A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary on a surface with a coefficient of kinetic friction of 0.15 when hit, how far does it move after the bullet emerges?

Answer:

Thx for points merry Christmas answer 2

Explanation:

Answer:2

Explanation:

Explanation:

Mass of carte 1 is 110 kg and that of crate 2 is 230 kg

Force required to lift crates is equal to its crate i.e. W = mg

On Moon, a = 1.625 m/s²

Weight of crate 1, W = 110 kg × 1.625 m/s²  = 178.75 N

Weight of crate 2, W = 230 kg × 1.625 m/s²  = 373.75 N

On Earth, g = 9.8 m/s²

Weight of crate 1, W = 110 kg × 9.8 m/s²  = 1078 N

Weight of crate 2, W = 230 kg × 9.8 m/s²  = 2254 N

Hence, this is the required solution.

The forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.

Given the following data:

Scientific data:

Mathematically, the weight of an object is given by the formula;

\(Weight = mg\)

Where;

\(Weight \;A= 110 \times 1.6\)

Weight A = 176 Newton.

\(Weight \;B=230 \times 1.6\)

Weight B = 368 Newton.

\(Weight \;A= 110 \times 9.8\)

Weight A = 1,078 Newton.

\(Weight \;B=230 \times 9.8\)

Weight B = 2,254 Newton.

In conclusion, the forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.

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Answer:

meteor

Explanation:

A asteroid stays still and a meteor goes fast

Answer:

meteor

Explanation:

or some people call it a shooting star

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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\(\huge\color{pink}\boxed{\colorbox{black}{Answer ☘}}\)

12 mC

We are given that...

\(C_{1} = 4mF \\ V_{1} = 50v \\ C_{2} = 6mF \\ V_{2} = 30v \\ \\ we've \: to \: find \: the \: final \: charge \: on \: the \: 6mF \\capacitor \:- \\ \\ we \: know \: that ,\: \\ Q = CV \\ \\ using \: the \: formula \: \\ Q_{1} = 4 \times 50 = 200mC \\ Q_{2} = 6 \times 30 = 180mC \\ \\ total \: charge , \: Q_{1} - Q_{2} = 200 - 180 = 20mC \\ \\ let \: V \: be \: the \: final \: potential \: \\ 4V + 6V = 20mC\\ 10V = 20mC \\ V = \frac{20}{10} = 2V \\ final \: charge \: Q = CV = 6 \times 2 = 12mC\)

therefore,

hope helpful~

The height of the mansion that the assassin shot the target from is determined as 1,164.9 ft.

The time of motion of the bullet is calculated as follows;

-h = vsinθ(t)  - ¹/₂gt²

-6.1 = (vt) sin63  - ¹/₂(32)t²

-6.1 = 0.89vt - 16t² ---(1)

X = vcosθ t

294 = (vt)cos63

294 = 0.454vt

vt = 294/0.454

vt = 647.577 ---(2)

solve (1) and (2) together;

-6.1 = 0.89(647.577) - 16t²

16t² = 576.344 + 6.1

16t² =  582.44

t² = 582.44/16

t² = 36.4

t = √36.4

t = 6.03 s

v = 647.577/t

v = 647.577/6.03

v = 107.4 ft/s

h = vt + ¹/₂gt²

h = (107.4 x sin63 x 6.03) + ¹/₂(32)(6.03)²

h = 1,158.8 ft

H = 1,158.8 ft + 6.1 ft = 1,164.9 ft

Thus, the height of the mansion that the assassin shot the target from is determined as 1,164.9 ft.

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1.47  is the coefficient of static friction between a mass of 0.75kg and a horizontal surface

m=0.75 KG

g=9.8 M/S^2

N=5 N

F=µN

µ=F/N

µ=mg/N

µ=0.75×9.8÷5

µ=1.47

We are physically surrounded with friction. An object moving along a path is resisted by a force known as static friction. Lastly, use an easy example to comprehend it. Think about the activity we perform frequently called walking. We are constantly in contact with the floor while we work. Motion presses against the ground as we move it backward, and we then advance our feet.

One key concept to be aware of in order to minimize friction is the fact that it operates in the opposite direction from relative motion. This phenomena may be useful for reducing the speed of the action until it eventually comes to a stop.

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The electrostatic force of repulsion between the two charges is equal to 0.25 x 10¹¹ N.

The coulomb's law is used to find the force between two point charges. The force can be calculated using the formula -

F = 1/4πε₀ |Q₁||Q₂|/r²

Given is two charged objects separated by a distance of 0.6 m such that one object has a charge of -5 C and the other has a charge of +2C.

The electrostatic force of repulsion between the two charges is given by-

F = 1/4πε₀ |Q₁||Q₂|/r²

F = 9 x 10⁹ x (5 x 2)/(0.6)²

F = 90 x  10⁹/0.36

F = 9 x 10¹¹/36

F = 0.25 x 10¹¹ N

Therefore, the electrostatic force of repulsion between the two charges is equal to 0.25 x 10¹¹ N.

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C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

The answer is  energy 3 times as much. option A.

To calculate the amount of energy released when a 5 kg object is converted to pure energy, we can use Einstein's famous equation: E = mc². In this equation, E represents energy, m represents mass, and c represents the speed of light.

Given that the mass of the object is 5 kg, we can calculate the energy using the equation:

E = (5 kg) * (c²)

Now, to compare this energy with the amount of energy the Earth receives from the Sun every second, we need to determine the Earth's solar energy input.

The solar constant is the amount of solar radiation received per unit area at the Earth's distance from the Sun. Its average value is approximately 1361 Watts per square meter (W/m²). Multiplying this value by the surface area of the Earth (approximately 510 million square kilometers), we can estimate the total energy received by the Earth from the Sun every second.

Energy from the Sun = (1361 W/m²) * (510,000,000,000 m²)

To compare the energy released from converting a 5 kg object to energy with the energy received from the Sun, we divide the former by the latter:

Energy conversion / Energy from the Sun = [(5 kg) * (c²)] / [(1361 W/m²) * (510,000,000,000 m²)]

Simplifying the equation, we find:

Energy conversion / Energy from the Sun = (5 kg * c²) / (1361 W/m² * 510,000,000,000 m²)

The value of c² is approximately (3x10^8 m/s)² = 9x10^16 m²/s².

Plugging in the values, we get:

Energy conversion / Energy from the Sun = (5 kg * 9x10^16 m²/s²) / (1361 W/m² * 510,000,000,000 m²)

Simplifying further:

Energy conversion / Energy from the Sun ≈ 3.52

Therefore, the amount of energy released when a 5 kg object is converted to pure energy is approximately 3.52 times larger than the amount of energy the Earth receives from the Sun every second.

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The net force on the top block is 33.54 N.

Net force is the sum or resultant of two or more forces acting on a body.

Also, the net force is the force which is the sum of all the forces acting on an object simultaneously.

The sum of the upward forces is calculated as follows;

F(upward) = 50 N - 20 N = 30 N

The sum of the horizontal forces is calculated as follows;

F(horizontal) = 15 N

The net force or resultant force on the top block is calculated as follows;

F(net) = √Fy² + Fx²

where;

F(net) = √Fy² + Fx²

F(net) = √[(30)² + (15)²]

F(net) = 33.54 N

Thus, the net force or resultant force on the top block is determined as 33.54 N.

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The bus resultant displacement is approximately 4.14 km at an angle of 59.5 degrees north of east.

The first movement is 2 km due east, which means it has an x-component of 2 km and a y-component of 0 km.

The second movement is 5 km at 45 degrees north of east. This can be broken down into x and y components using trigonometry: x = 5 km * cos(45) = 3.54 km y = 5 km * sin(45) = 3.54 km

The third movement is 4 km at 30 degrees north of west. This can also be broken down into x and y components using trigonometry: x = -4 km * cos(30) = -3.46 km (negative because it’s towards the west) y = 4 km * sin(30) = 2 km

The fourth movement is 2 km due south, which means it has an x-component of 0 km and a y-component of -2 km.

Adding up all the x and y components, we get: x_total = 2 + 3.54 + (-3.46) + 0 = 2.08 km y_total = 0 + 3.54 + 2 + (-2) = 3.54 km

The magnitude of the resultant displacement can be calculated using the Pythagorean theorem: resultant_displacement = sqrt(x_total^2 + y_total^2) = sqrt(2.08^2 + 3.54^2) ≈ 4.14 km

The direction of the resultant displacement can be calculated using the arctan function: direction = arctan(y_total / x_total) ≈ 59.5 degrees north of east

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Given :

Pressure, P = 0.4 lb/in².

Depth, h = 42 in.

To Find :

The density of a liquid.

Solution :

Pressure at height h of a liquid of density \(\rho\) is given by :

\(P = \rho g h\)   ....1)

Here, g = 386.04 in/s²( acceleration due to gravity )

Putting all values in equation 1, we get :

\(P = \rho g h\\\\0.4 = \rho\times 386.04 \times 42\\\\\rho=\dfrac{0.4}{42\times 386.04}\ lb/in^3\\\\\rho=\dfrac{0.4}{42\times 386.04}\times 12^3\ lb/ft^3\\\\\rho=0.0426\ lb/ft^3\)

Hence, this is the required solution.

The liquid's surface tension in N/m is determined as 0.25 N/m.

Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.

Mathematically, the formula for surface tension of a liquid is given as;

γ = F/L

γ = F/2x

where;

From Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.

F = kx

where;

The final equation for the surface tension of the liquid film becomes;

γ = F/2x

γ = kx/2x

γ = k/2

γ = (0.5 N/m) / 2

γ = 0.25 N/m

Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.

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Answer:

in the Earths core

Explanation:

Answer:

Kinetic energy = 1500 J

Explanation:

The computation of the block's kinetic energy is shown below:

As we know that

Conservation of energy is

PE_i + KE_i = PE_f + KE_f

where,

Initial Potential energy = PE_i = m gh = 10kg× 10m/s^2 × 10m = 1000 J

Initial Kinetic energy = KE_i = (0.5) m V^2 = (0.5) (10 kg) (10 m/s)^2 = 500 J

Final potential energy = PE_f = mgh = 0      

As h = 0 which is at reference line

So

PE_i + KE_i = PE_f + KE_f

Now put these valeus to the above formulas

1000 J + 500 J = 0 + KE_f

After solving this

Kinetic energy = 1500 J

The block's kinetic energy is closest to 1500 Joules.

The energy is always conserved.

So that, the total kinetic energy will be sum of initial potential energy and kinetic energy during falling.

Given that, mass(m)=10kg, v=10m/s, h=10m,g=10m/s^2

              K.E=(1/2)mv^2 + mgh

              K.E=(1/2)*10*100 + (10*10*10)

              K.E=500 + 1000=1500Joule

The  block's kinetic energy is closest to 1500 Joules.

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Answer:

It something big enough for this

might be balance force, because the stacks of sticks remains stationary/ stable

definition of balance force = it is when resultant force acting on an obeject is zero and its said to be equilibrium. by newton's first law, the object remains stationary or continues moving at a constant velocity,

bye, hope u understand

The projectile's time of flight is approximately 6.6 seconds, which is closest to option B.

An object that is shot into the air and subsequently proceeds along a curved route while being pulled by gravity is said to be in projectile motion. There is no additional propulsion or lift involved. A ball that is tossed, a bullet that is shot from a pistol, or a rocket that is launched into space are examples of things in projectile motion.

We can use the kinematic equations of motion to calculate the projectile's time of flight. The initial velocity can first be divided into its horizontal and vertical components as follows:

\(Vx = V \times cos(\theta)\\= 65 m/s \times cos(30)\\= 56.18 m/s\\Vy = V \times sin(theta)\\= 65 m/s \times sin(30)\\= 32.5 m/s\\\)

where V is the magnitude of the initial velocity, and theta is the launch angle (30 degrees).

The horizontal velocity of the projectile remains constant throughout its flight, while the vertical velocity changes due to the effect of gravity. At the highest point of the trajectory, the vertical velocity becomes zero, and the time it takes to reach this point is equal to half of the time of flight.

The time it takes for the projectile to reach the highest point can be found using the following kinematic equation:

\(V_y = V_oy + a \times t\)

where Voy is the vertical component of the initial velocity (in this case, 32.5 m/s), a is the acceleration due to gravity (-9.81 m/s^2), and t is the time it takes to reach the highest point.

\(0 = 32.5 m/s + (-9.81 m/s^2) \times t\\t = 3.32 s\)

The total time of flight can be found by doubling the time it takes to reach the highest point:

time of flight = 2 × 3.32 s

                      = 6.64 s

Therefore, the projectile's time of flight is approximately 6.6 seconds, which is closest to option B.

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your answer would be C

by forcing air to move faster over the top of the wing thus creating higher pressure below the wing and lower pressure above the wing

hope this helped you- have a good day bro cya)

Answer:

What are igneous rocks?

Igneous rocks (from the Latin word for fire) form when hot, molten rock crystallizes and solidifies. The melt originates deep within the Earth near active plate boundaries or hot spots, then rises toward the surface. Igneous rocks are divided into two groups, intrusive or extrusive, depending upon where the molten rock solidifies

Answer:

Gravity

Explanation:

After 0.100 s, the cat would be 0.049 m below its initial position, with a velocity of 0.98 m/s. After 0.200 s, the cat would be 0.196 m below its initial position, with a velocity of 1.96 m/s. Finally, after 0.300 s, the cat would be  0.441 m below its initial position, with a velocity of approximately 2.94 m/s.

To calculate the position and velocity of the sleeping cat after certain time intervals, we need to make some assumptions and use basic principles of physics.

Assuming the cat falls vertically downward due to gravity and ignoring air resistance, we can apply kinematic equations to solve the problem.

(a) Position:

Using the equation for the position of an object in free fall, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is time, we can determine the position of the cat.

After 0.100 s: h = (1/2)(9.8 m/s^2)(0.100 s)^2 = 0.049 m (approximately)

After 0.200 s: h = (1/2)(9.8 m/s^2)(0.200 s)^2 = 0.196 m (approximately)

After 0.300 s: h = (1/2)(9.8 m/s^2)(0.300 s)^2 = 0.441 m (approximately)

(b) Velocity:

The velocity of the cat can be calculated using the equation v = gt, where v is the velocity and t is time.

After 0.100 s: v = (9.8 m/s^2)(0.100 s) = 0.98 m/s (approximately)

After 0.200 s: v = (9.8 m/s^2)(0.200 s) = 1.96 m/s (approximately)

After 0.300 s: v = (9.8 m/s^2)(0.300 s) = 2.94 m/s (approximately)

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An electron in a Hydrogen atom goes from the n=3 energy level to the n=1 energy level by emitting light. The energy of this light is (E)= 19.38×10⁻¹⁹ J.

Energy is a physical term. If a object is affected by some forces and move a distance that means object has some energy. It can be measured in Joule.

To calculate the energy we are using the formula,

E= hc/λ

To calculate the energy we have to calculate the wavelength= λ  first, we are using the formula,

1/λ=R[(1/n₁²)-(1/n₂²)]

Here we are given,

R= the Rydberg constant.=1.097×10⁷ /m

n₁= the final energy level.=1

n₂= the initial energy level.=3

we have to calculate the wavelength. = λ m

Now we put the values in above equation we get,

1/λ=R[(1/n₁²)-(1/n₂²)]

Or, 1/λ= 1.097×10⁷×[(1/1²)-(1/3²)]

Or,  1/λ= 1.097×10⁷×[(1/1)-(1/9)]

Or,  1/λ=0.975×10⁷ /m

Now we put the value in first equation, we get

E= hc/λ

Here we are given,

h=  the Planck's constant.= 6.626×10⁻³⁴ J.s

c= The speed of light.= 3×10⁸ m/s

we have to calculate the energy. = E J

Now we put the values in above equation,

E= hc/λ

Or, E= 6.626×10⁻³⁴×3×10⁸×0.975×10⁷

Or, E= 19.38×10⁻¹⁹ J

From the calculation we can say that, The energy of this light is (E)= 19.38×10⁻¹⁹ J.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

B. 10 cm

x^3 = 1 L

1 L = 1000 cm^3 (since 1 L = 1000 cm^3)

x^3 = 1000 cm^3

The  concentration of the solution will be 0.25M and the concentration of the  

sodium Hydroxide is 2.5 M .

A branch of chemistry deals with the application of  the laws of definite proportions and of the conservation of mass and energy to chemical activity. The quantitative relationship between constituent in a chemical substance.  

We have given here,

Moles of sodium chloride  =  0.25moles

Let us assume the the volume of  the solution is 1 L.

Molarity = 0.25/

Molarity will be 0.25 M

The mass of sodium Hydroxide is 20g and the molar mass is 40g ,

and the Volume will be 0.2L

Molarity = 20/ 40×0.2

Molarity = 2.5 mol / L

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Answer:

The frequency of light can be calculated using the formula:

`c = λv`

Where `c` is the speed of light in a vacuum, `λ` is the wavelength of light, and `v` is the frequency of light.

The speed of light in a vacuum is `3.00 × 10^8 m/s`.

To convert the wavelength from nanometers to meters, we need to divide by `1 × 10^9`.

Thus, the frequency of light with a wavelength of 655 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(655 × 10^-9 m)`

`v = 4.58 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`.

Similarly, the frequency of light with a wavelength of 515 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(515 × 10^-9 m)`

`v = 5.83 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz`.

Finally, the frequency of light with a wavelength of 475 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(475 × 10^-9 m)`

`v = 6.32 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.

So, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz` and the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

Kirchhoff's current law (KCL) can be written at each node using nodal analysis, and the voltages can be expressed in terms of the node voltages using Ohm's law.

The most chosen reference node in the nodal analysis is. a node that is connected to by the most elements. a node that has the greatest amount of voltage sources linked to it, or. a symmetry node.

An order template data node that references another data node is known as a reference node. The structure and data typing of the reference data node match those of the node it is referencing.

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