A qualitative variable is a variable that cannot be measured in numerical terms, but rather, is characterized by qualities or attributes that are not numerical. Option A is the correct answer.
Qualitative variables are also called categorical variables because they represent categories or groups. Examples of qualitative variables include gender, nationality, religion, and occupation.
In contrast, quantitative variables can be measured in numerical terms, such as age, height, weight, income, and test scores. Understanding the nature and characteristics of different types of variables is important for selecting appropriate statistical methods and techniques to analyze and interpret data.
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Express the given function has a composition of two functions and so that h(x) = (fog) h(x) 1 5x + Choose the correct pair of functions. O A f(x) = 5x +8 ) = OB. 40 = 2(x+3x+8 O c. f(x)=x-8. 9(x)= 3x 1 D. f(x)=6x9(x)=x-8 possible Express the given function has a composition of two functions f and g so that h(x) = (fog)(x). h(x) = 2X-8 Choose the correct pair of functions. O A x)=2x-8, g(x) = -1 OB. 100 g1x)=2x-8 O c. f(x)= 2 g(x)=x-8 D. lx=x-8, g(x) = 1 possible For f(x) = 2x and g(x) = x + 4 find the following. a. (fog)(x) b. (gof)(x) c. (fog)(2) a. What is (fog)(x)? (fog)(x)=(Simplify your answer.) b. What is (gof)(x)? (gof)(x)=(Simplify your answer.) c. What is (fogX2)? (fog)(2)-(Simplify your answer.)
The correct pair of functions that express h(x) = (fog)(x) as a composition of two functions are f(x) = 5x + 1 and g(x) = (x+8)/5.
Explanation: To find the functions f and g that compose h(x) = (fog)(x), we need to solve for f and g using the formula for function composition:(fog)(x) = f(g(x))Given that h(x) = (fog)(x) = (5x+1+8)/5 = (5x+9)/5, we can set g(x) = (x+8)/5 and f(x) = 5x+1 to get:(fog)(x) = f(g(x)) = f((x+8)/5) = 5((x+8)/5) + 1 = x + 9/5Therefore, the correct pair of functions that express h(x) as a composition of two functions are f(x) = 5x + 1 and g(x) = (x+8)/5.---For f(x) = 2x and g(x) = x + 4, we can find:a. (fog)(x) = f(g(x)) = f(x+4) = 2(x+4) = 2x + 8b. (gof)(x) = g(f(x)) = g(2x) = 2x + 4c. (fog)(2) = f(g(2)) = f(6) = 2(6) = 12Therefore, (fog)(x) = 2x + 8, (gof)(x) = 2x + 4, and (fog)(2) = 12.
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during a game of checkers, there is 16 pieces left. The ratio of black to red is 3:5 . How many black pieces are left on the board? Explain how you found the answer.
Since the ratio of the black to red is 3: 5
Then the total of the ratio is 3 + 5 = 8
Since there are 16 pieces left
By using the ratio method
black: red: total
3. : 5 : 8
x. : y : 16
By using cross multiplication
x x 8 = 3 x 16
8x = 48
Divide both sides by 8 to find x
x = 6
Since x represents the black left
The answer is 6 black left
A model car is constructed with a scale of 1:15. If the actual car is 12 feet long, which proportion represents the length x of the model car?
The length of the model car based on the information is 0.8 feet.
What is scale?It should be noted that scale simply shows the relationship between a measurement on a model as well as the corresponding measurement on the actual object.
From the information, the model car is constructed with a scale of 1:15.
When the actual car is 12 feet long, the length of the model will be illustrated as x. This will be:
= 1/15 = x / 12
Cross multiply
15x = 1 × 12
15x = 12
Divide
x = 12 / 15
x = 0.8
The length is 0.8 feet.
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ABCD is rotated counterclockwise about the origin. By how many degrees
was ABCD rotated?
Pure salt is made up of sodium and chloride. Each gram
of salt contains 0. 393 g of sodium. About how much
sodium is in 55. 7 g of pure salt?
21.615 grams of sodium will be present in 55.7 grams of pure salt.
What does multiplication mean?
A method of calculating the sum of two or more numbers is multiplication. It is one of the fundamental operations in mathematics that we perform on a daily basis.
Given that pure salt is made up of sodium and chloride.
In 1 gram of salt, 0.393 grams of sodium is present.
So in 55 grams of salt, 0.393*55 grams of sodium is present.
Which is equal to 21.615 grams of sodium.
Therefore in 55.7 grams of pure salt, 21.615 grams of sodium will be present.
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This is the second time asking this question
Which symbol correctly compares these fractions?
−35□−23
>
<
=
Answer:
The answer is -2/3 < -3/5
Help please this is for geometry. its easy.
Answer:
Step-by-step explanation:
ccadcdddddddddddddddddddddddd
Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.
a.
10
d.
4 5
b. 4 5
I
s 100
10
4
8
--
8 10
415
이
00
I
C. 10 85
815
I
10
I
2/5
I
211
552
415
Mark this and return
Next
Submit
The ratio of corresponding sides for the given similar triangles is 2/5.
In the given options, the ratio of corresponding sides is provided for each set of similar triangles. Let's analyze each option to determine the correct ratio:
a. 10
This option only provides a single number and does not specify the ratio of corresponding sides. Therefore, it is not the correct answer.
b. 4/5
This option provides the ratio 4/5 for the corresponding sides of the similar triangles. However, the ratio can be simplified further.
To simplify the ratio, we divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 4 and 5 is 1.
Dividing 4 and 5 by 1, we get:
4 ÷ 1 = 4
5 ÷ 1 = 5
Therefore, the simplified ratio is 4/5.
c. 10/85
This option provides the ratio 10/85 for the corresponding sides of the similar triangles. However, this ratio cannot be simplified further, as 10 and 85 do not have a common factor other than 1.
Therefore, the correct ratio of corresponding sides for the given similar triangles is 2/5, as determined in option b.
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Marcus wants to buy a gallon of orange juice. If a 1-gallon jug costs $4.58
and a quart costs $1.59, how much money would Marcus save by buying the
1-gallon jug instead of multiple quarts?
O A. $2.99
O
B. $0.19
C. $1.78
O D. $1.40
????
the conditions that the sum of forces and the sum of the torques both vanish:
Answer and Explanation: The conditions when the net force and the net torque are zero are called static equilibrium.
Find the following measure for this figure.
4
6
Lateral area =
24 square units
48 square units
96 square units
The surface area of the right circular cylinder will be 48π square units. Then the correct option is B.
The complete question is attached below.
What is the surface area of a right circular cylinder?Let r be the radius and h be the height of the cylinder.
Then the surface area of the cylinder will be
SA = 2πrh square units
r = 4 units
h = 6 units
Then we have
SA = 2 × π × 4 × 6
SA = 48π square units
Then the correct option is B.
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19=5+7x i need explanation it’s two step equation btw
Answer:
x = 2
Step-by-step explanation:
subtract both sides by 5. left with 14=7x. divide both sides by 7. x=2
Answer:
\(\boxed{\sf x=2}\)Step-by-step explanation:
\(\sf 19 =5+7x\)
First, let's swap sides so that all variable terms are on the left hand side.
\(\sf 5+7x=19\)
Subtract 5 from both sides:
\(\sf 7x=19-5\)
Subtract 5 from 19:
\(\sf 7x=14\)
Divide both sides by 7:
\(\sf \cfrac{7x}{7} =\cfrac{14}{7}\)
\(\sf x=2\)
_____________________________________
one possible combination is red and hearts. write down all the other possible combinationas. write your answer like this (R,H) you must write all your answers on one line
Answer:
hmmmm.... sorry but i really dont know this yet
Step-by-step explanation:
WILL,,GIVE,,BRAINLIEST!!!!!!!!!
Question:
In picture
HAVE A BRAINLY DAY!!!! :D
You do 22/7 and put the remainder over 7.
7 times 3 is 21 so the remainder is 1.
The answer is 3 and 1/7. Choice 3.
Answer:
\(3\frac{1}{7}\)
Step-by-step explanation:
Break it up by asking questions. First, how many 7's fit as a whole into 22:
22 ÷ 7 = 3What is the remainder:
7 × 3 = 2122 - 21 = 1Using the original denominator and our above math, write the mixed number:
\(3\frac{1}{7}\)I hope this helps!
Find the slope of a line with x-intercept 5 and y-intercept -3.
Answer:
3/5
Step-by-step explanation:
When you are given an x-intercept, the y value will always be 0.
When you are given a y-intercept, the x value will always be 0.
With the intercepts we are given, we can make two points we can solve for the slope with.
(5, 0)
(0, -3)
Now, find the slope with the formula [ y2-y1/x2-x1 ]
-3-0/0-5
-3/-5
3/5 or 0.6
Best of Luck!
Question 4 of 5
Meredith is trying to estimate √51 She uses this table of values:
7. 4² 7. 5²
Square 7. 02 07. 12 7. 22 7. 3²
Value 49. 0 50. 41 51. 84 53. 29 54. 76 56. 25
Square 7. 62 7. 72 7. 82 7. 92 8. 02
Value 57. 76 59. 29 60. 84 62. 41 64. 0
4
What should she do next to find √51 to the nearest hundredth?
OA. She should find the average of 7. 1 and 7. 2.
B. She should find the squares of numbers between 7. 2 and 7. 3.
OC. She should find the squares of numbers between 7. 1 and 7. 2.
O D. She should estimate that √51 is 7. 20.
SUBMIT
She needs to locate the squares of the integers between 7.1 and 7.2 in order to estimate √51.
What is the square root of a number?Finding an integer's square root is the inverse of squaring an integer. A number's square value is obtained by multiplying it by itself, whereas the square root of a number can be discovered by looking for a number that, when squared, produces the original value. It follows that a× a = b if "a" is the square root of "b." Every number has two square roots, one of a positive value and one of a negative value because the square of any number is always a positive number.
In the question given to us,
look at the table, we know
(7.1)² = 50.41 and (7.2)² = 51.84
So, (7.1) < √51 < 7.2 { estimate }
They should therefore determine the squares of the numbers between 7.1 and 7.2.
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The complete question is :
Meredith is trying to estimate √51 She uses this table of values:
What should she do next to find √51 to the nearest hundredth?
A. She should find the average of 7. 1 and 7. 2.
B. She should find the squares of numbers between 7. 2 and 7. 3.
C. She should find the squares of numbers between 7. 1 and 7. 2.
D. She should estimate that √51 is 7. 20.
Scarlett usually rides her bike about 1 and 1/5 hours every day. The distance between the library and school is 7/8 mile. Yesterday the bike had a problem and Scarlett only rode her bike 2/3 of the way from school to the library and walked the rest of the way. How far did she ride her bike
Scarlett typically rides her bike for around 1 and a half hours per day, thus she covered a distance of 7/12.
what is distance ?The overall uninspired velocity of an object will be its distance. Distance is the amount of space an object has traveled, regardless of where it began or ended. Distance would be the measurement of said size or extent of the separation between two places. It is important to keep in mind that the distance between two spots and the traveled between them aren't the same thing. Distance traveled is the sum of a line's length joining various places. Distance refers to the actual travel path of a body. Path length is another term for it. For instance, if an object is traveling from board to point P, the path's length will be similar to OP = 360 m.
given
We are aware of: t = 1 1/5 d = 7/8
Write down and replace 7/8 = v * (1* 1/5)
Remove the connecting element: 7/4 * 1/3
As a single fraction, write:
7 / 4*3
Determine the quotient or product: 7/12
Response: 7/12
Scarlett typically rides her bike for around 1 and a half hours per day, thus she covered a distance of 7/12.
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Justin and his friends went to a movie that started at 7:35 p.m. Justin got home 50 minutes after the movie ended. What time did Justin get home?
find an equation in standard form for the ellipse with the vertical major axis of length 6 and minor axis of length 4. (2 points)
Standard form of ellipse has equation \(\frac{y^2}{a^2} +\frac{x^2}{b^2} =1\) where, a and b are the halves of the length of major and minor axis respectively.
Given that,
Length of major axis(2a)=6.
So
a=6/2
=3
Length of minor axis(2b)=4.
So
b=4/2
=2
Putting in equation of standard ellipse. We get
\(\frac{y^2}{3^2} +\frac{x^2}{2^2} =1\)
After simplifying
4y² + 9x² = 36
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Solve for g.
9 - g = 2g
Answer:
g=3
Step-by-step explanation:
9 - g = 2g
+g +g
9=3g
divide both sides by 3
g=9
HELPPPPP ASAP 10 POINTS
Answer:
area = 38.47 cm²
Step-by-step explanation:
area = 1/4(3.14)(7²) = 38.47 cm²
Write the coordinates of the vertices after a dilation with a scale factor of 1/4, centered at the origin.
Answer:
E'(-2, 2)F'(0, 0)G'(-2, -2)Step-by-step explanation:
You want the coordinates of the vertices of ∆E'F'G' after ∆EFG has been dilated with a scale factor of 1/4.
DilationDilation about the origin multiplies each preimage coordinate by the scale factor.
E' = (1/4)E = (1/4)(-8, 8) = (-2, 2)
F' = (1/4)F = (1/4)(0, 0) = (0, 0)
G' = (1/4)G = (1/4)(-8, -8) = (-2, -2)
The coordinates after dilation are E'(-2, 2), F'(0, 0), G'(-2, -2).
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an 800 g steel plate has the shape of the isosceles triangle shown in the figure(figure 1).
The x- and y-coordinates of the center of mass are; (20, 0)
What is the center of mass of an object?The center of mass is the location where the sum of the relative position of the masses in a mass distribution is zero. It is the point where force can be applied on the distributed mass without causing a rotation of the system.
The mas of the steel plate = 800 g = 0.8 kg
The base length of the isosceles triangular plate = 20 cm = 0.2 m
The height of the isosceles triangular plate = 30 cm = 0.3 m
Considering a small strip of height, dx and width, I, we get
Area of small strip, dA = I·dx
Density of the plate for a unit thickness, ρ = M/A
Density of the small strip of mass dm = dm/dA
Considering the density of the plate as uniform, we get;
\(\displaystyle {\frac{dm}{dA} =\frac{M}{A}\)
Therefore;
\(\displaystyle {dm=\frac{M}{A}\times dA}\)
The area of the triangular plate, A = (1/2) × 0.2 m × 0.3 m = 0.03 m²
Mass of the plate, M = 0.8 kg
Therefore;
\(\displaystyle {dm=\frac{0.8}{0.03}\times I\cdot dx}\)
The width of the small strip, I, located at a distance x from the vertex of the triangular plate, using similar triangles, indicates;
\(\dfrac{I}{20} = \dfrac{x}{30}\)
\(I=20\times \dfrac{x}{30} = \dfrac{2}{3} \cdot x\)
Therefore;
\(\displaystyle {dm=\frac{0.8}{0.03}\times I\cdot dx} = \frac{0.8}{0.03}\times \dfrac{2}{3} \cdot x\cdot dx}\)
The center of mass, \(x_{cm}\), can be obtained with the formula; \(\displaystyle {x_{cm} = \dfrac{1}{M} \cdot \int\limits {x} \, dm }\)
Therefore; \(\displaystyle {x_{cm} = \dfrac{1}{0.8} \cdot \int\limits {x} \cdot \frac{0.8}{0.03} \cdot \frac{2}{3}\cdot x\, dx }\)
\(\displaystyle {x_{cm} = \dfrac{1}{0.8} \cdot \int\limits {x} \cdot \frac{0.8}{0.03} \cdot \frac{2}{3}\cdot x\, dx } = \dfrac{1}{0.8} \times \frac{0.8}{0.03} \times \frac{2}{3}\cdot \int\limits^3_0 {x^2} \, dx\)
\(\displaystyle {x_{cm} = \dfrac{1}{0.8} \times \frac{0.8}{0.03} \times \frac{2}{3}\cdot \int\limits^3_0 {x^2} \, dx = \frac{200}{9} \cdot \left[\frac{x^3}{3} \right]^{0.3}_0\)
\(\displaystyle {x_{cm} = \frac{200}{9} \cdot \left[\frac{x^3}{3} \right]^{0.3}_0=\frac{200}{9} \times \frac{0.027}{3} =0.2\)
The location of the x-coordinate center of mass, \(x_{cm}\) = 0.2 m = 20 cm from the vertex, which is the same location as the x-coordinate of the centroid of the plate of uniform density.
The plate is symmetrical about the x-axis, therefore, the y-coordinate of the center of mass is along the x-axis, which is \(y_{cm}\) = 0
The coordinate of the center of mass = (0.2, 0)
Part of the question requires the location of the coordinate of the center of mass of the triangular plate
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Evaluate the expression when z=7 3z+8
Answer:
Hi! The answer to your question is \(29\)
Step-by-step explanation:
\(3(7)+8\)
\(3(7) = 21\)
\(21 + 8\)
\(= 29\)
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Please help!
Write the equation that describes the simple harmonic motion of a particle moving uniformly around a circle of radius 7 units, with angular speed 2 radians per second.
The equation that describes the simple harmonic motion of the particle is:
x = 7 * sin(2t + φ)
The equation that describes the simple harmonic motion of a particle moving uniformly around a circle can be represented as:
x = A * sin(ωt + φ)
In this equation:
x represents the displacement of the particle at time t.
A represents the amplitude of the motion.
ω represents the angular frequency or angular speed of the motion.
t represents time.
φ represents the phase constant.
In the given scenario, the particle is moving uniformly around a circle of radius 7 units, with an angular speed of 2 radians per second. In circular motion, the displacement can be represented by the arc length along the circumference of the circle.
Since the angular speed is 2 radians per second, the angular frequency (ω) is also 2 radians per second.
Since the particle is moving uniformly, the amplitude of the motion (A) is equal to the radius of the circle, which is 7 units.
The phase constant (φ) determines the initial position of the particle at t = 0.
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Suppose we have 4 email messages. We have also classified 3 messages as normal and 1 as spam. Use Naïve Bayes multinomial to answer the question that follows. Use alpha=1 to avoid zero probabilities.
Message Content Classification
1 Chinese Beijing Chinese Normal
2 Chinese Chinese Shanghai Normal
3 Chinese Macao Normal
4 Tokyo Japan Chinese Spam
Round your answer to the nearest ten thousand
P(Tokyo | Spam)
Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.
To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.
3 messages are classified as "Normal."
1 message is classified as "Spam."
We calculate the probabilities as follows:
P(Class = Normal) = 3/4 = 0.75
P(Class = Spam) = 1/4 = 0.25
Next, we analyze the occurrence of words in each class:
For the "Normal" class:
The word "Chinese" appears 5 times.
The word "Beijing" appears 1 time.
The word "Shanghai" appears 1 time.
The word "Macao" appears 1 time.
For the "Spam" class:
The word "Tokyo" appears 1 time.
The word "Japan" appears 1 time.
The word "Chinese" appears 1 time.
Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):
P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9
P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9
P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9
P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9
P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7
P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7
P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7
To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:
P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)
≈ (6/9) * (0/9) * (0/9) * 0.75
= 0
P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)
≈ (2/7) * (2/7) * (2/7) * 0.25
≈ 0.017
Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.
In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.
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Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.
To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.
3 messages are classified as "Normal."
1 message is classified as "Spam."
We calculate the probabilities as follows:
P(Class = Normal) = 3/4 = 0.75
P(Class = Spam) = 1/4 = 0.25
Next, we analyze the occurrence of words in each class:
For the "Normal" class:
The word "Chinese" appears 5 times.
The word "Beijing" appears 1 time.
The word "Shanghai" appears 1 time.
The word "Macao" appears 1 time.
For the "Spam" class:
The word "Tokyo" appears 1 time.
The word "Japan" appears 1 time.
The word "Chinese" appears 1 time.
Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):
P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9
P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9
P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9
P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9
P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7
P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7
P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7
To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:
P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)
≈ (6/9) * (0/9) * (0/9) * 0.75
= 0
P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)
≈ (2/7) * (2/7) * (2/7) * 0.25
≈ 0.017
Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.
In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.
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When she was in Year 8, Sarah could run 800 metres
in 3 minutes and 20 seconds.
Three years later, when she was in Year 11, she could run 800 metres
in 2 minutes and 44 seconds.
Find the percentage improvement in her time
Sarah's percentage improvement in her time is 18% between Year 8 and Year 11.
What is percentage?A percentage is a means to represent a percentage of 100 as a part of a whole. "%" is the symbol for percentage. For instance, if there are 25 female students in a class of 100, we may say that there are 25% of female students in the class because 25 is 25/100, or 0.25 when represented as a fraction of 100.
In a variety of areas, including finance, statistics, and daily life, percentages are used. They are frequently used to compare values that are stated in different units, such as weight or height, and to describe changes, such as percentage increases or decreases. Many professions require the ability to understand percentages, and it is frequently vital to be able to convert between percentages, fractions, and decimals.
The percentage improvement can be given by the formula:
percentage improvement = ((old time - new time) / old time) x 100%
Converting the time in one unit we have:
3 minutes 20 seconds = 3(60) + 20 = 200 sec
2 minutes 44 seconds = 2(60) + 44 = 164 sec
Substituting the values we have:
percentage improvement = (200 sec - 164 sec) / 200 sec x 100%
percentage improvement = 18%
Hence, Sarah improved her time by 18% between Year 8 and Year 11.
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Graph the line with the slope of -4 and passing through ( 3, 5 ).
Answer:
See graph below of the line y - 5 = - 4 (x - 3) OR y = -4 x + 17Step-by-step explanation:
We can write the equation for such a line using the point-slope form [(y - y₁) = m (x - x₁)] where m = - 4 & (x₁ , y₁) = ( 3, 5 ). We can then find the x and y-intercept. The line we draw through these three points will be the line we are trying to find.
Equation of the Line
y - 5 = - 4 (x - 3)
Finding x and y-intercepts
y-intercept is 'c' when the line is in the slope-intercept form (y = mx + c)
since y - 5 = - 4 (x - 3)
y - 5 = -4 x + 12
y = -4 x + 17
∴ point of the y-intercept is (0, 17)
x-intercept occurs when y = 0
y = -4 x + 17
0 = -4 x + 17
-17 = -4x
x = ¹⁷/₄
∴ point of the x-intercept is (¹⁷/₄, 0)
Graph the line
We can now plug in the points and draw the line.
See the example below.
Note: You only need two points to graph the line. I just did a third as a check.
Please help trigonometry
Answer:
= 59.36
Step-by-step explanation:
S = 207
so, tan(16) = H/S
tan(16°) = 0.28674539
so H = tan(16) * S = 0.28674539 * 207 = 59.35629573
so the tree high = 59.36 foot
can anyone help me solve these please ?
Answer:
dufenschmertz evil incorporated...
Step-by-step explanation:
after hours ;)