answer all 4 question

Answer:

Step-by-step explanation:

Radius = 28 : 2 = 14 cm

Area = radius^2 x π = 14^2 x π = 196 π cm^2

Answer:

The radius is 13

The area is 530.93

Step-by-step explanation:

To find the radius of a circle, you divide the diameter (26) by 2.

And I dunno abt the area :') I just used a calculator

The calculation (3.4876)/(4.11+1.2) should be reported with three significant figures: 0.657.

To determine the number of significant figures in the answer to the calculation (3.4876)/(4.11+1.2), we need to consider the number of significant figures in the given values and apply the rules for significant figures in mathematical operations.

First, let's analyze the number of significant figures in the given values:

- 3.4876 has five significant figures.

- 4.11 has three significant figures.

- 1.2 has two significant figures.

To perform the calculation, we divide 3.4876 by the sum of 4.11 and 1.2. Let's evaluate the sum:

4.11 + 1.2 = 5.31

Now, we divide 3.4876 by 5.31:

3.4876 / 5.31 = 0.6567037...

Now, let's determine the number of significant figures in the result.

Since division and multiplication retain the least number of significant figures from the original values, the result should be reported with the same number of significant figures as the value with the fewest significant figures involved in the calculation.

In this case, the value with the fewest significant figures is 5.31, which has three significant figures.

Therefore, the answer to the calculation (3.4876)/(4.11+1.2) should be reported with three significant figures: 0.657.

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After answering the given query, we can state that When we condense equation the phrase, we get: \((4+i)^2 = 15 + 8i\) As a result, (4+i)2 becomes 15 + 8i.

A mathematical equation is a process that links two statements and indicates equality with the equals sign (=). A mathematical assertion that proves the equality of two mathematical statements is known as an equation in algebra. For instance, the equal symbol separates the numbers 3x plus 5 and 14 in the equation 3x + 5 = 14. A mathematical formula can be used to understand the connection between the two lines that are written on opposite sides of a letter. Frequently, the emblem and the particular program are identical. as in 2x - 4 = 2, for example.

Simplifying i2=-1: We get i2 x (-1) = -1 x by multiplying both sides by -1. (-1)

By condensing the left half, we obtain:

\(i^2 x (-1) = -(i^2)\)

On the right side, if we replace i2 with -1, we get:

\(-(i^2) = -(-1)\)

When we condense the right half, we obtain:

\(-(i^2) = 1\)

As a result, i2 = -1 can be expressed as i2 = 1.

Simplifying (4+i)2: By extending the formula, we obtain (4+i)2 = (4+i)(4+i)

By multiplying the variables, we can use the FOIL technique to:

(4+i)(4+i) equals 4x4 plus 4xi plus 4xi plus i2

When we combine similar words and simplify the first two terms, we get:

\((4+i)(4+i) = 16 + 8i + i^2\)

Using the i2 = -1 reduction, we obtain:

\((4+i)^2 = 16 + 8i - 1\)

When we condense the phrase, we get:

\((4+i)^2 = 15 + 8i\)

As a result, (4+i)2 becomes 15 + 8i.

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Answer:

2

Step-by-step explanation:

Using the graph of tanx attached, we know that each period starts and restarts after each π. I've contrasted the periods of the functions in blue versus what we have between the two points in green.

From -3π/4 to 5π/4, we have.....

1/4 of a period

1 full period

3/4 of a period

1/4 + 1 + 3/4 = 2 periods

I hope this helps!

Using trigonometric ratio, the length of BE is 10 units, the value of sin B is 0.64 and cos B is 0.64 respectively

This is the ratio between the angles and sides of a right-angle triangle. The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).

In this problem, we have that

1)

Using tangent of B

tan B = opposite / adjacent

tan B = NE / BE

3/4 = 7.5 / BE

BE = 7.5 / 0.75

BE = 10

2)

To find sin B, we need to calculate the hypothenuse of the triangle which we will use Pythagoras's theorem

NB² = BE² + NE²

NB² = 10² + 7.5²

NB = 12.5

sin B = NE / NB

sin B = 7.5 / 12.5

B = sin⁻¹ (7.5 / 12.5)

B = 0.64

3)

cos B = BE / NB

cos B = 10 / 12.5

B = cos⁻¹ (10/12.5)

B = 0.64

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Answer

1;120

2;60

3;20

Step-by-step explanation:

Let \(\(a\)\) and \(\(b\)\) be integers such that \(\(ab = 4\)\). We want to prove that \(\((a - b)^3 - 9(a - b) = 0\).\)

Starting with the left side of the equation, we have:

\(\((a - b)^3 - 9(a - b)\)\)

Using the identity \(\((x - y)^3 = x^3 - 3x^2y + 3xy^2 - y^3\)\), we can expand the cube of the binomial \((a - b)\):

\(\(a^3 - 3a^2b + 3ab^2 - b^3 - 9(a - b)\)\)

Rearranging the terms, we have:

\(\(a^3 - b^3 - 3a^2b + 3ab^2 - 9a + 9b\)\)

Since \(\(ab = 4\)\), we can substitute \(\(4\)\) for \(\(ab\)\) in the equation:

\(\(a^3 - b^3 - 3a^2(4) + 3a(4^2) - 9a + 9b\)\)

Simplifying further, we get:

\(\(a^3 - b^3 - 12a^2 + 48a - 9a + 9b\)\)

Now, notice that \(\(a^3 - b^3\)\) can be factored as \(\((a - b)(a^2 + ab + b^2)\):\)

\(\((a - b)(a^2 + ab + b^2) - 12a^2 + 48a - 9a + 9b\)\)

Since \(\(ab = 4\)\), we can substitute \(\(4\)\) for \(\(ab\)\) in the equation:

\(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 48a - 9a + 9b\)\)

Simplifying further, we get:

\(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 39a + 9b\)\)

Now, we can observe that \(\(a^2 + 4 + b^2\)\) is always greater than or equal to \(\(0\)\) since it involves the sum of squares, which is non-negative.

Therefore, \(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 39a + 9b\)\) will be equal to \(\(0\)\) if and only if \(\(a - b = 0\)\) since the expression \(\((a - b)(a^2 + 4 + b^2)\)\) will be equal to \(\(0\)\) only when \(\(a - b = 0\).\)

Hence, we have proved that if \(\(ab = 4\)\), then \(\((a - b)^3 - 9(a - b) = 0\).\)

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a. Present value of $400 per year for 14 years at 14%: $2,702.83
b. Present value of $200 per year for 7 years at 7%: $1,155.54
c. Present value of $400 per year for 7 years at 0%: $2,800
d. Present value of $400 per year for 14 years at 14% (annuity due): $2,943.07
  Present value of $200 per year for 7 years at 7% (annuity due): $1,233.24
  Present value of $400 per year for 7 years at 0% (annuity due): $2,800

To find the present values of the ordinary annuities, we can use the formula for the present value of an annuity:

PV = PMT * [(1 - (1 + r)^(-n)) / r]
Where:
PV = Present value
PMT = Payment per period
r = Interest rate per period
n = Number of periods

a. $400 per year for 14 years at 14%:
PV = $400 * [(1 - (1 + 0.14)^(-14)) / 0.14]

≈ $2,702.83

b. $200 per year for 7 years at 7%:
PV = $200 * [(1 - (1 + 0.07)^(-7)) / 0.07]

≈ $1,155.54

c. $400 per year for 7 years at 0%:
Since the interest rate is 0%, the present value is simply the total amount of payments over the 7 years:
PV = $400 * 7

= $2,800

d. Reworking previous parts assuming they are annuities due:
For annuities due, we need to adjust the formula by multiplying it by (1 + r):

a. Present value of $400 per year for 14 years at 14%:
PV = $400 * [(1 - (1 + 0.14)^(-14)) / 0.14] * (1 + 0.14)

≈ $2,943.07

b. Present value of $200 per year for 7 years at 7%:
PV = $200 * [(1 - (1 + 0.07)^(-7)) / 0.07] * (1 + 0.07)

≈ $1,233.24

c. Present value of $400 per year for 7 years at 0%:
Since the interest rate is 0%, the present value remains the same:
PV = $400 * 7

= $2,800

In conclusion:
a. Present value of $400 per year for 14 years at 14%: $2,702.83
b. Present value of $200 per year for 7 years at 7%: $1,155.54
c. Present value of $400 per year for 7 years at 0%: $2,800
d. Present value of $400 per year for 14 years at 14% (annuity due): $2,943.07
  Present value of $200 per year for 7 years at 7% (annuity due): $1,233.24
  Present value of $400 per year for 7 years at 0% (annuity due): $2,800

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Using the information provided in the table, The total holding cost is  $547.50, the total setup cost is $600 and the total cost is  $1,147.50.

To develop a POQ (Periodic Order Quantity) solution use a lot-for-lot solution, which means that we will order exactly what we need for each period.

The missing values can be found on the attached table.

From the table, the total holding cost which is the sum of the holding costs for all periods is $547.50 while the total setup cost which is the sum of the setup costs for all periods is $600.

Therefore, the total cost is the sum of the holding cost and the setup cost and it is calculated as $1,147.50.

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The coordinates of the orthocenter of triangle XYZ are (3,2).

To find the coordinates of the orthocenter of triangle XYZ, we need to find the intersection point of the altitudes.

First, we need to find the equations of the three altitudes. An altitude is perpendicular to a side and passes through the opposite vertex.

The equation of the line through X(-1,-4) and perpendicular to YZ is:

y - 4 = (4-(-4))/(7-(-1))(x-7)

y - 4 = 8/8(x-7)

y = -x + 11

The equation of the line through Y(4,7) and perpendicular to XZ is:

y - 7 = (-1/4)*(x-4)

y = (-1/4)x + 8.5

The equation of the line through Z(7,4) and perpendicular to XY is:

y - 4 = (7-(-1))/(-4-(-4))(x-7)

y - 4 = -8/10(x-7)

y = -4/5*x + 36/5

Next, we need to find the intersection points of these lines. We can solve the system of equations:

y = -x + 11

y = (-1/4)x + 8.5

y = -4/5*x + 36/5

Solving this system of equations, we get the coordinates of the orthocenter H:

H(3,2)

Therefore, the coordinates of the orthocenter of triangle XYZ are (3,2).

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answer done last mai btaa dena correct hai

The unit tangent vector t(t) is (3, 4t, 2t) / sqrt(9 + 20t^2), and the unit normal vector n(t) is (3, 4, 2t) / sqrt(25 + 4t^2).

The unit tangent vector t(t) of the given vector function r(t) = (3t, 1 + 2t^2, t^2) is obtained by dividing the derivative of r(t) by its magnitude. The derivative of r(t) is (3, 4t, 2t), and the magnitude of this vector is sqrt(9 + 20t^2). Therefore, t(t) = (3, 4t, 2t) / sqrt(9 + 20t^2).

The unit normal vector n(t) can be obtained by dividing the derivative of t(t) by its magnitude. The derivative of t(t) is (3, 4, 2t), and the magnitude of this vector is sqrt(25 + 4t^2). Thus, n(t) = (3, 4, 2t) / sqrt(25 + 4t^2).

These unit vectors t(t) and n(t) represent the direction of motion and the direction of the curve's curvature at each point t, respectively, providing valuable information about the behavior of the vector function r(t).

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Answer: The answer C the one in the botton the one that has the arrow Up

Step-by-step explanation:

Step-by-step explanation:

This graph

Have a nice day

The speed of both printers operating together is 1.333 hours which was found using the given data.

The formula used to explain the connection between speed, distance, and time is speed = distance/time.

Given: Newspapers can be printed twice as quickly on a modern printing press as they can on an old one. The old one takes four hours to publish the afternoon edition.

Let,

a = Speed of New printing press

b = Speed of Old printing press

x = Speed of both printers operating together

We know that,

(1/a)+(1/b)=(1/x)

(1/2)+(1/4)=(1/x)

(4/8)+(2/8)=(1/x)

6/8=1/x

x=8/6

x=1.333

Therefore, the speed of both printers operating together is 1.333 hours which was found using the given data.

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Based on your question, it sounds like you are asking about random variables that have a joint probability density function (PDF) of 1/50 over a certain range of values.

In probability theory, a random variable is a variable whose value is determined by chance. It can take on a range of possible values, and the probabilities of each possible value occurring can be described using a probability distribution.

A joint probability density function is a function that describes the probabilities of two or more random variables taking on specific values simultaneously. In your case, you have two random variables that have a joint PDF of 1/50.

Without knowing the specific range of values over which the PDF is defined, it's hard to provide a more detailed answer. However, here are a few general observations about random variables and joint PDFs:

- Random variables can be either discrete or continuous. Discrete random variables take on specific, countable values (e.g. the number of heads in a series of coin tosses), while continuous random variables can take on any value within a certain range (e.g. the height of a randomly selected person).
- A joint PDF is typically used to describe the behavior of two or more continuous random variables. It gives the probability density at each point in the two-dimensional space defined by the values of the two variables.
- The total probability over the entire range of values for a joint PDF must sum to 1. This ensures that the probability of all possible outcomes occurring is equal to 1.

I hope this helps! If you have any further questions or clarifications, please let me know.
It seems that you are asking about random variables with a joint probability density function (pdf) of 1/50. Random variables are quantities that can take on different values according to some probability distribution. When two or more random variables are considered together, their relationship can be described using a joint pdf. In this case, the joint pdf is 1/50, indicating that the probability of a specific combination of these random variables is 1/50.

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The answer is option (C), that is, the events of rolling a fair die two times are independent. The events are neither disjoint nor exclusive.

When rolling a fair die two times, one can get any one of the 36 possible outcomes equally likely. Let A be the event of obtaining an even number on the first roll and let B be the event of getting a number greater than 3 on the second roll. Let’s see how the outcomes of A and B are related:

There are three even numbers on the die, i.e. A={2, 4, 6}. There are four numbers greater than 3 on the die, i.e. B={4, 5, 6}. So the intersection of A and B is the set {4, 6}, which is not empty. Thus, the events A and B are not disjoint. So option (A) is incorrect.

There is only one outcome that belongs to both A and B, i.e. the outcome of 6. Since there are 36 equally likely outcomes, the probability of the outcome 6 is 1/36. Now, if we know that the outcome of the first roll is an even number, does it affect the probability of getting a number greater than 3 on the second roll? Clearly not, since A∩B = {4, 6} and P(B|A) = P(A∩B)/P(A) = (2/36)/(18/36) = 1/9 = P(B). So the events A and B are independent. Thus, option (C) is correct. Neither option (A) nor option (C) can be correct, so we can eliminate options (D) and (E).

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Answer:

^two dimentional figure with algebra^

the perimwter from triangle is:

s1 + s2 + s3

ok, enter:

s1 + s2 + s3= 369

x + (8x -5) + 2x = 369

x + 8x - 5 + 2x = 369

group according to the same variable

(x + 8x + 2x) + (-5)=369

11x + (-5)=369

11x - 5= 369

11x = 369 + 5

11x =374

x =374 : 11

x = 34

ok, subtituted:

s1= x

=34 feet

s2= 8x - 5

=8(34) - 5

=272 - 5

=267 feet

s3= 2x

=2(34)

=68 feet

Answer: If anything below sea level is a negative integer then anything above sea level is a positive integer. An integer that could represent a helicopter could be anything from +1 to +1000 and on.

Using division operation, the length it will take the three hoses to fill the pool is 8.33 hours.

The division operation is one of the four basic mathematical operations, including addition, subtraction, and multiplication.

The division operation involves the dividend, the divisor, and the result called the product.

In this situation, it will take Hose A 10 hours to fill the pool and Hose B 5 hours.  If the two hoses are in use, it will 7.5hours (10 + 5)/2.

When the third hose is added, it will take 8.33 hours (10 + 5 + 10)/3.

The first hose's filling rate for the pool = 10 hours

The second hose's filling rate for the pool = 5 hours

The third hose's filling rate for the pool = 10 hours (the slower rate)

The total number of hours used by the three hoses = 25 hours (10 + 5 + 10)

The number of hoses used = 3

The length of time it will take the 3 hoses to fill the pool = 8.33 hours (25/3)

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As a result, the two phrases are logically equal. The two formulations are not logically identical, as we can see. The two formulations are not logically identical, as we can see.

An expression or mathematical expression is a finite collection of symbols that is well-formed according to context-dependent norms.

Here,

(a) The first statement can be expressed as:

(~j -> (l v ~r))

The second statement can be expressed as:

((r ^ ~l) -> j)

To determine whether the two expressions are logically equivalent, we can use truth tables. A truth table is a method for checking the validity of logical equivalences by comparing the truth values of the two expressions for all possible combinations of inputs.

Truth table for (~j -> (l v ~r)) and ((r ^ ~l) -> j):

j l r (~j -> (l v ~r)) ((r ^ ~l) -> j)

T T T T T

T T F T T

T F T F F

T F F T T

F T T T T

F T F T T

F F T T T

F F F T T

Since both expressions have the same truth values for all possible combinations of inputs, we can conclude that the two expressions are logically equivalent.

(b) The first statement can be expressed as:

(j -> ~l)

The second statement can be expressed as:

(~j -> l)

Truth table for (j -> ~l) and (~j -> l):

j l (j -> ~l) (~j -> l)

T T T F

T F T T

F T T T

F F T T

Since the expressions have different truth values for some combinations of inputs, we can conclude that the two expressions are not logically equivalent.

(c) The first statement can be expressed as:

((r v ~l) -> j)

The second statement can be expressed as:

(j -> (r ^ ~l))

Truth table for ((r v ~l) -> j) and (j -> (r ^ ~l)):

j l r ((r v ~l) -> j) (j -> (r ^ ~l))

T T T T T

T T F T T

T F T T T

T F F T T

F T T T F

F T F T F

F F T T F

F F F T T

Since the expressions have different truth values for some combinations of inputs, we can conclude that the two expressions are not logically equivalent.

We can conclude that the two expressions are logically equivalent. We can conclude that the two expressions are not logically equivalent. We can conclude that the two expressions are not logically equivalent.

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in order

median

mean

mode

Answer:

Cost price = 1,000 rs

Step-by-step explanation:

Given:

Gain % = 20%

Discount = 5%

Amount of gain = 140

Find:

Cost price

Assume

Cost price = x

Computation:

Market Price = x( 100% + 20% gain)

Market price = 1.2x

Discount = [1.2x][5%]

Discount = 0.06x

Sell Price = 1.2x - 0.06x

Sell Price =1.14x

Profit = Sell Price - Cost price

Profit = 1.14x - x

140 = 0.14 x

x = 1,000 rs

Cost price = 1,000 rs

the limit of the given function as x approaches 0 from the right is 0.

To determine the limit of the function as x approaches 0 from the right, we need to evaluate the expression.

lim(x->0+) x²(ln(x))²

We can rewrite the expression as:

lim(x->0+) (x²)(ln(x))²

As x approaches 0 from the right, the natural logarithm of x approaches negative infinity, and squaring it will still result in a positive number. Also, x² approaches 0.

So, we have:

lim(x->0+) (x²)(ln(x))² = 0*(negative infinity)² = 0*infinity = 0

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Answer: i belive that it is 38.70

Step-by-step explanation:  39.6 - 2.35 + 1.45 = 38.70

Answer:

38.70

Step-by-step explanation: