An article in the Nov. 11, 2005, issue of the San Luis Obispo Tribune reported that researchers making random purchases at California Wal-Mart stores found scanners coming up with the wrong price 8.3% of the time. Suppose this was based on 200 purchases. The National Institute for Standard and Technology says that in the long run at most two out of every 100 items should have incorrectly scanned prices.

a. Develop a test procedure with a significance level of (approximately) .05, and then carry out the test to decide whether the NIST benchmark is not satisfied.

b. For the test procedure you employed in (a), what is the probability of deciding that the NIST benchmark has been satisfied when in fact the mistake rate is 5%?

Answer:

15,000,000 grams

Step-by-step explanation:

300 * 50 = 15,000kg

kg to grams is *1000

15,000 * 1000 = 15,000,000

Answer:

15,000,000.

Step-by-step explanation:

Answer: \(45^{\circ}\)

Step-by-step explanation:

\(\angle ABC\) is formed by \(\overline{AB}\) and \(\overline{BC}\), so we can begin by finding their slopes.

\(m_{\overline{AB}}=\frac{2-5}{4-7}=-1\\m_{\overline{BC}}=\frac{2-2}{9-4}=0\)

This means that:

\(\tan \left(\angle ABC \right)=\left| \frac{-1-0}{1-(0)(-1)} \right|\\\tan \left(\angle ABC \right)=1\)

As \(\angle ABC\) is acute, this means \(m\angle ABC=\boxed{45^{\circ}}\)

You add 7 to 1/3 and that gives 22/3

Given: A three-digit number is to be made using 1, 3, 5, and 8

To Determine: How many numbers can be made if repeated digits are allowed

If repeated digits are allowed, we would suggest with replacement.

Then we would have 4 options for the first digit,

4 options for the 2nd digit,

and 4 options for the 3rd digit

This can be represented as:

Hence, the total number that would be made if repeated digits were allowed is 64

True, While "-1000 2/3" is not a real fraction, it can be represented as the improper fraction -2998/3.

The statement "-1000 2/3 is not a real fraction" is true. A real fraction is a mathematical expression that represents a ratio of two real numbers. In a fraction, the numerator and denominator are both real numbers, and they can be positive, negative, or zero.

In the given statement, "-1000 2/3" is not a valid representation of a fraction. The presence of a space between "-1000" and "2/3" suggests that they are separate entities rather than being part of a single fraction.

To represent a mixed number (a whole number combined with a fraction), a space or a plus sign is typically used between the whole number and the fraction. For example, a valid representation of a mixed number would be "-1000 2/3" or "-1000 + 2/3". However, without the proper formatting, "-1000 2/3" is not considered a real fraction.

It's important to note that "-1000 2/3" can still be expressed as an improper fraction. To convert it into an improper fraction, we multiply the whole number (-1000) by the denominator of the fraction (3) and add the numerator (2). The result would be (-1000 * 3 + 2) / 3 = (-3000 + 2) / 3 = -2998/3.

In conclusion, while "-1000 2/3" is not a real fraction, it can be represented as the improper fraction -2998/3.

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Answer:

1 the first

Step-by-step explanation:

I'm not sure

The average rate of change over is 1.

Given that;

the function is,

⇒ g (t) = - (t - 1)² + 5

Hence, We need to determine the average rate of change over the interval - 4 ≤ t ≤ 5.

The value of G(-4):

The value of G(-4) can be determined by substituting t = -4 in the function

⇒ g (t) = - (t - 1)² + 5

Thus, we have,

⇒ g (t) = - (-4 - 1)² + 5

⇒ g (t) = - 20

Thus, the value of G(-4) = -20

The value of G(5):

The value of G(5) can be determined by substituting t = 5 in the function , we get,

⇒ g (t) = - (t - 1)² + 5

⇒ g (t) = - (5 - 1)² + 5

⇒ g (t) = - 11

Thus, the value of G(5) is, -11

Now, Average rate of change:

The average rate of change can be determined using the formula,

⇒ G(b) - G (a) / (b - a)

where, a = - 4 and b = 5

Substituting the values, we get,

⇒ G(5) - G (-4) / (5 - (-4))

⇒ ( - 11 - (- 20)) / 9

⇒ 9/9

⇒ 1

Thus, the average rate of change over the interval is. 1.

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Answer:

90%

Step-by-step explanation:

72/80=0.9 so as a percentage that would be 90%

There are 51 metal benches in the park

According to the question we have been given that

   Number of wooden benches = 24

We have to calculate number of metal benches.

Let the number metal benches be x.

The according to the question

     W = x - 27 where, W = wooden benches

Here , W = 24

Putting the required in the above equation for x we get

  24 = x - 27

x = 24 + 27

 x = 51

Hence the number of metal benches = 51 and we can see that 27 less of metal benches is 24 which is the number of wooden benches.

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Answer:

100°

Step-by-step explanation:

The sum of all the angles of a kite is 360°.

So:

360-(124+36)

=200

∠s = 200/2

    =100°

Hope this helped lol

Answer:

6.7 * 10^7

Step-by-step explanation:

Step 1: We have the following equation:

3(x - 5) = 5x - (3 - x)

Step 2: Solve the parentheses

3x - 15 = 5x - 3 + x

Step 3: Like terms

3x - 5x -x = - 3 + 15

-3x = 12

Step 4: Dividing by -3 at both sides

-3x/-3 = 12/-3

x = -4

Step 5: Let's prove the answer is correct

3 (-4 - 5) = 5 * -4 - (3 - -4)

3 (-9) = -20 -3 - 4

-27 = - 27

The solution is correct

Answer:

Step-by-step explanation:

To find the limit of (n!)^(1/n) as n approaches infinity, we can use the Stirling's approximation for n!, which is:

n! ≈ (n/e)^n √(2πn)

where e is the mathematical constant e ≈ 2.71828, and π is the mathematical constant pi ≈ 3.14159.

Using this approximation, we can rewrite (n!)^(1/n) as:

(n!)^(1/n) = [(n/e)^n √(2πn)]^(1/n) = (n/e)^(n/n) [√(2πn)]^(1/n)

Taking the limit as n approaches infinity, we have:

lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n)

Using the fact that lim a^(1/n) = 1 as n approaches infinity for any constant a > 0, we can simplify the second term as:

lim [√(2πn)]^(1/n) = 1

For the first term, we can rewrite (n/e)^(n/n) as [1/(e^(1/n))]^n and use the fact that lim a^n = 1 as n approaches infinity for any constant 0 < a < 1. Thus, we have:

lim (n/e)^(n/n) = lim [1/(e^(1/n))]^n = 1

Therefore, combining the two terms, we have:

lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n) = 1 x 1 = 1

Hence, the limit of (n!)^(1/n) as n approaches infinity is 1.

Answer:1

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

The exponent is the top number, which in this case would be 8.

Answer:

169.83

Step-by-step explanation:

big brain

9514 1404 393

Answer:

Step-by-step explanation:

a) The down payment is 9.5% of the price, so is ...

  down = 0.095×$214,000 = $20,330

__

b) The amount of the loan is the remaining value after the down payment is made:

  $214,000 -20,330 = $193,670

__

c) The monthly payment is given by the amortization formula:

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

payment on Principal P at interest rate r for t years

  A = $193,670(0.0115/12)/(1 -(1 +0.0115/12)^(-12·35)) ≈ $560.35

__

d) The total cost of the house is ...

  down + (monthly payment)×(number of months)

  = $20,330 + $560.35×420

  = $255,677

Answer:

green line or "b"

Step-by-step explanation:

we can set this up into the slope intercept form

y=mx+b

where m is the slope and b is y intercept

12=3x+4y

-3x -3x

-3x+12=4y

/4.  /4.  /4

-3/4x+3=y

we can see the only line with a negative slope and a y intercept at 3 is the green line or "b"

hopes this helps please mark rainliest

The unknown length x is given as follows:

x = 6.

The geometric mean theorem states that  length of the altitude drawn from the vertex of the right angle of the right triangle to its hypotenuse is the geometric mean between the measures of the two segments of the hypotenuse.

The two segments have the lengths given as follows:

4 and 9.

The altitude is of x, hence it is given as follows:

x² = 36

x = sqrt(36)

x = 6.

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When x is equal to 1, the Function f(x) = -4x - 5 yields a value of -9.

The find ƒ(1) for the function f(x) = -4x - 5, we need to substitute x = 1 into the function and evaluate the expression.

Replacing x with 1, we have:

ƒ(1) = -4(1) - 5

Simplifying further:

ƒ(1) = -4 - 5

ƒ(1) = -9

Therefore, when x is equal to 1, the value of the function f(x) = -4x - 5 is ƒ(1) = -9.

Let's break down the steps taken to arrive at the solution:

1. Start with the function f(x) = -4x - 5.

2. Replace x with 1 in the function.

3. Evaluate the expression by performing the necessary operations.

4. Simplify the expression to obtain the final result.

In this case, substituting x = 1 into the function f(x) = -4x - 5 gives us ƒ(1) = -9 as the output.

It is essential to note that the notation ƒ(1) represents the value of the function ƒ(x) when x is equal to 1. It signifies evaluating the function at a specific input value, which, in this case, is 1.

Thus, when x is equal to 1, the function f(x) = -4x - 5 yields a value of -9.

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(i)  \(\lim_{x \to \frac{\pi^-}{2}}\) h(x) = 3

(ii) \(\lim_{x \to \frac{\pi^+}{2}}\) h(x) = -1

(iii) h(0) = 1/7

The value of λ must be 7, for h(x) to be continuous at x = 0.

The given function is,

h(x) = 1/7, when x = 0

      = 1 - 2 cos 2x, when x < π/2

      = 1 + 2 cos 2x, when x > π/2

      = x cos x/sin λx, when x < 0

Now,

(i) \(\lim_{x \to \frac{\pi^-}{2}}\) h(x) = \(\lim_{x \to \frac{\pi^-}{2}}\) (1 - 2 cos 2x) = 1 - 2 cos π = 1 + 2 = 3

(ii) \(\lim_{x \to \frac{\pi^+}{2}}\) h(x) = \(\lim_{x \to \frac{\pi^+}{2}}\) (1 + 2 cos 2x) = 1 + 2 cos π = 1 - 2 = -1

(iii) h(0) = 1/7

Since the function is continuous at x = 0, so

\(\lim_{x \to 0}\) h(x) = h(0)

\(\lim_{x \to 0}\) x cos x/sin λx = 1/7

\(\lim_{x \to 0}\) cos x.\(\lim_{x \to 0}\) 1/λ(sinλx/λx) = 1/7

1/λ = 1/7

λ = 7

Hence the value of λ must be 7.

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Answer:

What do you need help with mate?

Step-by-step explanation:

you don't have a question posted.

Given:

points (8,4) and (10,8)

Using the distance formula, and the given two points, we have the following:

The family  can spend 1 hour on the trampoline and 2 hours in the pool and the inequalities are 10t + 5p ≤ 25  and t + p < 4.

a ) Let the time on the trampolines  = t  

           10t + 5p ≤ 25

            t + p < 4

b )No, the family cannot  spend 1 hour in the trampoline and 3 hours in the pool.

c ) No, the family cannot  spend 2 hours in the trampoline and 1.5 hours in the pool.

         10t + 5p ≤ 25

         10(2)+ 5(1.5) = 27.5

d ) Yes, the  family  can spend 1 hour on the trampoline and 2 hours in the pool.

        10t + 5p ≤ 25

        10(1)+ 5(2) = 20

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Answer:

p/4

Step-by-step explanation:

You have p amount of peanuts and 4 baseball fans, so you divide p among 4, which is p/4

Answer: its p/10

Step-by-step explanation: i just did it

Answer:

theres no photo :))) btw God bless you

Answer:

AUB={1,2,3,4,5,7,8,9}

ALL THE NUMBERS WITHOUT REPEATING

AnB={5}

THE NUMBER THE HAVE IN COMMON

(AnB)n(BnC)={5}not too sure

CUD={1,3,6,7,8,10}

a rectangle

Quadrliaterals which have 4 right angles are squares and rectangles.

The 4 sides of the a square are equal. Hence, it cannot be a square.

Properties of a rectangle:

- It has 4 right angles

- the opposite sides are parallel

- the opposite sides are congruent

- diagonals are congruent

The quadrilateral which fits the desciption in the question is a rectangle.

Along with proof of (a.) and (d.), (b.) Power tower: one level is a, (k + 1) levels is a raised to the power of a power tower with k levels, (c.) A(2, n) <= 2 ↑↑ n for all positive integers n, where ↑↑ denotes power tower notation.

The idea of a fully computable function that is not primitive recursive is illustrated by the recursively constructed mathematical function known as the Ackermann function. Since m and n are non-negative integers, it is commonly written as A(m, n).

a.) Prove using regular induction that \(A(1, n) \leq 2^n\) for all positive integers n:

Base Case: For n = 1, A(1, 1) = 2, which is equal to \(2^1\).

Inductive Hypothesis: Assume that \(A(1, k) \leq 2^k\) for some positive integer k.

Inductive Step: We need to show that \(A(1, k + 1) \leq 2^{(k + 1)}\). Using the recursive definition of A(m, n), we have \(A(1, k + 1) = A(0, A(1, k)) = 2^{(A(1, k))}\leq 2^{(2^k)}\) (by inductive hypothesis)\(< = 2^{(2^{(k + 1)})}\).

Therefore, by regular induction, we have proved that \(A(1, n) \leq 2^n\) for all positive integers n.

b.) A power tower with one level is defined as a, and a power tower with (k + 1) levels is defined as a raised to the power of a power tower with k levels.

c.) \(A(2, n) \leq 2\) ↑↑ n for all positive integers n, where ↑↑ denotes power tower notation.

d.) The recursive definition of a triple arrow-up notation for power towers is:

a ↑↑↑ 1 = a (base case)

a ↑↑↑ (k + 1) = a ↑↑ (a ↑↑↑ k) (recursive step)

This definition states that a triple arrow-up notation with one level is equal to the base value "a", and a triple arrow-up notation with (k + 1) levels is equal to "a" raised to the power of a triple arrow-up notation with "k" levels.

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Complete Question: ( Refer to image)

The reduction in inventory should be entered as a credit in the given journal entry so it looks like :

Date           Account            Account         Number        Debit     Credit

1 - Oct        Inventory                1020                                           $ 26, 000

Inventory refers to the goods and materials that a company holds for sale or use in the normal course of business. Inventory is usually credited when it is sold by a company to another company.

This represents a reduction in inventory. The exact timing of when inventory is credited depends on the accounting method used by the company. But for this company, whenever they do credit it, the inventory is to be credited by $ 26, 000.

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Answer:

True,

Definition of equation for you: a statement that the values of two mathematical expressions are equal (indicated by the sign =).