as a car drives past a person standing on a sidewalk, the driver keeps a hand on the horn. how does the pitch of the horn differ for the driver and the person standing on the sidewalk?

Answer:

the time period is 22.63 years

Explanation:

The computation of the number of years taken is as follows:

According to the Keplers law

\(T^2 \propto R^3\)

Here T denotes the time period

And, R denotes the average distance among the sun and planet

Now let us assume for earth

R_1 & T_1 be 1 year

So, for Planet

\(R_2 = 8R_1 , T_2 = ?\)

Now applied Keplers law

\((\frac{T_2}{T_1})^2 \propto (\frac{R_2}{R_1})^3\\\\(T_2)^2 = (\frac{8R_1}{R_1})^3 \times 1^2\\\\(T_2)^2 = 512\\\\T_2 = 22.674\)

So, the time period is 22.63 years

The problem feature of the Milky Way's rotation that led to the proposal of dark matter is the observation that stars and gas in the outer regions of galaxies, including the Milky Way, are moving at unexpectedly high velocities, defying expectations based on visible matter alone.

The problem arises from the understanding of gravity and the laws of motion. Based on the visible matter observed in galaxies, such as stars and gas, the expected velocities of objects in the outer regions should decrease as their distance from the galactic center increases.

However, observations have shown that the velocities remain relatively constant or even increase, indicating the presence of additional mass not accounted for by visible matter.

To explain this discrepancy, scientists hypothesized the existence of dark matter, which is an invisible and as-yet-undetected form of matter that does not interact with light but exerts gravitational effects.

The presence of dark matter can explain the observed high velocities in the outer regions of galaxies, including the Milky Way, and reconcile them with our understanding of gravity and motion.

Therefore, the unexpected high velocities of stars and gas in the outer regions of galaxies, including the Milky Way, challenged expectations based solely on visible matter, leading to the proposition of dark matter.

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Answer:

physical

Explanation:

As the pressure on the gas increases, the volume will decrease and the temperature will increase. Thus option c is correct.

A gas that obeys the gas laws regardless of the pressure and temperature is known as an ideal gas. The particles of an ideal gas have no intermolecular forces and have negligible volume.

A model of an ideal gas is shown here. A student designs an experiment to test the impact of increasing the pressure on the system. Which prediction is most likely to be supported by the data?

A) As pressure on the gas increases, the volume and temperature will both decrease.

B) As the pressure on the gas increases, the volume and temperature will also increase.

C) As pressure on the gas increases, the volume will decrease and the temperature will increase.

D) As pressure on the gas increases, the volume will increase and the temperature will decrease.

Here,

The variation of volume and temperature according to the variation in pressure can be obtained from the ideal gas equation,

            PV = nRT

From the equation we can write that,

P ∝ 1/V

P ∝ T

Therefore, the increase in pressure can cause the decrease in volume and increase in temperature.

Hence the correct option is

(c) As the pressure on the gas increases, the volume will decrease and the temperature will increase.

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A total differential is an equation in which all the differentials can be integrated independently of each other. To verify that the given expressions are total differentials, we must check if they meet the conditions of being an exact differential function.The given expression is not an exact differential function.

According to the exact differential function, an expression dQ should be equal to the sum of two partial derivatives of the same function. i.e, dQ= dP+ dRA primitive function of an expression is obtained by integrating the given expression partially. Let's solve the given expressions, one by one:

1. Expression : (x² + 2xy-y²)dx + (x²-2xy - y²)dy. Now, we need to find the partial derivatives of the above function with respect to x and y.∂P/∂x = x² + 2xy - y²  ∂Q/∂y = x² - 2xy - y².

On verifying, we get:∂P/∂x = ∂Q/∂y.

Hence, the given expression is an exact differential function.

To find the primitive function, we need to integrate any one of the partial derivatives with respect to x and other with respect to y.

∴ P(x,y) = ∫(x² + 2xy - y²)dx = x³/3 + x²y - xy² + C1 and ∴ Q(x,y) = ∫(x² - 2xy - y²)dy = x²y - y³/3 + C2.

Therefore, the primitive function of the expression is: P(x,y) = Q(x,y) = x³/3 + x²y - xy² - y³/3 + C2.

Expression : (2xcosy - y² sinx) dx + (2ycosx - x² siny) dy. Now, we need to find the partial derivatives of the above function with respect to x and y.∂P/∂x = 2cosy  ∂Q/∂y = 2ycosx.

On verifying, we get:∂P/∂x ≠ ∂Q/∂y .

Hence, the given expression is not an exact differential function.

Therefore, there does not exist a primitive function for the given expression.

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The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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0.05*0.2=0.05*0.15+0.015*m2',

m2'=1/6 m/s,

m2'=0.17 m/s

N I C E - D A Y!

Answer:

Acceleration is -1.2 m/s² and distance covered is 135 m.

Explanation:

A train going at a speed of 18m / s brakes and stops in 15s calculates its acceleration and the distance traveled when braking

Given that,

The initial speed of the train, u = 18 m/s

Final speed, v = 0

Time, t = 15 s

We need to find acceleration and distance traveled when braking. Let a is acceleration and distance traveled.

Acceleration,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18}{15}\\\\a=-1.2\ m/s^2\)

Using third equation of motion,

\(v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-18^2}{2\times (-1.2)}\\\\d=135\ m\)

Hence, acceleration is -1.2 m/s² and distance covered is 135 m.

The frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.

To find the answer, we need to know more about the friction.

                    \(m=140*10^{-3} kg\\w=1 rev/s=2\pi rad/s\\r_1=14*10^{-2}m\\g=9.81m/s^2\\\)

                    \(f=F_c=ma_c=m*r_1w^2\\f=140*10^{-3}*14*10^{-2}*4*\pi ^2=0.77N\)

                              \(f_s=kN,\\\\Where, \\N=mg\\\\k=\frac{f_s}{mg}\)

                         \(F_c=f_s=mrw^2=140*10^{-3}*24*10^{-2}*4\pi ^2\\f_s=1.325N\)

                   \(k=\frac{1.325}{140*10^{-3}*9.81}=0.964\)

Thus, we can conclude that, the frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.

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Answer:

d = 2.54 [m]

Explanation:

Through the theorem of work and energy conservation, we can find the work that is done. Considering that the energy in the initial state is only kinetic energy, while the energy in the final state is also kinetic, however, this is zero since the body stops.

\(E_{k1}+W=E_{k2}\\\)

where:

W = work [J]

Ek1 = kinetic energy at initial state [J]

Ek2 = kinetic energy at the final state = 0.

We must remember that kinetic energy can be calculated by means of the following expression.

\(\frac{1}{2} *m*v^{2}-W=0\\W= \frac{1}{2} *4*(5)^{2}\\W= 50 [J]\)

We know that work is defined as the product of force by distance.

\(W=F*d\)

where:

F = force [N]

d = distance [m]

But the friction force is equal to the product of the normal force (body weight) by the coefficient of friction.

\(f=m*g*0.5\\f = 4*9.81*0.5\\f = 19.62 [N]\)

Now solving the equation for the work.

\(d=W/F\\d = 50/19.62\\d = 2.54[m]\)

Answer: Created Fall 2016 by Ronald Wilson Inductive reasoning uses a set of specific observations to reach an overarching conclusion; it is the opposite of deductive reasoning. So, a few particular premises create a pattern which gives way to a broad idea that is likely true.

Explanation: No explanation lol. But I hope this is helpful!

The equation for conservation of energy with friction is PEi + KEi + Wfriction = PEf + KEf.

Friction is a force that resists the relative motion of two surfaces that are in contact with each other. It is a force that works to oppose motion between two surfaces and is created when two objects rub against each other. Friction is the result of two surfaces interacting and the electrons of each surface reacting with the other. The rougher the surfaces, the more friction is generated. Friction can cause objects to heat up, slow down, or even stop.

The equation for conservation of energy states that the total energy of a system must remain constant. Friction is a form of energy, so it must be taken into account in the equation. In this case, the equation is modified to include the work done by friction (Wfriction) on the system. Thus, the equation for conservation of energy with friction is PEi + KEi + Wfriction = PEf + KEf.

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Answer:

he reason would be straightforward in case you have complete the test already. The bottles have a undeniable volume of air interior them.. you have often happening that gases do strengthen in case of heating.So, the air interior the bottle in sunlight expands.. often, in case you don't have an go out course for the air, it would desire to develop the stress interior the bottle or if is extra suitable than a undeniable decrease.It may blow up the bottle too. As u would desire to have considered some bicycle tires explode while saved below warm sunlight.Here, even with the undeniable fact that, we are offering an get away course for the air interior the bottle via keeping a balloon above.So the elevated air escapes into the balloon thereby swelling it.While the balloon saved below would not have a lot variations to observe. Its truly an straightforward test to do..

Explanation:

Answer:

240 N

Explanation:

La fuerza de la tensión del cable es la masa por la aceleración (F=ma).

F = (60)(4) = 240 N

The volume of the material would change by 0.00012%.

Material is anything that has physical existence and can be perceived by one or more of the five senses. It is anything that has mass and occupies space. Examples of materials include wood, metal, plastic, paper, fabric, glass, stone, water, air, and living organisms.

The coefficient of volume thermal expansion (β) is related to the coefficient of linear thermal expansion (α) by the equation β = 3α. Therefore, the value of β for the given material would be 3(4 × 10-5K-1) = 0.00012K-1.
This means that for every degree Kelvin of temperature change, the volume of the material would change by 0.00012%.

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The kinetic energy acquired by the ball from the bat is 100 J.

Kintetic energy :- kinetic energy is the energy an object has because of its motion.

The force with which the bat strikes the ball is 2×10^4 N.

Bat stays in contact with ball for a distance of 5×10^-3m.

Kinetic energy acquires by the ball = Work done by the ball.

kinetic energy = F * d

(where f is force applied by the bat on the ball and d is displacement of ball during this force applied)

Now, substituting the values given in the question, we have:

KE = 2×10^4 * 5×10^-3

KE = 100 J

Hence, Kinetic energy acquired by the ball from bat is 100J.

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To determine the position u of the mass at any time t, we can use the equation of motion for a mass-spring system without damping:n m * u''(t) + k * u(t) = 0

m = 2 lb / (32.2 ft/s^2) = 0.062 lb·s^2/ft

The spring constant k can be determined using Hooke's law:

k = F / x

where F is the force exerted by the mass and x is the displacement. In this case, the force F is the weight of the mass, and the displacement x is 6 in:

k = (2 lb) / (6 in) = (2 lb) / (6 in) * (1 ft/12 in) = 0.111 lb/ft

The equation of motion now becomes:

0.062 * u''(t) + 0.111 * u(t) = 0

To solve this second-order linear homogeneous differential equation, we assume a solution of the form u(t) = A * cos(ωt + φ).

Substituting this assumed solution into the equation of motion, we get:

-0.062 * A * ω^2 * cos(ωt + φ) + 0.111 * A * cos(ωt + φ) = 0

-0.062 * ω^2 + 0.111 = 0

Solving for ω, we get:

ω = sqrt(0.111 / 0.062) = 2.258 rad/s

From ω, we can determine the frequency f and period T:

f = ω / (2π) = 2.258 / (2π) ≈ 0.359 Hz

T = 1 / f ≈ 2.786 s

The amplitude A is determined by the initial conditions. When the mass is pulled down an additional 3 in (0.25 ft) and released, it reaches its maximum displacement, so A = 0.25 ft.

Therefore, the position u of the mass at any time t is given by:

u(t) = 0.25 * cos(2.258t)

To draw the graph of u(t), plot the position u on the y-axis and time t on the x-axis, using the equation u(t) = 0.25 * cos(2.258t). The graph will be a cosine wave with an amplitude of 0.25 ft.

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Answer:

The answer is C.) 300,000,000 m/s

Explanation:

Light travels at a constant rate of 300,000,000 m/s. this can be determined by dividing the distance (144,000,000,000 meters) by the time (480 seconds). that's pretty fast. in fact, nothing can travel any faster than this. ever.

Light travels at a constant rate of 300,000,000 m/s. This can be determined by dividing the distance (144,000,000,000 meters) by the time (480 seconds). That's pretty fast. In fact, nothing can travel any faster than this. Ever.

The speed of water in the constriction is faster when compared to the rest of the pipe.

The venturi effect consists of a physical phenomenon applied in fluid dynamics in which the pressure of flow decreases when there is a constraint in the conduct, accompanied by an increase in velocity of the fluid due to a decrease in cross-sectional area of the conduct.

The constriction is said to have a lower radius when compared to the rest of the pipe.

Applying the equation of continuity, A₁ v₁ = A₂ v₂

where, A is the area

v is the velocity

It is said from the above equation that, if area decreases velocity increases and if area increases velocity decreases, as velocity and area are inversely proportional to each other.

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The battery in an electric circuit provides electricity to the rest of the circuit using electrical energy. Also changes the form of the electrical energy.

Energy is defined as the capacity of a physical system to perform work. The ability of an atom's charged particles to initiate an activity or move an object is known as electrical energy. Electrical energy is produced by the transfer of electrons between atoms.

An electro-chemical device known as a battery energy storage system  charges energy from the grid or a power plant and then discharges that energy later to produce electricity or other grid services as needed.

The battery in an electric circuit changes chemical energy into electrical energy and also provides electricity to the rest of the circuit.

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Answer:

a

Explanation:

Undersea mountain ranges are mountain ranges that are mostly or entirely underwater, and specifically under the surface of an ocean. If originated from current tectonic forces, they are often referred to as a mid-ocean ridge. In contrast, if formed by past above-water volcanism, they are known as a seamount chain.

Answer:

Acceleration of one cyclist=\(2.67m/s^2\)

Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.

Explanation:

We are given that

Initial velocity of one cyclist, u=0 m/s

Final velocity of one cyclist, v=8m/s

Time, t=3 s

Initial velocity of another cyclist, u'=0

Final velocity of another cyclist, v'=30m/s

Time, t'=8 s

We know that

Acceleration, \(a=\frac{v-u}{t}\)

Using the formula

\(a=\frac{8-0}{3}=\frac{8}{3}=2.67m/s^2\)

Acceleration of one cyclist=\(2.67m/s^2\)

Acceleration of another cyclist, a'=\(\frac{30-0}{8}m/s^2\)

Acceleration of another cyclist, a'=\(3.75m/s^2\)

Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.

Answer:

Invasive species alter and degrade the environment, and have a negative effect on both native species and the people who live and work there. The impacts of invasive species include: Reduced biodiversity. Decreased availability and quality of key natural resources.

Explanation:

Hope this helps!

Answer:

Friction is another force that energy gets "wasted" on in the dragging. Therefore, the machine gives you less mechanical advantage when too much friction is involved because it wastes energy. It also makes it less efficient!

Answer:

C. Increasing the temperature increases the reaction rate.

Explanation:

The reaction rates aren't listed in any specific order, and haven't been combined.

Increasing concentration on it's own increases the reaction rate, increasing the temperature on it's own increases the reaction rate, and adding metal on it's own increases the reaction rate.

Since the question is referring specifically to the effects that temperature has on the reaction rate of the reaction being tested, all we need to do is look at the "Original" Conditions and the "Higher temperature" Conditions on the table.

The reaction rate before changing anything (Original conditions) was 10 seconds. After increasing the temperature (Higher temperature conditions), the reaction rate was 5 seconds.

5 seconds is less than 10 seconds, which means that less time was taken for it to react, so that means that the reaction rate was faster when the temperature was increased.

Answer:

Find the vertical velocity of the rider just as they leave the top of the ramp:

Vertical component of velocity = 5 m/s

Horizontal component of velocity = 10 m/s

Total velocity = √(5² + 10²) = √125 ≈ 11.2 m/s

Calculate the time it takes for the rider to reach the maximum height:

Initial vertical velocity = 5 m/s

Final vertical velocity = 0 m/s

Acceleration due to gravity = -9.81 m/s²

Using the kinematic equation vf = vo + at, where vf = 0, vo = 5 m/s, and a = -9.81 m/s²:

t = (vf - vo) / a = (0 - 5) / (-9.81) ≈ 0.51 s

Calculate the maximum height that the rider will reach above the ground:

Using the kinematic equation d = vot + 1/2at², where d is the maximum height above the ground, vo = 5 m/s, a = -9.81 m/s², and t ≈ 0.51 s:

d = 5(0.51) + 1/2(-9.81)(0.51)² ≈ 1.52 m

Therefore, the maximum height that the rider will reach above the ground is approximately 1.52 meters.

Answer:

Explanation:

v=u+at

Final velocity v=0 , u=35m.s, a=-a , t=0.02

a=u/t = 35/0.02 = 1750 m/s2

force = mass * acceleration = 0.15 * 1750 = 262.5N