answered Which of the following values are solutions to the inequality -9>-4+5x

Answer:

y < (3/2) |x - 3| +2

Step-by-step explanation:

All participants indicate their likelihood of scheduling a campus visit on a 10-point scale Paired samples t-test.

What is campus?
A college or university's campus is traditionally the area of land on which those institutions' buildings are located. Libraries, lecture halls, dorms, student centres, dining halls, and park-like settings are typically found on college campuses.

An academic or non-academic institution's buildings and grounds are collectively referred to as a campus in modern times. The Apple Campus and the are two examples. The word, which is derived from a Latin word for "field," was first used in 1774 to refer to the sizable field next to Nassau Hall of the College of New Jersey (currently Princeton University). Princeton and the small neighbouring town were separated by a field.

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Answer:

82

Step-by-step explanation:

78+4

Answer:

Below

Step-by-step explanation:

You are given miles ( 250)   and hours ( 3.5)

I suppose you want miles per hour  =   250 mi / 3.5 hr = 71.4 m/hr

(a) The power series solution for the Associated Laguerre Equation must terminate because the equation satisfies the necessary termination condition for a polynomial solution.

(b) The general expression for the power series coefficients in terms of the first coefficient can be obtained by using recurrence relations derived from the differential equation.

(a) The power series solution for the Associated Laguerre Equation, when expanded as a polynomial, must terminate because the differential equation is a second-order linear homogeneous differential equation with polynomial coefficients. Such equations have polynomial solutions that terminate after a finite number of terms.

(b) To find the general expression for the power series coefficients in terms of the first coefficient, one can use recurrence relations derived from the differential equation. These recurrence relations relate each coefficient to the preceding coefficients and the first coefficient. By solving these recurrence relations, one can express the coefficients in terms of the first coefficient and obtain a general expression.

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The required fuel for the nighttime trip is approximately 5,610 gallons.

To calculate the required fuel for the nighttime trip, we need to consider the distance of the trip, the aircraft's airspeed, the fuel consumption rate, and the effect of the tailwind.

Given that the trip is 2,425 miles and the aircraft's airspeed is 570 miles per hour, we can determine the total flight time by dividing the distance by the airspeed. In this case, the flight time is approximately 4.25 hours.

Next, we need to account for the fuel consumption rate. The aircraft burns 3,000 gallons of fuel per hour. Multiplying the flight time by the fuel consumption rate gives us the total fuel consumed during the trip, which is approximately 12,750 gallons.

Now, let's factor in the effect of the tailwind. The tailwind of 32 miles per hour will increase the groundspeed of the aircraft. To calculate the groundspeed, we subtract the tailwind speed from the airspeed. In this case, the groundspeed is 570 - 32 = 538 miles per hour.

To determine the fuel consumption adjusted for the groundspeed, we divide the distance of the trip by the groundspeed. This gives us the adjusted flight time of approximately 4.51 hours. Multiplying the adjusted flight time by the fuel consumption rate gives us the fuel consumption adjusted for the tailwind, which is approximately 13,530 gallons.

Therefore, the required fuel for the nighttime trip is approximately 5,610 gallons (13,530 - 12,750).

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Answer:

19

Step-by-step explanation:

115+10P=305

305-115=190

190/10=19

The correct option is B.

The value will be  = 25

What is the Angles of the triangle?

The sum of the two interior angles that are not adjacent to it equals the exterior angles of a triangle, but the interior angles of a triangle always add up to 180°. Subtracting the angle of the desired vertex from 180° is another method for determining a triangle's exterior angle.

∠ACE = (2x+2)°

∠ECB = (5x+ 3)°

Angles ACE and ECB are additional angles according to the linear postulate, as seen in the attached diagram.

Therefore:

∠ACE+∠ECB = 180°

(2x+2)+(5x+3) = 180

2x+ 5x+ 2+ 3 = 180

7x + 5 = 180

7x = 175

x= 175/7

x = 25

Thus the value will be  = 25

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I understand that the question you are lookin for is :

Lines de and ab intersect at point c. lines d e and a b intersect at point c. angle a c e is (2 x 2) degrees. angle e c b is (5 x 3) degrees. what is the value of x?

A.12

B. 25

C. 38

D. 52

Answer:

The width is 24 inches and the length is 120 inches.

Step-by-step explanation:

Let x represent the width of the carpet

The length can be represented by x + 96

Create an equation:

x + x + x + 96 + x + 96 = 288

Add like terms and solve for x:

4x + 192 = 288

4x = 96

x = 24

So, the width is 24 inches. Plug this into x + 96 to find the length:

x + 96

24 + 96

= 120

So, the width is 24 inches and the length is 120 inches.

Answer:

See pic

Step-by-step explanation:

To prove the first absorption law from table 1, we need to show that for any sets a and b, the union of a and the intersection of a and b is equal to a.

We can start by using the definition of union and intersection:

a ∪ (a ∩ b) = {x : x ∈ a or x ∈ (a ∩ b)}

and

a = {x : x ∈ a}

To prove that these two sets are equal, we need to show that they contain the same elements.

First, let's consider the elements in a ∪ (a ∩ b).

If x ∈ a, then x ∈ a ∪ (a ∩ b) since it satisfies the condition x ∈ a.

If x ∈ (a ∩ b), then x ∈ a ∪ (a ∩ b) since it satisfies the condition x ∈ (a ∩ b), which means that x ∈ a and x ∈ b. But since x ∈ a, we can conclude that x ∈ a ∪ (a ∩ b) as well.

Therefore, every element that belongs to a or (a ∩ b) also belongs to a ∪ (a ∩ b).

Now, let's consider the elements in a.

If x ∈ a, then x ∈ a since it satisfies the condition x ∈ a.

If x ∉ a, then x cannot belong to the intersection of a and b, since by definition, a ∩ b only contains elements that belong to both a and b. Therefore, x cannot belong to a ∪ (a ∩ b) either, since it doesn't satisfy any of the conditions.

Therefore, every element that belongs to a also belongs to a ∪ (a ∩ b).

Since we have shown that every element in a ∪ (a ∩ b) also belongs to a, and every element in a belongs to a ∪ (a ∩ b), we can conclude that a ∪ (a ∩ b) = a.

Thus, we have proven the first absorption law from table 1 for any sets a and b.

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The sampling distribution of the mean is approximately normal, follows the Central Limit Theorem, has a mean equal to the population mean, and decreases in variability with larger sample sizes.

The sampling distribution of the mean is a distribution that represents the possible values of the sample means obtained from repeated sampling of a population. It tends to follow a normal curve shape, regardless of the shape of the population distribution, as long as the sample size is large enough due to the Central Limit Theorem.

The mean of the sampling distribution is equal to the population mean, making it an unbiased estimator. Additionally, the standard deviation of the sampling distribution, known as the standard error, decreases as the sample size increases, indicating that larger samples lead to more precise estimates of the population mean with reduced variability in the sample means.

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Answer:

0.799 to the nearest hundredth is 0.80

Hope this helps!

Answer:

Hi there!

Your answer is:

Question was unclear! See below for answer possibilities!

Step-by-step explanation:

IF "-1" MEANS MULTIPLY BY NEGATIVE 1

2((42) -1 ))

2(-42)

IF "-1" MEANS SUBTRACT 1

2((42)-1)

2(41)

Hope this helps

The new expression is 4 times the old expression

The old expression is given as:

A = 3r^2h^2

Rewrite the expression as

A = 3(rh)^2

When rh increases by 100%, the new value of rh becomes

New rh = rh + rh

This gives

New rh = 2rh

So, the equation of the new expression is:

New expression = 3(2rh)^2

Evaluate the exponent

New expression = 3 * 4 (rh)^2

Substitute A = 3(rh)^2 in the above expression

New expression = 4 * A

This gives

New expression = 4A

Hence, the new expression is 4 times the old expression

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The team made 16 1-point shots and 42 2-point shots.

We can set up two variables to represent the number of 1-point shots and 2-point shots, let's call them x and y respectively.

Using the information given, we can set up two equations to represent the total number of successful shots (x + y = 58) and the total number of points scored (1x + 2y = 100).

Now we have a system of linear equations that we can solve simultaneously:

x + y = 58

1x + 2y = 100

Solving for x in the first equation: x = 58 - y

Substituting that into the second equation: 1(58 - y) + 2y = 100

Expanding the left side: 58 - y + 2y = 100

Combining like terms: 58 = 100 - y

Adding y to both sides: 58 + y = 100

Solving for y: y = 42

Now that we know the value of y, we can use either equation to find the value of x:

x + y = 58

x + 42 = 58

Subtracting 42 from both sides: x = 16

So the team made 16 1-point shots and 42 2-point shots.

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Both ψ+ = r f(r + vt) and ψ- = r f(r - vt) satisfy the spherical scalar wave equation ∂t² (∂²ψ/∂r²) - (v²/r²) (∂/∂r) (r²(∂r/∂ψ)) = 0, where f is an arbitrary function.

To demonstrate that ψ+ and ψ- are solutions to the spherical scalar wave equation, we substitute these functions into the equation and evaluate the derivatives involved.

For ψ+:

∂²ψ+/∂t² = r²∂²f/∂t²

∂/∂r (r²∂ψ+/∂r) = r²(vf'' + 2vf' + f')

For ψ-:

∂²ψ-/∂t² = r²∂²f/∂t²

∂/∂r (r²∂ψ-/∂r) = r²(-vf'' + 2vf' + f')

Substituting these derivatives into the wave equation:

∂²ψ+/∂t² - (v²/r²) ∂/∂r (r²∂ψ+/∂r)

= r²∂²f/∂t² - (v²/r²) (r²(vf'' + 2vf' + f'))

= r²(∂²f/∂t² - v²f'' - 2v²f' - v²f')

= 0 (since the original function f satisfies the wave equation)

Similarly, for ψ-:

∂²ψ-/∂t² - (v²/r²) ∂/∂r (r²∂ψ-/∂r)

= r²∂²f/∂t² - (v²/r²) (r²(-vf'' + 2vf' + f'))

= r²(∂²f/∂t² + v²f'' - 2v²f' + v²f')

= 0 (since the original function f satisfies the wave equation)

Therefore, both ψ+ and ψ- satisfy the spherical scalar wave equation ∂t² (∂²ψ/∂r²) - (v²/r²) (∂/∂r) (r²(∂r/∂ψ)) = 0 by substituting them into the equation and demonstrating that the resulting expressions are zero.

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Answer:

Y=7

Step-by-step explanation:

(X,Y) or (-2,?)

X=-2

4×(-2)-4y=20

-8-4y=20

-4y=20+8 /÷(-4)

Y=7

Answer:

4th one

Step-by-step explanation:

just do it. i know im right

Answer:

m=20

Step-by-step explanation:

Boxplots are most useful for graphically comparing distributions of numerical data, including the median, quartiles, and potential outliers. Therefore, the correct answer is "comparing two populations graphically."

Boxplots allow us to see the distribution of the data, including measures of central tendency (such as the median), and the spread of the data (such as the interquartile range).

Additionally, boxplots can help identify potential outliers and asymmetry in the data.

They are particularly useful for comparing multiple groups or populations side-by-side to identify any differences in their distributions.

Boxplots are most useful for graphically comparing distributions of numerical data, including the median, quartiles, and potential outliers.

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The percentage of graduating classes had taken fewer than 6 math classes is 10%.

In essence, percentages are fractions with 100 as the denominator. To show that a number is a percentage, we place the percent sign (%) next to it. For instance, you would have received a 75% grade if you answered 75 out of 100 questions correctly on a test (75/100).

Given that this year 75% of the graduating class has taken at least 8 math classes. of the remaining class members, 60% had taken 6 or 7 math classes

75 % took at least 8 math courses

of the remaining class members( 25 % remain ),

60 % took 6 or 7 math courses, thus 60 % of 25 % is

0.6x25 %=15 % took 6 or 7 math courses

so 75 % took 8 or more math courses, 15 % took 6 or 7 math courses, therefore that leaves 10 % taking fewer than 6 math courses ( 75 %+15 %=90 %, 100 %-90 %=10 %)

Therefore the percentage of graduating class who had taken fewer than 6 math classes is 10%.

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The NPV of the project is $0 when the cost of capital is around 31%, and the project becomes unprofitable beyond this point.

Given data, The upfront cost of the project is $900,000Year 1 revenues

= $800,000Year

2 revenues = $1,500,000 Year

3-5 revenue decline by 40% each year Fixed costs = $100,000 per year Variable costs = 50% of revenue

Year-wise cash flows: Year 0: -$900,000 Year

1: $800,000 - 50%($800,000) - $100,000 = $300,000Year

2: $1,500,000 - 50%($1,500,000) - $100,000 = $550,000Year

3: $0.6(1 - 0.4)($1,500,000) - 50%($0.6(1 - 0.4)($1,500,000)) - $100,000

= $210,000Year

4: $0.6(1 - 0.4)2($1,500,000) - 50%($0.6(1 - 0.4)2($1,500,000)) - $100,000 = $126,000Year

5: $0.6(1 - 0.4)3($1,500,000) - 50%($0.6(1 - 0.4)3($1,500,000)) - $100,000 = $75,600

Net cash flow in years 0-5 = -$900,000 + $300,000 + $550,000 + $210,000 + $126,000 + $75,600

= $362,600.

The following is the NPV profile of the project: For the cost of capital of 10%, the project's NPV can be calculated by discounting the cash flows by the cost of capital at 10%.

NPV = -$900,000 + $300,000/(1 + 0.10) + $550,000/(1 + 0.10)2 + $210,000/(1 + 0.10)3 + $126,000/(1 + 0.10)4 + $75,600/(1 + 0.10)5

= -$900,000 + $272,727.27 + $452,892.56 + $152,979.17 + $80,362.63 + $42,429.59

= $101,392.22

The project's NPV is $101,392.22 when the cost of capital is 10%.When the NPV is zero, it is called the project's Internal Rate of Return (IRR). The NPV is positive when the cost of capital is below the IRR, and the NPV is negative when the cost of capital is above the IRR. When the IRR is less than the cost of capital, the project is unprofitable.The following table shows the NPV of the project at various costs of capital:The NPV of the project is $0 when the cost of capital is around 31%, and the project becomes unprofitable beyond this point.

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Answer: 8.63844

Step-by-step explanation:

Answer:

None

Step-by-step explanation:

It would be easier to ask your teacher instead of getting wrong answers from random people. Ever think of that :0

The assumptions include:

1. The observations are normally distributed.

2 The observertions are independent.

Test hypotheses include the null hypothesis that the anxiety level is same before after the course and the alternative hypothesis that the anxiety level derveases after taking the course.

The standard deviation is 1.1475. The value of to will be:

= -1.125 / (1.1475 / √16)

= 3.9212

Based on the p value, it should be noted that the null hypothesis is rejected.

In conclusion, the anxiety level decrease after the students take the course.

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Before you took this course, you probably heard many stories about Statistics courses. Oftentimes parents of students have had bad experiences with Statistics courses and pass on their anxieties to their children. To test whether actually taking AP Statistics decreases students' anxieties about Statistics, an AP Statistics instructor gave a test to rate student anxiety at the beginning and end of his course.

Anxiety levels were measured on a scale of 0-10. Here are the data for 16 randomly chosen students from a class of 180 students:

Do the data indicate that anxiety levels about Statistics decreases after students take AP Statistics? Test an appropriate hypothesis and state your conclusion.