an object is executing simple harmonic motion. what is true about the acceleration of this object? (there may be more than one correct choice.)choose all that object is executing simple harmonic motion. what is true about the acceleration of this object? (there may be more than one correct choice.)choose all that acceleration is a maximum when the displacement of the object is a acceleration is a maximum when the displacement of the object is acceleration is zero when the speed of the object is a acceleration is a maximum when the object is instantaneously at acceleration is a maximum when the speed of the object is a maximum.request answer

Answers

Answer 1

An object is executing simple harmonic motion, statements that are true about the acceleration of this object : - Acceleration is a maximum when the displacement of the object is a maximum; - Acceleration is zero when the speed of the object is a maximum ; - Acceleration is a maximum when the object is instantaneously at rest.

When an object is executing simple harmonic motion, it means that it is oscillating back and forth about an equilibrium position due to a restoring force that is proportional to its displacement from that position. Examples of simple harmonic motion include a mass on a spring, a pendulum, or a vibrating tuning fork.

1. Acceleration is a maximum when the displacement of the object is a maximum: This is because the restoring force is strongest when the displacement from equilibrium is greatest. According to Newton's second law of motion (F = ma), a greater force results in a greater acceleration.

2. Acceleration is zero when the speed of the object is a maximum: This occurs at the equilibrium position, where the object momentarily comes to a stop before changing direction. At this point, the restoring force is zero and the acceleration is also zero.

3. Acceleration is a maximum when the object is instantaneously at rest: This occurs at the turning points of the motion, where the object is momentarily at rest before changing direction. At this point, the restoring force is strongest and the acceleration is also at a maximum.

Therefore, the correct choices for what is true about the acceleration of an object executing simple harmonic motion are:

- Acceleration is a maximum when the displacement of the object is a maximum.
- Acceleration is zero when the speed of the object is a maximum.
- Acceleration is a maximum when the object is instantaneously at rest.

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Related Questions

16. Which of these provides most of the oxygen in Earth's
atmosphere?

coral reefs
rainforest plants
ocean phytoplankton
continental grasslands

Answers

Answer:

Ocean phytoplankton

Explanation:

The sea and ocean creates oxygen from the plants (sea creatures) that exist there. These plants generate oxygen when used as a-product of photosynthesis, a mechanism that transforms carbon dioxide through sunlight into carbohydrates that the body(plants) can use for nutrition.

A snowball that will be used to build a snowman is at the top of a only hill. If the
potential energy of the snowball is 520 J and the mass of the snowball is 2.2 kg,
what is the height of the hill?

Answers

Answer:

h = 24.11 m

Explanation:

Given that,

The potential energy of the snowball is 520 J

The mass of the snowball is 2.2 kg

We need to find the height of the hill. The potential energy of an object is given by the formula as follows :

\(E=mgh\)

g is acceleration due to gravity

h is height of the hill

\(h=\dfrac{E}{mg}\\\\h=\dfrac{520}{2.2\times 9.8}\\\\h=24.11\ m\)

So, the height of the hill is 24.11 m.

When ⁶⁰₁₄₄Nd decays to 58₁₄₀Ce , identify the particle that is released. (a) a proton (b) an alpha particle (c) an electron(d) a neutron (e) a neutrino

Answers

When ⁶⁰₁₄₄Nd decays to 58₁₄₀Ce, the particle that is released is an electron (option c).

The term "beta decay" or "-decay" refers to this kind of radioactive decay. In beta decay, a neutron within an atom's nucleus is changed into a proton, and the nucleus releases an electron (also referred to as a beta particle). The equation: can be used to describe this process.

⁶⁰₁₄₄Nd → ⁵⁸₁₄₀Ce + e⁻

The particle that is released during the decay process is designated as the electron (e) in this equation. The 58140Ce nucleus is created when the neutron in the 60144Nd nucleus is changed into a proton while the electron is released with tremendous energy.

It should be noted that an antineutrino (ve-bar) is also released along with the electron during beta decay. However, among the available choices, the particle is directly the emphasis.

Hence, the answer is option C.

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The engine of a small and unmanned airplane produces a known and specific sound frequency (not given). A stationary sound detection device observes that the known emitted sound frequency is 90% of the perceived sound frequency. Relative to the detection device, in which direction and at what velocity is the plane moving

Answers

Answer:

the source (plane) moves away from the observer ,     v_{s} = 38.2 m / s

Explanation:

This is an exercise in the Doppler effect, which is the change in frequency due to the relative movement of the source and the observer; in this case the observer the sound detection system that is fixed and the source (plane) is mobile, in this case the relationship that describes the process is

            \(f'= f ( \frac{v}{v \ \frac{-}{+} \ v_{s} })\)

where negative sign is for the source moving towards the observer

It indicates that the frequency of the received sound is 90% of the emitted frequency

         f '/ f = 0.90

let's substitute

           0.9 = \(\frac{v}{v \ \frac{-}{+} \ v_{s} }\)

            \(v \ \frac{-}{+} v_{s}\) = v / 0.9

           

The speed of sound is v = 344 m / s, let's substitute

           \(344 \ \frac{-}{+} v_{s}\) = 344 / 0.9

           344 \ \frac{-}{+} v_{s} = 382.2

Let's analyze this expression, to fulfill the equation the speed of the source must be positive, therefore the source moves away from the observer

           344 +\(v_{s}\)= 382.2

           v_{s} = 382.2 -344

           v_{s} = 38.2 m / s

¿Qué fuerza se deberá aplicar en un embolo pequeño de una prensa hidráulica

de 12 cm de area, para levantar un cuerpo de 70 000 N de peso, que se encuentra en el embolo mayor y cuya área es de 85 cm?

Answers

The force that needs to be applied to the small piston of the hydraulic press to lift a body weighing 70,000 N is approximately 495,833.33 N.

To calculate the force required to lift a body using a hydraulic press, we can use Pascal's principle, which states that the pressure applied to an enclosed fluid is transmitted equally in all directions.

In this case, we have a hydraulic press with a small piston of 12 cm² area and a large piston of 85 cm² area. The weight of the body to be lifted is 70,000 N.

Step 1:

Calculate the pressure on the small piston:
Pressure = Force / Area
Pressure = 70,000 N / 12 cm²

Step 2:

Calculate the force required on the large piston:
Force = Pressure x Area
Force = Pressure x 85 cm²

Let's solve these calculations.

Step 1:
Pressure = 70,000 N / 12 cm²
Pressure = 5,833.33 N/cm²

Step 2:
Force = 5,833.33 N/cm² x 85 cm²
Force = 495,833.33 N

Therefore, the force that needs to be applied to the small piston of the hydraulic press to lift a body weighing 70,000 N is approximately 495,833.33 N.

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A lightning bolt travels at 270,000 miles/hour. How fast is that in meters per second? Note that 1 mile = 1609 meters.

Answers

Answer:120700.8

Explanation:

Practice questions 1) A flea has a mass of 4.5 x10^-7 and can jump vertically upwards to a height of 6cm.calculate (a) the kinetic energy of the flea as it leaves the ground (b)its initial velocity.

Answers

The kinetic energy of the flea is 2.7×10^-7J and the initial velocity is 1.09m/s

What is kinetic energy?

The kinetic energy of an object is the energy that it possesses due to its motion. It is also defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Kinetic energy is measured in Joules and it is expressed as K.E = ½mv². Where m is the mass of the object and v is it's velocity.

the initial velocity of the object can be calculated as

V²= u²-2gh. At this point the final velocity will be 0

u²= 2gh

u² = 2× 9.8× 0.06m

u² = 1.18

u= √1.18

u= 1.09m/s

therefore K.E = ½× 4.5× 10^-7× 1.09²

K.E = 2.7×10^-7 J

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True or false?
There is no
difference
between speed
and velocity

Answers

Answer:

False

Explanation:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

The reactance of a capacitor is 4.0 k ohms at a frequency of 0.60 khz. What is the capacitance?

Answers

The capacitance of a capacitor can be calculated using the formula C = 1 / (2πfXc), In this case, the reactance is given as 4.0 kΩ (4000 Ω) and the frequency is 0.60 kHz (600 Hz).

Using the formula, we can substitute the given values to find the capacitance:

C = 1 / (2π * 600 * 4000) = 1.32 × 10^(-7) Farads.

Therefore, the capacitance of the capacitor is approximately 1.32 × 10^(-7) Farads.

The capacitance of a capacitor determines its ability to store electric charge and is measured in Farads. The reactance of a capacitor is an opposition to the flow of alternating current and depends on the frequency of the current.

In this case, we are given the reactance and frequency, and we can use the formula to calculate the capacitance. By substituting the values into the formula, we find that the capacitance is 1.32 × 10^(-7) Farads. This means that the capacitor can store a small amount of electric charge at the given frequency and reactance.

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how much time does it take for a bird flying at a speed of 45 mph to travel a distance of 1800 miles?​

Answers

1000 kilometres........

What is a living factor in the environment

Answers

Answer:

A living factor in the environment refers to any living organism or species that play a role in the ecosystem and contributes to the balance of the natural environment. Examples of living factors in the environment include plants, animals, fungi, and microorganisms.

Please help me! Those who love cars and motorcycles I think you can help me
there is a kawasaki H2R 236hp; 217kg
a Mac Laren:625hp; 1375kg
a Bugatti 1100hp; 2136kg
and a 1350hp Nissan GTR; 1650kg
Which car will be able to reach 320km/h before the motorcycle?
The Data:
The power associated with one horsepower is 735.5 watts

Answers

The only vehicle capable of outpacing the Ninja H2R out of the box was the severely tuned, 1,350 horsepower SPE Nissan GT-R, which caught and passed the superbike at the.

Which is faster, the Kawasaki Ninja H2R or the Bugatti?

Slowly coming off the line, the biker eventually catches up with and surpasses the Veyron.When the H2R triggers the speed camera at 194.5 mph—nearly 15 mph faster than that of the Bugatti—it is still harsh in acceleration.

A bike is faster than a Lamborghini, right?

The bike easily overtakes the Lamborghini after another strong start from the latter.In comparison, the Huracan needs 9.6 seconds to finish the quarter mile.

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HELP ME PLEASE. explain it if you can

HELP ME PLEASE. explain it if you can

Answers

The planet Ralph is falling into is Jupiter.

Ralph can use the period of the pendulum he created to determine the gravitational field strength of the planet he is falling into. The formula for the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the gravitational field strength. Rearranging this formula to solve for g, we get g = 4π²(L/T²).

Plugging in the values given, we get:

For Jupiter, g = 4π²(0.05 m)/(0.282 s)² = 24.59 m/s²

For Saturn, g = 4π²(0.05 m)/(0.282 s)² = 10.34 m/s²

For Neptune, g = 4π²(0.05 m)/(0.282 s)² = 11.03 m/s²

For Uranus, g = 4π²(0.05 m)/(0.282 s)² = 8.76 m/s²

Comparing the calculated values to the table given, we can see that the closest match is Jupiter with a gravitational field strength of 24.79 m/s². Therefore, Ralph is falling into Jupiter.

What is jupiter?

Jupiter is the fifth planet from the sun and the largest planet in our solar system. It is a gas giant, which means it is mostly composed of hydrogen and helium, and it has no solid surface. Instead, the gas gradually becomes denser and hotter as you move closer to the center of the planet.

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What do good electrical conductors and thermal conductors have in common?

Answers

Answer:

Usually, electrical conductors have loosely bound electrons. Materials that conduct heat are thermal conductors. ... Metals typically conduct both heat and electricity. Carbon conducts ​electricity as graphite, but insulates as diamond, so the form or allotrope of a material can be important

compare the optical density air and glass

Answers

Answer:

Glass is an optically denser medium than air and water.

Explanation:

hope it helps have a nice night!

Answer:

The speed of light depends on the optical density of the medium. Therefore, light travels with different speeds in different media having different optical densities. For example, the speed of light in air is 3 × 108 m/s, whereas that in glass is 2 × 108 m/s and in water, it is 2.25 × 108 m/s

A car slows down from 27.7 m/s
to 10.9 m/s in 2.37 s.
What is its acceleration?

Answers

Answer:

a = (Vf - Vi) / t = (10.9 - 27.7) / 2.37 = -16.8 / 2.37 = -7.09 m/s/s

negative means slowing down

Explanation:

A racehorse gallops at a speed of 65 km / h. how long will it take to reach the finish line in a 1,500 m race?

Answers

It will take the racehorse approximately 83 seconds (or 1 minute and 23 seconds) to reach the finish line in a 1,500 m race at a speed of 65 km/h.

To find out how long it will take the racehorse to reach the finish line, we need to use the formula:

time = distance ÷ speed

where:

distance = 1,500 m

speed = 65 km/h = (65 × 1,000) m/h = 65,000 m/h

Now, we need to convert the speed from meters per hour to meters per second, since the distance is given in meters. We can do this by dividing the speed by 3,600 (the number of seconds in an hour):

speed = 65,000 m/h ÷ 3,600 s/h = 18.06 m/s (rounded to two decimal places)

Substituting the values into the formula, we get:

time = 1,500 m ÷ 18.06 m/s = 83.03 seconds (rounded to two decimal places)

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Analysis Questions 1. If the candies were packaged mechanically, what would you expect to see in the distribution? 2. If the candies were packaged randomly, what would you expect to see in the distribution? 3. What did your data show you? What does it suggest? 4. Find someone else in the class who had the same candy as you. Compare your results. Does your data agree? Explain Conclusion 5. Does the data cause you to support or reject your hypothesis? Explain.

Answers

1. If the candies were packaged mechanically, I would expect to see an even distribution of each color. This is because machines are typically programmed to distribute items evenly.

2. If the candies were packaged randomly, I would expect to see an uneven distribution of each color. This is because there is no way to guarantee that each color will be represented equally when items are packaged randomly.

3. My data showed me that the distribution of colors in the bag of Skittles was uneven. This suggests that the candies were not packaged mechanically, but were instead packaged randomly.

4. I compared my results with someone else in the class who had the same candy as me. Their results were similar to mine, which suggests that the distribution of colors in the bags of Skittles is not consistent.

5. The data causes me to reject my hypothesis that the candies were packaged mechanically. The data suggests that the candies were instead packaged randomly.

Here are some additional thoughts on the data:

* The uneven distribution of colors in the bag of Skittles could be due to a number of factors, such as the way the candies are sorted, the way the machines are programmed, or the way the bags are filled.

* It is important to note that the data is based on a small sample size. It is possible that the distribution of colors would be more even if a larger sample size was used.

* Overall, the data suggests that the candies are not packaged mechanically. However, more research is needed to confirm this conclusion.

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Which acceleration-time graph corresponds to the motion of the car if it moves toward the right, while slowing down at a steady rate

Which acceleration-time graph corresponds to the motion of the car if it moves toward the right, while

Answers

We define acceleration as the rate of change of the velocity

Thus, if you have positive velocity and positive acceleration, your speed increases.

If you have positive velocity and negative acceleration, your speed decreases.

Now you get the idea, we will see that the correct option is graph 1.

We know that the car moves towards the right (let's define this as "the car has positive velocity") and we also know that te car is slowing down constantly (thus the acceleration needs to be negative and constant).

By looking at the graphs, the only one with these properties is graph 1.

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A passenger aeroplane accelerates from rest along a runway. It accelerates at a uniform rate for 3.5s. At this point it reaches a speed of 84 m/s and then takes off. Calculate the acceleration of the aeroplane along the runway.

Answers

Please find attached photograph for your answer. Do comment whether it is useful or not. Mark as Brainliest if you like my answer.

A passenger aeroplane accelerates from rest along a runway. It accelerates at a uniform rate for 3.5s.

You are allowed to change the number of molecules of each substance by adding coefficients in front of the formulas.

True
False

Answers

Answer:

This is false.

Explanation:

No; you cannot change the formulas of individual substances because the chemical formula for a given substance is characteristic of that substance. What you can do, however, is to change the number of molecules that react or are produced.

Can anyone help with this physics question

Can anyone help with this physics question

Answers

i think trace 1 is ac and trace 2 if dc but i’m not sure what will happen when a higher frequency is added?

How stars are twinkling in the sky?

Answers

Answer:

As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

What is the acceleration of a vehicle that changes its velocity from 100 km/h to a dead stop in 30 s ? Answer in units of m/s 2 .

Answers

Answer:

a = \(-\frac{25}{27}\) m/s²

Explanation:

Acceleration (a) = (final velocity - initial velocity) ÷ (final time - initial time) =  \(\frac{v_{f} - v_{i} }{t_{f} - t_{i} }\)

Converting the speed from km/h to m/s;

100 km = 100000m

1hr = 3600s

∴ 100km/hr ⇄ \(\frac{100000 m}{3600 s}\) = \(\frac{250}{9} m/s\)

Acceleration = \(\frac{0 - 250/9}{30}\) = \(-\frac{250}{9 * 30} = -\frac{25}{27}\) m/s²

i.e deceleration = \(\frac{25}{27}\) m/s²


What causes the spectral shifts you observed?
• How can scientists use spectra analysis to support the Big
Bang Theory?

Answers

Spectral shifts are caused by the movement of the spectrum to shorter wavelengths, while the Big Bang Theory is supported by spectra analyses because we can determine how spectra of electromagnetic radiation from stars changes depending on their relative position.

What is the Big Bang Theory?

The Big Bang Theory is a widely accepted model in physics about the boring of the Universe, which it is believed occurred though a big explosion, while light spectra refers to the observation of the electromagnetic radiation emitted by stars.

Therefore, with this data, we can see that the Big Bang Theory obtains supportive evidence from the emission of electromagnetic spectra of stars.

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A person runs 3km north. One hour later, she runs 3km south, which of the following statements describes the persons complete trip

Answers

The person's complete trip was a 6km round trip because they traveled 3km north and then 3km south, returning to their original location.

What is trip?

A trip is a journey or excursion to some destination, usually for a specific purpose. It can be as short as a day trip or as long as a round-the-world adventure. A trip typically involves travel by foot, car, railroad, boat, or airplane and often involves multiple destinations. It may also involve activities such as camping, hiking, sightseeing, and other leisure activities. Travelers usually plan trips in advance to ensure they have enough time to see and do the things they want to. Trips can also be spontaneous, with travelers deciding on the fly where to go and what to do.

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A circular current-carrying loop lies so that the plane of the loop is perpendicular to a constant magnetic field of strength B. Suppose that the radius R of the loop could be made to increase with time t so that R = at, where a is a constant. What is the magnitude of the emf that would be generated around the loop as a function of t? (A) 2πBa^2t (B) πBa^2t (C) 2πBat (D) 2πBt (E) (π/3)Ba^2t^3

Answers

The magnitude of the emf generated around the loop as a function of t is 2πBa²t. (A)

Steps to calculate the emf generated around the loop


1. The area A of the circular loop is given by A = πR² = π(at)².


2. The magnetic flux Φ through the loop is given by Φ = B * A, where B is the magnetic field strength.


3. Substituting A into the magnetic flux equation, we get Φ = B * π(at)².


4. According to Faraday's law of electromagnetic induction, the magnitude of emf is given by the absolute value of the time rate of change of magnetic flux: emf = |dΦ/dt|.


5. Differentiating Φ with respect to t: dΦ/dt = B * π * 2(at) * a.


6. The magnitude of the emf generated is therefore: 2πBa²t.(A)

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A student drops a feather off the top a building. The feather averages 1.5m/s while
fluttering to the ground.
Determine all unknowns.

Answers

The acceleration with which an object falls through a fluid decreases as the speed of the object increases under gravity, to the point where the speed becomes constant, which is known as the terminal speed of the object

The unknown parameters are the mass of the feather, the density of the air, the feather's projected area and the coefficient of drag

The reason the above selected parameters are the correct unknowns is as follows;

The known parameter;

The speed of the feather the student drops off the building's top = 1.5 m/s

The required parameter;

The unknown parameters

Method;

Determine the terminal velocity parameters of the feather

The terminal velocity, \(\mathbf{V_t}\), of an item is the maximum steady speed the item reaches as it falls through a fluid. The terminal velocity of the feather is given by the following equation

\(Terminal \ velocity, V_t = \mathbf{\sqrt{\dfrac{2 \cdot m \cdot g}{\rho \cdot A \cdot C_d} }}\)

Where;

\(\mathbf{V_t}\) = Terminal velocity = The constant speed of the feather

m = Mass of the feather

g = Gravitational acceleration

ρ = Air density

A = The feather's projected area

\(C_d\) = Drag coefficient

The average speed of the feather = 1.5 m/s = The feathers typical or most common speed = The terminal velocity of the feather, \(\mathbf{V_t}\);

Plugging in \(\mathbf{V_t}\) = 1.5 m/s gives;

\(V_t = 1.5 \ m/s = \mathbf{\sqrt{\dfrac{2 \cdot m \cdot g}{\rho \cdot A \cdot C_d} }}\)

Therefore, the unknown parameters with regard to the feather falling are the parameters that are to be specified, including;

The mass of the featherThe density of air at the locationThe feather's projected areaThe drag coefficient

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Look at the variables for this lab. Which variable would we have to change in order to change the amount of current flowing through the wire?

Answers

Where are the variables from the lab?

what is the length of a box in which the difference between an electron's first and second allowed energies is 1.2×10−19 j

Answers

The length of the box is approximately 1.66 × 10^−6 meters, or 1.66 micrometers.

The difference between the energy levels of an electron in an atom is given by the formula:

ΔE = E2 - E1 = hν

where ΔE is the difference between energy levels, E1 and E2 are the energies of the initial and final states, h is the Planck's constant, and ν is the frequency of radiation emitted or absorbed during the transition.

We can rearrange this formula to solve for the frequency:

ν = ΔE/h

Given ΔE = 1.2×10−19 J, and the value of the Planck's constant is h = 6.626 × 10^−34 J⋅s, we can calculate the frequency:

ν = ΔE/h = (1.2×10−19 J) / (6.626 × 10^−34 J⋅s) ≈ 1.810 × 10^14 Hz

The frequency is related to the wavelength of radiation by the speed of light, c:

c = λν

where c is the speed of light, λ is the wavelength, and ν is the frequency.

We can rearrange this formula to solve for the wavelength:

λ = c/ν

The speed of light is approximately 3 × 10^8 m/s, so:

λ = (3 × 10^8 m/s) / (1.810 × 10^14 Hz) ≈ 1.66 × 10^−6 m

Therefore, the length of the box is approximately 1.66 × 10^−6 meters, or 1.66 micrometers.

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