Answer:
2156J
Explanation:
Given parameters:
Height of lift = 10m
Mass = 22kg
Unknown:
Work done by the machine = ?
Solution:
Work done is the force applied to move a body through a certain distance.
So;
Work done = Force x distance
Here;
Work done = mass x acceleration due to gravity x height
Work done = 22 x 9.8 x 10 = 2156J
Which of the following is an adaptation that helps protect the animal?
8.) If a car moving at 50km/h skids 15m with locked brakes, how far does the same car moving at 100km/h
skid with locked brakes?
a. 15m
b. 30m
d. 120m
c. 60m
9.) A lever is used to lift a heavy load. When a 50N force pushes one end of the lever down 1.2m, the load
rises 0.12m. What is the approximate mass (not weight) of the load?
a. 50kg
c. 100kg
d. 500kg
b. 5kg
10.) A block and tackle is used to lift a tractor that weights 210,000N a distance of 10m above the ground. The
maximum force you are able to supply is about 700N. Assuming that you must use every bit of your maximum
force in lifting the tractor (i.e. the tractor begins to rise when you pull with 700N), what length of rope will you
have to pull?
(8) A car starting with a speed v skids to a stop over a distance d, which means the brakes apply an acceleration a such that
0² - v² = 2 a d → a = - v² / (2d)
Then the car comes to rest over a distance of
d = - v² / (2a)
Doubling the starting speed gives
- (2v)² / (2a) = - 4v² / (2a) = 4d
so the distance traveled is quadrupled, and it would move a distance of 4 • 15 m = 60 m.
Alternatively, you can explicitly solve for the acceleration, then for the distance:
A car starting at 50 km/h ≈ 13.9 m/s skids to a stop in 15 m, so locked brakes apply an acceleration a such that
0² - (13.9 m/s)² = 2 a (15 m) → a ≈ -6.43 m/s²
So the same car starting at 100 km/h ≈ 27.8 m/s skids to stop over a distance d such that
0² - (27.8 m/s)² = 2 (-6.43 m/s²) d → d ≈ 60 m
(9) Pushing the lever down 1.2 m with a force of 50 N amounts to doing (1.2 m) (50 N) = 60 J of work. So the load on the other end receives 60 J of potential energy. If the acceleration due to gravity is taken to be approximately 10 m/s², then the load has a mass m such that
60 J = m g h
where g = 10 m/s² and h is the height it is lifted, 1.2 m. Solving for m gives
m = (60 J) / ((10 m/s²) (1.2 m)) = 5 kg
(10) Is this also multiple choice? I'm not completely sure, but something about the weight of the tractor seems excessive. It would help to see what the options might be.
Research the precision of a range of instruments in your classroom.
The precision of the range of instruments was done in the class room with few things like scale volumetric flask based on the criteria mentioned below.
The maximum and minimum range values that an instrument may measure for a quantity or signal, such as amps, volts, or ohms. A lot of multimeters have an auto range feature that automatically chooses the right range based on the measurement's magnitude. This offers the highest resolution of a measurement in addition to a meaningful reading.
Precision is the capacity of an instrument to repeatedly duplicate the same measurement with reliability.
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What do you predict would happen if you brought a negatively charged balloon next to an uncharged piece of paper?.
The charged balloon sticks to a wall due to electrostatic force between the charged balloon and the wall.
What happens when a charged balloon is brought close to another charged balloon?The negatively charged balloon contains an excess of elections. Like charges repel, so the electrons in the balloon repel the electrons in the paper.Therefore, a part of the paper would gain a slightly positive charge. Opposite charges attract, so the paper would want to stick to the balloon/will follow the balloon.When you bring the balloon near a little piece of paper, the negative balloon repels the electrons in the paper so part of the paper near the balloon is positive. Since positive and negative attract, the paper moves toward the balloon. The negatively charged balloon attracts the paper.When the negatively charged balloon approaches a wall, the negative charges in the wall are repelled (or pushed away). This leaves a positive charge on the wallboard at the spot where the balloon touches.Because electrons are negatively charged, the balloon acquires a net negative charge. The balloon's negative charges are attracted to the positive charges in the can, and so the can rolls toward the balloon. As the balloon is pulled away from the can, the can will continue to roll toward the balloon.Any charged object - whether positively charged or negatively charged - will have an attractive interaction with a neutral object. Positively charged objects and neutral objects attract each other; and negatively charged objects and neutral objects attract each other.To learn more about balloon sticks refer to:
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1. A 0.1 mm diameter glass tube is inserted into a ethyl alcohol at 20 degree centigrade in a cup. How much does the Glycerin rise in the tube. The angle of alcohol with tube is 0 degree. D=0.1 mm=0.001 m 0∘ alcohol angel 20∘ ethyl alcohol η=1.1×10^−3 N⋅sec/ m^2sg=.0.79
A 0.1mm diameter glass tube is inserted into an ethyl alcohol at 20 degrees centigrade in a cup. The angle of alcohol with the tube is 0 degrees. D = 0.1 mm = 0.001m, alcohol angle is 0 degrees, ethyl alcohol
\(η=1.1×10^-3 N⋅sec/ m², s_g\)
=0.79.
We have to determine how much glycerin rises in the tube. The force that moves the liquid through the tube is the difference between the downward force of gravity on the liquid column and the upward capillary force produced by the surface tension of the liquid against the walls of the tube.
The height to which the fluid rises in a capillary tube may be measured by balancing the capillary force against the force of gravity on the column.
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How does the mass of a star determine its lifetime? Why?
The mass of a star plays a crucial role in determining its lifetime. In general, more massive stars have shorter lifetimes, while less massive stars have longer lifetimes. This occurs due to two main factors: nuclear fusion rate and fuel availability.
Firstly, the nuclear fusion rate is the process by which a star converts hydrogen into helium, releasing energy in the form of light and heat. Massive stars have stronger gravitational forces, which leads to higher pressures and temperatures in their cores. This causes nuclear fusion to occur at a faster rate, releasing more energy and making the star shine brighter. However, this increased rate of fusion also means that the star consumes its fuel more rapidly.
Secondly, fuel availability refers to the amount of hydrogen a star has for nuclear fusion. Although massive stars contain more hydrogen, the faster rate of fusion means that they deplete their fuel much more quickly than less massive stars. As a result, they have shorter lifetimes.
In summary, a star's mass determines its lifetime because more massive stars have higher nuclear fusion rates and deplete their fuel more quickly, leading to a shorter lifespan. On the other hand, less massive stars have slower fusion rates, conserving their fuel and enjoying longer lifetimes.
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11. In order for an object moving at 10 m/s to have a kinetic energy of 1800
Joules, the object must have a mass in the range of *
O 0-10 kg
O 20-30 kg
30-40 kg
Answer:
20 to 30
Explanation:
20 to 30 is the correct answer
the speed of sound in air at 10°c is 305m/s calculate the speed of sound when the air temperature is 32°c
Helpppp!!!
You are sitting on a dock watching water waves as they pass. you noticed at 5 waves to pass by certain spot every 20 seconds you also noticed at the crest of the water line up exactly with two points that are 6 m apart.
A) what is the frequency of these waves?
B)what is the wavelength of the waves described above?
C) what is the velocity of the waves from where u are watching?
Please show ur workkkkk
Answer:
A) 0.25 Hz
B) 6 m
C) 1.5 m/s
Explanation:
The number of waves that pass a certain spot every 20 seconds = 5 waves
The distance between the crest = 6 m
A) The frequency of the wave, f = The number of cycles per second = 5/20 = 0.25 per second = 0.25 Hz
B) The wavelength of the wave, λ = The distance between crests = 6 m
C) The velocity of the wave, v = f × λ = 0.25/s × 6 m = 1.5 m/s.
Do u think heaven is real?
Answer:
Yes, heaven is for real – and it is heaven, indeed, because we have the hope and assurance of meeting Jesus face-to-face. In the meantime, let’s not just read books and watch movies about the reality of heaven – let’s tell as many people as we can, as often as we can, about the place that will be greater than we can possible imagine.
(10 points) A uniform magnetic field B has constant strength b teslas in the z-direction 11.0. B = (0,0,01 (a) Verity that A = Bxr is a vector potential for B, where r = {x,y,0) (b) Calculate the flux
(a) A = B × r is a vector potential for B, where r = {x, y, 0}.
(b) The flux through a surface S can be calculated as Φ = ∫B·dA, where B is the magnetic field and dA is an infinitesimal area vector perpendicular to the surface.
Determine the vector potential?(a) To verify that A = B × r is a vector potential for B, we need to show that ∇ × A = B.
Using the cross product property, we have ∇ × A = ∇ × (B × r). Applying the vector identity (A × B) × C = B(A · C) - C(A · B), we get ∇ × (B × r) = B(∇ · r) - r(∇ · B).
Since ∇ · r = 0 (as r = {x, y, 0}), and ∇ · B = 0 (as B has a constant magnitude in the z-direction), we find that ∇ × A = B, verifying A = B × r as the vector potential for B.
(b) The flux through a surface S can be calculated as Φ = ∫B·dA, where B is the magnetic field and dA is an infinitesimal area vector perpendicular to the surface.
Given that B has a constant strength b teslas in the z-direction, the flux through surface S will be Φ = ∫B·dA = ∫(0, 0, b) · (dxdy) = b∫dxdy = bA, where A is the area of the surface S.
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Calculate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2.
After considering the given data we conclude that the wavelength of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2 is approximately 102.55 nm.
To evaluate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2, we can apply the Rydberg formula:
\(1/\lambda = R(1/n_1^{2} - 1/n_2^{2} )\)
Here:
λ = wavelength of the emitted light
R = Rydberg constant \((1.097 *10^7 m^{-1} )\)
\(n_1\) and \(n_2\) = initial and final energy levels of the electron
Applying substitution of the given values, we get:
\(1/lambda = (1.097 * 10^7 m^{-1} )(1/6^{2} - 1/2^{2} )\)
Evaluating for λ, we get:
λ = 102.55 nm
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please ans both urgent
Answer:
d I guess not sure
b if down I guess
Explanation:
if worng then plz dont say anything as I am not sure about the ans
What is the electric field 6.44 m from the centre of the terminal of a Van de Graaff with a 9.82 m charge, noting that the field is equivalent to that of a 3.811C charge at the centre of the terminal?
The electric field at 6.44 m from the center of the terminal of a Van de Graaff generator with a 9.82 mC charge is 1530 N/C.
Electric field is a measure of the force that an electric charge experiences when it is placed in an electric field. The electric field at a point in space is proportional to the charge at that point and inversely proportional to the square of the distance from the point to the source of the field.
In this case, the electric field at 6.44 m from the center of the terminal of the Van de Graaff generator is equivalent to the field produced by a 3.811 C charge at the center of the terminal.
Using the formula for electric field, E = kQ / r^2, where E is electric field, k is Coulomb's constant (8.99 x 10^9 N m^2/C^2), Q is the source charge (3.811 C), and r is the distance from the source (6.44 m), we can calculate the electric field to be 1530 N/C.
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what type of quantity is measured by the following units: joules, volts, ev
Joules, volts, and electron volts (eV) are units used to measure different types of physical quantities related to energy and electricity.
Joules (J) measure energy, which can be in various forms such as potential, kinetic, or thermal energy. It is a derived unit in the International System of Units (SI) and is defined as the amount of work done when a force of one newton displaces an object by one meter in the direction of the force.Volts (V) measure electric potential difference, also known as voltage, between two points in an electric circuit. It indicates the amount of work needed to move a unit of electric charge between these points. One volt is equivalent to one joule of energy per coulomb of charge.Electron volts (eV) measure energy on a smaller scale, typically at the atomic or subatomic level. It is the amount of kinetic energy gained or lost by a single electron when it is accelerated through an electric potential difference of one volt. It is commonly used in particle physics and quantum mechanics to express the energies of particles, atoms, and other small-scale phenomena.In summary, joules measure energy, volts measure electric potential difference, and electron volts measure energy on a smaller scale, particularly for atomic and subatomic particles.
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a d'arsonal meter movement has a full scale current value of 100 ua and a resistance of 5k. what size resistor mut be placed in series with this meter
In a d'Arsonval meter movement with a full-scale current value of 100 μA and a resistance of 5k, the size resistor must be placed in series with this meter is 45.5KΩ
To calculate the size of the resistor needed in series with the meter movement, we need to determine the voltage drop across the meter movement at full scale deflection.
We can use Ohm's Law to calculate the voltage drop:
V = IR
where V is the voltage drop, I is the current, and R is the resistance of the meter movement.
At full scale deflection, I = 100 μA and R = 5kΩ, so:
V = (100 μA) * (5kΩ) = 0.5V
To ensure that the meter movement is not damaged and that the current through it remains at or below the full-scale value, we need to limit the current through the meter movement by adding a resistor in series with it.
Let's assume we want the meter to have a full-scale deflection when a voltage of 5V is applied across the entire circuit (meter movement + series resistor).
To calculate the value of the series resistor needed, we can use Ohm's Law again:
R = V / I
where R is the resistance of the series resistor, V is the voltage drop we want to achieve across the series circuit, and I is the current that we want to flow through the circuit (in this case, 100 μA).
Plugging in the values we get:
R = (5V - 0.5V) / (100 μA) = 45.5kΩ
So , 45.5kΩ resistor should be placed in series with the meter movement to achieve full-scale deflection when a voltage of 5V is applied across the entire circuit.
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A block of mass 8.5 kg is being pushed at a constant speed up a ramp that is raised 28o above the horizontal. If the coefficienct of kinetic friction between the ramp and the block is 0.34, what is the magnitude of the applied force?
The amount of applied force is 25.56 N if the ramp and the block have a 0.34 coefficient of kinetic friction.
How can you figure out how much force is being applied?The normal force, which is equal to the part of gravity that is perpendicular to the ramp, must first be determined:
mg = cos(28°)
N is equal to (8.5 kg)(9.81 m/s2)cos(28°).
N = 75.24 N.
friction equals N
friction equals (0,34) (75.24 N)
friction equals 25,56 N
Given that the block is travelling at a constant speed, the applied force must be equal to the force of friction in both magnitude and direction.
applied force = friction
Force exerted = 25.56 N
Consequently, the applied force is 25.56 N in size.
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What is the first law of gravity??
Answer:
every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
Explanation:
A gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. When 254 kcal of heat is added to the gas, the volume is observed to increase slowly from 12.0 m^3 to 16.2 m^3.
a. Calculate the work done by the gas.
b. Calculate the change in internal energy of the gas.
The work done by the gas for question A will be 4.2 * 10^5 J.
The change in internal energy of the gas for question B is 6.43 * 10^5 J.
What is work (in gas)?For a gas, it is the product of the pressure P and the volume V during a change of volume. The formula for work done in gas is W (work) = P (pressure) * V (volume)
Now, let's calculate the work done by gas to answer question A.
Work = Pressure * (Volume 2 - Volume 1)
= 1 atm * (16.2 - 12)
= 10^5 Pa * 4.2
= 4.2 * 10^5 J
So the work done by the gas is 4.2 * 10^5 J.
Now, let's find the change in internal energy of the gas.
The heat energy added to the system is
Q = 254kcal
= 254kcal * (4184J / 1 kcal)
= 1.063 * 10^6 J
The change in internal energy of gas is
ΔU = Q (the heat energy added) - W (work done by gas)
= 1.063 * 10^6 J - 4.2*10^5 J
= 6.43 * 10^5 J
Therefore, the change in internal energy of the gas is 6.43 * 10^5 J
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The Egyptians and the Greeks both shared which belief about preparing for important dreams? A. Dream preparation was a foolish custom only practiced by the superstitious. B. Dream preparation increased the likelihood of getting the right dream. C. Dream preparation was a simple process of going to sleep at the right time. D. Dream preparation could keep a person from having any dreams at all. Please select the best answer from the choices provided A B C D.
Answer:
B
Explanation:
Edg 2021
Boxes A and B both remain at rest. Is the static friction force on A larger than, smaller than or equal to the friction force on B? A= 20 kg 30 N phi 0.4
B= 10 kg 30 N phi 0.5 a. fA>fb
b. fA
c. We need more information to draw a conclusion.
d. fA=fb
The static friction force on box A and B can be calculated using the equation fs ≤ μs * N.
Where fs is the static friction force, μs is the coefficient of static friction, and N is the normal force acting on the object. For box A, the static friction force is fs = μs * N = 0.4 * (20 kg * 9.8 m/s^2) = 78.4 N. For box B, the static friction force is fs = μs * N = 0.5 * (10 kg * 9.8 m/s^2) = 49 N. Therefore, the static friction force on box A is larger than the friction force on box B (fA > fB). This is because the friction force is directly proportional to the weight of the object and the coefficient of static friction. Box A has a larger weight and a smaller coefficient of static friction than box B, which results in a larger static friction force acting on it to keep it at rest.
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A floating ice block is pushed through a displacement vector d= (15 m)i - (12 m)j along a straight embankment by rushing water,which exerts a force vector F = (210 N)i - (150 N)j on the block.How much work does the force do on the block during thedisplacement?
Given that a floating ice block is pushed through a displacement vector d = (15 m)i - (12 m)j along a straight embankment by rushing water,
which exerts a force vector F = (210 N)i - (150 N)j on the block. We need to find how much work the force does on the block during the displacement.Work done by the force is given as,W = F.dWhere, F is the force and d is the displacement vector of the object.
So, substituting the given values in the above equation, we have;W = (210 N)i - (150 N)j . (15 m)i - (12 m)j=> W = (210 N x 15 m) + (150 N x 12 m)=> W = 3150 Nm + 1800 Nm=> W = 4950 NmTherefore, the force does 4950 Nm of work on the block during the displacement.
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identify the first-row transition metal m that satisfies the requirements given (more than one answer may be possible). be sure to show your work.
To identify the first-row transition metal that satisfies the given requirements, The first-row transition metals include elements from Scandium (Sc) to Zinc (Zn). Each of these elements has unique properties and characteristics.
The first-row transition metals consist of elements from Scandium (Sc) to Zinc (Zn) in the periodic table. These elements are characterized by their partially filled d-orbitals and exhibit various properties such as high melting and boiling points, variable oxidation states, and the ability to form colored compounds. Each transition metal in this range has its own atomic number, electron configuration, and unique set of properties. Therefore, without specific criteria or requirements, it is not possible to determine which transition metal satisfies the given conditions. By providing more details, such as desired chemical properties or specific characteristics, it would be easier to identify the suitable transition metal.
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what is the acceleration of a proton moving with a speed of 9.5 m/s at right angles to a magnetic field of 1.5 t ?
The acceleration of the proton is approximately 3.43 x 10^15 m/s^2.
A proton that moves at right angles to a magnetic field experiences a magnetic force that causes it to follow a circular path. This is due to the fact that the magnetic force acting on a charged particle moving at right angles to a magnetic field is proportional to the product of the magnetic field, the charge, and the velocity. As a result, the acceleration of the proton can be calculated using the following formula:
a = (qvB) / m
where q is the charge of the proton, v is its velocity, B is the magnetic field strength, and m is the mass of the proton.
Given that a proton moves with a speed of 9.5 m/s at right angles to a magnetic field of 1.5 T, the acceleration can be calculated as follows:
a = (qvB) / m = (1.602 x 10^-19 C x 9.5 m/s x 1.5 T) / (1.673 x 10^-27 kg)≈ 3.43 x 10^15 m/s^2
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two football players with mass of 75 kg and 100 kg run towards each other with a combined speed of 6 m per second and 8 m per second respectively. if they grab each other as they collide the combines speed of the two players just after the collision would be
When two objects collide and stick together, their combined speed after the collision can be calculated using the conservation of momentum principle. The principle states that the total momentum of an isolated system remains constant if no external forces act on it.
In this case, the initial momentum of the two players before the collision can be calculated as follows:
75 kg * 6 m/s + 100 kg * (-8 m/s) = 450 kg m/s
After the collision, the players stick together, and their combined speed can be calculated as follows:
Final momentum = (75 kg + 100 kg) * v
450 kg m/s = 175 kg * v
v = 450 kg m/s / 175 kg = 2.57 m/s
So, the combined speed of the two players just after the collision would be 2.57 m/s.
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Find the rate of change of the volume of a cube with respect to the length of its side when =11
When s = 11, the rate of change of the volume of the cube with respect to the length of its side is 363 cubic units per unit change in side length.
To find the rate of change of the volume of a cube with respect to the length of its side, we need to differentiate the volume formula with respect to the side length.
Let's denote the side length of the cube as "s" and the volume as "V."
The volume of a cube is given by the formula V = s³.
To find the rate of change of V with respect to s, we differentiate V with respect to s:
dV/ds = 3s².
Now, if we substitute s = 11 into the expression, we can find the rate of change at that specific value:
dV/ds = 3(11)²
= 3(121)
= 363.
Therefore, when s = 11, the cube's volume changes at a rate of 363 cubic units for every unit increase or decrease in side length.
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1. Which of the following contains scarar quantities only a) Speed, energy b) velocity, energy (1) 9elocity, marmentum d) speed, displacement
The correct answer is: "d) speed, displacement". Speed and displacement are merely scalar. Speed is magnitude without direction, a scalar quantity. Displacement is a scalar quantity that only measures an object's position change.
The only scalar option is "d) speed, displacement." Scalar quantities can be described solely by their magnitude or numerical value. They have no vectors. Speed is a scalar quantity since it measures distance covered. It measures speed without direction.
Displacement means moving an object in a certain direction. Displacement is a scalar quantity if just the magnitude of the position shift is considered. Velocity is a vector quantity because it comprises magnitude (speed) and direction. It shows how fast an object changes direction. Momentum, the product of mass and velocity, is a vector quantity. Direction and magnitude. Therefore only "d) speed, displacement" is scalar since it includes speed (scalar) and disregards direction for displacement.
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1. What is a radioactive isotope
Answer:
A radioactive isotope, also known as a radioisotope, radionuclide, or radioactive nuclide, is any of several species of the same chemical element with different masses whose nuclei are unstable and dissipate excess energy by spontaneously emitting radiation in the form of alpha, beta, and gamma rays.
Explanation:
its right dawg
What type of element gains electrons in ionic bonding, and what type of charge will it create?
Explanation:
Nonmetals tend to gain electrons and become anions. For example, in Fig. 2.22 A, a neutral oxygen atom (O), with eight protons and eight electrons, gains two electrons. This gives it two more negative charges than positive charges and an overall charge of 2–.
Spring constant of 80 N/m how much elastic potential if it’s stretched .20 metered
The elastic potential energy of the spring is 1.6 J.
What is the elastic potential energy of the spring?
The elastic potential energy of the spring is the energy stored in the spring and it is calculated as follows;
U = ¹/₂kx²
where;
k is the spring constant x is the extension of the springThe given parameters include;
the spring constant of the spring, k = 80 N/mthe extension of the spring, x = 0.2 mU = ¹/₂kx²
U = ¹/₂ (80) (0.2)²
U = 1.6 J
Thus, the elastic potential energy of the spring is a function of the spring constant and the extension of the spring.
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