An ultracentrifuge accelerates from rest to 9.97 X 105 rpm in 1.51 min. What is its angular acceleration in radians per second squared? angular acceleration: radls? What is the tangential acceleration of a point 8.90 cm from the axis of rotation? tangential acceleration: m/s? What is the radial acceleration in meters per second squared and in multiples of g of this point at full revolutions per minute? radial acceleration: m/s? radial acceleration in multiples of g:

A flow rate of approximately 7.16 cubic meters per second is required to produce 1 MW of power with 87% efficiency, given that the water enters and leaves the system at a low speed and loses 160 m of altitude during the process.

To determine the water flow required to produce power in this scenario, we need to use the formula:
Power = (density of water x gravitational constant x flow rate x height difference) / efficiency
The given information states that the water loses 160 m of altitude and that we can neglect its change of kinetic energy, so we only need to consider the potential energy change. The gravitational constant is 9.81 m/s^2, and the efficiency is given as 87%.
Therefore, the formula becomes:
Power = (1000 kg/m^3 x 9.81 m/s^2 x flow rate x 160 m) / 0.87
Simplifying this formula, we get:
Flow rate = Power x efficiency / (density of water x gravitational constant x height difference)
Assuming a power output of 1 MW (or 1,000,000 W), the flow rate required is:
Flow rate = 1,000,000 W x 0.87 / (1000 kg/m^3 x 9.81 m/s^2 x 160 m)
Flow rate = 7.16 m^3/s
Therefore, a flow rate of approximately 7.16 cubic meters per second is required to produce 1 MW of power with 87% efficiency, given that the water enters and leaves the system at a low speed and loses 160 m of altitude during the process.

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Answer:

It will travel at 1 m/s2

Answer:

It will travel at 1 m/s2

Explanation:

Answer:

probly c or b

Explanation: experinse

Answer: A, C, E

Explanation:

Potassium and sodium both belong to Group 1. They have the same number of valence electrons. Therefore, they form similar compounds with other elements.

Yes , Crystalline regions in thermoplastics help increase their strength, stiffness, and resistance to heat.

This is because the crystalline structure provides a more ordered arrangement of polymer chains, which increases the intermolecular forces and makes the material stronger.

Crystallinity in thermoplastics can be introduced by cooling the material from its molten state to its solid state, which allows the polymer chains to arrange themselves in a more ordered structure. This is known as "thermal crystallization."

Alternatively, crystallinity can be induced by stretching or orienting the material in a particular direction, which also causes the polymer chains to align themselves in a more ordered structure. This is known as "cold crystallization" or "orientation-induced crystallization."

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a)

i. The force exerted on the piston by the air in the freezer is 240 N.

ii. The work done on the piston by the air as it pushes the piston 0.021 m into the cylinder is 5.04 J.

b) The change in the internal energy of the cylinder is 3486 J.

a)  

i. To calculate the force exerted on the piston by the air in the freezer, we can use the formula:

Force = Pressure * Area

Given:

Pressure (P) = 1.0 × \(10^5\) Pa

Area (A) = 2.4 ×\(10^(^-^3^) m^2\)

Substituting these values into the formula, we have:

Force = (1.0 × 10^5 Pa) * (2.4 ×\(10^(^-^3^) m^2)\)

      = 240 N

ii. To calculate the work done on the piston by the air in the freezer as the air pushes the piston, we can use the formula:

Work = Force * Distance

Given:

Force = 240 N

Distance (d) = 0.021 m

Substituting these values into the formula, we have:

Work = (240 N) * (0.021 m)

     = 5.04 J

b) To calculate the change in the internal energy of the cylinder, we can use the formula:

ΔU = mcΔT

Given:

Initial temperature (T1) = 21°C = 21 + 273 = 294 K

Final temperature (T2) = -18°C = -18 + 273 = 255 K

Thermal capacity (c) = 89 J/°C

Substituting these values into the formula, we have:

ΔU = (89 J/°C) * (294 K - 255 K)

   = 3486 J

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The first part of the question asks about the lethal dose of γ rays in Sv, while the second part asks about the energy released in a fission reaction.

Part A: The lethal dose of γ rays in Sv is dependent on various factors, including the duration of exposure and the individual's sensitivity to radiation. However, the given information states that a dose of 4.7 Sv in a short period would be lethal to about half of the people subjected to it. This means that 4.7 Sv is a very high dose of radiation and can cause severe damage to the body.

Part B: The given fission reaction involves the neutron (n) colliding with uranium-235 (235U), resulting in the formation of zirconium-94 (94Zr), tellurium-139 (139Te), and three neutrons. To determine the energy released in this reaction, we need to calculate the difference in the mass of the reactants and products and then convert it into energy using Einstein's famous equation, E=mc². By subtracting the mass of the reactants from the mass of the products, we get a mass defect of 0.203775 u. Multiplying this by the speed of light squared (\(c{2}  = 9 * 10^{16}  m^{2} /s^{2}\)) gives us the energy released, which is \(1.83 * 10^{13}\) J.

A dose of 4.7 Sv of γ rays in a short period can be lethal to about half of the people exposed to it. The energy released in the given fission reaction is 1.83 * 10¹³ J, which is a significant amount of energy. Both parts of the question demonstrate the potential dangers and power of radiation and nuclear reactions.

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The total momentum of the system is 22500 kg-m/s i + 37500 kg-m/s j.

Momentum is given by the formula,

P = m * v

where, m is mass

v is velocity

Given that,

Mass of the first car m₁ = 1500 kg

Mass of the second car m₂ = 1500 kg

Velocity of the first car v₁ = 25 m/s

Velocity of the second car v₂ = 15 m/s

The momentum of the first car is p₁ = m₁ * v₁ = 1500 * 25  = 37500 kg-m/s j

The momentum of the second car is p₂ = m₂ * v₂ = 1500 * 15  = 22500 kg-m/s i

The total momentum of the system is sum of momentum of both the cars.

⇒ 22500 kg-m/s i + 37500 kg-m/s j

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Answer:

Elevate the wound.

Hope this helped!

The answer is that gravity does 29.4 Joules (J) of work on the book as it is lifted from the table to the bookshelf.

When the book is lifted from the table to the shelf, gravity does some work on the book. The book was at a certain height when it was lifted, and its final position was 2.25 meters above the ground.

Work is the force multiplied by the distance through which it acts, so work is done on the book by gravity. The book has no acceleration, so the net force acting on it is zero. The force of gravity is counteracted by the force of the lift.

The work done by gravity on the book is zero because gravity has no movement in the direction of force when the book is being lifted. When you pick the book up and place it on the bookshelf, gravity doesn't do any work because the book doesn't move up or down.  The energy used to lift the book is the same as the work done against gravity, which is given by the formula:

Potential energy (PE) = mghWhere m is the mass of the book, g is the acceleration due to gravity, and h is the height the book is lifted to.

Therefore, Potential energy (PE) = mgh = 2.0 × 9.8 × (2.25 − 0.75) = 29.4 J. Hence, the work done by gravity on the book is 29.4 J.

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Given :-

To Find :-

Solution :-

For figure refer to attachment .

So the block will move if the angle of the inclined plane is greater than the angle of repose . We can find it as ,

\(\longrightarrow \theta_{repose}= tan^{-1}(\mu_s)\)

Substitute ,

\( \longrightarrow \theta_{repose}= tan^{-1}( 0.2)\)

Solve ,

\(\longrightarrow\underline{\underline{\theta_{repose}= 16.6^o }}\)

Hence ,

\(\longrightarrow\theta_{plane}>\theta_{repose}\)

Hence the block will slide down .

Now assuming that block is released from the reset , it's initial velocity will be 0m/s .

And the net force will be ,

\(\longrightarrow F_n = mgsin53^o - \mu_k N \)

Substitute, N = mgcos53⁰ ( see attachment)

\( \longrightarrow ma_n = mgsin53^o - \mu_k mgcos53^o \)

Take m as common,

\( \longrightarrow\cancel{m }(a_n) = \cancel{m}( gsin53^o - \mu gcos53^o)\)

Simplify ,

\( \longrightarrow a_n = gsin53^o - \mu_k g cos53^o\)

Substitute the values of sin , cos and g ,

\( \longrightarrow a_n = 10( 0.79 - 0.2 (0.6)) \)

Simplify ,

\( \longrightarrow a_n = 10 ( 0.79 - 0.12 ) \\\\ \longrightarrow a_n = 10 (0.67)\\\\ \longrightarrow \underline{\underline{a_n = 6.7 m/s^2}}\)

Now using the Third equation of motion namely,

\( \longrightarrow2as = v^2-u^2\)

Substituting the respective values,

\( \longrightarrow2(6.7)(5) = v^2-(0)^2 \)

Simplify and solve for v ,

\( \longrightarrow v^2 = 67 m/s\\\\\longrightarrow v =\sqrt{67} m/s \\\\\longrightarrow\underline{\underline{ v = 8.18 m/s }} \)

Hence the velocity after covering 5m is 8.18 m/s .

Answer:

Because we wish that a dragon would just destroy school and you can ride your new dragon to starbucks, you'll be famous!!! BUT THEN REALITY SMACKS YOU IN THE FACE WITH A STUPID STACK OF HOMEWORK!!!

Explanation:

Answer:  Diffraction effects are more easily detected in the case of sound waves than light waves.
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Sound waves have higher wavelength and its wavelength is comparable to the dimension of opaque encounters in our daily life. Hence diffraction effects are more easily detected in the case of sound waves than light waves.

Explanation: There for it's "TRUE"

Answer:

True

Explanation:

You're welcome.

The brightest star is Sirius (-1.46).

The apparent magnitude of a star is a measure of how bright the star appears to an observer on Earth. Here are some key points to explain this concept:

1. Apparent magnitude is a logarithmic scale that quantifies the brightness of a star relative to other stars in the sky.

2. The scale is set such that a difference of 5 magnitudes corresponds to a brightness ratio of exactly 100:1.

3. Lower magnitudes correspond to brighter stars, with negative magnitudes being the brightest.

4. The human eye can perceive stars down to an apparent magnitude of about 6 under optimal viewing conditions, but telescopes can detect much fainter objects.

5. The apparent magnitude of a star depends on both its intrinsic brightness (absolute magnitude) and its distance from Earth.

6. Stars can appear to have the same apparent magnitude even if they have very different absolute magnitudes, due to differences in their distances.

So, the apparent magnitude of a star is a logarithmic measure of its brightness as seen from Earth, which depends on both its intrinsic brightness and its distance from us. Lower magnitudes correspond to brighter stars, and the scale is set such that a difference of 5 magnitudes corresponds to a brightness ratio of 100:1.

The apparent magnitude of a star is a measure of how bright it appears to an observer on Earth. It is a logarithmic scale, meaning that each increase of 1 in magnitude corresponds to a decrease in brightness by a factor of approximately 2.5.

Therefore, a star with a smaller apparent magnitude is brighter than a star with a larger apparent magnitude. Based on the given table, Sirius has the smallest apparent magnitude (-1.46) and is the brightest star.

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An ideal solenoid has an inductance of 6.8 mh. to generate an EMF of 2.6 v, The current should change at a rate of 2.62 * \(10^{-3}\) A / second

induced EMF in a solenoid = -L * (di/dt)

∈ = -L * (di/dt)

di/dt = - L / ∈

       = - 6.8 * \(10^{-3}\) / 2.6

       = - 2.62 * \(10^{-3}\) A / second

The current should change at a rate of 2.62 * \(10^{-3}\) A / second

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Answer:

Av = 12.9 [km/h]

Explanation:

We must remember that the average speed is defined as the relationship between the space traveled over a certain time.

\(Av = x/t\)

where:

Av = average speed [km/h]

x = distance [km]

t = time [hr]

For when he was on the bus

The distance can be calculated by clearing the equation, for the term of the distance

\(x_{1}= A_{v}*t\\x_{1}= 15*1.6\\x_{1}=24[km]\)

For when Andy was walking

\(x_{2}=A_{v}*t\\x_{2}=4.5*0.4\\x_{2}=1.8 [km]\)

Now the total time is the sum of 1.6 + 0.4 = 2 [hr], and the total distance is the sum of the distances calculated above.

\(x = 24 + 1.8\\x = 25.8 [km]\)

The average speed is calculated using the ratio of space to time.

\(Av = 25.8/2\\Av = 12.9 [km/h]\)

Answer:

0.667 m/s

Explanation:

Given that,

Mass of a rubber bullet, m₁ = 20 g = 0.02 kg

Initial speed of rubber bullet, u₁ = 60 m/s

Mass of the wood block, m₂ = 3 kg

Initial speed of the wooden block, u₂ = 0

A rubber bullet hits the stationary wood block. The rubber bullet  ricochets off the wood block with a velocity of 40.0 m/s in the opposite  direction.

Final speed of rubber bullet, v₁ = -40 m/s

Using the conservation of momentum. It will remains conserved. Let v₂ is the velocity of the wood block.

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\0.02 \times 60+3\times 0=0.02 \times (-40)+3\times v_2\\\\1.2=-0.8+3v_2\\\\2=3v_2\\\\v_2=0.667\ m/s\)

So, the velocity of the wood block is 0.667 m/s.

Given data-Mass of the pumpkin, m = 7.77 kgHeight from which pumpkin falls, h = 12.3 mTime taken by pumpkin to come to rest, t = 444 ms = 0.444 s. Average force imparted by the ground on the pumpkin = F, Here, we need to calculate the average force exerted by the ground on the pumpkin.

We can calculate the same using the work-energy principle. According to the work-energy principle, the work done on an object is equal to the change in its kinetic energy. Mathematically, W = ΔKE  Total work done on the pumpkin is equal to the work done by the gravitational force of the earth on the pumpkin when it falls from a height of h. So, W = mghHere, g = 9.81 m/s² is the acceleration due to gravity. Work done by the ground on the pumpkin when it comes to rest = -1/2 mv². By the work-energy principle, W = work done by the ground + work done by gravity on the pumpkin= -1/2 mv² - mghHere, the final velocity of the pumpkin, v = 0 as it comes to rest. Therefore, W = -mghAs we know, W = Fd, where d is the distance through which the force is applied. Here, d = h.Hence, F = -mgThe negative sign indicates that the direction of the force exerted by the ground is opposite to the direction of motion of the pumpkin (i.e., upward direction). So, substituting the given values,m = 7.77 kg, g = 9.81 m/s², h = 12.3 mF = - (7.77 kg) × (9.81 m/s²) × (12.3 m) = -907.1961 N (upward)Therefore, the average force imparted by the ground on the pumpkin is 907.1961 N (upward).

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The final image is located approximately 133.42 cm to the right of the second lens.

To calculate the position of the final image relative to the second lens, we can use the lens formula:

1/f = 1/v - 1/u

where f is the focal length of the lens, v is the image distance, and u is the object distance.

For the first lens:

f₁ = -50 cm (negative focal length for a negative lens)

u₁ = -300 cm (object distance to the left of the lens)

Using the lens formula, we can find the image distance for the first lens:

1/v₁ - 1/u₁ = 1/f₁

1/v₁ = 1/f₁ - 1/u₁

1/v₁ = 1/-50 - 1/-300

1/v₁ = -1/50 + 1/300

1/v₁ = -6/300 + 1/300

1/v₁ = -5/300

v₁ = -300/5

v₁ = -60 cm

The image formed by the first lens is located 60 cm to the left of the first lens.

For the second lens:

f₂ = 200 cm (positive focal length for a positive lens)

u₂ = -116 cm (object distance to the right of the first lens)

Using the lens formula, we can find the image distance for the second lens:

1/v₂ - 1/u₂ = 1/f₂

1/v₂ = 1/f₂ - 1/u₂

1/v₂ = 1/200 - 1/-116

1/v₂ = 1/200 + 1/116

1/v₂ = 116/23200 + 200/23200

1/v₂ = 316/23200

v₂ = 23200/316

v₂ ≈ 73.42 cm

The image formed by the second lens is located approximately 73.42 cm to the right of the second lens.

To calculate the position of the final image relative to the second lens, we subtract the image distance of the first lens from the image distance of the second lens:

Final image position = v₂ - v₁

Final image position ≈ 73.42 - (-60)

Final image position ≈ 133.42 cm

Therefore, the final image is located at a distance of approximately 133.42 cm to the right of the second lens.

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In a parallel circuit the current flows trough different paths.

Then, A parallel circuit is described as a type of circuit in which there are several current paths.

Answer:

B

Explanation:

i worked it out on a diffrent sheet so its hard to explain

The current, according to Ohm's law if, if The voltage between two points in a circuit is 5 V and the resistance between the points is 80 ohms, is 0.063 A so, option B is correct.

Electric currents can be created by the movement of any electric charge carriers, including ions (atoms that have gained or lost one or more electrons), holes, or subatomic charged particles (such electrons with a negative charge or protons with a positive charge) (electron deficiencies that may be thought of as positive particles).

Given:

The voltage between two points in a circuit is 5 V,

If the resistance between the points is 80 ohms,

Calculate the current using Ohm's law as shown below,

Current = The voltage between two points / the resistance between the points

Current = 5 / 80

Current = 0.0625

Current = 0.063 A,

Thus, the current according to Ohm's law is 0.063 A.

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A current of 1.00 A flows in a wire. 1.60 × 10¹⁹ electrons flow past any point in the wire per second.

Let's calculate how many electrons are flowing past any point in the wire per second.

The amount of electric charge flowing through a conductor per unit time is known as electric current. The current flowing in a wire is a measure of the quantity of electrons passing a certain point in the circuit. When one coulomb of charge passes a point in the wire per second, the current is 1 ampere.

A coulomb of charge corresponds to 6.24 × 1018 electrons, or Avogadro's number (6.02 × 1023) of electrons. As a result, the amount of electrons flowing past any point in the wire per second can be calculated as follows:

I = Q / t

Charge = I * t

Charge = 1.00 C

Charge = 6.24 × 10¹⁸ electrons

Therefore, Number of electrons flowing past any point in the wire per second

= (1.00 C / 6.24 × 10¹⁸ electrons) x 1s

= 1.60 × 10⁻¹⁹

coulombs of charge / electron1.60 × 10⁻¹⁹ coulombs of charge / electron = 1 electron per 1.60 × 10⁻¹⁹ seconds

Therefore, 1.60 × 10¹⁹ electrons flow past any point in the wire per second.

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Answer:

9 years old and he/she crawl like at 2 years old

In a simple harmonic motion, the kinetic energy of the oscillating mass reaches a maximum at the equilibrium position or the mean position of the oscillation.

Oscillation is the motion of an object that regularly moves about a central position or point in a periodic manner. A simple harmonic motion is a type of oscillation that is regular and repeating, where the object vibrates about an equilibrium or mean position.

Simple harmonic motion is characterized by the following features: It is periodic and symmetrical about the equilibrium position.

The acceleration is proportional and in the opposite direction to the displacement from the equilibrium, position. The kinetic energy of the oscillating mass reaches a maximum at the equilibrium position.

When the mass reaches the extremities of its displacement, the potential energy is maximum while the kinetic energy is minimum.

At the mean or equilibrium position, the potential energy is minimum and the kinetic energy is maximum.  The maximum kinetic energy is equal to the maximum potential energy at the extremities of displacement.

This means that the total mechanical energy of the oscillating mass is constant or conserved throughout the motion.

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Energy cannot be generated or destroyed; it can only be changed from one form of energy to another, according to the rule of conservation of energy. This implies that a system always possesses the same amount of energy, barring external energy addition.

There are three fundamental quantities that are preserved in mechanics. These are power, forward motion, and angular momentum. Energy is a conserved quantity, which could surprise you if you've read instances in previous pages, such the kinetic energy of charging elephants.

According to a conservation law in physics, a certain measurable attribute of an isolated physical system does not change over time as the system changes.

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Energy cannot be created or destroyed, says the law of conservation of energy. For instance, when a toy car is rolled down a ramp and slams into a wall, kinetic energy is transformed into potential energy.

In mechanics, three fundamental quantities are conserved. Power, forward motion, and angular momentum are these. If you've seen examples on earlier chapters, such the kinetic energy of charging elephants, it could come as a surprise to you that energy is a conserved quantity.

Energy cannot be created or destroyed; instead, it can only be changed from one type of energy to another, according to the principle of energy conservation.

This means that a system always has the same amount of energy unless additional energy is added from the outside. This is especially puzzling in the case of non-conservative forces, where energy is converted from mechanical to thermal but the total amount of energy remains constant. To be used, energy must be transformed from one form to another.

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The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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Answer: C 1440 C

Explanation:

Charge = current (amp) x time (second)

\(9.6 \times 2.5 \times 60 = 1.44 \times 10^3\,\rm C$\)

The maximum speed will be 0.74m/s

Friction, the force that resists a solid object from sliding or rolling over another. Frictional forces, such as the traction required to walk without slipping, can be beneficial, but they also present significant resistance to motion. About 20% of a car's engine power is expended to overcome the frictional forces of moving parts.

The speed that corresponds to the maximum centripetal force (Fₓ) that could be provided by the friction is given as:

f = Fₓ

f = μN is the friction force. where, μ is the coefficient of static friction and this is the maximum force the friction can provide.

Fₓ  = mv²/r

N = mg (flat road)

Thus:

μ mg = mv²/r

So, according to the given question:

μ = 0.60

m = 1200kg

r = 95.0 mm or 95×10⁻³m

μ mg = mv²/r

0.60 × 9.8 = v²/ 95×10⁻³

v² = 558.6 ×10⁻³

v = 0.74m/s

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