now describe the relationship between the force and the electric field. again, how are they related conceptually and mathematically?

Answer:

a weak interaction between particles the result from mass

Answer:

sequence

Explanation:

sequences are the way in which things are ordered, for example: 1, 2, 3, 4 is a sequence:)

Answer:

10m/s

Explanation:

Data

mass=55kg, Maximum height (h1) =10m

Height reached when going down (h2)= 5m

final velocity (v)=?

At Maximum height the velocity is zero

hence intial velocity is 0m/s

The change in Potential energy = change in kinetic energy

mgh1-mgh2=1/2mv²-1/2mu²

But (u)= 0m/s

mgh2-mgh1=1/2mv²

mg(h1-h2)=1/2mv²

2g(h1-h2)=v²

v²=2(10m/s²)(10m-5m)

v²=100m²/s³

v=10m/s

The magnitude of the current in the second wire is 2.4 A, if the magnetic field strength is found to be zero between the two wires at a distance of 2.9cm from the first wire.

When two parallel wires are present, and a current flows in one wire, then it produces a magnetic field around it. The magnetic field created by one wire affects the magnetic field produced by another wire. Due to the magnetic field interaction, a force is created between the wires. If the magnetic field strength between the wires is zero, then it means the magnetic fields of the wires cancel out.

Using Biot-Savart law, the magnetic field produced by the first wire is given by:

B₁ = μ₀I₁/2πd

where μ₀ is the magnetic constant, I₁ is the current in the first wire, and d is the distance between the two wires.

The direction of the magnetic field is perpendicular to the plane of the current and a circular path around the wire. If two parallel wires carry current in the same direction, they attract each other, and if the current is in the opposite direction, they repel each other.

As the magnetic field strength is zero between the wires at a distance of 2.9 cm from the first wire, the magnitude of the magnetic field produced by the second wire is given by:

B₂ = μ₀I₂/2πd

At the point where the magnetic field strength is zero, the sum of the two magnetic fields is zero.

Hence, we can write:

B₁ + B₂ = 0

μ₀I₁/2πd + μ₀I₂/2πd = 0

(μ₀/2πd) (I₁ + I₂) = 0

I₁ + I₂ = 0

I₂ = -I₁

I₂ = -2.4 A

I₂ has a magnitude of 2.4 A and is flowing in the opposite direction of the first wire.

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The maximum height travelled by the ball before returning to the ground is 8.62 m.

The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.

H = (u²sin²θ) / 2g

where;

H = (26² (sin 30)²) / (2 x 9.8)

H = 8.62 m

Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.

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The parts found in an electric generator for the conversion of electric energy into other forms of energy such as mechanical or chemical energy are an armature, a permanent magnet, an electromagnet brushes, and slip rings.

An electric generator is a device that converts motive power into electric power for use in an external circuit.

Parts of electric generators include the following;

These parts of electric generator helps in the generation of electricity or conversion of electric energy into mechanical energy or light energy or chemical energy.

Thus, the parts found in an electric generator for the conversion of electric energy into other forms of energy such as mechanical or chemical energy are an armature, a permanent magnet, an electromagnet brushes, and slip rings.

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Answer:

armature

permanent magnet

electromagnet

brushes

slip rings

Explanation:

edge 2022-2023

The mass of the whole cookie is not directly important to this experiment.

In this experiment, the key variables involved are the rate of acceleration/deceleration and the time it takes for the train or cookie to reach certain speeds or come to a stop.

These variables depend on factors such as the applied force and the friction between the train or cookie and its surroundings. The mass of the whole cookie itself does not directly affect these variables.

However, it is worth noting that the mass of the cookie could indirectly influence the frictional forces or the force required to accelerate or decelerate the cookie, depending on the specific conditions and setup of the experiment.

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The time taken for the radioactive material to decay from 400 counts per sec to 50 counts per sec is 3 years.

We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 400 count per sec

Amount remaining (N) = 50 count per sec

Number of half-lives (n) =?

N × 2ⁿ = N₀

50 × 2ⁿ = 400

Divide both side by 50

2ⁿ = 400 / 50

2ⁿ = 8

2ⁿ = 2^3

n = 3

Thus, 3 half-lives has elapsed

Finally, we shall determine the time taken for the radioactive material to reduce to 50 counts per sec. This can be obtained as follow;

Number of half-lives (n) = 3

Half-life (t½) = 1600 years

Time (t) =?

t = n × t½

t = 3 × 50,457,600,000 seconds

t = 151,372,800,000 seconds = 3 years

Therefore, it will take 3 years for the radioactive material to decay to 50 counts per second.

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To Make I the subject you need to get it by itself. To do this divide both sides by V and t:

I = E/Vt

2.1831 N-m work is done by the student to raise a textbook of 5.7kg to a distance of 38.3cm.

The amount of work done by the student on the book can be calculated using the formula W = F x d, where W is the work, F is the force, and d is the distance.

In this case, the force is equal to the weight of the book, 5.7 kg,

and the distance the book raised is = 38.3 cm.

Using the formula, the work done is \(W = 5.7 kg * 38.3 * 10^{-2}m\)

W = 2.1831 N-m.

This means that the student did 2.1831 N-m of work to raise the book a distance of 38.3 cm.

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Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].

CR​ < CY​ < CB​

The factors which affect the critical angle are

(a) The colour (or wavelength) of light

(b) The temperature

(i) Effect of colour of light: The critical angle for a pair of media is less for the violet light and more for the red light. Thus the critical angle increases with the increase in wavelength of light.

(ii) Effect of temperature: The critical angle increases with increase in temperature because on increasing temperature of medium, its refractive index decreases.

According to the question,

μ 1​ sinCR​ =1

μ 2​ sinCY =1

μ 3​ sinCB​ =1

μ 1​ > μ 2​  and μ 2​ > μ 3

⟹μ 1​ > μ 2​ > μ 3

CR​ < CY​ < CB​

Thus,

The critical angle increases with the increase in wavelength of light.

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Radioactivity is a part of our earth - it has existed all along. Naturally occurring radioactive materials are present in its crust, the floors and walls of our homes, schools, or offices and in the food we eat and drink. There are radioactive gases in the air we breathe. Our own bodies - muscles, bones, and tissue - contain naturally occurring radioactive elements.

75km=75000m

35min=2100 seconds

Velocity=Displacement/Time

=75000/2100

=750/21

=35.71 m/s

If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.

It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.

Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.

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(a) A concave mirror is a converging element.

(b) Light is observed to converge to a point after being reflected from a plane mirror. The incident rays were converging before striking the mirror.

(a) A concave mirror is a converging element. It has a curved surface that reflects light rays inward, causing them to converge at a single point known as the focal point. This makes concave mirrors useful for applications like focusing light or creating magnified images in telescopes and makeup mirrors.

(b) In the case of a plane mirror, when light rays converge to a point after being reflected, it indicates that the incident rays were converging before striking the mirror. This is because plane mirrors only change the direction of light rays without altering their paths relative to each other. If the incident rays were parallel or diverging, they would maintain their parallel or diverging nature after reflection.

Here is a simple diagram to illustrate this:
```
Incident rays:       /   \
                   /     \
Plane mirror: ------------
Reflected rays:     \     /
                     \ /
```

In the diagram, the incident rays are converging before striking the plane mirror, and after reflection, they continue to converge to a point.

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Answer:

C. A baseball bat strikes a baseball.

Explanation:

Newton's second law of motion states that acceleration happens when force is applied on the mass.

A baseball bat strikes a baseball is the best example of Newton's second law of motion because acceleration of the baseball is directly proportional to the force by which baseball bat hit it.

Hence, the correct option is 'C. A baseball bat strikes a baseball.'

Answer:

Baseball bla

Explanation:

yes

Answer:That depends on whether both people are pulling in the same direction against a fixed object or pulling against each other. If pulling in the same direction, the total force is 300 N + 300 N = 600 N. If the two people are pulling against each other, the total force is 300 N in the rope is 300 N, or a net of zero.

Explanation:.

A football workout involves two linemen who are pushing on the coach and the sled. The sled and the coach's combined mass is 300 kg, while the coefficient of friction between the sled and the grass is .800. The sled accelerates at a rate of .580 m/s/s. We need to determine the force applied to the sled by the linemen.

The total force acting on the sled is:Force = Mass × AccelerationF = 300 kg × .580 m/s/s = 174 NSince the sled and the grass's coefficient of friction are known, we can determine the force applied to the sled by the linemen using the following equation:

Frictional Force = Coefficient of Friction × Normal Force

The normal force is equal to the weight of the sled and the coach. Thus,Normal Force = Mass × GravityN = 300 kg × 9.81 m/s/s = 2943 NFrictional Force = .800 × 2943 N = 2354.4 NThe force applied to the sled by the linemen is the difference between the total force acting on the sled and the frictional force.

Force Applied by Linemen = Total Force − Frictional ForceF = 174 N − 2354.4 N = −2180.4 NThe linemen are exerting a force of −2180.4 N on the sled in the opposite direction to the sled's movement. This is because the frictional force is greater than the total force acting on the sled.

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Answer:

The reason you feel weightless is because there is no force pushing against you, since you are not in contact with anything. Gravity is pulling equally on all the particles in your body. This creates a sensation where no forces are acting on you and you feel weightless.

The direction of the force on a current carrying wire located in an external magnetic field. The correct answer is c. Both choices A and B are valid.

According to the right-hand rule, when a current-carrying wire is placed in an external magnetic field, the direction of the force on the wire is perpendicular to both the current and the magnetic field. This means that the force is perpendicular to the direction of the current flow in the wire as well as the direction of the magnetic field lines. The force on the wire is a result of the interaction between the magnetic field and the moving charges in the wire. The magnetic field exerts a force on the charges, causing the wire to experience a mechanical force. The magnitude and direction of this force can be determined using the right-hand rule. When the wire is perpendicular to the magnetic field, the force will be the strongest. If the wire is parallel or antiparallel to the magnetic field, the force will be zero. The direction of the force can be determined by using the right-hand rule, where the thumb points in the direction of the current, the fingers point in the direction of the magnetic field, and the palm indicates the direction of the force. Therefore, the force on a current-carrying wire located in an external magnetic field is both perpendicular to the current and perpendicular to the magnetic field, making choice c, "Both choices A and B are valid," the correct answer.

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327 degrees

Have a great day!

Here, we are required to determine which chemical formula is the product of the reaction between CaO and C02 given that matter is neither created nor destroyed.

The chemical formula of the product of this reaction is ; CaCO3.

The law of conservation of mass is the basis for the balancing of equations of chemical reactions.

The law states that matter( which is the building block of mass) can neither be created nor destroyed.

Therefore, in a reaction where one molecule of calcium oxide, CaO, and one molecule of carbon dioxide, CO2, combine in a chemical reaction to form one substance;

The chemical formula of the product of this reaction is ; CaCO3.

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Answer:

63.2N

Explanation:

\(Solution,\\\\Mass(m)=39.5kg\\\\\\Gravity(g)=1.6m/s^{2} \\Now,\\\\Weight -on- moon=m*g=39.5*1.6m/s^{2} =63.2N\)

When you are halfway around the stadium, average speed value cannot be 0.

Average speed = Total distance travelled / Time taken.

Since you ran halfway across the stadium, a certain amount of distance has been covered. The only way the average speed can be zero is if you remained stationary over a given interval of time.

In a distance-time graph, at the halfway point in the stadium, slope is equal to zero. So, Instantaneous speed is zero. In a Velocity-time graph, at the halfway point in the stadium, slope is equal to zero. So, Instantaneous acceleration is zero. In a Velocity ( w.r.t. time )-time graph, at the halfway point in the stadium, slope is equal to zero. So, Average acceleration is zero.

Therefore, when you are halfway around the stadium, average speed value cannot be 0.

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The Sammie is speaking with a sound intensity of 10⁻⁴ watts/m²  . the dB intensity level of Sammie's voice is 80 dB.

given that :

The sound intensity = 10⁻⁴ watts/m²

The intensity level of sound , L = 10 log ( I / Io) dB

where ,

I = 10⁻⁴  watts/m²

Io = 10⁻¹² watts/m²

therefore,

L = 10 log ( I / Io) dB

L = 10 log ( 10⁻⁴  watts/m² / 10⁻¹² watts/m² ) dB

L = 10 log ( 10⁸) dB

L = 10 × 8 dB

L = 80 dB

Thus, the  intensity level of sound is 80 dB.

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Answer:

time is 3 seconds.

Explanation:

formula is given in the picture

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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