When it comes to money, you are either_____
or a_______

The 90% confidence interval is: (2.51, 3.22)

It is a boundary of values which is eventually to comprise a population value with a certain degree of confidence. It is usually shown as a percentage whereby a population means lies within the upper and lower limit of the provided confidence interval.

We have the following information :

The level of significance is calculated as:

\(\alpha =1-c\\\\\alpha =1-0.90\\\\\alpha =0.10\)

The degrees of freedom for the case is:

df = n - 1

df = 15 - 1

df = 14

The 90% confidence interval is calculated as:

=x(bar) ±\(t_\frac{\alpha }{2}\), df \(\frac{s}{\sqrt{n} }\)

= 2.86 ±\(t_\frac{0.10 }{2}\), 14 \(\frac{0.78}{\sqrt{15} }\)

= 2.86 ± 1.761 × \(\frac{0.78}{\sqrt{15} }\)

= 2.86 ± 0.3547

= (2.51, 3.22)

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Answer:

\(k=\frac{3}{10}\) or \(0.3\)

Step-by-step explanation:

\(\frac{3}{2k}=5\)

\(\frac{3}{2k}*2k=5*2k\) (Multiply both sides of the equation by \(2k\) to get rid of the denominator)

\(3=10k\) (Simplify)

\(10k=3\) (Symmetric Property of Equality)

\(\frac{10k}{10} =\frac{3}{10}\) (Divide both sides of the equation by \(10\) to get rid of \(k\)'s coefficient)

\(k=\frac{3}{10}\) or \(0.3\) (Simplify)

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There is a 0.0625 percent chance that a book on a two-hour reserve will be checked out for a time that is less than or equal to 1.

and the median checkout duration is

\(\begin{array}{l}\\P\left( {x \le \mu } \right) = 0.5\\\\\frac{{{\mu ^2}}}{{16}} = 0.5\\\\{\mu ^2} = 0.5 \times 16\\\\{\mu ^2} = 8\\\end{array} \\\mu = 2.83\)

The median value of an orderly dataset is the precise number that makes up the mean. The ratio between the lowest and highest 50% of the statistics is known as a normal or likelihood measure. When determining the median and mode, there are several formulas that may be employed to identify if there are unusual or even amounts of values.

Here,

a)\(F\left( {X = x} \right) = \frac{{{x^2}}}{{16}},{\rm{ }}0 < x < 4\)

\(P\left( {X \le 1} \right)\)

\(\begin{array}{c}\\P\left( {X \le 1} \right) = F\left( {X = x} \right)\\\\ = \frac{{{1^2}}}{{16}}\\\\ = 0.0625\\\end{array}\)

There is a 6.25% chance that the amount of time a book on a two-hour reserve is less than or equal to 1.

b)\(\begin{array}{c}\\P\left( {0.5 \le X \le 1} \right) = F\left( 1 \right) - F\left( {0.5} \right)\\\\ = 0.0625 - 0.0156\\\\ = 0.0469\\\end{array}\)There is a 4.69% chance that the amount of time a book on a two-hour reserve is between 0.5 and 1.

d)

\(\begin{array}{l}\\P\left( {x \le \mu } \right) = 0.5\\\\\frac{{{\mu ^2}}}{{16}} = 0.5\\\\{\mu ^2} = 0.5 \times 16\\\\{\mu ^2} = 8\\\end{array} \\\mu = 2.83\)

The median duration is 2.83.

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Let:

x = duration of each call

y = cost of the call

Since the cost of the call and the length of the call are related. we can model the situation as a linear equation of the form:

a 5-minute overseas call costs $5.91 and a 10-minute call costs $10.86, so:

Let:

Using elimination method:

Replace the value of m into (1):

Therefore, the cost as a function of time is:

Answer:

x = 135°

Step-by-step explanation:

x and y are supplementary angles, that is they sum to 180° , then

x + y = 180 ← substitute x = 3y into the equation

3y + y = 180

4y = 180 ( divide both sides by 4 )

y = 45

then

x = 3y = 3 × 45° = 135°

For the given system of equations, the x-coordinate is 2.

What is the system of linear equations in two variables?

A linear equation in two variables is one that is written in the form ax + by + c=0, where a, b, and c are real numbers and the coefficients of x and y, i.e. a and b, are not equal to zero.

For example, 10x+4y = 3 and -x+5y = 2 are two-variable linear equations.

The given equations are

               y = x + 12  ---------(I)

             2x + y = 18  ---------(II)

Put the value of y = x + 12 in equation (II), and we get

            2x + x + 12 = 18

             3x + 12 = 18

              3x = 18 - 12

              3x = 6

                x = 6/3

                x = 2

Hence, for the given system of equations, the x-coordinate is 2.

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The writer's profit is $84.00. To calculate the writer's profit, you need to consider the premiums collected from selling the call options, the interest earned on those premiums, and the cost of buying the shares to complete the call contract.The premiums collected from selling the call options are:$0.91 x 100 = $91.00The interest earned on those premiums over 30 days at 5% is:($91.00 x 0.05 x 30) / 365 = $0.38The total amount of cash available to the writer at expiry is therefore:$91.00 + $0.38 = $91.38The cost of buying the shares to complete the call contract is:100 x $42 = $4,200.00Since the underlying asset is worth $39 at expiry, the writer can buy the necessary shares for:100 x $39 = $3,900.00The writer's profit is therefore:$91.38 - $3,900.00 = $84.00Since the writer made a profit, the answer is $84.00.

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To sketch the region enclosed by the curves y = x^3 - 4x and y = 12x and determine the appropriate method of integration. By evaluating the definite integral ∫[-4 to 4] (12x - (x^3 - 4x)) dx, we can calculate the area of the region enclosed by the given curves.

The curves intersect when x^3 - 4x = 12x. Simplifying this equation, we get x^3 - 16x = 0. Factoring out x, we have x(x^2 - 16) = 0, which gives us x = 0 and x = ±4 as the intersection points.

To determine whether to integrate with respect to x or y, we can observe that the region is vertically bounded by the curves. Therefore, we'll integrate with respect to x.

To find the area of the region, we'll integrate the difference of the upper and lower curves within the given bounds, from x = -4 to x = 4.

Now, for a more detailed explanation:

First, let's analyze the curves individually. The curve y = x^3 - 4x represents a cubic function, and y = 12x represents a linear function. By plotting these curves on a graph, we can observe that they intersect at three points: (0, 0), (-4, -48), and (4, 48).

To determine the enclosed region, we need to find the x-values at which the curves intersect. Setting the two equations equal to each other, we have x^3 - 4x = 12x. Rearranging this equation, we get x^3 - 16x = 0. Factoring out x, we have x(x^2 - 16) = 0, giving us x = 0 and x = ±4 as the x-values of intersection.

Since the region is vertically bounded by the curves, we'll integrate with respect to x. To find the area, we'll integrate the difference between the upper curve (y = 12x) and the lower curve (y = x^3 - 4x) within the bounds from x = -4 to x = 4.

By evaluating the definite integral ∫[-4 to 4] (12x - (x^3 - 4x)) dx, we can calculate the area of the region enclosed by the given curves.

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I am 6 1/9 Hope this helps

Answer:23

Step-by-step explanation:

Answer:

The system of equations has no solutions

Step-by-step explanation:

Here, we want to solve the system of equations simultaneously;

-2 = -y - x

y = -1 - x

Substitute the second into the first

-2 = -(-1-x) - x

-2 = 1 + x - x

We can see that the system has no solutions

Answer:

I think its 900 square feet

Step-by-step explanation:

SA formula for triangular prism

SA=p×H+2B

p is perimeter

h is height

B is area of the base (Base times height)

perimeter is 9+12+15 which is 36

height is 20

area of one of the base is 108

now plug it in and calculate

36×20+2(108)

this is 936

you round down to 900 obviously

and there you go

Answer:

11.25

Step-by-step explanation:

20% is 1/5 so decide by 5

Answer: 2.25 weeks

Step-by-step explanation:  So to find this problem we can use the equation 28 + 5x = 10 +13x, so if you do trial and error you can easily get 2.25.

Actually, 0 degrees is not a counterexample for the expression sin(y)*tan(y) = cos(y).

To see why, let's substitute y = 0 degrees into the expression:

sin(y)*tan(y) = cos(y)

sin(0)*tan(0) = cos(0)

0*tan(0) = 1

0 = 1

As we can see, the equation does not hold for y = 0 degrees. However, this does not make 0 degrees a counterexample, because 0 degrees is not in the domain of the tangent function.

The tangent function is undefined at odd multiples of 90 degrees (e.g. 90, 270, etc.), because at those angles the denominator of the tangent function becomes zero. Therefore, we cannot substitute y = 0 degrees into the expression sin(y)*tan(y) = cos(y), because it would result in division by zero.

In summary, 0 degrees is not a counterexample for the expression sin(y)*tan(y) = cos(y), because it is not in the domain of the tangent function.

Answer:

addition

Step-by-step explanation:

There is only plus signs

Recapturing a higher percent of marked alligators affects the estimated total population by making it high enough to support an accurate estimate.

This is referred to as the total number of species or organisms in an area at a given period of time.

Recapture rates are high enough to support an accurate estimate. The Lincoln-Peterson calculation tends to overestimate the population size, especially if the number of recaptures is small.

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Answer: B

Step-by-step explanation:  B, because lines A and C would more likely connect to B

The type of sampling described in the scenario is known as systematic sampling.

Systematic sampling involves selecting elements from a population in a systematic and predetermined manner. In this case, the researcher is selecting every 20th name from the student directory to form her sample. This method of sampling is relatively simple to execute and can be less time-consuming compared to other methods such as random sampling. However, it is important to ensure that the selected interval does not coincide with any underlying patterns in the population that may bias the results.

Overall, systematic sampling can be a useful method for obtaining a representative sample from a large population, but it is important to consider the potential limitations and biases associated with this approach.

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Answer:

Step-by-step explanation:

Answer:

starts at 40 shirts and ends at 8 days at an even slope of 5

Step-by-step explanation:

Answer:

Please

pelo

Step-by-step explanation:

ok que se puede decir que no la encuentro por la noche y que me voy para allá para allá para que me den una solución y me voy para allá y voy saliendo de ahí

Answer:

Step-by-step explanation:

f(x) * g(x) = (5x**2) * (x**3 + 2x**2 - 5x) using distribution of 5x**2 to all terms

              = 5x**5 + 10x**4 - 25x**3

              = 5x**3(x**2 + 2x - x)

This exercise has nothing to do with inverse operations.

Let L represent the number of lawns Tyler mows, and D the number of dogs he walks.

If he earns $20 for each lawn mown, then mowing L lawns earns him $20L. For example, if he mows 1 lawn, he gets $20. If he mows 2 lawns, he earns $40. And so on.

The same could be said about dog-walking. If he earns $15 for each walk, then walking D dogs is worth $15D. For example, if he walks 1 dog, he gets $15; for 2 dogs, $30; and so on.

If after a week he has earned a total of $260, then

20L + 15D = 260

which can optionally be simplified a bit by dividing through both sides by 5 to get

4L + 3D = 52

Since you mentioned "inverse", I suspect you interpreted the question as asking how many lawns Tyler mowed and how many dogs he walked. This is impossible, you cannot determine exactly how many lawns or dogs were involved. But there are only 4 ways this can happen, since L and D must be counting numbers.

D = 4, L = 10

D = 8, L = 7

D = 12, L = 4

D = 16, L = 1