Keshawn's age is 8, and since Alexa's age is consecutive and even, her age would be 8 + 2 = 10.
What is consecutive even integers?
Cοnsecutive even integers are even integers that fοllοw each οther by a difference οf 2. If x is an even integer, then x + 2, x + 4, x + 6 and x + 8 are cοnsecutive even integers.
Let's assume that Keshawn's age is represented by the variable x. Since their ages are consecutive even integers, Alexa's age would be x + 2.
According to the given information, the sum of the square of Alexa's age and 5 times Keshawn's age is 140. We can express this information in an equation:
(x + 2)² + 5x = 140
Expanding the square term:
x² + 4x + 4 + 5x = 140
Combining like terms:
x² + 9x + 4 = 140
Moving all terms to one side of the equation:
x² + 9x + 4 - 140 = 0
Simplifying:
x² + 9x - 136 = 0
To solve this quadratic equation, we can factor it or use the quadratic formula. Let's use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
For our equation, a = 1, b = 9, and c = -136. Plugging these values into the formula:
x = (-9 ± √(9² - 4 * 1 * -136)) / (2 * 1)
Simplifying further:
x = (-9 ± √(81 + 544)) / 2
x = (-9 ± √625) / 2
x = (-9 ± 25) / 2
We have two possible solutions:
1. x = (-9 + 25) / 2 = 8
2. x = (-9 - 25) / 2 = -17
Since age cannot be negative, we disregard the second solution.
Therefore, Keshawn's age is 8, and since Alexa's age is consecutive and even, her age would be 8 + 2 = 10.
Alexa's age is 10.
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Write an quation of a line that passes through the point (1,-10) and is perpendicular to y= -1/3x+5
Answer:
y=3x-13
Step-by-step explanation:
because it is perpendicular to y=-1/3x+5 the gradient is 3.
so, so far for the line you are working out you have y=3x+c
now substitute the points(1,-10) into this equation
so... -10=3 times 1 +c
which gives
-10=3+c
now solve to get c
so...-10-3=c
-13=c
so the equation of the line is ...y=3x-13
Each histogram represents a set of data with a median of 29.5. Which set of data most likely has a mean that is closest to 29.5?
A graph shows the horizontal axis numbered 9 to 48. The vertical axis is numbered 1 to 5. The graph shows an upward trend from 1 to 33 then a downward trend from 33 to 45.
A graph shows the horizontal axis numbered 15 to 48. The vertical axis is numbered 1 to 5. The graph shows an upward trend from 1 to 30 then a downward trend from 30 to 45.
A graph shows the horizontal axis numbered 12 to 56. The vertical axis is numbered 2 to 8. The graph shows an upward trend from 1 to 32 then a downward trend from 32 to 56.
A graph shows the horizontal axis numbered 15 to 54. The vertical axis is numbered 1 to 5. The graph shows an upward trend from 1 to 24, a downward trend from 24 to 27, an upward trend from 27 to 30, a downward trend from 30 to 39, an upward trend from 39 to 45, a downward trend from 45 to 48, then an upward trend from 48 to 51.
To determine which set of data most likely has a mean closest to 29.5, we need to analyze the shape and position of the histograms in relation to the value 29.5.
Looking at the histograms described:
The first histogram ranges from 9 to 48, and the upward trend starts from 1 and ends at 33, followed by a downward trend. This histogram suggests that there may be values lower than 29.5, which would bring the mean below 29.5.
The second histogram ranges from 15 to 48, with an upward trend from 1 to 30 and then a downward trend. Similar to the first histogram, it suggests the possibility of values lower than 29.5, indicating a mean below 29.5.
The third histogram ranges from 12 to 56, and the upward trend starts from 1 and ends at 32, followed by a downward trend. This histogram covers a wider range but still suggests the possibility of values below 29.5, indicating a mean below 29.5.
The fourth histogram ranges from 15 to 54 and exhibits multiple trends. While it has fluctuations, it covers a wider range and includes both upward and downward trends. This histogram suggests the possibility of values above and below 29.5, potentially resulting in a mean closer to 29.5.
Based on the descriptions, the fourth histogram, with its more varied trends and wider range, is most likely to have a mean closest to 29.5.
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The distance between two locations on a map is 6 centimeters (cm). If 1 cm on the map corresponds to an actual distance of 15 miles,
what is the actual distance, in miles, between the two locations?
04
Answer:
Step-by-step explanation:
6x15=90
90miles
How do you simplify (1/8)^(4/3) ?
Answer:
1/16
Step-by-step explanation:
Rational Exponents can be rewritten as Radicals:
\((\frac{1}{8})^{\frac{4}{3}}=\sqrt[3]{\frac{1}{8}}^{4}\)
Take the cube root of 1/8 = 1/2.
Raise (1/2) to the 4th power
Step-by-step explanation:
the numerator (top part) of a fractional exponent means "to the power of ...".
the denominator (bottom part) of a fractional exponent means "the ...th root".
so,
(1/8)^(4/3) means the cubic root of 1/8 to the power of 4.
these 2 operations can be done in any sequence.
it is the same if we first put 1/8 to the power of 4 and then get the cubic root, or if we first get the cubic root of 1/8 and then put that result to the power of 4.
to keep the numbers small, I prefer here to start with the cubic root :
cubic root (8) = 2, because 2³ = 8.
and so, cubic root (1/8) = 1/2
(1/2)⁴ = 1/16
that's it.
(1/8)^(4/3) = 1/16
we say that four circles have an intersection point at p if at least two of the circles intersect at p. what is the greatest possible number of intersection points of four circles of different sizes
The greatest possible number of intersection points for four circles of different sizes is 12.
The greatest possible number of intersection points of four circles of different sizes can be calculated by considering the maximum number of intersection points each pair of circles can have and then summing them up.
When two circles intersect, they can have a maximum of two intersection points. So, if we have four circles, we can find the maximum number of intersection points by considering each pair of circles separately.
For the first circle, it can intersect with the other three circles at most two times each, giving us a total of 2 * 3 = 6 intersection points.
For the second circle, it can intersect with the remaining two circles at most two times each, giving us a total of 2 * 2 = 4 intersection points.
The third circle can intersect with the last remaining circle at most two times, giving us a total of 2 * 1 = 2 intersection points.
Finally, the fourth circle doesn't have any other circle left to intersect with, so it doesn't contribute any additional intersection points.
Now, we can sum up the intersection points from each pair of circles: 6 + 4 + 2 + 0 = 12.
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I need help asap please all you have to do is find x and complete the maze please help me
Answer:
10, 8, -9, 5, 11, 3, -5, 9, 7 and finally -7
How many packs of DVD's can you buy with one hundred twelve dollars if one pack costs fourteen dollars ?
Answer:
8 packs
Step-by-step explanation:
112/14=8
When Ford had to pull their national campaign, this was particularly disheartening as their media planners and buyers had spent a great deal of time considering the myriad of advertising outlets available to them and determining which outlets would be best to place their buys in. This best describes which media challenge faced by media planners and buyers today? O increasing audience fragmentation O increasing media options O increasing behavioral targeting O increasing costs O increasing competition
The media challenge faced in the scenario is increasing audience fragmentation.
What do you mean by the term Selling price?The cost price is abbreviated as C.P. The price at which an article is sold is known as its selling price. The selling price is abbreviated as S.P.It is a price above the cost price and includes a percentage of profit also.
The media challenge described in the scenario is increasing audience fragmentation. Audience fragmentation occurs when there are numerous media options available, and consumers have different preferences and behaviors regarding media consumption. This makes it challenging for media planners and buyers to identify the most effective media outlets to reach their target audience. In the case of Ford, their media planners and buyers had put a lot of effort into selecting the best media outlets, but still had to pull their campaign due to the challenges posed by audience fragmentation. Therefore, the media challenge faced in the scenario is increasing audience fragmentation.
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Abigail’s parents pay her $5 an hour for weeding the yard and pay her little sister $3 an hour for raking leaves.
Write an expression in two different ways to represent the amount their parents will pay Abigail and her sister for working the same number of hours
I dont get help me
Answer: (MAKE ME BRAINLIST PLEASE)
Answer: For Abigail W = $5t
For her younger sibling W= $3t
Bit by bit clarification:
How about we address the compensation with W
t as the time spent on work in hours
Abigail will be paid $5 every hour, her all out compensation will be
W(abg) = $5t
Her younger sibling will be paid $3 every hour, her complete compensation will be
W(lts) = $3t
Help me out please and thank you
Answer:
I got B
75+20+85=180
which number has which number has the lowest value? 1/6 1/3 - 1/9 1/3 - 1/6 1/4 - 1/6the lowest value?
the fraction with the lowest value is 1/12.
Company revenue quadratic function.
Angel
The revenue, in billions of dollars, for a company in the year 2002 was $2.7 billion. One year later, in 2003, the revenue had risen to $3.4 billion. In 2005, the revenue climbed to $3.9 billion, before falling to $2.7 billion in 2008. The revenue, r, in billions of dollars, for the company, is a quadratic function of the number of years since 2002, x. what is the vertex of the function?
To find the quadratic function that represents the revenue of the company as a function of the number of years since 2002, we can use the vertex form of a quadratic function:
r(x) = a(x - h)^2 + k
where a is the coefficient of the quadratic term, h is the x-coordinate of the vertex, and k is the y-coordinate of the vertex.
We can use the given revenue values to set up a system of three equations:
2.7 = a(0 - h)^2 + k
3.4 = a(1 - h)^2 + k
2.7 = a(6 - h)^2 + k
Subtracting the first equation from the second, and the first equation from the third, we get:
0.7 = a(1 - h)^2
0 = a(6 - h)^2
Since a cannot be zero (otherwise we wouldn't have a quadratic function), we can divide the second equation by the first to get:
6 - h = 10
which gives us h = -4.
Substituting h = -4 into the first equation, we get:
2.7 = a(0 - (-4))^2 + k
2.7 = 16a + k
Substituting the revenue value for 2005, we get:
3.9 = a(3 - (-4))^2 + k
3.9 = 49a + k
Solving for a and k, we get:
a = -0.1
k = 4.3
Therefore, the quadratic function that represents the revenue of the company as a function of the number of years since 2002 is:
r(x) = -0.1(x + 4)^2 + 4.3
The vertex of this function is at (-4, 4.3).
Angel
What is the sum of the numbers in the sequence 3, −4, 5, −6, . . . , 101?
We can notice that the sequence alternates between adding an odd number and subtracting an even number. The first term is 3, which is odd, so the sequence starts by adding an odd number. The second term is -4, which is even, so the sequence then subtracts an even number. This pattern continues, so the sum of the sequence can be written as:
3 - 4 + 5 - 6 + ... + 101
We can group the terms into pairs:
(3 - 4) + (5 - 6) + ... + (99 - 100) + 101
Each pair of terms adds up to -1, so we can simplify the expression to:
-1 -1 -1 ... -1 + 101
where there are 50 pairs of -1's. The sum of 50 -1's is -50, so the sum of the sequence is:
-50 + 101 = 51
Therefore, the sum of the numbers in the sequence 3, −4, 5, −6, . . . , 101 is 51.
Angel
What is 12 7/8 - 56/17?
To subtract mixed numbers like 12 7/8, we first need to convert it to an improper fraction. We can do this by multiplying the whole number by the denominator of the fraction, and adding the result to the numerator. This gives us:
12 7/8 = (12 × 8 + 7)/8 = 103/8
Now we can subtract 56/17 from 103/8. To do this, we need to find a common denominator for the two fractions. The least common multiple of 8 and 17 is 136, so we can rewrite the fractions with this denominator:
103/8 = (103/8) × (17/17) = 1751/136
56/17 = (56/17) × (8/8) = 448/136
Now we can subtract the two fractions:
1751/136 - 448/136 = (1751 - 448)/136 = 1303/136
We can simplify this fraction by finding a common factor to divide both the numerator and denominator. Since both 1303 and 136 are relatively prime, we cannot simplify it any further. Therefore, the final answer is:
12 7/8 - 56/17 = 1303/136
Angel
A circle in the xy-plane has a diameter with endpoints (2,4) and (2,14). An equation of this circle is (x-2)^2+(y-9)^2=r^2 ,where r is a positive constant. What is the value of r?
The center of the circle is the midpoint of the diameter, which is at (2, (4+14)/2) = (2, 9). We can substitute this center point into the equation of the circle to get:
(x - 2)^2 + (y - 9)^2 = r^2
(2 - 2)^2 + (9 - 9)^2 = r^2
0 + 0 = r^2
So we see that r = 0. Therefore, the equation of the circle is just:
(x - 2)^2 + (y - 9)^2 = 0
This describes a single point in the xy-plane, which is the center of the circle. Note that this point is already on the given diameter, so it makes sense that the radius is zero.
Angel
which number has which number has the lowest value? 1/6 1/3 - 1/9 1/3 - 1/6 1/4 - 1/6the lowest value?
To compare these fractions, we can first find a common denominator for all of them. The least common multiple of 2, 3, and 4 is 12, so we can rewrite the fractions with this denominator:
1/6 = 2/12
1/3 - 1/9 = (3/12) - (1/12) = 2/12
1/3 - 1/6 = (2/6) - (1/6) = 1/6
1/4 - 1/6 = (3/12) - (2/12) = 1/12
So the fractions can be ordered as follows, from least to greatest:
1/12 < 1/6 < 2/12 = 1/3 - 1/9 < 1/3 - 1/6
Therefore, the fraction with the lowest value is 1/12.
Find the slope of the line ( 4,5) (-3,1)
Point 1: (-3 , -1) x1=-3 y1= -1
Point 2: ( 4, 5) x2= 4 y2= 5
To find the slope of the line use the formula \(\frac{y2-y1}{x2-x1}\)
\(\frac{y2-y1}{x2-x1}\) Insert Values
\(\frac{5-(-1)}{4-(-3)}\) Remove Brackets
\(\frac{5+1}{4+3}\) Simplify
\(\frac{6}{7}\)
The slope is \(\frac{6}{7}\)
Now you will find the percent survival of each of your eight clients to the end of his or her policy using the simulation in the spreadsheet. for each potential client, you will see whether he or she would be alive at the end of his or her policy. the cells in the spreadsheet that you should look at to determine this are highlighted in yellow. next, go to the worksheet labeled task 2b and record either alive or dead for the first trial. once you do this, the all column will say yes if all the clients were alive at the end of their policies or no if all the clients were not alive at the end of their policies. were all the clients alive at the end of their policies in the first trial?
In the first trial of the simulation, the question asks whether all the clients were alive at the end of their policies. The answer to this question can be found in the "All" column of the worksheet labeled "Task 2b."
To determine whether all the clients were alive at the end of their policies in the first trial, we need to refer to the "All" column in the "Task 2b" worksheet. This column indicates whether all the clients were alive or not at the end of their policies for each trial. If the "All" column says "Yes," it means all the clients were alive at the end of their policies in that trial. If it says "No," it means at least one client was not alive at the end of their policy in that trial.
To answer the specific question about the first trial, we need to refer to the corresponding row in the "All" column. If the first trial's row in the "All" column says "Yes," it means all the clients were alive at the end of their policies in the first trial. If it says "No," it means at least one client was not alive at the end of their policy in the first trial.
Without access to the specific spreadsheet and data, I am unable to provide a definitive answer about the clients' status in the first trial.
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Solve the equation for u.
Uw + uq=r
Answer:
u = \(\frac{r}{w+q}\)
Step-by-step explanation:
Given
uw + uq = r ← factor out u from each term on the left side
u(w + q) = r ← divide both sides by (w + q)
u = \(\frac{r}{w+q}\)
The equation uw + uq = r is solved for u will be written as u = r / (w + q).
What is the solution to the equation?The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.
The equation is given below.
uw + uq = r
Simplify the equation for u, then the equation will be written as,
uw + uq = r
u(w + q) = r
u = r / (w + q)
The equation uw + uq = r is solved for u will be written as u = r / (w + q).
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determine the angle of rotation at the point z0 = 2 i when w = z 2
The angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\)\) is \(\(2\arctan(2)\),\) which is approximately 1.107 radians or 63.43 degrees.
To determine the angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\),\) we can follow these steps:
1. Express \(\(z_0\)\) in polar form: To find the polar form of \(\(z_0\)\), we need to calculate its magnitude \((\(r_0\))\) and argument \((\(\theta_0\))\). The magnitude can be obtained using the formula \(\(r_0 = |z_0| = \sqrt{\text{Re}(z_0)^2 + \text{Im}(z_0)^2}\)\):
\(\[r_0 = |2i + 1| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}\]\)
The argument \(\(\theta_0\)\) can be found using the formula \(\(\theta_0 = \text{arg}(z_0) = \arctan\left(\frac{\text{Im}(z_0)}{\text{Re}(z_0)}\right)\)\):
\(\[\theta_0 = \text{arg}(2i + 1) = \arctan\left(\frac{2}{1}\right) = \arctan(2)\]\)
2. Find the polar form of \(\(w\)\): The polar form of \(w\) can be expressed as \(\(w = |w|e^{i\theta}\)\), where \(\(|w|\)\) is the magnitude of \(\(|w|\)\) and \(\(\theta\)\) is its argument. Since \((w = z^2\)\), we can substitute z with \(\(z_0\)\) and calculate the polar form of \(\(w_0\)\)using the values we obtained earlier for \(\(z_0\)\):
\(\[w_0 = |z_0|^2e^{2i\theta_0} = \sqrt{5}^2e^{2i\arctan(2)} = 5e^{2i\arctan(2)}\]\)
3. Determine the argument of \(\(w_0\):\) To find the argument \(\(\theta_w\)\) of \(\(w_0\)\), we can simply multiply the exponent of \(e\) by 2:
\(\[\theta_w = 2\theta_0 = 2\arctan(2)\]\)= 1.107 radians
Therefore, the angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\)\) is \(\(2\arctan(2)\).\)
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The complete question is:
"Determine the angle of rotation, in radians and degrees, at the point z0 = 2i + 1 when w = z^2."
if c= what is the value of a?
Answer:
a= 17√3/ 2 or a≈14.72
Step-by-step explanation:
c = 17 and is the side opposite to the angle C
c=AB =17
a= BC because is the side opposite to angle A
sin 60° = opp./hyp = BC / AB = BC/17
sin 60° = BC /17 multiply both sides by 17
BC = 17* sin 60 = 17√3/2 ≈14.72
Solve for the letter A
Answer:
a=bcd
Step-by-step explanation:
Answer:
a=bcd
Step-by-step explanation:
Let's solve for a.
a
dc
=b
Step 1: Multiply both sides by cd.
a=bcd
Answer:
a=bcd
What is the median of the following numbers?
6,4, 1,9,3,8,3,5, 10
Median = 5
Mean = 5.4444444444444
Mode: 3
Range = 9
Minimum = 1
Maximum = 10
How to find Median:
Arrange your numbers in numerical order. Then the second step is to have an odd number, divide by 2 and round up to get the position of the median number. The last step is to find the even number and if you have it, divide it by 2.
Answer: 5
Hope this helps.
In ΔBCD, \text{m}\angle B = (5x+14)^{\circ}m∠B=(5x+14)
∘
, \text{m}\angle C = (x+19)^{\circ}m∠C=(x+19)
∘
, and \text{m}\angle D = (2x+19)^{\circ}m∠D=(2x+19)
∘
. What is the value of x?x?
Answer:
x = 16
Step-by-step explanation:
m<B+m<C+m<D = 180°
5x + 14 + x + 19 + 2x + 19 = 180
8x + 52 = 180
8x = 180 - 52
x = 128/8
x = 16
The length of a rectangle is represented by the function L(x) = 2x. The width of that same rectangle is represented by the function W(x) = 8x2 − 4x + 1. Which of the following shows the area of the rectangle in terms of x?
(L + W)(x) = 8x2 − 2x + 1
(L + W)(x) = 8x2 − 6x + 1
(L ⋅ W)(x) = 16x3 − 4x + 1
(L ⋅ W)(x) = 16x3 − 8x2 + 2x
Answer:
Step-by-step explanation:
The area of a rectangle is given by the product of its length and width. Therefore, the area of the rectangle is:
A(x) = L(x) ⋅ W(x) = 2x(8x^2 - 4x + 1)
Simplifying the expression, we get:
A(x) = 16x^3 - 8x^2 + 2x
Therefore, the answer is (D) (L ⋅ W)(x) = 16x3 − 8x2 + 2x.
Given h(x)=-x-4, find h (-6)
The required solution is 2.
It is required to find the value of h (-6).
What is function?A function is defined as a relation between a set of inputs having one output each. function is a relationship between inputs where each input is related to exactly one output. Every function has a domain and codomain or range. A function is generally denoted by f(x) where x is the input.
Solution:
The given equation is
h(x)= -x-4
We have to find h (-6)
By put the value of x=-6 in given equation we get,
h(-6) = -(-6)-4
h(-6) = 6-4
h(-6) = 2
Hence. the required solution is 2.
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a polynomial of degree four with leading coefficient 1 and integer coefficients has two real zeros, both of which are integers. which of the following can also be a zero of the polynomial? A. 1+i√11/2B. 1+i/2C. 1/2+iD. 1+i/2E. 1+i√13/2
If we let a = 0, b = 1, and c = 1, then the polynomial
\(x(x-1)(x^2 +\)
Since the polynomial has integer coefficients, if one of the roots is a complex number, then its conjugate must also be a root. Therefore, options A and E cannot be roots of the polynomial, since they have non-real conjugates.
We know that the polynomial has degree 4, so it has four roots in total (counting multiplicities). We also know that two of the roots are integers, so let's call them a and b. Then the polynomial can be written as:
\((x - a)(x - b)(cx^2 + dx + e)\)
where c, d, and e are integers (because they are the coefficients of the quadratic factor). We know that the leading coefficient is 1, so c must be nonzero.
Since the polynomial has two real roots, its discriminant must be nonnegative:
\(d^2 - 4ce > = 0\)
We can use this inequality to rule out some of the answer choices. For example, option C cannot be a root, because if we substitute x = 1/2 + i into the polynomial, we get:
(\((1/2 + i) - a)((1/2 + i) - b)(c((1/2 + i)^2) + d(1/2 + i) + e)\)
The real part of this expression is:
(1/4 - a + 1/4 - b)(c(1/4 - 1) + d/2 + e) = -(a + b - 1/2)(3c/4 + d/2 + e)
If we assume that a and b are integers, then this expression is an integer multiple of 3c/4 + d/2 + e. However, we can choose values of c, d, and e such that 3c/4 + d/2 + e is not an integer (for example, if c = 4, d = 1, and e = 0, then 3c/4 + d/2 + e = 4.5). Therefore, the real part of the expression cannot be zero, and option C cannot be a root.
We can also rule out option D using the same argument. If we substitute x = 1 + i/2, then the real part of the expression is:
((1 + i/2) - a)((1 + i/2) - b)(c((1 + i/2)^2) + d(1 + i/2) + e)
(1 - a + i/2)(1 - b + i/2)(c(5/4 + i) + d(3/2 + i/2) + e)
The real part of this expression is an integer multiple of c(5/4) + d(3/2) + e, which can be non-integer for some choices of c, d, and e.
Therefore, the only possible answer choices are A and B. To determine whether they are roots of the polynomial, we can use the fact that the sum and product of the roots are given by:
a + b + (complex roots) = -d/c
ab(complex roots) = e/c
We know that a and b are integers, so if we can find a polynomial with integer coefficients that has roots a, b, and either A or B, then that root is also a root of the original polynomial.
For option A, we have:
1 + i√11/2 = 2(cos(75°) + i sin(75°))
Therefore, if we let a = 0, b = 1, and c = 1, then the polynomial
\(x(x-1)(x^2 +\)
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3. A train travels 20 km at a uniform speed of 60 km/h and the next 20 km at a uniform speed of 80km/h. Calculate its average speed.
Answer:
Given,
Distance traveled = 20 km
Speed = 60 km/h
So, timetaken=DistanceSpeed=2060=13h
For the next journey
Distance traveled = 20 km
Speed = 80 km/h
So, timetaken=DistanceSpeed=2080=14h
Now,
Total distance traveled = 20 + 20 = 40 km
Total time taken = 13+14=712
We know,
Averagespeed=TotaldistancetraveledTotaltimetaken=40712=68.5 km/h
Hence the average speed of the train is 68.5 km/h
Please Help! After reading equation of the line from the graphing utility, Heather wrote in her notebook that the line of best fit is represented by the equation y = 0.77x + 1.34.
Answer:
The correct options are;
Heather likely did not make an error writing the equation of the line in her notebook because 0.77 and 1.34 are the slope y-intercept of the equation she recorded
Step-by-step explanation:
Based on the coordinates on the plot, Heather did not make a mistake in writing the line of best fit as the graph plotted with the points in the question figure as follows;
x, y
10.6, 9.4
8.2, 8.2
6.4, 7.3
6.6, 5.8
4.4, 5.4
4, 3.4
2.5, 4.4
2.2, 3
0.85, 1.5
Has an equation of he form, y = 0.7885·x + 1.3694.
The sum of two positive numbers is 16. What is the optimum value (maximum or minimum) for the sum of their squares?
\(x=8\) and \(y=8\) are the two positive integers whose sum is \(16\) and sum of their squares is minimum.
What is optimum value ?
The optimum value is a minimum or maximum value of the objective function over the feasible region of an optimization problem.
If a function is strictly increasing in a definite interval and increases up to a fixed value and after this, it starts decreasing, then that point is called maximum point of the function and value of function at that point is called maximum value.
If a function is strictly decreasing in a definite interval and decreases up to a fixed value and after this, it starts increasing, then that points is called minimum point of the function and the value of function at that point is called minimum value.
Conditions for finding maxima and minima
The conditions for maxima and minima for a function \(y=f(x)\) at a point \(x=a\) are as follow:
1. Necessary condition
for maxima and minima, the necessary condition is
\(f'(x)=\frac{dy}{dx}\)
2.Suffiecient condition
for maxima and minima, the necessary condition are
for maximum value
at \(x=a,\frac{d^2y}{dx^2}\) should be negative.
for minimum value
at \(x=a, \frac{d^2y}{dx^2}\) should be positive.
The sum of two positive number is \(16\).
We have to find the maximum and minimum value for the sum of their squares.
The sum of two positive number is 16.
let the number be \(x\) and \(y\), such that \(x > 0\) and \(y > 0\)
sum of the number is \(x+y=16\)
sum of squares of the number \(S=x^2+y^2\)
\(x+y=16\\y=16-x ----------1\\S=x^2+y^2\\S=x^2+(16-x)^2-----------2\)after substituting the value of y from equation 1
for finding the maximum and minimum of given function we can find it by differentiating the function with \(x\) equal it to \(0\)
Differentiate the equation 2
\(\frac{dS}{dx} =\frac{d}{dx}[x^2+(16-x)^2]\\\frac{dS}{dx}=\frac{d}{dx}(x^2)+\frac{d}{dx}(16-x^2)\\ \frac{dS}{dx}=2x+2(16-x)(-1)---------3\)
Now equating the first derivative equal to zero
so, \(\frac{dS}{dx}=0\)
\(2x+2(16-x)(-1)=0\\2x-2(16-x)=0\\2x-32+2x=0\\4x-32=0\\4x=32\\x=\frac{32}{4}=8\)
As \(x > 0, x=8\)
Now, for checking if the value of \(S\) is minimum or maximum at \(x=8\), we will perform the second derivative of \(S\) with respect to \(x\)
\(\frac{d^2S}{dx^2}=\frac{d}{dx}[2x+2(16-x)(-1)]\\\frac{d^2S}{dx^2}=\frac{d}{dx}[2x-2(16-x)]\\\frac{d^2S}{dx^2}=\frac{d}{dx}(2x)-2\frac{d}{dx}(16-x)\\\frac{d^2S}{dx^2}=2-2(0-1)\\\frac{d^2S}{dx^2}=2-0+2=4\\\frac{d^2S}{dx^2}=4\)
According to the sufficient condition if the second derivative is positive then the value is minimum
hence for \(x=8\) will be the minimum point of the function \(S\).
Therefore the function \(S\) sum of squares of the two number is minimum at \(x=8\)
from equation \(1\)
\(y=16-x\\y=16-8\\y=8\)
Therefore , \(x=8\) and \(y=8\) are the two positive numbers whose sum is \(16\) and the sum of their squares is minimum.
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Louise buys 4 pencils for £1.20. How much does one cost? :)
Answer:
O.3 pound
Step-by-step explanation:
1.20/4=0.3 pound
Answer:
1.20 divided 4 = 0.3
One pencil costs £0.3
Step-by-step explanation:
When considering stand-alone risk, the return distribution of a less risky investment is more placed ("tighter") than that of a riskier investment. What shape would the return distribution have for an investment witha) completely certain returns andb) completely uncertain returns?
For an investment with completely certain returns, the return distribution would be a very tight, vertical line at the predetermined return. This is because the risk associated with the investment is zero, meaning the return will not vary regardless of market conditions.
For an investment with completely uncertain returns, the return distribution would be a flat line with no particular shape. This is because the risk associated with the investment is very high, meaning the return could be anything, as it is impossible to predict the returns with any degree of accuracy.
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a radial saw has a circular cutting blade with a diameter of 10 inches and it spins at 2000rpm if there are 12 cutting teeth per inch on the cutting blade how many teeth cross the cutting surface each second
The number of teeth that cross the cutting surface each second is 12560 teeth.
A radial saw has a circular cutting blade with a diameter of 10 inches and it spins at 2000rpm if there are 12 cutting teeth per inch on the cutting blade, the number of teeth that cross the cutting surface each second can be calculated as follows:First, let us find the circumference of the circular cutting blade: $C = πd$ where d is the diameter of the blade.Circumference of blade $C = πd=π×10=31.4 inches$.To find the number of teeth crossing the cutting surface each second, we need to find the linear speed of the cutting edge of the blade. Linear speed is the distance traveled per unit time.Linear speed = Circumference of blade × RPM = 31.4 × 2000 = 62,800 inches per minute.To find the speed in seconds, we divide by 60. Speed in seconds = 62,800 / 60 = 1046.67 inches/second.There are 12 teeth per inch on the cutting blade. Therefore, the number of teeth that cross the cutting surface each second is:1046.67 inches/second × 12 teeth per inch = 12560 teeth per second. Thus, the number of teeth that cross the cutting surface each second is 12560 teeth.
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I need help with this I don’t know how to find the Discriminant or the Nature of the root
The roots of the quadratic equation \(3x^{2} -4x+2 = 0\) as shown is imaginary.
What is the term discriminant?In mathematics, we use the term discriminant to explain the formula that can be used to show the nature of the roots of quadratic equation. In this case, we want to use the discriminant to test the roots of the equation; 3x^2 - 4x + 2 = 0
Now, the discriminant is;
√b^2 - 4ac
b = (-4)
a = 3
c = 2
Then we try to substitute and obtain;
√ (-4)^2 - 4 * 3 * 2
√16 - 24
√-8
Hence the roots of the equation are imaginary.
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Definition: This is a decimal number which never ends, but whose digits after the decimal point come in a predictable pattern. Example: 5.32
Answer:
the answer is repeating
Step-by-step explanation:
I hope this helps you :)
Answer: Repeating decimal
Step-by-step explanation: