaction mixture (m), and the equation used is ΔH = Cp * (T2 - T1) * m.

In a coffee cup calorimetry experiment, the following data or information is needed to determine the enthalpy change for a reaction:

The initial temperature of the reaction mixture (T1) and the final temperature after reaction (T2).

The heat capacity of the calorimeter, usually represented by "Cp".

The mass of the reaction mixture.

The equation used to calculate the enthalpy change (ΔH) in a coffee cup calorimetry experiment is given by:

ΔH = q = Cp * (T2 - T1) * m

where q is the heat gained or lost by the reaction mixture, m is the mass of the reaction mixture, Cp is the heat capacity of the calorimeter, T2 is the final temperature of the reaction mixture, and T1 is the initial temperature of the reaction mixture.

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The balloon inflated indoors after deflating outdoors in the chilly winter weather due to Charles law.

A rule that says the volume of a perfect gas at constant pressure is inversely correlated with the absolute temperature.

The balloon contracts as a result of the helium becoming denser than before as the temperature drops. In order to preserve heat, the helium molecules lose energy, slow down, and migrate closer together. As a result, the volume within the balloon reduces since they are moving closer together rather than outward toward the balloon's shell, which would cause the balloon to expand and subsequently contract. The Charles law is the gas law that makes this happen.

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Answer:

23 43 45 43

Explanation:

During glycolysis NAD reduces to form NADH and H⁺. Generally, reduction is gain of electrons and thus gaining of negative charge. The atom is said to be reduced when it acquire electrons.

Glycolysis is defined as a process in which glucose (sugar) is partially broken down by cells in enzyme reactions that do not need oxygen. Cells use one of the method to produce energy known as glycolysis.

Nicotinamide adenine dinucleotide (NAD+) is one of the important molecule used in the process of glycolysis. It is a cofactor which usually regulates metabolism through its electron transport function in the redox reaction in glycolysis and the TCA cycle, In glycolysis, NAD+ reduces forming NADH and H⁺.

NAD reduces to form NADH and H⁺ during glycolysis, so it gains electrons during the process.

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The slowest step in a reaction mechanism is known as the rate-determining step. The rate-determining step limits the overall rate and therefore determines the rate law for the overall reaction.

Overall reaction equation:

2NO (g) + O2(g) ---------> 2NO2(g)

Overall rate= k1 [NO]^2

Overall reaction equation:

2NO (g) + O2(g) ---------> 2NO2(g)

The overall reaction equation is obtained by adding the two equations. This now gives the actual overall equations when intermediates must have been cancelled out.

Since k1<<k2 which me as that the first step is much slower than the second step, then the first step is the rate determining step, being the slowest step in the non elementary reaction sequence.

Therefore overall rate;

Overall rate= k1 [NO]^2

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The structure that best fits the given data is 1,4-dibromobenzene.

The presence of two methyl singlets in the proton NMR spectrum indicates the presence of two methyl groups in the compound. This suggests the presence of a substituent attached to the benzene ring.

The proton-decoupled 13C NMR spectrum displays six peaks, indicating the presence of six distinct carbon environments. In 1,4-dibromobenzene, there are two carbon atoms attached to the methyl groups, which gives two peaks. The benzene ring itself has four unique carbon environments, each with a different chemical shift, resulting in four additional peaks.

The structure of 1,4-dibromobenzene matches the data because it contains two methyl groups and displays a total of six peaks in the proton-decoupled 13C NMR spectrum, consistent with the given information.

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Answer:

1. burial

2. Choice

3. pleasure

Explanation:

Mark brainliest! Please!

The proper way to bring the temperature on lab thermometers down is to shake the thermometer to lower the temperature.

Swing the thermometer back and forth by grabbing it at the end farthest from the tip.

Make sure it falls below the average body temperature, which is 96.8 °F (36.0 °C), at the very least.

This way you have successfully lowered the temperature of the thermometer as it is now below the body temperature of a human, on the average.

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If 4.00 mL of vinegar needs 43.5 mL of 0.150 m NaOH  to reach the equivalence point in a titration, The grams of the acetic acid is 119.9 g.

Given that :

The molarity of NaOH = 0.150 M

The volume of NaOH = 43.5 mL = 0.0435 L

The moles = molarity × volume

                 = 0.150 × 0.0435

                 = 0.0065 mol

At equivalence point ,

Moles of CH₃COOH = moles of NaOH

The molarity of the CH₃COOH = moles / volume

                                                   = 0.0065 / 0.004

                                                   = 1.625 mol

Volume of  CH₃COOH = 1.50 × 0.946353

                                     = 1.230 L

The mass of the Acetic acid = 1.625 × 1.230 × 60

                                               = 119.9 g

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mass of helium = 18.6 g. To answer this question, we can use the ideal gas law, which relates the pressure, volume, temperature, and amount of a gas.

According to 1, the ideal gas law is often written as:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the ideal gas constant and T is the temperature of the gas.

We are given the values of P, V and T, and we need to find n. We can rearrange the equation to solve for n:

n = PV/RT

We also need to make sure that we use consistent units for P, V, T and R. According to 2, if we use R = 8.31 J/K/mol, then we must use P in pascals (Pa), V in cubic meters (m³), and T in kelvins (K).

We can convert the given values to these units as follows:

P = 1.89 x 10³ kPa x 10³ Pa/kPa = 1.89 x 10⁶ Pa

V = 685 L x 10⁻³ m³/L = 0.685 m³

T = 62°C + 273.15 = 335.15 K Plugging these values into the equation for n, we get:

n = (1.89 x 10⁶ Pa) x (0.685 m³) / (8.31 J/K/mol) / (335.15 K)

n = 4.64 mol

To find the mass of helium in grams, we need to multiply n by the molar mass of helium, which is 4 g/mol according to 3. Therefore,

mass of helium = 4.64 mol x 4 g/mol = 18.6 g

Rounding to three significant digits, we get:

mass of helium = 18.6 g

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Answer

4.76 mol Fe

Procedure

Consider the following balanced equation and determine the limiting reagent using the coefficients method

2Al(s) + Fe₂O3(aq)--> Al2O3(aq) + 2Fe(s)

The lowest amount is the one produced by the iron (III) oxide therefore that is the limiting reagent and 4.76 mol of Fe is the max amount that can be produced of Iron.

Answer:

0.086J/g°C

Explanation:

The following data were obtained from the question:

Mass (M) = 30g

Initial temperature (T1) = 10°C

Final temperature (T2) = 45°C

Change in temperature (ΔT) = T2 – T1 = 45°C – 10°C = 35°C

Heat (Q) released = 90J

Specific heat capacity (C) of wood =..?

We can obtain the specific heat capacity of the wood as follow:

Q = MCΔT

90 = 30 x C x 35

Divide both side by 30 x 35

C = 90/(30 x 35)

C = 0.086J/g°C.

Therefore, the specific heat capacity of the wood is 0.086J/g°C.

The molality or the molal concentration of acetic acid is 0.796 molal.

The molarity of the solution is 0.763 mol/L

The density of the solution is 1.004 g/mL. Hence, the mass of 1 liter solution is 1004 g

The mass of the solute in 1 Liter 0.763 M acetic acid = 0.763 mol/L * 60 g/mol

The mass of the solute in 0.763 M acetic acid = 45.78 g

Mass of water = 1004 - 45.78 g

Mass of water = 958.22 g or 0.95822 Kg

Molality of solution = 0.763/0.95822

Molality of solution = 0.796 molal

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Option A, BF, does not violate the octet rule, option B, XeO, satisfies the octet rule for all atoms, option C, Ne, is a noble gas and already has a complete octet, and option D, AICI3, has complete octets for both the atoms and does not violate any rules.

The incorrect Lewis structure is likely to be the one that violates the octet rule, has an incomplete octet or has an odd number of electrons.

In the given options, only option E, NH, violates the octet rule. Nitrogen has five valence electrons and each hydrogen has one valence electron. If we draw the Lewis structure for NH, we get three lone pairs on nitrogen and one unpaired electron.

This makes a total of nine valence electrons, which is one more than the total available. Therefore, NH does not follow the octet rule and is the incorrect Lewis structure.

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Answer:

Electrolysis is the process by which ionic substances are decomposed (broken down) into simpler substances when an electric current is passed through them. Electricity is the flow of electrons or ions.

Explanation:

hope it helped:)))))

Answer:

Energy transfer is the movement of energy from one location to another. For example, when electricity moves from a wall plug, through a charger, to a battery.

Explanation:

Hope this helps

Answer:5) super Volcano eruption

Explanation:

Answer:

#1, #2, #4, and #6 are the answers.

Explanation:

#2, #4, and #6 have something to do with radioactivity which is mostly categorized in nuclear reactions, #3 and #5 are partly categorized in thermal reactions while a chemical plant explosion is almost categorized as a chemical bomb; Chemical explosions may be either decomposition or combination reactions. Decomposition reactions occur in materials such as trinitrotoluene (TNT) and nitroglycerine. Combination reactions require that two or more components react together exothermically to produce hot gases. Some examples are ammonium nitrate and fuel oil (ANFO), and gunpowder (potassium nitrate, carbon, and sulfur). In conclusion, #1, #2, #4 and #6 are the answers.

Answer:

The most common example is the molar volume of a gas at STP (Standard Temperature and Pressure), which is equal to 22.4 L for 1 mole of any ideal gas at a temperature equal to 273.15 K and a pressure equal to 1.00 atm.If an ideal gas at a constant temperature is initially at a pressure of 3.8 atm and is then allowed to expand to a volume of 5.6 L and a pressure of 2.1 - 18914… ... of 5.6 L and a pressure of 2.1 atm, what is the initial volume of the gas? ... An ideal gas is at a pressure of 1.4 atm and has a volume of 3 L.

Explanation:

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The percent \(C_2O_4{2-}\) in each of the following:

\(H_2C_2O_4\) : 0 %

\(Na_2C_2O_4\): 67.2 %

\(K_2C_2O_4\): 54.19 %

\(K_3[Al(C_2O_4)_3].3H_2O.\): 18.76 %

To calculate the percent \(C_2O_4^{2-}\) in each compound, we need to determine the molar mass of \(C_2O_4^{2-}\) and the molar mass of the entire compound. Then we can use the following formula:

Percent\(C_2O_4^{2-}\) = \(\frac{\text{Molar mass of C2O42-}}{\text{Molar mass of the compound}} \times 100\]\)

Let's calculate the percent \(C_2O_4^{2-}\)  in each compound:

1.\(H_2C_2O_4\) (Oxalic acid):

Molar mass of\(C_2O_4^{2-}\)- = (2 × Atomic mass of C) + (4 × Atomic mass of O) = (2 × 12.01 g/mol) + (4 × 16.00 g/mol) = 90.03 g/mol

Molar mass of the compound = (2 × Atomic mass of H) + (2 × Atomic mass of C) + (4 × Atomic mass of O) = (2 × 1.01 g/mol) + (2 × 12.01 g/mol) + (4 × 16.00 g/mol) = 90.03 g/mol

{Percent\(C_2O_4^2-\)} = \\(\frac{90.03}{90.03} \times 100 = 100\%\]\)

2. \(Na_2C_2O_4\)(Sodium oxalate):

Molar mass of \(C_2O_4^{2-}\)- = 90.03 g/mol

Molar mass of the compound = (2 × Atomic mass of Na) + (2 × Atomic mass of C) + (4 × Atomic mass of O) = (2 × 22.99 g/mol) + (2 × 12.01 g/mol) + (4 × 16.00 g/mol) = 134.02 g/mol

Percent \(C_2O_4^{2-}\) =\(\frac{90.03}{134.02} \times 100 \approx 67.20\%\]\)

3.\(K_2C_2O_4\) (Potassium oxalate):

Molar mass of \(C_2O_4^{2- }\)- = 90.03 g/mol

Molar mass of the compound = (2 × Atomic mass of K) + (2 × Atomic mass of C) + (4 × Atomic mass of O) = (2 × 39.10 g/mol) + (2 × 12.01 g/mol) + (4 × 16.00 g/mol) = 166.22 g/mol

Percent \(C_2O_4^{2- }\)=\(\frac{90.03}{166.22} \times 100 \approx 54.19\%\]\)

4. \(K_3[Al(C_2O_4)_3].3H_2O.\)

Molar mass of the compound = (3 × Molar mass of K) + Molar mass of Al + (3 × Molar mass of C2O42-) + (3 × (2 × Molar mass of H)) + (1 × Molar mass of O) = (3 × 39.10 g/mol) + 26.98 g/mol + (3 × 90.03 g/mol) + (3 × (2 × 1.01 g/mol)) + 16.00 g/mol = 479.41 g/mol

Percent \(C_2O_4^{2-}\):

Percent \(C_2O_4^{2-}\)= 90.03/479.41 × 100 ≈1 8.76 %

Percent C2O42-= 479.41/90.03 ×100≈18.76%

Therefore, the percent C2O42− in \(K_3[Al(C_2O_4)_3].3H_2O\) is approximately 18.76%.

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To calculate the percent composition of C2O42− in each compound, determine the molecular weight of each compound and the weight of C2O42-. Use these to compute the percent composition.

The aim here is to calculate the percent composition of C2O42− in different compounds such as H2C2O4, Na2C2O4, K2C2O4, and K3[Al(C2O4)3]⋅3H2O. First, find the molecular weight of each compound using the molecular weights of H, C, O, Na, K, and Al. For instance, the molecular weight of H2C2O4 (Oxalic acid) = 2*1 (H) + 2*12 (C) + 4*16 (O) = 90 g/mole.

Then calculate the weight of the C2O42- in each compound, which = 2*12 (C) + 4*16 (O) = 88 g/mole. To find the percent composition, the formula is (part/whole) * 100. So, for H2C2O4, it would be (88/90) * 100 = 97.78%

Repeat this process for the other compounds to find the percentage of C2O42− in each.

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According to molar concentration, the solution's molarity is 0.125 M.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molarity=mass/ molar mass ×1/volume of solution in liters.Substitution in formula gives, molarity=14/148.3×1/0.75=0.125 M.

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