An auto mechanic spills 81 mL of 3.2 M H2SO4 solution from a rebuilt auto battery. How many milliliters of 1.6 M NaHCO3 must be poured on the spill to react completely with the sulfuric acid

When the experiment is performed with 0.35g of potassium, less hydrogen gas is created, which has an impact on the volume of gas produced.

What are the properties of potassium?

A silvery-white metal, potassium is malleable enough to be easily sliced with a knife. Within a few of seconds, potassium metal combines quickly with ambient oxygen to produce flaky, white potassium peroxide.

Potassium metal is a good conductor of heat and electricity, is soft and white with a silvery luster, and has a low melting point. A flame colored with potassium has a lavender hue, and its vapour is green. With 2.6 percent of the mass of the crust's mass, it is the eighth most common element there.

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Explanation:

the sulfur ato is in group 6 of the periodic table. In order to become an ion the ato needs to gain 2 electrons so it has a full outer shell of electron and is stable. so the atom S goes to S2+ + 2e

The answer is System.

When a scientific investigation is in progress, its used to perform and understand the natural phenomenon that goes on using the scientific method. Since this is a descriptive investigation, it provides a descriptive account of any system by looking at it without any prior knowledge to that subject. This method of investigation does not use a hypothesis. Thus, proves our answer correct.

Best of Luck!

Answer:

The answer is System.

Explanation:

When a scientific investigation is in progress, its used to perform and understand the natural phenomenon that goes on using the scientific method. Since this is a descriptive investigation, it provides a descriptive account of any system by looking at it without any prior knowledge to that subject. This method of investigation does not use a hypothesis. Thus, proves our answer correct.

Answer:

violet

Explanation:

Hydrocarbons are generally soluble in nonpolar solvents.

Hydrocarbons are generally soluble in nonpolar solvents such as benzene because they have similar molecular characteristics.

Hydrocarbons are molecules composed of carbon and hydrogen atoms that form nonpolar covalent bonds. Since these molecules have no charge, they do not readily dissolve in polar solvents such as water, which is composed of polar covalent bonds with partial positive and negative charges on its atoms.

Benzene, on the other hand, is a nonpolar solvent that is composed of carbon and hydrogen atoms arranged in a symmetrical ring structure. The electrons in benzene are shared equally between its atoms, making it nonpolar and unable to dissolve polar substances.

When hydrocarbons are added to benzene, the nonpolar nature of both substances allows them to mix and dissolve into one another. This is due to the fact that like dissolves like, meaning that polar solvents dissolve polar solutes and nonpolar solvents dissolve nonpolar solutes.

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Answer:

Metals on top of the activity series can displace metals at the bottom and they are highly reactive as compared to metals at the bottom of the series.

Hence, the order is X>W>Y>Z.

The maximum wavelength of light that will still break O2 molecules apart is approximately 3.335 nanometers.

To calculate the maximum wavelength of light required to break O2 molecules apart, we can use the equation:

E = hc/λ

where:

E is the energy required to break the molecules (496.0 kJ/mol),

h is Planck's constant (6.62607015 × 10^-34 J·s),

c is the speed of light (2.998 × 10^8 m/s), and

λ is the wavelength of light.

First, let's convert the energy requirement from kJ/mol to J/mol:

496.0 kJ/mol = 496.0 × 10^3 J/mol

Now, we can rearrange the equation to solve for the wavelength (λ):

λ = hc/E

Substituting the given values:

λ = (6.62607015 × 10^-34 J·s × 2.998 × 10^8 m/s) / (496.0 × 10^3 J/mol)

Calculating this expression:

λ = 3.335 × 10^-9 m

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Answer:

165.3 cm^3

Explanation: hope this is correct!!

P1 * V1 / T1 = P2 * V2 / T2

P1 = 84.6 kPa

V1 = 215 cm³

T1 = 23.5°C = 23.5 + 273 K = 296.5 K

At STP:

P2 = 101.3 kPa

V2 = ?

T2 = 273 K

Answer:

Organisms can be classified into one of three domains based on differences in the sequences of nucleotides in the cell's ribosomal RNAs (rRNA), the cell's membrane lipid structure, and its sensitivity to antibiotics. 3. The three domains are the Archaea, the Bacteria, and the Eukarya.

Explanation:

Answer:

(i) specific heat

(ii) latent heat of vaporization

(iii) latent heat of fusion

Explanation:

i. Q = mcΔT; identify c.

Here, Q is heat, m is the mass, c is the specific heat and ΔT is the change in temperature.

The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C is known as the specific heat.  

ii. Q = mLvapor; identify Lvapor

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg liquid into 1 kg vapor at constant temperature.  

iii. Q = mLfusion; identify Lfusion

Here, Q is the heat, m is the mass and L is the latent heat of fusion.  

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg solid  into 1 kg liquid at constant temperature.  

(i) c is the molar heat capacity of the substance.

(ii) Lvapor is the latent heat of evaporation of the substance

(iii) Lfusion is the latent heat of fusion of the substance

All the 3 equations fall under Calorimetry.

In all the equation Q is the amount of heat required.

(i) First equation represents the amount of heat required to raise the temperature of a substance of mass m.

                          Q = mcΔT

       here c is the molar heat capacity of the substance and ΔT is the chnage in temperature.

(ii) Second equation represents the amount of heat required to convert a substance of mass m from liquid phase to vapour phase.

                          Q = mLvapor

        here Lvapor is the latent heat of evaporation of the substance

during evaporation no change in temperature occurs.      

(iii) Third equation represents the amount of heat required to convert a substance of mass m from solid phase to liquid phase.

                          Q = mLfusion

        here Lfusion is the latent heat of fusion or melting of the substance

during fusion no change in temperature occurs.    

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Answer:

violet

Red has the longest wavelength and violet has the shortest wavelength. When all the waves are seen together, they make white light. Ultraviolet (UV) light—is radiation with a wavelength shorter than that of visible light, but longer than X-rays, in the range 10 nm to 400 .

Explanation:

The radii of the first, second, and third Bohr orbits of hydrogen are 0.529 Å, 2.12 Å, and 4.77 Å respectively. The equation is as follows:

r = n^2 * (0.529 Å) / Z.

In this equation, r represents the radius of the orbit, n represents the principal quantum number (which corresponds to the energy level of the orbit), 0.529.

Å is a constant representing the Bohr radius, and Z is the atomic number of the nucleus (which is 1 for hydrogen).
To calculate the radii of the first, second, and third Bohr orbits of hydrogen, we can substitute the values of n into the equation.

For the first orbit (n = 1): r = 1^2 * (0.529 Å) / 1 r = 0.529 Å
For the second orbit (n = 2): r = 2^2 * (0.529 Å) / 1 r = 2.12 Å
For the third orbit (n = 3): r = 3^2 * (0.529 Å) / 1 r = 4.77 Å

Therefore, the radii of the first, second, and third Bohr orbits of hydrogen are 0.529 Å, 2.12 Å, and 4.77 Å respectively.

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Answer:  True. Only primary alcohols can be oxidized to carboxylic acids using an oxidizing agent such as potassium permanganate (KMnO4) or chromium trioxide (CrO3) in an acidic solution. Secondary alcohols can be oxidized to ketones, but not to carboxylic acids, while tertiary alcohols cannot be oxidized at all using these reagents.

Explanation:

Balanced chemical equation:

\(3 Ba(NO3)2 (aq) + 2 K3PO4 (aq) ----- > 6 KNO3 (aq) + Ba3(PO4)2(s)\)

What is double-displacement reaction?

In an aqueous solution, a double-displacement reaction takes place when the positive and negative ions of two ionic compounds exchange positions to form two completely different compounds.

Chemical formula for :

Barium nitrate---> Ba(NO3)2  (aq)

Pottasium Phosphate = K3PO4 (aq)

Reaction between these two is a type of double displacement type reaction in which ions are exchanged , forming

Pottasium Nitrate -----> KNO3 (aq)

Barium Phosphate -----> Ba3(PO4)2 (s)

(aq) means the phase is aqueous and (s) means phase is solid or the compound precipitated out .

Now, writing the molecular formula using the above data , we get:

\(Ba(NO3)2 (aq) + K3PO4 (aq) ------ > KNO3 (aq) + Ba3(PO4)2 (s)\)

A equation is called balanced when number of chemical species are same on both sides of the equation .

Here, in product side there are 3 Ba and 2 (PO4) and only 1 Ba and 1 PO4 in reactant side to balance this let's multiply

2 with K3PO4 on reactant side and ,

3 with Ba(NO3)2 on reactant side

The equation thus becomes:

\(3 Ba(NO3)2 (aq) + 2 K3PO4 (aq) ------ > KNO3 (aq) + Ba3(PO4)2 (s)\)

Now,

There are 6 K atoms on reactant side to balance this let's multiply 6 with KNO3 in product side by doing so we also balanced NO3.

Consequently, the balanced chemical equation is

3 Ba(NO3)2 (aq) + 2 K3PO4 (aq) ----- > 6 KNO3 (aq)  + Ba3(PO4)2(s)

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Answer:

1.) Fluorine

2.) Francium

3.) Nonmetals

4.) Metals

5.) Aluminum

6.) Helium

Explanation:

The equation of the formation of lead II nitrate is;

Pb (s) + N2(g) + 3O2(g) --> Pb(NO3)2(s)

The equation of the formation of NaCl is 2Na(s) + Cl2(g) --->NaCl(s)

The equations of formation of the NaCl and Pb(NO3)2 from the standard states have been shown above.

The physical state of a substance under normal circumstances, which are commonly described as a pressure of 1 atmosphere (atm) and a temperature of 25°C, is known as the standard state of a substance.

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Answer

C) no energy is lost; the total amount of energy remains the same.

Explanation

The law of conservation of energy states that "The energy can neither be created nor destroyed - only converted from one form of energy to another." Therefore some energy will be used for metabolism while the other can be used for other properties and some can be stored.

Answer:

increases as you move down a group as the number of electrons increases. Therefore, the atomic radius increases as the group and energy levels increase

Explanation:

Answer:

tap the closed end of the capillary on the counter use a long plastic or glass tube as a drop guide tap the open end of the capillary on the counter use a needle to physically push it to the bottom.

Answer:

i would say (c)

Explanation:

Answer:c

Explanation:

Unpaired electrons: The number of electrons that are singly occupying an orbital in a molecule or atom are unpaired electrons. Unpaired electrons in metal complexes are linked to the chemical and physical properties of a molecule. When all electrons are paired with another, the molecule has no unpaired electrons,

therefore a diamagnetic molecule is formed. Unpaired electrons cause paramagnetism in molecules and atoms.The given complex ion is [Co(OH)6]3-. For determining the unpaired electrons, we have to write down the electronic configuration of the given complex ion.

The electronic configuration of Co is [Ar]3d74s2.Now, in Co(III) ion, the 3d level is expected to be half-filled, and then the 4s level is emptied. Therefore, the electronic configuration of the given complex ion [Co(OH)6]3- is: [Co(III)]=[Ar]3d6We know that d-orbitals have five orbitals and can have a maximum of 10 electrons (i.e., five pairs of electrons).The electronic configuration of Co(III) ion indicates that all the electrons are paired up i.e., there is no unpaired electron. Therefore, the correct option is "d) 0". 0" and the of this is that the electronic configuration of the given complex ion [Co(OH)6]3- is [Co(III)]=[Ar]3d6 which indicates that all the electrons are paired up i.e., there is no unpaired electron. Therefore, the correct option is "d) 0".

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Answer:

The following are the four unusual characteristics of water due to hydrogen bonding:  

1. Water exhibits high specific heat as the presence of hydrogen bonds enhances the concentration of energy needed for the molecules to accelerate the speed, thus, elevating the specific heat.  

2. Water has both high melting and high boiling points as hydrogen bonds enhance the energy, which is needed at the time of phase change, thus, increasing both the melting and the boiling points.  

3. The hydrogen bonds present in the water gives rise to robust intermolecular attractions, therefore, enhancing the surface tension.  

4. The hydrogen bonds present in the water makes the water to exhibit high heat of vaporization, that is, of about 41 KJ/mol.  

Answer:

High boiling and melting points: Hydrogen bonds increase the amount of energy required for phase changes to occur, thereby raising the boiling and melting points.

High specific heat: Hydrogen bonds increase the amount of energy required for molecules to increase in speed, thereby raising the specific heat.

Lower density as a solid than as a liquid: Hydrogen bonds increase the volume of the solid by holding molecules apart, thereby decreasing the density.

High surface tension: Hydrogen bonds produce strong intermolecular  attractions, which increase surface tension.

Answer:

Explanation:

Metamorphic rocks started out as some other type of rock, but have been substantially changed from their original igneous, sedimentary, or earlier metamorphic form. Metamorphic rocks form when rocks are subjected to high heat, high pressure, hot mineral-rich fluids or, more commonly, some combination of these factors.

Answer: metamorphic

Explanation:

Edge:)

Explanation:

Metals and non-metals can be identified either by their position in the periodic table or by their properties.

he metal elements are found on the left hand side of the periodic table, and the non-metal elements are found on the right. You can imagine a zig-zag line, starting at B-Al-Si, separating metals from non-metals.

Answer:

Muscovite is the mineral

Hazard signs such as "Flammable," "Oxidizer," and "Corrosive" National Fire Protection Association (NFPA) diamond Gas Cylinder sign posted signs convey information about chemical storage.

Pictograms are pictorial symbols that are used to express particular information about a chemical's risks. OSHA mandates pictograms on principal labels to indicate chemical dangers. The exact OSHA danger categorization determines each pictogram(s). There are several forms of risks in the workplace, including chemical, ergonomic, physical, and psychological hazards, to mention a few. Dangerous situations. Employees who operate with machinery or on construction sites are more likely to be exposed to safety concerns.  Biological dangers. Biological dangers are exceedingly hazardous  Physical dangers Ergonomic risks Chemical risks Workload risks.

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Answer:

JUST B

Explanation:

The equator is a hypothetical line passing through the center of the planet at latitude 0°. The Northern Hemisphere and the Southern Hemisphere are the two equal halves of the earth that are separated by the equator.

Greater gravitational force is exerted on the mass of denser objects and materials. This explains why materials with varying densities stack together  

At a transform plate border, the grinding motion between the plates causes shallow earthquakes, significant lateral rock displacement, and a wide zone of crustal deformation. Along the San Andreas Fault in western California, a landscape of this kind may be seen more spectacularly than anywhere else on Earth.

The inner core and the outer core, which encircle the mantle, are the two layers that make up the core. The Bullen discontinuity is the line dividing these two regions. Radius Core The 2,200 kilometers (1,367 miles) thick outer core is primarily made of liquid nickel and iron.

What layers of the Earth is represented by layer 1 and layer 2?

Composition-based Layers

The following layers are visible in a cross section of the Earth: First, there is the crust, followed by the mantle, the outer core, the inner core, the lithosphere, the asthenosphere, the outer core, and the inner core. Based on composition, the earth's core, mantle, and crust are divided: Less than 1% of the mass of Earth is made up of the crust.

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According to ideal gas equation and assuming number of moles as 1 and volume as 6.35×10\(^-6\) liters the pressure in the bulb is 1.837×10\(^-3\)  atmospheres.

The ideal gas equation is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.

Substituting n=1 ,V=6.35×10\(^-6\) L,R=8.314,ΔT=1130°C=1403.15 K in the above equation P=1×8.314×1403.15/6.35×10\(^-6\) =1.837×10\(^-3\) atmospheres.

Thus, the pressure in the bulb when it reaches its operating temperature is 1.837×10\(^-3\) atmospheres.

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The substance with the weakest intermolecular forces, CH₄, would have the lowest magnitude for the heat of fusion among the given options. This is because weaker intermolecular forces require less energy to change a substance from a solid to a liquid.

Heat of fusion is the energy required to change a substance from its solid state to its liquid state without changing its temperature. It is a physical property that varies among different substances and can be used to compare their melting points. It depends on the strength of the intermolecular forces between its molecules. The stronger the intermolecular forces, the more energy is required to break them and change the substance from solid to liquid. Substances with weaker intermolecular forces require less energy for the same change in state.

Out of the given options, the substance with the lowest magnitude for the heat of fusion would be the one with the weakest intermolecular forces. Therefore, methane would require the least amount of energy to change from a solid to a liquid, and it would have the lowest magnitude for the heat of fusion.

In comparison, CH₃OH (methanol), NH₃ (ammonia), and CHF₃ (trifluoromethane) have stronger intermolecular forces due to the presence of hydrogen bonding, dipole-dipole interactions, and/or van der Waals forces. These stronger intermolecular forces make it more difficult to change these substances from a solid to a liquid, and they would require more energy to do so. Therefore, the heat of fusion of these substances would be higher than that of methane.

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