An iron has a power of 1000 W. How much energy will it electrically transfer each second?

An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I

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Answer:

D

Explanation:

because the correct answer is D

Answer: 3645 Joules/ 1 hour

Explanation: I did it just now.

Enzymes. ... This is because heat energy causes more collisions, with more energy, between the enzyme molecules and other molecules. However, if the temperature gets too high, the enzyme is denatured and stops working. A common error in exams is to write that enzymes are killed at high temperatures.

The total charge in the circuit is 240 microcoulombs.

To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.

In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.

To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.

Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.

Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.

Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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Answer:

A

Explanation:

Answer:

Which two characteristics are used to classify stars on the Hertzsprung-Russell diagram?

Explanation:

The characteristics that are used in order to classify the stars on the Hertzsprung-Russell diagram are size, density, temperature, and absolute brightness. They do not use the composition as they use the spectrographs for that purpose.

Hope that helped.

Answer:

Temp and absolute brightness

Explanation:

Took the test

Answer:

Hola

Explanation:

espero que te ayude gracias por los puntod

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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Answer: A

Explanation:

Isotopes of different elements differ by the number of neutrons inside the nucleus.

The isotope of uranium-238 is different from the isotope uranium-235 by number of neutrons in the nucleus.

Isotopes are two or more types of atoms that have the same atomic number and position in the periodic table, and that differ in nucleon numbers due to different numbers of neutrons in their nuclei.

Uranium-238 is the most common isotope of uranium found in nature, with a relative abundance of 99%. It can be used for radiation shielding or as projectiles in armor-piercing weapons.

Uranium-235 is the only naturally occurring fissile isotope, which makes it widely used in nuclear power plants and nuclear weapons.

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Answer:

Hertzsprung-Russell Diagram

The Hertzsprung-Russell diagram (HR diagram) is one of the most important tools in the study of stellar evolution. Developed independently in the early 1900s by Ejnar Hertzsprung and Henry Norris Russell, it plots the temperature of stars against their luminosity (the theoretical HR diagram), or the colour of stars (or spectral type) against their absolute magnitude (the observational HR diagram, also known as a colour-magnitude diagram).

Depending on its initial mass, every star goes through specific evolutionary stages dictated by its internal structure and how it produces energy. Each of these stages corresponds to a change in the temperature and luminosity of the star, which can be seen to move to different regions on the HR diagram as it evolves. This reveals the true power of the HR diagram – astronomers can know a star’s internal structure and evolutionary stage simply by determining its position in the diagram.

Explanation:

Hence the answer is C : Super Giants

Use the work-energy theorem. The total work done on the plane is equal to the change in its kinetic energy:

W = ∆K

W =  1/2 (1.5 kg) (6 m/s)² - 1/2 (1.6 kg) (8 m/s)²

W = -21 J

(Note that the work must be negative since the "braking" force opposes the direction in which the plane is moving.)

According to the graph below, the statements about these cars must be true are :

options B and C are correct

Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

There are some similarities  between velocity and speed and they include:  

Velocity (v) is known as a vector quantity that measures displacement (or change in position, Δs) over the change in time.

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The graph is attached below:

Answer:

can y

Explanation:

jj

The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.

The equation for the settling velocity of a particle:

V_s = (2/9) * (ρ_p - ρ_w) * g * r^2 / η

where V_s is the settling velocity, ρ_p is the particle density, ρ_w is the water density, g is the acceleration due to gravity, r is the particle radius, and η is the water viscosity.

1. We can rearrange the equation to solve for the particle radius:

r = [9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)

We want to find the particle diameter, which is twice the radius, so we can substitute 2r for d in the following equation:

d = 2r = 2[9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)

To remove the smallest particles, we want to use the smallest settling velocity possible, which corresponds to a particle just barely settling to the bottom of the clarifier. Therefore, we can set V_s equal to the minimum settling velocity required for particles to be removed:

V_s = Q / (A * X)

where Q is the flow rate (25 MGD), A is the surface area of one clarifier (πr^2), and X is the overflow rate, which is the flow rate per unit area of the clarifier. A typical overflow rate for a sedimentation basin is 600-1200 gallons per day per square foot (gpd/ft^2), or 2.5-5 m^3/day/m^2. We will use the lower end of this range, 2.5 m^3/day/m^2.

Substituting in the values for Q, A, and X, we get:

V_s = (25 MGD) / (π(8 m)^2 * 2.5 m^3/day/m^2) = 0.00159 m/s

Now we can substitute the values for η, ρ_p, ρ_w, g, and V_s into the equation for the particle diameter:

d = 2[9(1 g/(m*s))(0.00159 m/s) / (2(1200 kg/m^3 - 998.2 kg/m^3)(9.81 m/s^2))]^(1/2) = 0.0257 mm

So, the smallest particles that can be removed by these clarifiers have a diameter of approximately 0.0257 mm.

2. To find the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1, we can use the same overflow rate and flow rate as before, and we can assume a depth of 3 m. The surface area of one clarifier must still be the same as before, so we can use the equation for the surface area of a rectangle:

A = L * W

where L is the length and W is the width.

Substituting in the values for Q, X, and A, we get:

W = (25 MGD) / (5 * 24 hr/day * 60 min/hr * 60 s/min * 2.5 m^3/day/m^2 * 5 * L)

Simplifying, we get:

W = 0.023 L

So, the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.

Therefore, The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and a rectangular clarifier's minimum width is 0.023 times the length when the length-to-width ratio is 5:1.

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Answer: 13.9 m

Explanation:

Answer:

13.9m

Explanation:

Answer on Edge

Answer:

e. none of the above

Explanation:

The frequency of an oscillating pendulum is the number of oscillation per unit time.

Mathematically, the frequency of an oscillating pendulum is given by the formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Hence, none of the changes mentioned will increase the frequency of an oscillating pendulum.

The ways to solve this problem is through knowledge dissemination, citizens who were outraged by the article about the negative statements and malicious stories about Filipinos, could submit positive articles about the culture of the Filipino people.

Another way could be through open dialogue, with Filipino internet users, publicly apologizing seeking to become more involved with the Filipino community.

Therefore, the best way to solve the problem is through ethically-based freedom of expression, avoiding stereotypes of a culture you don't belong to, and looking for a way to disseminate respectful and empathetic information about a people.

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A 0.842g sample of Hydrogen-3 decays to 0.0526g. Approximately 4.206 half-lives have occurred.

To determine the number of half-lives that have occurred, we can use the decay equation and the concept of exponential decay. The decay equation for radioactive decay is given by:

N(t) = N₀ * (1/2)^(t/T),\((1/2)^(^t^/^T^),\)

where N(t) is the remaining amount of the substance at time t, N₀ is the initial amount, t is the time elapsed, and T is the half-life of the substance.

In this case, we have an initial mass of 0.842g (N₀) and a remaining mass of 0.0526g (N(t)). We can set up the equation as follows:

0.0526g = 0.842g \(* (1/2)^(^t^/^1^2^.^3^2)\),

where t represents the number of half-lives that have occurred.

To solve for t, we can take the logarithm of both sides of the equation:

log(0.0526g/0.842g) = log\([(1/2)^(^t^/^1^2^.^3^2^)\)].

Using the logarithmic property log(\(a^b\)) = b*log(a), we can rewrite the equation as:

log(0.0526g/0.842g) = (t/12.32) * log(1/2).

Simplifying further:

log(0.0526g/0.842g) = (t/12.32) * (-log2),

where log2 is the logarithm base 2.

Now, we can solve for t:

t = (12.32 * log(0.0526g/0.842g)) / (-log2).

Using the given values and performing the calculation, we find:

t ≈ 4.206.

Therefore, approximately 4.206 half-lives have occurred.

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The essence of the commercial is to draw the attention of the public to the products of a firm.

Commercials are the primary ways by which companies promote their products. The essence of the commercial is to draw the attention of the public hence the commercial is  designed with music graphics and other means that aid effective communication.

The commercial that got my attention is that of the United Bank for Africa owing to the beautiful blend of orchestra music used in the advertisement which appeals immediately to the mind. The advert targets the business class in the society and aims at granting soft credit to small and medium scale entrepreneurs. It conveys its message to the clientele via music. The advert can be regarded as a trend.

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Answer:

Explanation:

the distance have the following relation:

d = (1/2)gt2

D=32.0 m

t =√ (2D/g) = √(2*32.0m/9.8m/s2) = 2.56s

it take 2.56s from the glasses to hit the ground

when the glasses hit the ground, the pen only travel Δt =2.56s - 2.00s = 0.56s

x = (1/2)g(Δt)2 = 0.5*9.8m/s2*(0.56s)2 = 1.54 m

the pen only travel 1.54m

so the pen is above the ground 32.0m - 1.54m = 30.46m

The pen is 30.46m above the ground. when the glasses hit the ground. It is represented by x.

Height is a numerical representation of the distance between two objects or locations on the vertical axis.

The height can refer to a physical length or an estimate based on other factors in physics or common use. |

The given data in the problem is;

h is the height from the top of a stadium = 32.0 m

t is the time period when the pen is dropped later =  2.00 s

x is the height above the ground

a is the air resistance. a = -g = -9.81 m/s²

From the second equation of motion;

\(\rm H =ut+\frac{1}{2} gt^2 \\\\ \rm H =\frac{1}{2} gt^2 \\\\ \rm t = \sqrt{\frac{2H}{g} } \\\\ \rm t = \sqrt{\frac{2 \times32.0 }{9.81} } \\\\ \rm t =2.56\ sec\)

When the glasses fall to the ground, the pen only travels a short distance;

\(\rm \triangle t = 2.56 -2.00 \\\\ \rm \triangle t = 0.56 \ sec\)

So the pen travel the distance;

\(\rm h= \frac{1}{2} g \triangle t^2 \\\\ \rm h= \frac{1}{2} \times 9.81 (0.56)^2 \\\\ h=1.54 \ m\)

The pen above the ground is found as;

\(\rm x = H-h \\\\ \rm x = 32.0-1.54 \\\\ \rm x =30.46 \ m\)

Hence the pen is 30.46m above the ground. when the glasses hit the ground.

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The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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Answer:

Kinetic Energy!

Explanation:

Kinetic energy is energy in motion.

Answer:

Explanation:

The answer is kinetic energy.

Answer:

Below

Explanation:

weight = mass * g  <==g is less on the moon, so your weight is less on the                      moon

         to calculate weight, you have to use the g of the planet you are on

The MASS does not change....it will be 6kg on the moon or earth

Weight of 30 kg on earth =    30 * g = 30 * 9.81 = 294 N

Answer:

0.1 m/s (or 100 cm/s)

Explanation:

At the first point on the graph’s faded grid, the object has traveled 1 meter in 10 seconds. At the next point, the object traveled 2 meters in 20 seconds. This is a 1 to 10 ratio, or 1/10, which is 0.1 in decimal format.

The area under the velocity time graph is 125 m and the meaning of the area is displacement.

The area under a velocity time graph represents the displacement of the object.

total area of the graph = A1 + A2

total area of the graph = ¹/₂ (base₁)(height₁) + ¹/₂ (base₂)(height₂)

total area of the graph = ¹/₂(4)(40) + ¹/₂(3)(30)

total area of the graph = 125 m

Thus, the area under the velocity time graph is 125 m and the meaning of the area is displacement.

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Answer:

Explanation:

A scientist adds different amounts of salt to 5 bottles of water. She then measures how long it takes for the water to boil. What is the responding variable in this experiment? A. The time it takes for the water to boil B. The amount of salt added to the water C. The kind of bottles used D. The brand of salt used

Answer:

only in the column for metalloids

Explanation:

Did it on edge!

Franklin should place this property only in the column for metalloids, therefore the correct answer is option A.

The elements of the periodic tables that behave as metal, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.

Generally, metalloids have an intermediate position in the periodic table which is in between metals and nonmetals.

As given in the problem The table shows columns that Franklin uses to organize his notes on the properties of elements. His notes state that some elements are widely used in semiconductors, A 3-column table with 2 rows. The first row has entries as metals, metalloids, and nonmetals. The second row has entries nothing, nothing, nothing.

As metalloids are widely used as semiconductors across several electronic and electrical applications.

Thus, Franklin should only list this characteristic under metalloids, therefore the correct answer is option A.

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