at a 25% off sale you buy a game for 45$ what was the original price

Answer:

\( \frac{1}{m - n} - \frac{m + n}{m {}^{2} - n {}^{2} } \)

Factor if necessary:

x²-y²=(x+y)(x-y) use this formula

\(\frac{1}{m - n} - \frac{m + n}{ {(m + n)(m - n)}}\)

\(\frac{1}{m - n} - \frac{1}{ {(m - n)}}\)

Take lcm and subtract:

=0

Answer:

0

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

→ 1/ ( m - n) - (m + n)/ ( m² - n² )

→ 1/ ( m - n) - ( m + n)/(m+n)(m-n)

→ 1/( m - n) - 1/ ( m - n)

→ 0

The order of the angles from the least measure to greatest measure is ∠HGB, ∠ECD, ∠FGH and ∠GBH. The solution has been obtained by using the properties of angles.

What is an angle?

When two rays or lines share an endpoint, they form an angle, which is a figure in plane geometry.

We are given that CEFH is a parallelogram. We know that the adjacent angles of a parallelogram are supplementary.

So,

⇒∠FEC + ∠HCE = 180°

⇒124° + ∠HCE = 180°

⇒∠HCE = 56°

We know that angles on a straight line form a linear pair.

So,

⇒∠BCH + ∠HCE + ∠ECD = 180°

⇒90° + 56° + ∠ECD = 180°

⇒∠ECD = 34°

We know that the opposite angles of a parallelogram are equal.

So,

⇒∠FEC = ∠FHC

⇒∠FHC = 124°

Now,

⇒∠FHC + ∠FHG = 180°

⇒∠FHG = 56°

Using the angle sum property of triangle, we get

⇒∠FHG + ∠FGH + ∠GFH = 180°

⇒56° + ∠FGH + 87° = 180°

⇒∠FGH = 37°

∠GHB = 124°     (Vertically opposite angles)

∠CHB = 56°     (Vertically opposite angles)

Using the angle sum property of triangle, we get

⇒∠BCH + ∠CHB + ∠HBC = 180°

⇒90° + 56° + ∠HBC = 180°

⇒∠HBC = 34°

∠GBH = 44°    (Straight line angle)

∠HGB = 12°     (Angle sum property of triangle)

Hence, order of the angles from the least measure to greatest measure is ∠HGB, ∠ECD, ∠FGH and ∠GBH.

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Answer: 5π/3 (5,236)

Step-by-step explanation: Length of the whole circle arc is 2πr, in this case it is 12π. 50° is 50/360 = 5/36 part of the arc, so we can multiply 12π by 5/36 to get an answer. 12π * 5/36 = 5π/3.

To calculate the terminal value of the firm at time 3, we can use the Gordon Growth Model formula:

Terminal Value = Cash Flow at Time 3 * (1 + Growth Rate) / (Discount Rate - Growth Rate)

Given: Cash Flow at Time 3 = $73,900 Growth Rate = 2.2% Discount Rate = Risk-Free Rate + Beta * Market Risk Premium Risk-Free Rate

= 3.6% Beta

= 1.47 Market Risk Premium

= 7.4%

First, let's calculate the Discount Rate: Discount Rate = 3.6% + 1.47 * 7.4% = 3.6% + 10.8378%

= 14.4378%

Now, we can calculate the Terminal Value: Terminal Value = $73,900 * (1 + 2.2%) / (14.4378% - 2.2%) ≈ $73,900 * 1.022 / 0.1213778 ≈ $73,900 * 8.4258

Terminal Value ≈ $623,444.42

Therefore, the correct option for the terminal value of the firm at time 3 is: a. $667,229.73 (None of the provided options matches the calculated value)

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3 students play all three sports.The number of students who play both baseball and tennis is 8, the number of students who play both tennis and football is 5, and the number of students who play both baseball and football is 10. Find the number of students who play all three sports.

Given:Conard High School has 5050 students who play on the baseball, football, and tennis teams. Some students play more than one sport. If 1515 play tennis, 2525 play baseball, 3030 play football, 88 play tennis and baseball, 55 play tennis and football, and 1010 play baseball and football.Find:How many students play all three sports?Solution:We can use the formula for three sets to solve the given problem.N(A U B U C) = n(A) + n(B) + n(C) - n(A ∩ B) - n(B ∩ C) - n(C ∩ A) + n(A ∩ B ∩ C)Where, A, B, and C are the sets of the students who play tennis, baseball, and football respectively.n(A) = 15, n(B) = 25, and n(C) = 30n(A ∩ B) = 8, n(A ∩ C) = 5, and n(B ∩ C) = 10We have to find n(A ∩ B ∩ C)Using the formula we get:n(A U B U C) = n(A) + n(B) + n(C) - n(A ∩ B) - n(B ∩ C) - n(C ∩ A) + n(A ∩ B ∩ C)50 = 15 + 25 + 30 - 8 - 10 - 5 + n(A ∩ B ∩ C)50 = 47 + n(A ∩ B ∩ C)n(A ∩ B ∩ C) = 50 - 47n(A ∩ B ∩ C) = 3 studentsSo, 3 students play all three sports.

Conard High School has 50 students who play more than one sport, and the number of students who play tennis, baseball, and football is 15, 25, and 30, respectively. We are given that 8 students play both tennis and baseball, 5 students play both tennis and football, and 10 students play both baseball and football. We are to find how many students play all three sports.We can use the formula for three sets to solve the given problem.N(A U B U C) = n(A) + n(B) + n(C) - n(A ∩ B) - n(B ∩ C) - n(C ∩ A) + n(A ∩ B ∩ C)Where A, B, and C are the sets of the students who play tennis, baseball, and football, respectively. The formula is based on the fact that the number of students who play any two sports is counted twice and hence needs to be subtracted once.To use this formula, we need to determine the number of students who play tennis only, baseball only, and football only. We can do this by subtracting the number of students who play two sports from the total number of students who play each sport. Then, we can substitute these values in the formula.n(A) = 15 - (8 + 5) = 2n(B) = 25 - (8 + 10) = 7n(C) = 30 - (5 + 10) = 15n(A U B U C) = 2 + 7 + 15 - 8 - 10 - 5 + n(A ∩ B ∩ C)50 = 47 + n(A ∩ B ∩ C)n(A ∩ B ∩ C) = 50 - 47n(A ∩ B ∩ C) = 3Therefore, 3 students play all three sports.

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The expression for the given Venn diagram is (AUC) - (A∩B) + (A∩B∩C)

Given is a Venn diagram, we need to find an expression for the given region,

So,

The Venn diagram contains three sets A, B and C,

The included part is =

The whole part of A and C and the common part of all the three sets, but it does not include the common or total part of A and B,

∩ = common part, ∪ = total part

Hence the expression for the given Venn diagram is (AUC) - (A∩B) + (A∩B∩C)

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A line chart is a type of graph used to show the relationship between two variables.

It is used for plotting data points that are connected by a straight line. The two variables can be either continuous or categorical. The line chart is useful for visualizing the relationship between the two variables and how they change over time. Line charts can be used to display data over a period of time, such as stock prices, or to compare different categories of data.

A pyramid chart is a type of graph used to compare different groups of data. It is usually used to show the relative sizes of different categories within a data set. The pyramid chart is generally preferred over the column chart because it is easier to compare the relative sizes of the different categories.

Pie charts are a type of graph used to show the relative size of different categories in a data set. They are useful for visualizing the proportions of the different categories. Pie charts can generally be used instead of bar charts, but they are not as useful for comparing the relative sizes of different categories or for displaying data over a period of time.

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It is false that Parametric models are reliable when the models are flexible in terms of the project's size

Parametric models are mathematical models that make assumptions about the distribution of the data being modeled. These models rely on the estimation of one or more parameters that define the distribution, such as the mean and variance of a normal distribution.

While parametric models can be very useful when the underlying assumptions are met and the data follows the assumed distribution, they can be unreliable when the assumptions are not met. For example, if the data does not follow a normal distribution, using a parametric model based on a normal distribution may lead to incorrect conclusions.

In terms of project size, the reliability of parametric models depends on the specific model and the nature of the data being modeled. Some parametric models may be more or less flexible in terms of accommodating different sample sizes or project sizes. However, in general, the reliability of a parametric model depends on the appropriateness of the underlying assumptions and the fit of the model to the data, rather than the size of the project.

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Answer:

The total price to pay is $95.718.

Step-by-step explanation:

Solve for the total cost of the entrees first

$35(3) = $105

Taking off 14%, that means that the customer is only to pay

100% - 14% = 86% of the total price or 0.86 in decimal

Discounted price = $105(0.86)

Discounted price = $90.30

Lastly, add the 6% sales tax or 0.06 in decimal

Total price = $90.30(1.06)

Total price = $95.718

Answer:

801.66

Step-by-step explanation:

calculator

Answer:

801.6632653061

Step-by-step explanation:

.......

Answer:

Unit rate is literally 1/x.

Step-by-step explanation:

U can figure out the rest!

Answer:

5985.97

Step-by-step explanation:

A=33

2a2=3·3

2·482≈5985.96759

The Equivalent equation using the Subtraction Property of Equality is y = 2.

If we have an expression as ( a + b ) = c

Then as per subtraction property of equality [ (a + b ) - b = c - b ]

Here given 9y = 4y + 10

Simplifying this equation, we get

⇒9y - 4y = 10

⇒( 9 - 4 )y = 10

⇒5y = 10

therefore, y = ( 10 ÷ 5 )

⇒y = 2

Therefore the equivalent equation is y = 2.

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Answer:

x = -2 ,  y = 2

Step-by-step explanation:

hope this helps :)

The probability that the sample average falls outside the 3-sigma control limits of the X-bar chart is 0.27%.

The 3-sigma control limits are calculated using the standard deviation of the process. If the process is in control, then 99.73% of the sample averages will fall within the 3-sigma control limits. The remaining 0.27% of the sample averages will fall outside the control limits.

In this case, the sample size is 4, which is smaller than the sample size of 9 that was used to construct the control chart. This means that the control limits for the sample of size 4 will be narrower than the control limits for the sample of size 9.

As a result, the probability that the sample average falls outside the control limits will be higher for the sample of size 4.

Specifically, the probability that the sample average falls outside the 3-sigma control limits for a sample of size 4 is 0.27%. This means that there is a 0.27% chance that the new employee will observe a sample average that falls outside the control limits, even if the process is in control.

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Answer: 6x^2 - 17x + 12.

Step-by-step explanation:

To multiply these two binomials, we can use the FOIL method, which stands for First, Outer, Inner, Last. This gives us:

(2x - 3)(3x - 4) = (2x)(3x) + (2x)(-4) + (-3)(3x) + (-3)(-4)

Simplifying each term, we get:

(6x^2) + (-8x) + (-9x) + 12

Combining like terms, we can simplify this to:

6x^2 - 17x + 12

Therefore, (2x-3)(3x-4) can be expressed as the trinomial 6x^2 - 17x + 12.

Answer:

= 5^-8 . 5^-10

= 5^(-8 ) + (-10)

=5^-18

Answer:

5^-18

Step-by-step explanation:

\((5^{-8})(5^{-10}) = 5^{-8-10} = 5^{-18}\)

A type I error occurs when a researcher mistakenly rejects a true null hypothesis. In other words, it is a false positive result. Let's break down what happens in a type I error:

1. The researcher starts with a null hypothesis, which assumes that there is no significant relationship or effect between the variables being studied.

2. To test the null hypothesis, the researcher collects data and performs statistical analysis.

3. In a type I error, the researcher incorrectly concludes that there is a significant relationship or effect when, in fact, there is none.

4. This error can happen due to various reasons, such as sample size, random chance, or flaws in the experimental design.

To avoid type I errors, researchers typically set a predetermined significance level (often denoted as α) before conducting the study. The significance level represents the probability of making a type I error. By setting a lower significance level, such as α = 0.05, researchers aim to reduce the chances of mistakenly rejecting the null hypothesis.

In the context of the given question, if the researcher is trying to reduce error and avoid a type I error, it means they want to minimize the risk of incorrectly inferring findings to another practice setting. This would increase the confidence that nurses have in applying the research findings to their own work.

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To find an implicit equation for the plane passing through the points (-4, -1, 5), (-9, 0, 10), and (1, -4, 5), we can use the cross product of two vectors in the plane.

Let's denote the three points as A (-4, -1, 5), B (-9, 0, 10), and C (1, -4, 5).

First, we find two vectors in the plane by taking the differences between the points:

Vector AB = B - A = (-9, 0, 10) - (-4, -1, 5) = (-5, 1, 5)

Vector AC = C - A = (1, -4, 5) - (-4, -1, 5) = (5, -3, 0)

Next, we calculate the cross product of these two vectors:

Normal vector N = AB x AC

= (-5, 1, 5) x (5, -3, 0)

Using the determinant expansion method to calculate the cross product, we get:

N = (1 * 0 - 5 * (-3), 5 * 0 - (-5) * 0, -5 * (-3) - 1 * 5)

= (15, 0, 10)

Now, we have the normal vector of the plane as N = (15, 0, 10).

Using the general equation for a plane, Ax + By + Cz + D = 0, where (A, B, C) is the normal vector, we can substitute the values:

15x + 0y + 10z + D = 0

To find D, we substitute one of the points in the equation. Let's use point A (-4, -1, 5):

15 * (-4) + 0 * (-1) + 10 * 5 + D = 0

-60 + 0 + 50 + D = 0

-10 + D = 0

D = 10

Therefore, the implicit equation for the plane passing through the points (-4, -1, 5), (-9, 0, 10), and (1, -4, 5) is:

15x + 10z + 10 = 0.

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Answer:

Merry Christmas!!!! :D

Step-by-step explanation:

The awnser is 1 :D

Answer:

x=1

Step-by-step explanation:

15x=5(4-x)

15x=20-5x

20x=20

x=1

Happy Holidays! Please give me brainliest!

Answer:

5,386,830

Step-by-step explanation:

Answer:

B. 173.25 cm^2

Step-by-step explanation:

just multiply them all.

That is, if \(y_1(x), y_2(x), ..., y_n(x)\)are all solutions of the ODE, then any linear combination of the form \(c_1y_1(x) + c_2y_2(x) + ... + c_n*y_n(x)\) is also a solution of the ODE, where \(c_1, c_2, ..., c_n\) are constants.

True.

This property is known as the superposition principle for linear ODEs, and it arises from the linearity of the differential equation. A linear ODE is an ODE of the form:

\(a_n(x)y^(n) + a_(n-1)(x)y^(n-1) + ... + a_1(x)y' + a_0(x)y = f(x)\)

where y^(k) denotes the k-th derivative of y(x) with respect to x, and \(a_n(x), a_(n-1)(x), ..., a_1(x), a_0(x)\)and f(x) are given functions of x.

Suppose that y1(x) and y2(x) are both solutions of this ODE, so that when we substitute them into the differential equation, we get:

\(a_n(x)y1^(n) + a_(n-1)(x)y1^(n-1) + ... + a_1(x)y1' + a_0(x)y1 = f(x)\)

and

\(a_n(x)y2^(n) + a_(n-1)(x)y2^(n-1) + ... + a_1(x)y2' + a_0(x)y2 = f(x)\)

We want to show that any linear combination of y1(x) and y2(x), such as c1y1(x) + c2y2(x) where c1 and c2 are constants, is also a solution of the ODE.

To do this, we substitute the linear combination into the differential equation:

\(a_n(x)(c1y1(x) + c2y2(x))^(n) + a_(n-1)(x)(c1y1(x) + c2y2(x))^(n-1) + ... + a_1(x)(c1y1'(x) + c2y2'(x)) + a_0(x)(c1y1(x) + c2y2(x)) = f(x)\)

Using the linearity of differentiation and the distributive property of multiplication, we can simplify this expression:

\(c1(a_n(x)y1^(n) + a_(n-1)(x)y1^(n-1) + ... + a_1(x)y1' + a_0(x)y1) + c2(a_n(x)y2^(n) + a_(n-1)(x)y2^(n-1) + ... + a_1(x)y2' + a_0(x)y2) = f(x)\)

Since y1(x) and y2(x) satisfy the differential equation individually, the expressions in parentheses on the left-hand side are equal to f(x). Therefore, we have shown that the linear combination c1y1(x) + c2y2(x) also satisfies the differential equation, and is therefore a solution of the ODE.

In general, this result extends to any finite linear combination of solutions of the ODE. That is, if y1(x), y2(x), ..., yn(x) are all solutions of the ODE, then any linear combination of the form c1y1(x) + c2y2(x) + ... + cn*yn(x) is also a solution of the ODE, where c1, c2, ..., cn are constants.

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The question is an illustration of inequalities and equation.

The system of inequalities are: \(\mathbf{3x + 4y \ge 24}\) and \(\mathbf{13x + 4y = 64}\)

Represent the number of hours for lines 1 and 2 with x and y.

So, we have:

Minibus

Line 1 = 3

Line 2 = 4

Total: At least 24

Media-blue

Line 1 = 13

Line 2 = 4

Total = 64

At least means greater than or equal to.

So, the system of inequalities are:

\(\mathbf{3x + 4y \ge 24}\)

\(\mathbf{13x + 4y = 64}\)

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Answer:

2% of 1kg

Step-by-step explanation:

20g/1kg x 100

= 20g/1000g x 100

1/50 x 100

=2

Therefore, 20g is 2% of 1kg

Hope it helps you

Answer:

2%

Step-by-step explanation:

1kg=1000g

=20/1000×100%

=2%

Answer:

it blinks 1,200 times

Step-by-step explanation:

Answer:

75 + 25h

Step-by-step explanation:

Hope this helps

Answer:

Step-by-step explanation:

J