A worker drops a wrench from the top of a tower 80 m tall. What is the velocity when the wrench strikes the ground? Round to the nearest 100ths place.

Answer:25N/

Explanation:

Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

\(I\) = \(\frac{1}{2}\)ε₀cE\(_{max\)²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E\(_{max\) is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E\(_{max\)  )

E\(_{max\) = 350/f kV/m

given that frequency of 60 Hz, we substitute

E\(_{max\) = 350/60 kV/m

E\(_{max\) = 5.83333 kV/m

E\(_{max\) = 5.83333 kV/m × ( \(\frac{1000 V/m}{1 kV/m}\) )

E\(_{max\) = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

\(I\) = \(\frac{1}{2}\)ε₀cE\(_{max\)²

\(I\) = \(\frac{1}{2}\) × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

\(I\) = 45 × 10³ W/m²

\(I\) = 45 × 10³ W/m² × ( \(\frac{1 kW/m^2}{10^3W/m^2}\) )

\(I\) = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Laboratory experiments on Earth have examined that each element in the periodic table emits photons only at definite wavelengths (determined by the excitation state of the atoms).

These photons are manifest as either emission or absorption lines in the spectrum of an astronomical object, and by observing the position of these spectral lines, we can detect which components are present in the object itself or along the line of sight.

although, when astronomers observe spectral lines in extragalactic objects (such as galaxies and quasars), they find that the wavelength of the notice spectral lines is different from the laboratory experiments.

In most cases, the wavelength of the spectral lines is longer and thus are shifted toward the red end of the spectrum they are redshifted.

There are many explanations for this redshift phenomenon.

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Answer:

Explanation:

Let the separation required be d .

Force between rod = 10⁻⁷ x  2 I₁ I₂ L / d

where I₁ and I₂ are current in them , d is distance of separation and L is length of wire .

Force between rod = 10⁻⁷ x  2 x 1200 x  1200 x .69  / d

= .1987 /d

Restoring Force by spring = k x where k is force constant and x is compression .

= 130 x .03

= 3.9 N

For balancing

Restoring Force by spring = Force between rod

.1987 /d = 3.9

d = .1987 /3.9

= .0509 m

= 5.09 cm .

Answer:

Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction.

Explanation:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

when two body interact.........

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

How do digital signals work?

An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.

Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

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Answer:

Explanation:

To find the current flowing in the circuit, we can use Ohm's Law and Kirchhoff's circuit laws.

Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V / R

In this case, the voltage (V) is the electromotive force (EMF) of the current source, which is 14 V. The total resistance (R) in the circuit is the sum of the internal resistance (r) and the resistances of the two resistors (R1 and R2):

R = r + R1 + R2

Given that the internal resistance (r) is 1Ω and each resistor (R1 and R2) has a resistance of 3Ω, we can substitute these values into the equation:

R = 1Ω + 3Ω + 3Ω = 7Ω

Now we can calculate the current (I):

I = V / R = 14 V / 7Ω = 2 A

Therefore, the current flowing in the circuit is 2 Amperes.

Answer:

I = ΔVA[1 - α (T₀ - T)]/Lρ₀

Explanation:

We have the following data:

ΔV = Battery Terminal Voltage

I = Current through wire

L = Length of wire

A = Cross-sectional area of wire

T = Temperature of wire, when connected across battery

T₀ = Reference temperature

ρ = Resistivity of wire at temperature T

ρ₀ = Resistivity of wire at reference temperature

α = Temperature Coefficient of Resistance

From OHM'S LAW we know that;

ΔV = IR

I = ΔV/R

but,  R = ρL/A   (For Wire)

Therefore,

I = ΔV/(ρL/A)

I = ΔVA/ρL

but,   ρ = ρ₀[1 + α (T₀ - T)]

Therefore,

I = ΔVA/Lρ₀[1 + α (T₀ - T)]

I = [ΔVA/Lρ₀] [1 + α (T₀ - T)]⁻¹

using Binomial Theorem:

(1 +x)⁻¹ = 1 - x + x² - x³ + ...

In case of [1 + α (T₀ - T)]⁻¹, x = α (T₀ - T).

Since, α generally has very low value. Thus, its higher powers can easily be neglected.

Therefore, using this Binomial Approximation, we can write:

[1 + α (T₀ - T)]⁻¹ = [1 - α (T₀ - T)]

Thus, the equation becomes:

I = ΔVA[1 - α (T₀ - T)]/Lρ₀

The increase in tension on the steel wire is 8,484.75 N.

The given parameters;

The area of the steel wire is calculated as follows;

\(A = \pi r^2\\\\A = \pi \times (2\times 10^{-3})^2\\\\A = 1.257 \times 10^{-5} \ m^2\)

The extension of the steel wire is calculated as follows;

\(\Delta l = \alpha \times l\times \Delta T\\\\\Delta l = (12\times 10^{-6}) \times (8) \times (10 + 273)\\\\\Delta l = 0.027 \ m\)

The increase in tension on the steel wire is calculated as follows;

\(E = \frac{stress}{strain } = \frac{\ F/A}{\Delta l/l} \\\\E = \frac{F\times l}{A \times \Delta l} \\\\F = \frac{E\times A \times \Delta l }{l} \\\\F = \frac{(2\times 10^{11}) \times (1.257\times 10^{-5})\times 0.027}{8} \\\\F = 8,484.75 \ N\)

Thus, the increase in tension on the steel wire is 8,484.75 N.

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Answer:

What are the four contributing factors that may lead to an increase of learners abusing substances in school?

Peer pressure. ...

Socializing.

Community.

Socioeconomic status.

Stress.What are the four contributing factors that may lead to an increase of learners abusing substances in school?

Peer pressure. ...

Socializing.

Community.

Socioeconomic status.

Stress.What are the four contributing factors that may lead to an increase of learners abusing substances in school?

Peer pressure. ...

Explanation:

Answer:

The position of the arrows will not be on the target i.e. outside the bull's eye, neither will they be close to one another (widely scattered).

Explanation:

Accuracy refers to the closeness of a measurement to an actual or accepted value while precision refers to the closeness of measurements to one another.

Using archery as an illustration of precision and accuracy, measurements (arrows) that are neither accurate not precise are those arrows that will be far away or outside the bull's eye region (target) of the board and also far apart from one another.

In a nutshell, the arrows will be distant from the bull's eye or target (not accurate) and also distant from one another (not precise).

Answer:

Speed v = 2.04 m/s

the speed at which gasoline moves through the fuel line is 2.04 m/s

Explanation:

Given;

Mass transfer rate m = 5.37x10^-2 kg/s.

Density d = 739 kg/m3

radius of pipe r = 3.37x10^-3 m

We know that;

Density = mass/volume

Volume = mass/density

Volumetric flow rate V = mass transfer rate/density

V = m/d

V = 5.37x10^-2 kg/s ÷ 739 kg/m3

V = 0.00007266576454 m^3/s

V = 7.267 × 10^-5 m^3/s

V = cross sectional area × speed

V = Av

Area A = πr^2

V = πr^2 × v

v = V/πr^2

Substituting the given values;

v = 7.267 × 10^-5 m^3/s/(π×(3.37x10^-3 m)^2))

v = 0.203678639672 × 10 m/s

v = 2.04 m/s

the speed at which gasoline moves through the fuel line is 2.04 m/s

Answer:

All the statements above are true for martin and his brother in the book "My Brother Martin".

The late Dr. Martin Luther King Jr.'s older sister and renowned educator Christine King Farris collaborate with renowned illustrator Chris Soentpiet to tell this "outstanding" (School Library Journal) and motivational tale of how a boyhood event sparked a movement that would alter the course of history. In "My Brother Martin," Martin Luther King tells us what it was like to be a young kid of seven. Martin Luther King Jr. was a little boy who played jokes, practised the piano, and made friends without taking race into consideration long before he rose to fame as a global visionary.

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The complete question is missing, so i have attached the complete question.

Answer:

A) FBD is attached.

B) The condition that must be satisfied is for ω_min = √(g/r)

C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).

Explanation:

A) I've attached the image of the free body diagram.

B) The formula for the net force is given as;

F_net = mv²/r

We know that angular velocity;ω = v/r

Thus;

F_net = mω²r

Now, the minimum downward force is the weight and so;

mg = m(ω_min)²r

m will cancel out to give;

g = (ω_min)²r

(ω_min)² = g/r

ω_min = √(g/r)

The condition that must be satisfied is for ω_min = √(g/r)

C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).

Answer:

Material that allow the electrons to move freely in order to produce a current

Please mark as brainliest if answer is right

Have a great day, be safe and healthy  

Thank u  

XD  

Answer:

We can solve for the magnitude of vector C by first isolating it on one side of the equation:

2A - 6B + 3C = 2j

3C = 2j - 2A + 6B

C = (2/3)j - (2/3)A + 2B

Now that we have an expression for vector C, we can find its magnitude using the formula:

|C| = sqrt(Cx^2 + Cy^2 + Cz^2)

where Cx, Cy, and Cz are the x, y, and z components of vector C, respectively.

Since the equation only gives us information about the y-component of vector C, we can assume that the x and z components are zero. Therefore,

Cx = 0

Cy = 2/3

Cz = 0

|C| = sqrt((0)^2 + (2/3)^2 + (0)^2)

|C| = sqrt(4/9)

|C| = 2/3

Therefore, the magnitude of vector C is 2/3.

The time period and frequency of the glider are found to be 3.7 second and 0.27 Hz respectively.

The air glider is oscillating between the 3.00 cm marl and 59.0 cm mark.

It is given that the air glider completes 10 oscillations in 37.0 seconds.

So, in order to find the time period of the oscillation, we can write,

Time taken by glider to complete 10 oscillations = 37 seconds.

Time taken by glider to complete 1 oscillation = 37/10 seconds.

Time taken by glider to complete 1 oscillation = 3.7 seconds.

So, the time period of oscillation of the glider is 3.7 seconds.

Now, the frequency of the air glider will be,

f = 1/T

Where,

T is the time period,

So, putting values,

f = 1/3.7 Hertz

f = 0.27 Hz.

So, the frequency of the air glider is 0.27 Hz.

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Complete question - an air-track glider attached to a spring oscillates between the 3.00 cm mark and the 59.0 cm mark on the track. the glider completes 10.0 oscillations in 37.0 s. Find the a. Time period b. Frequency.

Answer:

2.12m/s

Explanation:

Given parameters:

Force on trolley  = 1.5N

Mass of trolley  = 0.2kg

Unknown:

Velocity of the trolley  = ?

Solution:

To solve this problem, we first find the acceleration of the trolley;

          Force  = mass x acceleration

         Acceleration  = \(\frac{Force }{mass}\)

Insert the parameters and solve;

          Acceleration  = \(\frac{1.5}{0.2}\)   = 7.5m/s²

Now to find the acceleration;

  Initial velocity  = 0m/s

  v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

  Distance  = 30cm and this is 0.3m

     v² = 0² + 2(7.5)0.3  = 4.5

     v = √4.5 = 2.12m/s

The impulses and changes in momentum are identical because equal forces are applied over equal periods of time.

The momenta of the two carts are identical since they both begin at rest and experience equal changes in momentum. We are aware that force is the same as mass multiplied by acceleration. Due to the initial resting state of both carts, u = 0 m/s, and the plastic cart moves 1 m. Newton's second law states that when the same force is applied to the two carts, the plastic cart will have more final momentum than the lead cart because of the momentum principle. Newton's third law states that every object feels the same force for the same length of time, which results in the same impulse and consequent change in momentum.

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Due to equivalent forces being delivered over equal times, the impulses and changes in momentum are identical.

The acceleration is determined by dividing the net force by the mass. An object's acceleration doubles if the net force exerted on it also doubles. Increased mass will result in a halving of acceleration.

Second Law of Motion: Force In accordance with his second law, a force is defined as the change in momentum (mass times velocity) per change in time. The definition of momentum is the product of the mass m and the velocity V of an object.

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Explanation:

p = mv

26 kg m/s = (6.5 kg) v

v = 4 m/s

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Answer:

Explanation:

Please post if there is a graph showing the data.

Without a graph, in general the trend can be described as:

"positive" when the dependent variable increases with an increase in independent variable

"negative" when the dependent variable decreases with an increase in independent variable

"neutral" when the dependent variable remains the same with an increase or decrease in independent variable

Answer: Solubility; decreasing

Explanation:

Given:

Weight of arm = 42.3 N

Let's determine the magnitude of the tension force in the deltoid muscle force exerted by the shoulder.

Here, we are to find Ft and Fs.

To solve for Ft, take the equation for the sum of forces about point O.

We have:

Rewrite the equation for Ft and evaluate:

Therefore, Ft = 737.51 N

Now, for the sum of vertical forces, we have:

• For the sum of horizontal forces, we have:

Now, we have the equations:

Combine both equations:

Square all terms:

Solving further:

Take the square root of both sides:

ANSWER:

• Ft = 737.51 N

• Fs = 730.53 N

Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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