An unbalanced 16 N force is applied to a 2.0 kg mass. What is the
acceleration of the mass? (F=ma)*
A 2 m/s^2
B 8 m/s^2
C 6 m/s^2
D 4 m/s2

Answer:

In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.

Explanation:

Answer:

D all of the above

Explanation:

This is because newtons laws of motion explains movement of a body due to a force applied while that of gravity explains motion of a body under gravity and this captures a, b, and c

All the given options are following the Newton's laws of motion and Newton's law of gravity separately. All of the above options are correct. Hence, option (d) is correct.  

The given problem is based upon the Newton's law of motion as well as Newton's law of gravity. So let us analyze each of the given cases as:

(a)

The Earth moves around the Sun : This statement follows the Newton's first law of motion, which says that an object will continue its state of motion, until any external force is being applied on the object. Since, Earth is offered with no net force. Therefore, Newton's law is applicable.

(b)

Moon movers around Earth: This statement also follows the above explanation for the Newton's first law. Which makes moon to revolve around the Earth on an account of no net force. Hence, it will continue its circular motion and hence Newton's law of motion is followed.

(c)

An apple falls from a tree: This statement is based on Newton's law of gravity, which says that every particle in the universe attracts other particles such that the force of attraction is directly proportional to the product of their masses and inversely proportional to square of distance between them. Since, Earth has more mass than apply, therefore Earth will attract the apple downwards.

Thus, we can conclude that all the given options are following the Newton's laws of motion and Newton's law of gravity separately. All of the above options are correct. Hence, option (d) is correct.  

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Answer:

Evaporation is the vaporization of a liquid to the gaseous phase which occurs at the liquid's surface when the gas above the surface is unsaturated or contains less amount of the evaporating substance and the molecules at the surface absorbs enough energy during the transfer of energy from internal collision to withstand the vapor pressure of the surrounding and exist as a gas

a) Evaporation can explain the decrease in mass as follows;

Given that evaporation is the conversion of a liquid to a gas, the loss in mass of the ethanol can be explained by the conversion of some of the ethanol liquid to gas by evaporation such that the volume of ethanol remaining, and therefore, the mass of ethanol is reduced

b) The evaporation of the energized ethanol molecules from the surface of the ethanol results in a loss of energy of the remaining ethanol in the beaker, which can be observed as a reduction in temperature of the ethanol

Explanation:

According to the law of conservation of angular momentum, if the Sun suddenly shrinks in size, but the mass remains the same, then the Sun would rotate faster than it does now. This is because the angular momentum of the Sun is constant, so if the size decreases, then the rotation must increase to maintain the same level of angular momentum.

The law of conservation of angular momentum states that the total angular momentum of a system remains constant if no external torque is acting on it.

This means that if the Sun suddenly shrinks in size, then the total angular momentum of the system (Sun + planets) must remain constant.

Since the mass of the Sun remains the same, its moment of inertia must decrease when it shrinks in size, which means that its angular velocity must increase in order to maintain the same level of angular momentum.

Therefore, the Sun would rotate faster than it does now if it suddenly shrinks in size while its mass remains the same.

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Answer:

140 m/s

Explanation:

v = u + at

v = 8 + 3.5(40) = 140 + 8 = 140

C) always true

Consider an RLC series circuit. The impedance of the circuit increases if Xc increases. Option (C) is always true.In an RLC series circuit, the impedance (Z) is given by;Z² = R² + (XL - XC)²Where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.The capacitive reactance is inversely proportional to the capacitance, thus if Xc increases, the capacitive reactance decreases. Hence the denominator in the equation above decreases, thereby increasing the impedance. Therefore, it is true that the impedance of an RLC series circuit increases if Xc increases.

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The graph in which the block will travel with the greatest speed is the graph with the greatest displacement at given equal forces.

Based on the principle of work energy theorem, the work done in moving the block against the frictionless floor is equal to the kinetic energy.  

K.E = ¹/₂kx²

K.E = ¹/₂Fd

¹/₂mv² = ¹/₂Fd

mv² = Fd

v² = Fd/m

v = √ (Fd/m)

Thus, the graph in which the block will travel with the greatest speed is the graph with the greatest displacement at given equal forces.

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Answer:

Od- Wooden

Explanation:

It would not make sense if it was non-wood because that make it no a wood base product, OC is not right because its not a a plant that produces wood as its structural tissue and thus has a hard stem.   An OA justT o take or get a supply of wood. so its Od

a. Use Hooke's law to find the spring constant k :

F = kx   ⇒   10 N = k (2 mm) = k (0.002 m)   ⇒   k = 5000 N/m

b. Use Hooke's law again to find the extension x given a force of 25 N :

F = kx   ⇒   25 N = (5000 N/m) x   ⇒   x = 0.005 m = 5 mm

c. We end up with the same force as in part (b) :

F = kx   ⇒   F = (5000 N/m) (5 mm) = (5000 N/m) (0.005 m) = 25 N

Answer:

the branch currents are as follows:

  top left: I2 = 0.625 A

  middle left: I1 = 2.500 A

  bottom left: I1-I2 = 1.875 A

  top center: I2+I3 = 2.500 A

  bottom center: I2+I3-I1 = 0 A

  right: I3 = 1.875 A

Explanation:

You can write the KVL equations:

Top left loop:

  I2(4) +(I2 +I3)(2) +I1(1) = 10

Bottom left loop:

  (I1-I2)(4) +(I1-I2-I3)(2) +I1(1) = 10

Right loop:

  (I2+I3)(2) +(I2+I3-I1)(2) = 5

In matrix form, the equations are ...

  \(\left[\begin{array}{ccc}1&6&2\\7&-6&-2\\-2&4&4\end{array}\right]\cdot\left[\begin{array}{c}I_1\\I_2\\I_3\end{array}\right] =\left[\begin{array}{c}10\\10\\5\end{array}\right]\)

These equations have the solution ...

  \(\left[\begin{array}{c}I_1\\I_2\\I_3\end{array}\right] =\left[\begin{array}{c}2.500\\0.625\\1.875\end{array}\right]\)

This means the branch currents are as follows:

  top left: I2 = 0.625 A

  middle left: I1 = 2.500 A

  bottom left: I1-I2 = 1.875 A

  top center: I2+I3 = 2.500 A

  bottom center: I2+I3-I1 = 0 A

  right: I3 = 1.875 A

_____

This can be worked almost in your head by using the superposition theorem. When the 5V source is shorted, the 10V source is supplying (I1) to a circuit that is the 4 Ω and 2 Ω resistors in parallel with their counterparts, and that 2+1 Ω combination in series with 1 Ω for a total of a 4Ω load on the 10 V source. That is, I1 due to the 10V source is 2.5 A, and it is nominally split in half through the upper and lower branches of the circuit. There is no current flowing through the (shorted) 5 V source branch.

When the 10V source is shorted, the 5V source is supplying a 4 +4 Ω branch in parallel with a 2 +2 Ω branch, a total load of 8/3 Ω. This makes the current from that source (I3) be 5/(8/3) = 15/8 = 1.875 A. There is zero current from this source through the 1 Ω resistor.

Nominally, the current from the 5V source splits 2/3 through the 2 Ω branch and 1/3 through the 4 Ω branch.

Using superposition, I2 = I1/2 -I3/3 = (2.5 A/2) -(1/3)(15/8 A) = 0.625 A. This is the same answer as above, without any matrix math.

  (I1, I2, I3) = (2.5 A, 0.625 A, 1.875 A)

__

It helps to be familiar with the formulas for resistors in series and parallel.

i) The turning moment is measured in newton-meters (Nm) at 240 Nm.

ii) A 150 N force exerted at hole B, 1.6m above ground, produces the same turning moment as a 300 N force.

i) The turning moment about pivot P can be calculated by multiplying the force applied by the perpendicular distance between the force and the pivot point. In this case, the distance is given as 0.8m.

Turning moment = force x perpendicular distance

Turning moment = 300N x 0.8m

Turning moment = 240 Nm

The unit for turning moment is newton-meters (Nm).

ii) The turning moment is constant, so set the turning moment about pivot P from part (i) equal to the turning moment produced by the force at hole B.

240 Nm = force x 1.6m

force = 240 Nm / 1.6m

force = 150 N

Therefore, a force of 150 N applied at hole B, 1.6m above the ground, would produce the same turning moment as a force of 300 N applied at hole A, 0.8m above the ground.

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Answer:

Sir Isaac Newton was an English mathematician, physicist, astronomer, theologian, and author

Explanation:

but he is most importantly known for having formulated the theory of universal gravity

and for having invented the calculus in the mid to late 1660s

Horatio's work on the box is calculated as follows: Work = Force x Distance = 120 N x 4 m = 480 J The solution is therefore choice (a) 480 J.

To calculate the work done by Horatio on the box, we need to use the formula for work, which is:

Work = Force x Distance x Cosine of the angle
In this case, the force (F) is 120 N, the distance (d) is 4 meters, and the angle between the force and distance is 0 degrees since he pushes parallel to the floor. Cosine of 0 degrees is 1. So, the formula becomes:

Work = 120 N x 4 m x 1
Now, multiply the force and the distance:

Work = 480 J

So, Horatio does 480 joules of work on the box, making the correct answer (a) 480 J.

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Answer:

C)  Total displacement = 1275 m or 1.275 km

Explanation:

We'll break this into two parts:  

1) Displacement during constant speed, and

2) Displacement during the acceleration phase.

Constant Speed

The displacement for this segment is already stated:  1 km.  But the information includes the time, which will allow us to calculate the speed of travel.  We'll need this for the next phase of acceleration.

Distance = Speed x Time

Speed = Distance/Time

Time = 1 minute + 20 sec, or 80 sec.

Speed = 1 km/80 sec

Speed = 0.0125 km/sec

Since we'll be using meters (not km) in the next step, convert 0.0125 km/sec to m/sec with a conversion factor:  

  (0.0125 km/sec)*(1000m/1 km) = 12.5 m/sec

Acceleration Phase

The obect is moving at a speed of 12.5 m/sec (from above) and then accelerates at a rate of 0.125 m/sec^2 for 20 seconds.

The distance (s) an object travels during this acceleration (a) is gven by:

  s = vi*t + (1/2)a*t^2,

where vi is the initial velocity (12.5 m/sec in this case), a is the acceleration (0.125 m/sec^2), and t is the time (20 seconds).

s = (12.5 m/sec)(20 sec) + (1/2)(0.125 m/sec^2)*(20 sec)^2

s = 275 meters

Now add the two distances:

1) Constant Speed Phase = 1000 m

2)  Acceleration Phase    =  275 m

Total displacement = 1275 m or 1.275 km

The equilibrant force needed to compensate for the resultant force of vectors f1 and f2 can be calculated by finding the negative vector sum of f1 and f2.

To find the equilibrant force, we need to determine the force that can precisely balance the resultant force of f1 and f2. The resultant force is the vector sum of f1 and f2. In order to compensate for this resultant force and achieve equilibrium, the equilibrant force must have the same magnitude but act in the opposite direction.

By calculating the negative vector sum of f1 and f2, we obtain the equilibrant force. This is done by taking the negative of each component of the resultant force vector. The equilibrant force will have the same magnitude as the resultant force but will act in the opposite direction to counterbalance the effects of f1 and f2.

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In order to determine the equilibrant force that would be needed to compensate for the resultant force of the vectors f1 and f2 that you calculated in question 4, one must first add the two forces using vector addition. Then, the equilibrant force can be found by taking the opposite of the resultant force.

Mathematically, the equilibrant force can be calculated as follows:

In mechanics, an equilibrant force is a force that brings an object into mechanical equilibrant. According to Newton's second law, an object has zero acceleration when the vector sum of all the forces acting on it is zero.

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The heat transfer rate by convection is given by the following equation: qcon v = h × A × (Tb - Ta)The heat transfer rate by radiation is given by the following equation: qra d = σ × A × [(Tb + 273)4 - (Ts + 273)4] × εEquating the above equations, we get,

The steady convective heat flux from the base plate to air is given by the following equation: qcon v = h × A × (Tb - T where, qcon v = steady convective heat flux from the base plate to air h = convective heat transfer coefficient A = area of the base plate.

Tb = temperature of the base plate Ta = temperature of the air. The heat transfer rate by convection is given by the following equation: qcon v = h × A × (Tb - T Use the definition of net radiative heat transfer and heat transfer rate equation for thermal radiation together with emissivity of steel ca0.5 to calculate the steady radiative heat flux from the base plate to the surrounding.

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The graph that corresponds to 0.1 s in one complete cycle is graph D.

option D is the correct answer.

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.

Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.

From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;

Period = 1 s / 10

Period = 0.1 s

From the graphs, the only option that has one complete cycle in one second is option D.

Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.

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Answer:

d

Explanation:

From the calculation, there is a net force that acts on the car and then the acceleration that is produced by the net force is 0.296 m/s^2.

The term net force refers to the force that is acting on an object that makes it to move. We have to recall that the force of friction is the force the limits the motion of an object. In other words, it is the force of friction that makes a body not to be able to move and this must be overcome by the forward force when it is greater than the friction force.

Now;

Mass of the car = 1352 kg

Forward force = 7820 N

Coefficient of friction = 0.56

Frictional force = μmg

= 0.56 * 1352 kg * 9.8 m/s^2

= 7419.8 N

Net force = Forward force - Frictional force

= 7820 N -  7419.8 N

= 400.2 N

Then;

Net force = ma

m = mass

a = acceleration

a = Net force/m

a = 400.2 N/ 1352 kg

a = 0.296 m/s^2

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No, when light spreads out and diminishes, gaps do not exist between photons.

Although a distant star's light does spread out and get weaker as it moves, this just affects the wave intensity and does not cause gaps in the wave.

As a result, no matter how faint light becomes, no spatial gaps ever occur in it when it moves across free space if you think of photons as waves.

Light's fundamental units, photons, move in a wavelike fashion. The quantity of photons per unit area and the energy of each photon decline when light diffuses, which causes a reduction of the light intensity. The photons, however, go on their uninterrupted journey across space in a continuous stream. Although the distances between the photons may widen as the light disperses, the photon stream is uninterrupted.

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The 0.4 kg, 0.5 m radius ball rolling without slipping indicates that the rotational and translational kinetic energy are as follows;

a. The rotational kinetic energy = 0.02·ω²

b. The translational kinetic energy = 0.2·v²

c. The total kinetic energy is 0.28·v²

Rotational kinetic energy is the energy a body possesses due to the rotation of the object about an axis around which the object rotates

a. The formula for the rotational kinetic energy is presented as follows;

\(K.E_{Rotational}= \dfrac{1}{2}\cdot I\cdot \omega^2\)

Where;

I = The moment of inertia of the body around the axis of rotation

ω = Angular velocity of the body

The moment of inertia of the spherical ball is found using the formula;

\(I =\dfrac{2}{5} \cdot m\cdot r^2\)

Where;

m = The mass of the ball = 0.4 kg

r = The radius of the ball = 0.5 m

Therefore;

\(I =\dfrac{2}{5} \times 0.4\times 0.5^2 = 0.04\)

The moment of inertia of the ball is I = 0.04 m³

\(K.E_{Rotational}= \dfrac{1}{2}\times 0.04\cdot \omega^2= 0.02 \cdot \omega^2\)

The rotational kinetic energy of the ball is 0.02·ω²

b. The translational kinetic energy is K.E. = 0.5·m·v²

The translational kinetic energy is therefore;

Translational K.E. = 0.5 × 0.4 × v² = 0.2·v²

c. The total kinetic energy, K.E. = Translational K.E. + \(K.E_{Rotational}\)

K.E. = 0.2·v² + 0.02·ω²

\(K.E. = 0.2\cdot v^2 + 0.02\cdot \left(\dfrac{v}{r} \right)^2\)

= 0.5 m

\(K.E. = 0.2\cdot v^2 + 0.02\cdot \left(\dfrac{v}{0.5} \right)^2 = \dfrac{7}{25} \cdot v^2 = 0.28\cdot v^2\)

The total kinetic energy is K.E. = 0.28·v²

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The heat equation is Q = mcT

Q is the total amount of heat transferred to or from something.

The energy that an object has as a consequence of motion is known as kinetic energy. It is described as the effort required to propel a mass-determined body from rest to the indicated velocity.

An illustration of kinetic energy

Kinetic energy, which may be seen in the motion of an item or subatomic particle, is the energy in motion. Kinetic energy exists in every particle and moving object. Example of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, but a charge particles in an electric field.

The energy from mass that is moving is known as kinetic energy. An element's kinetic energy is the power it possesses as a result of motion.

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The electric fields is always directed from higher potential to the lower potential.

The electric fields always aiming from the region of higher potential to the region of lower potential. So the force of electrostatic and the direction of the travel of electrons will be always from lower potential to the region of higher potential.

An electric field is defined as the physical field which covers the electrically charged particles and also they can apply force on all other charged particles.

So we can conclude that the electric fields is always directed from higher potential to the lower potential.

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It will take 1.6s for the ice to melt.

First we have to write the expression for the heat balance equation for the system

Q supply = Qgain/

t= mLf/t

Here, m is the ice,

Lf is the latent heat of fusion

and t is the time taken to melt the ice.

Now we have to substitute the required value in the above expression to determine the value of time.

636 kJ/s = (3 kg)(334 kJ/kg) / tt =1.575 s

What is latent heat?
The heat or energy that is absorbed or released during a substance's phase shift is known as latent heat. It could go from a solid to a liquid or from a liquid to a gas, or vice versa. Enthalpy, a characteristic of heat, is connected to latent heat.

Therefore, the closest option is 1.6s

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Answer:

T₂ =  218.16 k = -54.84°C

Explanation:

Consider, the general gas equation:

PV = nRT

where,

P = Pressure of Gas

V = Volume of Gas

n = No. of Moles of Gas = mass in gram/Molecular Mass = m/M

R = Gas Constant

T = Temperature of Gas

Now,

PV = mRT/M

P/mT = RM/V

since, RM/V = Constant values in both final and initial states.

therefore,

P₁/m₁T₁ = P₂/m₂T₂

T₂ = P₂m₁T₁/m₂P₁

where,

T₂ = Final Temperature = ?

P₂ = Final Pressure = 1.8 atm

m₁ = Initial Mass = 10 kg

P₁ = Initial Pressure = 5 atm

m₂ = Final Mass = 10 kg/2 = 5 kg

T₁ = Initial Temperature = 30°C + 273 = 303 k

Therefore,

T₂ = (1.8 atm)(10 kg)(303 k)/(5 kg)(5 atm)

T₂ =  218.16 k = -54.84°C

density(ρ) = mass (m) : volume (V)

Answer:

To calculate the change in gravitational potential energy of the book as it falls from different starting points, we need to use the formula:

ΔPE = mgh

where ΔPE is the change in gravitational potential energy, m is the mass of the book, g is the gravitational acceleration (9.81 m/s^2), and h is the change in height.

A) If the book is released from a point on the floor of the room to the left of the hatch, it will fall towards the hatch and then fall further towards the basement floor. The change in height is the distance from the floor to the basement floor, which is 2.2 meters. Therefore, the change in gravitational potential energy is:

ΔPE = (7.5 N) x (9.81 m/s^2) x (2.2 m) = 162.8 Joules

B) If the book is released from a point on the floor of the room to the right of the hatch, it will fall towards the hatch and then fall further towards the basement floor as well. Therefore, the change in gravitational potential energy is the same as in Part A:

ΔPE = (7.5 N) x (9.81 m/s^2) x (2.2 m) = 162.8 Joules

C) If the book is released from a point at the height of the chair seat (0.45 m above the floor), it will fall towards the hatch and then fall further towards the basement floor. The change in height is the distance from the chair seat to the basement floor, which is:

h = 0.45 m + 2.2 m = 2.65 m

Therefore, the change in gravitational potential energy is:

ΔPE = (7.5 N) x (9.81 m/s^2) x (2.65 m) = 187.8 Joules

D) If the book is released from a point at the height of the bookshelf (1.5 m above the floor), it will fall directly towards the basement floor. The change in height is the distance from the bookshelf to the basement floor, which is:

h = 1.5 m + 2.2 m = 3.7 m

Therefore, the change in gravitational potential energy is:

ΔPE = (7.5 N) x (9.81 m/s^2) x (3.7 m) = 268.4

The moon is applying an equal force to that of the Earth. This is because of Newton’s 3rd law. The Earth exerts a force on the moon, and in turn, the moon exerts and equal but opposite force on the Earth.

Answer:

Human-driven changes in arrive utilize and arrive cover such as deforestation, urbanization, and shifts in vegetation designs moreover change the climate, coming about in changes to the reflectivity of the Soil surface (albedo), emanations from burning timberlands, urban warm island impacts and changes within the normal water cycle.