Arrange the values according to magnitude.

54000

9.0 * 10 ^ - 6

7.8 * 10 ^ - 6

3.4 * 10 ^ - 2

2.5 * 10 ^ 5

Answer:

Increases, decreases

Explanation:

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

convection is not form of energy

A change in the size of the moon jellies' resource population can change the number of births in the moon jelly population because the big size of the resources can produce more births.

When there is more energy storage molecules present in the moon jellies, they can reproduce more, in more births. Fewer deaths would also lead to the jelly population increasing. The sea turtle population, and the moon jellies consumer population is also decreased.

There must be a change to the birth rate or the death rate in the moon jelly population. Within a population, organisms are born and dying continuously. If the number of births and deaths in a given time interval are equal, then the population size will remain stable.

So we can conclude that a large population of resources will lead to more births.

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Answer:

The H—C—H bond angle in methane is the tetrahedral angle, 109.5°. This angle is obtained when all four pairs of outer electrons repel each other equally. The bond angles in ammonia and in water are less than 109.5° because of the stronger repulsion by their lone pairs of electrons.

Explanation:

hope it helps!

Baking soda can be used to cure acidity as it a base and has a pH value of around 8-9.

According to the Arrhenius concept, base is defined as a substance which yields hydroxyl ions on dissociation.These ions react with the hydrogen ions of acids to produce salt in an acid-base reaction.

Bases have a pH higher than seven as they yield hydroxyl ions on dissociation.They are soapy in touch and have a bitter taste.According to the Lowry-Bronsted concept, base is defined as a substance which accepts protons .Base react violently with acids to produce salts .Aqueous solutions of bases can be used to conduct electricity .They can also be used as indicators in acid-base titrations.

They are used in the manufacture of soaps,paper, bleaching powder.Calcium hydroxide ,a base is used to clean sulfur dioxide gas while magnesium hydroxide can be used as an antacid to cure acidity.

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Answer:

N2 + H20

Explanation:

chemical equation balancer

The element with the electron configuration, 1s2 3s2 3p6 3s2 3p6 3d6 4s2, will be iron.

In the electronic configuration of elements, the number of electrons possessed by the element is shared into the orbitals according to their energy levels.

The electrons are first shared in orbitals in the same energy level before pairing starts.

Also for neutral atoms, the number of electrons is equivalent to the number of protons. The number of protons in itself represents the atomic number of elements.

Thus, considering this electron configuration, 1s2 3s2 3p6 3s2 3p6 3d6 4s2; the total number of electrons in all the orbitals is 26. The element with the atomic number of 26 is iron.

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Answer:

Molecular formulas describe the exact number and type of atoms in a single molecule of a compound. The constituent elements are represented by their chemical symbols, and the number of atoms of each element present in each molecule is shown as a subscript following that element's symbol.

Explanation:

hope this helped !

Answer:

0.753 grams of copper metal are required to react with 4.00 grams of silver nitrate to produce copper (II) nitrate

Explanation:

mass = moles * Mr

                      Equation of this reaction:

---------------------------------------------------------------------------------------------

Find moles of silver nitrate:

4 = moles * 170

→ \(\frac{2}{85}\) moles

so find the mass of copper metal:

mass =  \(\frac{1}{85}\) * 64

mass of copper is 0.753 grams.

Answer:

Answer: 1.38 moles

Explanation: According to Avogadro's law, 1 mole of every substance contains Avogadro number of particles (atoms, molecules or ions) i.e.6.023*10^23  particles.

Given : 1 mole molecule of water contains 6.023*10^23 molecules of water.

6.023*10^23  molecules are present in = 1 mole

 8.30*10^23molecules will be present in =

1/6.023*10^23 ×8.30*10^23=1.38 moles

Thus  molecules is equal to 1.38 moles.

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Answer:

66.7%

Explanation:

The reaction for the titration of the excess ferrous ion is:

We calculate the moles of Fe⁺² from the used moles of KMnO₄:

Then we substract those 0.30 mmol from the original amount used:

The reaction between ferrous ammonium sulfate and MnO₂ is:

So we convert those 3.5 mmol Fe⁺² that were used in this reaction to MnO₂ moles:

Then we convert MnO₂ to Mn₃O₄, using the reaction:

Finally we convert Mn₃O₄ moles to grams:

And calculate the percent

Answer:

hello your question is incomplete attached below is the complete question

Pyridinium  ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH  and after the reaction it comes out neutral.

N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while

B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion

Explanation:

Pyridine ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH  and after the reaction it comes out neutral.

N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while

B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion

attached below is the remaining part of the solution

Answer:

they're

Explanation:

solid, liquid and gas

The electric current is  0.025 A

Electric current refers back to the go with the flow of energy in an electronic circuit and to the amount of strength flowing through a circuit. it's far measured in amperes (A). the bigger the cost in amperes, the more energy is flowing within the circuit.

Ag+ + e¯ →Ag

1F deposits 107.87 g/mol (molecular mass) of silver

1F = 96500 C

Let, 107.87 g/mol needed = 96500 C

Number of coulombs required to deposit 0.3650 g of silver =(96500/107.87) 0.3650  

Q = 326.5 C

According to Faraday’s law, Q = I x t

I = 326.5 C / (216 x 60 s) = 0.025 A

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Answer:

What is the question?

Explanation:

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Answer:

The percent of CaCO₃ in the sample is 75%.

Explanation:

We can find the percent of CaCO₃ in the sample knowing that 30 g of Ca are present in 100 g of CaCO₃.

First, we need to find the number of moles of Ca, and since the ratio of Ca in CaCO₃ is 1:1 we can find the percent of CaCO₃ in the sample as follows:

\( mol CaCO_{3} = mol Ca = \frac{30 g}{40 g/ 1 mol} = 0.75 mol \)

Now, the mass of CaCO₃ is:

\( m CaCO_{3} = 0.75 moles*100 g/mol = 75 g \)

Finally, the percent of CaCO₃ in 100 g of the sample is:                                        

\( \% CaCO_{3} = \frac{75 g}{100 g}*100 = 75 \% \)                  

Therefore, the percent of CaCO₃ in the sample is 75%.

I hope it helps you!                

Answer:

gain at least one electron

Answer:

59.8287

Explanation:

I put that answer in and it is correct.

Answer:

gravity

Explanation:

Chlorine is the most commonly used chemical sanitizer agent and there are so many factors that influences the effectiveness of these chemical sanitizers like- Temperature, Concentration, Contact time, Water Hardness, pH but bacterial cell history does not affect the efficiency of sanitizers.

Factors influencing the effectiveness of chemical sanitizer:

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The reaction for the formation of phosgene from carbon monoxide and chlorine. The  rate law for this reaction is R = k [CO] [Cl₂].

The reaction is as follows :

CO + Cl₂ --->  COCl₂

The general rate equation for the reaction is :

R =  k [CO]^m [Cl₂]^n

Where,

The r is the rate of the reaction

The k is the rate constant

The [CO] and [Cl₂] are the molar concentrations of the each reactant

The  m and n are the reaction orders for the each reactant

The overall order is equals to the sum of all the individual orders.

overall order m + n = 2.

n = 2 - m = 2 - 1 = 1

The reaction is first order in Cl₂.

Thus the rate law for this reaction is R = k [CO] [Cl₂]..

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Answer:

53.5gram.

Explanation

Explanation: number of moles = number of molecule ÷ avogadro's number. => moles = 6.022 × 10²³ ÷ 6.022 × 10²³ = 1 mole. mass of 1 mole of NH4Cl = 1 × molar mass.

Answer:

Nucleus.

Explanation:

The sponge is a multicellular organism that consists of pores that allows water to move through the body. Sponges belong to the kingdom Animalia and phylum Porifera. Sponges can reproduce by budding. Sponges are placed in kingdom Animalia because they are unable to make their own food, made of more than one cell, and absence of cell wall.

Answer:

B

Explanation:

Balance the following chemical equations:

1. N2 + 3 H2 → 2 NH3

Ex: Synthesis reaction

2. 2 KClO3 → 2 KCl + 3 O2

Single Replacement reaction

3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl

Decomposition reaction

4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2

Double Replacement reaction

5. 2 H2 + O2 → 2 H2O

Combustion reaction

6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2

Synthesis reaction

7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Decomposition reaction

8. C3H8 + 5 O2 → 3 CO2 + 4 H2O

Combustion reaction

9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O

Double Replacement reaction

10. 4 P + 5 O2 → 2 P2O5

Synthesis reaction

11. 2 Na + 2 H2O → 2 NaOH + H2

Single Replacement reaction

12. 2 Ag2O → 4 Ag + O2

Decomposition reaction

13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

Combustion reaction

14. 2 KBr + MgCl2 → 2 KCl + MgBr2

Double Replacement reaction

15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O

Double Replacement reaction

16. C5H12 + 8 O2 → 5 CO2 + 6 H2O

Combustion reaction

17. 4 Al + 3 O2 → 2 Al2O3

Synthesis reaction

18. Fe2O3 + 2 Al → 2 Fe + Al2O3

Single Replacement reaction

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INFORMATION:

We have the next balanced ionic equation:

2Al(s) + 3Cu²⁺(aq) → 2Al³⁺(aq) + 3Cu(s)

And we must determine the half-reaction that represents the reduction that occurs

STEP BY STEP EXPLANATION:

To determine it we must use the given information about the ionic charge of atoms given in the formula

We can see that there is a reduction in the formula since we initially have 3Cu²⁺ and then we obtain 3Cu

Since the initial ionic charge for Cu is 2+, we need to add 2e¯ to obtain Cu. Then, the reduction half-reaction would be Cu²⁺ + 2e¯ → Cu

ANSWER:

(4) Cu²⁺ + 2e¯ → Cu

Answer:

• There are 1.8 mol of nitrogen in 0.30 mol of caffeine.

• There are 21.6 mol of hydrogen in 2.7 mol of caffeine.

• There are 16.0 mol of carbon in 2.0 mol of caffeine.

• There are 5.0 mol of oxygen in 2.5 mol of caffeine.

Explanation:

Answer: 6.23

Explanation:

1) solve for pH  

pH=-log (H3O+) = - log 1.7 X 10^-8 =7.77

2) now do 14-pH  = 14 -7.77=6.23