name a language that always does short-circuit evaluation of boolean expressions. name one that never does it.

Answer:

the  half answer is pretty easy just look at it really really good hope this helps..

Explanation:

Answer:

Tech A

Explanation:

A faulty vacuum booster can actually affect the operation of an engine. Engine stalls when brakes are applied. And this can happen when the diaphragm that is inside the brake booster fails. The failing thus allows air to bypass the seal. When the brakes are then pressed, the engine will actually feel like it will stall, and the idle will most probably drop. Also, asides a reduction in the break performance quality, a stalling engine is very bad and can result to many negative effects.

This method calculates depreciation based on the number of units produced, rather than the passage of time. Depletion is calculated based on the depletion rate and the number of units extracted during the year.

Marion uses the units-of-production method to calculate depreciation on its mining facilities and equipment. This method takes into account the number of units produced during the year, rather than the passage of time, to determine the depreciation expense. For example, if Marion produces 100,000 units of ore in a year and the mining facilities and equipment have a total useful life of 1 million units, the depreciation expense for that year would be calculated as 10% of the total depreciable cost.

Depletion, on the other hand, is calculated based on the depletion rate and the number of units extracted during the year. The depletion rate is determined by dividing the cost of the mineral reserves by the estimated number of units of the mineral that can be extracted. For example, if Marion has a mineral reserve valued at $1,000,000 and estimates that it can extract 1,000,000 units of the mineral, the depletion rate would be $1 per unit.

To calculate the depletion expense for the year, Marion multiplies the number of units extracted during the year by the depletion rate. The resulting figure provides an estimate of the reduction in the value of the mine and its associated assets over time. By regularly calculating depletion and depreciation, Marion can track the value of its assets and plan for future investments and expenditures.

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Answer:

299.36 feet

Explanation:

\(To \ find \ the \ distance \ of \ the \ ball \ from \ the \ home \ plate. \\ \\ From \ the \ given \ information:\)

\(Height \ h = 4 \ ft\)

\(Initial \ speed \ V_o = 98 \ ft/s ec\)

\(The \ angle \ \theta = 45^0\)

\(Acceleration \ due \ to \ gravity (g)= 32.2 \ ft/s\)

\(U_x = V_o \ cos 45 = \dfrac{98}{\sqrt{2}}\)

\(U_y = V_o \ sin 45 = \dfrac{98}{\sqrt{2}}\)

So;

\(S_y = u_y t - \dfrac{1}{2}gt^2\)

\(-1 =\dfrac{98}{\sqrt{2}}t - \dfrac{1}{2}*32*1.85t^2\)

By solving:

\(t_1 = 4.32 \ sec\)

Thus;

\(horizontal \ distance = U_x t\)

\(= \dfrac{98}{\sqrt{2}}\times 4.32\)

\(\mathbf{=299.36 \ feet}\)

\(\mathbf{Thus \ , the \ distance \ from \ the \ home \ plate \ = \ 299.36 \ feet}\)

A true statement about the seal between the respirator and the wearer's face is: D. facial hair can prevent a respirator from properly sealing to the wearer’s face.

A respirator can be defined as a personal protective equipment that is typically worn over the face to protect the mouth and nose, while protecting the wearer from inhaling smoke, dust, or other toxic chemical substances.

In this context, a true statement about the seal between the respirator and the wearer's face is that facial hair has the ability to prevent a respirator from properly sealing to the wearer’s face.

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Answer:

See explanation

Explanation:

Since no figure was given, I'll explain how to do this problem theoretically. The formula for shear flow is \(q=\frac{VQ}{I}\) where V is the shear force, Q is the moment of area (more on this later), and I is the moment of inertia.

The first step to solve this problem is to find the resultant internal forces of the beam. This can be done in several ways, but the easiest is to solve the beam statically and draw a shear diagram to determine the maximum shear force V.

The second step to solving this problem is to determine the location of the neutral axis of the cross section if it is not given. The formula for the neutral axis is  \(NA = \frac{\sum y*A}{\sum A}\). The y in this equation represents the middle of the small shapes that the web is divided into. An I-beam can be thought of as 3 rectangles, while a T-beam can be thought of as 2. The A in this formula represents the area of each of the rectangles (an I-beam will have 3 of these and a T-beam will have 2).

The third step for this problem is to find the moment of inertia. There are several formulas for moment of inertia depending on the shape of the cross section. I-beam's and T-beams both can be thought of as multiple rectangles, so they have the same base formula of \(I=\frac{1}{12}bh^3\) where b is the base of the rectangles and h is the height. For I-beams, the easiest way to calculate moment of inertia is to think of the entire cross section as a big rectangle that had two smaller rectangles cut out of it. The formula for this moment of inertia becomes \(I=\frac{1}{12} b_{big}h^{3} _{big}-\frac{1}{6}b_{small}h^{3}_{small}\). Note that this form of moment of inertia already takes into account subtracting 2 small rectangles. For T-beams, this approach will not work, so the parallel axis theorem must be used. The moment of inertia for the T-beam becomes \(I=\frac{1}{12}b_{1} h^{3}_{1} +b_{1}h_{1}dy_{1}^{2} +\frac{1}{12}b_{2} h^{3}_{2} +b_{2}h_{2}dy_{2}^{2}\) where the terms with the subscript 1 represent the first rectangle and the terms with the subscript 2 represent the second rectangle. The dy terms represent the distance from the center of that specific rectangle to the neutral axis.

The fourth step for this problem is to find Q. The formula to find Q is \(Q=\sum y'A'\) where y' represents the distance from the neutral axis to the center of the "wanted" point and A' is the area of the rectangle that has the wanted point at its center. (This would be the area above or below the thickness (t) if you were solving for maximum shear \(\tau=\frac{VQ}{It}\)).

The last step for this problem is to substitute the found values into the formula for shear flow \(q=\frac{VQ}{I}\). V came from step 1, Q came from step 4, and I came from step 3.

Answer:

D

Explanation:

Because the Boat D engine looks fast

As there is no internal fluid pressure acting on the pipe, the maximum hoop stress across the segment of the pipe is therefore zero.

The formula below can be used to determine the maximum hoop stress (h) along the pipe section:

σh = (p x d) / (2 x t) (2 x t)

The pipe in this instance has an external diameter (d) of 600 mm and an internal diameter of 440 mm. The following formula can be used to determine the pipe wall's thickness (t):

t = (d – D) / 2 t = (600 – 440) / 2 t = 80 mm

When the values are added to the formula, we obtain:

h = (600 mm x 0 N/mm2) / (2 x 80 mm)

σh = 0 N/mm²

As there is no internal fluid pressure acting on the pipe, the maximum hoop stress across the segment of the pipe is therefore zero.

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Answer: i got you its d

Explanation:had the smae question as you

Answer:

control loop unit

Explanation:

Edmentum/Plato

Using R, the built-in dataset "mtcars" can be loaded, and OLS regression can be performed to investigate the relationship between 1/4 mile time and the vehicle's number of cylinders, gross horsepower, rear axle ratio, weight, and number of carburetors. Residuals can be plotted to assess the presence of autocorrelation and heteroskedasticity, and a variance inflation test can be conducted to check for multicollinearity among the independent variables.

To perform the analysis, the "mtcars" dataset in R can be loaded using the command `data(mtcars)`. The OLS regression can be conducted using the `lm()` function with the dependent variable "1/4 mile time" and the independent variables "number of cylinders," "gross horsepower," "rear axle ratio," "weight," and "number of carburetors." The results of the regression analysis, including coefficients, p-values, and model fit statistics, can be obtained.

Next, the residuals of the regression model can be plotted using the `plot()` function to visually assess the presence of autocorrelation and heteroskedasticity. Additional statistical tests, such as the Durbin-Watson test for autocorrelation and the Breusch-Pagan test for heteroskedasticity, can be performed to quantitatively evaluate these issues.

Furthermore, the variance inflation factor (VIF) can be calculated for each independent variable to identify potential multicollinearity. The `vif()` function from the "car" package in R can be used to compute the VIF values. Higher VIF values indicate a stronger correlation between independent variables.

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Answer:

yes

Explanation:

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Answer:

no

Explanation:

How many trees would it take to reverse climate change?

1.2 trillion trees

Crowther says planting 1.2 trillion trees would give a reduction "way above" that figure. To put that in context, global CO2 emissions are around 37 billion tons per year.Apr 17, 2019

Explanation:

There are 8.35 pounds in a gallon of water. Water weighs 1 gram per cubic centimeter or 1 000 kilogram per cubic meter, i.e. density of water is equal to 1 000 kg/m³; at 25°C (77°F or 298.15K) at standard atmospheric pressure.

Answer:

  Technician B

Explanation:

In simplistic terms, the "hot wire" connects the load device to the source of electrical energy. The ground wire provides the return path for current from the load device to the energy source. In many circuits, the "ground wire" is at, near, or defined as "ground" potential (the actual potential of the Earth).

Technician A seems to be confused. Technician B is more correct.

An environmental hazard is a substance, state or event which has the potential to threaten the surrounding natural environment and/or adversely affect human's health. This term incorporates topics like pollution, natural disasters and human-made hazards. Health studies investigate the human health effects of exposure to environmental hazards ranging from chemical pollutants to natural, technological or terrorist disasters. The environment in which we live can be considered as having three fundamental sets of components, physical, chemical, biological. Associations between an exposure and an adverse health effect do not, on their own, prove that the former is the cause of the latter. Many other non-causal associations could explain the findings. Physical hazards involve environmental hazards that can cause harm with or without contact. Examples are earthquakes, electromagnetic fields, floods, light pollution, noise pollution, vibration, x-rays etc. Radioactivity is associated with an exposure dependent risk of some cancers notably leukaemia. The scientific evidence of adverse health effects from general environmental exposure to these fields is "not proven". If there are adverse effects yet to be proven, the risk is probably likely to be small. Chemical substances cause significant damage to the environment. Tobacco smoke is the single biggest known airborne chemical risk to health, whether measured in terms of death rates or ill-health. To a much lesser degree of risk, these adverse effects apply to non-smokers exposed passively to sidestream tobacco smoke. Health effects of concern are asthma, bronchitis, lung cancer and similar lung diseases, and there is good evidence relating an increased risk of symptoms of these diseases with increasing concentration of Sulphur dioxide, ozone and other pollutants. Biohazards generally fall into two broad categories: those which produce adverse health effects through infection (microorganisms, viruses or toxins) and those which produce adverse effects in non-infective (allergic) ways.

Hope this helps...:)

PRIVACY 1920I/BAA3613 Issue No. 1 Show that 200 mg/L of CaCO3 and 234 mg/L of NaCl are the same. A sample of water was subjected to an ion analysis, and the outcomes are displayed in Table

Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute in a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass per unit volume is typically used. The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume. Although concentration is typically used to describe chemical solutions, it may be computed for any mixture. The term "concentration" in chemistry refers to the elements that make up a combination or solution. Here's how concentration is defined and how it can be calculated using various techniques.

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Answer:

- Work done is 2.39 kJ

- heat transfer is 20.23 kJ/kg

Explanation:    

Given the data in the question;

First we obtain for specific volumes and specific enthalpy from "Table Properties Refrigerant 134a;

Specific Volume v₁ =  0.02547 m³/kg

Specific enthalpy u₁ = 243.78 kJ/kg

Specific Volume V₂ = 0.02846 m³/kg

Specific enthalpy u₂ = 261.62 kJ/kg

p = 8 bar = 800 kPa

Any changes in kinetic and potential energy are negligible.

So we determine the work done by using the equation at constant pressure

]Work done W = p( v₂ - v₁ )

we substitute

W = 800 kPa( 0.02846 m³/kg - 0.02547 m³/kg )

W = 800 kPa( 0.00299 m³/kg )

W = 2.39 kJ

Therefore, Work done is 2.39 kJ

Heat transfer;

using equation at constant pressure

Heat transfer Q = W + ( u₂ - u₁ )

so we substitute

Q = 2.392 kJ + ( 261.62 kJ/kg - 243.78 kJ/kg )

Q = 2.392 kJ +  17.84 kJ/kg )

Q = 20.23 kJ/kg

Therefore, heat transfer is 20.23 kJ/kg

The thevenin equivalent with respect to the terminals a and b is 0 V in series with 120 N.

Terminals are an interface between the user and a computer system. They allow users to interact with the system by providing a command line interface. Terminals are used to access applications and services, enter data, and produce output. They are also used to monitor system performance and manage system resources. Terminals can be either physical or virtual. Physical terminals use hardware, such as keyboards and monitors, to interact with the system.

To find the Thevenin equivalent with respect to the terminals a and b, we can use the Thevenin theorem.

This states that the Thevenin equivalent is equal to the open-circuit voltage (Vt) across the terminals a and b, in series with the equivalent resistance (Rt) between the terminals a and b.

Vt = 0 V

Rt = 120 N

Therefore, the Thevenin equivalent with respect to the terminals a and b is 0 V in series with 120 N.

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Answer:

No matter what u post on a football page, some fatherless dude will either say "pessi" or "penaldo"

Answer:

  4 A

Explanation:

Current is found using Ohm's law.

  I = V/R

  I = (240 volts)/(60 ohms) = 4 A

The heating element current is 4 amperes.

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

As the given state of stress at a point is plane stress with in-plane principal stresses 2.0 MPa and 8.0 MPa, the absolute maximum shear stress at this point can be found by .

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After the loops complete, the contents of the array a will be {1, 1, 1, 1, 1, 1, 1, 1, 1, 1}.

This is because the loop starts at index 1 and goes until index 9 (i < 10), and for each iteration, the value at index i is set to the value at index i - 1. Since the value at index 0 is 1, all the values in the array will be set to 1. This means that the resulting array will contain all 1s, from index 0 to index 9.

As a result, the array a will contain 10 elements, each with the value 1. This is a common pattern used when dealing with arrays in programming, as it allows for manipulating elements in the array without having to manually set the values.

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After the loops complete, the contents of the array a will be {1, 1, 1, 1, 1, 1, 1, 1, 1, 1}.

This is because the loop starts at index 1 and goes until index 9 (i < 10), and for each iteration, the value at index i is set to the value at index i - 1. Since the value at index 0 is 1, all the values in the array will be set to 1. This means that the resulting array will contain all 1s, from index 0 to index 9.

As a result, the array a will contain 10 elements, each with the value 1. This is a common pattern used when dealing with arrays in programming, as it allows for manipulating elements in the array without having to manually set the values.

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Answer:

The first five terms of the given geometric sequence are

8,40,200,1000,5000

Explanation:

:)

Answer:

A uniform T-section beam is 100 mm wide and 150 mm deep with a flange thickness of 25 mm and a web thickness of 12 mm. If the limiting bending stresses for the material of the beam are 80 MN/m2 in compression and 160 MN/m2 in tension, find the maximum u.d.l. that the beam can carry over a simply supported span of 5 m.

Explanation:

hope this helps if not let me know

Answer:

Some good ways and popular ways are:

1. Investing in data literacy.

2. Think about cybersecurity.

3. Choosing good and the right tools.

4. Establish metrics that matter.

Explanation:

These all are helpful.

(Hope this helped! Have a great day.)

The first performance tool a technician would use to check if a computer has sufficient hardware resources for a specific application is a resource monitor.

A resource monitor is the ideal tool for a technician to assess hardware resource utilization on a computer. It provides real-time information about CPU usage, memory consumption, disk activity, and network traffic. By analyzing these metrics while the particular application is executing, the technician can determine if the computer has enough CPU power, memory, and disk space to handle the application's requirements.

If the resource monitor shows high CPU usage, excessive memory consumption, or heavy disk activity, it may indicate that the computer is struggling to meet the demands of the application. The technician can then consider upgrading the hardware or optimizing system settings to ensure smooth performance.

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