A piece of wire of resistance R is bent through 180 at mid point and two halves are twisted together. What is the resistance of wire

Answers

Answer 1

The resistance of the wire bent through 180 degrees at its mid point and the two halves are twisted together 0.25R.

Resistance of the wire

The resistance of a wire directly proportional to the length of the wire and inversely proportional to the area of the wires.

R = ρL/A

where;

L is length of wireA is area of the wireρ is resistivity

When the piece of wire is bent through 180 degrees at its mid point and the two halves are twisted together. So, the length is halved (l/2) and the area of cross section is doubled (2A).

\(R =\rho \frac{\frac{1}{2} l}{2A} \\\\R = \frac{1}{4} (\frac{\rho L}{A} )\\\\R_{new} = \frac{R}{4}\)

Thus, the resistance of the wire bent through 180 degrees at its mid point and the two halves are twisted together 0.25R.

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Related Questions

Match each hypothesis for how the Moon formed with the statement that best describes it.

The Moon was locked into orbit by Earth's
gravity as it was passing by it.

The Moon was formed from the same cloud
of material as Earth.

The Moon was formed from the collision between
Earth and another Mars-sized body.

The Moon was formed from collisions and combining
of planetesimals.

giant impact theory
arrowRight

colliding planetesimals hypothesis
arrowRight

capture hypothesis
arrowRight

accretion hypothesis
arrowRight

Answers

The Moon was formed from the collision between Earth and another Mars-sized body- giant impact theory

The Moon was formed from collisions and combining- The Colliding Planetesimals Theory

The Moon was locked into orbit by Earth's gravity as it was passing by it- capture hypothesis

The Moon was formed from the same cloud of material as Earth- accretion hypothesis

Define The Colliding Planetesimals Theory.

Early in the Solar System's existence, planetesimals (extremely massive rocks like asteroids) orbiting the Sun and the Earth came into contact with one another, breaking them apart. Condensing from this material was the Moon.

According to the capture hypothesis, put forth by Michael Mark Woolfson in 1964, the Solar System came into being as a result of tidal interactions between the Sun and a protostar with a low density. The Sun's gravity would have attracted material from the protostar's diffuse atmosphere, which would have subsequently collapsed to create the planets.

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I’ll give brainliest

Ill give brainliest

Answers

The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

Thus, Waveforms with periodic variations are those that recur consistently at set intervals.

The phrase is typically used in electronics to describe periodically changing voltages, currents, or electromagnetic fields. It is typically used in acoustics to describe constant periodic sounds caused by changes in air pressure or other media.

In these situations, the signal's frequency, amplitude, or phase shift have no bearing on the waveform, which is a characteristic. Additionally, non-periodic signals like chirps and pulses can be referred to by this name.

Thus, The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

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A parallel circuit has four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. How much current is supplied by the source?

Answers

A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.

The sum of the branch currents in a parallel circuit can be calculated by adding up the values of the individual branch currents. In this case, we have four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. Thus, the sum of the branch currents is:120 mA + 380 mA + 250 mA + 2.1 A= 2.85 ATherefore, the current supplied by the source in this parallel circuit is 2.85 A. This is because, in a parallel circuit, the current from the source is split between the different branches of the circuit. Each branch will have a different current, but the sum of all the branch currents will always equal the current supplied by the source

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a violin is less than 0.5 m long. a bass fiddle is more than 1.5 m long. which instrument do you expect to be able to play notes with a lower pitch and why?

Answers

Explanation:

When there is a high frequency sound the speed of the vibrations is faster and makes a high pitch sound. When there is a low frequency sound the speed of the vibrations is slower and makes a lower pitch sound.

why might calcium be a important in the diet of many living things

Answers

Answer:

Calcium is an essential mineral that is important in the diet of many living things as it plays several important roles in the body:

1. Bone and teeth formation: Calcium is a key component of bones and teeth, making them strong and healthy.

2. Muscle function: Calcium plays a critical role in muscle contraction and relaxation, helping muscles function properly.

3. Nerve function: Calcium is involved in the transmission of nerve impulses, which allows for proper communication between nerve cells.

4. Blood clotting: Calcium is required for blood clotting, which is important for preventing excessive bleeding after an injury.

5. Cellular signaling: Calcium is involved in many cellular signaling pathways, helping to regulate various physiological processes in the body.

Therefore, having an adequate amount of calcium in the diet is crucial for the overall health and well-being of many living organisms.

A geosynchronous satellite orbits Mars (mass = 6.42 x 1023 kg) once every Martian day, 88640 s. At what radius does it orbit?

Answers

Answer:

angular speed ω = 2PI / T rad/sec  

ω^2*r = M*G/r^2

r = ³√ M*G/ω^2 = ³√6.42*10^23*6.67*10^-11*88640^2/39.5 = 2.04*10^7 m

Explanation:

A geosynchronous satellite orbits Mars once every Martian day, 88640 s then the radius of the orbit will be equal to 2.04 × 10⁷ m.

What is gravity?

The fundamental force of attraction operating on all matter is recognized as gravity, also spelled gravity, in mechanics. It has no impact on identifying the interior properties of common matter because it is the weakest force known to exist in nature.

As per the given data in the question,

Mass, m = 6.42 x 10²³ kg

Time, T = 88640 s

Use the formula of velocity for satellite,

v = 2πR/T

Where R represents the radius

Use the formula of centripetal acceleration,

\(a_c\) = v²/R

Thus;

\(a_c\) = (2πR/T)²/R

= 4π²R/T²

The formula for gravitational acceleration is:

\(a_g\) = Gm/R²

G = 6.674 × 10⁻¹¹ m³/kg. s²

Now, the satellite's gravitational acceleration is what is responsible for its centripetal acceleration. Thus,

Centripetal acceleration = gravitational acceleration.

Thus;

4π²R/T² = Gm/R²

Making R the subject gives;

R = ∛(GmT²/4π²)

Substitute the values in the above equation,

R = ∛((6.674 × 10⁻¹¹ × 6.42 x 10²³ × 88640²)/(4 × π²))

R = 2.04 × 10⁷ m

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If you have two uncertainties, and they are from two different sources and contribute to the uncertainty of a measurement, what formula should be used to combine these and find the total uncertainty for the measurement?

Answers

The propagation errors we can find the uncertainty of a given magnitude is the sum of the uncertainties of each magnitude.

                           Δm = ∑  \(| \frac{dm}{dx_i} | \ \Delta x_i\)

Physical quantities are precise values ​​of a variable, but all measurements have an uncertainty, in the case of direct measurements the uncertainty is equal to the precision of the given instrument.

When you have derived variables, that is, when measurements are made with different instruments, each with a different uncertainty, the way to find the uncertainty or error is used the propagation errors to use the variation of each parameter, keeping the others constant and taking the worst of the  cases, all the errors add up.

If m is the calculated quantity, x_i the measured values ​​and Δx_i the uncertainty of each value, the total uncertainty is

                      Δm = ∑  \(| \frac{dm}{dx_i } | \ \Delta x_i\)    | dm / dx_i | Dx_i

               

for instance:

If the magnitude is  a average of two magnitudes measured each with a different error

                     m = \(\frac{m_1+m_2}{2}\)

                     Δm = | \(\frac{dm}{dx_1}\) |  Δx₁ + | \(\frac{dm}{dx_2}\) | Δx₂

                     \(\frac{dm}{dx_1}\) = ½

                     \(\frac{dm}{dx_2}\) = ½

                     Δm = \(\frac{1}{2}\) Δx₁ + ½ Δx₂

                     Δm = Δx₁ + Δx₂

In conclusion, using the propagation errors we can find the uncertainty of a given quantity is the sum of the uncertainties of each measured quantity.

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help with this please

help with this please

Answers

Answer:

I think that those are all true but I'm not completely sure.

Help me out here please!!!

Help me out here please!!!

Answers

Answer:

I beleive the answer is d

Explanation:

This is beause theball starts going back down because the velocity slows down.

Answer:

d

Explanation:

the velocity changes as it goes down

A 0.1 kg tennis ball is brought from a speed of 15 m/s to a speed of 45 m/s when hit by a tennis racket. If this done over 0.05 seconds, what is the power generated by the tennis racket

Answers

2.2 because i said so

Which of the following is an example of a wave?
A. A falling tree
B. A running faucet
C. A rising elevator
D. A doorbell sound

Answers

The example of a wave is D. A doorbell sound.

Answer:

D. A doorbell sound

that's it

How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food

A. The amount of oxygen in the atmosphere increased

B. Mass extinctions occurred

C. The oceans became larger

D. Rainfall increased

Answers

The amount of oxygen in the air was increased

650 N boy and a 419 N girl sit on a 150 N porch swing that is 2.0 m long. If the swing is supported by a chain at each end, what is the tension in each chain when the boys sits .8 m from one end and the girls sits .5 m from the other end

Answers

The tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.

Principle of moments

The Principle of Moments states that when a body is in equip, the sum of clockwise moment about a point is equal to the sum of anticlockwise moment about the same point.

The formula for calculating moment is given below:

Moment = Force × perpendicular distance from the pivot

Calculating the tension in the chains

From the principle of moments:

Let tension in chain 1 be T1 and tension in chain 2 be T2.

T1 + T2 = 150 + 650 + 419

T1 + T2 =1219

Taking all distances from chain 1,

Sum of Moments = 0

419 × 0.5 + 150 × 0.85 + 650 × 0.9 = T2 × 1.7

T2 = 922/17

T2 = 542.35 N

Then, T1 = 1219 - 542.35

T1 = 676.65 N

Therefore, the tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.

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A 1875 kg car going 23.0 m/s rear-ends a 1025 kg compact car going 17.0 m/s on ice in the same direction. The two cars lock together. How fast do the cars move together immediately after the collision?

Answers

Answer:

21 m/s

Explanation:

If

m1 = mass of 1875 kg car

u1 initial speed of 187 kg car = 23.0 m/s

m2 = mass of 1025 kg car

u2= initial speed of 1025 kg car = 17.0 m/s

Since they stuck together, they have a common final velocity v

From principle of conservation of linear momentum

m1u1 + m2u2 = (m1 + m2) v

v= m1u1 + m2u2/(m1 + m2)

v= 1875 × 23 + 1025× 17/(1875 + 1025)

v= 43125 + 17425/2900

v= 21 m/s

The final velocity of both cars is 20.87 m/s.

How do you calculate the velocity?

Given that the two cars have a mass of 1875 kg and 1025 kg respectively and the velocity of both the cars is 23.0 m/s and 17.0 m/s.

The common velocity of both cars is given below.

\(v (m_1+ m_2) = m_1u_1 + m_2u_2\)

Where v is the final velocity of both cars, m1 and m2 are the mass of both cars respectively. u1 and u2 are the initial velocities of both cars.

Substituting the values, we get the final velocity.

\(v ( 1875 + 1025) = 1875 \times 23 + 1025 \times 17\)

\(v = 20.87 \;\rm m/s\)

Hence we can conclude that the final velocity of both the cars is 20.87 m/s.

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For a substance to change from a gas to a liquid what must happen to its particles
A. they must lose enough of their kinetic energy that their motion is influenced by the attractions between them
B. they must gain enough kinetic energy ti allow them to move freely while still being attracted to one another
C. They must lose enough of their kinetic energy so that the attractions between them hold in place as they vibrate
D. They must gain enough kinetic energy to break out of their ridged structure and move independently

Answers

For a substance to change from a gas to a liquid, its particles A. must lose enough of their kinetic energy that their motion is influenced by the attractions between them.

We want to know what change takes place when the particles of a substance that goes from gas to liquid. We need to consider that:

In a gas, the particles move freely, with great kinetic energy and the attraction forces between them are negligible.In a liquid, the particles have some degree of movement, although less than in the gas state and the attraction forces are higher.

For a substance to change from a gas to a liquid what must happen to its particles:

A. they must lose enough of their kinetic energy so that their motion is influenced by the attractions between them. TRUE. The attraction between the molecules causes them to move less in the liquid state. B. they must gain enough kinetic energy to allow them to move freely while still being attracted to one another. FALSE. Liquids have lower kinetic energies than gases. C. They must lose enough of their kinetic energy so that the attractions between them hold in place as they vibrate. FALSE. Even though they must lose kinetic energy, they still have some left to move rather than just to vibrate. D. They must gain enough kinetic energy to break out of their ridged structure and move independently. FALSE. Liquids have lower kinetic energies than gases.

For a substance to change from a gas to a liquid, its particles A. must lose enough of their kinetic energy that their motion is influenced by the attractions between them.

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Answer: A

Explanation:

What kind of wave is formed (transverse or longitudimal wave, pick one) is formed by ripples on a calm pond? With explanation! Please help, most detailed answer will get brainliest and many points.

Answers

Answer:

Transverse

Explanation:

It's tranverse because the water molecules are moving repeatedly up and down vertically when the waves move horizontally across the waters surface.

12. A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the Earth to the surface. If the satellite had a weight at the surface of 4000 N, what is the force of gravity (weight) of the satellite when it is in its orbit? Give your answer in newtons, N.

Answers

Answer:

Explanation:

F = GmM/d²

As gravity force is proportional to the inverse of the square of the distance,

doubling the distance will reduce the weight to a forth.

F' = GmM/(2d)²

F' = ¼GmM/d²

F' = ¼F = ¼(4000)

F' = 1000 N

Circuits
Calculate the total Resistance, Current, and Power in the circuits

CircuitsCalculate the total Resistance, Current, and Power in the circuits

Answers

The total resistance of the circuit is 3 ohms.

The total current in the circuit is 4 A.

The power of the circuit is 48 W.

What is the total resistance of the circuit?

The total resistance of the circuit is calculated as follows;

1 / Rt = 1/R1 + 1/R2 + 1 / R3

1/Rt = 1/6 + 1/12 + 1/12

1/Rt = 0.3333

Rt = 3 ohms

The total current in the circuit is calculated as follows;

I = V / Rt

I = ( 12 ) / ( 3 )

I = 4 A

The power of the circuit is calculated as follows;

P = IV

P = ( 4 x 12 )

P = 48 W

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A car traveling 85 km/h is 250 m behind a truck
traveling 73 km/h.

Answers

Time needed = t = 20.83 s

Further explanation

Given

car speed = 85 km/h

truck speed = 73 km/h

Required

the time it takes for the car to reach the truck

Solution

When the car reaches the truck, the distance between them will be the same

x car - 250 m = x truck

General formula for distance (d) :

d = v.t

So the equation becomes :

85t-250 = 73t

12t=250

t = 20.83 s

how long does the guided discovery stage of the drawing in phase last? in training program

Answers

Answer
2 to 3 weeks
This aspect of the drawing-in phase can last 2 to 3 weeks, or as little as a few workouts, and is designed to a) reverse the effects of disuse, b) get the clients oriented to all available technologies, c) allow the clients to learn what their options are and which exercises they likes best.

Answer:

2 to 3 weeks

Explanation:

B. Write short notes on:
1. Horticulture
2. Pisciculture
3. Aviculture
4. Veterinary science
5. Intensive farming.

Answers

1. Horticulture is the agriculture of plants, mainly for food, materials, comfort and beauty for decoration.

2.Pisciculture also known as fish farming is the rearing of fish for food in enclosures such as fish ponds or tanks.

3.Aviculture is the practice of keeping and breeding birds, especially of wild birds in captivity. Aviculture is generally focused on not only the raising and breeding of birds, but also on preserving avian habitat, and public awareness campaigns.

4. Veterinary medicine is the branch of medicine that deals with the prevention, control, diagnosis, and treatment of disease, disorder, and injury in animals. Along with this, it also deals with animal rearing, husbandry, breeding, research on nutrition and product development.

5. Intensive agriculture, also known as intensive farming and industrial agriculture, is a type of agriculture, both of crop plants and of animals, with higher levels of input and output per cubic unit of agricultural land area.

Hope this helps.

3. What is the weight of a 462-kg bar?


Answers

Answer:

F = M g = 462 kg * 9.80 m/s^2 = 4528 Newtons

It somewhat unfortunate that weight in the English System is measured in pounds (mass in slugs) and in the metric system weight is measured in Newtons (mass in kilograms)

Which class of metals are the only ones to produce a magnetic field? A. Transition B. Alkaline earth C. Metalloids D. Alkali​

Answers

The answer is c.

I think but don’t get mad if I’m wrong

Based on the diagram, how is the greenhouse gas effect maintained?

Human activities absorb sunlight to create stable warm temperatures of Earth.
Sunlight absorbed at the surface results in greenhouse gases warming the atmosphere.
Greenhouse gases produced from human activities heat surface temperatures of Earth.
Sunlight is reflected by the surface of Earth, and heat is trapped in the atmosphere by greenhouse gases.

Based on the diagram, how is the greenhouse gas effect maintained? Human activities absorb sunlight to

Answers

The correct statement is " Sunlight absorbed at the surface results in greenhouse gases warming the atmosphere." The correct option is B.

The greenhouse effect is a natural phenomenon that keeps the Earth's temperature within a range that is suitable for humans and other forms of life. The greenhouse effect is maintained by certain gases in the atmosphere, known as greenhouse gases, which trap the sun's energy and warm the Earth's surface.

Option A, which states that human activities absorb sunlight to create stable warm temperatures on Earth, is not correct. Human activities do not directly absorb sunlight. However, they do release greenhouse gases, which contribute to the greenhouse effect and increase the temperature of the Earth's surface.

Option C, which states that greenhouse gases produced from human activities heat the surface temperatures of Earth, is partially correct. Human activities, such as burning fossil fuels, do release greenhouse gases that contribute to the greenhouse effect. However, this option suggests that the greenhouse gases themselves heat the surface of the Earth, which is not accurate. The greenhouse gases trap heat in the atmosphere, which warms the Earth's surface.

Option D, which states that sunlight is reflected by the surface of the Earth, and heat is trapped in the atmosphere by greenhouse gases, is not entirely accurate. The Earth's surface absorbs the sun's energy, and some of this energy is reflected back into space. The rest is absorbed by the Earth's surface and then re-emitted as heat. The greenhouse gases in the atmosphere trap this heat and prevent it from escaping into space, which causes the Earth's temperature to rise.

Therefore, The correct answer is option B.

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A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ

Answers

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

How do I determine the kinetic energy?

We'll begin by obtaining the velocity of the flywheel. This is shown below:

Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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The two angled ropes are used to support the crate in Figure P5.7. The tension in the ropes can have any value up to 1500 N. When the tension exceeds this value, the ropes will break. What is the largest mass the ropes can support?

The two angled ropes are used to support the crate in Figure P5.7. The tension in the ropes can have

Answers

Answer:

170 kg

Explanation:

Free-Body Diagram:

Let's start by drawing a free body diagram for this problem. Let's call the tension in the left rope \(T_1\) and the tension in the right rope \(T_2\).

Now we can construct a free body diagram using the horizontal and vertical components of the two tension forces.

Let's start with the left tension force:

Horizontal component (x): \(T_1 \cdot cos(30)\)Vertical component (y): \(T_1 \cdot sin(30)\)

The right tension force:

Horizontal component: \(T_2 \cdot cos(45)\)Vertical component: \(T_1 \cdot sin(45)\)

In order to see what these forces look like on the diagram, look at the first image attached. (1)

Now, we can create the FBD using the components of the tension forces and the force of gravity pulling on the crate, known as w.

The horizontal components of \(T_1\) and \(T_2\) go on the left and right of the FBD, respectively. The two vertical components go on top, and the weight force is on the bottom. We know that weight = mg.

To see what the free body diagram should look like, see the second image attached. (2)

Now that we have the FBD, we can write a system of equations using the sum of forces in both the x- and y-direction.

Since the crate is not moving in either the horizontal or vertical direction, we can say that the net force acting on the crate is 0.

\(F_\text{net} = 0\)

This means that the sum of x forces and the sum of y forces are both 0. Let's set the top and right to be the positive direction and the bottom and left to be the negative direction. Now we can write the system of equations:

\(\sum F_x = T_2 \cdot cos(45) - T_1\cdot cos(30) = 0\) \(\sum F_y = T_1 \cdot sin(30) +T_2\cdot sin(45) - mg = 0\)

There are many ways to solve this system of equations, but I will be showing the top two ways that I tend to solve these types of problems.

Method 1:

Solve for \(T_1 \cdot sin(30)\) and \(T_1 \cdot cos(30)\) in both equations.

\(T_1 \cdot cos(30) = T_2 \cdot cos(45)\) \(T_1\cdot sin(30) = mg - T_2 \cdot sin(45)\)

We know that \(\frac{sin\theta}{cos\theta}\) = \(tan\theta\), so we can reorder both equations and divide them.

\(T_1\cdot sin(30) = mg - T_2 \cdot sin(45)\) \(T_1 \cdot cos(30) = T_2 \cdot cos(45)\) \(tan(30)=\frac{mg-T_2\cdot sin(45)}{T_2\cdot cos(45)}\)

Note that \(\frac{T_1}{T_1}\) cancels, leaving us with tan(30).

Now that we have this equation, we can plug in known values. We are trying to solve for m, the largest mass of the crate that the ropes can support. We know that:

\(g=9.8\ \frac{m}{s^2}\) \(T_2=1500\ \text{N}\)  

Let's substitute these values into our equation:

\(tan(30)=\frac{m(9.8)-(1500)\cdot sin(45)}{(1500)\cdot cos(45)}\)

Multiply 1500 * cos(45) to both sides of the equation.

\(tan(30) \cdot (1500 \cdot cos(45)) =9.8m-(1500 \cdot sin(45))\)  

Add 1500 * sin(45) to both sides of the equation.

\(tan(30) \cdot (1500 \cdot cos(45)) + 1500 \cdot sin(45)) =9.8m\)

Divide both sides of the equation by 9.8.

\(\frac{tan(30) \cdot (1500 \cdot cos(45)) + (1500 \cdot sin(45)) }{9.8}= m\)

Simplify.

\(\frac{1673.032607}{9.8}=m\) \(m=170.717613\)

The largest mass the ropes can support is around 170 kg (round down, not up).

Method 2:

We can use the system of equations again.

\(T_1 \cdot cos(30) = T_2 \cdot cos(45)\) \(T_1\cdot sin(30) = mg - T_2 \cdot sin(45)\)

This time, let's do a little guess and check. Using the first equation, plug in 1500 N for T2 and solve for T1.

\(T_1 \cdot cos(30) = (1500) \cdot cos(45)\)

Divide both sides of the equation by cos(30).

\(T_1=\frac{1500 \cdot cos(45)}{cos(30)}\)

Simplify.

\(T_1=1224.744871 \ \text{N}\)

Now plug in 1500 N for T1 and solve for T2.

\((1500) \cdot cos(30) = T_2 \cdot cos(45)\)

Divide both sides by cos(45).

\(T_2=\frac{1500\cdot cos(30)}{cos(45)}\) \(T_2=1837.117307 \ \text{N}\)

Since the tension cannot exceed 1500 N without the rope breaking, we must use the first substitution, where \(T_1=1224.744871\) and \(T_2=1500 \ \text{N}\).

Now we can use these known values and plug them into the second equation: \(T_1\cdot sin(30) = mg - T_2 \cdot sin(45)\)

Add \(T_2 \cdot sin(45)\) to both sides of the equation.

\(mg=T_1 \cdot sin(30) + T_2 \cdot sin(45)\)

Divide both sides of the equation by g.

\(m=\frac{T_1 \cdot sin(30) + T_2 \cdot sin(45)}{g}\)

Plug in known values and solve for m.

\(m=\frac{(1224.744871) \cdot sin(30) + (1500) \cdot sin(45)}{9.8}\)  

Simplify.

\(m=\frac{1673.032607}{9.8}\) \(m=170.717613\)

As you can see, we get the same answer with either method. The largest mass the ropes can support is 170 kg.

The two angled ropes are used to support the crate in Figure P5.7. The tension in the ropes can have
The two angled ropes are used to support the crate in Figure P5.7. The tension in the ropes can have

What is energy anything that takes up space and has mass a change in the position of an object a push or pull the ability to cause change in matter

Answers

Energy is that which has the ability to cause change in matter.

What is energy?

Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.

So in simple definition we can say that energy is that which has the ability to cause change in matter.

Based on the given statements we can classify them as;

anything that takes up space and has mass - matter.cause a change in the position of an object through push or pull - forcethe ability to cause change in matter - energy.

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QUESTIONS An athlete, during his race in the 100 m sprint in the 2008 Beijing Olympics, exerted #force of 850 s on the race track using his show on the right foot at an angle of 50/' to the horizontal, 850 N 3.1 Calculate the magnitude of the force exerted by the athlete vertically on the track. 3.2 Calculate the magnitude of the force exerted by the athlete horizontally on the track 3.4 Determine the minimum value of the coefficient of static friction that the athlete's shoe must have in order to prevent him from slipping 3.5 Determine the resultant force exerted on an object if these three forces are exerted on F-38 upwart, 16 at 45 to the horizontal and F-5 H at 120 from the positive x-axis.​

Answers

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

In addition to acceleration, what else will be a maximum at the amplitude for SHM?

A. Potential energy
B. Kinetic energy
C. Nuclear energy
D. Chemical energy

Answers

It is Potential energy's

The Mars Rover Curiosity has a mass of 900 kg. Taking the gravitational field strength to be 9.8 N/kg
on Earth and 3.7 N/kg on Mars, give the value of the weight of the Rover on earth and mars

Answers

The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.

Weight of objects on Earth and on Mars

The weight of an object is given by the product of its mass and the gravitational field strength at its location.

On Earth:

Weight = mass x gravitational field strengthWeight = 900 kg x 9.8 N/kgWeight = 8820 N

On Mars:

Weight = mass x gravitational field strengthWeight = 900 kg x 3.7 N/kgWeight = 3330 N

Therefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.

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