Answer:
SMA= 24 degrees
Step-by-step explanation:
add the other given angles together: 66 + 90= 156
subtract 158 from 180 (every triangle has a total of 180 degrees): 180-156 = 24
Solve for x: -4x - 4 = -4(x + 2)
Oo
O-4
O All real numbers
O No solution
What is the circumference of the circle when there's a radius of 5
Find the value of C that completes the square for x^2-2x + C
Answer:
C = 1.
Step-by-step explanation:
x^2 - 2x = (x - 1)^2 - 1 so:
x^2 - 2x + C = (x - 1)^2 - 1 + C
So to get a perfect square C must be 1 ( as -1 + 1 = 0):-
(x - 1)^2 - 1 + 1 = (x - 1)^2
Checking this:
x^2 - 2x + 1
= (x - 1)(x - 1) which is a perfect square./
you are in a line at the bank drive-through and 8 cars are in front of you. you estimate that the clerk is taking about two minutes per car to serve. how long do you expect to wait in line?
After using the principle of multiplication for calculation. The total amount of time needed to wait in line is 16 minutes.
here,
We need to implement the principle of multiplication .So looking at the question it is given to us that there are 8 cars present in front at the bank drive-through, and the total time taken by the clerk is 2 minutes.
therefore,
Total time needed to wait in line is
= Number of cars in line * Time taken by the clerk
= 8 x 2
= 16 minutes
After using the principle of multiplication. The total amount of time needed to wait in line is 16 minutes.
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Solve the system of linear equations by elimination.
8x - 5y = 11
4x – 3y = 5
Find the missing side. Round to the nearest tenth.
Step-by-step explanation:
1. have info for adjacent side and hypotenuse
so use; cosine
cos32=x/19
x=cos32×19
=15.9
2. have info for opposite side and hypotenuse
so use; sine
sin63=16/x
x=16/sin63
=95.6
3. have info for opposite side and adjacent side
so use; tangent
tan26=17/x
x=17/tan26
=14.4
4. have info for opposite side and adjacent side
so use tangent
tan42= x/13
x=tan42×13
x=29.8
Water leaking onto a floor forms a circular pool. The circumference of the pool increases at a rate 24 cm/min. How fast is the area of the pool increasing when the radius is 5 cm
The area of the pool increasing at the rate of 753.98 cm²/min when the radius is 5 cm
How quickly does the pool's area grow when the radius is 5 cm?Given:
radius of the pool increases at a rate of 24 cm/min
To Find:
How quickly does the pool's area grow when the radius is 5 cm?
Solution:
we are given with the circular pool
hence the area of the circular pool =
A = πr²-----------------------------(1)
The area of the pool os increasing at the rate of 24 cm/min, meaning that the area of the pool is changing with respect to time t
so differentiating eq (1) with respect to t , we have
dA/dt =π 2r dr/dt
we have to find dA/dt with dr/dt = 24 cm/min and r = 5cm
substituting the values
dA/dt = π 2(5)24
dA/dt = π 26*8
dA/dt = π 240
dA/dt =240π
dA/dt = 753.98
The area of the pool increasing at the rate of 753.98 cm²/min when the radius is 5 cm
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4 ten and 17 hundredth in decimals UNSERIOUS ANSWERS REPORTED
Answer:
40.17
Step-by-step explanation:
4 ten: 4 × 10 = 40
17 hundredth: 17 × 0.01 = 0.17
4 ten and 17 hundredth in decimals: 40 + 0.17 = 40.17
you toss a fair coin 9 times. find the probability of no more than 8 heads given that at least one toss resulted in heads.
On tossing a fair coin 9 times, the probability of no more than 8 heads where at least one toss is heads would be 511/512.
What is Probability?The possibility of an event happening is gauged by probability. Many things are difficult to forecast with absolute confidence. We can only anticipate the likelihood of an event occurring using it. Probability can vary from 0 to 1, with 0 being an impossibility and 1 denoting a certainty. For pupils in Class 10, probability is a crucial subject since it teaches all the fundamental ideas of the subject. One is the probability of every event in a sample space.
How to solve?
total number of possibilities on tossing a coin 9 times= 2^9
number of ways to get all heads = 1/2^9
number of getting at most 8 heads = number of ways of getting one tail
= 1 - 1/2^9
=511/512
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E. Elementary Properties of Cosets
Let G be a group, and H a subgroup of G. Let a and b denote elements of G. Prove the following:
7. If J is a subgroup of G such that J = H ∩ K, then for any a ∈ G, Ja = Ha ∩ Ka. Conclude that if H and K are of finite index in G, then their intersection H ∩ K is also of finite index in Theorem 5 of this chapter has a useful converse, which is the following:
Cauchy’s theorem If G is a finite group, and p is a prime divisor of |G|, then G has an element of order p.
The property states that if J is a subgroup of G such that J = H ∩ K, then for any a ∈ G, Ja = Ha ∩ Ka. This implies that if H and K are subgroups of finite index in G, their intersection H ∩ K is also of finite index.
The property, we need to show that Ja = Ha ∩ Ka for any a ∈ G.
Let x ∈ Ja, then x = ja for some j ∈ J = H ∩ K. Since j ∈ H and j ∈ K, we have x = ja ∈ Ha and x = ja ∈ Ka, which implies that x ∈ Ha ∩ Ka. Hence, Ja ⊆ Ha ∩ Ka.
Conversely, let y ∈ Ha ∩ Ka. Then y ∈ Ha and y ∈ Ka, which means y = ha = ka for some h ∈ H and k ∈ K. Since j = h^-1k ∈ J = H ∩ K, we have y = ha = jk ∈ Ja. Therefore, Ha ∩ Ka ⊆ Ja.
Combining both inclusions, we conclude that Ja = Ha ∩ Ka for any a ∈ G.
Now, if H and K are of finite index in G, it means that both H and K have a finite number of distinct left cosets in G. Since their intersection H ∩ K is a subset of both H and K, it follows that H ∩ K also has a finite number of distinct left cosets in G. Therefore, H ∩ K is of finite index in G.
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what scale of measurement is used for the independent variable
The scale of measurement used for the independent variable in a research study is determined by the nature of the variable and the research question. The four scales of measurement are nominal, ordinal, interval, and ratio.
Nominal scales are used for variables that have no inherent order, such as gender or race. Ordinal scales are used for variables that have a specific order, but the difference between each value is not necessarily equal, such as education level or socioeconomic status. Interval scales are used for variables where the difference between each value is equal, but there is no true zero point, such as temperature or time. Ratio scales are used for variables where the difference between each value is equal, and there is a true zero point, such as weight or height.To know more about scale of measurement, visit:
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Which expression represents the second partial sum for...?
Answer:
c
Step-by-step explanation:
just took the quiz
Answer:
C
Step-by-step explanation:
Edge2021
Can I get help please
The amount of money that I will have at the end of 20 years would be =$4,480. That is option D
What is compound interest?Compound interest is defined as the interest that is being earned on an account which is based on the rate and the time the investment was made.
The total amount invested (p)= $2,000
The rate of investment (r) = 5%
The time of investment(t)= 12 year
The compound interest warm from that account;
= P×T×R/100.
= 2,000×12×5/100
= 120000/100
= $1200
For the next 8 years with the rate of 8% ;
= 2,000×8×8/100
= 128000/100
= $1280
The total compound interest = $1200+$1280= $2,480
Therefore, the amount of money that I will have at the end of 10 years would be = 2000+2480 = $4,480
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Mai spent $64 on fruit at the grocery store. She spent a total of $80 at the store. What percentage of the goal did she spend on fruit?
Answer:
80%
Step-by-step explanation:
64/80 = .8/1
multiply by a hundred and you get 80%
A population of bears is decreasing the population this year is 200 bears after 1 year it is estimated that the population will be 160 bears after 2 years it is estimated that the population will be 128 bears what equation describes the bear population in any year x?
Answer:
The equation is;
y = 200•0.8^x
where y is the number of bears remaining and x is the year number in particular
Step-by-step explanation:
Let us have the rate of decrease as r and we set up an exponential equation
y = I• ( 1 - r)^x
where r is the percentage decrease, I is the initial population = 200 and x is the number of years
For the population after 1 year, we have;
160 = 200( 1 -r)^x
divide both sides by 200
0.8 = (1-r)^1
0.8 = 1 - r
r = 1 - 0.8
r = 0.2
So the equation will be;
y = 200( 1 - 0.2)^x
y = 200•0.8^x
Find the slope of the lines graphed below.
Giving brainliest to whoever answers all correct.
Answer:
1.slope is 2
2.slope is -3/5
3.slope is 1
4.vertical line slope 0 undefined
5.x=-5
6.horizontal line slope 0 undefined
Step-by-step explanation:
Answer:
1) 2 2) -3/5 3) 1 4) Undefined 5) -5 6) 0
Step-by-step explanation:
8. Johnny trades a used laptop for a new model. The exchange lacks commercial substance. The used laptop has a book value of $1,000 (historical cost of $2.500 minus accumulated depreciation of $1,500) and a fair value of $1.200. The new model has a list price of $2,500. In addition to trading in the used laptop. Johnny must pay $800 cash in exchange for the new model.
What is the journal entry needed to record this transaction?
9. Barry trades newer used equipment for an older version of the same equipment. The exchange lacks commercial substance. The newer equipment that Barry trades away has a book value of $90,000 (historical cost of $140,000 minus accumulated depreciation of $50,000) and a fair value of $100,000. In addition to receiving the older equipment, Barry receives $20,000 in the exchange. What is the journal entry needed to record this transaction?
Therefore, The journal entry for Johnny to record this transaction is Debit: New laptop for $2,500, Credit: Used laptop for $1,000, Credit: Cash for $800, Credit: Gain on exchange for $700. The journal entry for Barry to record this transaction is: Debit: Old equipment for $120,000, Debit: Loss on exchange for $10,000, Credit: New equipment for $100,000, Credit: Cash for $20,000.
When a company exchanges an old model of a laptop for a new model, the exchange lacks commercial substance. Johnny traded a used laptop with a book value of $1,000 (historical cost of $2,500 minus accumulated depreciation of $1,500) and a fair value of $1.200 for a new laptop with a list price of $2,500. Johnny also needs to pay $800 cash to purchase the new model. The journal entry to record the transaction would be as follows:Debit: New laptop for $2,500Credit: Used laptop for $1,000Credit: Cash for $800Credit: Gain on exchange for $700 ($2,500 - $1,800)Barry trades newer used equipment for an older version of the same equipment that lacks commercial substance. The newer equipment that Barry trades away has a book value of $90,000 (historical cost of $140,000 minus accumulated depreciation of $50,000) and a fair value of $100,000. In addition to receiving the older equipment, Barry receives $20,000 in exchange. The journal entry to record the transaction would be as follows:Debit: Old equipment for $120,000Debit: Loss on exchange for $10,000 ($100,000 - $90,000)Credit: New equipment for $100,000Credit: Cash for $20,000.
Therefore, The journal entry for Johnny to record this transaction is Debit: New laptop for $2,500, Credit: Used laptop for $1,000, Credit: Cash for $800, Credit: Gain on exchange for $700. The journal entry for Barry to record this transaction is: Debit: Old equipment for $120,000, Debit: Loss on exchange for $10,000, Credit: New equipment for $100,000, Credit: Cash for $20,000.
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A company's profit increased linearly from $5 million at the end of year 2 to $17 million at the end of year 6.
(a) Use the two (year, profit) data points (2, 5) and (6, 17) to find the linear relationship y = mx + b between x = year and y = profit.
(b) Find the company's profit at the end of 3 years.
(c) Predict the company's profit at the end of 8 years.
Below, you will learn how to solve the problem.
(a) To find the linear relationship y = mx + b between x = year and y = profit, we first need to find the slope (m) and the y-intercept (b).
The slope (m) is the change in y (profit) divided by the change in x (year):
m = (17 - 5)/(6 - 2)
m = 12/4
m = 3
Next, we can use one of the data points (2, 5) and the slope (3) to find the y-intercept (b):
5 = 3(2) + b
b = 5 - 6
b = -1
So the linear relationship between x = year and y = profit is:
y = 3x - 1
(b) To find the company's profit at the end of 3 years, we can plug in x = 3 into the equation:
y = 3(3) - 1
y = 8
So the company's profit at the end of 3 years is $8 million.
(c) To predict the company's profit at the end of 8 years, we can plug in x = 8 into the equation:
y = 3(8) - 1 = 23
So the company's profit at the end of 8 years is predicted to be $23 million.
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Use division, the Fraction Number Line Poster, or fraction circle pieces to rename the fractions as mixed numbers.
a.
12
5
=
b.
15
2
=
Use division, the Fraction Number Line Poster, or fraction circle pieces to rename the fractions as mixed numbers.
a.
12
5
=
b.
15
2
=
Answer:
\(2\frac{2}{5}\)
\(7\frac{1}{2}\)
Step-by-step explanation:
A study of iron deficiency among infants compared samples of infants following different feeding regimens. One group contained breastfed infants, while the infants in another group were fed by a standard baby formula without any iron supplements. The summary results on blood hemoglobin levels at 12 months of age are provided below. Furthermore, assume that both samples are sampled from populations that are reasonably normally distributed. (M.F. Picciano and R.H. Deering?The influence of feeding regimens on iron status during infancy,? American Journal of Clinical Nutrition, 33 (1980), pp. 746-753)
Group n x s
Breast-fed 23 13.3 1.7
Fourmula 19 12.4 1.8
(a) Test the hypothesis that there is a difference in the population means between breast-fed infants and formula-fed infants at α = 0.05. Assume the population variances are unknown but equal.
(b) Construct a 95% confidence interval for the difference in population means between breast-fed infants and formula-fed infants. Assume the population variances are unknown but equal.
(c) Write at least one complete sentence describing how your answers to parts (a) and (b) yield the same conclusion about whether there is a difference in the mean blood hemoglobin levels. Hint: Be sure to use the number 0 when discussing the conclusions.
A. statistically significant difference in the mean blood hemoglobin levels between breastfed infants and formula-fed infants at α = 0.05.
B. the 95% confidence interval for the difference in population means between breast-fed infants and formula-fed infants is (−0.06, 1.18).
C. Both the hypothesis test and the confidence interval lead to the same conclusion that there is a difference in the mean blood hemoglobin levels between the two feeding regimens.
What is null hypothesis?
In statistics, the null hypothesis (H0) is a statement that assumes that there is no significant difference between two or more groups, samples, or populations.
(a) To test the hypothesis that there is a difference in the population means between breast-fed infants and formula-fed infants, we can use a two-sample t-test with equal variances. The null hypothesis is that the population means are equal, and the alternative hypothesis is that they are not equal. Using α = 0.05 as the significance level, the critical value for a two-tailed test with 40 degrees of freedom is ±2.021.
The test statistic can be calculated as:
t = (x1 - x2) / (Sp * √(1/n1 + 1/n2))
where x1 and x2 are the sample means, Sp is the pooled standard deviation, and n1 and n2 are the sample sizes. The pooled standard deviation can be calculated as:
Sp = √(((n1 - 1) * s1² + (n2 - 1) * s2²) / (n1 + n2 - 2))
where s1 and s2 are the sample standard deviations.
Plugging in the values from the table, we get:
t = (13.3 - 12.4) / (1.776 * √(1/23 + 1/19)) = 2.21
Since the absolute value of the test statistic is greater than the critical value, we reject the null hypothesis and conclude that there is a statistically significant difference in the mean blood hemoglobin levels between breastfed infants and formula-fed infants at α = 0.05.
(b) To construct a 95% confidence interval for the difference in population means between breast-fed infants and formula-fed infants, we can use the formula:
(x1 - x2) ± tα/2,Sp * √(1/n1 + 1/n2)
where tα/2,Sp is the critical value of the t-distribution with (n1 + n2 - 2) degrees of freedom and α/2 as the significance level.
Plugging in the values from the table, we get:
(x1 - x2) ± tα/2,Sp * √(1/n1 + 1/n2)
= (13.3 - 12.4) ± 2.021 * 1.776 * √(1/23 + 1/19)
= 0.56 ± 0.62
Therefore, the 95% confidence interval for the difference in population means between breast-fed infants and formula-fed infants is (−0.06, 1.18).
(c) The hypothesis test and the confidence interval both lead to the conclusion that there is a difference in the mean blood hemoglobin levels between breast-fed infants and formula-fed infants. In part (a), we rejected the null hypothesis that the population means are equal, which means we concluded that there is a difference. In part (b), the confidence interval does not contain 0, which means we can reject the null hypothesis that the difference in means is 0 at the 95% confidence level.
Therefore, both the hypothesis test and the confidence interval lead to the same conclusion that there is a difference in the mean blood hemoglobin levels between the two feeding regimens.
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Cole is taking a 170-mile trip by car. If he drives for 2 hours with an average speed of 60 miles per hour, how many miles will he still need to drive to complete his trip?
A: 50
B: 110
C: 120
D: 340
Cola need 50 miles to drive to complete his trip.
Option A is true.
What is Distance?
The total movement of an object without any regard to direction is called distance.
Given that;
Cole is taking a 170-mile trip by car.
He drive for 2 hours with an average speed of 60 miles per hour.
Now, Distance cover in 2 hours with speed 60 miles per hour is calculated as;
Since, Distance = Speed x time
Hence, Distance = 60 x 2 = 120 miles.
So, Remaining speed to complete his trip = 170 - 120 = 50 miles.
Hence, Cola need 50 miles to drive to complete his trip.
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f (x) = -3 + 7. Find the inverse of f(x) and its domain.
O A. f-1(x) 277 - 3, where x=-7
O B. f-1(x) = +7 +3, where x# 7
c. f-1(x) = 11 – 3, where x# 3
O D. f-1(x) = + 3, where x# 3
S
Note: Your function is missing some information. It seems your function is
\(f\left(x\right)=\frac{-3}{x}+7\).
So, I am solving the question based on the function \(f\left(x\right)=\frac{-3}{x}+7\), because it would still solve your query.
Answer:
Please see the explanation.
Step-by-step explanation:
Given the function
\(f\left(x\right)=\frac{-3}{x}+7\)
A function g is the inverse of a function f for y = f(x), x=g(y)
\(y=\frac{-3}{x}+7\)
Replace x with y
\(x=\frac{-3}{y}+7\)
solve for y
\(y=-\frac{3}{x-7}\)
so the inverse of \(f\left(x\right)=\frac{-3}{x}+7\) will be:
\(f^{-1}\:\left(x\right)=-\frac{3}{x-7}\)
Finding the domain of \(f^{-1}\:\left(x\right)=-\frac{3}{x-7}\)
As we know that domain is the set of the possible input values where the function is defined.
so the function domain must be: \(x<7\quad \mathrm{or}\quad \:x>7\)
Therefore,
\(\mathrm{Domain\:of\:}\:-\frac{3}{x-7}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<7\quad \mathrm{or}\quad \:x>7\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:7\right)\cup \left(7,\:\infty \:\right)\end{bmatrix}\)
Suppose that IQ scores have a bell-shaped distribution with a mean of 105 and a standard deviation of 15. Using the empirical rule, what percentage of IQ scores are between 90 and 120?
68% of IQ scores are found to be between 90 and 120
What is empirical rule?The empirical rule states that for a normal distribution, about 68% of the data falls within one standard deviation from the mean, 95% of the data falls within two standard deviation from the mean and 99.7% of the data falls within three standard deviation from the mean.
Given mean of 105 and a standard deviation of 15.
68% of data falls within one standard deviation from the mean = mean ± standard deviation = 105 ± 15 = (90, 120)
68% of IQ scores are between 90 and 120
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A pharmaceutical company wants to test the effectiveness of a new allergy drug. The company identifies 250 females 30-35 years old who suffer from severe allergies. The subjects are randomly assigned into two groups. One group is given the new allergy drug and the other is given a placebo that looks exactly like the new allergy drug. After six months, the subjects' symptoms are studied and compared. Answer parts (a) through (c) below.
After six months, the subjects' symptoms are studied and compared. Answer parts are given below.
What is the hypothesis?An assumption or concept is given as a hypothesis for the purpose of debating it and testing if it might be true.
Given:
A pharmaceutical company wants to test the effectiveness of a new allergy drug.
The company identifies 250 females 30–35 years old who suffer from severe allergies.
The subjects are randomly assigned into two groups.
One group is given the new allergy drug and the other is given a placebo that looks exactly like the new allergy drug.
After six months, the subjects' symptoms are studied and compared.
Here, 30-35 year-old girls are used to test the new allergy medication's effects.
(a)
Females between the ages of 30 and 35 who are the test subjects are the experimental units.
The new allergy medication, whose results are being studied, is the remedy.
It's best to choose C.
(b)
A bias may develop if a researcher or patient knows whether subjects received a medication or a placebo.
In this case, choice B is preferable.
(c)
If neither the researcher nor the subject knew whether they were receiving a medicine or a placebo, the study would be considered double-blind.
In this case, choice A is preferable.
Therefore, all the correct choices are given above.
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The complete question is given in the image.
Enter the value of
a
,
b
, and
c
if
x
2
−
x
−
1
=
0
Answer:
\(a=1\\b=-1\\c=-1\)
Step-by-step explanation:
Standard form:
\(ax^2+bx+c=0\)
Identify the values in:
\(x^2-x-1=0\)
\(a=1\\b=-1\\c=-1\)
Point F is on line segment EG. Given FG = 3x – 5, EF = x, and
EG = 5x – 8, determine the numerical length of FG.
A line segment can have one or more points on it. The numerical length of FG is 4
Given that:
\(FG = 3x - 5\)
\(EF = x\)
\(EG = 5x - 8\)
Because point F is on EG, then:
\(EG = EF + FG\)
So, we have:
\(5x - 8 = x + 3x - 5\)
\(5x - 8 = 4x - 5\)
Collect like terms
\(5x - 4x = 8 - 5\)
\(x =3\)
Recall that:
\(FG = 3x - 5\)
Substitute \(x =3\)
\(FG = 3 \times 3 - 5\)
\(FG = 9 - 5\)
\(FG = 4\)
Hence, the numerical length of FG is 4
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Find the perimeter of the figure to the nearest hundredth.
Please help me
Answer:
24.00
You have to add all 4 sides of the figure.
Answer:
26.85 in
Step-by-step explanation:
The circumference of the whole circle of diameter 5 in is C = πd, which here is C = π(5 in), or approximately 5π in. We take only half of this, since the figure shows a semicircle, not a full circle. Then the half-circumference is (5/2)π.
To find the perimeter: add up the lengths forming the perimeter:
7 in + (5/2)π in + 7 in + 5 in, or:
19 in + (5/2)π ≈ 26.85 in
(ii) the position of a ball rolling in a straight line is given by x = 2.0 - 3.6 t 1.1 t 2 , where x is in meters and t in seconds.
The position of the ball at t = 2 seconds is -0.8 meters.
The position of a ball rolling in a straight line is given by the equation x = 2.0 - 3.6t + 1.1t^2, where x is the position in meters and t is the time in seconds. To find the position of the ball at a specific time, we can plug in the value of t into the equation and solve for x.
For example, if we want to find the position of the ball at t = 2 seconds, we can plug in 2 for t and solve for x:
x = 2.0 - 3.6(2) + 1.1(2)^2
x = 2.0 - 7.2 + 4.4
x = -0.8
Therefore, the position of the ball at t = 2 seconds is -0.8 meters.
Similarly, we can plug in any value of t into the equation to find the position of the ball at that specific time.
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What is the value of the expression below
x = 8 and y = 3
9x + 7y
9x+7y
x=8 and y=3
9(8)+7(3)
72+7(3)
72+21
=93
Select the correct answer. What is the domain of the function graphed above? A. B. C. D.