Answer:
Resting Point
Explanation:
Answer: amplitude
Explanation:
what is the specific heat capacity of the metal?
Answer:
Once you have the data, the formula is used where Q is the heat lost by or gained by the sample m is the mass of the sample ΔT is the temperature change of the sample. When you plug in your data and solve for c, that will be your specific heat capacity.
I hope this helps. :)
Explanation:
Use Q = sm∆T to determine the heat capacity of the metal. (Make sure to use the heat given off by the metal, the mass of the metal, and the temperature change of the metal in this calculation.)
The heat of vaporization (DHovap) of benzene at 298 Kelvin is 33.89 kJ/mol and its vapor pressure is 96 torr. Calculate Keq at 298 Kelvin.
The heat of vaporization (DHovap) of benzene at 298 Kelvin is 33.89 kJ/mol and its vapor pressure is 96 torr.
To calculate Keq at 298 Kelvin, we will use the following equation; Delta G = -RT ln Keq
Where;
ΔG = Gibbs Free Energy
R = Gas constant
T = Temperature
Keq = Equilibrium constant
Given:
DHovap = 33.89 kJ/mo
lT = 298
KPH2O = 96 torr
First, we will convert vapor pressure to atm using the following;1 atm = 760 torrPH2O = 96 torr/760 torr/atm= 0.1263 atm. Now we can calculate ΔG using the following equation;ΔG = DHovap - RT ln(PH2O). Where; R = 8.314 J/mol.K Note that we need to convert kJ to J.1 kJ = 1000 JDHovap = 33.89 kJ/mol = 33.89 x 1000 J/mol DHovap = 33,890 J/molΔG = (33,890 J/mol) - (8.314 J/mol.K)(298 K)ln(0.1263 atm)ΔG = - 20602.88 J/mol. Now, we can solve for Keq by rearranging the equation for ΔG;ΔG = -RT lnKeqKeq = e^(-ΔG/RT)Keq = e^(-(-20602.88 J/mol)/(8.314 J/mol.K)(298 K))Keq = 2.37 x 10^21Answer: The Keq at 298 Kelvin is 2.37 x 10^21.
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What will happen if we keep the metallic can in a water bath having cold water.Give reason
Answer:
when a cold metallic is put in a water bath with cold water than the laws of thermodynamics and calorimetry suggests that both the solid and the liquid will engage in heat exchange until they attain equilibrium.
once they both are at equal temperature, no heat transfer will continue and the bodies will just stat in a packed atmosphere.
How many joules of heat are needed to raise the temperature of 15.0 g of
iron from 11°C to 66°C, if the specific heat of iron is 0.45 J/g°C?
371.25 joules of heat energy are needed to raise the temperature of 15.0 g of iron from 11°C to 66°C.
To solve this problemThe following formula can be used to determine the amount of heat energy needed to raise a substance's temperature:
Q = m * c * ΔT
Where
The heat energy in joules is QThe substance's mass, m, is expressed in gramsc is a substance's specific heat capacity expressed in J/g°CΔT is the change in temperature in degrees CelsiusGiven the following values:
m = 15.0 g (mass of iron)
c = 0.45 J/g°C (specific heat of iron)
ΔT = 66°C - 11°C = 55°C (change in temperature)
Plugging these values into the formula, we can calculate the heat energy (Q):
Q = 15.0 g * 0.45 J/g°C * 55°C
Q = 371.25 J
Therefore, 371.25 joules of heat energy are needed to raise the temperature of 15.0 g of iron from 11°C to 66°C.
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how can ethers impact us?
Ethers can impact us in several ways, both positive and negative like 1-Anesthesia 2-Solvents and Industrial Applications 3-Flammability 4-Health Effects
1-Anesthesia: Certain ethers, such as diethyl ether, have been historically used as general anesthetics due to their ability to induce loss of consciousness and provide pain relief during surgical procedures.
2-Solvents and Industrial Applications: Ethers can be used as solvents in various industries, including pharmaceuticals, paints, and cleaning products. However, prolonged exposure to certain ethers, especially those with high volatility, can lead to health issues such as respiratory irritation and central nervous system effects.
3-Flammability: Ethers are generally highly flammable and can pose a fire hazard if not handled properly. Precautions should be taken to ensure safe storage and handling of ether-based products.
4-Health Effects: Some ethers, such as ethylene glycol ethers, can have toxic effects on the body, particularly on the reproductive system and blood cells. Prolonged exposure or ingestion of these ethers can lead to serious health complications.
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What is the definition of thermal chemistry?
The study of change that involves cool objects
The study of change that involves temperature
The study of change that involves heat
Answer:
the second one
Explanation:
thermal has to do with temperature
Pwease halp, If a decrease in temperature accompanies a reaction, what occurred?
Energy was released.
Energy was destroyed.
Energy was created.
Energy was absorbed.
Answer: energy was released.
Explanation: i took the quiz.
there are 3.0 g of NO and 3.0 g of CO reacting. what is the limiting reactant ?
Answer:
NO will be the limiting reagent.
Explanation:
The balanced equation is:
2 NO + 2 CO → N₂ + 2 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
NO: 2 molesCO: 2 molesN₂: 1 moleCO₂: 2 molesBeing the molar mass of each compound:
NO: 30 g/moleCO: 28 g/moleN₂: 28 g/moleCO₂: 44 g/moleThen by stoichiometry the following quantities of mass participate in each reaction:
NO: 2 moles* 30 g/mole= 60 gCO: 2 moles* 28 g/mole= 56 gN₂: 1 mole* 28 g/mole= 28 gCO₂: 2 moles* 44 g/mole= 88 gThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, you can use a simple rule of three as follows: If 56 grams of CO react with 60 grams of NO, 3 grams of CO react with how much mass of NO?
\(mass of NO=\frac{3 grams of CO*60 grams of NO}{56 grams of CO}\)
mass of NO= 3.21 grams
But 3.21 grams of NO are not available, 3 grams are available. Since you have less moles than you need to react with 3 grams of CO, NO will be the limiting reagent.
issued this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your etext. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon.
The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.
Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.
Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.
According to the given data;
Decomposition of carbon monoxide (CO);
Oxygen produced = 3.36 g
Carbon produced = 2.52 g
We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;
Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol
Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol
Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;
0.21 mol C / (0.21 mol O) = x
Simplifying the equation, we have;
x = 1
Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.
Decomposition of carbon dioxide (CO₂);
Oxygen produced = 9.92 g
Carbon produced = 3.72 g
Following the same calculations as before;
Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol
Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol
Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;
0.31 mol C / (0.62 mol O) = y
Simplifying the equation, we have;
y = 0.5
Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.
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--The given question is incomplete, the complete question is
"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--
Which type of bond is found in an alkane?
O A. Double only
B. Single and double
O C. Single only
O D. Single and triple
Considering the definition of alkanes, single bonds are found in an alkane.
Definition of AlkanesAlkanes are a class of hydrocarbons (compounds containing only carbon and hydrogen) that are made up of a variable number of carbon atoms joined together by single bonds. In turn, each carbon atom bonds to hydrogen atoms, which may eventually be replaced by other atoms or functional groups.
In other words, alkanes are open or closed chain molecules that are linked by simple bonds.
Alkanes are saturated hydrocarbons because the bonds between carbon atoms are simple and stable. And as mentioned, the hydrogen atoms bonded to each carbon atom can be replaced by other atoms, such as halogens (fluorine, bromine, chlorine) or various groups or “radicals”. In the latter case, the structure becomes more complex giving rise to branched alkanes.
SummaryIn summary, single bonds are found in an alkane.
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Answer: C) single only
Explanation:
just got it right
Select the statement(s) that accurately describe what a pedigree chart shows.
A. Future predictions of inherited genes
B. Specific alleles being inherited by offspring
C. Inherited traits in a family
D. Male and female family members
E. Genotypes and phenotypes being inherited
A pedigree chart shows Inherited traits in a family; the correct option is C
What is a pedigree chart?A pedigree chart is a chart that shows how traits are passed on from parents to offspring.
A pedigree chart is used in the study of inheritance or genetics.
A pedigree chart can for example be used to study the inheritance pattern of traits such as sickle cell anemia. In such a pedigree chart, the genotype of the parents is used to study how the trait is being transferred and can also predict the likelihood of the offspring of the parents inheriting that trait.
A pedigree chart can also be used to backtrace how a particular trait came into a particular family.
In conclusion, a pedigree chart is a chart that shows how traits are passed on from the parents and offspring of a family.
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volume measures from other liquids help meh solve the purple pipette but read the directions firsts
Answer:
liquids
Explanation:
are not solids
big brain answer
sample of gas occupies a volume of 57.4 ml . as it expands, it does 119.9 j of work on its surroundings at a constant pressure of 783 torr . what is the final volume of the gas?
The final volume of the gas is approximately 57.242 mL.
To find the final volume of the gas, we can use the equation for work done by a gas at constant pressure:
Work = -PΔV
Where:
Work is the work done by the gas on its surroundings (given as 119.9 J),
P is the pressure of the gas (given as 783 torr), and
ΔV is the change in volume.
Since the pressure is constant, we can rearrange the equation to solve for ΔV:
ΔV = -Work / P
Plugging in the values:
ΔV = -119.9 J / (783 torr)
We need to convert the pressure from torr to atm to maintain consistent units:
ΔV = -119.9 J / (783 torr * (1 atm / 760 torr))
ΔV = -0.158 L
The negative sign indicates that work is done on the gas, causing it to expand. To find the final volume, we add the change in volume to the initial volume:
Final Volume = Initial Volume + ΔV
Final Volume = 57.4 mL + (-0.158 L)
Final Volume = 57.4 mL - 0.158 mL
Final Volume = 57.242 mL
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If 3/5 < x < 67%, which of the following could be the value of x?
Answer:
2/3, or .66
Explanation:
which of the following statements is true for specific gravity measured by the urine chemical reagent strip method?
The specific gravity measured by the urine chemical reagent strip method is a measure of the density of the urine compared to water.
What is specific gravity?
The ratio of a substance's density (mass per unit volume) to the density of a specific reference material is known as its relative density or specific gravity. When determining a substance's specific gravity, liquids are typically compared to the densest form of water (at 4 °C or 39.2 °F); for hydrocarbons, the reference point is air at room temp (20 °C or 68 °F). Scientific jargon favours the term "relative density," which is frequently abbreviated as "RD," while deprecating the term "specific gravity." A substance is less dense than the reference if its relative density is less than 1, and it is denser than the reference if it is greater.
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An atom X that has 12 protons and 12 electrons, loses 2 electrons to form an ions, What will be the ion? What will be the number of protons and electrons in the ions?
An atom X that has 12 protons and 12 electrons, loses 2 electrons to form an ions, the charge of ion will be X⁺² the number of protons 12 and electrons in the ions is 10.
An atom X has 12 protons and 12 electrons that means X is a neutral atom and the atomic no. is 12 because total no. of protons is equal to atomic number. When it looses the 2 electrons then atom becomes positively charged ion . the charge on the ion is +2.
now, the no. of protons will be = 12
number of electrons will be = 12 - 2 = 10
Thus, An atom X that has 12 protons and 12 electrons, loses 2 electrons to form an ions, the charge of ion will be X⁺² the number of protons 12 and electrons in the ions is 10.
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what is 43 mg into grams
Hello there :) here are the answers and hope you a GREAT Thanksgiving :)
0.043 grams
What is the role of Cl2 in the following
reaction?
CL + NaOH Nacl+ NaCO3+H2O
Answer:
Cl2 acts as an oxidizing agent
Explanation:
The balanced equation is
Cl2+NaOH⟶NaCl+NaClO3+H2O
Cl2 acts as a reactant in this chemical reaction
Cl2 receives one electron and thus reduces itself from Cl2 to 2 Cl−. This indicates that 2Cl- will oxidize some other element and hence Cl2 act as an oxidizing agent.
What would happen to other populations if they didn't have limitng factors?
Answer:
In the natural world, limiting factors like the availability of food, water, shelter and space can change animal and plant populations. Other limiting factors, like competition for resources, predation and disease can also impact populations. Other changes in limiting factors will cause a population to decrease.
Balance the following chemical equation by using System of equations Nag Pou + Ba(NO₂), ) Bag(Poes)₂ + NaNo₂
To balance the chemical equation: NaPO3 + Ba(NO2)2 → Ba(PO3)2 + NaNO2. substituting a = c into the third equation: a = c From the fourth equation, we have: 3a = 2c + 2a 3a = 2a + 2a a = 0.
We can set up a system of equations based on the number of atoms of each element on both sides of the equation. Let's denote the coefficients of the balanced equation as follows:
NaPO3: a
Ba(NO2)2: b
Ba(PO3)2: c
NaNO2: d
Now, we can write the system of equations:
Na: a = d
Ba: b = c
P: a = c
O: 3a = 2c + 2d
N: 2b = d
Solving this system of equations will give us the balanced coefficients. From the first equation, we can substitute d = a into the fifth equation:2b = a Substituting this back into the second equation: b = c Now, substituting a = c into the third equation: a = c From the fourth equation, we have: 3a = 2c + 2a 3a = 2a + 2a a = 0
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A student carrying a glass cup trips and drops the glass, then it shatters.
What type of change is this?
A. Physical change
B. Chemical change
C. Mixture change
(Need explanation too)
Answer:
A
Explanation:
Answer:
A is the correct answer I believe
NiSe2 + Ca3(PO4)2 = Ni3(PO4)2 + CaSe
balance please
The Gateway Arch in St. Louis, MO is approximately 630 ft tall. How many U.S. half dollars would be in a stack of the same height? Each half dollar is 2.15 mm thick.
Answer:
The number of half dollars in the stack of the height of the Gateway Arch in St. Louis is 89,313 half dollars
Explanation:
The given height of the Gateway Arch in St. Louis = 630 ft
The thickness of each half dollar = 2.15 mm
By conversion of factors, we have;
1 feet = 304.8 mm
Therefore;
630 ft. = 304.8 × 630 mm = 192,024 mm
The number of half dollars that will stack up to 630 ft or 192,024 mm, is therefore, given as follows;
The number, n, of half dollars in the stack of the height of the Gateway Arch in St. Louis = The height of the Gateway Arch in St. Louis/(The thickness of each half dollar)
n = 630 ft/(2.15 mm/(half dollar)) = 192,024 mm/(2.15 mm/(half dollar)) = 89,313.49 ≈ 89,313 half dollars
The number of half dollars in the stack of the height of the Gateway Arch in St. Louis = 89,313 half dollars.
A compound is 54.53 % C , 9.15 % H , and 36.32 % O by mass. What is the empirical formula of the compound
The empirical formula of the compound is C2H4O. To determine the empirical formula of a compound, you need to find the simplest whole-number ratio of atoms present in the compound.
Start by assuming you have 100 grams of the compound. This assumption allows you to work with percentages as grams.
Convert the masses of each element into moles by dividing the mass (in grams) by the molar mass of that element. The molar masses are approximately 12.01 g/mol for carbon (C), 1.01 g/mol for hydrogen (H), and 16.00 g/mol for oxygen (O).
Mass of C: 54.53 g / 12.01 g/mol = 4.54 mol
Mass of H: 9.15 g / 1.01 g/mol = 9.06 mol
Mass of O: 36.32 g / 16.00 g/mol = 2.27 mol
Divide each mole value by the smallest number of moles calculated to obtain the mole ratio relative to the smallest number of moles.
Mol ratio of C: 4.54 mol / 2.27 mol = 2
Mol ratio of H: 9.06 mol / 2.27 mol = 4
Mol ratio of O: 2.27 mol / 2.27 mol = 1
If necessary, multiply all the mole ratios by the same number to achieve whole numbers. In this case, multiplying by 2 gives whole-number ratios.
Empirical formula: C2H4O
Therefore, the empirical formula of the compound is C2H4O.
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The molecular weight of table salt, NaCl, is 58. 5 g/mol. A tablespoon of salt weighs 6. 37 grams.
Calculate the number of moles of salt in one tablespoon.
First, complete the unit conversion using dimensional analysis:
Answer:
Answer in picture
Explanation:
Earth's mantle is made mostly of material in what state of matter?
Answer:
Solid Rock / SolidsExplanation:
\(--------------------------------------------\)
According to EarthObservatory, The Earth’s mantle is mostly made of solid rock. The misconception of a liquid mantle arises from expressions like “a subducted tectonic plate sinks into the mantle” or “continental drift”, expressions that implicitly refer to the liquid element.
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Hope this helps! <3
\(--------------------------------------------\)
calculate the number of moles in 2 kg of iron
Answer:
111600 moles
Explanation:
Number of moles= Mass ×Mr, where Mr is the relative molecular mass of the substance of interest. Note that the mass is calculated in terms of grams (1 kg= 1000 g), while the Mr can be found using the periodic table.
Mass of iron
= 2 kg
= 2(1000)
= 2000 g
Mr of iron= 55.8
Number of moles
= 2000(55.8)
= 111600 mol
Additional:
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https://brainly.com/question/21042927Write a balanced half-reaction for the oxidation of solid manganese dioxide to permanganate ion in acidic aqueous solution. be sure to add physical state symbols where appropriate.
The balanced oxidation half equation is given below:
MnO₂ + H₂O → MnO₄⁻ + H⁺ + 3 e⁻What are oxidation reactions?Oxidation reactions are reactions in which the oxidation of the species increases.
Oxidation reactions can involve addition of oxygen or electronegative elements to a substance or the removal of hydrogen or electropositive elements from a substance.
The balanced half-reaction for the oxidation of solid manganese dioxide to permanganate ion in acidic aqueous solution is given below:
MnO₂ + H₂O → MnO₄⁻ + H⁺ + 3 e⁻
In conclusion, the balanced oxidation half equation shows that three electrons were lost by the manganese (iv) ion to form manganese (vii) ion.
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Methane, CH4, diffuses in a given apparatus at the rate of 30 mLimin . At what rate would a gas with a molar mass of 100 diffuse under the same conditions?
The rate at which a gas with a molar mass of 100 would diffuse under the same conditions is approximately 93.75 mL/min.
The rate of diffusion of a gas is inversely proportional to the square root of its molar mass, according to Graham's Law of Diffusion. Therefore, we can use Graham's Law to determine the rate at which a gas with a molar mass of 100 would diffuse under the same conditions.
Graham's Law states that the ratio of the rates of diffusion of two gases is equal to the square root of the ratio of their molar masses. In this case, we can set up the following equation:
(rate of methane) / (rate of unknown gas) = sqrt(molar mass of unknown gas / molar mass of methane)
Substituting the given values into the equation, we have:
(30 mL/min) / (rate of unknown gas) = sqrt(16 g/mol / 100 g/mol)
Simplifying the equation, we find:
(rate of unknown gas) = (30 mL/min) * sqrt(100 g/mol / 16 g/mol)
Calculating the expression on the right-hand side, we get:
(rate of unknown gas) = (30 mL/min) * sqrt(6.25)
Therefore, the rate at which a gas with a molar mass of 100 would diffuse under the same conditions is approximately 93.75 mL/min.
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If the absorbance of a Co(NO3)2 solution is 0.253 and that of a Ni(NO3)2 solution is 0.145 at 510nm and it is known that there is no interaction between the species, the absorbance of a solution prepared by mixing 10 mL of the Co(NO3)2 solution with 10 mL of the Ni(NO3)2 solution will be
How many molecules it interacts with will determine how much of the light is absorbed. Let's say you have an organic dye that is really brightly colored.
It will have a relatively high absorption if it is in a moderately concentrated solution since there are several molecules to interact with the light. However, it could be quite challenging to detect any color at all in a solution that is extremely diluted. The absorption will be quite low. Let's say you wished to compare this color to another substance. You couldn't compare them logically to see which one absorbed more light unless you were careful to account for the concentration.
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