Advertisements on the internet, television, and radio try to get you to buy something by making a claim or statement. These claims will often sound scientific. However, many advertisements make statements or conclusions that are not entirely true. Advertisements sometimes exaggerate, which means they make a statement that a product is or does more than is actually true.

When deciding if an advertisement is true, look for other data that supports these claims. The data should come from peer-reviewed journals or trusted science textbooks.

Research a product you see advertised. What claim does it make? Does other scientific data support this claim? Decide if the claim is factual, fictional, or an exaggeration. List your sources to show your inference.

Answer:

hello hope this helps :)

a pure substance consists only of one element or one compound. a mixture consists of two or more different substances, not chemically joined together.

Explanation:

Answer:

4.35 mL

Explanation:

The water line falls halfway inbetween the 4.4 and 4.3 mark.

The number halfway between 4.3 and 4.4 is 4.35.

Therefore, the volume of the liquid in the graduated cylinder is 4.35 mL.

Answer:

21

Explanation:

To find the total atoms.

Multiply 3 *2 and you will get 6

Then multiply 3 * 5 and you will get 15.

You do this because there is 3 as a coefficient and is before the chemical compound. Furthermore, that means the same thing as a parenthesis.

Last of all, add 15 + 6 and you will get 21.

Therefore, there are a total of 21 atoms.

The oxidation number of reactant Fe is 0 while the  oxidation number of iron in the product is +3

The term redox reaction implies a reaction in which there is an increase in the oxidation number of a specie and the decrease in the oxidation number of another specie.

Now we have the answers as follows;

1) The oxidation number of reactant Fe is 0

2) The oxidation number of reactant oxygen is 0

3) The oxidation number of iron in the product is +3

4) The oxidation number of oxygen in the product is -2

5). Iron is oxidized in the reaction

6) Oxygen is reduced in the reaction

7) The oxidizing agent in this case is the oxygen atom

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The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)

In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.

The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.

The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.

In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.

It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.

Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.

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Answer:

The concentration of the nitric acid (HNO3) solution is 72 M.

Explanation:

To determine the concentration of the nitric acid solution, we can use the concept of stoichiometry and the equation of the neutralization reaction between nitric acid (HNO3) and sodium hydroxide (NaOH):

HNO3 + NaOH → NaNO3 + H2O

The balanced equation shows that the molar ratio between HNO3 and NaOH is 1:1. This means that 1 mole of HNO3 reacts with 1 mole of NaOH.

Given:

Volume of HNO3 solution = 10.0 ml

Volume of NaOH solution = 3.6 ml

Molarity of NaOH solution = 0.2 M

To find the concentration of the HNO3 solution, we need to calculate the number of moles of NaOH used in the neutralization reaction:

moles of NaOH = volume of NaOH solution * molarity of NaOH solution

= 3.6 ml * 0.2 M

= 0.72 mmol (millimoles)

Since the molar ratio between HNO3 and NaOH is 1:1, the number of moles of HNO3 in the solution is also 0.72 mmol.

Now, we can calculate the concentration of the HNO3 solution using the formula:

concentration (in M) = moles of solute / volume of solution (in L)

concentration = 0.72 mmol / 0.010 L

= 72 mmol/L

= 72 M

Therefore, the concentration of the nitric acid (HNO3) solution is 72 M.

Answer:

\(\boxed {\boxed {\sf 0.0455 \ L}}\)

Explanation:

We are asked to calculate the liters given the molarity and moles in a solution.

Molarity is a measure of concentration in moles per liter. It is calculated with the following solution:

\(molarity= \frac{moles \ of \ solute}{liters \ of \ solution}\)

The molarity of the solution is 4.40 molar of potassium chloride (KCl). 1 molar is equal to 1 mole per liter, so the molarity is also 4.40 moles of potassium chloride per liter. There are 0.200 moles of potassium chloride or solute. The liters of solution is unknown, so we can use the variable x.

\(4.40 \ mol \ KCl/ L = \frac{ 0.200 \ mol \ KCl}{x}\)

Since we are solving for x, we must isolate the variable. First, cross multiply. Multiply the first numerator by the second denominator, then the first denominator and the second numerator.

\(\frac {4.40 \ mol \ KCl/ L}{1} = \frac{ 0.200 \ mol \ KCl}{x}\)

\(4.40 \ mol \ KCl / L * x= 1 * 0.200 \ mol \ KCl\)

\(4.40 \ mol \ KCl / L * x= 0.200 \ mol \ KCl\)

x is being multiplied by 4.40 moles of potassium chloride per liter. The inverse operation of multiplication is division. Divide both sides by 4.40 mol KCl/L

\(\frac {4.40 \ mol \ KCl / L * x}{4.40 \ mol \ KCl / L}= \frac {0.200 \ mol \ KCl}{{4.40 \ mol \ KCl / L}}\)

\(x= \frac {0.200 \ mol \ KCl}{{4.40 \ mol \ KCl / L}}\)

The units of moles of potassium chloride cancel.

\(x= \frac {0.200}{{4.40 L}}\)

\(x= 0.0454545454545 \ L\)

The original measurements of liters and moles have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ten-thousandth place (0.0454545454545). The 5 to the right of this place (0.0454545454545) tells us to round the 4 up to a 5.

\(x \approx 0.455 \ L\)

There are approximately 0.455 liters in a 4.40 molar solution with 0.200 moles of solute.

Based on the given bright-line spectra and the observed wavelengths in the mixture's spectrum, the elements G and J are the ones present in the mixture.

From the given bright-line spectra and the spectrum of the mixture, we can determine the elements present in the mixture by comparing the specific wavelengths observed. Examining the bright-line spectra, we can identify that G has a distinct wavelength at 650 nm, J at 600 nm, L at 550 nm, and M at 500 nm.

Looking at the spectrum of the mixture, we can observe two prominent wavelengths, 650 nm and 600 nm. These correspond to the wavelengths of G and J, respectively. Since the spectrum of the mixture does not exhibit the wavelengths specific to L (550 nm) or M (500 nm), we can conclude that only G and J are present in the mixture.

Therefore, based on the given bright-line spectra and the observed wavelengths in the mixture's spectrum, the elements G and J are the ones present in the mixture.

This analysis relies on the principle that each element has characteristic wavelengths at which they emit light. By comparing the observed wavelengths in the mixture's spectrum with those of the individual elements, we can determine the elements present in the mixture.

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Answer:

the answer woul be 89 if you do the math right

Explanation:

Oxygen is in group 6 and has 6 valence electrons.

What is meant by electrons?

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Braxtons dog eats 3 times more than Abbys

Answer:

Braxton's dog eats 3 times more food.

Explanation:

Plasmids help you obtain the copies of the gene you need.

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We are told that the entire packet contains 8 servings, each serving weighs 42 grams. These 42 grams of a portion of flatbread are equivalent to 19 grams, of these 19 grams 12 are dietary fiber and 2 grams of sugar alcohol.

If we subtract the types of carbs we will have:

19g-12g-2g= 5g.

The net carb means the number of carbohydrates in a food that your body can digest and use for energy.

Dietary fiber and sugar alcohol can not be digested, so we don't count these carbs. Therefore the net carbs will be 5g, as the packet says.

Answer: There are 5g of net carbs per serving

Answer:

The answer to your question is given below

Explanation:

We'll begin by converting 500 cm³ to L. This can be obtained as follow:

1000 cm³ = 1 L

Therefore,

500 cm³ = 500 cm³× 1 L / 1000 cm³

500 cm³ = 0.5 L

Next, we shall determine the number of mole of Na₂CO₃ in the solution. This can be obtained as follow:

Volume = 0.5 L

Molarity = 2 M

Mole of Na₂CO₃ =?

Molarity = mole /Volume

2 = Mole of Na₂CO₃ / 0.5

Cross multiply

Mole of Na₂CO₃ = 2 × 0.5

Mole of Na₂CO₃ = 1 mole

Finally, we shall determine the mass of 1 mole of Na₂CO₃. This can be obtained as follow:

Mole of Na₂CO₃ = 1 mole

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mass of Na₂CO₃ =?

Mass = mole × molar mass

Mass of Na₂CO₃ = 1 × 106

Mass of Na₂CO₃ = 106 g

Thus, to prepare the solution, weigh 106 g of Na₂CO₃ and dissolve in 500 cm³ (i.e 0.5 L) of water.

Answer:

0.15 moles of sodium hydroxide are in the solution.

Explanation:

Molarity is a unit for expressing concentration of solutions. Molarity is defined as the number of moles of solute per liter of solution.

The molarity of a solution is calculated by dividing the moles of the solute by the liters of the solution:

\(Molarity (M)=\frac{number of moles of solute}{volume}\)

Molarity is expressed in units (\(\frac{moles}{liter}\)).

So, a molarity of 0.750 M indicates that 0.750 moles are present in 1 L of solution. Then the following rule of three can be applied: if in 1000 mL (being 1 L = 1000 mL) there are 0.750 moles, in 200 mL how many moles are there?

\(amount of moles=\frac{200 mL*0.750 moles}{1000 mL}\)

amount of moles=0.15

0.15 moles of sodium hydroxide are in the solution.

The amount of moles of sodium hydroxide (NaOH) in 200.0 mL of a 0.750 M sodium hydroxide solution is 0.15 moles.

HOW TO CALCULATE NUMBER OF MOLES:

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The heat released by each molecule, in joules, when ethanol undergoes complete  combustion is 2.28 × \(10^-18\) J.

The number of moles in 1.00 g  of ethanol is obtained from;

Mass of ethanol/molar mass of ethanol

Molar mass of ethanol = 46.07 g/mol

Number of moles =  1.00 g/46.07 g/mol = 0.022 moles of ethanol

1 mole of ethanol contains 6.022 × \(10^23\) molecules

0.022 moles of ethanol contains  0.022 moles ×  6.022 × \(10^23\) molecules/1 mole

=  1.32 × \(10^22\) molecules of ethanol

If 1.32 × \(10^22\) molecules of ethanol release  29.8 × \(10^3\) J of heat

1 molecule of ethanol will release 1 molecule × 29.8 × 10^3 J / 1.32 × \(10^22\)

=  2.28 × \(10^-18\) J

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Answer:

a. pentane = C5H12

b. Heptane = C7H16

c. Hexyne = C6H10

d. Octene = C8H16

e. Nonane = C9H20

Hope it helps.

1-pentene

Molecular Formula C5H10

Condensed Structural FormulaCH2=CH(CH2)2CH3

Melting Point (°C)–138

Boiling Point (°C)30

2- heptane is the straight-chain alkane with the chemical formula H3C(CH2)5CH3 or C7H16, and is one of the main components of gasoline (petrol).

Number of half-lives is 3

The decay of this radioactive unknown compound is a first-order process.

We can express the time dependence of its mass m using a first-order integrated rate law, where k is the rate constant:

mt = mass at time t

m0 = initial mass

t = time

Procedure:

1) We need to find "k":

From the first-order rate law we clear k,

\(\frac{mt}{mo} = e^{-kxt}\)

㏑\((\frac{mt}{mo})= -kxt\)

\(\frac{ln(\frac{mt}{mo}) }{-t} = k\)

\(k=\frac{ln(\frac{65.59ng}{ 524.7 ng} )}{-47 }\)

k = 0.044\(days^{-1}\)

2) We find the half-life from the value of k we have just calculated:

\(t\frac{1}{2}\) =\(\frac{ln2}{k}\) = 15.7days

3) The number of half-lives of the unknown sample is:

Number of Half-lives = 47 days / 15.7 days = 3 (approx.)

Hence 3 is a correct answer.

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Answer:

To calculate original weight - multiply by 2 the number of times one half live has passed.

12 x 2 = 24

24 x 2 = 48

48 x 2 = 96

96 x 2 = 192

original weight = 192g

In the balanced equation \(2C_{2} H_{6}\) + \(7 O_{2}\) --> \(4 CO_{2}\) + \(6H_{2}O\) if 21 g of \(C_{2} H_{6}\) reacts with 32 g O₂, C₂H6 is the limiting reactant.

To determine the limiting reactant, we need to compare the amount of each reactant to the stoichiometric ratio in the balanced equation.

Let's calculate the number of moles for each reactant using their molar masses:

For \(C_{2} H_{6}\) (ethane):

Molar mass of \(C_{2} H_{6}\) = 2(12.01 g/mol) + 6(1.01 g/mol) = 30.07 g/mol

Number of moles of C₂H6 = 21 g / 30.07 g/mol ≈ 0.698 mol

For O₂ (oxygen):

Molar mass of O₂ = 2(16.00 g/mol) = 32.00 g/mol

Number of moles of O₂ = 32 g / 32.00 g/mol = 1.00 mol

Next, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation:

2 moles of \(C_{2} H_{6}\) react with 7 moles of O₂ to produce 4 moles of CO₂ and 6 moles of H₂O.

From the given amounts, we have:

0.698 mol \(C_{2} H_{6}\) and 1.00 mol O₂.

Using the stoichiometric ratio, we can calculate the expected amount of CO₂ and H₂O produced for each reactant:

For C₂H6:

Expected moles of CO₂ = 0.698 mol C₂H6 * (4 mol CO₂ / 2 mol C₂H6) = 1.396 mol CO₂

For O₂:

Expected moles of CO₂ = 1.00 mol O₂ * (4 mol CO₂ / 7 mol O₂) ≈ 0.571 mol CO₂

Comparing the expected moles, we see that the calculated amount of CO₂ is greater when used \(C_{2} H_{6}\) as the limiting reactant. Therefore, the limiting reactant in this reaction is \(C_{2} H_{6}\).

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Answer: 1. halve

2. halve

3. double

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

\(E=\frac{hc}{\lambda}\)

E= energy

\(\lambda \) = wavelength of the wave

h = Planck's constant  

c = speed of light

Thus as wavelength and energy have inverse realation, when wavelength will halve , energy will double.

2. The between wavenumber and energy of the wave follows the equation:

\(E=h\times c\times \bar{\nu}\)

E= energy

\(\bar{\nu}\)\(\nubar\) = wavenumber of the wave

h = Planck's constant  

c = speed of light

Thus as wavenumber and energy have direct relation, when wavenumber will halve , energy will be halved.

3. The relationship between energy and frequency of the wave follows the equation:

\(E=h\times \nu\)

where

E = energy

h = Planck's constant  

\(\nu\) = frequency of the wave

Thus as frequency and energy have direct realation, when frequency will double , energy will double.

Answer:

171.34 g/mol

Explanation:

Ba molar mass = 137.328 g/mol

O molar mass = 15.999 g/mol * 2 = 31.9980 g/mol

H molar mass = 1.008 g/mol * 2 = 2.0160 g/mol

137.328 + 31.9980 + 2.0160 = 171.3420 = 171.34 g/mol

The theoretical yield of Fe is 335.1 g.

54.0 g of C is needed.

The volume of CO2 produced is 0.992 L.

198.05 g of CO2 was produced.

The percent yield of the reaction is 75.2%.

The balanced chemical equation for the reaction is:

2Fe2O3 + 3C → 4Fe + 3CO2

Using the equation, we can calculate the theoretical yield of Fe and the amount of C needed.

To calculate the theoretical yield of Fe:

Convert the given mass of Fe2O3 to moles:

480 g Fe2O3 x (1 mol Fe2O3/ 160 g Fe2O3) = 3.0 mol Fe2O3

Use stoichiometry to find the moles of Fe produced:

2 mol Fe2O3 → 4 mol Fe

3.0 mol Fe2O3 x (4 mol Fe / 2 mol Fe2O3) = 6.0 mol Fe

Convert moles of Fe to grams:

6.0 mol Fe x (55.85 g Fe / 1 mol Fe) = 335.1 g Fe

To calculate the amount of C needed:

Use stoichiometry to find the moles of C needed:

2 mol Fe2O3 → 3 mol C

3.0 mol Fe2O3 x (3 mol C / 2 mol Fe2O3) = 4.5 mol C

Convert moles of C to grams:

4.5 mol C x (12.01 g C / 1 mol C) = 54.0 g C

To find the volume of CO2 produced, we need to calculate the number of moles of CO2 produced using stoichiometry.

Use stoichiometry to find the moles of CO2 produced:

2 mol Fe2O3 → 3 mol CO2

3.0 mol Fe2O3 x (3 mol CO2 / 2 mol Fe2O3) = 4.5 mol CO2

Convert moles of CO2 to volume using the ideal gas law:

PV = nRT

V = nRT/P

V = (4.5 mol) (0.0821 L atm mol^-1 K^-1) (298 K) / (1 atm)

V = 0.992 L

To find the mass of CO2 produced:

Use the molar mass of CO2 to convert from moles to grams:

4.5 mol CO2 x (44.01 g CO2 / 1 mol CO2) = 198.05 g CO2

To calculate the percent yield of the reaction:

Use the given mass of Fe (252 g) and the theoretical yield of Fe (335.1 g) to calculate the percent yield:

Percent yield = (actual yield / theoretical yield) x 100%

Percent yield = (252 g / 335.1 g) x 100%

Percent yield = 75.2%

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Answer:

4.80×10³ years

Explanation:

Let the original amount (N₀) of ²²⁶Rn = 1 g

Therefore,

12.5% of the original amount = 12.5% × 1 = 12.5/100 × 1 = 0.125 g

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Original amount (N₀) = 1

Amount remaining (N) = 0.125 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

0.125 = 1/2ⁿ × 1

0.125 = 1/2ⁿ

Cross multiply

0.125 × 2ⁿ = 1

Divide both side by 0.125

2ⁿ = 1/0.125

2ⁿ = 8

Express 8 in index form with 2 as the base

2ⁿ = 2³

n = 3

Thus, 3 half-lives has elapsed.

Finally, we shall determine the time taken for only 12.5% of the original sample of ²²⁶Rn to remain.

This can be obtained as follow:

Half-life (t½) = 1.60×10³ years

Number of half-lives (n) = 3

Time (t) =?

t = n × t½

t = 3 × 1.60×10³

t = 4.80×10³ years.

Thus, it will take 4.80×10³ years for 12.5% of the original sample of ²²⁶Rn to remain.

Explanation:

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Answer:

(we use hess's law) it is so simple but the second reaction is not correct please right it

The "alum" used in cooking is potassium aluminum sulfate hydrate, KAl(SO4)2·x H2O and the value of x calculated is 12.

Alum is a type of chemical compound, usually hydrated double sulfate salt of aluminum having general formula X Al ₂·12 H ₂O, where X is  monovalent cation such as potassium or ammonium.

Given mass of KAl(SO₄)₂.XH₂O = 4.74 g

and mass of water = 2.16 g

So, mass of KAl(SO₄)₂ = 4.74 – 2.16 = 2.58 g

Molar mass of KAl(SO₄)₂ ;

= 39 + 27 + 2[32 + (4×26)]

Now, molar mass of KAl(SO₄)₂ = 258 g/mol

Molar mass of H₂O ;

= (2×1) + 16

Now, molar mass of H₂O = 18 g/mol

Hence, KAl(SO₄)₂ = 2.58 / 258 = 0.01

and H₂O = 2.16 / 18 = 0.12

KAl(SO₄)₂ = 0.01 / 0.01 = 1

H₂O = 0.12 / 0.01 = 12

The formula of the compound is obtained as KAl(SO₄)₂.12H₂O

Comparing KAl(SO₄)₂.12H₂O with KAl(SO₄)₂.XH₂O,  value of X is 12.

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The correct answer from the given four options is B: The equilibrium will shift to the left if sulfur trioxide is added to the system.

In chemistry, equilibrium refers to the state of a reversible reaction where the forward and reverse reactions occur at the same rate. In other words, the concentrations of reactants and products remain constant over time, and there is no net change in the amount of each substance. At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction, and the system is said to be in a dynamic state. Equilibrium is an important concept in many areas of chemistry, including acid-base reactions, solubility, and chemical kinetics.

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Answer:

x = (-4 + √30) / 2, or x = (-4 – √30) / 2

Explanation:

x = (-b ± √b² – 4ac) / 2a →

y = ax² + bx + c

given

y = 2x² + 8x – 7 →

x = (-(8) ± √(8)² – 4(2)(-7)) / 2(2) →

x = (-8 ± √64 + 56) / 4 →

x = (-8 ± √120) / 4 →

x = (-8 ± 2√30) / 4 →

x = (-4 ± √30) / 2 →

x = (-4 + √30) / 2, or x = (-4 – √30) / 2