Answers
Answer:
The ratio is \(\frac{B_1}{B_2} = 1.265\)
Explanation:
From the question we are told that
The density of fresh water is \(\rho__{f}} = 998 \ kg/m^3\)
The density of ethanol is \(\rho_{e} = 789 \ kg /m^3\)
Generally speed of a wave in a substance is mathematically represented as
\(v = \sqrt{\frac{B}{\rho} }\)
Here B is the adiabatic bulk modulus of the substance while \(\rho\) is the density of the substance
So at constant wave speed
\(\sqrt{\frac{B_1}{\rho_1} } = \sqrt{\frac{B_2}{\rho_2} }\)
=> \(\frac{B_1}{\rho_1} = \frac{B_2}{\rho_2}\)
=> \(B_1 \rho_2 = B_2\rho_1\)
=> \(\frac{B_1}{B_2} = \frac{\rho_1}{\rho_2}\)
Here \(\rho_1 =\rho__{f}} = 998 \ kg/m^3\) and \(\rho_2 = \rho_{e} = 789 \ kg /m^3\)
So
=> \(\frac{B_1}{B_2} = \frac{998}{789}\)
=> \(\frac{B_1}{B_2} = 1.265\)
Related Questions
find then circumference
Answers
Answer:
A. 13 cm
Explanation:
here the total diameter is given 4 cm,
here the radius then will be 2 cm.
use the formula of circumference of circle = 2πr ........where r is the radius
using the formula: 2 * π * 2 = 4π = 12.57 = 13 cm.
find distance of this v-t graph
Answers
Distance = Speed x Time
The distance of the v-t graph as shown in the diagram is 1000 m.
How to find the distance in a v-t graph?
To calculate the distance in a velocity-time graph, we find the total area under the graph
From the graph in the question above,
Distance in the v-t graph = Area of a tripezium = h(a+b)/2A = h(a+b)/2........................ Equation 1Where:
A = Total distance of the v-t graphh = Height of the tripeziuma and b = Both parallel side of the tripeziumFrom the diagram,
h = 50 secondsa = 10 m/sb = 30 m/sSubstitute these values into equation 1
A = 50(10+30)/2A = 50×20A = 1000 mHence, the distance is 1000 m.
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They realize there is a thin film of oil on the surface of the puddle. If the index of refraction of the oil is 1.81, and they observe the reflected light in the air to be orange (wavelength of 600 nm), what is the thickness of the film of oil in nanometers? Give your answer with one decimal place please.
Answers
Answer:
The right solution is "165.8 nm".
Explanation:
Given:
Index of refraction,
n = 1.81
Wavelength,
λ = 600 nm
We know that,
⇒ \(t=\frac{\lambda}{2\times n}\)
By putting the values, we get
\(=\frac{600}{2\times 1.81}\)
\(=165.8 \ nm\)
where is the mask of the vehicle that has 50,000 N and 25 m/s/s
Answers
The vehicle has a 2000kg mass.
briefly? Is the formula for F MA in Newtons?Take a mass's acceleration into account. Use the formula F = m a to determine the force's value. Kilogram-meter/second-squared will be used as the unit of force. The short name for this unit, which is made up of the three basic SI units, is newton.
F= ma
m= F/a
m= 50000/25
m= 2000 kg
What is an easy way to define Newton's second law?According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force acts on a mass (object). This law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. The force that propels you forward on your bicycle comes from your leg muscles.
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As a torque activity, your Physics TA sets up the arrangement decribed below. A uniform rod of mass mr = 158 g and length L = 100.0 cm is attached to the wall with a pin as shown. Cords are attached to the rod at the r1 = 10.0 cm and r2 = 90.0 cm mark, passed over pulleys, and masses of m1 = 281 g and m2 = 177 g are attached. Your TA asks you to determine the following: (a) The position r3 on the rod where you would suspend a mass m3 = 200 g in order to balance the rod and keep it horizontal if released from a horizontal position. In addition, for this case, what force (magnitude and direction) does the pin exert on the rod? Use standard angle notation to determine the direction of the force the pin exerts on the rod. Express the direction of the force the pin exerts on the rod as the angle F, measured with respect to the positive x-axis (counterclockwise is positive and clockwise is negative). r3 = Fp = F = (b) Let's now remove the mass m3 and determine the new mass m4 you would need to suspend from the rod at the position r4 = 20.0 cm in order to balance the rod and keep it horizontal if released from a horizontal position. In addition, for this case, what force (magnitude and direction) does the pin exert on the rod? Express the direction of the force the pin exerts on the rod as the angle F, measured with respect to the positive x-axis (counterclockwise is positive and clockwise is negative). m4 = Fp = F = (c) Let's now remove the mass m4 and determine the mass m5 you would suspend from the rod in order to have a situation such that the pin does not exert a force on the rod and the location r5 from which you would suspend this mass in order to balance the rod and keep it horizontal if released from a horizontal position. m5 = r5 =
Answers
a) Recall, the net torque on the rod must be zero. Thus,
Σt = 0
where
t represents torque
Thus,
t1 + t2 - tr - t3 = 0
t = rF
where
F = force
r = distance
r1F1 + r2F2 - rrFr - r3F3 = 0
r3F3 = r1F1 + r2F2 - rrFr
r3 = (r1F1 + r2F2 - rrFr)/F3
Note,
F1 = T1 = m1g
F2 = T2 = m2g
F3 = T3 = m3g
Thus,
r3 = (r1m1g + r2m2g - rrmrg)/m3g
g cancels out
r3 = (r1m1 + r2m2 - rrmr)/m3
From the information given,
r1 = 10 cm = 10/100 = 0.1 m
r2 = 90 cm = 90/100 = 0.9 m
rr = 100/2 = 50 cm = 50/100 = 0.5 m
m1 = 281 g = 281/1000 = 0.281 kg
m2 = 177g = 0.177 kg
mr = 158g = 0.158 kg
m3 = 200g = 0.2kg
By substituting these values into the equation,
r3 = (0.1 x 0.281 + 0.9 x 0.177 - 0.5 x 0.158)/0.2
r3 = 0.542 m
The force exerted by the pin, Fp = mg
g = 9.8
Fp = (m3 - mr - m1 - m2)g
Fp = (0.2 + 0.158 - 0.281 - 0.177)9.8
Fp = - 0.981
Taking the absolute value,
IFpI = 0.981 N
F = - 90 degrees
b) r1F1 + r2F2 - rrFr - r4F4 = 0
r4F4 = r1F1 + r2F2 - rrFr = 0
F4 = (r1F1 + r2F2 - rrFr)/r4
Note,
F1 = T1 = m1g
F2 = T2 = m2g
F3 = T3 = m3g
F4 = T4 = m4g
Thus,
m4g = (r1m1g + r2m2g - rrmrg)/r4
m4g = (r1m1 + r2m2 - rrmr)/r4
r4 = 0.2
By substituting these values into the equation,
m4 = (0.1 x 0.281 + 0.9 x 0.177 - 0.5 x 0.158)/0.2
m4 = 0.542 kg
The force exerted by pin is
Fp = (m4 + mr - m1 - m2(g
Fp = (0.542 + 0.158 - 0.281 - 0.177)9.8
Fp = 2.37 N
Fp = 2.37 N
F = 90 degrees
c) When the pin does not exert a force,
Fp = 0
F1 + F2 - Fr = F5
m1 + m2 - mr = m5
m5 = 0.281 + 0.177 - 0.158
m5 = 0.3 kg
Since the net torque on the rod is zero,
t1 + t2 - tr - t5
t5 = t1 + t2 - tr - t5
t5 = t1 + t2 - tr - t5
r5 = r1F1 + r2F2 - ffFr)/F5
r5 = (r1m1 + r2m2 - rrmr)/m5
r5 = (0.1 x 0.281 + 0.9 x 0.177 - 0.5 x 0.158)/0.3
r5 = 0.36
How would increasing the pressure of this reaction affect the equilibrium
Answers
Explanation:
c because there is element
Answer:
C. H2 and N2 would react to produce more NH3
Explanation:
A.P.E.X
A circuit is complete when there is a ______ path for electricity to travel from one end of the energy source to the other end.
lesson 5.04
Question 6 options:
zig zag path
continuous path
broken path
random path
Answers
Answer:
.....when there is a continuous path for electricity....
^_^ Pls mark my answer as brainliest ^_^
a 0.50 kg book is being pushed on a horizontal table. the force pushing the book is 6n and the frictional force between the book and the surface has magnitude f
Answers
The magnitude of the frictional force is f = μ * 4.9 N.
What is magnitude?
Magnitude is a term used in physics to describe an object's maximum size and direction. Scalar and vector quantities both use magnitude as a common factor. We are aware that scalar quantities are those that have only magnitude by definition. Those quantities with both direction and magnitude are considered vector quantities. An earthquake's size is measured in terms of its length, breadth, and width. It is calculated based on the earthquake's actual size. A single magnitude is thought to exist for an earthquake. Due to variables like the type of material surface and distance from the epicentre, the magnitude of the shaking brought on by the earthquake varies depending on where it occurs.
The frictional force between the book and the surface is the resistive force pushing back against the pushing force of 6N. The magnitude of this resistive force depends on the coefficient of friction between the book and the table surface, as well as the normal force, which is equal to the weight of the book (0.50 kg * 9.8 m/s2 = 4.9 N).
The magnitude of the frictional force (f) can be calculated using the equation f = μ * N, where μ is the coefficient of friction and N is the normal force. Thus, the magnitude of the frictional force is f = μ * 4.9 N.
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The world record for the 100-meter dash is 9.76 s. What is the runner's average speed?
Answers
Answer:
mine is 9.75 so take that as you will
Explanation:
Two identical blocks are heated to different temperatures. The blocks are placed so that they touch, and heat begins to flow between blocks. The pair of blocks is insulated, so no energy escapes.
Lastly, the temperature of each block is measured again. Which pair of temperatures is possible?
Answers
The pair of blocks is insulated, so no energy escapes. The pair of temperatures possible is 95 +95 temperature blocks.
What is thermal equilibrium?When two objects are in direct contact and transfer heat through conduction. When the both object attain same temperature after sometime, they are called in thermal equilibrium.
Two identical blocks are heated to different temperatures. The blocks are placed so that they touch, and heat begins to flow between blocks. The heat will continue to until and unless they have same temperatures. After they being isolated, the temperature of both will be same and no heat is transferred outside.
Thus, the pair of temperatures possible is 95 +95 temperature blocks.
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An electron moves from point i to point f, in the direction of a uniform electric field. During this motion:Group of answer choicesthe work done by the field is positive and the potential energy of the electron-field system increasesthe work done by the field is negative and the potential energy of the electron-field system increasesthe work done by the field is positive and the potential energy of the electron-field system decreasesthe work done by the field is negative and the potential energy of the electron-field system decreasesthe work done by the field is positive and the potential energy of the electron-field system does not change
Answers
Answer:
the work done by the field is positive and the potential energy of the electron field system decreases
Explanation:
This exercise asks to find the work and the potential energy of an electron in an electric field.
Work is defined by
W = F .d = F d cos θ
the electric force is
F_e = q E
W = q E d cos θ
since the charge of the electron is negative the force is in the opposite direction to the electric field
W = - e E d
we select the direction to the right is positive, point i is to the left of point f,
therefore the work moving from point i to point F has two possibilities
* The electric field lines go from i to f point , so that point i is on the side of the positive charges, so the electron approaches them, This movement is opposite to that indicated
* the field line reaches point i, this implies that the charges are negative, so the electrioc field is then negativeand the electron charge is negative too. The electron moves away from this point, this is in accordance with the indicated movement
In the latter case the electric field lines go from f to i point, therefore the Work is positive
Now let's examine the potential energy
ΔU = - q E .d
so we see that this definition is related to work,
ΔU = -W
Therefore, as the work is positive, the power energy must decrease
When reviewing the different answers, the correct ones are:
the work done by the field is positive and the potential energy of the electron field system decreases
The work done by the electron while moving from point \(i\) to point \(f\) in the direction of uniform electric field is negative and the potential energy of the electron increases.
An electron moves from point i to point f, in the direction of a uniform electric field, then the potential energy of the electron can be calculated s given below.
\(\Delta V=-qEd\)
Where \(\Delta V\) is the potential energy, \(E\) is the electric field, \(q\) is the charge and \(d\) is the displacement of the electron.
The work done by the electron in the uniform electric field can be calculated as,
\(W = F\times d \times cos\theta\)
Where \(W\)is the work done by electron, \(F\) is the electric force, \(d\) is the displacement of the electron and for uniform electric field, the value of \(\theta\) is zero.
Hence \(W=F\times d\times 1\\W=F \times d\)
Electric force \(F = q E\)
By substituting the value of electric force on the above formula,
\(W = qEd\)
Hence, the relation between the work done the electron in an uniform electric field and potential energy of the electron can be given below.
\(W = -\Delta V\)
The work done by the electron is negative and the potential energy of the electron increases.
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Which one of the following is the longest length?
(a) 100 m
(b) 104 µm
(c) 107 nm
(d) 102 mm
Answers
Okay, let's convert all the lengths to the same unit to compare:
(a) 100 m = 100 meters
(b) 104 μm = 104 micrometers = 104 × 10^-6 meters = 0.000104 meters
(c) 107 nm = 107 nanometers = 107 × 10^-9 meters = 0.000000000997 meters
(d) 102 mm = 102 millimeters = 102 × 10^-3 meters = 0.0102 meters
The longest length is:
(a) 100 m = 100 meters
The answer is option (a).
Answer: 100 m
Explanation:
1 μm = \(10^{-6}\) m = 0,000001 m
1 nm = \(10^{-9}\) m = 0,000000001 m
1 mm = \(10^{-3}\) m = 0,001 m
∴ 100 m es la mayor longitud
What is the average velocity if the initial velocity of an object is 10 m/s & the final velocity is 28 m/s
Answers
Answer:
\(v_{1} = 19 m/s\)
Explanation:
\(v_{1} = \frac{(v_{2} + u)}{2}\), where \(v_1\) = avg. velocity, \(v_2\) = final velocity, and \(u\) = initial velocity.
A 1500-kg car goes around a flat 25-m-radius circular track at 10 m/s (approximately 22 mph). What is the maximum speed this car can go without sliding, in m/s? The coefficients of friction between the tire and the road on a dry day are µs = 1.0 and µk= 0.80. Use g = 10 m/s2.
Answers
The maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.
What is a fοrce?Fοrce is a physical quantity that describes the interactiοn between twο οbjects οr between an οbject and its envirοnment. A fοrce can cause an οbject tο accelerate, change directiοn, οr defοrm. Fοrce is a vectοr quantity, meaning it has bοth magnitude and directiοn. It is measured in units οf Newtοns (N).
The fοrmula fοr fοrce is:
F = ma
where F is the fοrce, m is the mass οf the οbject, and a is the acceleratiοn οf the οbject. This fοrmula is knοwn as Newtοn's Secοnd Law οf Mοtiοn. It states that the fοrce acting οn an οbject is directly prοpοrtiοnal tο its mass and acceleratiοn.
The maximum speed that the car can gο arοund the circular track withοut sliding can be calculated using the centripetal fοrce equatiοn:
Fc = mv² / r
where Fc is the centripetal fοrce required tο keep the car mοving in a circle οf radius r, m is the mass οf the car, v is the velοcity οf the car, and r is the radius οf the circular track.
Tο prevent sliding, the fοrce οf static frictiοn between the tires and the rοad must be greater than οr equal tο the maximum fοrce that can be exerted by static frictiοn, which is equal tο µs times the nοrmal fοrce (N = mg), where µs is the cοefficient οf static frictiοn and g is the acceleratiοn due tο gravity.
In this case, the centripetal fοrce required tο keep the car mοving in a circle οf radius 25 m is:
Fc = mv² / r = (1500 kg) x (10 m/s)² / (25 m) = 6000 N
The maximum fοrce οf static frictiοn that can be exerted between the tires and the rοad is:
Ff = µs x N = (1.0) x (1500 kg) x (10 m/s² ) = 15000 N
Tο find the maximum speed that the car can gο withοut sliding, we need tο find the velοcity that cοrrespοnds tο a centripetal fοrce οf 15000 N:
Fc = mv² / r = (1500 kg) x (vmax)² / (25 m) = 15000 N
Sοlving fοr vmax, we get:
vmax = sqrt(15000 N x 25 m / 1500 kg) = 27.39 m/s
Therefοre, the maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.
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Question 7 of 25
Maurice is comfortable with a high level of risk and wants to make a quick
return on his investment. Which type of investment would be the best option
for Maurice?
A. A certificate of deposit
B. An individual retirement account (IRA)
C. A hedge fund
D. A money market account
Answers
Answer:
A hedge fund is correct!
Explanation:
1.) What would a person who weighs 625N on Earth weigh on a planet that has the same mass as Earth but half its radius?
2.) A man whose mass is 95kg on Earth’s surface is in a spacecraft at a height of twice Earth’s radius (that is, R is 3 Earth radii) above Earth’s surface. What is his mass (not weight) there?
Answers
Answer:
Below
Explanation:
1) Gravity force =~ m1 m2 / r^2 now half the radius
= m1 m2 / ( 1/2r)^2 = 1/4 m1m2/r^2 so the force will be 1/4
625 * 1/4 = 156.25 N
2) mass does not change..it is a measure of the amount of mass an object has .... it will still be 95 kg
A skier starts from rest and accelerates down a slope 2 at 23 m/s^2. How much time required for the skier to reach a speed of 9.3 m/a? NEED AN ANSWER show work
Answers
The skier's speed at time t is
v = (23 m/s²) t
To reach a speed of 9.3 m/s, the skier would need
9.3 m/s = (23 m/s²) t
t = (9.3 m/s) / (23 m/s²)
t ≈ 0.404 s
The time required for the skier to reach given final speed is 0.404 seconds
Given the data in the question;
Since the skier starts from rest
Initial velocity; \(u = 0\)Final velocity; \(v = 9.3m/s\)Acceleration; \(a = 23m/s^2\)To determine how much time is required for the skier to reach the final speed, we us the First Equation of Motion:
\(v = u +at\)
Where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
We substitute our given values into the equation;
\(9.3m/s = 0 + ( 23m/s^2\ * t )\\\\t = \frac{9.3m/s}{23m/s^2} \\\\t = 0.404s\)
Therefore, the time required for the skier to reach given final speed is 0.404 seconds
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The smoke from the Old Man’s furnace travels up from the basement at a velocity of |.5 meters per second. Ralphie is sitting in the kitchen above and can smell the smoke within 6 seconds. What is the approximate distance that the smoke travels up from the furnace?
Answers
The approximate distance that the smoke travels up from the furnace is 9metres.
What is distance?Distance is described as a numerical or occasionally qualitative measurement of how far apart objects or points are. In the field of physics or everyday usage, distance is usually referred to a physical length or an estimation based on other criteria.
Parameters given:
Velocity = 1.5
time = 6 seconds
We know that distance = speed x time
Hence, distance = 1.5 x 6 seconds
distance = 9 meters.
Distance is a scalar quantity that refers to how much ground an object has covered in the course of its motion while we can describe displacement as a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
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What is the relationship between mass and
potential energy?
Answers
(a)Find the force (in N) of electrical attraction between a proton and an electron that are 7.4 ✕ 10−11 m apart.
(b)Compare this to the gravitational force between these particles. (Enter the gravitational force, in N.
Answers
The electrostatic force of attraction between the proton and electron is 4.2 x 10⁻⁸N.
The gravitational force between the proton and electron is 1.9 x 10⁻⁴⁷N.
a) Charge on proton = charge on electron = q = 1.6 x 10⁻¹⁹C
Distance between the proton and electron, r = 7.4 x 10⁻¹¹m
The electrostatic force of attraction between the proton and electron is given by,
F = 1/4πε₀(q²/r²)
F = 9 x 10⁹ x (1.6 x 10⁻¹⁹)²/(7.4 x 10⁻¹¹)²
F = 9 x 10⁹ x 2.56 x 10⁻³⁸/54.76 x 10⁻²²
F = 4.2 x 10⁻⁸N
b) Mass of the electron, m₁ = 9.1 x 10⁻³¹kg
Mass of the proton, m₂ = 1.67 x 10⁻²⁷kg
Distance between the proton and electron, r = 7.4 x 10⁻¹¹m
The gravitational force between the proton and electron is given by,
F = Gm₁m₂/r²
F = 6.67 x 10⁻¹¹x 9.1 x 10⁻³¹x 1.67 x 10⁻²⁷/(7.4 x 10⁻¹¹)²
F = 1.9 x 10⁻⁴⁷N
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Stop to Think 7.1 Which one is greater- the attraction of the Earth on 1 kg lead or the attraction of 1 kg of led
on the Earth?
TYY
Answers
Answer:
1 kg lead to earth is greater attraction as mass of earth is much more than 1kg lead.
Explanation:
Objects with more mass have more gravity. Gravity also gets weaker with distance. So, the closer objects are to each other, the stronger their gravitational pull is. Earth's gravity comes from all its mass
If the 100 g mass is replaced by a 200 g mass, which variables in Tnet = la change, and which
remains constant? Justify your answer.
Answers
The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.
What is the changed variable in the equation?The formula for net torque acting on an object is given as;
T(net) = Ia
where;
a is the angular accelerationI is the moment of inertiaT(net) is the net torqueThe moment of inertia of an object is given as;
I ∝ MR²
where;
M is the massR is the radius of the objectSo mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.
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Think of a book at rest on a flat leveled surface and another book (same type) that is sliding and slowing down to a complete stop on the
same surface.
a. What force(s) is on the sliding book that is not on the book at rest? Explain why.
b. If the sliding book was speeding up instead, describe how the free body diagram would be drawn differently than the book at rest.
Answers
B. The arrow in the direction the book travels is larger than the other lines and there would also be a backwards force from the drag
what is meant by reticlinear propatigation of light?
Answers
Answer:
The property of light going in a straight lines in a homogenous straightforward medium is known as rectilinear engendering of light.
Answer:
the property of light travelling in a straight lines in a homogenous transparent medium
Explanation:
A small lead ball, attached to a 1.75-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled at a constant rate of three revolutions per second and is released on the upward part of the circular motion when it is 2.1 m above the ground. The ball travels straight upward. In the absence of air resistance, to what maximum height above the ground does the ball rise?
Answers
Answer:
h = 57.6 m
Explanation:
First, we find the linear speed of the ball while in circular motion:
v = rω
where,
v = linear speed of ball = ?
r = radius of circle = length of rope = 1.75 m
ω = angular speed = (3 rev/s)(2π rad/1 rev) = 18.84 rad/s
Therefore,
v = (1.75 m)(18.84 rad/s)
v = 32.98 m/s
Now, we apply the 3rd equation of motion on the ball, when it breaks:
2gh = Vf² - Vi²
where,
g = - 9.8 m/s² (negative sign due to upward motion)
h = height covered = ?
Vf = Final Velocity = 0 m/s (since, the ball finally stops at highest point for a moment)
Vi = Initial Velocity = 32.98 m/s
Therefore,
2(- 9.8 m/s²)h = (0 m/s)² - (32.98 m/s)²
h = ( - 1088.12 m²/s²)/( - 19.6 m/s²)
h = 55.5 m
since, the ball was initially at a height of 2.1 m from ground. So, the total height from ground, will now become:
h = 55.5 m + 2.1 m
h = 57.6 m
A zebra is running at 80 kmh in front of a lion that is moving with 100 km h. If the zebra is 15 km ahead of lion, how long (in minutes) it
takes for the lion to catch the zebra if their velocities remain unchanged?
Answers
Answer: 45 minutes
Explanation:
hope this helps!
What is the answer to this?
Answers
Answer:
B
Explanation:
Answer:
B
Explanation:
ball is dropped from a height of 45 m on a floor. If at each collision with the floor the ball loses the nineteen percent of kinetic energy then the speed of the ball just after striking the floor second time, is (g = 10 m s–2)
Answers
The speed of the ball just after striking the floor a second time, is 30.0 m/s.
Initial height (h) = 45 m
Acceleration due to gravity (g) = 10 m/s²
Energy loss per collision (k) = 19% = 0.19
At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).
When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:
K₁ = PE = mgh
Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:
h = (1/2)gt²
t = sqrt(2h/g)
Using this time, we can calculate the initial kinetic energy (K₁):
K₁ = mgh = m * 10 m/s² * 45 m
Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:
K₂ = K₁ * 0.81
The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):
v₂ = v₁
To find the speed just before the first collision (v₁), we can use the equation of motion:
v = gt
Substituting the time (t) we found earlier, we have:
v₁ = g * sqrt(2h/g)
Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:
v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)
v₂ = v₁
By evaluating the expression, we find:
v₁ ≈ 30.0 m/s
v₂ ≈ 30.0 m/s
Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.
For more such questions on kinetic energy:
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If a space probe moves 20 m in 4 s, how fast is it moving?
Answers
Answer:
Speed =distance/time.
=20/4
=5m/s.
Formula: s = d/t
s = speed
d = distance
t = time
Solve using the values we are given.
s = 20/4
s = 5m/s
best of Luck!
Which landscape feature can be caused by chemical
weathering?
OU-shaped valley
O Basalt columns
O Limestone caves
Answers
Answer: Limestone Caves
Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.