Frequency of ripples is 2.58Hz if the wavelength of ripples is 3.43cm and speed of ripples is 8,87m/sec.
Ripples are the moment impact of wind on water and they subside as fast as they structure, as the surface strain of the water hoses their endeavors. In the event that a breeze blows consistently across a sufficiently enormous fix of water for a couple of hours then the waves become waves and these won't be hosed with such ease.
We know that there is a co-relation between speed, wavelength and frequency of ripple, which is given by
Speed=frequency × wavelength or
=> c =v×λ
Now,we have λ=3.43cm =0.0343m,c=8.87m/sec,v=?
So,on putting the values, we get
=>8.87 = v × 3.43
=>v=8.87/3.43
=>v=2.58Hz.
Hence,frequency is 2.58Hz.
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A squirrel jumps into the air with a velocity of 7 m/s at an angle of 20 degrees. What is the maximum height reached by the squirrel?
Answer:
.3m
Explanation:
Apex
0.3 is right i just got it right on the test for A P E X :D
two converging lenses, each of focal length 14.8 cm, are placed 39.7 cm apart, and an object is placed 30.0 cm in front of the first lens. where is the final image formed? the image is located cm ---location--- what is the magnification of the system?
The final image is formed by two converging lenses at 15.3 cm in front of the second lens and the magnification of the system is -0.99.
To find the location of the final image, we can use the lens formula:
1/f = 1/do + 1/di
where f is the focal length of the lens, do is the object distance, and di are the image distance.
For the first lens, f = 14.8 cm and do = 30.0 cm. Plugging these values into the lens formula gives:
1/14.8 = 1/30 + 1/di
Solving for di, we get:
di = 20.1 cm
This means that the first lens forms an image 20.1 cm behind it, which serves as the object for the second lens.
Using the lens formula again for the second lens, f = 14.8 cm and do = 39.7 - 20.1 = 19.6 cm. Plugging these values into the lens formula gives:
1/14.8 = 1/19.6 + 1/di
Solving for di, we get:
di = 9.1 cm
Therefore, the final image is formed 9.1 cm behind the second lens.
To find the magnification of the system, we can use the formula:
m = - di/do
where m is the magnification, di is the image distance, and do is the object distance.
Plugging in the values we found, we get:
m = -9.1/30.0 = -0.303
Therefore, the magnification of the system is -0.303, which indicates that the image is inverted and smaller than the object.
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(a) You wish to determine the height of the smokestack of a local coal burning power plant. You convince a member of the maintenance crew to mount the support for a simple pendulum at the top of the stack and you suspend a 1.00 kg mass that just misses the ground at its lowest point from the pendulum cord. If the period of the pendulum is 18.7 s, determine the height of the smokestack. 8455.69 Incorrect: Your answer is incorrect. What factors influence the period of a simple pendulum
Answer:
a. 86.80 m
b. i. The mass of the bob
ii. The length of the pendulum
Explanation:
a. Determine the height of the smokestack.
Using T = 2π√(L/g) where T = period of pendulum = 18.7 s, L = length of pendulum = height of smokestack and g = acceleration due to gravity = 9.8 m/s².
So, making L subject of the formula, we have
T = 2π√(L/g)
T/2π = √(L/g)
squaring both sides, we have
(T/2π)² = L/g
L = (T/2π)²g
Substituting the values of the variables into the equation, we have
L = (T/2π)²g
L = (18.7 s/2π)²(9.8 m/s²)
L = (2.976 s)²(9.8 m/s²)
L = 8.857 s² × 9.8 m/s²
L = 86.796 m
L ≅ 86.80 m
b. What factors influence the period of a simple pendulum
The factors that influence the period of a simple pendulum are
i. The mass of the bob
ii. The length of the pendulum
how much work does a 60kg person do in walking up 5m of stairs
Answer:
If I’m correct 300 joules
Explanation:
Which statement best describes the general movement of air masses?
A.
They move from areas of high humidity to areas of low humidity.
B.
They move from areas of high altitude to areas of low altitude.
C.
They move from areas of low temperature to areas of high temperature.
D.
They move from areas of high pressure to areas of low pressure.
Answer:
d
Explanation:
i looked it up
An electron moves through a potential difference of 1500 V. The magnitude of the change in potential energy experienced by the electron is
a. 1500 eV.
b. 1200 eV.
c. 1300 eV.
d. 1000 eV.
The magnitude of the change in potential energy experienced by the electron is a. 1500 eV.
Potential difference = 1500V
Charge of an electron = -1.6 x 10^-19
The energy that is capable of changing into another form of energy is called potential energy. The potential energy of an object is influenced by its physical characteristics and location within a system. Potential energy can take on various shapes. For example: due to an object's mass and location within a gravitational field, it has the potential energy of gravity.
Calculating the magnitude of the change in potential energy -
ΔPE = qΔV
Substituting the values -
\(PE = (-1.6 x 10^-19 C) x (1500 V)\)
\(PE = -2.4 x 10^-16 J\)
Converting to electron volts (eV) -
= PE/Charge of electron
\(PE = -2.4 x 10^-16 J / (1.6 x 10^-19 C/eV)\)
= -1500 eV
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how large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 105 m m at a speed of 102 km/h k m / h ?
The car must have a static friction coefficient of 0.568 in order to safely round the bend.
What is a suitable friction coefficient?"The Occupational Safety and Health Administration advises that walking surfaces have a static coefficient of friction of 0.5," reads the appendix statement (at A4. 5). The allocation of a 0.5 COF to OSHA is most likely explained by the regulatory proposal from OSHA and the mention in ADAAG taken together.
To get the static friction coefficient required for a vehicle to travel at 102 km/h around a flat curve with a radius of 105 m,
F = mv²/r
F = μs * N
μs × N = mv²/r
N = mg
μs × mg = mv²/r
μs = v²/(gr)
μs = (102 km/h)² / (9.8 m/s² × 105 m)
μs = 0.568
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A basketball is shot from an initial height of 2.4 m with an initial speed v0=12 m/s directed at an angle θ0=35 ∘ above the horizontal. at what angle to the horizontal did the ball enter the basket?
To find the angle at which the ball enters the basket, we need to use the equations of motion for projectile motion. The equations are:
y = y0 + v0y*t - (1/2)*g*t^2
x = x0 + v0x*t
where y is the vertical position, y0 is the initial vertical position, v0y is the initial vertical velocity, g is the acceleration due to gravity, t is the time, x is the horizontal position, x0 is the initial horizontal position, and v0x is the initial horizontal velocity.
The ball enters the basket at an angle of 0° to the horizontal.
We know that
y0 = 2.4 m, v0 = 12 m/s, θ0 = 35°, and g = 9.8 m/s^2. We can find v0x and v0y using the angle:
v0x = v0*cos(θ0) = 12 m/s*cos(35°) = 9.82 m/s
v0y = v0*sin(θ0) = 12 m/s*sin(35°) = 6.92 m/s
The ball enters the basket when y = 0, so we can set the equation for y equal to 0 and solve for t:
0 = 2.4 m + 6.92 m/s*t - (1/2)*9.8 m/s^2*t^2
Using the quadratic formula, we find that t = 0.74 s or t = -0.63 s. We discard the negative value, so t = 0.74 s.
Now we can use the equation for x to find the horizontal position of the basket:
x = x0 + v0x*t = 0 + 9.82 m/s*0.74 s = 7.27 m
Finally, we can use the equation for the tangent of the angle to find the angle at which the ball enters the basket:
tan(θ) = y/x = 0/7.27 m = 0
θ = tan^-1(0) = 0°
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if there is a gravitational force between all objects, why do we not feel or observe it?
Answer:
We do. It's just way too small compared to the force between the objects we're observing and the earth. It's like looking inside a room with an elephant and a grain of rice. The rice is there, it's just too small compared to the room and the elephant inside for you to notice it. Or, if you ever traveled on a plane, you can easily see the towns, or the roads, but not the single people walking the street.
A light ray travels through water and reflects off a glass surface back into the water. How do the phases of the incident light and the reflected light compare?.
The light travels through water and gets reflected off on the glass surface into the water. There had been a 180° phase change between the incident and the reflected wave. This is called Total internal reflection (TIR).
In total internal reflection, in physics, a ray of light in a medium such as water or glass is completely reflected back into the medium from the surrounding surfaces. This phenomenon occurs when the angle of incidence is greater than a certain critical angle called the critical angle.
TIR only occurs when both of the following two conditions are met
Light is in a denser medium and is approaching a less dense medium. The angle of incidence should be greater than the so-called critical angle.Thus, the phases which include the TIR are the incident and the reflected phase and the incident light hits the surface while the reflected light reflects back.
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A cat falls from a table of height 1.3 m. What is the impact speed of the cat?
O A. 7.5 m/s
O B. 2.5 m/s
O C. 5.0 m/s
O D. 25.5 m/s
SUBMIT
The impact speed will be
v^2 = 2*9.8*1.3
v^2 = 25.48
v= 5.04 m/s or O C. 5.0 m/s
Which phase of cell division is shown?
Exploring meiosis.
A. metaphase
B. prophase
C. anaphase
D. telophase
Answer:
Anaphase
Explanation:
This is because the spindle fibres have shortened and is pulling the chromatids towards the poles of the cell. The chromatids have also separated.
The cell division which is shown in the picture is anaphase. The correct option is C.
What are the phases of meiosis?Meiosis is divided into two main phases, each with its own set of subphases:
1 Meiosis I:
a. Prophase I: This is the longest and most complex phase of meiosis. During this phase, homologous chromosomes pair up and form bivalents, and crossing over occurs between the homologous chromosomes. The nuclear envelope breaks down, and spindle fibers form from the centrioles at opposite poles of the cell.
b. Metaphase I: During this phase, the homologous chromosomes line up along the metaphase plate, with one chromosome from each homologous pair facing each pole of the cell.
c. Anaphase I: During this phase, the spindle fibers contract and pull the homologous chromosomes towards opposite poles of the cell.
d. Telophase I: During this phase, the chromosomes reach the poles of the cell and the nuclear envelope reforms around each set of chromosomes. The cell then undergoes cytokinesis, resulting in two daughter cells.
2. Meiosis II:
a. Prophase II: During this phase, the nuclear envelope breaks down, and spindle fibers form from the centrioles at opposite poles of the cell.
b. Metaphase II: During this phase, the chromosomes line up along the metaphase plate, with sister chromatids facing opposite poles of the cell.
c. Anaphase II: During this phase, the spindle fibers contract and pull the sister chromatids towards opposite poles of the cell.
d. Telophase II: During this phase, the chromosomes reach the poles of the cell and the nuclear envelope reforms around each set of chromosomes. The cell then undergoes cytokinesis, resulting in four haploid daughter cells.
Meiosis involves two rounds of chromosome segregation, resulting in four haploid daughter cells that are genetically distinct from the parent cell.
Therefore, The correct option is C i.e anaphase.
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how to find average velocity on a velocity time graph
To find the average velocity on a velocity-time graph, you need to calculate the slope of the line connecting two points on the graph. The average velocity represents the change in velocity divided by the change in time between those two points.
To calculate the average velocity, you can use the formula:
Average velocity = (change in velocity) / (change in time)
You can determine the change in velocity by finding the difference between the final velocity and the initial velocity. The change in time is the difference in the time coordinates of the two points.
Select two points on the velocity-time graph, typically denoted by (t₁, v₁) and (t₂, v₂), where t represents time and v represents velocity. Then, substitute the values into the formula mentioned above to calculate the average velocity.
It's important to note that the average velocity provides information about the overall change in velocity over a specific time interval, rather than instantaneous velocity at a particular moment.
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The golf ball below has reached the top of its trajectory in the time shown. What will the totalhang time be when the ball hits the ground? Assume no air resistance or spin
A. 6.15 seconds
B. 8.20 seconds
C. 12.30 seconds
D. 16.40 seconds
The correct option would be option B. 8.20 seconds. The motion of the golf ball can be divided into two phases. They are; The time for the golf ball to reach the maximum height and the time for the golf ball to return to the ground. The time for the golf ball to reach the maximum height is half of the total hang time.
The given figure is shown below:
Given,
Initial velocity, u = 15 m/s (upward direction)
Final velocity, v = 0 m/s (at the maximum height)
Acceleration, a = g = 9.8 m/s² (downward direction)
Time taken to reach the maximum height, t = 3 seconds
The formula to find the height of the golf ball is given by;
h = ut + 1/2at²h = 15 x 3 + 1/2 x 9.8 x 3²h = 67.05 m
In the second phase, the golf ball falls from the maximum height to the ground. The time taken by the ball to reach the ground from the maximum height is the same as the time taken to reach the maximum height from the ground.The velocity of the golf ball while it hits the ground is the same as its initial velocity.
Hence, we can use the following formula to find the total hang time:
t = 2u/gt = 2 x 15 / 9.8t = 3.06 seconds
Therefore, the correct option is B. 8.20 seconds.
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Quarks are only inside of protons
In 1964 Gell Mann and Zweig introduced a baryonic triplet consisting of three hypothetical particles that are termed as Quarks.
The quark model is able to explain many features of elementary particles and gives a good insight into the structure of baryons and mesons.
Quarks are the fermions as the basic building block if we use fermions then we can get fermions and bosons. These bosons are assumed as antiquark pairs.
Actually the three quarks proposed are - up quark (u) , down quark(d), strange quark (s)Quarks and antiquarks have fractional charge . For example u quark ,\(q= e(1/2 +1/2*1/3 +1/2*0)\\=+2/3 e\)Quarks have no internal structure as they are point particles.Hadron like proton is composed of three quarks.Quarks are found in protons but can't say quarks are only found in protons. Because evidently quarks and gluons are basic building blocks of protons as wells as neutrons.To study more about quarks-
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when a track coach develops a training plan for a 16-year-old sprinter, which form of cardiorespiratory exercise can be included to improve anaerobic power?
High-intensity interval training (HIIT) can be included in a training plan to improve anaerobic power in a 16-year-old sprinter.
Anaerobic power is the ability to perform short, high-intensity bursts of activity without relying on oxygen. HIIT involves alternating periods of high-intensity exercise with periods of rest or lower intensity exercise. This type of training has been shown to improve anaerobic power in athletes. A track coach may design a HIIT program that includes sprints, plyometric exercises, and resistance training to improve the sprinter's power and speed.
However, it is important for the coach to consider the individual athlete's current fitness level and adjust the intensity and volume of the program accordingly to avoid injury and overtraining. Adequate rest and recovery time should also be included in the training plan to allow for proper adaptation and improvement in performance.
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A ball of mass m, moving at a velocity v, collides with a stationary ball of mass 2m. The two balls stick together. What is the fraction of the initial kinetic energy is lost on impact?
Answer:
67%
Explanation:
In the absence of external forces, the total momentum of the system before the collision is equal to the total momentum after the collision. Since the second ball is initially at rest, the total momentum before the collision is simply m*v.
After the collision, the two balls stick together and move with a common velocity, which can be calculated using conservation of momentum:
m*v + 0 = (m+2m) * v_final
Solving for v_final, we get:
v_final = v/3
The initial kinetic energy of the system is:
K_i = 0.5mv^2
The final kinetic energy of the system is:
K_f = 0.5*(3m)v_final^2 = 0.5(3m)(v^2/9) = 0.5m*v^2/3
The fraction of the initial kinetic energy lost on impact is:
( K_i - K_f ) / K_i = ( 1 - 1/3 ) = 2/3 = 0.67
Therefore, 67% of the initial kinetic energy is lost on impact.
How is the capacitance of a capacitor related to the charge stored on the capacitor and the potential difference across the capacitor?.
Answer:
Capacitance is the ratio of the charge to the potential difference. How is the charge stored on a capacitor related to the capacitance of the capacitor and the potential difference across the capacitor? The charge equals the product of the capacitance and the potential difference.
Explanation:
Hope this helps
why does a mirror reverse left and right, but not up and down
A mirror reverses left and right but not up and down because it reflects light rays without changing the orientation of objects in relation to gravity, while our perception of left and right is influenced by our own point of view.
The phenomenon of a mirror reversing left and right but not up and down is a result of the way reflections occur.
When we look at an object in a mirror, the mirror reflects the light rays that enter our eyes. The mirror doesn't actually change the orientation of the object itself. However, our perception of the reflected image is influenced by how we interpret the direction of the reflection.
Left and right are relative orientations based on our own point of view. When we face a mirror, our left side appears on the mirror's right side, and our right side appears on the mirror's left side. This reversal occurs because the mirror reflects light rays in a way that preserves the angles at which they strike the mirror's surface.
On the other hand, up and down are absolute orientations in relation to gravity. Gravity pulls objects in a consistent downward direction, and the mirror does not alter the orientation of objects with respect to gravity. Therefore, the reflection in the mirror appears to maintain the same up-down orientation.
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Car AMass: 1,500 kgVelocity: 10 m/sCar BMass: 1,500 kgVelocity: 25 m/sCar CMass: 1,000 kgVelocity: 10 m/sWhich order shows decreasing momentum?A, B, CB, A, CC, B, A
Answer:
B, A, C
Explanation:
The momentum is equal to the mass times the velocity, so for each car the momentum is equal to
Car A
Momentum = Mass x Velocity
Momentum = 1,500 kg x 10 m/s
Momentum = 15,000 kg m/s
Car B
Momentum = Mass x Velocity
Momentum = 1,500 kg x 25 m/s
Momentum = 37,500 kg m/s
Car C
Momentum = Mass x Velocity
Momentum = 1,000 kg x 10 m/s
Momentum = 10,000 kg m/s
Then, the decreasing momentum is B, A, C because
37,500 is greater than 15,000 and 15,000 is greater than 10,000
So, the answer:
B, A, C
I need Help! Can You Please Help Me?
_______ is essential for building amino acids.
(Choose One)
Nitrogen
Oxygen
Calcium
Carbon
Hydrogen
Phosphorus
Answer:
Oxygen or Hydrogen?
Explanation:
To make amino acids, fermentation tanks are filled with molasses and sugar ingredients such as sugar cane, corn and cassava. Ideal conditions are achieved for stirring, oxygen supply, temperature and pH levels. The desired amino acids are then purified from this fermented broth.
"An amino acid is an organic molecule that is made up of a basic amino group (−NH2), an acidic carboxyl group (−COOH), and an organic R group (or side chain) that is unique to each amino acid."
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A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?
The ratio of time of flight for inelastic collision to elastic collision is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂Considering inelastic collision, the final velocity of the system is calculated as;
\(m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\\)
The time of motion of the system form top of the table is calculated as;
\(v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)\)
Considering elastic collision, the final velocity of the system is calculated as;
\(m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2\)
Apply one-directional velocity
\(u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1\)
Substitute the value of \(v_1\) into the above equation;
\(m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)\)
where;
\(v_2\) is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
\(v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)\)
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
\(\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2\)
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This doesn’t make sense, there is no angle so I can’t use Fnet=mgcos(theta) and can’t find acceleration in a=mgsin(theta).
The magnitude of the net force on the block while it is sliding is 9.8 N.
What is the angle of inclination of the plane?
The angle of inclination of the plane is calculated by applying the principle of trigonometry ratio.
Considering the vertical height (10 m) and length of the incline (20 m);
sin θ = 10 m / 20 m
sin θ = 1/2
sin θ = 0.5
θ = arc sin(0.5)
θ = 30⁰
The magnitude of the net force on the block while it is sliding is calculated as follows;
F(║) = F(net) = mg sinθ
where;
m is mass of the blockg is acceleration due to gravityF(║) implies parallel force, since there is no friction on the inclineF(net) = (2 x 9.8) x sin(30)
F(net) = 9.8 N
Thus, the net force on the block is the parallel component of the weight of the block.
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Can someone please help me it's urgent!
Answer:
6.8 x 10^6
Explanation:
Look up M A T H W A Y it will help you with all of your algebra needs
Select the correct answer?
Answer:
The answer is d i think so yea
Explanation:
hope u hae a really good day
If the voltmeter used in problem 84 holds steady at 45 V and the ammeter reading holds steady at 5.0 A, estimate the time in seconds required to completely vaporize the water in the beaker. Use 4,2 kJ/kg. C as the specific heat of water and 2,3 x 10^6 J/kg as the heat of vaporization of water.
If the voltmeter holds steady at 45 V and the ammeter reading holds steady at 5.0 A. It would take approximately 12133.3 seconds, or about 3.37 hours, time to completely vaporize the water in the beaker.
Since the voltmeter reading and ammeter reading hold steady, the power input to the water is constant. The power input is given by the product of the voltage and current
P = VI = (45 V)(5.0 A) = 225 W
The energy required to vaporize the water can be found using the heat of vaporization of water
Q = mL = (1 kg)(2.3 x \(10^{6}\) J/kg) = 2.3 x \(10^{6}\) J
The energy required to raise the temperature of the water from room temperature to boiling can be found using the specific heat of water
Q = mcΔT = (1 kg)(4.2 kJ/kg. C)(100 C) = 420 kJ = 420,000 J
The total energy required to completely vaporize the water is the sum of the energy required to raise the temperature and the energy required to vaporize
Qtotal = Q + 420,000 J = 2.3 x \(10^{6}\) J + 420,000 J = 2.72 x \(10^{6}\) J
The time required to deliver this amount of energy at a constant power of 225 W is
t = Qtotal / P = (2.72 x \(10^{6}\) J) / (225 W) = 12133.3 s
Therefore, it would take approximately 12133.3 seconds, or about 3.37 hours, to completely vaporize the water in the beaker.
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What would the overall resistance be in a series circuit if there's an unknown R, 3Ω,3Ω and a current of 2A?
Answer:
R + 6 ohms
Explanation:
The current is the same in all three resistors
i = 2 amps
The problem is that the total voltage is unknown.
R = r
R1 =3 ohms
R2 = 3 ohms
The voltage drop is E = I*R
I = 2 amps
R1 = 3 ohms
R1 = 3 ohms
E = 3*2 = 6 volts
The second 3 ohm resistor also has 6 volts across it.
The total is 12 volts so far. But we know nothing more on how to solve for R.
All you can say is that the total resistance = R + 6 ohms
If the distance between two objects is 15.00 m and the distance is tripled, then what is the new distance?
Answer:
so the answer is 45
Explanation:
you 15x3=45
5x3=15
this is a another way to do it add 15+15+15=45
15+15=30
then you add 15
then you get 45
NASA is conducting a test with the Perseverance Rover to investigate the gravity on Mars. They test a pendulum with a length of L on the Earth and find it has a period of 1.0 s. The Perseverance Rover has a similar pendulum with a length of L/2. If the acceleration due to gravity on Mars is 1/3 the acceleration due to gravity on the Earth, what is the period of the Perseverance Rover's pendulum on Mars?
If the time period of the pendulum in earth is 1 seconds, then the length L is 0.24 m. If length in mars is L/2 and acceleration due to gravity is 1/3rd of that of earth, the time period of the pendulum on mars is 1.216 seconds.
What is time period of oscillation ?The time period of oscillation of a pendulum is the time taken to complete oscillation. It is related to the length l, and acceleration due to gravity g as:
T = 2π √l/g
T for earth = 1 s
g for earth = 9.8 m/s²
then l = T/4π² × g
l = 1/4π²× 9.8 m/s²
= 0.24 m
If in mars L = L/2 = 0.24 /2 = 0.12 m
g = 9.8 m/s²/3 = 3.22m/s²
Then time period T = 2π × √0.12 m/3.22m/s²
T = 1.216 s.
Therefore, the time period of the Rover's pendulum in mars is 1.216 seconds.
Find more on period of oscillation:
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A spring is attatched at one end to support B and at the other end to collar A, as represented in the figure. Collar A slides along the vertical bar between points C and D.Part A when 0 = 28 degrees, what is the distance from point A to point B to the nearest tenth of a foot?Part B When the spring is stretched and the distanced from point A to point B is 5.2 feet, what is the valuue of 0 to the nearest tenth of a degree?
(A) The distance from point A to point B to the nearest tenth of a foot will be 3.4 ft.
(B) The value of 0 to the nearest tenth of a degree will be 54.8°
SOH, CAH, and TOA are the trigonometry ratios that need to be solved in order to find necessary measures or angles in a right triangle.
A) Reference angle = 28 degrees
Distance A-B = ?
Adjacent = 3 ft
We will calculate the distance between A-B by using the trigonometry function, CAH, that is:
Cos ∅ = adj ÷ hyp
Cos 28° = 3 ÷ A-B
A-B = 3 ÷ Cos 28°
A-B = 3.4 ft
B) Reference angle = ?
Distance A-B = 5.2 ft
Adjacent = 3 ft
We will calculate the distance between A-B by using the trigonometry function, CAH, that is:
Cos ∅ = adj ÷ hyp
Put the values
Cos ∅ = 3 ÷ 5.2
∅ = Cos⁻¹ (3 ÷ 5.2)
∅ = 54.8°
You can also learn about trigonometry function from the following question:
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