12.8 rad
Explanation:
The angular displacement \(\theta\) through which the wheel turned can be determined from the equation below:
\(\omega^2 = \omega_0^2 + 2\alpha\theta\) (1)
where
\(\omega_0 = 0\)
\(\omega = 34.7\:\text{rad/s}\)
\(\alpha = 47.0\:\text{rad/s}^2\)
Using these values, we can solve for \(\theta\) from Eqn(1) as follows:
\(2\alpha\theta = \omega^2 - \omega_0^2\)
or
\(\theta = \dfrac{\omega^2 - \omega_0^2}{2\alpha}\)
\(\:\:\:\:= \dfrac{(34.7\:\text{rad/s})^2 - 0}{2(47.0\:\text{rad/s}^2)}\)
\(\:\:\:\:= 12.8\:\text{rad}\)
Lucy took 3 hours to cover 2/3 of a journey. She covered the remaining 60 miles in 2 hours. What was the average speed for the whole journey?
The correct answer is 36 miles per hour
Explanation:
To find the average speed, the first step is to find the total time and the total distance Lucy covered because the formula for average speed is the total distance divided into the total time.
Total Distance
It is known Lucy covered 2/3 of the total distance first, and then she completed the remaining distance (60 miles). According to this, the last distance or 60 miles represents 1/3 of the total distance.
\(\frac{2}{3} + \frac{1}{3} = \frac{3}{3}\) (Total distance)
Also, if 60 miles is equivalent to 1/3 this number can be used to find the total distance. In this case, just multiply 60 by 3 = 180 miles as 60 is one-third.
This means the total distance is 180 miles
Total Time
It is known the first part of this journey took 3 hours and the second took 2 hours. This means the total time was 5 hours (3 + 2 = 5)
Find the average speed
\(Average speed =\frac{Distance}{time}\)
\(Average speed = \frac{180 m}{5 h}\)
\(Average speed = 36m/h\)
Suppose the voltage source for a series RL-circuit were given as V0sin(ωt) instead of V0cos(ωt). Write an expression for the current amplitude in terms of V0, ω, R, and L.
Required:
a. Calculate the current amplitude, in milliamperes, when V0= 1.9 V, ω = 51 rad/s, R = 21 Ω, and L = 0.52 H.
b. Calculate the phase constant, in radians in the range -π/2 ≤ φ ≤ π/2, for the circuit parameter values given in part (b).
Answer:
Explanation:
This is an RL circuit, therefore:
Impedance; z = \(\mathbf{\sqrt{R^2+L^2}}\)
\(\mathbf{z = \sqrt{R^2+(Lw)^2}}\)
Current amplitude
\(\mathbf{I_o = \dfrac{V_o}{z}} \\ \\ \mathbf{I_o = \dfrac{V_o}{\sqrt{R^2+L^2\omega ^2}}}\)
a)
Given that:
\(V_o = 1.9 \ V \\ \\ \omega= 51 \ rad/s\\\\ R = 21 \Omega \\ \\ L = 0.52 H\)
∴
\(I_o= \dfrac{1.9}{\sqrt{21^2+(0.52\times 51)^2}}\)
\(\mathbf{I_o= 0.0562} \\ \\ \mathbf{I_o = 56.2 \ mA}\)
b)
Phase constant :
\(tan \ \phi = \dfrac{L \omega}{R } \\ \\ tan \ \phi = \dfrac{0.52 \times 51}{21} \\ \\ tan \phi = 1.263\)
\(\text{Phase constant : }\phi = tan^{-1} (1.263) \\ \\ \phi = 51.6^0\\ \\\text{To radians} \phi = 51.6 \times \dfrac{\pi}{180} \\ \\ \phi = 0.287 \pi \\ \\ \mathbf{\phi = 0.9 \ rad}\)
(a)The value of current amplitude will be 56.2 milliamperes.
(b)The value of the phase constant will be 0.9 rad.
What is an RL circuit?RL Circuits often known as RL networks or RL filters are a form of a circuit that uses a mix of inductors and resistors and is powered by a source of electricity.
The given data in the problem is;
I₀ is the current amplitude =?
V₀= 1.9 V
ω is the angular velocity = 51 rad/s
R is the resistance in the circuit = 21 Ω
Ф is the phase constant=?
(a) The value of current amplitude will be 56.2 milliamperes.
The formula for the current amplitude is given as;
\(\rm I_0= \frac{V_0}{\sqrt{R^2+L^2 \omega^2} } \\\\\)
\(\rm I_0= \frac{1.9}{\sqrt{(21)^2+(0.52\times 51)^2} } \\\\\)
\(\rm I_0 = 0.0562 \ A \\\\ \rm I_0 =56.2 mA\)
Hence the value of the current amplitude will be 56.2 milliamperes.
(b)The value of the phase constant will be 0.9 rad.
The formula for phase constant is given by;
\(\rm tan\phi=\frac{L\omega}{R} \\\\ \rm tan\phi=\frac{0.52\times 51}{21} \\\\ \rm tan\phi=1.263 \\\\ \rm \phi = tan^{-1}(1.263) \\\\ \phi= 51.6 ^0\)
To convert degree into radian the following formula is used;
\(1 \pi =180^0 \\\\ 1^0=\frac{\pi}{180} \\\\ 51.6^0=51.6 \times \frac{\pi}{180} \\\\ \phi=0.9 \ rad\)
Hence the value of the phase constant will be 0.9 rad.
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jerome pitches a baseball of mass 0.300 kg. the ball arrives at home plate with a speed of 40.0 m/s and is batted straight back to jerome with a return speed of 52.0 m/s. what is the magnitude of change in the ball's momentum?
The change in the momentum of the ball is 3.6 Kgm/s.
What is momentum?The term momentum has to do with the product in the velocity of a body and mass of the body. We have to recall at this point that rate of change of momentum is directly related to the impressed force and this is in accordance with the Newton second law of motion.
Now we have to look at the few pieces of information that we can be able to glean from the question;
Mass of the object = 0.300 kg
Initial speed of the object = 40.0 m/s
Final speed of the object = 52.0 m/s
Given that the change in the velocity of the object is given by;
m( v - u)
m = Mass of the object
v = Final speed of the object
u = Initial speed of the object
change in the velocity of the object = 0.300(52 - 40)
= 3.6 Kgm/s
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Part B
Enter into the table your calculated value for the spring constant, then play with different values of mk
until you get a close match to the motion. (Note: It will never be perfect. Remember that there are two
kinds of spring damping. Both are at work here, but we are not going to model both.) Once you're
satisfied with your model, record your model values in the table below.
The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.
What is Spring constant?The stiffer the spring is and the harder it is to stretch, the larger the spring constant.
Springs are pliable mechanical devices that regain their previous shape after deforming, i.e. after being stretched or compressed. They are an essential part of many different mechanical devices.
The well-known metal coil has evolved into an essential element in the modern world, appearing in everything from engines to appliances to tools to automobiles to medical equipment and even basic ball-point pens. The spring's ability to store mechanical energy accounts for its widespread use and applications.
Therefore, The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.
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A student builds a battery-powered car from a kit. Which series of energy transformations takes place as the car drives forward? A. Chemical energy Mechanical energy Electrical energy 1 - B. Chemical energy Electrical energy Mechanical energy 1. C. Mechanical energy - Electrical energy - Chemical energy. D. Electrical energy Chemical energy Mechanical energy
Answer:
B
Explanation:
First the battery uses chemical energy ===> to make electrical energy ===> to make mechanical energy
When carbon bonds with oxygen,
what
gas is formed?
When carbon bonds with oxygen, what gas is formed?
Answer:
Carbon dioxide
Explination:
I remember it from biology.
I hope this helps ^-^
In a chemical reaction, carbon combines with oxygen to form carbon dioxide gas.
What is a chemical reaction?A chemical reaction can be defined as a process that causes the chemical transformation of one chemical substance to another. The chemical reactions accompany chemical changes that involve the rearrangement of electrons in the forming and breaking of bonds between atoms, with no change to the nuclei.
The substances which are primarily involved in a reaction are known as reactants or reagents. Chemical reactions are commonly characterized by a chemical change, and yield products, which exhibit properties different from the reactants.
Chemical reactions take place at a characteristic rate of reaction at a given temperature, pressure, and chemical concentration. The rates increase with the increasing temperature of the reaction when more thermal energy is available to achieve the activation energy for breaking bonds between atoms.
The combustion reaction takes place when carbon combines with oxygen to produce carbon dioxide gas.
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a stone is placed in a graduated cylinder, which was filled to the 35ml mark. the level rises to 42ml. what happens to the volume of the stone?
The volume of the stone is 7ml
How do we find the volume of irregular object ?When an object is immersed in a liquid, The volume of the liquid displaced by the object is equal to the volume of the object. This method is usually used to find the volume of irregular object whose volume can not be found using formula. For example, a shapeless stone displaces the water by 10cm³, therefore the volume of the stone is 10cm³.
One milliliter (1 mL) of water has a volume of 1 cubic centimeter (1cm3).
The graduated cylinder is marked at 35ml. When a stone is placed into it, it rises to 42ml, therefore the measure of displacement is (42-35)ml = 7ml.
Therefore the volume of the stone is 7ml
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Answer: 7ml
Explanation:
question is included in the picture!!! PUT REAL ANSWERS OR I WILL REPORT YOU
Answer:
Explanation:
this is like rubbing a balloon on your head to make your hair stand up. Do that to the can. The balloon is filled , ofc, and then just rub the balloon on the can. This will charge the can with static electricity. :P
Is the declining acreage of land used for farming in the United States a major problem?
a. No, food is essential for life and therefore there is no higher valued use for land than providing foodstuff, eventually government regulators will step in an reverse the
current trend.
b. Yes, unless public pressure leads to a reversal of this trend, America can expect food shortages in the future.
c. No, it is primarily a reflection of the increased productivity in agriculture and shift of the land to higher valued uses.
Od. Yes, unless government regulation slows the commercial development of land, market forces will lead to the virtual depletion of land for agricultural use.
Answer:
C. No, it is primarily a reflection of the increased productivity in agriculture and shift of the land to higher valued uses.
Explanation:
Declining acreage of land used for farming in the United States is not necessarily a major problem. The decline in land used for farming can be a reflection of increased productivity in agriculture, which allows farmers to produce more food on less land. Additionally, the shift of land to higher valued uses such as commercial development, housing, and recreation can also contribute to the decline in land used for farming. While it's important to ensure that there is enough land for food production, it's also important to consider the other economic and social benefits of different uses for land.
Which chart correctly describes the properties of magnets and electromagnets?
Answer:
The second chart seems to be correct
Explanation:
I need help with (c) please
The frequency of light with a wavelength of 655 nm is 4.58 x 1014 Hz, the frequency of light with a wavelength of 515 nm is 5.83 x 1014 Hz, and the frequency of light with a wavelength of 475 nm is 6.32 x 1014 Hz. The frequency of light can be calculated using the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency.
The visible spectrum of electromagnetic radiation has a range of wavelengths that varies from the longest (red) to the shortest (violet) that our eyes can detect. The frequencies of light with wavelengths of 655 nm, 515 nm, and 475 nm can be calculated using the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency.(a) For light with a wavelength of 655 nm, the frequency can be calculated as: c = λν ==> ν = c/λ where c = 3.00 x 108 m/s (speed of light in a vacuum)λ = 655 nm = 6.55 x 10-7 m. Therefore, ν = (3.00 x 108 m/s) / (6.55 x 10-7 m) = 4.58 x 1014 Hz(b) For light with a wavelength of 515 nm, the frequency can be calculated as: c = λν ==> ν = c/λ where c = 3.00 x 108 m/s (speed of light in a vacuum)λ = 515 nm = 5.15 x 10-7 m. Therefore, ν = (3.00 x 108 m/s) / (5.15 x 10-7 m) = 5.83 x 1014 Hz(c) For light with a wavelength of 475 nm, the frequency can be calculated as: c = λν ==> ν = c/λ where c = 3.00 x 108 m/s (speed of light in a vacuum)λ = 475 nm = 4.75 x 10-7 m. Therefore, ν = (3.00 x 108 m/s) / (4.75 x 10-7 m) = 6.32 x 1014 Hz.For more questions on frequency
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Tony ran 600 meters in 60 seconds. What was Tony's speed during the
race?
An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. What is its speed when it hits its target?
The speed of the artillery shell when it hits its target is 100 m/s.
Given:
Initial vertical displacement (y) = 200 m
Vertical displacement at 100 m in the air (y') = 100 m
Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)
Using the equation for vertical displacement in projectile motion:
y' = vy^2 / (2g),
where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).
100 m = vy^2 / (2 * 9.8 m/s^2),
vy^2 = 100 m * 2 * 9.8 m/s^2,
vy^2 = 1960 m^2/s^2,
vy = sqrt(1960) m/s,
vy ≈ 44.27 m/s.
Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.
Hence, the speed of the artillery shell when it hits its target is 100 m/s.
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An environmentally conscious physics student 250 N
mows her lawn with a push mower, exerting
a force of 250 N along the handle as shown. 40°
How much force is actually being used to push
the mower along the grou
The force actually being used to push the mower along the ground is 191 N.
When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.
To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.
To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:
Horizontal component = Applied force * cos(angle)
Plugging in the values, we get:
Horizontal component = 250 N * cos(40°)
Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.
Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.
By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.
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Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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Need ASAP! Please Provide the Answer. I do not need an explanation. Thank you.
An iguana runs back and forth along the ground. The horizontal position of the iguana in meters over time is shown below.
The displacement of the iguana between 0 and 5 seconds is 6 m and the distance is 15 m.
What is displacement?
The displacement of an object is the change in the position of the object.
Displacement = change in position of the iguana
Displacement = position (5 seconds) - Position (0 seconds)
Displacement = 6 m - 0 m = 6 m
Distance traveled by the iguanaThis the total path covered by iguana in the first 5 seconds.
Distance = speed x time
speed = (6 - 0) / (3 - 1) = 3 m/s
Distance traveled by 0 and 5 seconds = 5 x 3 m/s = 15 m
Thus, the displacement of the iguana between 0 and 5 seconds is 6 m and the distance is 15 m.
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how is newtons first law of motion related to the concept of inertia?
HELPP MEE
Which image illustrates the desired interaction of a sound wave with
soundproofing material in a recording studio?
Soundproofing material is required for blocking sound during some works like recording voice in the studio. Image D represents the interaction of a sound wave with soundproofing material in a recording studio.
What is the basis of soundproofing?Soundproofing is done by absorbing the sound. A very much used material for this is a dense foam.
Foam and like materials absorbs sound and it travels directly into the soft surface resulting in soundproofing.
Thus, the correct option is C, as the D image is showing the absorption.
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Answer: C.D
Explanation:...
Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from 1.0 bar to 2.0 bar.
The change in the Gibb's free energy per mole (G) is 1.96 J.
The given parameters:
Density of the ice, ρ = 917 kg/m³Initial pressure, P₁ = 1.0 barFinal pressure, P₂ = 2.0 barTemperature, T = - 10 CMass of water = 18 gThe change in the Gibb's free energy per mole (G) is calculated as follows;
\(\Delta G = V(P_2-P_1) \\\\\)
where;
V is the volume of the ice
\(Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L\)
Change in pressure;
\(P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm\)
The change in the Gibb's free energy per mole (G);
\(\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G = 0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J\)
Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.
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what is the 'Water Column"
Answer:a vertical expanse of water stretching between the surface and the floor of a body of water
Explanation:
Hey, I need help can someone help me out, please?
Explanation:
6) newton
7) f =ma = 15*15 = 225N
8) a= 100/20 = 5ms^-2
Answer:
6 newton
7) f =ma = 15*15 = 225N
8) a= 100/20 = 5ms^-2
Explanation:
this is right pls mark as brainliest
a force is something that ___ an object to ____
Answer:
which can cause an object with mass to change its volocity
19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.
The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula
W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.
Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.
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A 42.6kg lamp is hanging from wires as shown in figure.The ring has negligible mass. Find tensionsT1, T2,T3 if the object is in equilibrium.
Answer:
T1 = 417.48N
T2 = 361.54N
T3 = 208.74N
Explanation:
Using the sin rule to fine the tension in the strings;
Given
amass = 42.6kg
Weight = 42.6 * 9.8 = 417.48N
The third angle will be 180-(60+30)= 90 degrees
Using the sine rule
W/Sin 90 = T3/sin 30 = T2/sin 60
Get T3;
W/Sin 90 = T3/sin 30
417.48/1 = T3/sin30
T3 = 417.48sin30
T3 = 417.48(0.5)
T3 = 208.74N
Also;
W/sin90 = T2/sin 60
417.48/1 = T2/sin60
T2 = 417.48sin60
T2 = 417.48(0.8660)
T2 = 361.54N
The Tension T1 = Weight of the object = 417.48N
Please help me out! I will pay real money to whoever solves this
Answer:
I KNOW THE ANSWER IT WILL COST 30$
Explanation:
calculate the percentage contraction of a rod moving with a velocity of 0.8c in a direction inclined at 60° to its own length
Answer:
Let lo be the length of the rod in the frame in which it is at rest and s' is the frame which is moving with a speed 0.8c in a direction making an angle 60° with x-axis. The components of lo along and perpendicular to the direction of motion are lo cos 60° and lo sin 60° respectively.
Now length of the rod along the direction of motion
= lo cos 60°_/1-(0.8) 2/c2
= lo/2×0.6
= 0.3 lo.
Length of the rod perpendicular to the direction of motion.
= lo sin 60°
=_/3/2 lo
Length of moving rod
l = [(0.3lo)2+{lo_/3/2} 2] 1/2
= 0.916 lo.
Percentage contraction
= lo-0.916lo/lo×100
= 8.4%.
Explanation:
Brainliest?Which of the the following quantities has the same unit as kilowatt - hour?
(a) Force × time
(b) Force × distance
(c) Force × acceleration
(d) Force × velocity
Answer:
I think (d) is your answer...
Force × velocity is the quantities has the same unit as kilowatt - hour. hence option D is correct.
What is Force ?A force in physics is an effect that changes the velocity of a mass-moving object, causing it to accelerate from rest, for example. It is a vector quantity since it can be a push or a pull and always has magnitude and direction. It is denoted by the letter F (formerly P) and is measured in newtons (N), the SI unit of force.
The net force exerted on an object is equal to the rate at which its momentum varies over time, according to Newton's second law in its original formulation. According to this equation, an object's acceleration is precisely proportional to the net force applied on it if its mass remains constant.
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A 3 kg block is placed on a flat smooth surface and pushed horizontally with a force of 2N. What is the acceleration
Answer:
0.67 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
f is the force
m is the mass
From the question we have
\(a = \frac{2}{3} \\ = 0.66666...\)
We have the final answer as
0.67 m/s²Hope this helps you
An ant climbs vertically on a fence. Its motion is shown on the following graph of vertical position � yy vs. time � tt. Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec. Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec. What is the instantaneous speed of the ant at time � = 8 s t=8 st, equals, 8, start text, space, s, end text?
The instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s.
To find the instantaneous speed of the ant at time t=8s, we need to calculate the derivative of the displacement function with respect to time. Since the displacement of the ant is given by a piecewise function, we need to differentiate each segment of the function separately and then piece them together. From 0s to 4s, the displacement of the ant decreases linearly from 6m to 2m. The slope of this segment is -1m/s. From 4s to 7s, the displacement of the ant is constant at 2m. The slope of this segment is zero. From 7s to 9s, the displacement of the ant increases linearly from 2m to 5m. The slope of this segment is 1.5m/s. Finally, from 9s to 10s, the displacement of the ant is constant at 5m. The slope of this segment is zero.
Therefore, the instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s. This means that the ant is moving upwards at a constant speed of 1.5m/s at time t=8s. It's important to note that the instantaneous speed of the ant tells us how fast it's moving at a specific moment in time. It's not the same as the average speed over a given time interval, which would be calculated by dividing the total displacement by the total time elapsed.
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Weather hazards and natural disasters such as tsunamis, earthquakes, and flooding are considered which type of migration factor?
A. Pull factor
B. Both push and pull factors
C. Neither push or pull factor
D. Push factor
Answer:
D. Push Factor
Explanation:
Pull factors are known as positive aspects of a place that make people want to stay/remain in that area.Push factors are known as negative aspects of a place that make people want to leave/depart from that area.Weather hazards and natural disasters are horrendously negative things that people actively seek to avoid; they make people want to leave or depart from an area in order to escape them. As such, they are considered push factors.
(Weather hazards and natural disasters are not pull factors because when discussing push vs pull we are specifically describing the mentioned factor. This aspect is not considered both because the migration factor mentioned in this question actively makes people want to move to any area that avoids their issue. Remember that pull factors make people want to move to a specific place for a unique advantage, while push factors make people want to move to any general place for a common advantage.)