A+block+of+1.2kg+is+placed+on+an+included+plane+at+60°+to+the+horizontal.+Calculate.+a.The+force+that+will+make+the+block+to+slide+down+the+plane.B.The+coefficient+of+friction+.C.+The+normal+reaction+d.+The+friction+force

Answer:

shown below

Explanation:

1) P = F/A

P = 500 / 0.5

P = 1000N/m²

2) W = mg

W = 50 x 9.8

W = 490

P = F/A

P = 490 / 0.01

P = 49000N/m²

3) P = F/A

For E:

P = 40000 / 0.5

P = 80000N/m²

For W:

P = 600 / 0.0075

P = 80000N/m²

They're exerting the same amount of pressure on the ground

Answer:

horse rider

Explanation:

it will help in the future  and its fun

So the surface area of the portion of the semi-cone z = √x^2y^2 that lies between the planes z = 5 and z = 15 is 4π/3 [15^3 - (5/3)^3] - 4π/3 [5^3 - (5/3)^3], or approximately 1431.32 square units.

To find the surface area of the portion of the semi-cone z = √x^2y^2 that lies between the planes z = 5 and z = 15, we first need to determine the limits of integration.
We know that the semi-cone is symmetric about the z-axis, so we can limit our integration to the first octant, where x, y, and z are all positive. We also know that the semi-cone is bounded by the planes z = 5 and z = 15, so we can integrate with respect to z from z = 5 to z = 15.
Next, we need to express the surface area in terms of x and y. We can use the formula for the surface area of a surface of revolution:
A = 2π ∫ [f(x)] [(1 + [f'(x)]^2)1/2] dx
In this case, our function f(x) is the square root of x^2y^2, or f(x) = xy. So we have:
A = 2π ∫ [xy] [(1 + [y/x]^2)1/2] dx
Integrating this expression with respect to x from x = 0 to x = √(z^2 - y^2) gives us the surface area of the portion of the semi-cone between z = 5 and z = 15.
Finally, we can evaluate this integral using integration by substitution. After simplification, we get:
A = 4π/3 [z^3 - (5/3)^3]
So the surface area of the portion of the semi-cone z = √x^2y^2 that lies between the planes z = 5 and z = 15 is 4π/3 [15^3 - (5/3)^3] - 4π/3 [5^3 - (5/3)^3], or approximately 1431.32 square units.

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Quick Answer: Science Can’t Figure Out Why Our Bikes Don’t Fall Over When We Ride Th Some physicists thought that the spinning wheels of a bicycle create enough angular momentum

If a machine allows us to apply less force to do work, the cost is that we must apply the force over a greater distance.

The above is so because, according to the principle of work and energy, the amount of work done remains constant, but the force and distance can be traded off. In other words, if we decrease the force required to do a certain amount of work, we must increase the distance over which the force is applied in order to compensate.

Therefore, For example, consider a simple lever. By using a lever, we can apply less force to lift a heavy object, but we must move the lever over a greater distance in order to do so. The work done, which is the product of the force and the distance, remains constant. In this case, the force is reduced, but the distance over which it is applied is increased.

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Answer:

7657

Explanation:

b. FALSE

If the velocity of particle is high then they will collide with each other with a greater force because their momentum will be high

force is a push or pull on a body .

Momentum is the product of mass and velocity,

More the velocity, higher will be the momentum.

since force is  directly proportional to rate of change of momentum

F = Δp/Δt

so on when bodies having higher velocities collide their rate of change of momentum is higher hence more will be the force

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The tension required for the vibrating wire to produce its correct frequency of 4.1 kHz. is  187 N

The tension required for the vibrating wire can be calculated using the wave equation:

f = (1/2L) √(T/μ)

where f is the frequency of the vibrating wire, L is the length of the wire, T is the tension in the wire, and μ is the linear mass density of the wire (mass per unit length).

We can first calculate the linear mass density of the wire using its diameter and density:

μ = (π/4) d²ρ

= (π/4) (3.5 × 10⁻⁴ m)² (7.8 × 10³ kg m⁻³)

= 0.076 kg m⁻¹

Substituting the given values into the wave equation and solving for T:

T = (4π²μL²f²) / 1

= (4π²)(0.076 kg m⁻¹)(0.050 m)²(4.1 × 10³ Hz)²

= 187 N

Therefore, a tension of 187 N is required for the vibrating wire to produce its correct frequency of 4.1 kHz.

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Answer:126N

Explanation:

The equally spaced dots shows a car if it were accelerating constantly.

The term acceleration has to do with the rate of change of the velocity of a body with time. We know that velocity is a vector quantity. This implies that both the magnitude and the direction of the velocity are all important. The same goes for acceleration. The acceleration is a vector quantity so both its magnitude and direction are deemed as important.

Now we know that if the acceleration is uniform or constant, the velocity would increase by equal amounts in equal time intervals. We now have to check out to see the cases in which the image suggests that the velocity changes by equal amounts in equal time intervals.

Looking at the image as attached, the dots are equally spaced. The equal spacing of the dots shows us the way and manner in which the velocity of the car increases. Thus the image attached shows us that the velocity does increase by equal amounts in equal time intervals.

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Answer:

F=-50N

M=200kg

U=15m/s

F=Ma

a=F/M=-50/200=-0.25

V^2-U^2=2aS

0-(15)^2=2(-0.25)S

S=-225/-0.5=450m

V=U+at

0=15-0.25t

t=-15/-0.25=60s

Explanation:

Hope this helps, let me know if you have any questions!

Have a great day.

Answer:

C. 5.8 m/s

Explanation:

You just need to multiply the rate of gravity, 9.8 m/s/s, by 0.59, time. You would get 5.782 so you would round it up to 5.8

To determine the molar mass of the unknown gas, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

First, we need to convert the given pressure from mmHg to atm. Since 1 atm is equal to 760 mmHg, the pressure of 970 mmHg is equivalent to 1.276 atm.

Next, we need to convert the temperature from Celsius to Kelvin by adding 273.15. The temperature of 46 °C becomes 319.15 K.

Now, we can rearrange the ideal gas law equation to solve for n, the number of moles of the gas. Using the given pressure, volume, and temperature values, we have:

(1.276 atm) * (0.939 L) = n * (0.0821 L·atm/mol·K) * (319.15 K)

Simplifying the equation, we find:

n = (1.276 * 0.939) / (0.0821 * 319.15) = 0.0426 mol

Finally, we can calculate the molar mass of the unknown gas by dividing the mass of the sample by the number of moles:

Molar mass = (3.20 g) / (0.0426 mol) = 75.17 g/mol

Therefore, the molar mass of the unknown gas is 75.17 g/mol, rounded to two decimal places.

2. The number of grams of Krypton in the mixture is 25.48 g. This can be calculated as follows:

Step 1: Calculate the moles of methane (CH4):

Molar mass of methane (CH4) = 16.04 g/mol

Moles of methane = 11.1 g / 16.04 g/mol ≈ 0.691 mol

Step 2: Use the ideal gas law to calculate the moles of krypton (Kr):

Pressure (P) = 3.86 atm

Volume (V) = 7.60 L

Temperature (T) = 86 °C + 273.15 = 359.15 K

Ideal gas constant (R) = 0.0821 L·atm/(mol·K)

n = (PV) / (RT)

n = (3.86 atm * 7.60 L) / (0.0821 L·atm/(mol·K) * 359.15 K)

n ≈ 0.995mol

Step 3: Calculate the moles of krypton:

Moles of krypton = n - moles of methane

Moles of krypton ≈ 0.995 mol - 0.691 mol ≈ 0.304mol

Step 4:  Calculate the number of grams of krypton:

Grams of krypton = Moles of krypton × Molar mass of krypton

Grams of krypton = 0.304 moles × 83.80 g/mol

Grams of krypton ≈ 25.48 g

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Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.

Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500

Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000

a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units

Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units

b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production

Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit

Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit

c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production

Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700

Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300

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Answer:

Transverse waves

Explanation:

Light moves in waves. Light waves are different from sound waves in that light travels in transverse waves (as opposed to longitudinal, which is how sound waves travel). A light wave that travels in a direction is called a light ray.

The light waves travel as Transverse waves. Therefore, option (1) is correct.

Transverse waves can be defined as waves that usually oscillate along paths that are perpendicular to the direction in which the wave is traveling. Examples of transverse waves involve the vibration of the guitar, electromagnetic waves, water surface ripples, primary waves of the earthquake, and seismic S waves.

Particles of matter in a transverse wave, oscillate up and down about their mean location rather than follow the path of the transmission of the wave.

A transverse wave can be described as every particle of the medium traveling around its mean position in an opposite direction of the propagating direction of the wave.

Transverse waves can be produced in solids and on the surface of liquids. Transverse waves are not possible to create in liquids or gases. Therefore, electromagnetic waves or light waves travel as Transverse waves.

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Water has a freezing point of zero degrees and a boiling point of one hundred degrees on the Celsius temperature scale. A brine solution's freezing point is set at zero degrees Fahrenheit, while that of water is 32 degrees.

It comes in the forms of hail, frost, snow, and sleet. 0 degrees Celsius is the freezing point of water (32 degrees Fahrenheit). The molecules of water start to enlarge as the temperature approaches the freezing point.

The temperature at which a substance becomes liquid or solid is known as the melting or freezing point of that substance. Depending on the degree of bonding between the particles and their mass, different substances have varying melting points.

Water typically has a freezing point and melting point of 0 °C or 32 °F. If supercooling takes place or there are pollutants in the water that could cause freezing point depression to happen, the temperature may be lower. Water can remain a liquid at temperatures as low as -40 to -42°F under some circumstances.

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The new payment for the same trip, based on Earth time instead of taxi time, is approximately 11.5 sellers.

According to the problem, the rocket taxi moves at half the speed of light. Let's denote the speed of light as c.

The time dilation formula in special relativity is given by:

\(\(\Delta t' = \frac{\Delta t}{\sqrt{1 - \frac{v^2}{c^2}}}\)\)

Where:

\(\(\Delta t'\)\) is the time measured in the moving frame (rocket taxi)

\(\(\Delta t\)\)is the time measured in the stationary frame (Earth)

v is the velocity of the moving frame (rocket taxi)

c is the speed of light

In this case, the time measured in the taxi frame \((\(\Delta t'\))\) is one hour (60 minutes), and the velocity of the taxi (v) is half the speed of light \((c/2)\). We want to find the time measured in the Earth frame \((\(\Delta t\))\).

Plugging in the given values, we have:

\(\(\Delta t = \Delta t' \times \sqrt{1 - \frac{v^2}{c^2}}\)\)

\(\(\Delta t = 60 \times \sqrt{1 - \frac{(c/2)^2}{c^2}}\)\)

\(\(\Delta t = 60 \times \sqrt{1 - \frac{1}{4}}\)\)

\(\(\Delta t = 60 \times \sqrt{\frac{3}{4}}\)\)

\(\(\Delta t = 60 \times \frac{\sqrt{3}}{2}\)\)

\(\(\Delta t = 30 \sqrt{3}\)\)

Therefore, the time measured on Earth for the one-hour trip in the taxi is \(\(30 \sqrt{3}\)\) minutes.

Now, we need to calculate the new payment based on Earth time. We are given that the original payment for the one-hour trip in taxi time is 10 sellers.

If the taxi drivers' union demands that pay be based on Earth time instead of taxi time, the new payment will be proportional to the ratio of Earth time to taxi time.

\(\(\text{New payment} = \frac{\text{Original payment}}{\text{Taxi time}} \times \text{Earth time}\)\)

\(\(\text{New payment} = \frac{10 \text{ sellers}}{60 \text{ minutes}} \times (30 \sqrt{3} \text{ minutes})\)\)

\(\(\text{New payment} = \frac{10}{60} \times 30 \sqrt{3} \text{ sellers}\)\)

\(\(\text{New payment} = 0.1667 \times 30 \sqrt{3} \text{ sellers}\)\)

\(\(\text{New payment} = 5 \sqrt{3} \text{ sellers}\)\)

\(\(\text{New payment} \approx 8.66 \text{ sellers}\)\)

Rounding to the nearest seller, the new payment for the same trip would be approximately 9 sellers.

Hence, the new payment for the same trip, based on Earth time instead of taxi time, is approximately 11.5 sellers.

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21jir231uri21deqw21Answer:e

Explanation:

r1rm3k1rk21jkr21jikjr21kjkf21j

Answer:    7.94

7.94

Explanation: i got u

Two speakers, A and B, produce identical sound waves. A listener is 3.20 m from speaker A. The listener is  2.367 meters away from speaker B.

The distance between a listener and a speaker for constructive interference is given by:

Distance = (m × λ) ÷ 2

The speed of the sound is given by:

v = f × λ

Where:

v is the speed of sound

f is the frequency (72.4 Hz)

The wavelength obtained is:

λ = v ÷ f

λ = 343 ÷ 72.4

λ = 4.734 m

Since the listener is experiencing constructive interference, the order of interference (m) is likely 1:

Distance = (m × λ) ÷ 2

Distance = (1 × 4.734) ÷ 2

Distance = 2.367 m

Therefore, the listener is  2.367 meters away from speaker B.

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Answer

Yes.

Explanation:

20.43mg is equal to 0.02043g.

The net force acting on the box is 18 N

The net force acting on the box is the vector sum of forces f1 and f2. The net force is given by the formula:
F_net = F_1 + F_2

where F_net is the net force and F_1 and F_2 are the individual forces.

F_1 has a magnitude of 7 N and F_2 has a magnitude of 11 N. Therefore, the net force, F_net, has a magnitude of 18 N and can be expressed as:
F_net = 7 N + 11 N = 18 N

This means that the box is experiencing a net force of 18 N.

Imagine two arrows pointing in opposite directions, with the magnitude of each arrow indicating the magnitude of the respective force. When added together, the arrows should result in an arrow with a magnitude of 18 N.

This new arrow indicates the direction and magnitude of the net force acting on the box.

The net force is calculated by adding the vectors F_1 and F_2. This is done by adding the x and y components of each vector.

In this example, both F_1 and F_2 are in the same direction, so only the magnitudes are added to get the net force.

This is how it works: F_net = 7 N + 11 N = 18 N.

The net force acting on the box is 18 N and is the vector sum of forces f1 and f2.

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Answer:

Mono-chromatic, Poly-chromatic. When a wave moves from one medium into another at an angle other than 90 degrees the wave will change direction and continue to follow a new straight-line path

                                              Thank you

Streamflow is the flow of water in streams, rivers, and other channels, and is a key component of the water cycle. It's influenced by a variety of factors, including the shape and depth of the riverbed, the gradient of the stream, the size and shape of the channel, and the amount of water flowing through it. The given statement is false.It is affected by many factors.

All of these factors influence the velocity of the streamflow. Riverbed and streamflow relationshipThe velocity of streamflow is primarily influenced by the gradient or slope of the riverbed. A shallow slope will not yield high velocity streamflow, but instead will create a slow-moving, meandering stream with a high potential for sedimentation and erosion. In contrast, a steep gradient will create a fast-moving stream with a higher velocity and more turbulent water. As a result, a steeper slope will produce higher velocity streamflow than a shallower slope, which will produce slower-moving streamflow. Therefore, a riverbed with a shallow slope will not yield high velocity streamflow. The statement is false.

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It would take 1.556 seconds for the barrier to crumple and safely slow down the person with a force of 1180 N.

To calculate the time required to crumple the barrier and safely slow down the person, we can use the concept of impulse.

The impulse, denoted by J, is defined as the product of force and time, and it represents the change in momentum of an object. In this case, the impulse required to safely slow down the person can be calculated using the maximum force and the person's initial momentum.

The momentum of a person is given by the product of their mass and velocity:

Momentum = mass × velocity

Given that the person's mass is 68 kg and their velocity is 27 m/s, the initial momentum is:

Initial momentum = 68 kg × 27 m/s

To safely slow down the person, the impulse provided by the barrier should be equal to the change in momentum.

Therefore, we have:

Impulse provided by barrier = Final momentum - Initial momentum

Since the person is brought to rest, the final momentum is zero. Thus, we have:

Impulse provided by barrier = -Initial momentum

Now we can express the impulse in terms of force and time:

Impulse provided by barrier = Force × Time

Plugging in the known values, we can solve for time:

-Initial momentum = Force × Time

68 kg × 27 m/s = 1180 N × Time

Simplifying the equation, we find:

Time = (68 kg × 27 m/s) / 1180 N

Evaluating the expression:

Time = 1836 kg·m/s / 1180 N

Finally, converting kg·m/s to seconds, we get:

Time ≈ 1.5559 seconds

Therefore, it would take approximately 1.556 seconds for the barrier to crumple and safely slow down the person with a force of 1180 N.

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Answer:

A or B(the answers)

Explanation:

they seem like the most right

Answer:

I'm pretty sure it's b

Explanation:

Answer:

Approximately \(1.04 \; {\rm J \cdot g^{-1} \cdot K^{-1}}\).

Explanation:

Multiply energy input by efficiency to find the useful energy output:

\(\begin{aligned}& (\text{useful out}\text{put}) \\ &= (\text{efficiency})\, (\text{energy in}\text{put}) \\ &= (87.5\%)\, (1560\; {\rm kJ}) \\&= (0.875)\, (1560\; {\rm kJ}) \\ &= 1365\; {\rm kJ}\end{aligned}\).

In other words, \(1365\; {\rm kJ}\) of energy was supplied to the air in the building.

The standard unit of energy is Joules (\({\rm J}\).) Apply unit conversion:

\(\begin{aligned}(1365\; {\rm kJ})\, \left(\frac{10000\; {\rm J}}{1\; {\rm kJ}}\right) = 1.365\times 10^{6}\; {\rm J}\end{aligned}\).

Let \(c\) denote the specific heat capacity of the air in this building. Let \(m\) denote the mass of the air.

Let \(Q\) denote the energy supplied to the air. Let \(\Delta T\) denote the change in temperature. The equation \(Q = c\, m\, \Delta T\) relates these quantities.

In this question, the change in the temperature of the air in this building is:

\(\Delta T = (22.1\; {\rm ^{\circ} C}) - (11.6\; {\rm ^{\circ} C}) = 10.5\; {\rm K}\).

Rearrange the equation \(Q = c\, m\, \Delta T\) to find specific heat capacity \(c\):

\(\begin{aligned}c &= \frac{Q}{m\, \Delta T} \\ &= \frac{1.365 \times 10^{6}\; {\rm J}}{(125\; {\rm kg})\, (10.5\; {\rm K})} \\ &\approx 1.04 \times 10^{3}\; {\rm J \cdot kg^{-1} \cdot K^{-1}}\end{aligned}\).

The acceleration of the rocket has a velocity of 7.9 km/s is 0.79 m/s²

The velocity of the rocket = 7.9 km/s

The time taken by the rocket = 10 seconds

Acceleration can be found by dividing the velocity by time.

The acceleration of the rocket can be found using the formula,

                    a = v/t

where a is the acceleration of the rocket

           v is the velocity of the rocket

           t is the time taken

Let us substitute the known values in the above equation, we get

                  a = 7.9 / 10

                     = 0.79 m/s²

Therefore, the acceleration of the rocket is 0.79 m/s²

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Answer:

a = v^2 / R        where a is the centripetal acceleration and R the radius

v = 2 π R N / t        where (N / t) is the revolutions / sec giving distance / time

a = 4 g         horizontal acceleration

4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2

(N / t)^2 = g / (π^2 * R)

N / t = 1 /  π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2  = .352 / sec

The air pressure calculated using barometric formula at an elevation of 2000 meters is 0.068 MPa if the air pressure at sea level is 0.1 MPa.

Air pressure =  0.1 MPa

Elevation height = 2000 meters

The barometric formula is used to calculate the air pressure at an elevation of 2000 meters. Here the atmospheric pressure decreases when the elevation increases. The barometric formula is:

P = P₀ * exp(-M * g * h / (R * T))

P = pressure of altitude

P₀ = pressure at sea level

M = molar mass of Earth's atmoshpere = 0.02896 kg/mol

g =  acceleration due to gravity = 9.8 m/s²

h =  altitude height = 2000 m

R = ideal gas constant = 8.314 J/(mol·K)

T =  temperature of the air at a constant.

Substituting the values:

P = 0.1 MPa * exp(-0.02896 kg/mol * 9.8 m/s² * 2000 m / (8.314 J/(mol·K) * T))

T = 293K

P = 0.1 MPa * exp(-0.02896 kg/mol * 9.8 m/s² * 2000 m / (8.314 J/(mol·K) * 293 K))

P = 0.1 MPa * exp(0.2929808 / (8.314 J/(mol·K) * 293 K))

P =  0.1 MPa * exp(0.2929808 / 2436.002))

P  = 0.068 MPa

Therefore, we can conclude that the air pressure at an elevation of 2000 meters is 0.068 MPa.

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