ASAP answer right and I will do a giveaway

Answer:

Current in circuit = 2 amp

Explanation:

Given:

Voltage of battery = 10 V

First Resistance R1 = 1 ohm

Second Resistance R2 = 4 ohm

Resistor connected in series

Find:

Current in circuit

Computation;

Resistor connected in series

So,

Total resistance R = First Resistance R1 + Second Resistance R2

Total resistance R = 1 ohm + 4 ohm

Total resistance R = 5 ohm

Current in circuit = V / R

Current in circuit = 10 / 5

Current in circuit = 2 amp

Answer:

C. the help our understanding of the formation of planetary bodies.

Explanation:

this is the answer of PLATO

Answer:

Frequency = 25 / 10 = 2.5 Hz

Explanation:

If the wave oscillates up and down 25 times in 10 seconds, then the frequency can be calculated as follows:

Frequency = Number of oscillations / Time

In this case, the number of oscillations is 25, and the time is 10 seconds. Therefore, the frequency is:

Frequency = 25 / 10 = 2.5 Hz

So the frequency of the wave is 2.5 Hertz, which means it completes 2.5 cycles or oscillations in one second.

Answer:

a) ΔV ’= 1.66 10¹ V= 16.6 V,  b)  U = 55.64 10⁻¹² J,  c)    U_f = 1.18 10⁻¹⁰ J

d)     W = 6.236 10⁻¹¹ J

Explanation:

Capacitance can be found for a parallel plate capacitor

          C = ε₀  \(\frac{A}{d}\)  

Let's reduce the magnitudes to the SI system

           A = 9.30 cm² (1 m / 10² cm) 2 = 9.30 10⁻⁴ m²

           c = 4.50 mm (1 m / 1000 mm) = 4.50 10⁻³ m

          Co = 8.85 10⁻¹²    9.30 10⁻⁴ /4.50 10⁻³

          Co = 1.829 10⁻¹² F

when the plates separate at d = 9.60 10⁻³ m, the capcitance changes to

          C = ε₀ \frac{A}{d_1}

          C = 8.85 10⁻¹² 9.30 10⁻⁴/9.60 10⁻³

          C = 8.57 10⁻¹³ F

a) the potential difference

            C =

since the capacitor is not discharged, let's look for the initial charge

            Co = \frac{Q}{ \Delta V}

             Q = C₀ ΔV

              Q = 1.829 10⁻¹² 7.80

             Q = 14.2662 10⁻¹² C

when the condensate plates are separated

             C = \frac{Q}{ \Delta V' }

              ΔV ’= Q / C

              ΔV ’= 14.266 10⁻¹² / 8.57 10⁻¹³

              ΔV ’= 1.66 10¹ V= 16.6 V

b) the stored energy is

             U = ½ C ΔV²

for initial separation

              U = ½ C₀ ΔV²

             U = ½ 1.829 10⁻¹² 7.80²

              U = 55.64 10⁻¹² J

c) The energy for end separation;

               U_f = ½ C DV’2

                U_f = ½ 8.57 10⁻¹³ 16,6²2

                U_f = 1.18 10⁻¹⁰ J

d) The work

as there are no losses, the work is equal to the variation of the energy

                W = ΔU = U_f -U₀

                 W = 1.18 10⁻¹⁰ - 55.64 10-12

                 W = 6.236 10⁻¹¹ J

Answer:poop

Explanation:

poop

The electric field strength at a distance of 10 cm from a charge of 2 μC is 3.6 x 10⁵ N/C.

If there's a charge present in any form, an electric field is linked with every point in space. The strength and direction of the electric field are expressed by the value of E, sometimes referred to as the strength of the electrical field, electric field intensity, or simply the electric field.

The following formula determines the magnitude of the electric field generated by a point charge:

where,

E = Electrical Field Strength = ?

k = 9 x 10⁹ Nm²/C²

q = magnitude of charge

q = 2 μC = 2x 10⁻⁶ C

r = distance = 10 cm

r = 0.10 m

Therefore,

When the values are entered into the equation, we obtain:

E = 9 x 10⁹ * (2 x 10⁻⁶) / (0.1)²

E = 3.6 x 10⁵ N/C

Because of this, the electric field intensity at 10 cm from a 2 μC charge is  3.6 x 10⁵ N/C.
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Single Wire moves down, loop rotates left.

A single-wire system is a method of transmitting power or signals using only a single conductor. This is in contrast to the usual use of a pair of wires to provide a complete circuit, or an electrical cable containing (at least) two conductors for this purpose.

A single-wire transmission line is not the same as a single-wire earth return system. This is beyond the scope of this article. The latter system relies on reverse current flow through earth, using earth as a second conductor between earth terminal electrodes. A single-wire transmission line does not have a second conductor of any kind. 

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The required force exerted on the cantilever beam is calculated to be 73,600 N.

A 3000 kg deck is cantilevered over a beam as shown in the figure.

The beam serves as the fulcrum, and the deck's weight is transferred through its centre of gravity, which is located at the middle of the deck.

Center of gravity is at,

(16 + 4)/2 = 10 ft

Converting 4 ft to meters, we have 1.22 m.

Converting 10 ft to meters, we have 3.05 m.

F × 1.22 = 3.05 × 3000 × 9.81

F = 73,600 N

Thus, the force exerted on the cantilever beam is calculated to be 73,600 N.

The given question is incomplete. The complete question is attached in the attachment below.

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Answer: A

Explanation:

No Jackie is not correct. UV rays are highly energetic relative to visible light and lower energy radiation like microwave or radio. UV rays are most definitely enough to damage human skin. If you have a bottle of sunscreen near you, it will say it protects from UV rays. UV rays is what causes sunburn.

Answer:

A

Explanation:

Im   sure that its A because it provides evidence of this anwser

Answer:

the length of the simple pendulum is 0.25 m.

Explanation:

Given;

mass of the air-track glider, m = 0.25 kg

spring constant, k = 9.75 N/m

let the length of the simple pendulum = L

let the frequency of the air-track glider which is equal to frequency of simple pendulum = F

The oscillation frequency of air-track glider is calculated as;

\(F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz\)

The frequency of the simple pendulum is given as;

\(F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m\)

Thus, the length of the simple pendulum is 0.25 m.

Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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the period of a mass-spring system with the  characteristics can be calculated using the formula T = 2π√(m/k), where m is the mass of the object and k is the spring constant. the period of the mass-spring system with the given characteristics is approximately 3.14 seconds.

A mass-spring system has the following characteristics: A spring that is initially stretched or compressed has an oscillatory motion around its equilibrium position. This is referred to as a mass-spring system.The period of the mass-spring system is the time it takes for one complete cycle, including compression and extension. The period is given by the equation

`T = 2π * √(m/k)`,

where T is the period, m is the mass attached to the spring, and k is the spring constant. Let's consider an example to better understand this formula: Suppose a mass of 5 kg is attached to a spring with a spring constant of 20 N/m. What is the period of the system?

T = 2π * √(m/k) = 2π * √(5/20) = 2π * √(1/4) = 2π * (1/2) = π ≈ 3.14s

Therefore, the period of the mass-spring system with the given characteristics is approximately 3.14 seconds.

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Equipment for radio and television – Article 810. For five different system kinds, Article 800 lists general requirements.

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The recurrent transition of something between two locations or states is referred to as oscillation.

Thus, A sine wave—a wave with everlasting motion like the side-to-side swing of a pendulum or the up-and-down action of a spring with a weight—is an example of an oscillation.

An oscillation is a periodic motion that repeats itself in a regular cycle. Around an equilibrium point or mean value, an oscillating movement takes place. Periodic motion is another name for it.

An oscillation is a continuous movement that occurs throughout time, whether it is going up and down or side to side.

Thus, The recurrent transition of something between two locations or states is referred to as oscillation.

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The acceleration of the box, a =3 m/s²

Mass of the box, m = 150 kg

The force applied to the right, F = 900 N

The acceleration of the box, a =3 m/s²

Answer: what characterizes moral development in mid to late childhood is

People at this level of moral development base their decisions on what their parents and/or law enforcement says is right. Stage 3 is about social conformity. ... Stage 4 is all about law and order for all. For example, someone may think, 'If I steal, I will break the law and breaking the law is wrong.Feb 17, 2016

Explanation:

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

Answer:

The net force on the object is zero.

Explanation:

An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".

For a constant non-zero velocity the net force on the object is zero.

Velocity is defined as the change in displacement per change in time of motion.

\(v = \frac{\Delta x}{\Delta t}= \frac{x_2 - x_1}{t_2 - t_1}\)

where;

Δx is the change in displacement

Δt is the change in time motion

When the change in the displacement is same for equal time interval, the resulting velocity will be constant but non-zero in magnitude.

Also, when the net force acting on an object is zero, the object will move with a constant velocity.

\(\Sigma F_x = 0\)

Thus, for a constant non-zero velocity the net force on the object is zero.

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The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.

The percent uncertainty in measuring the light weight object is calculated as follows;

\(= \frac{0.034}{11} \times 100\%\\\\= 0.309\%\)

The uncertainty of the heavy object if the scale remains constant is calculated as follows;

\(= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs\)

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Answer:

The frequency increases by 4 because it is inversely proportional to the wavelength.

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.

Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.

Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.

Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.

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Answer:

All other SI units are derived by multiplying, dividing or powering the base units in various combinations, For example: mechanical work is force applied multiplied by distance moved and has the unit newton metre written as Nm.

Explanation:

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The flux through the circle loop of wire is determined as 7.96 N/C.m².

The flux through the circle loop of wire is calculated by applying the following formula.

Ф = EA cosθ

where;

The area of the wire is calculated as follows;

A = πr²

A = π (2 m)²

A = 12.57 m²

The flux through the circle loop of wire is calculated as;

Ф = EA cosθ

Ф = 1.5 x 12.57 x cos (65)

Ф = 7.96 N/C.m²

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Answer:

173.2

Explanation:

The centripetal acceleration of the car moving in a radius of curvature of 200 m with a velocity of 26.8 m/s is 3.591 \(m/s^2\).

The centripetal acceleration is the rate at which a body moves through a circle. Considering that velocity is a vector quantity (that is, it has both a magnitude, speed, and direction). When a body moves in a circle, its direction is constantly changing, which causes a change in velocity and acceleration.

The circle's center is where the acceleration is pointed radially. The square of the body's speed along the curve divided by the distance r from the circle's center to the moving body determines the centripetal acceleration, which has a magnitude equal to ac.

Given information:

The velocity of the car, \(v=26.8 \ m/s\),

The radius of the curvature, \(r=200\ m\).

Calculate the acceleration by the formula given below,

\(\alpha =v^2/r\)

\(\alpha\) is the acceleration,

Substitute the values,

\(\alpha =(26.8)^2/200\)

\(\alpha = 3.591\ m/s^2\)

Therefore, the centripetal acceleration of the car moving in curvature is 3.591 \(m/s^2\)

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One notable athlete who has been associated with the use of performance-enhancing drugs (PEDs) is the American professional cyclist Lance Armstrong.

Armstrong gained worldwide recognition for his unprecedented seven consecutive victories in the Tour de France from 1999 to 2005. However, his remarkable achievements were tarnished when it was revealed that he had engaged in systematic doping throughout his career.

In 2012, after years of denial, Armstrong finally admitted to using banned substances, including erythropoietin (EPO), testosterone, corticosteroids, and blood transfusions, to enhance his performance. These substances boosted his endurance and oxygen-carrying capacity, providing him with an unfair advantage over his competitors. Armstrong's confession came after substantial evidence, including testimonies from teammates and extensive investigations, exposed his involvement in one of the most elaborate and sophisticated doping schemes in sports history.

Following his admission, Armstrong was stripped of his Tour de France titles and received a lifetime ban from professional cycling. The revelations surrounding his drug use had a profound impact on the sport, shaking its credibility and raising concerns about the prevalence of doping in cycling.

Armstrong's story serves as a cautionary tale, highlighting the ethical and moral dilemmas associated with doping in sports. His case underscores the importance of maintaining the integrity of athletic competition, the significance of stringent anti-doping measures, and the need for education and awareness regarding the risks and consequences of performance-enhancing substances.

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Answer:

Therefore, the GPE of the fish from the given height is 26.19 J.

Explanation:

The gravitational potential energy (GPE) of an object at a height h is given by the formula:

GPE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

In this case, the mass of the fish is 0.3 kg, the height from which it was dropped is 9 meters, and the acceleration due to gravity on Earth is approximately 9.81 m/s². Thus, the GPE of the fish can be calculated as:

GPE = (0.3 kg) × (9.81 m/s²) × (9 m) = 26.19 J

Therefore, the GPE of the fish from the given height is 26.19 J.

I like puffins

Answer:

The maximum speed of the stone without breaking the rope is 4.33 m/s.

Explanation:

Given;

maximum tension the rope can withstand, T = 75 N

mass of the rock, m = 6 kg

radius of the circle, r = 1.5 m

As the stone spin in a vertical circle, it performs circular motion with centripetal acceleration directed inwards. The maximum centripetal force during this motion will be equal to maximum tension on the rope.

\(F_c,_m_a_x = T = \frac{MV_m_a_x^{2} }{r}\\\\V_m_a_x^{2} = \frac{Tr}{M}\\\\V_m_a_x = \sqrt{\frac{75*1.5}{6}}\\\\V_m_a_x = 4.33 \ m/s\)

Therefore, the maximum speed of the stone without breaking the rope is 4.33 m/s.

Answer:

the density of the salt water is 1030 kg/m³

Explanation:

Given;

radius of the cylindrical pool, r = 2 m

depth of the pool, h = 1.3 m

specific gravity of the salt water, γ = 1.03

The atmospheric pressure, P₀ = 1.013 x 10⁵ Pa

Density of fresh water, \(\rho _w\) = 1000 kg/m³

The density of the salt water is calculated as;

\(Specific \ gravity \ of \ salt\ water \ (\gamma _s_w) = \frac{density \ of \ salt \ water \ (\rho_{sw})}{density \ of \ fresh \ water \ (\rho_{w})} \\\\1.03 = \frac{\rho_{sw}}{1000 \ kg/m^3}\\\\\rho_{sw} = 1.03 \times 1000 \ kg/m^3\\\\\rho_{sw} = 1030 \ kg/m^3\)

Therefore, the density of the salt water is 1030 kg/m³