an electron in a vacuum chamber is fired with a speed of 8000 km/s toward a large, uniformly charged plate 75 cm away. the electron reaches a closest distance of 15 cm before being repelled.
Answers
Therefore, the charge on the plate is 0.8326 C.
The given problem states that an electron in a vacuum chamber is fired with a speed of 8000 km/s toward a large, uniformly charged plate which is at a distance of 75 cm. The electron reaches a closest distance of 15 cm before being repelled.
We have to determine the charge on the plate. This can be done by using the equation of the motion of a charged particle in an electric field. The equation of motion of a charged particle is given as:
F = qE + ma
The electric force experienced by the particle is given as:
F = qE
Where q is the charge on the particle, and E is the electric field. The mass of the electron is given as m = 9.11 × 10^-31 kg.
Using the above equations, we can find the electric field experienced by the electron.
The distance traveled by the electron before it reaches the closest distance is given as:
d = 75 cm - 15 cm
= 60 cm
The time taken by the electron to travel this distance is given by:
t = d/v
where v is the speed of the electron.
The speed of the electron is given as:
v = 8000 km/s
= 8 × 10^6 m/s
Using the above equations, we can find the time taken by the electron to travel the distance:
d = 60 cm
= 0.6 mt
= 0.6/8 × 10^6
= 7.5 × 10^-8 s
The electric field experienced by the electron is given as:
E = F/qwhere F is the force experienced by the electron.The force experienced by the electron is given as:
F = ma = qE
Thus,
E = ma/q
= awhere a is the acceleration experienced by the electron.
a = (v-u)/t
where u is the initial velocity of the electron, which is zero.
a = v/t
= 8 × 10^6/7.5 × 10^-8
= 1.066 × 10^14 m/s^2
Substituting this value of a in the above equation, we get:
E = 1.066 × 10^14 N/CE
= 1.066 × 10^14 V/m
The electric field experienced by the electron is given by E = 1.066 × 10^14 V/m.
The electric field due to a uniformly charged plate is given by:
E = σ/2ε
where σ is the surface charge density of the plate, and ε is the permittivity of free space.
Substituting the given values, we get:
1.066 × 10^14 = σ/2εσ
= 2ε × 1.066 × 10^14σ
= 2 × 8.85 × 10^-12 × 1.066 × 10^14σ
= 1.885 C/m^2
The charge on the plate is given by:
Q = σAwhere A is the area of the plate.
A = πr^2
where r is the radius of the plate.
A = π(0.75/2)^2A
= 0.4418 m^2
Substituting this value of A in the above equation, we get:
Q = 1.885 × 0.4418Q
= 0.8326 C
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Related Questions
Find the gravitational potential energy of a body of mass 25kg,kept at a height of 4m
Answers
Answer:
Massm=2.5kg
Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .
Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mgh
Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mghU=2.5×10×15
Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mghU=2.5×10×15U=25/10×10×=375j
How much work do you do when you lift a 100 N child 0.5 m?
Answers
Answer:
50 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 100 × 0.5
We have the final answer as
50 JHope this helps you
The minute hand of a clock completes one revolution in one hour. There are 3,600 seconds in one hour. Calculate the frequency of the minute hand
Answers
The frequency of the minute hand is 1/60 Hz. Given that the minute hand of a clock completes one revolution in one hour and there are 3,600 seconds in one hour.
To calculate the frequency of the minute hand: Frequency of the minute hand = No. of revolutions per secondFirstly, let us calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 secondsIn one hour, the minute hand completes 1 revolution. So, in 1 second, the minute hand completes 1/3600 of the revolution.Now, we can calculate the frequency of the minute hand.
Frequency of the minute hand = No. of revolutions per second Frequency of the minute hand = 1/3600 HzTo calculate the frequency of the minute hand, we can use the following steps: Step 1: Calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 seconds In one hour, the minute hand completes 1 revolution.
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(03.03 mc)what happens when a sound wave moves from water to air?
Answers
When a sound wave moves from water to air, the speed of the sound wave slows down .
Option A is correct .
The water's sound will become quieter in the air. The sound is produced by the medium's molecules and particles vibrating. In contrast to the air, the molecules in water are tightly bound, making it a compact medium. Sound waves travel more slow inside water than through air.
2. Because of constructive interference, the new wave will have the same displacement as the previous waves.
Option A is correct .
If the top of one wave meets the crest of another wave of the same frequency at the same point, the wave interference is said to be constructive. When two waves that are in phase meet and form a new wave with a larger amplitude, this is called constructive wave interference.
Wave interference :The phenomenon known as wave interference occurs when two waves collide while traveling through the same medium. The medium takes on a shape as a result of the combined effect of the two individual waves on the medium's particles when waves interfere.
Incomplete question :
1.What happens when a sound wave moves from water to air?
A. It slows down.
B. It speeds up.
C. It stays the same.
D. It reverses.
2. When two mechanical waves have a displacement in opposite directions, and they overlap, what will the resulting wave look like and why?
A. The new wave will have the same displacement as the original waves due to constructive interference.
B. The new wave will have a smaller displacement than either of the original waves due to destructive interference.
C. The new wave will have a greater displacement than either of the original waves due to constructive interference.
D. The new wave will have the same displacement as the original waves due to destructive interference.
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consider a satellite orbiting the earth at 17,500 mph. what would happen to a rock released from the satellite?
Answers
Answer:
The rock would orbit the earth at a velocity of 17,500 MPH next to the satellite.
Francium-233 has a half-life of 22 minutes.A Geigor counter gives a reading of 58 counts per minute (cpm) from a sample of francium-233.What will the reading be 22 minutes later?You can ignore background radiation
Answers
Answer:
The reading of the Geiger counter, 22 minutes later = 29 counts per minute (cpm)
Explanation:
Half life is defined as the time taken for the amount ( or activity) of a substance to reduce to half its original value.
As stated in the question, the half life of Francium-233 is 22 minutes, \(t_{1/2} = 22 minutes\). This means that it takes 22 minutes for the activity of Francium-233 to reduce to half of its original value.
The original activity of Francium-233 = 58 counts per minute (cpm)
By the end of 22 minutes, the activity measured by the counter would have halved.
Activity of Francium-233 after 22 minutes = 58/2
Activity of Francium-233 after 22 minutes = 29 counts per minute (cpm)
A student attempts to measure his own ECG on an oscilloscope having a differential input. For Figure 6. 11, Z 1 MQ, Z 20km, Z 10kO2 in ZG 30 kn, and idb 0. 5 HA. Calculate the power-line interference the student observes
Answers
The power-line interference the student observes is 0.0063 V.
Given, the data;Z1 = 1 MΩ, Z2 = 20 kΩ, Z3 = 10 kΩ, ZG = 30 kΩ, idb = 0.5 μA
First, we need to calculate the common-mode voltage gain (Acm).
The formula for Acm is given by;
Acm = (Z2 / Z1) + (Z4 / Z3)
Acm = (20 / 1000) + (30 / 10,000)
Acm = 0.02 + 0.003
Acm = 0.023
The common-mode voltage gain (Acm) is 0.023.
Now, we need to calculate the common-mode voltage (Vcm)
The formula for Vcm is given by;Vcm = Vg * Acm
Where Vg = 120 V (given)∴
Vcm = 120 * 0.023
Vcm = 2.76 V
Therefore, the common-mode voltage (Vcm) is 2.76 V
Next, we need to calculate the common-mode rejection ratio (CMRR).
The formula for CMRR is given by;
CMRR = Ad / Acm
Where
Ad = differential gain
Ad = (Z3 / Z1)
Ad = 10,000 / 1000
Ad =10
The differential gain (Ad) is 10∴CMRR = 10 / 0.023CMRR = 434.78
The common-mode rejection ratio (CMRR) is 434.78.
Now, we need to calculate the interference voltage (Vinterference). The formula for Vinterference is given by;
Vinterference = Vcm / CMRR
Where Vcm = 2.76 V, and CMRR = 434.78∴
Vinterference = 2.76 / 434.78
Vinterference = 0.0063 V
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The following equation illustrates the chemical reaction that occurs in a plant.
water + carbon dioxide + light energy → sugar + oxygen
Based on the law of conservation of energy, what happened to the light energy in the reaction?
A. It was produced by the plant.
B. It was changed into oxygen gas.
C. It was destroyed during the chemical reaction.
D. It was converted into chemical energy stored in the sugar.
Answers
Answer:
option d
it was converted into chemical energy stored in the sugar
Answer:
D. It was converted into chemical energy stored in the sugar.
Explanation:
A. It was produced by the plant. This is false because light energy is a reactant and not a product formed by the plant.
B. It was changed into oxygen gas. This is false because light energy could not be transformed to oxygen gas by any chemical means. Instead, carbon dioxide leads to oxygen being produced by the plant.
C. It was destroyed during the chemical reaction. This is false, it cannot be destroyed during the chemical reaction. Instead, it was used up and converted into chemical energy stored in the sugar.
D. It was converted into chemical energy stored in the sugar. This is true.
hope this helps!! p.s. i really need brainliest :)
What's the kinetic energy of the roller coaster at the top and bottom of the hill? Use KE
mu
A kiddie roller coaster car has a mass 100 kilograms. At the top of a hill, it's moving at a speed of 3 meters/second. After reaching the bottom
of the hill, its speed doubles. The car's kinetic energy at the bottom is
v its kinetic energy at the top. The car has
joules of kinetic energy at the bottom of the hill.
Reset
Next
Answers
The kinetic energy of the car is four times greater at the bottom than it is at the top. At the base of the hill, the car's kinetic energy is 1800 joules.
Describe kinetic energy.The momentum an object has as a result of motion is known as kinetic energy. We must exert force on an object if we desire to accelerate it. To apply a force, we must exert effort. Once the work is finished, the objects will be moving because energy has now been transferred to it.
What elements influence the kinetic energy?Describe that a travelling internal force and speed are major factors that impact the amount of kinetic energy it will possess. Partially particles can result in the loss of kinetic energy through frictional, sound, and heat.
k = 1 /2 mv²
K = 1 /2 (100 kg) (3 m/s)²
= 450 J
K = 1 /2 (100 kg) (6 m/s)²
k = 1800 J
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HELP GIVING BRAINLIEST
Answers
Answer:
Ok let me figure this out
Explanation:
#9 asks what is the relationship between distance and force?
The relationships between the two are of the following: if you have distance you woulnt have force, and if there was no force then there is no distance, the 2 countereact each other and balance the scale
A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
Answers
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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hii! help asap. i’ll give brainliest thanks!
Answers
Answer:
a i believe
Explanation:
What is the resistance of resistor R3?
Answers
Answer: 2.0
Explanation: I KNOW !
2. A javelin is thrown through an angle of 30o to the horizontal. Find the time taken by the javelin to reach the maximum height if the initial velocity is 60ms-1 [ take g =10 ms-1]
Answers
Answer:
3 seconds
Explanation:
The initial velocity is 60 m/s at an angle of 30° to the horizontal, so we can calculate the initial velocity in the vertical direction as
Viy = Vi sin(θ)
Viy = 60 sin(30)
Viy = 60(0.5)
Viy = 30 m/s
Then, we can use the following equation to calculate the time that it takes to reach the maximum height.
\(\begin{gathered} v_{fy}=v_{iy}-gt \\ v_{fy}+gt=v_{iy} \\ gt=v_{iy}-v_{fy} \\ \\ t=\frac{v_{iy}-v_{fy}}{g} \end{gathered}\)At a maximum height the vertical velocity is 0 m/s, so replacing viy = 30 m/s, vfy = 0 m/s and g = 10 m/s², we get
\(\begin{gathered} t=\frac{30\text{ m/s-0m/s}}{10\text{ m/s}^2} \\ \\ t=\frac{30\text{ m/s}}{10\text{ m/s}^2} \\ \\ t=3\text{ s} \end{gathered}\)Therefore, the answer is 3 seconds
a block attached to an ideal spring oscillates horizontally with a frequency of 2 hz and amplitude of 0.5 m. if the spring constant is 160 n/m, what is the mass of the block in kg ?
Answers
The mass of the block is approximately 1.02 kg. If a block attached to an ideal spring oscillates horizontally with a frequency of 2 hz and amplitude of 0.5 m.
The frequency of oscillation is given by the formula f = (1/2π) √(k/m), where f is the frequency, k is the spring constant and m is the mass of the block. Rearranging the formula, we get m = k / (4π²f²). Substituting the given values, we get m = 160 / (4π² × 2²) = 5 kg (rounded to the nearest whole number). Therefore, the mass of the block is 5 kg.
The mass of the block attached to the ideal spring can be found using the formula for the frequency of oscillation, which is:
f = (1 / 2π) * √(k / m)
where f is the frequency (2 Hz), k is the spring constant (160 N/m), and m is the mass of the block (which we want to find).
Rearranging the formula to find m, we get:
m = k / (4π²f²)
Plugging in the values:
m = 160 N/m / (4π²(2 Hz)²)
m ≈ 1.02 kg
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the box with the changing data shows that the acceleration is constant at 4.90 m/s2, but i thought g = 9.80 m/s2. how is this possible?
Answers
The box with the changing data shows that the acceleration is constant at 4.90 m/s2, but i thought g = 9.80 m/s2.
The acceleration due to gravity (g) is different from the acceleration of the object itself. Although g is usually taken to be 9.8 m/s2, it can vary depending on the object's location and height above the Earth's surface. As a result, a falling object can experience acceleration greater than, less than, or equal to g when air resistance is taken into account or not
In the given scenario, the box is not necessarily in free fall; it could be undergoing linear motion along a surface. Furthermore, the box could be in free fall, but with air resistance affecting its motion. In this situation, the box's acceleration would be less than g.The box's acceleration may have been determined using an accelerometer or a ticker tape. Regardless, the acceleration indicates the rate at which the box's velocity is changing, which may or may not be equal to g.
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Suppose that the net external force (push minus friction) exerted on a lawnmower is 51 N. parallel to the ground. The mass of the mower is 24 kg. What is its acceleration?
Answers
Answer:
2.125 m/s^2
Explanation:
Use Newton's second law: Force equals mass times acceleration, F = ma. You know the force (51 N) and you know the mass of the mower (24 kg). Remembering that a Newton is the same as kg-m/s2, solve for acceleration:
F = ma
51 kg-m/s2 = 24 kg * a
2.125 m/s2 =a
If a net external force of 51N is extorted on a 24kg lawnmower parallel to the ground, the acceleration of the mower will be 2.125 m/s².
Given the data in the question;
Net External Force; \(F = 51N\)
Mass of the Mower; \(m = 24kg\)
Acceleration; \(a = ?\)
To determine the acceleration of the mower, we make use of the equation from the Newton's Second Law of Motion:
\(F = m\ * \ a\)
Where F is the force exerted, m is the mass and a is the acceleration.
But then, we know that; ( A newton is the same thing as \(1 kg.m/s^2\) )
Hence, Our Net External Force; \(F = 51kg.m/s^2\)
We substitute our values into the equation to find acceleration "a"
\(51kg.m/s^2 = 24kg\ *\ a\\\\a = \frac{51kg.m/s^2}{24kg} \\\\a = 2.125 m/s^2\)
Therefore, If a net external force of 51N is extorted on a 24kg lawnmower parallel to the ground, the acceleration of the mower will be 2.125 m/s².
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47. explain why the abundances of heavy elements in stars correlate with their positions in the galaxy.
Answers
The presence of heavy elements in stars correlates with their positions because these elements show which star formed first, and a star's brightness and spectral type show where it is in the galaxy.
Heavy elements are present in population I stars. It is concentrated in the discs of spiral galaxies and typically contains the sun. It is also hot, youthful, and brilliant. The majority of them are found in spiral arms. In globular clusters and the outer galactic halo, where the concentration of heavy elements is relatively low, population II stars are born. The important information to compare the locations of the stars is therefore their abundances of heavy metals. Energy must be added in order for elements heavier than iron and nickel to develop.
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multiple choice
15) A coiled spring used to help a door close has ________ ________energy when the door is open.
16) After braking, a bicycle's tires increase in temperature as friction causes some of the
mechanical energy to transfer to ________ energy.
Answers
According to conservation of energy, the energy of interacting bodies in a closed system remains constant. The total energy of an isolated system remains constant; it is said to be conserved over a period of time.
Elastic energy is the mechanical implicit energy stored in the configuration of a material or physical system as it's subjected to elastic distortion by work performed upon it. Elastic energy occurs when objects are impermanently compressed, stretched or generally misshaped in any manner.
The mechanical energy is never lost forever , rather it gets converted to thermal energy because of the friction .
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PLEASE HELP!!! WILL MARK BRAINLIEST
Answers
The environmental impact of the changes in the amount of energy resources is reduction in air pollution.
What are energy resources?Energy resources are the materials that can act as sources of energy which is grouped into two namely:
Renewable energy resources: These are energy resources that can easily be replaced by nature. A typical example is the solar energy.Non renewable energy resources: These are energy resources that cannot easily be replaced by nature. Examples include coal, nuclear and gas.From the given figures,
In 2014 renewable energy = 19%; while in 2015 it is = 25%
In 2014 non renewable energy when added = 79%; while in 2015 it is = 73%
This shows that there was reduction in the use of non renewable energy from 2014 to 2015 by 6%.
This would affect the environment positively as there would be reduction in air pollution caused by non renewable energy resources.
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what determines G the acceleration of gravity on the surface of a planet or Moon
Answers
Answer:
distance from the center of the planet
Explanation:
if a cannonball were fired horizontally from a cannon atop a very high mountain what would its trajectory look like
Answers
The trajectory of the cannonball will be in parabolic motion.
A trajectory is an object that only gravity acts on. The downward force, gravity, accelerates the projectile downward. The vertical components of motion are independent of each other, so gravity does not change the object's horizontal velocity. A vertical force does not cause horizontal movement. A vertical force acting on a horizontally moving object causes the object to deviate from its linear trajectory.
When an object moving forward is affected by gravity, it falls in a parabolic arc. Since the projectile is an object affected only by gravity, the projectile's path forward from the initial thrust momentum is parabolic.
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Which force does not operate at a distance of 1 m?
A. Weak nuclear
O B. Electric
C. Gravitational
D. Magnetic
Answers
Answer:
A
Explanation:
Water is added to a measuring cylinder containing 100 cm3 of liquid paraffin. (the density of paraffin is 0.80 g/ cm3 and that of the water is 1.0 g / cm3 .) as the water is added, the level of the paraffin rises to 150 cm3 . the paraffin and water do not mix. what finally is the total mass of liquid in the measuring cylinder?
Answers
The total of the liquid in the measuring cylinder given the data from the question is 130 g
What is density?The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
How to determine the mass of paraffin Density of paraffin = 0.80 g/cm³Volume of paraffin = 100 cm³Mass of paraffin =?Mass = Density × Volume
Mass of paraffin = 0.8 × 100
Mass of paraffin = 80 g
How to determine the mass of water Density of water = 1 g/cm³Volume of paraffin = 100 cm³Volume of paraffin + water = 150 cm³Volume of water = 150 – 100 = 50 cm³Mass of water =?Mass = Density × Volume
Mass of water = 1 × 50
Mass of water = 50 g
How to determine the mass of the mixture Mass of water = 50 gMass of paraffin = 80 gMass of mixture =?Mass of mixture = Mass of paraffin + Mass of water
Mass of mixture = 80 + 50
Mass of mixture = 130 g
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A rare decay mode has been observed in which 222Ra emits a 14C nucleus.(a) The decay equation is222Ra → AX + 14C.Identify the nuclide AX.208Pb 210Pb 209Bi 211Bi(b) Find the energy emitted by the decay. The mass (MeV) of 222Ra is 222.015353 u.
Answers
The nuclide AX is 208Pb.
The energy emitted by the decay is approximately 33.02 MeV.
(a) To identify the nuclide AX in the decay equation 222Ra → AX + 14C, we need to determine the atomic number of AX by subtracting the atomic number of the emitted particle (14C) from the atomic number of 222Ra (88).
The atomic number of 14C is 6 because it represents a carbon nucleus with 6 protons.
So, the atomic number of AX is 88 - 6 = 82.
The nuclide with atomic number 82 is lead (Pb). Therefore, the nuclide AX is 208Pb.
(b) To find the energy emitted by the decay, we need to calculate the mass difference between the initial state (222Ra) and the final state (AX + 14C).
The mass of 222Ra is given as 222.015353 u.
The mass of 208Pb is 207.976652 u, and the mass of 14C is 14.003241 u.
The mass difference is:
Δm = (mass of 222Ra) - (mass of 208Pb + mass of 14C)
= 222.015353 u - (207.976652 u + 14.003241 u)
= 222.015353 u - 221.979893 u
= 0.03546 u.
Since 1 atomic mass unit (u) is equivalent to approximately 931.5 MeV/c^2, we can calculate the energy emitted by the decay:
Energy = Δm * (931.5 MeV/c^2 per u)
= 0.03546 u * (931.5 MeV/c^2 per u)
≈ 33.02 MeV.
Therefore, the energy emitted by the decay is approximately 33.02 MeV.
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A student places two books on a table. One book weighs less than the other book. Which book has less gravitational potential energy? (Consider the reference point to be the floor.)
Answers
If a student places two books on a table, the one with less mass will have less gravitational potential energy compared to the one with more mass if they are at the same height above the floor.
When a student places two books on a table, the gravitational potential energy of each book depends on its mass and the height from the reference point, which in this case is the floor. The formula for gravitational potential energy is U=mgh, where U is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. Therefore, the book with less mass would have less gravitational potential energy compared to the book with more mass if they are placed at the same height.
This is because the potential energy of an object is directly proportional to its mass and height. Therefore, if two objects are at the same height, the one with less mass will have less potential energy. On the other hand, if two objects have the same mass, the one at a greater height will have more potential energy.
In conclusion, if a student places two books on a table, the one with less mass will have less gravitational potential energy compared to the one with more mass if they are at the same height above the floor.
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. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Answers
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
what is the car's average velocity
Answers
Answer:
vận tốc bằng quãng đường chia thời gian
Explanation:
v=s/t
An arrow has a mass of 0.08 kg and is flying 1.2 m above the ground with a
speed of 32 m/s. What is the total mechanical energy of the arrow? The
acceleration due to gravity is 9.8 m/s2.
O A. 4J
B. 42 J
C. 1 J
D. 40 J
Answers
B 42
Mechanical Energy= Kinetic Energy + potential energy TE=1/2mv²+mgH
= 41.9 J
A playground 82 ft long and 54 ft wide is to be resurfaced at a cost of $2.75 per sq ft. What will the resurfacing cost?Round to nearest integer or decimal
Answers
ANSWER:
$ 12177
STEP-BY-STEP EXPLANATION:
We must calculate the area of the playground, knowing that the area is equal to length times width, like this:
\(\begin{gathered} A=82\cdot54 \\ A=4428ft^2 \end{gathered}\)Now, knowing the area, we can calculate the total cost, like this:
\(\begin{gathered} C=2.75\cdot4428 \\ C=12177 \end{gathered}\)The resurfacing cost is $ 12177