A _ system is one in which one subsystem provides services to another subsystem.

Answer:

Gamma rays

Explanation:

Gamma rays have the highest frequency in the electro magnetic spectrum

Answer:

Five examples of locomotor movements are:

Hopping

Galloping

Walking

Running

Skipping

Explanation:

I hope it helps ❤❤

This following was true between both the two sites when there is a one volt potential difference.

How will you define charge?

The physical characteristic of matter who causes it to feel a force when exposed to an electromagnetic field is called electric charge. The two types of electric charges that protons and electrons most frequently carry are positive and negative charges. Charge movement is what produces energy.

Charged, also known as electric full control, electrical charge, as electrostatic charge and denoted by the symbol q, is a property of a unit of matter that indicates how many more or fewer electron than protons it contains.

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The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.

Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:

Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:

Solving for T2, we get:

Thus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

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Acceleration is the rate of change of velocity. Usually, acceleration means the speed is transforming, but not always. When an object moves in a circular path at a steady speed, it is still accelerating, because the focus of its velocity is changing.

a = 4,552 m / s²,   b)  a = 2,588 m / s²

Newton's second law is

F = ma

a = F / m

in this case the force remains constant

indicate us

* for a mass m₁

a₁ = F/m₁

a₁ = 12, m/ s²

* for a mass m₂

a₂= 3.3 m / s²

acceleration  m = m₂-m₁

substitute

\($\begin{aligned}&a=\frac{F}{m_{2}-m_{1}} \\&1 / a=\frac{m_{2}}{F}-\frac{m_{1}}{F}\end{aligned}$\)

let's calculate

1/a=1/3.3 - 1/12  = 0.21969

 a = 4,552 m / s²

a= 4,552m/s²

Speed ​​estimates the rate of movement of an object, that is, the distance traveled per unit of time. Acceleration calculates the rate of change of velocity, that is, the change in velocity between two different moments

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Answer:

salt

Explanation:

salt is a component for many acid base reactions

The kinetic energy of an object with mass 5kg and a constant velocity of 15m/s is 562.5J.

Kinetic energy is the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.

The kinetic energy of an object can be calculated using the following formula:

K.E = ½ mv²

Kinetic energy = ½ × 5 × 15²

Kinetic energy = 562.5J

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Answer:

is there more?

Explanation:

1.) The potential energy of an object can be calculated using the equation: PE = mgh

Where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

So, the potential energy of a 60 kg ball falling from a height of 20 m would be:

PE = 60 kg * 10 m/s² * 20 m = 12000 J (joules)

2.) The average power can be calculated using the equation: P = W / t

Where W is the work done and t is the time taken.

In this case, the work done can be calculated as W = mgh, where m is the mass of the girl (30 N), g is the acceleration due to gravity (10 m/s²), and h is the height of the stairs (5 m).

So, W = 30 N * 10 m/s² * 5 m = 1500 J

And the average power can be calculated as:

P = 1500 J / 6 s = 250 W (watts)

Answer:

Answer is in attached photo.

Explanation:

The solution is in the attached photo, do take note to solve these questions, multiple formulas are needed:

Q1) Potential Energy = Mass x Gravitational Accceleration x Height

= m x g x h (SI Unit: J)

Q2) Work Done = Force x Distance

= F x d (SI Unit: J)

Average Power = \(\frac{Total \ Work \ Done}{Total \ Time}\) (SI Unit: W)

Answer:

Resistance of the light bulb = 1.33 ohm (Approx.)

Explanation:

Given:

Current in electric bulb = 2 Amp

Voltage in battery = 1.5 Volt

Find:

Resistance of the light bulb

Computation:

Resistance = Voltage / Current

Resistance of the light bulb = Voltage in battery / Current in electric bulb

Resistance of the light bulb = 2 / 1.5

Resistance of the light bulb = 1.33 ohm (Approx.)

Answer:

A burning candle emits radiation in the form of heat and light. The Sun emits radiation in the form of light, heat, and particles. Uranium-238 decaying into Thorium-234 emits radiation in the form ofalpha particles.

Answer:

the sun

Explanation:

the sun emits radiation

Answer:  45 A

Explanation:

Primary only protection 3-phase

I =  3 phase kVA / ( 1.723 * V)

I = 30000 / ( 1.732 * 480 ) = 36.085 A

Table 450.3(B)

Currents of 9A or more column

primary only protection  = 125%

Max OCPD pri = 125% of I = 1.25 * 36.085 = 45.11 A

 Table 450.3(B) Note 1   does not apply, use next smaller Table 240.6(A)

Next smaller = 45 A

The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.

The exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.

The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.

Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.

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Answer:

D

Explanation:

Force (N) = mass (kg) × acceleration (m/s²) is the famous F=ma

Force = 25 * 4 in this case

Force = 100 N

Answer:

22.15 N/m

Explanation:

As we know potential energy = m*g*h

Potential energy of spring = (1/2)kx^2

m*g*h = (1/2)kx^2

Substituting the given values, we get -  

(400)*(9.8)*(10) = (0.5)*(k)*(2.0^2)

k = 39200/2.645

k = 19600 N/m

For safety reasons, this spring constant is increased by 13 % So the new spring constant is  

 k = 19600 * 1.13 = 22148 N/m = 22.15 N/m

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

The final velocity of a truck is 74.0 ft/s, if it accelerates at a range of 3.00 ft/\(s^2\) from an initial velocity of 5.00 ft/s, then it will take the truck 23.67 seconds to attain its final velocity of 74.0 ft/s.

v = u + at

Here, v =the final velocity, u =the initial velocity, a =the acceleration, and t =the time taken.

Substituting the given values, one can get,

74.0 ft/s = 5.00 ft/s + 3.00 ft/\(s^2\) × t

Solving for t, one gets,

t = (74.0 ft/s - 5.00 ft/s) / (3.00 ft/\(s^2\)) = 23.67 s (that is  23.67 seconds is needed to attain final velocity of 74.0 ft/s)

Hence, a truck needs 23.67 seconds time to attain its final velocity of 74.0 ft/s and this is the final velocity.

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Some object remains hot for a long period of time because they have low thermal conductivity and some object remain hot for a short period of time because they have high thermal conductivity.

Thermal conductivity is a property of a substance to allow heat to flow through it easily.

Thermal conductivity is a measure of how well a substance will conduct heat or not.

Objects that have high thermal conductivity gain heat easily and also lose heat easily. Hence, they get hot quickly and also get cold quickly.

Objects that have low thermal conductivity gain heat slowly and also lose heat slowly. Hence, they get hot slowly and also get cold slowly.

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Answer:

200 meters per second

Explanation:

wave speed = wavelength x frequency

2 meters x 100 hertz = 200 meters per second

Given :

Answer:

↪ v = u + gt

↪ v = 35 - 10 × 5

↪ v = 35 - 50

↪ v = -15 m/s

Therefore,the Velocity of the object 5 seconds later is -15 m/s.

Answer:

1.74 x 10^6

Explanation:

Brainliest :)

The approximate radius of the Moon is \(1.736 * 10^7\) meters, or 17,360 kilometers.

To find the radius of the Moon, we can use Newton's law of universal gravitation, which relates the acceleration due to gravity (g) to the mass of the celestial body (M) and the distance (radius, r) between the center of the body and the object experiencing the gravitational force.

The formula for the acceleration due to gravity on the surface of a celestial body is:

\(g = G * (M / r^2),\)

where:

g = acceleration due to gravity on the Moon's surface (\(1.62 m/s^2\)),

G = universal gravitational constant (approximately\(6.67430 * 10^{-11\) m^3/kg/s^2),

M = mass of the Moon (\(7.35 * 10^{22\) kg), and

r = radius of the Moon (what we want to find).

Let's rearrange the formula to solve for the radius (r):

\(r^2\) = G * (M / g).

Now, we can plug in the known values:

\(r^2 = (6.67430 * 10^{-11} m^3/kg/s^2) * (7.35 * 10^{22} kg / 1.62 m/s^2)\).

Calculate the value of \(r^2\):

\(r^2\) ≈ \(3.018 * 10^{14} m^2.\)

Finally, take the square root of both sides to find the radius (r):

r ≈ \(\sqrt{(3.018 * 10^{14} m^2)\)≈ \(1.736 * 10^7\) meters.

So, the approximate radius of the Moon is\(1.736 * 10^7\) meters, or 17,360 kilometers.

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The compressive stress in the steel column is found to be approximately 397.6 MPa.

The formula for calculating the area of a circle can be used to determine the steel column's cross-sectional area (A),

A = π*(d/2)², diameter of the column is d,

A = π*(0.4/2)²

A = 0.1257m²

The compressive stress (σ) in the column can be calculated using the formula, σ = F/A, F is the load carried by the column is F.

σ = 50 MN/0.1257m²

σ = 397.6 MPa

Therefore, the compressive stress in the steel column is approximately 397.6 MPa.

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The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path

From the formula in the question;

B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.

The accelerating voltage used to move the ions is called Vaccelm.

The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.

The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.

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Our muscles need more oxygen to make energy (in the form of ATP) while we workout.

When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.

Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.

The respiratory system is the organ system engaged in this process.

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# complete question:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Student 1: Wow! I am so hot and sweaty! I need some water to cool down.

Student 2: My cheeks are really red.

Student 3: I am breathing so hard, I can barely catch my breath!

Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.

The disk is equivalent to a solid cylinder 0.700 cm high and 3.80 cm in diameter. The shear deformation is .∆x=3.34×10⁻⁶ m.

Deformation refers to the change in size or shape of and object whereas displacements are the absolute change in to the  position of a point on the  the object. Deflections is the relative changes in external displacements in an object.

The shear deformation is .

Given that,

Shearing force F = 600 nm

Shear modulus S=1×10⁹ n/m²

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

S=Flo/A ∆x

∆x=Flo/(rd²/4)S

∆x=4Flo/(rd²/)S

Put the value into the formula

∆x=4×600×0.700×10²/3.14×1×10⁹×(4.00×10²)

∆x=3.34×10⁻⁶ m

Hence, The shear deformation is .∆x=3.34×10⁻⁶m

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