The tension in the cable is equal to the net force acting on the elevator, so the tension in the cable is 2.6E+4 N, which is the correct answer is D. 2.6E+4 N.
To find the tension in the cable, we need to use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. In this case, the elevator is being accelerated upward at a rate of 3.00 m/s^2, so the net force acting on it is:
Fnet = m * a
where m is the mass of the elevator and a is the acceleration. We can find the mass of the elevator by dividing its weight by the acceleration due to gravity:
m = W/g = 20 000 N / 9.80 m/s^2 = 2040.82 kg
Now we can find the net force:
Fnet = m * a = 2040.82 kg * 3.00 m/s^2 = 6122.46 N
The tension in the cable is equal to the net force acting on the elevator, so the tension in the cable is 2.6E+4 N, which is answer choice D.
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Which motor and body should Devon use to build the car with the greatest acceleration? motor 1, with body 1 motor 1, with body 2 motor 2, with body 1 motor 2, with body 2
Answer:
hello your question is incomplete below is the complete question
Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as shown in the table.
Which motor and body should Devon use to build the car with the greatest acceleration?
motor 1, with body 1
motor 1, with body 2
motor 2, with body 1
motor 2, with body 2
answer: Motor 2 body 1
Explanation:
F = ma
hence a ( acceleration ) = F / m
force of motor 2 = 15 N since the mass of the motor is the same and that of the bodies aren't given
The motor and body that would produce the greatest acceleration would be : Motor 2 Body 1 if the mass of Body 1 is less than the mass of Body 2
Answer:
c
Explanation:
c) The height of a mountain is 1360m. The barometer reading at the base of the mountain is 74cmHg. Given that the densities of mercury and air are 13,600Kgm and 1.25Kgm respectively, determine (3mks) the barometer reading at the top of the mountain.
The barometer reading at the top of the mountain is 98,737.6 Pa.
What is the barometer reading at the top of the mountain?The barometer reading at the top of the mountain is calculated as follows;
Atmospheric pressure at base = ρgh
= 1.25 kg/m³ x 9.81 m/s² x 0.74 m
= 9.1 Pa
Pressure due to mercury column at base;
= 13,600 kg/m³ x 9.81 m/s² x 0.74 m
= 98,727.8 Pa
Total pressure at base = Atmospheric pressure + Pressure due to mercury column
= 9.1 Pa + 98,727.8 Pa
= 98,736.8 Pa
The total pressure at the top of the mountain can be calculated as follows;
Total pressure at top = Pressure due to mercury column + ρgh
98,736.8 Pa = 101,325 Pa + 1.25 kg/m³ x 9.81 m/s² x h
98,736.8 Pa = 101,325 Pa + 12.263h
12.263h = -2,588.2
h = -211 m
Barometer reading at top;
= 101,325 Pa + 1.25 kg/m³ x 9.81 m/s² x (-211 m)
= 98,737.6 Pa
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the volume of a cylinder of height 11 inches and radius r r inches is given by the formula v = 11 π r 2 v=11πr2
The volume of a cylinder with a height of 11 inches and radius r inches is given by the formula v = 11πr^2.
The formula for the volume of a cylinder is given as V = πr^2h, where V represents the volume, r is the radius of the cylinder's base, and h is the height of the cylinder.
In this case, the given formula v = 11πr^2 represents the volume of a cylinder with a fixed height of 11 inches. The formula tells us that the volume (v) is equal to 11 times π times the square of the radius (r).
To find the volume of a specific cylinder, you can substitute the given value of the radius into the formula v = 11πr^2. By simplifying the equation, you can calculate the volume of the cylinder in cubic inches.
It's important to note that the units in the formula must be consistent. In this case, the height is given in inches, so the radius should also be in inches to ensure accurate results.
Therefore, the formula v = 11πr^2 represents the volume of a cylinder with a height of 11 inches and a variable radius, allowing you to calculate the volume for specific values of r.
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All of the following choices are examples of commonly used assessment methods for body
composition EXCEPT
A. waist to hip ratio
B. bioelectrical impedance analysis
C. the spongy bob technique
D. skinfold measurements this is PE please help mee
Answer:
letter D
Explanation:
sana po makatulong po sa inyo
surface?
What is the mass of an object that experiences a gravitational force of 700 N near the Earth's surface
Answer:
70kg
Explanation:
Given parameters:
Gravitational force = 700N
Unknown:
Mass of the person = ?
Solution:
The weight is gravitational force on the person and can be expressed as;
W = mg
m is the mass
g is the acceleration due to gravity = 10m/s²
So;
700 = m x 10
m = 70kg
On the balloon simulation what do the red circles represent? What kind of charge do they have
In the balloon simulation, the red circles represent positive charges.
Electrostatics is the branch of physics that studies electric charges at rest. The interaction between electric charges is the foundation for electrostatics. These interactions can either be repulsive or attractive, depending on the types of charges. Electrostatics plays an important role in many aspects of our daily lives.
For example, we use it in the design of electrical circuits, lightning rods, and particle accelerators. The simulation demonstrates the following electrostatic principles: Like charges repel and opposite charges attract.
Each balloon has an equal amount of positive and negative charges when it is neutral.When a balloon is rubbed, electrons are transferred from one surface to the other, creating an imbalance of positive and negative charges.The excess charge is spread over the surface of the balloon. This charge creates an electric field.
As the balloon is rubbed, some of the electrons from the balloon's surface are transferred to the wool. The balloon becomes positively charged while the wool becomes negatively charged. As the balloon is brought closer to the wall, the positive charges on the surface of the balloon repel the positive charges on the surface of the wall.
This repulsion results in the balloons sticking out from the wall, indicating that the charges on the balloon are repelling the charges on the wall.The red circles in the simulation represent the positive charges.
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A 16-year-old employee working for Southern Virginia College's (SVC) bookstore during the summer months is helping prepare for Fall sales. It's a good way to make extra money, and the teen is saving for a car.
Books from one supplier are shipped to the SVC bookstore in large crates equipped with rope handles on all sides. On one occasion, the teen momentarily pulled with a force of 713 N at an angle of 35.8° above the horizontal to accelerate a 114-kg crate of books. The coefficient of friction between the crates and the vinyl floor is 0.541.
Determine the acceleration experienced by the crate in m/s2. Use the approximation g ≈ 10 m/s2.
Answer: ___________ m/s2 (rounded to the hundredths or thousandths place)
The acceleration experienced by the crate is approximately 0.844 m/s
How to solve for the accelerationWeight of the crate:
Weight = mass × acceleration due to gravity
Weight = 114 kg × 10 m/s^2
Weight = 1140 N
Force of friction:
Force of Friction = coefficient of friction × normal force
Force of Friction = 0.541 × 1140 N
Force of Friction ≈ 616.74 N
Net force:
Net Force = Applied Force - Force of Friction
Net Force = 713 N - 616.74 N
Net Force ≈ 96.26 N
Acceleration:
Acceleration = Net Force / mass
Acceleration = 96.26 N / 114 kg
Acceleration ≈ 0.844 m/s
Therefore, the acceleration experienced by the crate is approximately 0.844 m/s
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Two pebbles are dropped into a pool of water as shown. If a new wave with a
greater amplitude results, which kind of wave interaction has occurred?
Answer:
Constructive interference
Explanation:
Answer:
C. Constructive interference
Explanation:
Please help if you have the time
A string is stretched between fixed supports 2.0 meters apart. When set in transverse vibration at a frequency of 120 Hz the string vibrates in four segments, as shown. What is the wave speed in the string?
We know, length of segment wave is half the wavelength .
Let, wavelength of wave is \(\lambda\).
So, length of segment will be \(\dfrac{\lambda}{2}\) .
Now, it is given that the string vibrates in four segments.
So,
\(L = 4\times \dfrac{\lambda}{2}\\\\L = 2\lambda\\\\\lambda = 1\ m\)
Speed can be given by :
\(speed = wavelength \times frequency\\\\speed = 1\times 120\ m/s\\\\speed = 120\ m/s\)
Therefore, the wave speed in the string is 120 m/s.
A. calculate the ph of a 1 l solution containing 1. 20ml of 5 m koh2. 10ml of 0.1 m glycine and 20ml of 2m hcl3.5ml of 2 m acetic acid and 5 grams of sodium acetate (82g/mol).\
The pH of a 1 L solution containing specific amounts of various substances, including KOH, glycine, HCl, acetic acid, and sodium acetate.
The pH of the solution, we need to consider the dissociation of the acidic and basic components present. The basic component, KOH, dissociates to produce OH- ions, while the acidic components, glycine, HCl, and acetic acid, contribute H+ ions. Sodium acetate acts as a buffer and can affect the pH of the solution.
First, we calculate the total amount of moles of H+ and OH- ions produced by the given substances. Then, we use these values to calculate the concentration of H+ ions. Finally, we apply the pH formula, which is the negative logarithm (base 10) of the H+ ion concentration, to determine the pH of the solution.
Taking into account the provided quantities and concentrations of the substances, along with their dissociation properties, we can calculate the total moles of H+ and OH- ions. From these values, we can determine the concentration of H+ ions and, subsequently, the pH of the solution.
In summary, the pH of the 1 L solution can be determined by considering the dissociation of the given substances and calculating the concentration of H+ ions. By applying the pH formula, we can obtain the pH value of the solution.
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Señalar la importancia de las capacidades fisico-motiz que se desarrollan en el futbol de salon y dar un ejemplo para cada uno
La respuesta correcta para esta pregunta abierta es la siguiente.
A pesar de que no anexas opciones o incisos para responder, podemos comentar lo siguiente.
La importancia de las capacidades físico-motriz que se desarrollan en el futbol de salón son determinantes para desarrollar o maximizar las actividades propias de este deporte con objeto de rendir al máximo y aspirar al mejor de los resultados.
Estas capacidades físico-motrices son las que le permiten a un jugador realizar su máximo esfuerzo, mejorar su desempeño físico y conseguir resultados positivos.
Estamos hablando de la fuerza, la velocidad y la resistencia.
La velocidad es la aceleración que el jugador de futbol necesita para aumentar su velocidad de un punto A, a un punto B, en el menor tiempo posible.
La resistencia es la capacidad del jugador de futbol para mantener ese nivel de aceleración y desempeño, sin bajar su rendimiento. Su capacidad física debe ser resistente para ser constante en su rendimiento físico.
La fuerza es la potencia con la que desempeña los movimiento físicos dentro de la cancha.
Use trigonometry to find the missing values of the sides of the triangles below.
Explanation:
tan ● = opposite / adjacent
tan 31.5 = 19 / F
0.613 = 19 / F
0.613F = 19
F = 31
sin ● = opposite / hypotenuse
sin 31.5 = 19 / a
0.52 = 19 / a
0.52a = 19
a = 36. 36
Using trigonometry, the base of the triangle is approximately 33.476, and the hypotenuse of the triangle is approximately 38.118.
To find the base and hypotenuse of a right triangle with one angle of 31.5 degrees and a given height of 19:
Here,
Opposite side = height = 19 (given)
Adjacent side = base (unknown)
Hypotenuse = hypotenuse (unknown)
First, let's find the base (adjacent side):
tan(θ) = opposite ÷ adjacent
tan(31.5 degrees) = 19/base
To find the base, we can rearrange the equation:
base = opposite ÷ tan(θ)
base = 19 ÷ tan(31.5 degrees)
Calculating the value:
base ≈ 33.476
So, the base of the triangle is approximately 33.476.
Now, using the Pythagorean theorem, we can write:
hypotenuse² = base² + opposite²
hypotenuse² = (33.476)² + 19²
hypotenuse ≈ 38.118
Therefore, the hypotenuse of the triangle is approximately 38.118.
Thus, base is 33.476, and hypotenuse is 38.118.
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Use a ruler and rank these waves from most to least for a) amplitude, b)wavelength c) frequency, d) period,
Amplitude (from highest to lowest): Wave 1, Wave 3, Wave 2 , Wavelength (from longest to shortest): Wave 1, Wave 2, Wave 3 , Frequency (from highest to lowest): Wave 3, Wave 2, Wave 1 and Period (from longest to shortest): Wave 1, Wave 2, Wave 3 by Using a ruler and rank these waves from most to least.
first, you would need to provide specific waves to compare. Once you have the waves to compare, you can follow these steps:
1. Use a ruler to measure the amplitude, wavelength, period, and frequency of each wave.
2. Rank the waves based on their measurements:
a) Amplitude: Order the waves from the highest to the lowest peak (or from the lowest trough to the highest peak).
b) Wavelength: Order the waves from the longest distance between two consecutive peaks (or troughs) to the shortest distance.
c) Frequency: Order the waves from the highest number of cycles per unit time (e.g., cycles per second) to the lowest.
d) Period: Order the waves from the longest time required to complete one cycle to the shortest time required.
After following these steps, you will have ranked the waves from most to least for amplitude, wavelength, frequency, and period.
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A body starts with an initial velocity of 10m/s and moves along a straight line with a constant acceletion. When the velocity of the particle is 50m/s, the acceleration is reversed in direction. find the velocity of the particle when it reaches it's starting point.
The velocity of the particle when it reaches the starting point = 70 m/s
Explanation:For the first part of the motion
The initial velocity, u = 10 m/s
The final velocity v = 50 m/s
\(\begin{gathered} v^2=u^2+2as_1 \\ 50^2=10^2+2as_1 \\ 2500-100=2as_1 \\ 2as_1=2400..........(1) \end{gathered}\)For the second part of the motion
The initial velocity, u = 50 m/s
Final velocity, v = 0 m/s
\(\begin{gathered} v^2=u^2-2as_2 \\ 0=50^2-2as_2 \\ 2as_2=2500........(2) \\ where\text{ s}_1\text{ is the distance covered during the first part of the motion} \\ s_2\text{ is the distance covered during the second part of the motion} \\ \end{gathered}\)Add equations (1) and (2)
\(\begin{gathered} 2as_1+2as_2=2400+2500 \\ 2a(s_1+s_2)=4900........(3) \end{gathered}\)Taking the whole motion as a whole
Let the velocity of the particle when it reaches the starting point be vn
\(\begin{gathered} v_n^2=u^2+2a(s_1+s_2) \\ \\ v_n^2=0^2+4900 \\ \\ v_n^2=4900 \\ \\ v_n=\sqrt{4900} \\ \\ v_n=70\text{ m/s} \end{gathered}\)The velocity of the particle when it reaches the starting point = 70 m/s
An object has a position given by = [2.0 m + ( 5.00 m/s)t] + [3.0 m - , where quantities are in SI units. What is the speed of the object at time
The speed of the object at time t = 2 seconds is 1.00 m/s.
To determine the speed of the object at a given time, we need to find the magnitude of its velocity vector at that time.
Given:
Position vector r(t) = [2.0 m + (5.00 m/s)t] + [3.0 m - t² m]
To find the velocity vector v(t), we take the derivative of the position vector with respect to time:
v(t) = d[r(t)]/dt
v(t) = d/dt [2.0 m + (5.00 m/s)t] + d/dt [3.0 m - t² m]
v(t) = 5.00 m/s + d/dt [3.0 m - t² m]
The derivative of a constant term is zero, so the velocity vector simplifies to:
v(t) = 5.00 m/s - d/dt (t²) m
Taking the derivative of t² with respect to time:
v(t) = 5.00 m/s - 2t m/s
Now, we can calculate the magnitude of the velocity vector (speed) at a specific time t:
Speed = |v(t)| = |5.00 m/s - 2t m/s|
To find the speed at a given time, substitute the appropriate value of t into the expression and calculate the magnitude.
For example, if t = 2 seconds:
Speed = |5.00 m/s - 2(2 s) m/s|
= |5.00 m/s - 4 m/s|
= |1.00 m/s|
= 1.00 m/s
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both MA and VR do not depend on fraction TRUE/FALSE
False. Both Mechanical Advantage (MA) and Velocity Ratio (VR) can depend on fractions when considering certain aspects of simple machines.
MA and VR are important concepts in physics that describe the performance of simple machines, such as levers, pulleys, and inclined planes. Mechanical Advantage is defined as the ratio of output force to input force. In some cases, this ratio can be represented as a fraction. For example, when using a lever with unequal arms, the ratio of the lengths of the arms can be expressed as a fraction, which affects the mechanical advantage. Velocity Ratio is the ratio of the distance moved by the effort to the distance moved by the load. In simple machines like pulleys and gear systems, the ratio of the number of teeth or the diameters of the gears or pulleys can be represented as a fraction, which impacts the velocity ratio. In summary, both MA and VR can be influenced by fractions, depending on the specific simple machine and the parameters being considered.
The term "mechanical advantage" describes how much or to what extent a force is amplified or increased by utilising a tool or a machine. It is possible to compute mechanical advantage as follows:
Height of Incline (HI) / Incline Length (LI)
Let's say I built a hedge that slopes 10 metres from point x to point y, which is the back of a truck. It's 5 metres from point y to the ground.
Suppose LI = 10 m and HI = 5 m.
10/5 = 2 is the mechanical advantage granted.
The effort distance is another name for the incline angle. According to our calculations, I saved effort by forgoing horizontal movement compared to what it would have taken to lift that object off the ground.
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A car drives in a straight line off a cliff of unknown height. If the cars speed was 5.0 meters per second and it landed 6.7 meters away from the cliff determine the height of the cliff
Using the kinematic equation of motion to solve for the height of the cliff. The equation is given by:
d = vₒt + ½at²
where d is the vertical displacement (the height of the cliff), vₒ is the initial velocity (0 m/s since the car is moving vertically downwards), t is the time taken to reach the ground and a is the acceleration due to gravity (-9.8 m/s²).
Rearranging the equation to solve for the height of the cliff:
d = ½(-9.8)t² + vₒt
The time t can be calculated from the horizontal displacement, dₓ, and the initial velocity, vₒ, using the equation:
dₓ = vₒt + ½at²
Rearranging this equation to solve for t:
t = (dₓ - ½at²) / vₒ
As, dₓ = 6.7 m, vₒ = 5.0 m/s and a = -9.8 m/s², so substituting these values into the equation:
t = (6.7 m - ½(-9.8 m/s²)(t)²) / (5.0 m/s)
Solving for t:
t = 1.34 s
Now, from the value of t, substitute it back into the first equation to find the height of the cliff:
d = ½(-9.8 m/s²)(1.34 s)² + 0 m/s (1.34 s)
d = 20.36 m
Therefore, the height of the cliff is 20.36 meters.
What is displacement?
The change in an object's location from its beginning position to its end position is measured by a vector quantity called displacement. The straight line that connects the object's starting and final places serve as a representation of the shortest distance between them. Distances like meters, feet, and miles are used to express displacement.
Displacement is a verb that denotes the movement or displacement of an object. The definition of displacement is the modification of an object's position. Displacement is defined as the final position minus the starting position.
The displacement, which is the change in the object's position, is a vector with a magnitude of 10 miles and a direction of east.
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how does a second class lever make our work easier
Answer:
In a second class lever, the load is located between the effort and the fulcrum. If the load is closer to the fulcrum than the effort, then less effort will be required to move the load. If the load is closer to the effort than the fulcrum, then more effort will be required to move the load.
Explanation:
from what i learned, if its farther away from the load, its easier to lift, like a wheel barrel
A concave mirror is also known as converging mirror
Answer:
true
Explanation:
they have a reflecting surface that is recessed inward
The ____________ of any amount of a solid, liquid, or gas relative to its volume is called density.
Answer:
The mass of any amount of a solid, liquid, or gas relative to its volume is called density.
Answer: The mass of any amount of a solid, liquid, or gas relative to its volume is called density.
When there is an increasing unbalanced force applied in the opposite direction as the motion, speed will ___________________ and acceleration will ________________________.
When there is an increasing unbalanced force applied in the opposite direction as the motion, speed will decrease and acceleration will increase.
What is Acceleration?This is defined as the rate of change of velocity with time and the unit is metres per seconds.
An unbalanced force will lead to the speed of the object decreasing as a result of the distance reached being on a decline. However, the acceleration will increase due to the applied force in which they have a direct relationship.
This is therefore the reasons why they were chosen as the most appropriate choice.
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Question in the photo
Answer:
a lever that is what is used
if molecule gains heat energy it converts liquid to gas
Answer:
Actually, the substance is the one that changes from liquid to gas.
The molecule just gains energy which overcomes the attraction force between it and neighboring molecule.
which one of the following statements concerning permanent magnets is false?
The statement "When a permanent magnet is cut in half, one piece will be a north pole and one piece will be a south pole" is False.
When a permanent magnet is cut in half, it does not result in separating the magnet into distinct north and south poles. Instead, each resulting piece will still have its own north and south poles. This phenomenon is known as magnetic domain alignment. The domains within a magnet are regions where the magnetic moments of atoms align in the same direction, creating a magnetic field. Cutting a magnet disrupts the alignment of these domains, but it doesn't create isolated north and south poles on separate pieces.
Regardless of how a permanent magnet is divided, each resulting piece will have its own north and south poles. The magnetic field lines will still flow from the north pole to the south pole within each piece. Therefore, the statement "When a permanent magnet is cut in half, one piece will be a north pole and one piece will be a south pole" is false.
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The complete question is
which of the following statements concerning permanent magnets is false?- the direction of a magnetic field is indicated by the north pole of a compass-when a permanent is cut in half, one piece will be a north pole and one piece will be a south pole-the north pole of a permanent magnet is attracted to a south pole-magnetic field line outside a permanent magnet originate from the north pole and end on the south pole-all permanent magnets are surrounded by the magnetic field
What is the formula for speed.
Answer:
Speed=distance travelled/time taken
Answer:
the formula for speed would be s= d/t
frozen preparations (ice cream, sorbet, gelato, granite) can be melted and re-frozen? which cannot be melted and re-frozen? why?
Frozen preparations such as ice cream, sorbet, gelato, granite can be melted and refrozen, except gelato which cannot be melted and refrozen. This is because the ice cream, sorbet, and granite all contain a high content of fat which allows them to melt and refreeze successfully without becoming damaged.
However, the process of freezing the gelato forms tiny ice crystals, which provide its unique texture. If gelato is melted, it will lose its texture and will not re-freeze successfully.A gelato is a dense Italian ice cream that has a creamy texture and has a lower fat content than traditional ice cream. It is made by mixing milk, sugar, and flavorings, such as nuts or chocolate, and then churned to incorporate air into the mixture.
So, the ice cream, sorbet, and granite all contain a high content of fat which allows them to melt and refreeze successfully without becoming damaged.
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The components of a 10.8-meters-per-second velocity at an angle of 34.° above the horizontal are
9.0 m/s vertical and 6.0 m/s horizontal
13 m/s vertical and 7.5 m/s horizontal
7.5 m/s vertical and 13 m/s horizontal
6.0 m/s vertical and 9.0 m/s horizontal
Answer:
6.0 m/s vertical and 9.0 m/s horizontal
Explanation:
For the vertical component, we use the formula:
Sin(34°) = y / 10.8Then we solve for y:
0.559 = y / 10.8y = 6.0And for the horizontal component, we use the formula:
Cos(34°) = x / 10.8Then we solve for x:
0.829 = x / 10.8y = 9.0So the answer is " 6.0 m/s vertical and 9.0 m/s horizontal".
What energy transformation takes place when you stretch a bungee cord?
A.
Kinetic energy transforms into potential energy.
B.
Mechanical energy transforms into sound energy.
C.
Elastic energy transforms into kinetic energy.
D.
Potential energy transforms into elastic energy.
Answer:
D.Potential energy transforms into elastic energy.A cement block accidentally falls from rest from the ledge of a 71.5-m-high building. When the block is 20.0 m above the ground, a man, 1.70 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?
Answer:
The man has at most 1.54 seconds to get out of the way.
Explanation:
To determine the time it takes for the cement block to fall from a certain height, we can use the equation for free fall: h = (1/2)gt²
where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s²), and t is the time.
In this scenario, the height from which the cement block falls is 71.5 m - 20.0 m = 51.5 m.
By rearranging the equation and solving for t, we have: t = √(2h / g)
t = √(2 * 51.5 m / 9.8 m/s²) ≈ 3.08 s
However, the man only has to consider the time it takes for the block to fall from a height of 20.0 m, which is given by:
t' = √(2 * 20.0 m / 9.8 m/s²) ≈ 1.54 s
Therefore, the man has at most 1.54 seconds to get out of the way.
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According to Newton’s first law of motion, when will an object at rest begin to move?
when its inertia decreases to zero
when an unbalanced force acts upon it
when the action and reaction forces are equal
when two equal and opposite forces act upon it
According to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.
option B is the correct answer.
What is Newton's first law of motion?Newton's first law of motion, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will continue in motion with a constant velocity unless acted upon by an external force.
In other words, an object will maintain its state of motion (whether it is at rest or moving in a straight line at a constant speed) unless a force acts upon it.
Thus, according to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.
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Answer:
its B
Explanation: