actuators (outputs) are being discussed. technician a says they are variable resistance/ reference-types, switches, and thermistors. technician b says they convert electrical current into mechanical action. who is correct?

Answer:

20.87 Pa

Explanation:

The formula for dynamic pressure is given as;

q= 1/2*ρ*v²

where ;

q=dynamic pressure

ρ = density of fluid

v = velocity of fluid

First find v by applying the formula for flow rate as;

Q = v*A   where ;

Q= fluid flow rate

v = flow velocity

A= cross-sectional area.

A= cross-sectional vector area of the pipe given by the formula;

A= πr² = 3.14 * 4² = 50.27 in²   where r=radius of pipe obtained from the diameter given divided by 2.

Q = fluid flow rate = 105 gpm----change to m³/s as

1 gpm = 0.00006309

105 gpm = 105 * 0.00006309 = 0.006624 m³/s

A= cross-sectional vector area = 50.27 in² -------change to m² as:

1 in² = 0.0006452 m²

50.27 in² = 50.27 * 0.0006452 = 0.03243 m²

Now calculate flow velocity as;

Q =v * A

Q/A = v

0.006624 m³/s / 0.03243 m² =v

0.2043 m/s = v

Now find the dynamic pressure q given as;

q= 1/2 * ρ*v²

q= 1/2 * 1000 * 0.2043² = 20.87 Pa

To enable high and low level testing of industrial data network systems, skills such as proficiency with industrial standard equipment and implementation of accredited testing methods are crucial.

These skills encompass knowledge of network protocols, configuration, and troubleshooting techniques necessary to conduct comprehensive testing of industrial data network systems. Utilizing industrial standard equipment ensures compatibility and accuracy in testing, while implementing accredited testing methods guarantees adherence to recognized industry standards and best practices.

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The phrase "system of rules where symbols represent actions" sums up programming languages the best.

Symbols that represent actions are used in a computer language's set of rules. Programming languages are the set of instructions that a computer uses to carry out projects. A programming language is a vocabulary and a set of grammatical rules for telling a computer or other computing equipment to carry out particular tasks.

High-level languages such as BASIC, C, C++, COBOL, Java, FORTRAN, Ada, and Pascal are typically referred to as programming languages. instruction. The principles that specify how a language is structured are known as syntax. In computer programming, syntax refers to the rules that govern how words, punctuation, and symbols are organized in a programming language. To define algorithms or write programs to control a machine's behavior, programmers utilize programming languages.

Therefore the correct answer is option A ) A set of rules where symbols represent actions.

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Hai

Your answer will be A.

If you lower the Air Pressure your Object will Float Down ward. The Air Pressure allows it to Fly.

The pressure field created by faster air movement over an airfoil is; A:  higher

When the air hits the front of the wing, the air will flow in a steeper curve upward, than the bottom wing flow which will lead to the creation of a vacuum on top of the wing that pulls more air towards the top of the wing.

Finally, this air above does the same thing but it will move faster as a result of the vacuum pulling it in, and as such the vacuum now lifts the wing. Thus, Faster air movement over an airfoil creates a higher pressure field.

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The enthalpy of combustion of methane at 25°C and 1 atm, assuming that the water in the products is in the liquid form, is -802.3 kJ/mol.

The enthalpy of combustion of methane can be calculated using the enthalpy of formation data for methane and water, and the balanced chemical equation for the combustion reaction:

CH4 + 2O2 -> CO2 + 2H2O

The enthalpy change for this reaction can be calculated using Hess's law, which states that the enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the original reaction. In this case, we can use the following reactions:

CH4 + 2O2 -> CO2 + 2H2O (target reaction)

CH4 + 2O2 -> CO2 + 2H2O + 890.3 kJ/mol (enthalpy of formation of CH4)

H2(g) + 1/2O2(g) -> H2O(l) + 285.8 kJ/mol (enthalpy of formation of H2O)

To use Hess's law, we need to reverse the second equation and multiply it by -1, and add it to the first equation to cancel out the H2O on the product side:

CH4 + 2O2 -> CO2 + 2H2O (target reaction)

CH4 + 2O2 -> CO2 + 2H2O + 890.3 kJ/mol (enthalpy of formation of CH4)

H2O(l) -> H2(g) + 1/2O2(g) -285.8 kJ/mol (enthalpy of formation of H2O)

Adding the three equations, we get:

CH4 + 2O2 -> CO2 + 2H2O, ΔH = -802.3 kJ/mol

Therefore, the enthalpy of combustion of methane at 25°C and 1 atm, assuming that the water in the products is in the liquid form, is -802.3 kJ/mol.

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It is likely that the population increase in the Kentucky town has had a positive effect on other businesses in the area. As more people move into the town, there will be an increased demand for goods and services, which can benefit local businesses by providing them with more customers and potentially increasing their sales.

Joe's Delivery Service should take this population increase into consideration when projecting future sales, as it may provide them with an opportunity to grow and expand their business. By understanding the impact of the population increase on other businesses in the area, Joe's Delivery Service can develop strategies and plans that take advantage of this growth and help them to achieve their sales goals.

The introduction of steel into the nineteenth-century industrial age changed the architectural style and scale forever.

Steel can be defined as hard, strong, tough grey (bluish-grey) alloy of iron and carbon that is typically used as a structural and fabricating material in Civil engineering and architecture.

During the industrial age of the nineteenth-century, the introduction of steel changed the architectural style and scale forever.

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Answer: True

Explanation:

The statement about the source term affecting all algebraic equations is; False

In the finite-element method of Analysis, we usually go from differential equations to a set of algebraic equations. Now, it is pertinent to note that each algebraic equation will tend to relate a nodal value with all other nodal values.

The assumed polynomial variation that will exist within each element is usually the basis for which we derive the algebraic equations. Thus, to derive the algebraic equations, we will have to assume a polynomial variation for the parameter values within each element.

The above can be done through interpolation of nodal parameter values in the post-processing stage. This is because the assumed polynomial variation within each element that is used for deriving the algebraic equations is also used for post-processing.

Finally, for each algebraic equation, the source term will tend to contribute to the coefficient that is taken to the right hand side of it and then entered into the corresponding row of the {f} vector.

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Complete Question is;

Select true or false.

The source term will affect all algebraic equations.

A.) True

B.) False

Answer:

The correct answer is letter "B" :- Phased

Explanation:

                             This approach is called Phased conversion. In a phased implementation, only a portion of the old system is replaced at first, allowing for testing and training before fully replacing the remaining old stations. During the implementation of a new checkout system, Target initially replaced only half of the old check out stations in each store while leaving the other half the same so bugs could be worked out and training could be completed on the new stations. After testing and training, Target they phased out the remaining old stations. This approach is called phased conversion.

                   Phased conversion refers to the strategy of transitioning one component of a business to a new system gradually. Phased conversion is a technique for testing new systems before fully implementing them, and it is common in situations when there is no deadline for completion. The phased conversion approach allows the testing of new equipment and the training of new employees while still allowing the company to conduct business. Phased conversion is the strategy used in this case. Phased conversion is an approach to implementing a new system in stages or phases, replacing some parts of the old system at a time until the new system is fully implemented. This approach is often used to minimize disruptions to ongoing operations and to allow for testing, training, and adjustment of the new system before it is fully deployed. The phased approach can help to identify and address any issues or problems with the new system before it is rolled out to the entire organization or customer base. This approach is commonly used in situations where it is important to maintain continuity of operations or to minimize the risk of failure or disruption during the transition to a new system.

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Explanation:The above problem is a programming problem based on Python.Here, in this exercise, the given Python program needs to be modified such that it will save a list as a binary file instead of a CSV file.The detailed explanation for modifying the CSV version of the write program and trip program is given below:1. For modifying the CSV version of the write program:a. Open the mpg_write.py file.b.

Then, save it as mpg_write_binary.py in the same directory.c. Modify this program so it saves the list as a binary file instead of a CSV file. The file should be named trips.bin.d. To do that, use the following code snippet:import picklewith open('trips.bin', 'wb') as file:# Write the data to filepickle.dump(trips, file)e.

Test the program to make sure it works. To do that, add statements that read the file at the end of the program and display the list that has been read. Use the following code snippet:with open('trips.bin', 'rb') as file:# Read the data from filetrips = pickle.load(file)print(trips)2. For modifying the CSV version of the trip program:a. Open the mpg.py file.b. Then, save it as mpg_binary.py.c. Modify this program so it works the same as it did with the CSV file. To do that, use the following code snippet:import picklewith open('trips.bin', 'rb') as file:# Read the data from filetrips = pickle.load(file)print(trips)Here, in the above code snippet, the binary file is opened in read mode and the data is read using pickle.load() function and is printed using the print() function

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Answer:

The answer is below

Explanation:

The complete question is attached.

a) Bernoulli equation is given as:

\(P+\frac{1}{2}\rho V^2+ \rho gz=constant\\\\\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\)

Where P = pressure, V = velocity, z = height, g = acceleration due to gravity and ρ = density.

\(\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\\\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_1}{\gamma} +\frac{V_1^2}{2g} +z_1=\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2\\\\but \ z_1=z_2,P_1=0,V_1=0,V_2=60\ mph=88\ ft/s. Hence:\\\\\frac{P_2}{\gamma} =-\frac{V_2^2}{2g} \\\\P_2=\gamma*-\frac{V_2^2}{2g} =\rho g*-\frac{V_2^2}{2g} \\\\P_2=-\frac{V_2^2}{2}*\rho=-\frac{(88.8\ ft/s)^2}{2} * 0.00238\ slug/ft^3=-9.22\ lb/ft^2\\\\P_2+\gamma_{H_2O}h-\gamma_{oil}(1/12 \ ft)=0\\\\\)

\(\gamma_{oil}=0.9\gamma_{H_2O}=0.9*62.4\ lb/ft^3=56.2\ lb/ft^3\\\\Therefore:\\\\-9.22\ lb/ft^2+62.4\ lb/ft^3(h)-56.2\ lb/ft^3(1/12\ ft)=0\\\\h=0.223\ ft\)

b)

\(\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2=\frac{P_3}{\gamma} +\frac{V_3^2}{2g} +z_3\\\\but \ z_3=z_2,V_3=0,V_2=60\ mph=88\ ft/s. \\\\\frac{P_2}{\gamma}+\frac{V_2^2}{2g} = \frac{P_3}{\gamma}\\\\\frac{P_3-P_2}{\gamma}=\frac{V_2^2}{2g} \\\\P_3-P_2=\frac{V_2}{2g}*\gamma=\frac{V_2^2}{2g}*\rho g\\\\P_3-P_2=\frac{V_2}{2}*\rho=\frac{(88\ ft/s^2)^2}{2}*0.00238\ slg\ft^3\\\\P_3-P_2=9.22\ lb/ft^2\)

Answer: A. Makes a commodity available for sale or exchange

Explanation: hope it helps ^w^

Yes, it is possible that an optimum insulation thickness exists for radial systems due to the competing effects associated with an increase in insulation thickness.

What  happened after increasing insulation thickness?

On one hand, increasing the thickness of insulation can improve the overall insulation performance of the system by reducing heat loss and increasing energy efficiency. This is because thicker insulation offers more resistance to heat flow and can therefore reduce the amount of heat lost from the system.

On the other hand, increasing insulation thickness also increases the cost of the system, and can add weight and size to the overall design, which can be a disadvantage in certain applications.

Therefore, there is likely to be an optimal insulation thickness that balances the benefits of improved insulation performance with the added costs and drawbacks of thicker insulation. Finding this optimal thickness requires careful consideration of the specific application, as well as factors such as the insulation material used, the desired level of energy efficiency, and the overall cost and size constraints of the system.

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The network output of the ideal Diesel cycle is therefore around 0.235 kJ. W net = MEP x displacement volume = (650 kPa) × (3.61125e-4 m3) = 0.23499 kJ.

based on a two-stroke engine's cylinder pressure at 0 degrees and 360 degrees during the intake and exhaust phases of the engine cycle, respectively. Cylinder pressure sensor apparatus is needed for direct measurement. IMEPg - IMEPn equals PMEP.

W_net = MEP x displacement volume

V_d = V_1 - V_2

P_1V_1 = mRT

V_1 = mRT / P_1

V_2 = V_1 + m_inj

V_inj = V_2 - V_c

V_c = V_1 - V_d / r

r = V_1 / V_2

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Answer:

depth

rod to use

travel speed

type of weld

tthe side to be welded on

Answer:

a) Mt = 0.0023229

b) = U1 = 214.07

c) = V₁  = 0.861 m³/kg

d) = Vr1 = 621.2

Explanation:

Given that

R = 0.287 KJ/kg.K, T1 = 300 K , P1 = 100 kPa , V1 = 500 cm³, r = 10 , Q = 60 kW , Speed N = 5600 RPM, Number of cylinders K = 4

specific heat at constant volume Cv = 0.7174 kJ/kg.K

Specific heat at constant pressure is 1.0045 Kj/kg.K

a)  To determine the total mass (kg) of air in the engine.

we say

P1V1 = mRT1

we the figures substitute

(100 x 10³) ( 500 x  10⁻⁶) = m ( 0.287 x  10³) ( 300 )

50 = m x 86100

m = 0.00005 / 86100 = 0.0005807 ( mass of one cylinder)

Total mass of 4 cylinder

Mt = m x k

Mt = 0.0005807 x 4

Mt = 0.0023229

b) To determine the specific internal energy (kJ/kg) at state 1

i.e at T1 = 300

we obtain the value of specific internal energy U1 at 300 K ( state 1) from the table ideal gas properties of air.

U1 = 214.07

c) To determine the specific volume (m³/kg) at state 1.

we say

V₁ = V1/m

V₁ = (500 x  10⁻⁶) / 0.0005807

V₁  = 0.861 m³/kg

d) To determine the relative specific volume at state 1.

To obtain the value of relative specific volume at 300 K ( i.e state 1) from the table ideal gas properties of air.

At T1 = 300 k

Vr1 = 621.2

     An op amp-based circuit known as a differentiator produces an output signal that is proportional to the differentiation of the input signal. In essence, an op amp differentiator is an inverting amplifier with an appropriate capacitor at its input end.

        Depending on the circuit time constant and the amplifier's bandwidth, the differentiator circuit produces the derivative of the input signal over a range of frequencies. Applying the input signal to the inverting input causes the output to be polarity-inverted with respect to the input signal.

       Why is a differentiator opamp used? The major application of this op-amp is to boost weak signal levels. Depending on the components used in the design, an op-amp differentiator can be either active or passive. We will utilize this differentiator amplifier in frequency modulators and wave shaping circuits because it essentially functions as a high pass filter.

      Why do op-amps utilize capacitors? A feedback capacitor is used in a typical op-amp circuit to restrict bandwidth. A feedback capacitor is a typical approach to minimize noise because restricting op-amp bandwidth will do so. Consider that a capacitor functions as a short to "high frequency" AC impulses in order to comprehend how the feedback capacitor operates.

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At 1.2mpa pressure and 50c

What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).

a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser

T2 = 46.29C - 5
T2 = 41.29C

Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg

(COP)r = 238/53
(Cop) = 4.490

Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.

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When a trait or a disease "runs in families", it means that the trait or disease is hereditary or inherited and can be passed down from one generation to another.What is heredity?Heredity refers to the passing on of traits from parents to their offspring, and it is a significant biological concept that explains why many traits and diseases may "run in families.

" Inherited traits are passed down from parent to child through DNA, the genetic material found in all cells of our body. Genetic mutations, which are changes in DNA, can cause a disease or a predisposition to a disease. Therefore, certain genetic traits or mutations may be present in a family's DNA, leading to an increased likelihood of inheriting that trait or mutation. Hence, the trait or disease "runs in the family.

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Answer:

Sure, I can help you with that. Here are the steps involved in solving the problem:

1. **Define the variables.**

The following variables are used in the problem:

* **h:** The height of the plate, which is 2 mm = 0.002 m

* **L:** The length of the plate, which is 1.25 m

* **W:** The width of the plate, which is 1.25 m

* **v:** The velocity of the plate, which is 0.18 m/s

* $\mu$: The dynamic viscosity of the oil, which is 2.5 N.s/m²

* $\rho$: The density of the oil, which is 0.85 * 1000 kg/m³ = 850 kg/m³

* g: The acceleration due to gravity, which is 9.8 m/s²

* F: The force required to lift the plate

2. **Determine the area of the plate.**

The area of the plate is calculated as follows:

```

A = L * W = 1.25 m * 1.25 m = 1.5625 m²

```

3. **Determine the volume of the oil displaced by the plate.**

The volume of the oil displaced by the plate is calculated as follows:

```

V = A * h = 1.5625 m² * 0.002 m = 0.00390625 m³

```

4. **Determine the weight of the oil displaced by the plate.**

The weight of the oil displaced by the plate is calculated as follows:

```

W_o = \rho * V * g = 850 kg/m³ * 0.00390625 m³ * 9.8 m/s² = 3.37 N

```

5. **Determine the force required to overcome the viscous drag on the plate.**

The force required to overcome the viscous drag on the plate is calculated as follows:

```

F_v = \mu * L * v = 2.5 N.s/m² * 1.25 m * 0.18 m/s = 0.46 N

```

6. **Determine the total force required to lift the plate.**

The total force required to lift the plate is calculated as follows:

```

F = F_o + F_v = 3.37 N + 0.46 N = 3.83 N

```

Therefore, the force required to lift the plate with a constant velocity of 0.18 m/s is 3.83 N.

Explanation:

Answer:

i think D

Explanation:

In the early 1990s, there was a growing demand for higher-speed local area network (LAN) connections to support increasingly data-intensive applications such as multimedia, graphics, and database management.

The existing Ethernet standard, known as 10BASE-T, provided a maximum data rate of 10 megabits per second (Mbps), which was becoming inadequate for many users.To address this need, the Institute of Electrical and Electronics Engineers (IEEE) developed a new Ethernet protocol known as 802.3u. This new protocol used a different physical layer technology called "100BASE-T", which allowed for data rates up to 100 Mbps over twisted pair copper cabling.This new protocol was called "Fast Ethernet" to distinguish it from the original 10BASE-T Ethernet.

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Answer:

I think trains are pretty awesome. There's a train in japan that levitates slightly and runs on magnetism. Pretty amazing. It's super fast too

Answer: Photo lines

Explanation: made more sense

The displacement of end D with respect to end A is \(-0.488 \times 10^{-3}\;m\)

Given the following data:

To determine the displacement of end D with respect to end A:

First of all, we would do a sectional cut of the circular rods at point A and then determine the sum of forces acting on it:

\(\sum F=0\\\\ 10000+N_1=0\\\\N_1 = -10000\;N\)

Mathematically, the displacement of a circular rod is given by this formula:

\(d = \frac{NL}{AE}\)

Where:

Substituting the given parameters into the formula, we have;

\(d_1 = \frac{-10000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_1 = \frac{-4350}{0.0003142 \times 68.9 \times 10^9}\\\\d_1 =-0.201 \times 10^{-3}\;meter\)

For section cut BC:

\(\sum F=0\\\\ 10000-20000+N_2=0\\\\N_2 = 10000\;N\)

\(radius = outer\;radius^2 - inner\;radius^2\\\\radius = 0.04^2 -0.03^2=0.0007\;m\)

\(d_2 = \frac{10000 \times 0.435}{\frac{3.142 \times 0.0007^2}{4} \times 68.9 \times 10^9} \\\\d_2 = \frac{4350}{0.00054985 \times 68.9 \times 10^9}\\\\d_2 =0.115 \times 10^{-3}\;meter\)

For section cut D:

\(\sum F=0\\\\ -20000-N_3=0\\\\N_3 =- 20000\;N\)

\(d_3 = \frac{-20000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_3 = \frac{-8700}{0.0003142 \times 68.9 \times 10^9}\\\\d_3 =-0.402 \times 10^{-3}\;meter\)

For the total displacement:

The total displacement is equal to the displacement of end D with respect to end A.

\(d_T = d_1 +d_2+d_3\\\\d_T = -0.201 \times 10^{-3} + 0.115 \times 10^{-3}-0.402 \times 10^{-3}\\\\d_T = -0.488 \times 10^{-3}\;m\)

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