An ice cream truck is going 25m/s to the East. It accelerates to 45m/s in the same direction over 5s. What is its acceleration? Show your work and include the correct units with your answer.

The scale will read 147N

The mass of the object, m = 15 kg

Since I am on the earth, the acceleration due to gravity on the earth is:

g = 9.8 m/s²

The scale will read the weight of the object, and is calculated below

The weight, W = mg

W = 15(9.8)

W = 147 N

Therefore, the scale will read 147N

Answer:

6 hours

Explanation:

240/40 =6

The speed of the truck is 40 miles per hour and distance travelled by the truck is 240 miles. Then, the time take for this travel is the distance divided by the speed that is 6 hours.

Speed is a physical quantity that describes the distance is covered per unit time. Speed is a scalar quantity thus having magnitude only. The rate of speed is called velocity. Velocity is a vector quantity.

The longer distance covered by an object within small time, the object is said to have greater speed. Thus speed is the ratio of change in distance to the change in time.

Given  that, speed of the truck = 40 mph

distance covered  = 240 miles

Time = distance/speed

t = 240 miles/40 mph = 6 hours.

Therefore, the time taken to travel by the truck is 6 hours.

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Answer: velocity is 20 m/s

Explanation: speed v = v0 + at =0 m/s + 4 m/s²·5s= 20 m/s

Answer:

0.5

Explanation:

Two resistors with resistances of 2 ohms and 4 ohms, respectively, are connected in series with a battery. The current through the 2 ohms resistor is 2A. How would one find the current through the 4 ohms resistor?

I = V/R we get I = 10/ 200 or .05 amps.

Answer:

K.Eₓ = 4 K.E

K.Eₓ = 9 K.E

Explanation:

Th formula for the kinetic energy of a body is given as follows:

\(K.E = \frac{1}{2}mv^2\\\)   ---------------equation (1)

where,

K.E = Kinetic Energy of Automobile

m = mass of automobile

v = speed of automobile

For twice speed:

vₓ = 2v

then,

\(K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(2v)^2\\K.E_{x} = 4\frac{1}{2}mv^2\\\)

using equation (1):

K.Eₓ = 4 K.E

For thrice speed:

vₓ = 3v

then,

\(K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(3v)^2\\K.E_{x} = 9\frac{1}{2}mv^2\\\)

using equation (1):

K.Eₓ = 9 K.E

A. The kinetic energy of automobile when it moves at twice the speed is 8000 J

B. The kinetic energy of automobile when it moves at three times the speed is 18000 J

Let the mass of the automobile be constant.

Let the initial velocity be v

A. Determination of the kinetic energy of the automobile when it moves at twice the speed.

KE₁ /v₁² = KE₂ / v₂²

2000 / v² = KE₂ / (2v)²

2000 / v² = KE₂ / 4v²

Cancel out v²

2000  = KE₂ / 4

Cross multiply

KE₂ = 2000 × 4

KE₂ = 8000 J

B. Determination of the kinetic energy of the automobile when it moves at three times the speed.

KE₁ /v₁² = KE₂ / v₂²

2000 / v² = KE₂ / (3v)²

2000 / v² = KE₂ / 9v²

Cancel out v²

2000  = KE₂ / 9

Cross multiply

KE₂ = 2000 × 9

KE₂ = 18000 J

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Answer:

The magnitude of third force is 74.4 N and direction of third force  is 72.8 degrees South.

Explanation:

Let F1, F2 and F3 are three forces exerted on an object.

\(\theta_1=90^{\circ}\)

\(\theta_2=60^{\circ}\)

\(|F_1|=33 N\)

\(|F_2|=44 N\)

We have to find the direction and magnitude of third force i.e F3.

\(F_{1x}=33cos(90^{\circ})=0 N\)

\(F_{1y}=33sin(90^{\circ})=33 N\)

\(F_{2x}=44cos(60^{\circ})=22 N\)

\(F_{2y}=44 sin(60^{\circ})=22\sqrt{3}=38.11 N\)

Now,

x-component of  resultant

\(R_x=F_{1x}+F_{2x}=0+22=22 N\)

y-component of resultant

\(R_y=F_{1y}+F_{2y}=33+38.11=71.11 N\)

\(|R|=\sqrt{R^2_x+R^2_y}\)

\(|R|=\sqrt{(22)^2+(71.11)^2}=74.4 N\)

\(\theta=tan^{-1}(\frac{R_y}{R_x})\)

\(\theta=tan^{-1}(\frac{71.11}{22})=72.8^{\circ}\) South

Hence, the magnitude of third force is 74.4 N and direction of third force  is 72.8 degrees South.

The magnitude and direction of the third force is;

F3 = 74.44 N

θ3 = 72.81° in the south direction

We are given;

F1 = 33 N

F2 = 44 N

θ1 = 90°

θ2 = 60°

Let the third force be F3 which will serve as the resultant

Let's first find the x and y component of the forces.

F1x = F1 cos θ1

F1x = 33 × cos 90

F1x = 0 N

F1y = F1 sin θ1

F1y = 33 × sin 90

F1y = 33 N

F2x = F2 cos θ2

F2x = 44 × cos 60

F2x = 22 N

F2y = F2 sin θ2

F2y = 44 × sin 60

F2y = 38.11 N

Thus, the resultant of the x component is;

F3x = F1x + F2x

F3x = 0 + 22

F3x = 22 N

The resultant of the y component is;

F3y = F1y + F2y

F3y = 33 + 38.11

F3y = 71.11 N

Thus, magnitude of resultant of the F3 force is;

F3 = √((F3x)² + (F3y)²)

F3 = √(22² + 71.11²)

F3 = 74.44 N

The direction of the resultant of F3 is;

θ3 = tan^(-1) F3y/F3x

θ3 = tan^(-1) 71.11/22

θ3 = 72.81° in the south direction

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6. Secondary rainbows occur when two internal reflections of light occur in raindrops. A secondary rainbow is formed when the light is refracted twice by the raindrop, with the colors being reversed compared to the primary bow. In a secondary rainbow, the colors are reversed compared to the primary rainbow.

Violet is always on the bottom of a primary bow, whereas red is always on the top.7. As light passes through ice crystals, blue light is bent the most and is, therefore observed on the inside. Light passes through hexagonal ice crystals in the atmosphere and is refracted or bent, creating a halo or an arc. When light is refracted, the red end of the spectrum is bent the least, while the blue-violet end of the spectrum is bent the most.

8. The main difference between a hurricane and a typhoon is in the Northern Hemisphere, typhoons have surface wind spinning clockwise, whereas hurricanes have surface wind spinning counterclockwise. While hurricanes are a common occurrence in the Atlantic Ocean and parts of the Pacific Ocean, typhoons form over the northwestern Pacific Ocean. Hurricanes can cause significant damage, with the most powerful storms resulting in a range of destruction from coastal flooding to complete devastation.

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The acceleration of an object traveling at terminal velocity is 0 m/s/s since it is not accelerating.

Terminal velocity is the maximum speed achieved by an object as it falls through a fluid such as air or water. The object's weight, drag coefficient, and surface area all affect its terminal velocity. Terminal velocity increases as an object's weight increases and its drag coefficient and surface area decrease. Terminal velocity is greatest when an object reaches its equilibrium between the force of gravity and the fluid's drag force. For example, a human skydiver has a terminal velocity of about 120 mph.

Terminal velocity is the maximum velocity an object can reach and remain at a constant speed as it is subjected to a constant force such as gravity. If the object is subject to any additional force, it will accelerate.

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Answer: Alicia and the president do not have enough of a particular resource. Alicia doesn’t have enough time, and the president doesn’t have enough money.

Explanation: This is Plato's sample answer.

The friction between the b;ock and surface is given by mass and accelerartion.

Force = mass * acceleration

Answer:

I was going to give you the paper where I saw it but since you are not giving enough points I can not give you so I am only going to give you some of these that are here sorry

Explanation:

1.

\(9^{2} + 12^2 = x^2\\81 + 144= x^2\\\sqrt{225} = \sqrt{x} \\ 15=x\\\\ 2.\\x^2+12^2+=13^2\\x^2+144 =169\\x^2 = 25\\\sqrt{x^2 =\sqrt{25\\\\\)

x=5

\(3.\\12^2+32^2 = x^2\\34.176= x\)

7.

5,12,13

9.

\(\frac{x}{4} ,\frac{12}{4} ,\frac{20}{4}\\\\\frac{x}{4},3,5 \\\\x=16\\\\12. \\x^2 + 48^2=50^2\\\\x^2=196\\x=14\)

Answer: 28n x 2m= 56n-m= 56 joules

Explanation:

To calculate the vertical momentum of a two-puck system after a collision, we need to know the masses of the pucks, their velocities before and after the collision, and the direction of the momentum.

Assuming that the collision is inelastic (meaning that the pucks stick together after the collision), we can use the conservation of momentum principle, which states that the total momentum of a closed system (such as the two-puck system) remains constant if there are no external forces acting on the system. Therefore, the sum of the vertical momenta of the two pucks before the collision must equal the sum of their vertical momenta after the collision.

To calculate the vertical momentum before the collision, we can use the formula:

p = m * v

where p = momentum,

m = mass,

v = velocity.

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The angle of refraction when a ray of light passes from air into water at an angle of 50.0° to the surface of the water is approximately 34.4°, and the speed of light in water is about 2.26 x 10⁸ m/s.

When light passes from one medium to another, it undergoes refraction, which involves a change in direction and speed. The angle of refraction is determined by Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the speeds of light in the two media.

In this case, the angle of incidence is 50.0° and the medium changes from air to water. By applying Snell's law, we can calculate the angle of refraction to be approximately 34.4°.

The speed of light in a medium is determined by the refractive index, which is the ratio of the speed of light in vacuum to the speed of light in the medium. The refractive index of water is approximately 1.33.

Therefore, the speed of light in water can be found by dividing the speed of light in vacuum (approximately 3 x 10⁸ m/s) by the refractive index, resulting in approximately 2.26 x 10⁸ m/s.

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The equation of GPE is mgH, where m is mass, g is gravitational acceleration, and H is the height.

If we're solving for the change in GPE, then:

∆\(U_{g}\) = mg∆H

Input our given values for m and g:

∆\(U_{g}\) = 0.25 * 9.80 * ∆H

The book falls from 2 meters high to 0.5 meters high, so:

∆\(U_{g}\) = 0.25 * 9.80 * (2.0 - 0.5)

∆\(U_{g}\) = 0.25 * 9.80 * 1.5

∆\(U_{g}\) = 3.675 (J)

Adjust for significant figures:

∆\(U_{g}\) = 3.7 (J)

The change in gravitational potential energy was 3.7 (J)

If you have any questions on anything I did to get to the answer, just ask!

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A projectile is launched vertically upward from the surface of Earth with an initial velocity. We need to determine its velocity after a given time interval.

When a projectile is shot upward, it experiences a constant acceleration due to gravity acting in the opposite direction of its motion. The magnitude of this acceleration is approximately 9.8 m/s².

To calculate the velocity of the projectile after a certain time, we can use the kinematic equation:

final velocity = initial velocity + (acceleration * time)

Given the initial velocity and the time, we can substitute the values into the equation:

final velocity = (initial velocity) + (9.8 m/s² * time)

By plugging in the values, we can find the final velocity after the given time interval.

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False.The container's volume has shrunk, which reduces the distance the gas molecules must travel before colliding.As a result, there will be more collisions every second, which will raise the pressure.

The gas particles have much less room to move about in a container if the volume is reduced.They will thus hit the container walls more frequently, which raises the pressure.

The average difference between molecules increases and the density of a gas (count of particles per cubic meter) decreases as a particular gas sample is permitted to occupy a greater volume. The speed of a molecules remains constant.The molecules must therefore move farther apart on average before colliding.

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Answer:

The net force on the object is 35 N directed up.

Explanation:

Net Force

The force is a vector because it has magnitude and direction. The net force is the sum of all the individual forces acting on an object.

Let's assume the forces directed upward are positive and the forces directed down are negative.

Force A: +50 N

Force B: -30 N

Force C: +25 N

Force D: -10 N

Net Force= 50 - 30 + 25 - 10 = 35 N

The net force on the object is 35 N directed up.

Explanation:

The potential energy of an object has the following formula

         Potential energy = mgh

      where m = mass of the object

                   g = acceleration due to gravity

                   h = height of the object

This means that the potential energy of an object depends upon its mass, acceleration due to gravity, and height.

In the given situation we have a bucket full of water. If the mass and acceleration due to gravity are not changed, the only way the potential energy can be decreased is by reducing the height of the bucket full of water.

This can be done by: -

         (i) Lifting the bucket full of water in such a way that you

             decrease its height as compared to the bench.

        (ii) Put the bucket full of water on a stool whose height is

            lower than the bench.

Answer:

1.By decreasing it's contents- this decreases the weight of the bucket thus decreasing the potential energy of the bucket.

2.By decreasing the height of the bench we have decreased the amount of potential energy stored in the bucket

The mass of cell wall is m = 6.082 x 10⁻¹⁶ kg = 6.082 x 10⁻¹⁰ mg , assuming the cell to be spherical and the wall to be a very thin spherical shell

Semi-permeable membrane - A membrane through which only smaller molecules like water can pass but not the bigger molecules like solutes is known as semi-permeable membranes (SPM)

--First, we find the the surface area of the cell wall. Since, the cell is spherical in shape. Therefore, surface area of cell wall will be:

                                             A = 4πr²

where,

A = Surface Area = ?

r = Radius of Cell = Diameter/2

                         = 2.2 μm/2

                         = 1.1 μm

                       = 1.1 x 10⁻⁶ m

Therefore,

                           A = 4π(1.1 x 10⁻⁶ m)²

                          A = 15.2 x 10⁻¹² m²

Now, we find the volume of the cell wall. For that purpose, we use formula:

V = Volume of the Cell Wall = ?

t = Thickness of Wall = 40 nm

= 4 x 10⁻⁸ m

Therefore,

                              V = (15.2 x 10⁻¹² m²)(4 x 10⁻⁸ m)

                                   V = 60.82 x 10⁻²⁰ m³

Now, to find mass of cell wall, we use formula:

                                 ρ = m/V

                                       m = ρV

where,

ρ = density of water = 1000 kg/m³

m = Mass of Wall = ?

Therefore,

                        m = (1000 kg/m³)(60.82 x 10⁻²⁰ m³)

                          m = 6.082 x 10⁻¹⁶ kg

                            = 6.082 x 10⁻¹⁰ mg

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Answer:

In general there are three sub-segments of "alternative" energy investment: solar energy, wind energy and hybrid electric vehicles

Answer:

Explanation:

The relevant conversion factors are ...

  1 m = 100 cm

  1 cm = 10 mm

  1 kg = 1000 g

  1 L = 1000 mL

These are based on the meanings of the SI prefixes:

  centi- = 1/100

  milli- = 1/1000

  kilo- = 1000

__

2000 g = 2 kg --- given

14000m = 14 km --- given

1600 mm = 160 cm

0.8 m = 80 cm

109 g = 0.109 kg

0.0056 kg = 5.6 g

0.075 L = 75 mL

16.5mm = 1.65 cm

It takes approximately 0.189 seconds for the bullet to stop moving within the tree trunk, assuming the frictional force is constant.

Frictiοn is the fοrce that resists mοtiοn when the surface οf οne οbject cοmes in cοntact with the surface οf anοther.

Given:

Mass of the bullet (m) = 7.80 g = 0.0078 kg

Initial velocity of the bullet (u) = 590 m/s

Final velocity of the bullet (v) = 0 m/s (since it stops moving)

Distance penetrated by the bullet (s) = 5.60 cm = 0.0560 m

To calculate the time it takes for the bullet to stop moving, we can use the equation of motion:

\(\rm v^2 = u^2 + 2as\)

Plugging in the values:

0² = (590 m/s)² + 2 * a * 0.0560 m

Simplifying:

0 = 348100 m²/s²+ 0.112 m * a

Rearranging the equation to solve for deceleration (a):

a = -348100 m²/s² / 0.112 m

a ≈ -3.107 × 10⁶ m²/s²

The negative sign indicates deceleration.

To find the time (t), we can use the equation:

a = (v - u) / t

Plugging in the values:

-3.107 × 10⁶ m²/s² = (0 m/s - 590 m/s) / t

Simplifying:

-3.107 × 10⁶ m²/s² = -590 m/s / t

Cross-multiplying:

-3.107 × 110⁶ m²/s² * t = -590 m/s

Dividing both sides by -3.107 × 10⁶ m²/s²:

t = -590 m/s / (-3.107 × 10⁶ m²/s²)

t ≈ 0.189 s

Therefore, it takes approximately 0.189 seconds for the bullet to stop moving within the tree trunk, assuming the frictional force is constant.

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Answer:

1) 150 [m/min]; 2) 250 [m/min].

Explanation:

1) time=10min; distance=1,5km, then the speed=distance/time=1.5/10[km/min]= 0.15 [km/min] or 150 [m/min] or 2.5 [m/s];

2) time=10 min; distance=2.5 km, the the speed=distance/time= 2.5/10= 0.25[km/min] or 250 [m/min] or ≈4.17 [m/s].

Answer:

r = 0.833 m/s

Explanation:

Givens

d = 1000 m

t = 20 minutes * [60 seconds / 1 minute] = 1200 seconds

Equation

Solution

r = d / t

r = 1000 m / 1200 seconds

r = 0.833 m/s

Answer:

If you know the total current and the voltage across the whole circuit, you can find the total resistance using Ohm's Law: R = V / I. For example, a parallel circuit has a voltage of 9 volts and total current of 3 amps. The total resistance RT = 9 volts / 3 amps = 3 Ω.

Explanation:

Answer:

4 * 10^-8 mg = .4 * 10^-7 mg        divide and multiply by 10

5.0 x 10^-7mg + .4 x 10^-7 mg = 5.4 x 10^-7 mg

Also 5.4 x 10^-7 mg = 5.4E-7 mg

(A) the original charge of the system is 21,250 μC. (B)  the final potential difference across the capacitor is 850 V. (C) The final energy of the system is 11,740,750 μJ.

To compute the original charge of the system, we can use the formula;

Q = C × V

where Q will be the charge, C will be the capacitance, and V will be the potential difference.

For the 25.0 μF capacitor charged to 850 V;

Q₁ = C₁ × V₁

= (25.0 μF) × (850 V)

Q1 = 21,250 μC

Therefore, the original charge of the system is 21,250 μC.

When the charged capacitor is connected in parallel to the uncharged capacitor, the potential difference across both capacitors becomes equal. This means the final potential difference across the capacitors will be the same as the initial potential difference of the charged capacitor, which is 850 V.

Therefore, the final potential difference across the capacitor is 850 V.

The energy stored in a capacitor can be calculated using the formula:

E = 0.5 × C × V₂

where E will be the energy, C will be the capacitance, and V will be the potential difference.

For the 25.0 μF capacitor with a potential difference of 850 V:

E₁ = 0.5 × C1 × V1²

= 0.5 × (25.0 μF) × (850 V)²

E₁ = 9,018,750 μJ

For the 8.00 μF capacitor with a potential difference of 850 V:

E₂ = 0.5 × C₂ × V2²

= 0.5 × (8.00 μF) × (850 V)²

E2 = 2,722,000 μJ

The final energy of the system is the sum of the energies of both capacitors;

E_final = E₁ + E₂

= 9,018,750 μJ + 2,722,000 μJ

E_final = 11,740,750 μJ

Therefore, the final energy of the system is 11,740,750 μJ.

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--The given question is incomplete, the complete question is

"A 25.0 μf capacitor is charged to a potential difference of 850 v . the terminals of the charged capacitor are then connected to those of an uncharged 8.00 μf capacitor. A) compute the original charge of the system B)compute the final potential difference across the capacitor C)compute the final energy of the system."--