According to the model, which two points on Earth are experiencing winter?
A.a
B.b
C.c
D.d

Answer:

Option C. 4.5×10¯² N

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +5×10¯⁶ C

Charge 2 (q₂) = –4×10¯⁶ C

Distance apart (r) = 2 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

The magnitude of the force can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × 5×10¯⁶ × 4×10¯⁶ / 2²

F = 0.18 / 4

F = 0.045

F = 4.5×10¯² N

Thus, magnitude of the force is 4.5×10¯² N

Answer:

It can be identified using physical properties such as density

Explanation:

Matter is any substance that has mass and takes up space. Therefore, it can be identified using physical properties such as density

Explanation:

We can identify matter by:

1.physical properties.

2.chemical properties.

Hope this helps...

The magnitude of the induced electric field at a point near the center of the solenoid and 2 cm from the axis is approximately 0.000589 T*m²/s.

The magnitude of the induced electric field at a point near the center of the solenoid can be calculated using the formula for the magnetic field inside a solenoid. The induced electric field is directly proportional to the rate of change of the magnetic field with respect to time. First, let's calculate the magnetic field at the given point near the center of the solenoid. The formula for the magnetic field inside a solenoid is given by B = μ₀ * n * I, where B is the magnetic field, μ₀ is the permeability of free space (4π * 10⁻⁷ T*m/A), n is the number of turns per unit length (500 turns/m), and I is the current (60 A/s).

The magnetic field at the given point can be calculated as follows:
B = μ₀ * n * I = (4π * 10⁻⁷ T*m/A) * (500 turns/m) * (60 A/s) = 0.075 T
Next, we can calculate the induced electric field at the given point using the formula E = -dΦ/dt, where E is the induced electric field and Φ is the magnetic flux. The magnetic flux is given by Φ = B * A, where A is the area perpendicular to the magnetic field.

The area at the given point can be calculated as follows:
A = π * r² = π * (0.05 m)² = 0.00785 m²
Now, we can calculate the induced electric field:
E = -dΦ/dt = -(d(B * A)/dt) = -A * dB/dt = - (0.00785 m²) * (0.075 T/s) = -0.000589 T*m²/s

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Answer:

B- He is correct. Evaporation is a physical change, but dissolving salt in water is a chemical change. The change in mass is evidence that a chemical change occurred.

Explanation: Dissolving Salt in water is a Chemical Change, Because the Salt arrangement is different in solid state than dissolved in water. As we can see in the image below, once the Salt is dissolved, it is separated into its ions, Na+ and Cl- Now, The evaporation process is a physical change, because the water doesn´t change its configuration H20 and it only changes its form, as we can see in the image below.

Answer:

B) He is correct. Evaporation is a physical change, but dissolving salt in water is a chemical change. The change in mass is evidence that a chemical change occurred.

Explanation:

hope this helps!! :)

Potential energy is transformed into kinetic energy its correct trust me have a nice day! :)

The pendulum is now swinging on Pluto.

Oscillation is the repetitive or periodic variation, usually over time, of a measurement about a central value or between two or more different states. Familiar examples of oscillations are swinging pendulums and alternating currents.

The oscillatory motion of a simple pendulum is defined as the periodic back-and-forth motion of the pendulum. The reciprocating motion of the bob starting at one end and returning to the same position is called a pendulum swing.

Oscillation is the repeated or periodic variation of a measurement about a central value  or between two or more different states, usually over time. Familiar examples of oscillations are swinging pendulums and alternating currents.

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An example of a project where an object with a high (k) value would be a benefit is one that has to do with the design of a rocket engine. Metals that have very high thermal conductivity are useful for building rocket engines. This is because of the amount of energy/heat that is required to be combusted by these parts to achieve a break from the earth's force field of gravity.

While engineering problems where having an object with a low (k) value would be a benefit is those that have to do with buildings. Buildings are made from concrete and brisk with have low thermal conductivity hence low

A k-value (also known as a k-factor or lambda value) is a measure of a material's thermal conductivity, or how quickly heat moves through it. It is a basic quality that is independent of material quantities.

Thermal conductivities of different building materials may be compared using k-values. This is often useful in determining the possibility of heat transmission between the inside and exterior of a structure.

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Explanation:

CON EL TEOREMA DE PITÁGORAS

v = \(\sqrt{(12 km/h)^{2} + (25 km/h)^{2}}\) = 27.7 km/h

The two possible angles that he can throw the ball is 13.1⁰ and 77⁰.

The time in air for each angle are 0.92 seconds and 4 seconds.

The range of a projectile is the maximum horizontal displacement of the projectile.

Mathematically, the range of a projectile is given as;

R = [u² sin(2θ)]/g

where;

sin(2θ) = Rg/u²

sin(2θ) = (18 x 9.8)/(20²)

sin(2θ) = 0.441

2θ = arc sin(0.441)

2θ = 26.2⁰

θ = (26.2⁰)/2 = 13.1⁰

θ' = 90 - 13.1⁰ ≈ 77⁰

R = Vₓt

t = R/Vₓ

t = (18 m) / (20 x cos77)

t = 4 seconds

t₂ =  (18 m) / (20 x cos13)

t₂ = 0.92 s

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The cured adhesive and UV-cured diacrylate exhibited the topology of crosslinked networks.

The topology of a material refers to its molecular structure or arrangement. The cured adhesive and UV-cured diacrylate both exhibit the topology of crosslinked networks.
Crosslinking occurs when the molecules of a material are connected by covalent bonds to form a three-dimensional network. This results in a material with improved mechanical properties, such as increased strength and durability.

In the case of the cured adhesive and UV-cured diacrylate, crosslinking is achieved through a chemical reaction that occurs when the material is exposed to curing agents or UV light. The resulting crosslinked network gives the material its unique topology.

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Answer:

25000 J or 25 kJ

Explanation:

K = 1/2 mv^2

where mass is in kilograms kg

and velocity is in metres per seconds m/s

Here, m = 2000, v = 5

v^2 = 5*5 = 25

1/2 mv^2 = 1/2 * 2000 * 25

= 50000/2

= 25000

Hope it helps!

Answer:

18,000 j

Explanation:

the lightbulb dissipates 5W of power

P = ΔE / Δt

rearrange to solve for energy

ΔE = PΔt

P = 5W

t =  1 hour = 60 minutes = 3600 seconds

ΔE = 5 * 3600

ΔE = 18000 J

The radial acceleration of the ball during its circular motion is approximately 59.4 m/s^2.

Centripetal acceleration, a = v^2 / r, where v is the speed of the ball and r is the radius of the circle.

The time it takes for the ball to reach the ground,

y = 1/2 g t^2

where y is the initial height of the ball (1.00 m), g is the acceleration due to gravity (9.81 m/s^2), and t is the time it takes for the ball to reach the ground.

t = sqrt(2y/g)

= sqrt(2 x 1.00 / 9.81)

≈ 0.45 s

Velocity, v = x/t

= 1.90 / 0.45

≈ 4.22 m/s

The radial acceleration of the ball during its circular motion can now be found using the equation,

a = v^2 / r

a = v^2 / r = (4.22)^2 / 0.300 ≈ 59.4 m/s^2

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The correct option is (a) Cocoa beans are used to make cocoa.

Cocoa bean shapes during manufacture The dried and fully fermented seed of Theobroma cacao, usually known as the cocoa bean or simply cocoa, is where cocoa solids and cocoa butter are extracted.

The dried, fully fermented cacao grain known as Theobroma is what is commonly referred to as a cacao bean or a cocoa bean. Solids, a mixture of nonfat substances, and cocoa butter, or lard, can be extracted from Theobroma cacao. The chocolate and meals from Mesoamerica were made from these cacao beans. As a result, cacao beans are used to create chocolate.

Hence, cocoa is made from cocoa beans.

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Answer:

3.75m/s²

Explanation:

g= GM/r²

For planet 1

\(g_{1}\)= GM/r²                   (i)

\(g_{1}\) = 15m/s²

for planet 2

radius= 2*r= 2r

g= GM/r

\(g_{2}\)= GM/(2r)²

\(g_{2}\)= GM/4r²

\(g_{2}\)=  GM/r² *1/4

from (i)

\(g_{2}\)=  \(g_{1}\) *1/4

\(g_{2}\) = 15/4

\(g_{2}\) = 3.75m/s²

Answer: D. Increasing in randomness.

Explanation: The concept related to this change is entropy. Entropy is a measure of the randomness or disorder in a system. According to the second law of thermodynamics, the entropy of an isolated system tends to increase over time. This means that natural processes often lead to an increase in randomness or disorder.

For example, imagine a container of gas molecules. Initially, the molecules may be confined to one side of the container, creating a region of higher concentration. However, over time, the gas molecules will naturally spread out and become more evenly distributed throughout the container. This increase in randomness or disorder corresponds to an increase in entropy.

Answer:

It will apply the greatest pressure of an area of 1.

Explanation:

To find pressure use the formula P = F/A

P = 100/1

P = 100

Answer:

10 N / cm^2

Explanation:

The Formiula is P = F / A

P = presure

F = Force in Newtons

A = area.

The answer is the smaller the area the larger the pressure.

The smallest area you have given us is 10 cm^2

The Pressure = 100N / 10 cm^2

Pressure = 10 N/cm^2  

Note: the units are not exactly standard units, but I've given the answer the way the question offers the units.

The ∆G°vap of butane at 1 atm and 228.5 K is +3.6 kJ/mol.

The standard Gibbs free energy change of vaporization (∆G°vap) can be calculated using the following equation:

∆G°vap = ∆H°vap - T∆S°vap

where ∆H°vap is the standard enthalpy change of vaporization, ∆S°vap is the standard entropy change of vaporization, and T is the temperature in Kelvin.

Substituting the values given for butane at 1 atm and 228.5 K:

∆H°vap = 22.4 kJ/mol

∆S°vap = 82.3 J/(mol K)

T = 228.5 K

Converting the units of ∆S°vap to kJ/(mol K):

∆S°vap = 82.3 J/(mol K) / 1000 J/(kJ) = 0.0823 kJ/(mol K)

∆G°vap = (22.4 kJ/mol) - (228.5 K)(0.0823 kJ/(mol K))

∆G°vap = 22.4 kJ/mol - 18.8 kJ/mol

Therefore, the ∆G°vap of butane at 1 atm and 228.5 K is +3.6 kJ/mol.

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Answer:

Vf = final velocity = 1.96 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f}^{2}=v_{o}^{2}-2*g*x\)

where:

Vf = final velocity [m/s]

Vo = initial velocity = 9.98 [m/s]

g = gravity acceleration = 9.81 [m/s²]

x = vertical distance [m]

\(v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s]\)

Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.

Answer:

The answer is A good luck :P

Answer:

A

Explanation:

The light Bounces off because it is reflecting off glass or anything else

To solve this we must be knowing each and every concept related to variables. Therefore, because the evidence cards all represent variables, none of them should be deleted.

A variable is any trait, characteristic, number, or quantity that changes over time or may take on different values in different contexts (as contrast to constants, such as n, which do not change).

Magnetic pole configuration is a variable since its values can vary.

The quantity of coils is indeed a variable since it might have several numbers.

Rail material is indeed a variable since its values might vary.

The distance between the automobile and the launcher is flexible since it might take various values.

Therefore, because the evidence cards all represent variables, none of them should be deleted.

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Hi there!

Recall that:

∑F = ma

In the given situation, there is acceleration occurring in the horizontal direction, so there is a net force.

∑F = Fa (Force applied) - Fκ (Force due to kinetic friction)

We can plug in given values to solve for the frictional force:

ma = Fa - Fκ

(4)(1) = 8 - Fκ

4 = 8 - Fk

Fκ= 4N (negative since working opposite to acceleration)

Now, solve given the new force:

4a = 16 - 4

4a = 12

a = 3 m/s², Answer C.

The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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Answer:

D. Energy in an isolated system remains constant.

Explanation:

Energy can be defined as the ability (capacity) to do work. The two (2) main types of energy are;

a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.

Furthermore, the various forms of energy are solar energy, electrical energy, chemical energy, thermal energy, wind energy, nuclear energy etc.

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

According to the law of conservation of energy, we can infer or deduce that the total energy of the system must stay the same because it cannot be destroyed, but kinetic energy (KE) can be transformed to potential energy (PE) and potential energy (PE) can be transformed to kinetic energy (KE) within the system.

A vacuum line is attached to a fuel-pressure regulator on many port-fuel-injected engines to create an equal pressure drop across the injectors and ensure consistent fuel delivery. Therefore, Option B is the correct answer.

The vacuum line attached to the fuel-pressure regulator helps create an equal pressure drop across the injectors. This is necessary because the fuel injectors require a specific pressure to deliver the correct amount of fuel to the engine cylinders.

The fuel-pressure regulator's primary function is to maintain a steady fuel pressure within the fuel rail. By connecting the vacuum line to the regulator, the intake manifold's vacuum is used to counterbalance the fuel pressure. As engine load and throttle position change, the intake manifold's vacuum also varies, which in turn affects the fuel pressure delivered to the injectors.

The vacuum line helps ensure that the fuel pressure at the injectors remains consistent regardless of engine load. This is important for maintaining fuel efficiency, engine performance, and emission control. By providing an equal pressure drop across the injectors, the vacuum line helps deliver the correct fuel-air mixture for optimal combustion and engine operation.

Hence, the vacuum line attached to the fuel pressure regulator in port-fuel-injected engines plays a crucial role in maintaining consistent fuel pressure and ensuring proper fuel delivery to the engine's cylinders. Therefore, Option B is the correct answer.

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Answer:

yes 5 is greater

Explanation:

Answer: 5 grams is greater than 508 milligrams. Even though the number '508' is larger than '5,' you need to look at the units.

Answer:

50.2 meters

Explanation:

When an object falls, it goes a distance d in time t according to the formula:

\(d=\frac{1}{2}*g*t^{2}\)

d is the distance in meter, g is the acceleration due to gravity with the value of 9.8\(m/s^{2}\) , t is the time in seconds

Therefore, \(d = \frac{1}{2}*9.8*(3.2)^{2}\)

d= 50.176 ≈ 50.2m

Explanation:

To solve this problem, we can use the formula:

ΔL = αLΔT

where ΔL is the change in length, α is the linear expansivity coefficient of brass, L is the original length of the brass rod, and ΔT is the change in temperature.

Given:

α = 2.0 × 10^-5 K^-1 (linear expansivity coefficient of brass)

L = 10.0 m (original length of the brass rod)

ΔT = 41°C - 30°C = 11°C (change in temperature)

Using the formula:

ΔL = αLΔT

ΔL = (2.0 × 10^-5 K^-1) × (10.0 m) × (11°C)

ΔL = 0.0022 m

Therefore, the new length of the brass rod at 30°C will be:

L' = L + ΔL

L' = 10.0 m + 0.0022 m

L' = 10.0022 m

So, the new length of the brass rod at 30°C will be approximately 10.0022 meters.

The maximum height reached by the ball thrown by the boy is determined as 12.5 m.

The angle of projection of the ball is calculated as follows;

R = u²sin2θ/g

50 =  u²/9.8

u² = 50 x 9.8

u² = 490

u = 22.14 m/s

H = u²sin²θ/2g

H = (22.14² x (sin45)²)/(2 x 9.8)

H = 12.5 m

Thus, the maximum height reached by the ball thrown by the boy is determined as 12.5 m.

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