A 5.95 M sugar solution is diluted from 100.0 mL to 812.5 mL. What is the concentration of the dilute solution

A polystyrene cup is used to minimise  the thermal energy loss because polystyrene cup is acts as a very good insulator.

It is important to use polystyrene cup to minimise thermal energy loss because it prevent the heat energy loss as it has air bubbled trapped inside them. if we hold a hot coffee in a polystyrene cup , the hot coffee does not burn your finger because it is a bad conductor of heat. it is a natural insulator. we can also use this styroform or polystyrene idea to make home warm in cold region , it reduce the transfer of heat ,so  that building stays warmer.

We can use plastic foam to reduce heat energy loss .  Both polystyrene and plastic foams are the good insulators and bad conductor of heat.

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CO₂ have a higher boiling point than CH₄ when they both possess dispersion forces because CO₂ consists of polar bonds between carbon and oxygen.

Intermolecular forces determine bulk properties, such as the melting points of solids and the boiling points of liquids.

Liquids boil when the molecules have enough thermal energy to overcome the intermolecular attractive forces that hold them together, thereby forming bubbles of vapor within the liquid.

CO₂ have a higher boiling point than CH₄ when they both possess dispersion forces because CO₂ consists of polar bonds between carbon and oxygen. The polarity increases the boiling point of the molecule.

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Answer:

43.93642

Explanation:

Phosphorus P 30.973762 1 86.0061

Hydrogen H 1.00794 5 13.9939

I don't know physics, but I hope this helps :)

(I'm a seventh grader so don't judge if this is wrong please)

Answer:

The answer is D

Explanation:

The element is in the 3rd period because n = 3.

The lines with the arrow that points inwards radiating from the charge from all directions. Therefore, option B is correct.

Electric field is generated by the charged bodies. The electric field lines around a positive charges will always be outward to all directions. The field lines around a negative point charge is always inward from all directions.

At one point, a field line is drawn tangential to the net. As a result, the direction of the electric field at any point is the same as the tangent to the electric field line. Second, the relative strength (magnitude) of the electric field at a point is correlated with the relative density of the field lines around that point. 

Always pointing away from a positive charge and in the direction of a negative point are electric field lines. In actuality, positive charges are where electric fields begin and negative charges are where they end. Field lines never cross one another, too. If they do, it suggests that the electric field there has two directions.

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Answer:

Argon

Explanation:

It has more electron than chlorine

The mass percent of benzoic acid in the sample is 55.5%.

The equation of the reaction is; HC7H5O2(aq) + NaOH(aq) ----> NaC7H5O2(aq) + H2O(l)

Number of moles of NaOH reacted = concentration × volume

Number of moles of NaOH reacted = 10.59/1000 L × 0.1546 M

Number of moles of NaOH reacted = 0.0016 moles of NaOH

Since the reaction is 1:1, 0.0016 moles of HC7H5O2 reacted also.

Hence, mass of HC7H5O2 = 0.0016 moles × 122 g/mol = 0.1952 g

Mass percent of HC7H5O2 in the original sample = 0.1952 g/ 0.3518 g × 100 = 55.5%

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Answer: A

Explanation:

Answer: Trail 2

Explanation: Because it has a pressure of 1 atm

Answer:

I think the awnser is B proteins

Explanation:

I could be wrong but this is off preveous knowleadge.

Answer:

Explanation:

Given data:

A) Volume of CO₂ = 0.100 L

Pressure = 307 torr

Temperature = 26°C

Mass of CO₂ = ?

Solution:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

26+273 = 299 K

307 torr/760 = 0.40 atm

0.40 atm × 0.100 L = n × 0.0821 atm.L/ mol.K  ×  299 K

0.04 atm.L =  n × 24.55 atm.L/ mol

n = 0.04 atm.L  / 24.55 atm.L/ mol

n = 0.002 mol

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.002 mol × 44 g/mol

Mass = 0.088 g

Given data:

b) Volume of C₂H₄ = 8.75 L

Pressure = 378.3 Kpa

Temperature = 483 K

Mass of C₂H₄  = ?

Solution:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

378.3KPa/101 = 3.73 atm

by putting values

3.73 atm × 8.75 L = n × 0.0821 atm.L/ mol.K  ×  483 K

32.64 atm.L =  n × 39.65 atm.L/ mol

n = 32.64 atm.L / 24.55 atm.L/ mol

n = 0.82 mol

Mass of C₂H₄ :

Mass = number of moles × molar mass

Mass =  0.82 mol × 28 g/mol

Mass = 22.96 g

c)

Given data:

A) Volume of Ar = 221 mL

Pressure = 0.23 torr

Temperature = -54°C

Mass of Ar = ?

Solution:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

-54+273 = 219 K

0.23 torr/760 = 0.0003 atm

221 mL/1000 = 0.221 L

0.0003 atm × 0.221 L = n × 0.0821 atm.L/ mol.K  ×  219 K

6.63×10⁻⁵ atm.L =  n × 17.98 atm.L/ mol

n = 6.63×10⁻⁵ atm.L  / 17.98 atm.L/ mol

n = 0.37×10⁻⁵  mol

Mass of Ar:

Mass = number of moles × molar mass

Mass = 0.37×10⁻⁵ mol × 39.9 g/mol

Mass = 14.76 ×10⁻⁵g

The number of moles the gas can be used to calculate the mass of the gas in each case.

Using;

a) PV = nRT

P = 307 torr or 0.4 atm

T =  26 °C + 273 = 299 K

V = 0.100 L

R = 0.082 atm LK-1mol-1

n = PV/RT

n =  0.4 atm ×  0.100 L / 0.082 atm LK-1mol-1 × 299 K

n = 0.00163 moles

Mass of CO2 =  0.00163 moles × 44 g/mol = 0.072 g

b) Again;

P = 378.3 kPa or 3.75atm

T = 483 K

V =  8.75 L

R = 0.082 atm LK-1mol-1

n = PV/RT

n = 3.75atm ×  8.75 L/0.082 atm LK-1mol-1 × 483 K

n = 0.83 moles

Mass of C2H4 =  0.83 moles × 28 g/mol = 23.24 g

c) Again;

P =  0.23 torr  or 0.0003 atm

V =  221 mL or 0.221 L

T =  -54 °C​ + 273 = 219 K

R = 0.082 atm LK-1mol-1

n = PV/RT

n =  0.0003 atm ×  0.221 L/0.082 atm LK-1mol-1 ×  219 K

n = 3.69 × 10^-6 moles

Mass of Ar  =  3.69 × 10^-6 moles × 40 g/mol

Mass of Ar  = 1.48 × 10^-4 g

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Answer:

Hydrogen sulfide is used primarily to produce sulfuric acid and sulfur. It is also used to create a variety of inorganic sulfides used to create pesticides, leather, dyes, and pharmaceuticals. Hydrogen sulfide is used to produce heavy water for nuclear power plants (like CANDU reactors specifically).

Explanation:

Sana Po it's help

Answer:

1. is Molar (with capital M)

2. is molal (m)

Explanation:

By definition, 1 Molar solutions have 1 mol of solute in 1 L of solution and 1 molal solutions have 1 mol of solute in 1 Kg of solvent

The factor that  doesn’t change the resistance of a wire is pressure. option A.

Resistance is a conductor's capacity to thwart the passage of current. It is controlled by the interplay of the applied voltage and the electric current passing through it. The amount of opposition any object applies to the flow of electric current is referred to as resistance.

The ohm, a unit of measurement for resistance, is represented by the Greek letter omega. According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them.

Hence option A is correct.

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missing part;

The pressure

The length of the resistor.

The thickness of the resistor.

The temperature of the conductor.

Answer:

It's obviously LIGHT ENERGY for me cuz it's from the flashlight..

Explanation:

Hope it helps you..

Your welcome in advance..

(ㆁωㆁ)

True. The statement "A rate law is an equation that mathematically describes how fast a reaction occurs" is true.

What is Rate of Reation?

The rate of reaction is the speed at which a chemical reaction takes place. It is a measure of how fast the reactants are consumed and the products are formed. The rate of reaction can be determined by measuring the change in concentration of a reactant or product over time. The rate of reaction is affected by several factors, including the concentration of reactants, temperature, pressure, and the presence of a catalyst.

A rate law is an equation that describes the relationship between the rate of a chemical reaction and the concentration of reactants in the reaction. The rate law helps to determine the order of the reaction with respect to each reactant, and it can be used to predict how changing the concentration of reactants will affect the rate of the reaction. The rate law can also help to determine the rate constant, which is a proportionality constant that relates the rate of the reaction to the concentration of reactants.

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Answer:

C. stocky bodies covered with thick fur or feathers

Explanation:

Animals in the tundra generally have stocky bodies covered with thick fur or feathers.

A tundra is a very cold biome. In fact, it is the coldest of all the biomes found on the earth. This region is found in the Arctic and other parts of the world. It is treeless, very cold and has little to no precipitation all year round.

The vapor pressure of the solution at 30°C is 0.9676781. The pressure that a vapor exerts on its condensed phases (solid or liquid) in a closed system at a specific temperature is known as vapor pressure.

The pressure of the solvent above the solution is known as the vapour pressure of a solution. Temperature, ambient pressure, and solute concentration all have an impact on a solution's vapour pressure. A manometer or a barometer can be used to determine a solution's vapour pressure. When a liquid is contained in a closed container, its molecules frequently crash into the walls of the container. Due to these collisions, the container's walls experience pressure equal to the liquid's vapour pressure.

Solution of P = (0.9677 x 31.8 mmHg)

P solution = 30.8 mmHg

X Solvent = 34.63588 mol/1.156 + 34.635

X Solvent = 0.9676781

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To convert acetone (propanone) to propanal, you can use a two-step process involving reduction and oxidation reactions. Here's a general outline of the process:

1. Reduction of Acetone to Isopropanol:

First, you need to reduce acetone to isopropanol (2-propanol) using a reducing agent. Common reducing agents for this step include sodium borohydride (NaBH₄) or lithium aluminum hydride (LiAlH₄).

Reaction conditions:

- Acetone + NaBH₄ (or LiAlH₄) → Isopropanol

- Solvent: usually an alcohol (e.g., methanol or ethanol) or an ether (e.g., THF)

- Temperature: room temperature or slightly above

2. Oxidation of Isopropanol to Propanal:

Next, oxidize isopropanol to propanal using an appropriate oxidizing agent. A common oxidizing agent for this step is pyridinium chlorochromate (PCC), which selectively oxidizes primary alcohols to aldehydes without over-oxidizing to carboxylic acids.

Reaction conditions:

- Isopropanol + PCC → Propanal

- Solvent: an aprotic polar solvent (e.g., dichloromethane)

- Temperature: room temperature

- Avoid strong oxidizing agents like potassium permanganate (KMnO₄) or chromium trioxide (CrO₃) because they can over-oxidize the isopropanol to propionic acid.

Answer:

The waters' temp increased

Explanation:

The temperature of the water in the swimming pool has increased due to the heat from the Sun. As a result, the particles in the water are moving faster and have a higher kinetic energy than in the morning.

The number of moles of acetic acid which has a molar mass of 60.05 g/mol present in 16.84 grams of acetic acid is 3.56.

Given the molar mass of Acetic acid (M) = 60.05 g/mol.

The mass of acetic acid (m) = 16.84g

Let the number of moles = n

A mole is a unit of measurement used in chemistry to measure amount of substance. It is calculated as molar mass by mass of the given substance. The mole is defined as the amount of a substance that contains as many elementary entities (atoms, molecules, ions, etc.) as there are atoms in exactly 12 grams of carbon-12. One mole of a substance contains this number of particles, and can be used to calculate the mass of a given sample of the substance.

n = 60.05/16.84 = 3.56 moles

Hence the required number of moles are 3.56.

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The concentration of chloride ions when 2.5 g of FeCl is dissolved in 150 mL of water is approximately 0.54 M.

To determine the concentration of chloride ions when 2.5 g of FeCl is dissolved in 150 mL of water, we need to consider the molar mass of FeCl and perform some calculations.

The molar mass of FeCl is 55.85 g/mol (for iron) + 35.45 g/mol (for chlorine), which gives a total molar mass of 91.3 g/mol for FeCl.

First, we need to calculate the number of moles of FeCl present in 2.5 g of the compound. This can be done using the formula:

moles = mass / molar mass

moles of FeCl = 2.5 g / 91.3 g/mol = 0.027 moles

Next, we convert the volume of water from milliliters (mL) to liters (L):

volume of water = 150 mL = 150/1000 L = 0.15 L

Now, we can calculate the concentration of chloride ions (Cl-) using the formula:

concentration (Cl-) = moles of Cl- / volume of water

Since FeCl dissociates into one Fe3+ ion and three Cl- ions, the number of moles of Cl- is three times the moles of FeCl:

moles of Cl- = 3 * moles of FeCl = 3 * 0.027 moles = 0.081 moles

concentration (Cl-) = 0.081 moles / 0.15 L = 0.54 M.

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There are approximately 0.0078 moles of molybdenum present in 0.75 grams.

In order to determine the number of moles of molybdenum present in 0.75 grams, we first need to know the molar mass of molybdenum. The molar mass of molybdenum (Mo) is 95.94 g/mol.

Next, we can use the formula:

moles = mass ÷ molar mass

Plugging in the given values, we get:

moles = 0.75 g ÷ 95.94 g/mol

Simplifying this expression, we get:

moles = 0.0078 mol

Therefore, there are approximately 0.0078 moles of molybdenum present in 0.75 grams.

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Answer:

Oxygen sodium hydrogen iron potassium chlorine are elements

Water is a compound

And magnesium ion is cation.

Morever oxygen hydrogen and chlorine are gases

Water and magnesium ion are liquid

And sodium iron potassium are solids

Explanation:

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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The decay of Xenon-146 follows an exponential decay model, where the amount of Xenon-146 remaining after time t is given by:

N(t) = N0 * (1/2)^(t/T)

where N0 is the initial amount of Xenon-146, T is the half-life of Xenon-146, and t is the time that has passed.

We are given that N0 = 416 g, N(t) = 13 g, and T = 37 hours. We can solve for t as follows:

N(t) = N0 * (1/2)^(t/T)

13 = 416 * (1/2)^(t/37)

Taking the natural logarithm of both sides:

ln(13) = ln(416) + (t/37) * ln(1/2)

Solving for t:

t = 37 * [ln(13/416) / ln(1/2)]

t ≈ 111.2 hours

Therefore, the Xenon-146 has been decaying for approximately 111.2 hours.

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

D. Electron pairs repelling each other push atoms apart

Explanation:

Hope this helps :) I just got it wrong on ap3x so I'm sure this is right

The VSEPR theory explain molecular shape by stating that the Electron pairs repelling each other push atoms apart. Hence, Option (D) is correct

Valence shell electron pair repulsion (VSEPR) theory, is a model used in chemistry to predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms.

It is also named the Gillespie-Nyholm theory after its two main developers, Ronald Gillespie and Ronald Nyholm.

Therefore, The VSEPR theory explain molecular shape by stating that the Electron pairs repelling each other push atoms apart. Hence, Option (D) is correct.

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The compound that acts as the precipitate in this reaction is Pbl₂, or lead(II) iodide.

In the given reaction equation:

KI + Pb(NO3)2 → KNO3 + Pbl₂

The precipitate formed is Pbl₂, which is lead(II) iodide. In the reaction, potassium iodide (KI) reacts with lead(II) nitrate (Pb(NO3)2) to form potassium nitrate (KNO3) and lead(II) iodide (Pbl₂).

Lead(II) iodide is insoluble in water, as mentioned in the statement. When the two chemicals are mixed, lead(II) iodide is formed as a solid precipitate, which appears as a golden substance, as described.

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