Atmospheric air at 35 degree C flows steadily into an adiabatic saturation device and leaves as a saturated mixture at 25 degree C. Makeup water is supplied to the device at 25 degree C. Atmospheric pressure is 98 kPa. Determine the relative humidity and specific humidity of the air.

omega_1 = ______ kg H_2O/kg dry air phi_1 = ______

Answer:

stopwatch method- measures the speed between two points.

radar meter method- uses electromagnetic waves that bounces off of an object causing the wave to change frequency to calculate the speed of the object with a radar machine.

pneumatic road tube method- uses two different tubes to record the time it takes to start and pass through the end line to calculate the speed of the object.

Answer:

Hope this helps :)

1. Define/Find the problem.

2. Explore/Research/Collect information.

3. Design the best solution base on your ideas/thoughts.

4. Create the solution.

5. Try the creation, put it to test/work.

6. Make the creation better, modify it.

Also, some additional steps are ...

7. Evaluate the solution, finishing thoughts/ideas.

8. Share your results with other engineers/people, final steps

Answer:

24 i believe

Explanation:

Through line biomechanics concentration and observation magic if International Society of Biomechanics in sports.

The recently developed professional association in biomechanics is the "International Society of Biomechanics in sports".It is the professional association in bio-mechanics.

It is an international society which is dedicated to bio-mechanics to sports. The main purpose of the society is to understand and study the human movement and its relation to sport bio-mechanics. They provide information regarding  bio-mechanics in sports.

Therefore, Through line biomechanics concentration and observation magic if International Society of Biomechanics in sports.

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The force over the inclined plane required to elevate the barrow is less than the straight surface as there was the tangential gravitational force acting on the barrow.

The force is the push or pulls experienced by the object when interacting with the other object. The force applied is calculated with respect to the force experienced by the object.

On moving the wheelbarrow over a straight surface, the gravitational force acting over it requires more force to elevate it in the opposite spatial relation.

Over the inclined plane, the wheelbarrow experiences the tangent of the gravitational force over it, and less force is required to elevate the barrow to the same level as the straight surface.

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Answer:

aqswdefrtghyujkijuhygtfrdesw

Explanation:

The java program to illustrate the data set will be;

import java.util.Scanner;

public class LabProgram {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       int n;

       n = scan.nextInt();

       while(n<=0){

           n = scan.nextInt();

       }

       float val[] = new float[n];

       for(int i = 0;i<val.length;i++){

           val[i] = scan.nextFloat();

       }

       float max = val[0];

       for(int i = 1;i<val.length;i++){

           if(max < val[i]){

               max = val[i];

           }

       }

       for(int i = 0;i<val.length;i++){

           val[i] = val[i]/max;

       }

       for(int i = 0;i<val.length;i++){

           System.out.printf("%.2f ",val[i]);

       }

       System.out.println();

   }

}

Java is a high-level, broad, object-oriented, and secure programming language created by Sun Microsystems, Inc.'s James Gosling in 1991.

Java programs are frequently asked about during interviews. These programs can be accessed via control statements, arrays, strings, oops, and so on.

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The XXX output of the following coding is return myData.itemCount * myData.price;. The correct option is B.

The output, which might take the form of text on a screen, printed materials, or sound coming from a speaker, is how the computer displays the outcomes of the operation.

totalPrice() function returns a double value.

So, XXX should be a return statement.

We can access itemCount of myData using

myData.itemCount

We can access pri

ce of myData using

myData.price

So, the return statement should be

return myData.itemCount * myData.price;

Therefore, the correct option is B. return myData.itemCount * myData.price;.

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Answer:

6.564 is the answers i learned that in the american school i live there

(a) The rms symmetrical fault current is 326.65 A

(b) The rms asymmetrical fault current at the instant the switch closes, assuming maximum dc offset is 397.4π A

(c) The rms asymmetrical fault current 5 cycles after the switch closes, assuming maximum dc off-set is 324.539 A

(d) The dc offset as a function of time if the switch closes when the instantaneous source voltage is 300 volts is 351.43\(e^{200t}\) A

Transmission line faults can generally be divided into the following categories:

A symmetrical fault in a power system is a type of fault that results in a short circuit involving all three phases. This could be a three phase short circuit or a three phase to ground fault.

When a fault is symmetrical, fault currents in the phases are symmetrical in that their magnitudes are equal and they are equally spaced by a 120° angle. So, a symmetrical fault with a high value of current in phases may be taken for granted as the norm.

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The peak frequency deviation, minimum bandwidth, and baud for a binary FSK signal for the given frequencies are respectively;

a) 0.5 kHz

b) 9 kHz

c) 4000

1) The peak frequency deviation is gotten from the formula;

∆f = |f_m - f_s|/f_b

where;

Thus;

∆f = |38 - 40|/4

∆f = 0.5 kHz

2) The minimum bandwidth is given by the formula;

B = 2(∆f + f_b)

B = 2(0.5 + 4)

B = 9 kHz

3) For FSK signal, N = 1, and the baud is gotten from the Equation;

baud = f_b/1

f_b = 4 kbps = 4000 bps

Thus; baud = 4000/1 = 4000

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1. We cannot solve nonlinear programming problems by simplex.The simplex method is utilized for linear programming problems only. The LP problems have linear constraints and a linear objective function. The nonlinear programming problems cannot be solved by the simplex method.

We have to use the other methods for these kinds of issues.2. In any integer basic feasible solution of the transportation problem, the number of positive variables is equal to half the number of functional constraints. It is feasible to use a solution that is restricted to whole numbers for transportation problems. We've got a few formulas that can help us figure out the answers.3. A discrete dynamic programming problem can be represented by a tree. To solve a dynamic programming problem, we typically use a graph structure known as a decision tree. The nodes of a decision tree represent decision points, and the arcs represent the choices available at each decision point.4. A tree is a special case of a graph. Trees are a special kind of graph, so it makes sense that they're also used to represent decision trees. Trees are graphs with nodes linked together in a particular manner. There is a parent-child relationship between the nodes of a tree, which means that each node has only one parent and zero or more children. Trees have no cycles, which means that there is no way to traverse the tree from a node to itself without first traversing a node that is not a descendant.

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During a reversible, adiabatic process, the entropy of the nitrogen will never always increase. Option D

In a reversible, adiabatic process, the entropy of an ideal gas remains constant.

This is known as the isentropic process.

The increase in entropy is related to the irreversible nature of a process and the transfer of heat from a high-temperature reservoir to a low-temperature reservoir.

However, in an adiabatic process, there is no transfer of heat and the process is reversible, meaning that the entropy of the nitrogen will remain constant.

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Answer: Why is even here then.

Explanation:

Answer:

Mathematics

Explanation:

⁄(⁄ ⁄•⁄ω⁄•⁄ ⁄)⁄

Answer:

It is a field if mathematics

Answer:

A) F = 0.011 N

B) ΔP = 5.6 N/m²

Explanation:

We are given;

surface tension coefficient; S = 0.07 N/m

Radius; r = 2.5 mm = 0.025 m

A) Formula to find the surface tension force(F) is given by;

F = SL

Where L is effective length = 2πr

F = 0.07 × 2π × 0.025

F = 0.011 N

B) Formula for difference in pressure droplet is;

ΔP = 2S/r

Thus;

ΔP = (2 × 0.07)/0.025

ΔP = 5.6 N/m²

An o ring intended for use in a hydraulic system using MIL-H-5606 (mineral base) fluid will be marked with a blue stripe or dot.

The CIA triad and the Parkerian hex are the fundamental principles of information security.

Parkeriano, or Parkerian hexad: is a set of six elements of information security proposed by Donn B. Parker.

1. Confidentiality.

2. Ownership or Control.

3. Integrity.

4. Authenticity.

5. Availability.

6. Utility

The Parkerian hexagram adds three more attributes to the three classic security attributes of the CIA triangle

these are the fundamental principles of information security.

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An engineer would indicate the unit of measurement used in a design in millimeters.

The primary unit of measurement is the stocking unit of measure for a given item in a specific organization. You must define an item attribute that serves as the primary unit of measurement when creating each item.

Because the technical drawings are scaled, engineers, architects, and builders may create the items according to exact specifications.

When understanding scales, the number on the left relates to the measurement of the drawing, while the number on the right represents the actual size of the object.

Therefore, a millimeter is used in a design.

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Answer:

  151.2 N

Explanation:

The upward force at A is 135/(135+325) times the total weight of the generator. The CW torque about point O that produces is ...

  (460 mm)(135/460)(160 kg)(9.8 m/s^2) = 211.68 N·m

For F to produce half that torque, it must be ...

  F(0.7 m) = (211.68 N·m)/2

  F = 211.68 N·m/(1.4 m) = 151.2 N

The complete question is;

The wheel and the attached reel have a combined weight of 50 lb and a radius of gyration about their center of ka = 6 in. If pulley B that is attached to the motor is subjected to a torque of M = 50 lb.ft, determine the velocity of the 200lb crate after the pulley has turned 5 revolutions. Neglect the mass of the pulley.

The image of this system is attached.

Answer:

Velocity = 11.8 ft/s

Explanation:

Since the wheel at A rotates about a fixed axis, then;

v_c = ω•r_c

r_c is 4.5 in. Let's convert it to ft.

So, r_c = 4.5/12 ft = 0.375 ft

Thus;

v_c = 0.375ω

Now the mass moment of inertia about of wheel A about it's mass centre is given as;

I_a = m•(k_a)²

The mass in in lb, so let's convert to slug. So, m = 50/32.2 slug = 1.5528 slug

Also, let's convert ka from inches to ft.

So, ka = 6/12 = 0.5

So,I_a = 1.5528 × 0.5²

I_a = 0.388 slug.ft²

The kinetic energy of the system would be;

T = Ta + Tc

Where; Ta = ½•I_a•ω²

And Tc = ½•m_c•(v_c)²

So, T = ½•I_a•ω² + ½•m_c•(v_c)²

Now, m_c is given as 200 lb.

Converting to slug, we have;

m_c = (200/32.2) slugs

Plugging in the relevant values, we have;

T = (½•0.388•ω²) + (½•(200/32.2)•(0.375ω)²)

This now gives;

T = 0.6307 ω²

The system is initially at rest at T1 = 0.

Resolving forces at A, we have; Ax, Ay and Wa. These 3 forces do no work.

Whereas at B, M does positive work and at C, W_c does negative work.

When pulley B rotates, it has an angle of; θ_b = 5 revs × 2π rad/revs = 10π

While the wheel rotates through an angle of;θ_a = (rb/ra) • θ_b

Where, rb = 3 in = 3/12 ft = 0.25 ft

ra = 7.5 in = 7.5/12 ft = 0.625 ft

So, θ_a = (0.25/0.625) × 10π

θ_a = 4π

Thus, we can say that the crate will have am upward displacement through a distance;

s_c = r_c × θ_a = 0.375 × 4π

s_c = 1.5π ft

So, the work done by M is;

U_m = M × θ_b

U_m = 50lb × 10π

U_m = 500π

Also,the work done by W_c is;

U_Wc = -W_c × s_c = -200lb × 1.5π

U_Wc = -300π

From principle of work and energy;

T1 + (U_m + U_Wc) = T

Since T1 is zero as stated earlier,

Thus ;

0 + 500π - 300π = 0.6307 ω²

0.6307ω² = 200π

ω² = 200π/0.6307

ω² = 996.224

ω = √996.224

ω = 31.56 rad/s

We earlier derived that;v_c = 0.375ω

Thus; v_c = 0.375 × 31.56

v_c = 11.8 ft/s

Answer:

it wqas red

Explanation:

red

This question is incomplete, the missing diagram is uploaded along this answer below.

Answer:

- The mass flow rate of air is 4.59 kg/s

- Area of the exit turbine is 0.066 m²

Explanation:

 Given the data in the question;

Using air as an ideal gas.

Turbine;

state 1: p₁ = 8 bar, T₁ = 960 K

state 2: p₂ = 1 bar, T₂ = 450 K

The inlet velocity is small compared to the exit velocity of 90 m/s

V₁ < V₂ = 90 m/s

Power of turbine W' = 2500 kW

Now, lets assume Q = 0 and ΔPE = 0

we know that; R = 0.2870 kJ/kg-K

Also. \(C_p\) at 700K = 1.075 kJ/kg-K

Now, using ideal gas law;

STATE1

v₁ = RT₁/p₁

so we substitute

v₁ = [(0.2870 kJ/kg-K)(960 K)/(8 bars )]|\(\frac{bar}{10^5N/m^2}\)||\(\frac{1000N.m}{kJ}\)| =  0.344 m³/kg

STATE2

v₂ = RT₂/p₁

we substitute

v₂ = [(0.2870 kJ/kg-K)(450 K)/(1 bars )]|\(\frac{bar}{10^5N/m^2}\)||\(\frac{1000N.m}{kJ}\)| =  1.2915 m³/kg

Now, from energy balance steady state;

0 = Q" - W" + \(m"_i\)( \(h_i\) + \(\frac{V_i^2}{2}\) + \(gz_i\)) - \(m"_B\)( \(h_B\) + \(\frac{V_B^2}{2}\) + \(gz_B\))

since we initially assume Q = 0 and ΔPE = 0

hence;

0 = \(-\frac{W"}{m"}\) + h₁ + \(\frac{V_1^2}{2}\) -  h₂ + \(\frac{V_2^2}{2}\)

\(\frac{W"}{m"}\) = h₁ + \(\frac{V_1^2}{2}\) -  h₂ + \(\frac{V_2^2}{2}\)

⇒  \(\frac{W"}{m"}\) = \(C_p\)(T₁ - T₂) + \(\frac{1}{2}\)( V₁² - V₂²)

we solve for m"

m" = W" / (\(C_p\)(T₁ - T₂) + \(\frac{1}{2}\)( V₁² - V₂²))

so we substitute;

m" = {[2500 kW] / [(1.075kJ/kg-K(960K - 450k) + \(\frac{1}{2}\)( (0)² - (90 m/s)²)) |kJ/1000N.m| |N/kg.m/s²|]} | kJ/s / kW|

m" = 4.59 kg/s

Therefore, the mass flow rate of air is 4.59 kg/s

From the mass body steady state;

0 = m"₁ - m"₂

so

m"₁ = m"₂ = 4.59 kg/s

now, the volumetric flow rate V"₂ will be;

V"₂ = m" × v₂

we  substitute

V"₂ =  4.59 kg/s × 1.2915 m³/kg = 5.93 m³/s

and

the volumetric flow rate V"₂ = A₂V₂

so;

Exit Area A = V"₂ / V₂

we substitute

A = (5.93 m³/s ) / (90 m/s)

A = 0.06589 ≈ 0.066 m²

Therefore, Area of the exit turbine is 0.066 m²

The stator winding of a three-phase motor is often referred to as the motor primary. So, the correct choice is option a.

In a three-phase motor, the stator winding is responsible for creating the rotating magnetic field necessary for the motor's operation. It is called the "primary" because it is the primary source of electromagnetic power in the motor. The stator winding consists of coils of wire that are carefully arranged and connected to form three phases: A, B, and C. When an alternating current is passed through the stator winding, it generates a rotating magnetic field. This magnetic field interacts with the rotor, which is the rotating part of the motor, causing it to rotate and produce mechanical power.

The term "primary" is used to distinguish the stator winding from the "secondary" winding, which is found in certain types of motors like transformers. In transformers, the primary winding receives electrical power and transfers it to the secondary winding through electromagnetic induction. However, in a three-phase motor, the stator winding is the primary source of power that initiates the rotation and provides the driving force. It is crucial for generating the magnetic field that interacts with the rotor to convert electrical energy into mechanical energy.

Therefore, referring to the stator winding of a three-phase motor as the motor primary accurately describes its role and its significance in the motor's operation.

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Answer:

identify function of the system unit and its components

Answer:

the answer c or e or do wha t the first guy do

Compare and contrast direct conversion and parallel conversion.

what is the exact process involved?

Both conversion tactics center on how users are transitioned to the new system. The old system is "unplugged" and the new system is turned on in a direct conversion. The new system must be used by the users; they have no other option. The old system is temporarily used while the new system is activated in the parallel conversion plan. The direct approach is obviously more dangerous because there is no backup in the event that severe system problems are found.

If a significant flaw in the new system is found, the parallel conversion will keep the old system operational. However, the expense and additional work of utilizing both systems at once must be taken into account.

Hence to conclude Compare and contrast direct conversion and parallel conversion involves running the old and new systems

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Answer:

(c) electronic

Explanation:

for pf, this is correct....Here is the sentence from the pf lesson

" The primary energy source for the controller within buildings is typically electric, pneumatic, or

electronic

."

The equation of motion of a linearized inverted pendulum is given by;

\($$J_t \ddot{x} + \gamma \dot{x} - mglx = u$$\)

Here, \(x\) represents the angle of the pendulum such that \(x=0\) represents the equilibrium position of the pendulum when it is pointing downwards. The other parameters are as follows;\(J_t\) - the moment of inertia of the pendulum\(\gamma\) - coefficient of friction between the pendulum and air resistance\(m\) - the mass of the pendulum\(\ell\) - the length of the pendulum\(g\) - the acceleration due to gravity\(u\) - the control inputThe equation of motion shows the relationship between the angle of the pendulum, its angular acceleration, and the control input.

The equation shows that the angular acceleration of the pendulum is proportional to the control input and inversely proportional to the moment of inertia. It is also proportional to the length of the pendulum and the sine of the angle of inclination. The equation of motion also shows that the angular acceleration of the pendulum is damped due to the friction and air resistance. This makes the pendulum come to rest after some time even without external control.The above equation can be solved using Laplace transforms. Let

\(\(x(s) = \mathcal{L} \{x(t)\}\)\(u(s)\)= \(\mathcal{L} \{u(t)\}\)\)

Then we have

\($$J_ts^2x(s) + \gamma s x(s) - mglx(s) = u(s)$$$$x(s) = \frac{1}{J_ts^2 + \gamma s - mgl} u(s)$$Therefore$$x(t) = \mathcal{L}^{-1} \{\frac{1}{J_ts^2 + \gamma s - mgl} u(s)\}$$\)

The Laplace transform can be used to find the response of the pendulum to different inputs, such as a step input or a sinusoidal input.

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