When 13.8 cm of water is added to one side of a U-tube containing mercury with a density of 13.6 g/cm³, the mercury rises by approximately 1.01 cm on the other side to balance the pressure.
To determine how high the mercury rises on the other side of the U-tube when 13.8 cm of water is added, we need to consider the principles of hydrostatics and the relationship between pressure and density in a fluid.
The density of mercury is given as 13.6 g/cm³, which means that it is much denser than water (which has a density of approximately 1 g/cm³). In a U-tube, the pressure at any given point is the same on both sides.
Initially, when there is only mercury in the U-tube, the pressure on both sides of the U-tube is equal. When water is added to one side, the pressure on that side increases.
This increase in pressure causes the mercury to rise on the other side to balance the pressure.
Using the equation for pressure, P = ρgh, where P is the pressure, ρ is the density, g is the acceleration due to gravity, and h is the height of the fluid column, we can set up an equation using the known values.
Initially, the pressure on both sides is the same, so the pressure due to the mercury column is equal to the pressure due to the water column:
ρ₁gh₁ = ρ₂gh₂,
where ρ₁ is the density of mercury, ρ₂ is the density of water, h₁ is the initial height of the mercury column, and h₂ is the height of the water column.
Since we want to find the height of the mercury column on the other side, we can rearrange the equation to solve for h₁:
h₁ = (ρ₂/ρ₁)h₂.
Substituting the given values, we have:
h₁ = (1 g/cm³ / 13.6 g/cm³) * 13.8 cm.
Simplifying the calculation, we find:
h₁ ≈ 1.01 cm.
Therefore, the mercury rises by approximately 1.01 cm on the other side from its original level when 13.8 cm of water is added to one side of the U-tube.
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What is the height at the peak of the projectiles trajectory if the magnitude vo equals 42.2 meters per second, and the angle ofΘis 41.8 degrees?
Take into account that the vertical final velocity of the projectile is given by:
\(v^2_y=v^2_{oy}-2gy\)Now, consider that at the peak of the trajectory, the vertical final velocity is zero. Moreover:
\(v^2_{oy}=v^2_o\sin ^2\theta\)Then, by solving for y into the equation for vy^2, you obtain:
\(\begin{gathered} o=v^2_o\sin ^2\theta-2gy \\ y=\frac{v^2_o\sin \theta}{2g} \end{gathered}\)where g = 9.8m/s^2 is the gravitational acceleration constant.
By using the given values for the angle and vo you obtain for the height of the peak y:
\(y=\frac{(42.2\frac{m}{s})(\sin 41.8)^2}{2(9.8\frac{m}{s^2})}\approx40.36m\)Hence, the height of the peak of the projectil trajectory is approximately 40.36 m
A prism is made from transparent plastic. In this plastic, light travels at 0.8
in air. Light enters one face of the prism at right-angles as shown.
NOT TO
SCALE
ө
The light just escapes from the sloping face of the prism.
What is angle 0?
A 37°
B
390
С
510
D
53°
Answer:
Real answer is im sorry if im wrong
Explanation:
A 53°
The value of the angle Θ will be 51.3°. Option C is correct.
What is the definition of geometry?It is concerned with the geometry, region, and density of various 2D and 3D shapes.
From snell's law;
\(\rm n= \frac{sini}{sinr} \\\\ 0.8= \frac{sin(90-\theta)}{sin \theta} \\\\ 0.8= cot \theta \\\\ \theta= cot^{-1} (0.8)\\\\ \theta =51.3^0\)
The value of the angle Θ will be 51.3°.
Hence,option C is correct.
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Science question! helppppp
Let's take this problem step-by-step:
What does this problem want to solve:
⇒ find two pendulums that will swing back and forth in the least amount
of time
Therefore:
⇒ must find the equation that calculates that period or swing time of a
pendulum
Equation: \(T = 2\pi \sqrt{\frac{L}{g} }\)
L: length of the pendulumg: gravitational accelerationBased on the equation:
⇒ the longer the string is ⇒ the greater the swing time
Thus:
⇒ pendulum Y and Z will have the least amount of swing time
Answer: (B)
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3. The potential energy of an object is determined by: a. the movement of the object b. the position of the object c. the speed of the object d. Objects cannot have potential energy.
Answer:
B. the position of the object
I need help with this science question, 50 points!
Answer:
an open circuit (A battery, bulb, wire,switch)
Explanation:
the battery supplies the power the wire carries the current from the battery to the bulb but the circuit is not completed if the switch is not connected (Switch )
Alan and Monica tested how fertilizer X affected the growth of a plant. Alan and Monica put 100 grams of fertilizer X in pot 1. They put 0 grams of fertilizer X in pot 2.
What is pot 2 called in science?
A.
a test group
B.
a data group
C.
an observational group
D.
a control group
Answer:
D.
a control group
Explanation:
In a scientific experiment such as the one above, there is an experimental group and a control group. The experimental group is the group that receives the treatment while the control group does not receive any treatment. The control group helps the researcher to observe if the treatment had any significant effect.
In this case, it will help Alan and Monica to determine if fertilizer X actually had an effect on the plant. Therefore, the pot with o grams of fertilizer in it is the control group.
5°=.........'. =.....,......."
15°6'35"=........... "
5400"=............°.........'
73530s=...........h..........min..........s
1h15min 27s=...........h=........min=..............
47°k=...........°C
58°k=...........°C
0,020kg=.........g
The correct answers to the conversions in the task above are as follows:
a. 5°C = 41°Fb. 15°C= 859.4 degrees radiansc. 5400°F = 2982.2°Cd. 1h 15min 27s = 1h = 75minutes e. 47°k = -226°Cf. 58°k = -215.15°Cg. 0.020kg = 20gWhat is meant by degrees celsius?The degrees celsius is a scale grade which is used to define two different points. This scale system for instance works on the principle of zero degrees (0°) for the freezing point of water and hundred degrees (100°) for the boiling point of water.
From the task given above on converting 0.020kg to g,
Recall:
1000g = 1kg
to convert 0.020kg to grams
then we will have
1000g = 1kg
x = 0.020kg
Cross multiplying
x = 1000 × 0.020
= 20.
This means that we have 20g in 0.020kg.
In conclusion, we can now confirm from the explanation given above that the symbol of degrees celsius is °C.
Complete question:
Convert the following:
a. 5°C to degrees Fahrenheit =.............°F
b. 15°C to radians = ...............
c. 5400 Fahrenheit to degrees Celsius = .....°
d. 1h15min 27s=...........h=........min=..............
e. 47°k=...........°C
f. 58°k=...........°C
g. 0.020kg=.........g
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a 0.60 kg book slides on a horizontal table. the kinetic friction force on the book has magnitude 1.8 n. (a) how much work is done on the book by friction during a displacement of 3.0 m to the left? (b) the book now slides 3.0 m to the right, returning to its starting point. during this second 3.0 m displacement, how much work is done on the book by friction? (c) what is the total work done on the book by friction during the complete round trip? (d) on the basis of your answer to part (c), would you say that the friction force is conservative or nonconservative? explain.
a) The work that is done on the book by friction during a displacement of 3.0 m to the left:
The work done by friction is given by the formula:
\(\[ W = F_{\text{friction}} \cdot d \cdot \cos(\theta) \]\)
Plugging in the values:
\(\[ W = (1.8 \, \text{N}) \cdot (3.0 \, \text{m}) \cdot \cos(180^\circ) \]\)
\(\[ W = -5.4 \, \text{J} \]\)
The negative sign indicates that the work done by friction is in the opposite direction of the displacement.
b) During the second 3.0 m displacement to the right, the work done by friction is calculated in the same way.
However, now the angle between the friction force and the direction of displacement is \(\( 0^\circ \)\) because friction is acting in the direction of displacement. So, the cosine of \(\( 0^\circ \)\) is 1.
\(\[ W = (1.8 \, \text{N}) \cdot (3.0 \, \text{m}) \cdot \cos(0^\circ) \]\)
\(\[ W = 5.4 \, \text{J} \]\)
c) The total work done on the book by friction during the complete round trip is the sum of the work done in both displacements:
Total work = Work to the left + Work to the right
Total work = \((-5.4 \, \text{J}) + (5.4 \, \text{J})\)
Total work = \(0 \, \text{J}\)
d) We can infer that the friction force is nonconservative since the total amount of work done by friction over the entire round trip is zero.
A conservative force does not depend on the direction of motion to perform work in its favor or against it since it conserves mechanical energy.
Thus, friction is nonconservative in this situation because it releases mechanical energy as heat and its work relies on the displacement's direction (different directions produce opposing work signs).
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DETAILS MY NOTES Write the nuclear symbols for each of the following. (Enter the mass number in the first raised box, the atomic number in the second lower box, and the element's symbol in the third box.) (a) strontium-90 90 38 Sr (b) xenon-133 133 54 Xe (c) technetium-95 95 To 43 (d) aluminum-25 25 13 Al
(a) The nuclear symbol for strontium-90 is 90 38 Sr.
(b) The nuclear symbol for xenon-133 is 133 54 Xe.
(c) The nuclear symbol for technetium-95 is 95 43 Tc.
(d) The nuclear symbol for aluminum-25 is 25 13 Al.
Here are the nuclear symbols for each of the given elements:
(a) Strontium-90: 90 38 Sr
Strontium has 38 protons in its nucleus. So, the atomic number of strontium is 38. The mass number of strontium-90 is 90. Therefore, the nuclear symbol for strontium-90 is 90 38 Sr.
(b) Xenon-133: 133 54 Xe
Xenon has 54 protons in its nucleus. So, the atomic number of xenon is 54. The mass number of xenon-133 is 133. Therefore, the nuclear symbol for xenon-133 is 133 54 Xe.
(c) Technetium-95: 95 43 Tc
Technetium has 43 protons in its nucleus. So, the atomic number of technetium is 43. The mass number of technetium-95 is 95. Therefore, the nuclear symbol for technetium-95 is 95 43 Tc.
(d) Aluminum-25: 25 13 Al
Aluminum has 13 protons in its nucleus. So, the atomic number of aluminum is 13. The mass number of aluminum-25 is 25. Therefore, the nuclear symbol for aluminum-25 is 25 13 Al.
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A ball of mass 0.15kg is kicked against a ridge vertical with horizontal velocity of 50m/s. If it rebounded with a horizontal velocity of 30m/s, calculate the impulse of the ball to the wall
So, the impulse of the ball to the wall is -12 N. It have same meaning to 12 N in opposite direction with its initial movement.
IntroductionHi ! In this ocassion, I will help you to solve the question about impulses. Impulse also relate to momentum, where the amount of impulse will cause the difference (indicated in units of direction) velocity when an object move. Impulses that have opposite direction to the original direction will have a negative value.
Formula UsedImpulse is the result of a change in momentum, so it can be expressed in this formula :
\(\sf{I = \Delta p}\)
\(\boxed{\sf{\bold{I = m (v' - v_0)}}}\)
With the following condition:
I = impulse (N.s)m = mass of the object (kg)\(\sf{v'}\) = final speed after collision (m/s)\(\sf{v_0}\) = initial speed before collision (m/s)Problem SolvingTips:We will use the starting point of the ball as a reference for the direction of ball's velocity. This is because what is being asked is the impulse of the ball to the wall not the impulse of the wall to the ball. But still, the value is the same.We know that :m = mass of the balls = 0.15 kg\(\sf{v'}\) = final speed of the balls = -30 m/s (30 m/s at the opposite direction from initial speed). \(\sf{v_0}\) = initial speed of the balls = 50 m/sWhat was asked ?I = impulse the ball to the wall = ... N.sProblem solving :\(\sf{I = m (v' - v_0)}\)
\(\sf{I = 0.15 (-30 - 50)}\)
\(\sf{I = 0.15 (-80)}\)
\(\boxed{\sf{I = -12 \: N.s}}\)
ConclusionSo, the impulse of the ball to the wall is -12 N. It have same meaning to 12 N in opposite direction with its initial movement.
a rock is dropped from a bridge and it hits the river 4.5 seconds later. How high is the bridge?
Answer:
99 meters
Explanation:
Apply the distance formula:
\( \displaystyle{s = ut + \dfrac{1}{2} g{t}^{2} }\)
where u is initial velocity which is 0 m/s since there is no initial velocity by dropping an object.
t is time which we know is 4.5 seconds. Finally, g is a constant of acceleration due to gravity which on Earth equals to 9.8 m/s². Therefore:
\( \displaystyle{s = 0 \cdot 4.5 + \dfrac{1}{2}(9.8) {(4.5)}^{2} } \\ \\ \displaystyle{s = \dfrac{1}{2}(9.8) {(4.5)}^{2} } \\ \\ \displaystyle{s \approx 99 \: \text{m}}\)
Therefore, the bridge is around 99 meters height.
How electromagnet works in circuit breaker
Explanation:
A circuit breaker is an automatic switch that cut off current in a circuit when the current become too large. When the current in a circuit increases, the strength of the electromagnet will increase in accordance; this will pull the soft iron armature towards the electromagnet.
Even though every action force has an equal but opposite reaction
force, they do not cancel one another and motion may still occur because
the
Answer: Action and reaction forces are applied to different objects
Explanation:
Answer:
action and reaction forces are applied to different objects
Explanation:
A negative charge of -2.0×10^ -4C and a positive charge of 8.0×10^ -4C are separated by 0.30 m. What is the force between the two charges?
There will be 16,000 N of force between the two charges. It is the force that a charge puts on another charge.
What is electric force?The electric force between two charges is inversely proportional to the square of the distance that separates them and directly proportional to the product of the charges.
Briefing:The given data in the problem is;
q₁ is the magnitude of charge 1= - 2.0x10⁻⁴ C
q₂ is the magnitude of charge 2 = + 8.0x10⁻⁴ C
k is the proportionality constant = 9 x 10⁹ Nm² / C²
r is the separated distance = 0.30 m
F is the electric force=?
The electric force is found as;
\(\mathrm{F}=\frac{\mathrm{Kq}_1 4 \mathrm{q}_2}{\mathrm{r}^2}\)
\(\mathrm{F}=\frac{9 \times 10^9 \times 2.0 \times 10^{-4}}{(0.30)^2}\)
F = 16,000 N
There will be 16,000 N of force between the two charges.
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a car reaches 80 kilometers per hour, then suddenly crashes into the concrete wall
Answer:
what is the question ? That is only a statement
What is the average speed of an object that travels 510 meters in 17 days?
a . 30 meters/day
b. 493 meters/day
c . 527 meters/day
d . 8670 meters/day
e . none of the above
What is the volume (in cm3) of a 63.4 g piece of metal with a density of 12.86 g/cm3?
The piece of metal with a density of 12.86 g/cm3 and a mass of 63.4 g has a volume of: 4.93 cm3
To solve this problem the density formula and the procedure that we have to use is:
d = m/v
Where:
v= volumed= densitym= massInformation about the problem:
d = 12.86 g/cm3m= 63.4 gv=?Applying the density formula and clearing the volume we get:
d = m/v
v= m/d
v= 63.4 g/ 12.86 g/cm3
v= 4.93 cm3
What is volume?It is the space occupied by a body, it is calculated by multiplying its dimensions, for example: length, height and width.
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What force is required to move a 90.0 kg object in a circle of diameter = 85.0 meters at a constant speed of 8.10 m/s?
The force required to move the 90 Kg object at a constant speed of 8.10 m/s is 138.94 N
How to determine the force required?The force required to keep an object moving in a circle is called Centripetal force. This is defined according to the following equation:
F = mv²/r
F is the centripetal forcem is the massv is the velocityr is the radiusWith the above formula, we can obtain the force required to move the 90 Kg object. Details below:
Mass of object (m) = 90 KgDiameter = 85.0 metersRadius (r) = Diameter / 2 = 85 / 2 = 42.5 metersSpeed of object (v) = 8.10 m/sForce required (F) =?F = mv²/r
F = (90 × 8.10²) / 42.5
F = (90 × 65.1) / 42.5
F = 5904.9 / 42.5
F = 138.94 N
Thus, the force required is 138.94 N
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The radius of a Bromine (Br) atom is 100 pm. What is its' Circumference?
Answer:
The circumference of the bromine atom is 628 pm
Explanation:
The formula for the circumference of a circle is 2πr.
Where π is 3.14 and r is the radius of the circle.
Since atoms have a circular shape. The formula above can be used to determine the circumference of an atom (bromine atom in particular).
circumference of the bromine atom is 2πr (where r is 100 pm)
2 × 3.14 × 100 = 628 pm.
The circumference of the bromine atom is 628 pm
Which of the following statements BEST predicts the outcome of the chemical reaction?
Answer:
Explanation:
what are the statement
Gibb's and Helmholtz equations predicts the direction and spontaneity of chemical reactions.
What is Gibb's and Helmholtz equation ?The Gibbs-Helmholtz equation is a thermodynamic equation that is used to calculate changes in a system's Gibbs free energy as a function of temperature. It explains how the Gibbs free energy, first proposed by Josiah Willard Gibbs, fluctuates with temperature.
Gibb's and Helmholtz equation is given by,
\((\frac{\partial(\frac{G}{T}) }{\partial T} )}}\right)_{p}=-{\frac {H}{T^{2}}},}\)
where T is the absolute temperature, H is the enthalpy, and G is the Gibbs free energy of the system, all under constant pressure p. According to the equation, the change in the G/T ratio under constant pressure as a result of an infinitesimally small change in temperature is a factor H/T2.
There is insufficient information about this problem, however the problem may be like this.
As a result, the direction and spontaneity of chemical processes are predicted by the Gibbs and Helmholtz equations. As a result, the answer is the Gibbs and Helmholtz equations.
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How do you solve for ΜK?How do you solve for ΜK?
μ k = f k N = f k w cos 25 ° = f k m g cos 25 °. Substituting known values on the right-hand side of the equation, μ k = 45. 0 N ( 62 kg ) ( 9. 80 m/s 2 ) ( 0. 906 ) = 0. 82
the solution is μk = 0.82.
Given that:μk = f_k /N = f_k w cos25° = f_k m g cos25°
μk can be solved using the formula above;
Substituting known values on the right-hand side of the equation,
μk = 45.0 N (62 kg) (9.80 m/s²) (0.906)
μk = 0.82
Therefore, the solution is μk = 0.82.
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A 1210 kg car is driving NE
(at 45.0°) at 15.2 m/s when it is
struck by a moving 1540 kg car.
Afterward, they stick together and
move directly east (at 0°) at 23.3
m/s. What was the y-component
of the second car's initial velocity?
Answer:
To find the y-component of the second car's initial velocity, we can use the principle of conservation of momentum. This principle states that the total momentum of a system remains constant unless there is an external force acting on the system.
In this case, we can consider the two cars as a system, and we can use the principle of conservation of momentum to find the y-component of the second car's initial velocity.
We can write the equation for conservation of momentum as follows:
m1v1 + m2v2 = (m1+m2)*v
Where:
m1 is the mass of the first car (1210 kg)
v1 is the velocity of the first car (15.2 m/s, NE at 45.0°)
m2 is the mass of the second car (1540 kg)
v2 is the velocity of the second car (the unknown we are trying to find)
v is the velocity of the system after the collision (23.3 m/s, E at 0°)
We can use this equation to solve for the y-component of the second car's initial velocity (v2). First, we need to express the velocities in the x and y directions.
For the first car, we have:
v1x = v1 * cos(45°) = 15.2 m/s * cos(45°) = 10.6 m/s
v1y = v1 * sin(45°) = 15.2 m/s * sin(45°) = 10.6 m/s
For the second car, we have:
v2x = v2 * cos(0°) = v2 * 1 = 0 m/s
v2y = v2 * sin(0°) = v2 * 0 = 0 m/s
For the system after the collision, we have:
vx = v * cos(0°) = v * 1 = 23.3 m/s
vy = v * sin(0°) = v * 0 = 0 m/s
Now we can substitute these values into the equation for conservation of momentum and solve for v2y:
m1v1x + m2v2x = (m1+m2)vx
1210 kg * 10.6 m/s + 1540 kg * 0 m/s = (1210 kg + 1540 kg) * 23.3 m/s
12776.6 kgm/s + 0 kgm/s = 2750 kg * 23.3 m/s
12776.6 kgm/s = 2750 kg * 23.3 m/s
m1v1y + m2v2y = (m1+m2)vy
1210 kg * 10.6 m/s + 1540 kg * v2y = (1210 kg + 1540 kg) * 0 m/s
12776.6 kgm/s + 1540 kg * v2y = 0 kgm/s
12776.6 kgm/s = -1540 kg * v2y
v2y = -12776.6 kg*m/s / 1540 kg
v2y = -8.28 m/s
Therefore, the y-component of the second car's initial velocity is approximately -8.28 m/s.
Explanation:
Predict how your observations would change if you used a beaker with the same mass of lower temperature water.
The transfer of warmth (heat) from one item to another is known as heat conduction. Therefore, we can witness heat or thermal conduction when two things with differing temperatures come into touch.
Thus, The heat transfers from the hotter (the cup) to the colder (our hands) object when we contact the hot cup. When we added hot water to the cup that was at normal temperature, thermal conduction also took place.
The object's temperature is actually a measurement of how quickly its atoms are moving. The total energy produced by the atoms' vibrations is measured by the heat.
As a result, the atoms inside it begin to travel more quickly, which inevitably raises the likelihood that they will collide and conduction. It also relies on the density of the material we are working with how much they will clash.
Thus, The transfer of warmth (heat) from one item to another is known as heat conduction. Therefore, we can witness heat or thermal conduction when two things with differing temperatures come into touch.
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2. An object travels 150 m at a rate of 5 m/s. How long did it take?
Answer:
269 because 150 x/6 =5 kk
Answer:
it took 30 seconds:)
Explanation:
in order to find the time you must divide distance( 150 m) by speed (5 m/s) which equals 30 seconds.
A spring with a cart at its end vibrates at frequency 5.0Hz\;Hz .
A. Determine the period of vibration.
B. Determine the frequency if the cart's mass is doubled while the spring constant remains unchanged.
C. Determine the frequency if the spring constant doubles while the cart's mass remains the same.
A. The period of vibration is the time it takes for one complete oscillation to occur. It is the reciprocal of the frequency. The period of vibration can be calculated using the formula:
Period = 1/Frequency
Given that the frequency of vibration is 5.0Hz, the period of vibration is:
Period = 1/5.0 s
Period = 0.2 s
B. If the cart's mass is doubled while the spring constant remains unchanged, the frequency of vibration will not change. This is because frequency is dependent on the spring constant and the mass of the cart and not on the amplitude of the oscillation.
C. If the spring constant doubles while the cart's mass remains the same, the frequency of vibration will also double. This is because frequency is directly proportional to the square root of the spring constant. Therefore, doubling the spring constant would lead to an increase in the frequency of vibration by a factor of square root of 2.
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A car speedometer has a 3% uncertainty. What is the range of possible speeds (in km/h) when it reads 100 km/h
The range of possible speeds when a car speedometer reads 100 km/h with a 3% uncertainty is 97 km/h to 103 km/h.
When a car speedometer has a 3% uncertainty, it means that the displayed speed can deviate by 3% from the actual speed. In this case, if the speedometer reads 100 km/h, the actual speed could be either lower or higher. For calculating the range of possible speeds, need to find the 3% deviation from 100 km/h.
For determining the lower limit of the range, subtract 3% of 100 km/h from 100 km/h:
Lower limit = 100 km/h - (3/100) * 100 km/h = 100 km/h - 3 km/h = 97 km/h
For determining the upper limit of the range, add 3% of 100 km/h to 100 km/h:
Upper limit = 100 km/h + (3/100) * 100 km/h = 100 km/h + 3 km/h = 103 km/h
Therefore, the range of possible speeds when the speedometer reads 100 km/h with a 3% uncertainty is from 97 km/h to 103 km/h.
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The average distance between the Sun and the Earth's is
R = 1.5 * 108 km. Calculate the distance traveled and
the displacement of the planet after exactly:
-6 months
-1 year
The distance traveled by the Earth after 6 months or 1 year is equal to the circumference of its orbit (2πR), and the displacement is zero for both time periods. To calculate the distance traveled and the displacement of the Earth after a certain time period, we can use the formula:
Distance = Speed * Time In this case, the speed of the Earth's revolution around the Sun is constant, so we can use the average distance between the Sun and the Earth (R) as the value for speed. Distance traveled after 6 months: The time period is 6 months, which is equal to 0.5 years.
Distance = R * Time
Distance = (1.5 * 10^8 km) * (0.5 years)
Distance = 7.5 * 10^7 km Displacement after 6 months: Displacement refers to the change in position, so we need to consider the direction as well. After 6 months, the Earth would have completed half of its revolution around the Sun, so the displacement is zero. This is because the Earth ends up in the same position relative to the Sun after half a year. Distance traveled after 1 year:
The time period is 1 year.
Distance = R * Time
Distance = (1.5 * 10^8 km) * (1 year)
Distance = 1.5 * 10^8 km
Displacement after 1 year: Similar to the previous case, the Earth completes one full revolution around the Sun in one year, so the displacement is zero. The Earth returns to its initial position after a complete revolution. Therefore, the distance traveled by the Earth after 6 months or 1 year is equal to the circumference of its orbit (2πR), and the displacement is zero for both time periods.
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what is an asteroid called that is smaller than a couple meters wide?
Answer:
Meteoroids
Explanation:
Meteoroids are significantly smaller than asteroids, and range in size from small grains to one-meter-wide objects. Objects smaller than this are classified as micrometeoroids or space dust.
The term by which an asteroid called is smaller than a couple of meters wide is a meteorite.
What are meteorites?A meteorite is a small group of rocks and debris. They are made by the collection of dust and small pebbles. They are smaller than asteroids, and they are formed in outer space, and they fall on earth from outer space, and when they fall into the earth with that great speed, they attain heat.
Meteorites also consist of metals, like nickel, carbides, sulfides, etc. It has been said that in old times the meteorite that contain iron, fall into the earth and the iron from them melted into the core of the earth. They are of different shapes and sizes.
Thus, the term by which an asteroid called is smaller than a couple of meters wide is a meteorite.
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Write an algorithm that calculate the time a train need to arrive at a detination given peed and ditance
An algorithm that calculates the time a train needs to arrive at a destination given speed and distance \(Time=\frac{Distance}{Speed}\).
What is Speed?The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.
The maximum speed that can be maintained when a period grows closer to zero is the starting speed.
By dividing the object's distance traveled by the duration of the interval, the mean pace of the object for the given period is calculated. Speed and velocity are not always the same thing.
The algorithm to calculate the time required will be,
Let the distance covered by the train is D and the speed of the train be S.
Then, the time taken by the train will be,
T = D/S
Here, D is the distance and S is the speed.
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on this infinite grid of ideal one-ohm resistors, what's the equivalent resistance between the two marked nodes
Equivalent resistance (R) = [(4/pi) - (1/2)]
From the question, we have
Equivalent resistance = (2/pi)*[1 + (1/3) + (1/5) + (1/7) + ……….. + (1/(2m-1))]
where m = diagonal nodes
For the first diagonal node we have m = 1
R = [(4/pi) - (1/2)]
Equivalent resistance (R) = [(4/pi) - (1/2)]
Equivalent resistance:
If a single resistance can replace the combination of resistances in such a manner that the current in the circuit remains unchanged, then that single resistance is called the equivalent resistance. It is the total resistance that you compute when you've added up all of the resistances of the components in the circuit, following the conventional series and parallel addition principles. The equivalent resistance of a network is that single resistor that could replace the entire network in such a way that for a certain applied voltage V you get the same current I as you were getting for a network.
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