A toaster has a resistance of 30 ohms. It draws 2A of current from the outlet. What is the potential difference ?
A. 60v
B. 2v
C. 15v
D.30v

Answers

Answer 1

Answer:

60V

Explanation: . V = IR = 1

30*2=60


Related Questions

100gm o2 gas is pressurized to 20 degree Celsius. done Also, how much heat energy will be converted into mechanical energy?

Answers

The heat energy that will be converted into mechanical energy is 1.83 kJ.

Heat capacity of the O2 gas

The heat energy that will be converted into mechanical energy is calculated as follows;

Q = mcΔθ

where;

m is mass = 100 g = 0.1 kgΔθ is change in temperaturec is specific heat capacity

at 20 ⁰C = 293 K, C = 0.915 kJ/kg K

Q = (0.1 kg)(0.915)(20 )

Q = 1.83 kJ

Thus, the heat energy that will be converted into mechanical energy is 1.83 kJ.

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A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a scale. Write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the variables in the problem statement.

Answers

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by \(F_{net} = mg + \frac{2mgh}{r}\)

Given the following data:

Mass, m = 1.7 kg.Height, h = 14.2 meters.Radius, r = 6.2 meters.

To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:

The forces acting on the ball.

In this scenario, there are two (2) forces acting on the bowling ball and these include:

Centripetal forceGravitational force

Mathematically, centripetal force is given by this formula:

\(F_c = \frac{mv^2}{r}\)     .....equation 1.

Mathematically, gravitational force is given by this formula:

\(F_g= mg\)    ....equation 2.

Where:

m is the mass.g is the acceleration due to gravity.v is the velocity.

Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:

\(P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh\) .....equation 3.

Substituting eqn. 3 into eqn. 2, we have:

\(F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}\)

At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:

\(W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}\)

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The figure below shows a ball resting on a frictionless track at position A.

The ball has a mass of 20 kg and is released from position A, the acceleration due to gravity is 9.8 m/s. How much kinetic energy will the ball have at position B?

 The figure below shows a ball resting on a frictionless track at position A.The ball has a mass of 20

Answers

To find the kinetic energy at position B, we need to know the height or the velocity at position B. Without this information, we cannot calculate the exact value of the kinetic energy.

To determine the kinetic energy of the ball at position B, we need to consider the m conservation of Mechanical energy. Since the ball is released from position A, we can assume that there is no initial kinetic energy (velocity is zero), and the total mechanical energy at position A is equal to the potential energy.

The potential energy at position A can be calculated using the formula:

Potential energy at A = mass * gravitational acceleration * height

Potential energy at A = 20 kg * 9.8 m/s² * height

Now, at position B, all the potential energy is converted into kinetic energy. The kinetic energy at position B is given by the formula:

Kinetic energy at B = 1/2 * mass * velocity²

Since the ball is released from rest, the velocity at position B can be determined using the conservation of mechanical energy:

Potential energy at A = Kinetic energy at B

20 kg * 9.8 m/s² * height = 1/2 * 20 kg * velocity²

Simplifying the equation, we get:

9.8 m/s² * height = 1/2 * velocity²

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2. A student walks 3 blocks East, 2 blocks North, 1 block West, and then 2 blocks
South.
a) What is the total distance traveled?

Answers

Answer:

8 blocks.

Explanation:

Given that,

A student walks 3 blocks East, 2 blocks North, 1 block West, and then 2 blocks  South.

We need to find the total distance traveled by the student. The distance covered by an object is equal to the sum of the total path covered. So,

Distance = 3 blocks + 2 blocks + 1 block + 2 blocks

= 8 blocks

So, the distance traveled by the block is 8 blocks.

A typical elevator car with people has a mass of 1500.0 kg. Elevators are currently approaching speeds of 20.0 m/s - faster than the speed.

Required:
What is the upward force required if the elevator moves upward 200.0 meters before reaching 20.0 m/s?

Answers

Answer:

1500N

Explanation:

Force = mass * acceleration

Given

Mass = 1500kg

Get the acceleration using the equation of motion;

v² = u²+2aS

20² = 0+2s(200)

400 = 400a

a = 400/400

a = 1m/s²

Get the upward force required

F = 1500 * 1

F = 1500N

Hence the upward force required if the elevator moves upward 200.0 meters before reaching 20.0 m/s is 1500N

calculate the electric potential energy in a capacitor that stores 9.40 x 10 to the negative 10 C of charge at 50.0 V

Answers

The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

The electric potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.

In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.

To find the capacitance value, we can use the formula:

C = Q / V

where Q is the charge stored in the capacitor and V is the voltage across the capacitor.

Substituting the given values, we get:

C = 9.40 x 10^-10 / 50.0

= 1.88 x 10^-11 F

Now we can use the formula for electric potential energy to find the energy stored in the capacitor:

U = (1/2) * 1.88 x 10^-11 * (50.0)^2

= 4.70 x 10^-8 J

Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

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Forces at Time 1
Forces at Time 2
The arrows represent forces. Choose all that are correct when comparing the bicyclist at Time
1 and Time 2.

A. The bicyclist is moving faster at Time 2.
B. The bicyclist is moving faster at Time 1.
C. The bicyclist is applying more force on the pedals at Time 2.
D. The bicyclist is applying more force on the pedals at Time 1.

Forces at Time 1Forces at Time 2The arrows represent forces. Choose all that are correct when comparing

Answers

The bicyclist is applying more force on the pedals at Time 2. Option C

What is the image?

If we look at the image that have been shown, we can be able to see that the force that is acting have been shows by the arrows that have been used to label the movement of the cyclist in the image that is shown here.

We can see that the forward arrow at the time 2 is seen to be larger than the forward arrow that is shown for time 1. The implication of this is that the cyclist is cycling harder and applying more force at time 2 than at time 1.

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The boy biked 600 m at a speed of 10 m/s, how long did it take him to bike the total distance?

Answers

Answer:60 seconds

Explanation: Since we have the boy's initial location si (0m), final location sf (600m) and his velocity v, we can have our position equation like so:

sf = si + vt
600 = 0 + 10t

Solve for t by dividing 600 by 10 and your time t = 60s

WHAT IS THE MEAING OF- Grouping Data​

Answers

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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Conceptual Example 14 provides useful background for this problem. A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carousel itself (without riders) has a moment of inertia of 105 kg·m2. When one person is standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s. However, as this person moves inward to a point located 0.507 m from the center, the angular velocity increases to 0.795 rad/s. What is the person's mass?

Answers

For one person standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s, the person's mass  is mathematically given as

m = 24.2 kg

What is the person's mass?

Generally, the equation for the conservation  angular momentum  is mathematically given as

(I + m * r0^2) * w0 = (I + m * r^2) * w^2

Therefore

(105 + m * 1.78^2) * 0.517 = (105 + m * 0.524^2) * 0.841

m = 24.2 kg

In conclusion, the mass  

m = 24.2 kg

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Draw the most complicated circuit you can where the voltage drop across the battery is 6v and the current out of the battery is 5ma. You must use at least 6 resistors in a combination of series and parallel arrangements. The resistors must be of realistic value(no decimals). Give me the value of the individual resistors so that the total resistance is appropriate for the given current and voltage

Answers

The exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

To determine the values of the resistors, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

Given that the voltage drop across the battery is 6V and the current out of the battery is 5mA (0.005A), we can calculate the total resistance:

Total Resistance (R_total) = Voltage (V) / Current (I)

R_total = 6V / 0.005A

R_total = 1200 Ω

Now, let's assign values to the individual resistors to achieve this total resistance:

R1 = 220 Ω

R2 = 470 Ω

R3 = 330 Ω

R4 = 680 Ω

R5 = 820 Ω

R6 = 350 Ω

With these values, the total resistance of the circuit would be:

R_total = R1 + (R2 || R3) + (R4 || R5) + R6

R_total = 220 Ω + (470 Ω || 330 Ω) + (680 Ω || 820 Ω) + 350 Ω

R_total ≈ 220 Ω + 214.8 Ω + 351.5 Ω + 350 Ω

R_total ≈ 1136.3 Ω

The slight deviation from the exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

Therefore, Here's a circuit diagram with six resistors in a combination of series and parallel arrangements to achieve a total resistance appropriate for a 6V battery and 5mA current:

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Draw the most complicated circuit you can where the voltage drop across the battery is 6v and the current

How much of the light striking the gray rectangle is absorbed. Question #4. Pic is below

How much of the light striking the gray rectangle is absorbed. Question #4. Pic is below

Answers

We are asked to find out how much of the light striking the gray rectangle is absorbed?

As you can see, 35% of the light got reflected after striking the gray rectangle.

The remaining light is

100% - 35% = 65%

65% of the light went into the gray rectangle and only 15% transmitted through it.

The light absorbed is

65% - 15% = 50%

50% of the light striking the gray rectangle is absorbed.

Part G
List several examples of applied force, normal force, and friction?

Answers

Examples of following forces mentioned -

Normal  Force   :- Book kept on the table , Girl standing on floor, ...infact every object experience a normal force in the universe.Applied Force    :- this term literally means force responsible for the movements in the object or changes in the object , like throwing stones , playing ball , pushing an object , moving a pen from desk to chair..etc...Friction force     :-Force responsible for the resistance in the flow of system's work , For example air resistance a type of obstruction experienced in air when a Paper ball is thrown from terrace of a society , Viscosity of honey is also an example of liquid friction / viscous drag...Sometimes friction is useful for the stability of universe. But some times its necessary. It is due to this force we walk without collapsing into the core of earth as earth is a market of gravitational field. To substantiate the field effect , friction is necessary to necessitate  the life in planet. Rubbing of hands in winter season is also another example.

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If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin​

Answers

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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Which contact force always acts against the direction of movement?
A. spring

В.
friction
C.
impact
D. normal

Answers

Answer:

the answer to your question is b

The diagram below shows snapshots of an oscillator at different times. What is the period of the oscillation

The diagram below shows snapshots of an oscillator at different times. What is the period of the oscillation

Answers

The recurrent transition of something between two locations or states is referred to as oscillation.

Thus, A sine wave—a wave with everlasting motion like the side-to-side swing of a pendulum or the up-and-down action of a spring with a weight—is an example of an oscillation.

An oscillation is a periodic motion that repeats itself in a regular cycle. Around an equilibrium point or mean value, an oscillating movement takes place. Periodic motion is another name for it.

An oscillation is a continuous movement that occurs throughout time, whether it is going up and down or side to side.

Thus, The recurrent transition of something between two locations or states is referred to as oscillation.

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Which medium will cause the light to bend the least when moving from water?

a. Glycerin b. Quartz c. Ruby

d. Acrylic

Answers

Answer:

B

Explanation:

Monucles work in different shapes

Which of these quantities is constant in uniform circular motion?
A.speed
B.Velocity
C.acceleration
D.displacement

Answers

the answer is A, speed

what do magnetic field lines look like when two magnets attract?

Answers

Answer:

Explanation:

If 2 magnets are attracting, then the north pole of one magnet is facing the south pole of the other.  The magnetic field lines between the two magnets are connected and the direction of flow is north to south.

SI unit differ from one country to another . true or false​

Answers

Answer:

false ..........false

Answer:

FALSE                                            

Explanation:

3. A cylindrical steel drum is tipped over and rolled along the floor of a ware house. If the drum has radius of 0.40m and makes on complete turns in every 8.0 s, how long does it take to roll the drum 36m?​

Answers

It takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

What is circumference of a circle?

We can use the formula for the circumference of a circle:

Circumference = 2 * π * radius

Given:

Radius (r) = 0.40 m

Circumference (C) = 2 * π * 0.40 m

We must figure out how many full rotations the drum makes to go 36 meters in order to calculate how long it takes to roll the drum. Since we are aware of the circumference, we can determine the number of full turns as follows:

Number of turns = Distance / Circumference

Given:

Distance = 36 m

Number of turns = 36 m / (2 * π * 0.40 m)

Now that we know how many turns there are, we can calculate the time by multiplying that number by the length of a turn, which is given as 8.0 seconds:

Time = Number of turns * Time per turn

Time = (36 m / (2 * π * 0.40 m)) * 8.0 s

By substituting the values into the equation, we can calculate the time:

Time = (36 / (2 * 3.14159 * 0.40)) * 8.0 s

Time ≈ 9.05 s

So, it takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

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Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air?

Answers

Answer:

Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.

Water is to be heated from 10°C to 80°C as it flows through a 2-cm-internal-diameter, 13-m-long tube. The tube is equipped with an electric resistance heater, which provides uniform heating throughout the surface of the tube. The outer surface of the heater is well insulated, so that in steady operation all the heat generated in the heater is transferred to the water in the tube. If the system is to provide hot water at a rate of 5 L/min, determine the power rating of the resistance heater. Also, estimate the inner surface temperature of the pipe at the exit.

Answers

Answer:

- the power rating of the resistance heater is 24139.5 W

- the inner surface temperature of the pipe at the exit is 96.34°C

Explanation:

Given the data in the question;

Flow rate of water in the tube V" = 5L/min = 8.333 × 10⁻⁵ m³/s        

The water is to be heated from 10°C to 80°C;

so Average or mean temperature \(T_{avg\) will be;

\(T_{avg\) = (T₁ + T₂) / 2 = (10 + 80) / 2 = 90/2 = 45°C

Now, from the Table " Properties of Water " at average temperature;

at \(T_{avg\) = 45°C

density p = 990.1 kg/m³

specific heat \(C_p\) = 4180 J/kg-k

thermal conductivity k = 0.637 W/m-°C

Now, we determine the mass flow;

m" = pV"

we substitute

m" = 990.1 × 8.333 × 10⁻⁵

m" = 0.08250 kg/s

we know that the power rating of the resistance heater is equal to the heat transfer rate to the water;

Q' = m"\(C_p\)( T₂ - T₁ )

we substitute

Q' = (0.08250 × 4180 ) ( 80 - 10 )

Q' =  344.85 × 70

Q' = 24139.5 W

Hence, the power rating of the resistance heater is 24139.5 W

Next, we determine the average velocity of water in the tube;

\(V_{avg\) = V" / \(A_c\)

\(V_{avg\) = V" / ( \(\frac{1}{4}\)πD² )

given that;  flows through a 2-cm-internal-diameter; D = 0.02 m

we substitute

\(V_{avg\) = (8.333 × 10⁻⁵) / ( \(\frac{1}{4}\)π × (0.02)² )

\(V_{avg\) = (8.333 × 10⁻⁵) / ( 3.14159 × 10⁻⁴ )

\(V_{avg\) =  0.265 m/s

Also, from table " saturated water property table "

At 45°C

viscosity μ = 0.596 × 10⁻³ kg/m-s

Prandtl number Pr = 3.91

Now, we determine the kinematic viscosity

v = μ / p

we substitute

v = ( 0.596 × 10⁻³ ) / 990.1

v = 6.01959 × 10⁻⁷ m²/s

so, Reynolds number in the flow region will be;

Re = (\(V_{avg\) × D) / v

we substitute

Re = ( 0.265 × 0.02) / (6.01959 × 10⁻⁷)

Re = 8804.586

we can see that our Reynolds number (  8804.586 ) more than 2300 and less than 10,000.

Hydraulic and thermal entry length are equal in this flow region,

such that;

\(L_h\) = \(L_t\)

⇒ 10 × D = 10 × 0.02 = 0.2 m

we can see that the entry length ( 0.2 m ) is smaller than the given length ( 13 m ) in the question; the flow is a turbulent flow.

So we the Nuddelt number

Nu = \(0.023Re^{0.8} Pr^{0.4\)

Nu = 0.023 × \(8804.586^{0.8\) × \(3.91^{0.4\)

Nu = 56.8

Hence, the heat transfer coefficient h will be;

h = \(\frac{k}{D}\) × Nu

we substitute

h = \(\frac{0.637}{0.02}\) × 56.8

h = 31.85 × 56.8

h = 1809.1 W/m²-°C

Now, area of the heat transfer will be

A\(_s\) = πDL

we substitute

A\(_s\) = π × 0.02 × 13

A\(_s\) = 0.8168 m²

Finally we determine the inner temperature of the pipe at exit. using the relation;

Q' = hA\(_s\)( T₃ - T₂ )

we substitute

24139.5 = 1809.1 × 0.8168( T₃ - 10 )

24139.5 = 1477.67288( T₃ - 80 )

24139.5 = 1477.67288T₃ - 118213.8304

24139.5 + 118213.8304 = 1477.67288T₃

1477.67288T₃ = 142353.3304

T₃ = 142353.3304 / 1477.67288T

T₃ = 96.34°C

Therefore, the inner surface temperature of the pipe at the exit is 96.34°C

If the average hang time of a professional football kick is 4.4s, then determine the average maximum height.

Answers

The average highest height of a professional football kick is 189.728 m if the hang time is 4.4 seconds on average.

What is meant by hang time?

A person or an object's total duration in the air after leaving the ground is known as their "hang time." From the time anything leaves the ground until it returns, it is measured.

We know,

y= gt²

Here,

y = Average maximum height

g = acceleration due to gravity

t = Average hang time

Given,

Average hang time (t) = 4.4s

Acceleration due to gravity (g) = 9.8 m/s² (assuming)

Inserting these values in the given equation,

y = gt²

  = 9.8×4.4×4.4

  = 189.728 m.

Hence, the average maximum height of the football is 189.728 m.

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Select the answer that helps conserve the most energy.
O walking to school
O driving a car to school
Otaking the bus to school​

Answers

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school​ both take up energy, unlike walking to school.

unless ur talking about energy, counting energy you produce and use to complete things, then it would be the 3rd one, taking the bus to school.

A car from the beginning was traveling at 27.8m/s when he stepped on the brakes and stopped. According to the DMV, this would leave a skid mark of 60m. What is his acceleration?

Answers

Answer:

-6.44 m/s²

Explanation:

Given:

Δx = 60 m

v₀ = 27.8 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (27.8 m/s)² + 2a (60 m)

a = -6.44 m/s²

A solid wooden door, 90 cm wide by 2.0 m tall, has a mass of 35 kg. It is open and at rest. A small 500-g ball is thrown perpendicular to the door with a speed of 20 m/s and hits the door 60 cm from the hinged side, causing it to begin turning. The ball rebounds along the same line with a speed of 16.0 m/s relative to the ground.

Required:
How much energy is lost during this collision?

a. 15J
b. 16J
c. 13J
d. 4.8J
e. 30J

Answers

Answer:

the kinetic energy lost in the collison is a) 30 J

Explanation:

given data

mass of door m1 = 35 kg

width a = 90 cm = 0.9 m

the mass of ball  m2 = 500 g = 0.5 kg

initial speed of ball  u = 20 m/s

final speed of ball  v = 16 m/s

r = 60 cm = 0.6 m

soluion

we will consider here final angular speed of the door = w

so now we use conservation of angular momentum  that is

Li = Lf    ........................1

that is express as

m2 × u × r = I × w + m2 × v × r

put here value and we get  

0.5 × 20 × 0.6 = \((m1 \times \frac{a^2}{12})\) × w + 0.5 × 16 × 0.6

solve it we get

w = 0.508 rad/s

so that here

the kinetic energy lost in the collison,

KE = KE initial - KE final     ..................2

put here value

KE = 0.5 × m2 × u² - (0.5 × I × w² + 0.5 × m2 × v²)

KE = 0.5 × (0.5 × 20² - (35 × 0.9² ÷ 12) × 0.508² - 0.5 × 16²) J

KE = 30 J

the kinetic energy lost in the collison is a) 30 J

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Jupiter is approximately 5 times farther away from the Sun than Earth is. If you were on Jupiter and you looked back at the Sun, how would its brightness compare to its brightness on Earth? (show your work and your calculation).

Answers

Answer:

10 times less bright

Explanation:

If Earth is 5 times farthest from the sun and Jupiter is 5 times farther than Earth then 5+5 is 10 therefor the sun is not as bright leading to 10 times less brightness.

What does a producer need to make its own food

Answers

Answer:

A producer needs the sun to make its own food, because producers use photosynthesis. In photosynthesis you use the sun to turn the air people breathe out and water into glucose and oxygen.

Explanation:

Hope this helps ^-^

Two beads, one blue and one green, are threaded on a wire, which is bent in the shape shown in the figure. The blue bead, with mass 0.445 kg, starts at A with zero initial velocity. At B, the blue bead undergoes an elastic collision with an initially stationary 0.610 kg green bead. To what height (in m) does the green bead rise along the wire? Note that
h = 1.50 m,
and neglect friction.

Answers

The 1.50–m initial height of the green bead, of mass 0.445–kg and the elastic collision with the blue bead of mass 0.610–kg, gives the height to which the green bead rises as approximately 1.07 meters

What is an elastic collision?

An elastic collision in a system is one in which, there is no net loss in the kinetic energy of the system.

During a perfectly elastic collision, we have:

Momentum coming into the collision = Momentum output of the collision

m₁·v₁ + m₂·v₂= m₁·v₁ₓ + m₂·v₂ₓ

The kinetic energy input, 0.5·m·v² = The kinetic energy output

0.5·m₁·v₁² + 0.5·m₂·v₂² = 0.5·m₁·v₁ₓ² + 0.5·m₂·v₂ₓ²

Where:

Subscript x represent the velocity after the collision.

From the principle of the conservation of energy, we have:

Potential energy, P.E. of the blue bead at A = The kinetic energy, K.E. at B

The potential energy gained by blue bead at A = m·g·h

Which gives: P.E. = 0.445 × 9.81 × 1.50 = 6.548175

K.E. = 0.5×0.445 × v₁² = 6.548175

v₁² = 6.548175 ÷ (0.5×0.445) = 29.43

v₁ = √(29.43) ≈ 5.425

Which gives: 0.445×5.425 + 0.610×0 = 0.445×v₁ₓ + 0.610·v₂ₓ

2.414125 = 0.445×v₁ₓ + 0.610·v₂ₓ...(1)

0.5·m₁·v₁² + 0.5·m₂·v₂² = 0.5·m₁·v₁ₓ² + 0.5·m₂·v₂ₓ²

0.5·m₁·v₁² = 6.548175

0.5·m₂·v₂² =  0.5·m₂ × 0 = 0

0.5·m₁·v₁² + 0.5·m₂·v₂² = 0.5·m₁·v₁ₓ² + 0.5·m₂·v₂ₓ²

6.548175 + 0 = 0.5 × 0.445 × v₁ₓ + 0.5 × 0.610 × v₂ₓ² = 0.2225·v₁ₓ² + 0.305·v₂ₓ²

6.548175 = 0.2225·v₁ₓ² + 0.305·v₂ₓ²...(2)

From equation (1), we have: 2.414125 - 0.610·v₂ₓ = 0.445×v₁ₓ

\(v_{1x} = \dfrac{2.414125 - 0.610 \cdot v_{2x}}{0.445}\)

Plugging in the value of v₁ₓ into equation (2) and simplifying with a graphing calculator gives:

488603753600·v₂ₓ² -2236114761440·v₂ₓ + 93968247=0

Which gives; v₂ₓ ≈ 4·576

The initial kinetic energy of the green bead is therefore found as follows; K.E. ≈ 0.5 × 0.610 × 4.576² = 6.38663168

P.E. = m·g·h = K.E.

\(\therefore P.E. = \dfrac{K.E.}{m \times g}\)

\(Height \ reached, h \approx \dfrac{6.38663168}{0.610 \times 9.81} \approx 1.07\)

The height to which the green bead rises is approximately 1.07 meters

Learn more about the principle of conservation of energy here:

https://brainly.com/question/15606227

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