A wildebeest runs with an average speed of
4.0
 
m
s
4.0
s
m
​
What was its distance travelled in meters?

For the magnetic fields:

From Faraday's law of electromagnetic induction, the emf induced in the wire is given by:

emf = -dΦ/dt

where Φ is the magnetic flux through the wire. The negative sign indicates that the induced emf opposes the change in magnetic flux.

The magnetic flux through each of the three regions can be calculated as follows:

Φ₁ = B₁WH/3

Φ₂ = B₂WH/3

Φ₃ = BWH/3

The total magnetic flux through the wire is:

Φ = Φ₁ + Φ₂ + Φ₃ = (B₁ + B₂ + B)WH/3

Taking the time derivative of the magnetic flux:

dΦ/dt = (B₁ + B₂ + B)(WH/3)(dB/dt)

Substituting the given values:

dΦ/dt = (3.00 μT + 2.50(3.00 μT))(0.23 m)(0.31 m)(1.00 m)/(3)(0.010 s) = 0.215 V

The induced emf is equal to the product of the current and the resistance of the wire:

emf = IR

Solving for I:

I = emf/R = 0.215 V / 4.00 mΩ = 53.8 A

The direction of the induced current can be determined using Lenz's law, which states that the direction of the induced current is such that it opposes the change in magnetic flux that produced it. In this case, the induced current will produce a magnetic field that opposes the change in the magnetic field through the wire.

As the magnetic field increases in the downward direction, the induced current will produce a magnetic field in the upward direction to oppose the increase. As the magnetic field decreases in the downward direction, the induced current will produce a magnetic field in the downward direction to oppose the decrease.

Therefore, the direction of the induced current will be counterclockwise.

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The correct statements for the focal point of a converging lens are:

A) A light ray entering parallel to the optical axis passes through the focal point on the other side of the lens.

C) A light ray passing through the focal point as it enters the lens goes through the focal point on the other side of the lens.

D) A light ray passing through the focal point as it enters the lens and exits the lens parallel to the optical axis.

A converging lens is a particular kind of lens that bends light in such a way that parallel light rays unite at a single focal point. Light bends towards the center of the lens because of its shape, which has a thicker center and a thinner edge. A distinct image is created at the focal point, which is where all of the refracted light converges. Common applications for this kind of lens include magnifying glasses, cameras, telescopes, and other optical equipment. Converging lenses—also known as convex lenses—may produce sharp, enlarged pictures because they can combine light. Converging lenses can be recognized by their form; they have a center that is rather thick.

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Answer:

it will stay still. unless its in space.

Explanation:

Answer:

200

Explanation:

20m/s*10sec=200

ANSWER:

STEP-BY-STEP EXPLANATION:

We have that the total energy is given by the following formula:

We replace and calculate the total value of the energy:

Graphical analysis of motion gives the graphical the relationships between position, velocity, and acceleration, versus time

2. Please find attached the required position versus time and acceleration versus time graphs

3. Please find attached the required velocity versus time and position versus time graphs

The reasons the attached graphs are correct are given as follows:

2. The given coordinates of the vertex points obtainable from the graph is first written as follows:

\(\begin{array}{|c|c|c|c|c|}\underline {Time, \ t}&\underline {Velocity, \ v}&Acceleration, a&\underline {Distance , \ s =v\cdot \Delta t+\dfrac{1}{2} \cdot a \cdot (\Delta t)^2}&Position\\0&-1&0&0&0\\2&1&1&0&0\\4&-1&-1&0&0\\6&1&1&0&0\\10&1&0&4&4\\12&0&-0.5&1&5\end{array}\)The distance covered between time intervals of time, s, is given as follows;

\(s = v \cdot \Delta t + (1/2) \cdot a \cdot ( \Delta t)^2\)

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Other values on the graph obtained by calculation on a spreadsheet are;

\(\begin{array}{|l|cl|}Time \ (s)&&Position \ (m)\\0.5&&-0.375\\1&&-0.5\\1.5&&-0.375\\2.5&&0.375\\3&&0.5\\3.5&&0.375\\4.5&&-0.375\\5&&-0.5\\5.5&&-0.375\\6.5&&0.5\\7&&1\\7.5&&1.5\\8&&2\\8.5&&2.5\\9&&3\\10&&4\\10.5&&4.4375\\11&&4.75\\11.5&&4.9375\\12&&5\end{array}\right]\)

Please find attached the acceleration versus time graph

3. The coordinates of the points are presented as follows:

\(\begin{array}{|c|cc|}\underline{Time\ (s)}&&\underline{Acceleration\ (m/s^2)}\\0&&0.5\\2&&0.5\\2&&0\\4&&0\\4&&-0.5\\6&&-0.5\\6&&0\\8&&0\\8&&0.5\\10&&0.5\\10&&-0.5\\12&&-0.5\end{array}\right]\)

The distance covered between time intervals, s, is given as follows;

\(s = v \cdot \Delta t + (1/2) \cdot a \cdot ( \Delta t)^2\)

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Using a spreadsheet application, more detailed values of the position can be found as shown in the graph created with MS Excel

0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6, 6.5, 7, 7.5, 8, 8.5, 9, 9.5, 10, 10.5, 11, 11.5, 12

0, 0.06, 0.25, 0.56, 1.00, 1.50, 2, 2.5, 3, 3.5, 3.81, 4.00, 4.06, 4.06, 4.06, 4.06, 4.06, 4.13, 4.31, 4.63, 5.06, 5.50, 5.81, 6, 6.06

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The given vectors E and F are in Cartesian form. To find their magnitudes, we can use the formula:

|v| = √(vx² + vy²)

where vx and vy are the x and y components of the vector.

Cartesian algebra, also known as coordinate algebra or analytic geometry, is a branch of mathematics that deals with the use of algebraic equations to describe geometric shapes and their properties. It is named after the French philosopher and mathematician René Descartes, who developed the Cartesian coordinate system, which provides a way to describe the position of points in space using numbers.

A. Magnitude of E:

|E| = √((3i)² + (1j)²)

= √(9i² + 1j²)

= √(9 + 1)

= √(10)

Therefore, the magnitude of E is √(10).

B. Magnitude of F:

|F| = √((1i)² + (-3j)²)

= √(1 + 9)

=√(10)

Therefore, the magnitude of F is √(10).

C. Magnitude of G = E + F:

G = E + F = (3i + 1i) + (1j - 3j)

= 4i - 2j

|G| = √((4i)² + (-2j)²)

=√(16 + 4)

= √(20)

= 2√(5)

Therefore, the magnitude of G is 2√(5).

D. Magnitude of H = -E - 2F:

H = -E - 2F = (-3i - 2i) + (-1j + 6j)

= -5i + 5j

|H| = √(-5i)² + (5j)²)

= √(25 + 25)

= √(50)

= 5√(2)

Therefore, the magnitude of H is 5√(2).

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Answer: x=14

Explanation:

there is 90° in a right angle so

(4x)+(2x+6) =90

collect like terms

6x+6=90

 -6 from both sides

6x=84

 ÷6

x=14

When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

Velocity and displacement are the two quantities that increases as the other decreases during simple harmonic motion.

If a body's velocity at any given moment is inversely proportional to its displacement from the mean position, its motion is said to be simple harmonic.

Angular harmonic frequency and time t are functions that can be used to explain simple harmonic motion:

Displacement from equilibrium has amplitude A:

x = Asin(ωt)

and velocity has amplitude ωA

v = dx/dt = ωAcos(ωt)

At ωt = 0, x = 0 while v = Aω (max).

At ωt = π/2, x = A (max) while v = 0.

As a result, v reaches it's maximum /2 (90°) before x does. Therefore, displacement follows velocity at a 90° angle.

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Answer:

rooting reflex

Explanation:

prettysure

Answer:

0.032 \(m/s^2\)

Explanation:

Given :

Weight of the astronaut = 69 kg

Weight of the physics book = 28 kg

Acceleration of the astronaut = 0.0130 \(m/s^2\)

The force that is applied on the astronaut :

\(F=ma\)

   \($=69 \times 0.013$\)

   = 0.897 N

Therefore, by Newton's 3rd law, we know that the force applied on the physics book is also F = 0.897 N

Therefore, the acceleration of the physics book is given by :

\($a = \frac{\text{Force on physics book}}{\text{mass of physics book}}$\)

\($a = \frac{0.897}{28}$\)

a = 0.032 \(m/s^2\)

Hence, the acceleration of the physics book is  0.032 \(m/s^2\).

Answer:

The acceleration of astronaut is 5.27 x 10^-3 m/s^2.

Explanation:

mass of astronaut, M = 69 kg

Mass of book, m = 28 kg

acceleration of book, a = 0.013 m/s^2

Let the acceleration of astronaut is A.

According to the Newton's third law, for every action there is an equal and opposite reaction.

So, the force acting on the book is same as the force acting on the astronaut but the direction is opposite to each other.

M A = m a

69 x A = 28 x 0.013

A = 5.27 x 10^-3 m/s^2

Answer:

4.545454 seconds

Explanation:

1500/330=4.545454 seconds

Answer:

4.5

Explanation:

the whole number 4.54 repeating

9038 kJ of heat is absorbed by the air assuming some air escapes through the cracks as the heated air in the house expands at constant pressure, and cost of this heat if the unit cost of electricity in that area is $0.075/kWh is $0.19.

In the physical sciences, pressure is defined as the perpendicular force per unit area or the stress at a point within a confined fluid.

A 42-pound box with a bottom area of 84 square inches will press down on a surface with a pressure equal to the force divided by the area over which it is applied, or half a pound per square inch.

The specific heat of air at room temperature is

\(C_p\) = 1.007 kJ/kg⋅°C              

The volume and mass of the air in the house are

V = Floor space × height

   = (200 m² )(3m)

   = 600 m ³

Mass = PV/RT

         = \(\frac{(1013 kPa)(600 m^3 )}{(0287 kPa.m/kg.K)(10+273.15 K)}\)

         = 7479 kg

The amount of heat that must be transferred to the air in the house as it is heated from 10 to 22°C is calculated, taking into account that the pressure in the house remains constant during heating, as follows:

Q = \(mC_p\) \((T_2 - T_1)\)

   = (747.9 kg)(1.007 kJ/kg⋅ °C)(22 – 10) °C

   = 9038 kJ

Noting that 1 kWh = 3600 kJ, the cost of this electrical energy at a unit cost of $0.075/kWh is

Enegy Cost = (Energy used)(Unit cost of energy)

                    = (9038/3600 kWh)($0.075/kWh)

                    =  $0.19

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Answer:

I think its d

Explanation:

I'm not sure I'm sorry if I'm wrong

The third law of motion defined the action and reaction force that the heavy ball should be fall at the same kind of the speed.

It defined that at the time when the two bodies should be interacted so here the forces should be applied to one another that should be equivalent to the magnitude also the direction should be opposite.

Also, we can called as the action law and the reaction.

Therefore, we can conclude that the third option is correct.

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Therefore, the power of the porter is 441,450 J/s, or approximately 441.5 watts.

The work done by the porter in lifting the 50 kg bag up the stairs can be calculated as the product of the force applied and the distance moved.

The force applied is the weight of the bag, which is given by:

F = m * g

where m is the mass of the bag and g is the acceleration due to gravity, which is approximately 9.81 m/s². Substituting the given values, we get:

F = 50 kg * 9.81 m/s²

F = 490.5 N

The distance moved by the porter in lifting the bag up one staircase is 30 cm, and the porter climbs 10 staircases in 10 seconds, which gives a speed of:

v = (10 * 30 cm) / 10 s

v = 30 cm/s

The power of the porter is the rate at which work is done, which can be calculated as:

P = W / t

where W is the work done and t is the time taken. Substituting the values, we get:

P = F * d * v / t

P = 490.5 N * 10 * 30 cm * 30 cm/s / 10 s

P = 441,450 J/s

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Answer:

C. 5730 years

Explanation:

N(t) = N(0)e^-kt

The half-life is T = 5730 years,

e^-kT = 1/2

→ k = - ln(1/2) / T

→ - ln(1/2) / 5730

→ 1.209681 x 10^-4 years^-1

The amount present dropped to 50%.

Then one half-life has elapsed, so the age is 5730 years.

Answer: B, increase the rate at which he turns the crank

Explanation: i got it right

The electric field strength at the point where 50 µC charge experienced an attractive force of 2.0 N is 4×10⁴ N/C

This is simply defined as the force per unit charge. Mathematically, it is expressed as:

E = F / Q

Where

From the question given above, the following data were obtained:

E = F/Q

E = 2 / 50×10¯⁶

E = 4×10⁴ N/C

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

Measurement is the comparison of any physical quantity of an object to a standard unit which is pre-determined. The standard units such as length, time, mass etc are known as the Fundamental units of Measurement.

Explanation:

Any object that can be measured is known as a physical quantity. So, to measure the physical quantity, we require some standard units. A measurement consists of two parts - the numerical measurement and the standard unit which is pre-determined. For example, the length of a given table is 10cm, which implies that 10 is the numerical value and the standard unit of measurement is centimeter (cm).

Measurements can be both Fundamental and Derived. Examples of Fundamental quantities are Length, Time etc, while example of Derived quantity is speed which is derived from Length and Time.

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(a)

Potential Energy  = 4.95 J

Kinetic Energy =0.132 J

b.) the total mechanical energy of the ball before Hanif spikes it is 5.08 J.

Potential energy (PE) = mgh

Kinetic energy (KE) = (1/2)mv^2

m = 0.226 kg

h = 2.29 m

v = 1.06 m/s

g = 9.81 m/s^2 (acceleration due to gravity)

PE = mgh = (0.226 kg)(9.81 m/s^2)(2.29 m) = 4.95 J

KE = (1/2)mv^2 = (1/2)(0.226 kg)(1.06 m/s)^2 = 0.132 J

(b) The total mechanical energy of the ball before Hanif spikes it is the sum of its potential and kinetic energy:

Total mechanical energy = PE + KE = 4.95 J + 0.132 J = 5.08 J

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The coefficient of kinetic friction between the chair and the waxed floor, does she just reach the glass without knocking it over is,

\(\mu_k\)= Coefficient of kinetic friction = 0.102

The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between the two surfaces.

Greek letter mu (μ) is typically used to represent it. In mathematics, is equal to F/N, where F is the frictional force and N is the normal force.

The coefficient of friction is dimensionless because both F and N are expressed in units of force (such as newtons or pounds).

For both static and kinetic friction, the coefficient of friction has different values. When an object experiences static friction, the frictional force resists any applied force, and the object stays at rest until the static frictional force is removed.

Using Energy conservation:

KEi + PEi + Wf = KEf + PEf

KEi = 0, since initially Albertine was at rest

KEf = 0, since finally Albertine need to be at rest to just reach the glass

PEi = (1/2)*k*x^2 = Initial Potential energy due to compression of spring

PEf = 0 (since at final position compression in spring is zero)

Wf = Work-done by friction = Ff×d = -μκ*m*g*d

So,

0 + (1/2)*k*x^2 -\(\mu_k\)*m*g*d = 0 + 0

\(\mu_k\)= k*x^2/(2*m*g*d)

Using given values:

\(\mu_k\) = 95.0*5.00^2/(2*60.0*9.80*19.8)

\(\mu_k\)= Coefficient of kinetic friction = 0.102

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Given that length of pendulum is 45 cm

Let T be the time period then the formula to find T will be

Here, g is the acceleration due to gravity which is equal to 9.8 m/s^2.

Substituting the values, we get

Hence, the time period will be 13.45 seconds.

Answer:

im not 100 percent but its probably 2 turtles 20m apart

Answer:

The magnitude of the vector addition is approximately 10.38

Explanation:

Recall that the vectors add easily in component form, just by adding component by component:

A = (6.7, -2.3)

B = (-5.5, 4.5)

C = (3.2, 7.2)

A + B + C = (6.7- 5.5 + 3.2, -2.3 + 4.5 + 7.2 ) = (4.4, 9.4)

Then, this vector's magnitude is calculated via:

\(\sqrt{4.4^2+9.4^2} \approx 10.38\)

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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