a student stands several meters in front of a smooth reflecting wall, holding a board on which a wire is fixed at each end. the wire, vibrating in its third harmonic, is 75.0cm long, has a mass of 2.25g, and is under a tension of 400 N. a second student, moving towards the wall, hears 8.30 beats per second. what is the speed of the student approaching the wall? (solve without calculus)

The factor that leads to loess deposit is when the wind carries fine sediment. That is option C.

The loess deposits are those deposits that are usually found at the edge of deserts.

The major factor that causes the formation of loess is the wind because they are entrained, transported, and deposited by the wind.

The fine particles carried by wind contains find grained sediments, organic particles that are capable of forming loess.

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1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.

2. The bright part of the moon appears bright due to the reflection of sunlight.

Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.

Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.

Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.

Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

(Total initial linear momentum = total final linear momentum.)

Momentum = mass × velocity

180×4 + 120×0 = 180×0 + 120×V

(180 ×4)/120 = V

The difference between these wavelengths is 15.85 nm.

What is wavelengths?

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.

The number of lines on the grating N= 900 cm

Distance between screen grating L= 2.24 m

Order number = 1

Distance y = 3.20 mm

We need to calculate the width of the slit

Using formula of width

\(d=\frac{1}{N}$$\)

Put the value into the formula

\($$\begin{aligned}d & =\frac{1}{900} \\d & =0.00111=1.11 \times 10^{-5} \mathrm{~m}\end{aligned}$$\)

We need to calculate the angular distance

\($$\theta=\frac{\lambda}{d}$$\)

The angular separation for different wavelength is

\($$\Delta \theta=\frac{\lambda_1-\lambda_2}{d}$$\)

We know that,

Linear separation is

\($$\Delta y=\Delta \theta L$$\)

We nee to calculate the difference between these wavelengths Put the value into the formula of angular separation

\(\begin{aligned}& \Delta y=L\left(\frac{\lambda_1-\lambda_2}{d}\right) \\& \lambda_1-\lambda_2=\frac{\Delta y \times d}{L} \\& \lambda_1-\lambda_2=\frac{3.20 \times 10^{-3} \times 1.11 \times 10^{-5}}{2.24} \\& \lambda_1-\lambda_2=1.585 \times 10^{-8} \\& \lambda_1-\lambda_2=15.85 \mathrm{~nm}\end{aligned}\)

Hence, The difference between these wavelengths is 15.85 nm.

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If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Taking into account the definition of enthalpy of vaporization, the heat needed to boil 5.0 kg of water at its boiling point is 11300 kJ.

The enthalpy of vaporization is the amount of energy required to change a unit of mass (for example, moles or kg) of a substance from phase liquid to phase gas at constant temperature and pressure.

In case of phase change from liquid to gas, this amount of energy is known as enthalpy of vaporization (symbolized as ∆H vap), also known as (latent) heat of vaporization or heat of evaporation.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

Replacing in the definition of latent heat:

Q = 5 kg× 2260 kJ/kg

Solving:

Q= 11300 kJ

Finally, the heat needed is 11300 kJ.

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Answer:

0.0816 kgm/s

Explanation:

From the question,

Momentum of the pellet just before it hits the modelling clay is = (mass of the pellet+ mass of the truck clay)×initial velocity of pellet.

P =(M+m)u...................... Equation 1

Where P =  initial momentum of the pellet, m = mass of the pellet, u = initial speed of the pillet, M = mass of the truck

Given: m = 2 g = 2/1000 kg = 0.002 kg, u = 0.8 m/s, M = 0.1 kg

Substitute these values into equation 1

P = (0.002+0.1)0.8

P = (0.102)0.8

P = 0.0816 kgm/s

The energy of the skater at each position is:

At position A, the skater is at the lowest point, so the PE is zero. The KE can be calculated using the formula KE = (1/2)mv², where m is the mass of the skater and v is the velocity:

KE = (1/2)(60 kg)(8 m/s)²

KE = 1920 J

Therefore, at position A, the skater has 1920 J of kinetic energy and 0 J of potential energy.

At position B, the skater has gained some height, so there is some potential energy. The KE can be calculated as before, and the PE can be calculated using the formula PE = mgh, where m is the mass of the skater, g is the acceleration due to gravity (9.81 m/s²), and h is the height:

KE = (1/2)(60 kg)(8 m/s)²

KE = 1920 J

PE = (60 kg)(9.81 m/s²)(3 m)

PE = 1764 J

Therefore, at position B, the skater has 1920 J of kinetic energy and 1764 J of potential energy.

At position C, the skater has reached the highest point, so the KE is zero. The PE can be calculated as before:

PE = (60 kg)(9.81 m/s²)(6 m)

PE = 3528 J

Therefore, at position C, the skater has 0 J of kinetic energy and 3528 J of potential energy.

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The weight of the plane is 3453.12 Newtons and the horizontal acceleration will be 20.206 m/s².

The weight of an object is the force which is acting on the object due to the gravity. Along the vertical direction, the plane is moving at a constant velocity, meaning that the net vertical acceleration is zero, so the vertical component of the 7920 N upward force is balanced by the weight of the object (pointing downward).

a. The vertical component of the upward force is given by:

Fy =Fsinθ

where,

F = 7920 N is the magnitude of the force

θ = 57.0° is the angle above the horizontal

Fy = 7920(sin57.0°)

Fy = 7920 × 0.436

Fy = 3453.12 N

The weight of the plane will be 3453.12 Newtons.

b. From the weight of the plane, we can calculate its mass:

m = W/ g

where, g = 9.8 m/s² is the acceleration due to gravity.

Along the horizontal direction, the 7920 N is not balanced by any other backward force: so, there is a net acceleration along this direction.

m = 3453.12/ 9.8

m = 352.36 kg

The horizontal component of the force is given by:

Fx = Fcosθ

Fx = 7920(cos57°)

Fx = 7920 × 0.899

Fx = 7120.08 N

According to Newton's second law, the net force along the horizontal direction is equal to the product between the plane's mass and the horizontal acceleration:

Fx = maₓ

So, if we solve for aₓ, we find:

aₓ = Fₓ/ m

aₓ = 7120.08/ 352.36

aₓ = 20.206 m/s²

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Answer:

D gravity

Explanation:

please mark me brainliest

Answer:

D. The force that the branch applies to the kitten

Explanation:

I just took the quiz and got it correct!

Explanation:

Without changing the constant speed, your friend can empty the contents of the wagon, or decrease the overall rate, or the terrain the wagon is traveling on, all of these would increase the wagon's speed. Also, you could try applying a heavier pulling force, like using a horse instead of yourself, or you and a horse to get going faster.

Hope this helps!

Answer:

it is double the temperature change of iron

The shape of a line graph displaying temperature change over time before boiling is typically linear and increasing.

In a line graph showing the temperature change over time of a liquid before it starts to boil, the shape is generally linear and increasing.

This is because as heat is applied to the liquid, its temperature increases at a consistent rate.

During this phase, the heat energy is used to increase the kinetic energy of the molecules in the liquid, causing a rise in temperature.

Once the boiling point is reached, the graph may show a plateau, as the energy is then used to change the liquid's state rather than further increase the temperature.

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Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.

Complete question is;

A long, circular aluminum rod is attached at one end to a heated wall and transfers heat by convection to a cold fluid. If the diameter of the rod is doubled, by how much would the rate of heat removal change?

Answer:

182.84 %

Explanation:

Formula for rate of heat transfer of an infinite log fin is given as;

q_f1 = (π/2) × (hk)^(½)) × D^(3/2)) × (T_b - T_∞)

Where D is diameter.

Now, if the diameter of the rod is doubled, it means Diameter is now 2D.

Thus;

q_f2 = (π/2) × (hk)^(½)) × (2D^(3/2)) × (T_b - T_∞)

To find how much the rate of heat removal will change, we will calculate as follows;

((q_f2/q_f1) - 1) × 100

Plugging in the relevant expressions, we have;

([[(π/2) × (hk)^(½)) × ((2D)^(3/2)) × (T_b - T_∞)]/[(π/2) × (hk)^(½)) × (D^(3/2)) × (T_b - T_∞)]] - 1) × 100

Upon simplifying, we have;

(((2D)^(3/2))/(D^(3/2)) - 1) × 100

((2^(3/2)) - 1) × 100

This gives;

182.84 %

Answer:

a) 12 ohm

that's what I kno

Answer:

lets go brandon!

Explanation:

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

Answer: Procrastination, Defiance, Laziness

Explanation:

Answer: impulsiveness

Explanation:

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.

The formula for net torque acting on an object is given as;

T(net) = Ia

where;

The  moment of inertia of an object is given as;

I ∝ MR²

where;

So mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.

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A mass on a string of unknown length oscillates as a pendulum with a time period of 4.00 s. If the mass is doubled, the time period will not change as time period is independent of the mass.

When the length of the string is doubled, the period is 5.656s.

The relationship between the period and the length of the pendulum is given as,

\(T = 2\pi \sqrt{l/g}\)

or, \(\frac{T1}{\sqrt{l1} } = \frac{T2}{\sqrt{l2} }\)

or, T2 = 5.656 s.

When the string length is halved, the time period is 2.83 s. It is calculated using the same equation given above.

The time period of oscillation of pendulum is independent of the amplitude. Hence, there won't be any changes if amplitude is halved.

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If a particle's velocity is nonzero, then its acceleration can be zero, because acceleration is the rate of change of velocity. If the velocity is constant and does not change, the acceleration is zero.

The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.

Because velocity is both a speed and a direction, there are only two ways to accelerate: modify your speed or your direction—or both.

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Answer:

wavelength

Explanation:

The displacement wave graphs show the wave at a given time, so we can identify the distance that exists from crest to crest. This distance is the wavelength of the wave. Therefore,

Displacement-distance wave graphs can be used to determine the wavelength of a wave

Answer:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object

Explanation:

it's newton's second law

Answer:

T = 99.51 hour

Explanation:

Mass of Uranus, \(M=8.68\times 10^{25}\ kg\)

The moon Umbriel orbits Uranus at a distance of \(2.66\times 10^8\ m\)

We need to find Umbriel's orbital period. Let it is T. Using Kepler's third law of motion to find it.

\(T^2\propto r^3\\\\T^2=\dfrac{4\pi^2r^3}{GM}\\\\T^2=\dfrac{4\pi^2\times (2.66\times 10^8)^3}{6.67\times 10^{-11}\times 8.68\times 10^{25}}\\\\T=358244.51\ s\)

As 1 hour = 3600 s

358244.51 s = 99.51 hour

Hence, Umbriel's orbital period is 99.51 hour.

Answer:

Explanation:

its 99.51 im not just saying that because of the person on top of me but i have all my notes from physics and from chemistry and from biology from when i was on acellus! but the top of me is right :)

Answer:

F₁ = 4 F₀

Explanation:

The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:

F₀ = mv₀²/r   --------------- equation (1)

where,

F₀ = Force on string at t₀

m = mass of ball

v₀ = speed of ball at t₀

r = radius of circular path

Now, at time t₁:

v₁ = 2v₀

F₁ = mv₁²/r

F₁ = m(2v₀)²/r

F₁ = 4 mv₀²/r

using equation (1):

F₁ = 4 F₀