A person weighs 60kg. Calculate the amount of work done if he is raised 12m into the air.

The efficiency of the process is 42%

From the question given above, the following data were obtained:

Useful energy = 250 watt

Wasteful energy = 600 watt

The efficiency of the process can be obtained as illustrated below:

\(efficiency \: = \frac{useful \: energy}{wasteful \: energy} \times 100 \\ \\ efficiency \: = \frac{250}{600} \times 100 \\ \)

Therefore, the efficiency of the process is 42%

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Answer:

Its actually 29%

Explanation:

Took the Test

The radius of the wheel with a tangential velocity of 4.3 m/s and centripetal acceleration of 72 m/s² is 0.25 meter.

The acceleration of an object ,moving through a  circular path is called the centripetal acceleration. It is related to the velocity and radius of curvature of the circular path as follows:

a = v²/r.

The tangential velocity or angular velocity is the rotational analogue of the linear velocity.

given that, tangential velocity v = 4.3 m/s

centripetal acceleration a = 72  m/s²

Then, radius of the wheel is calculated as follows:

r = v²/a

r = (4.3 m/s × 4.3 m/s)72 m/s²

 = 0.25 meter.

Therefore, the radius of the rotating wheel is 0.25 meter.

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Answer:

Conduction: Touching a stove and being burned. Ice cooling down your hand. .

Explanation:

Answer:

$20,900 decrease.

Explanation:

During the current year, Sue Shells, Inc.'s total liabilities decreased by $25,600 and stockholders' equity increased by $4,700. By what amount and in what direction did Sue's total assets change during the same time period? $20,900 decrease.

ANSWER:

A. Exothermic reactions release energy as heat, while endothermic reactions absorb energy as heat.

STEP-BY-STEP EXPLANATION:

An Endothermic Reaction is a chemical reaction that absorbs energy in the form of light or heat. In it, the energy or enthalpy of the reactants is less than that of the products. An Exothermic Reaction is a chemical reaction that gives off energy in the form of light or heat.

Answer:

Antarctica is a desert. It does not rain or snow a lot there. When it snows, the snow does not melt and builds up over many years to make large, thick sheets of ice, called ice sheets. Antarctica is made up of lots of ice in the form of glaciers, ice shelves and icebergs.

Answer: It will take 1/36 seconds.

Explanation:

As frequency (f) is equal to one oscillation per second.

Therefore, f = 1/T for one oscillation.

and wave speed (v) = λ / T

v = λ / T = λf

v = 6 x 60 = 360 m/s

Hence, to cover 10 meters time required will be

Speed = Distance/Time

Therefore, 360 = 10/ Time

So, Time = 10/ 360 = 1/36 seconds

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The third law of Newton's theory of motion states that there is a contrary response to every action. Anytime forceone body puts pressure on another, the second body puts equal and opposing pressure on the first.

It is quite acceptable to refer to a force of this level as a push and a pull. Force is not a property that an object 'has in it' or that it 'contains. One thing is subject to a force from another. There is no distinction between living and non-living things in the concept of a force.

Simply put, force is the push / pull motion. Both touch and non-forces are different types of force. Forces like nuclear effect, the force of gravity, frictional force, magnetism force, electric force, and spring force are a few examples.

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The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(c) The angular frequency of the oscillation is 7.885 rad/s.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

\(f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz\)

The angular frequency of the oscillation is calculated as follows;

\(\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s\)

The force constant of the spring is calculated as follows;

\(\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m\)

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Answer:

C. The sum remains the same.

Explanation:

The sum of the kinetic and potential energy remains the same as the all rolls from point A to E.

We know this based on the law of conservation of energy that is in play within the system.

The law of conservation of energy states that "energy is neither created nor destroyed within a system but transformed from one form to another".

Answer:

5m

Explanation:

(500 joules) / (100 newtons) =

5 meters

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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part a) If Q increases by 5 times its original value, the electrostatic force (F) will increase5 times as well.

part b) If r is halved (reduced by 2), the force will become four times stronger (since 2² = 4).

part c) If Q1 is positive and Q2 is negative, the charges will attract each other.

part d) If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same.

The electrostatic force is described as the force of attraction or repulsion between two charged particles.

With regards to Coulomb's Law, we have that the electrostatic force between two charges separated by a distance is :

Force = k * (Q1 * Q2) / r²

Where:

F_ =  electrostatic force

k = electrostatic constant

Q1 and Q2 =  magnitudes of the charges

r = distance

for case a:

If one of the charges, Q1 or Q2, increases by 5 times then the electrostatic force  will also increase by 5 times.

case b)

If the distance between the charges, r, is halved, the electrostatic force   will become four times stronger because (1/r²).

for case c.

if Q1 is positive and Q2 is negative, the charges will attract each other because of magnetic laws.

for case d.)

If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same as there is a resulting stronger gravitational or electromagnetic force.

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Answer: you have to divide and multiple fam

Explanation:

Answer:

Force = 60.08 N

Explanation:

Given that

Diameter d = 30 mm  

Holding pressure = 85 %  of Atmospherics pressure

Solution

As we know that  here 1 atm = 10⁵ N/m²

and pressure is known as force per unit area

pressure = \(\frac{F}{A}\)   ................1

put here value and we will get

F = \(0.85\times 10^5\times \frac{\pi}{4}\times 0.03^2\ N\)

solve it we get

Force = 60.08 N

There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

The density of a binary alloy can be calculated using the following equation:

ρ = w1ρ1 + w2ρ2

where,

ρ = density of the alloy

w1 and w2 = weight fractions of the two components (in this case, gold and silver)

ρ1 and ρ2 = densities of the pure components.

We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:

\(w_{Au}\) = 0.10

\(w_{Ag}\) = 0.90

We are also given the densities of pure gold and silver as:

ρ_Au = 19.32 g/\(cm^{3}\)

ρ_Ag = 10.49 g/\(cm^{3}\)

Now we can substitute these values into the density equation to find the density of the alloy:

ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag

ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))

ρ = 11.08 g/\(cm^{3}\)

Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.

To do this, we can use Avogadro's number and the atomic weights of gold and silver:

\(N_A\) = 6.022 × \(10^{23}\) atoms/mol

Aum = 196.97 g/mol

Agm = 107.87 g/mol

The number of gold atoms:

\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)

Substituting the values, we get:

\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol

\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)

Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

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A unit load of not less than 1/4 volt-amperes per square foot is included for storage spaces other than dwelling units.

The unit load can be described as the size of an assemblage into which a number of items are combined for ease of storage and handling, for example, a pallet load expresses a unit load that can be moved easily with a pallet jack, or a container load expresses a unit for shipping purposes.

A unit load can pack tightly into a warehouse rack, truck, or intermodal container, yet can be broken apart at a distribution point, generally a distribution center, or wholesaler, for sale to consumers or for use.

A unit load can be defined as the basic storage and transport unit arranged on modular support or in packaging to ensure efficient handling.

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The potential energy of the shot as it left the hand relative to the ground would be -524 J.

At the moment the shot putter releases the shot, the total energy of the system is:

E = KE + PE

where KE is the kinetic energy of the shot and PE is its potential energy relative to the ground. We can assume that the kinetic energy is entirely due to the motion of the shot in the horizontal direction, so we can write:

KE = (1/2)mv^2

where m is the mass of the shot, and v is its horizontal velocity. Substituting the known values, we get:

KE = (1/2)(5.00 kg)(15.0 m/s)^2 = 1125 J

At the maximum height of 14.5 m, the shot has zero kinetic energy, so all its energy is potential energy:

PE = mgh

where g is the acceleration due to gravity and h is the height above the ground. Substituting the known values, we get:

PE = (5.00 kg)(9.81 m/s^2)(14.5 m - 3.00 m) = 601 J

Therefore, the potential energy of the shot as it left the hand relative to the ground was:

PE = E - KE = 601 J - 1125 J = -524 J

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Heya!!

For calculate final velocity, lets applicate formula

                                                \(\boxed{V=V_o+a*t}\)

                                                 Δ   Being   Δ

                                            V = Final Velocity = ?

                                         Vo = Initial velocity = 4,3 m/s

                                          a = Aceleration = 3 m/s²

                                                 t = Time =5 s

⇒ Let's replace according the formula:

\(\boxed{V=4,3\ m/s +3\ m/s* 5\ s}\)

⇒ Resolving

\(\boxed{V=19,3\ m/s}\)

Result:

The velocity after 5 sec is 19,3 meters per second (m/s)

For calculate distance, lets applicate formula

                                              \(\boxed{x=V_o*t+\dfrac{a*t^{2}}{2}}}\)

                                                 Δ   Being   Δ

                                               x = Distance = ?

                                         Vo = Initial velocity = 4,3 m/s

                                          a = Aceleration = 3 m/s²

                                                 t = Time =5 s

⇒ Let's replace according the formula:

\(\boxed{x=4,3 * 5 +\dfrac{3*5^{2}}{2}}}\)

⇒ Resolving

\(\boxed{x = 59 \ m}\)

Result:

The distance is 59 meters.

Good Luck!!

A pitcher throws a baseball towards a batter at 30m/s. The batter swings his bat and hits the baseball, then there is a transfer of energy in this situation : c) Yes, because the force from the bat changes the motion of the ball.

Although baseball may appear hard and solid, it actually behaves much like a rubber ball. In the fraction of a second that ball collides with the swinging bat, ball compresses as the energy of motion goes into deforming the ball and transforms it into an elastic potential energy.

The collision of baseball with bat is elastic and the collision between baseball and glove is nearly inelastic.

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Answer:

Honestly, I don't know ¯\_(ツ)_/¯

Explanation:

The negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

Physical field that surrounds electrically charged particles and exerts force on all the other charged particles in the field is called an electric field.

Negatively charged sphere labeled Z will experience a force due to  electric field created by parallel plates. Since the vector is pointing right, we can assume that electric field is also pointing right.

Electric field lines are perpendicular to plates and are equally spaced. Therefore, electric field is uniform in magnitude and direction between the plates.

As the negatively charged sphere Z travels horizontally between plates, it will experience force in the direction opposite to electric field due to its negative charge. This force will cause sphere to slow down and  stop.

Since the electric field lines are equally spaced between the plates, electric field will be strongest at the edges of plates and weakest in the center. Therefore, negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

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Answer:

45.6 J

Explanation:

PE=mgh

m=0.155 kg

g=9.81 m/s^2

h=30.0 m

0.155(9.81)(30)=45.6

Answer:

1.4 m/s2

Explanation:

i took the test

The gravity at 380 km above the surface is, 86.42% weaker.

In order to calculate the distance from the center of the planet, the radius of the Earth will be added with the given distance above the Earth’s surface.

The relation of acceleration due to gravity is given by,

\(g= \dfrac{Gm}{R^2}\)

Here, G is the gravitational constant, m is the mass of the Earth, R is the distance from the center of the planet.

On plugging the values in the above relation.

\(g= \dfrac{6.67\times 10^{-11} \times 5.98 \times 10^{24}}{(6.38 \times 10^6 + 380000)^2}\)

The value of g at 380 km above earth surface is, 8.74.

The value of g at surface is 9.8.

The percentage difference = 8.74/9.8

= 0.86%

The gravity is, 86.42% weaker.

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Answer:

a

 \(y_1 = 0.004589 \ m\)

b

 \(y_2 =0.009179 \ m\)

Explanation:

From the question we are told that

   The wavelength of the red light is  \(\lambda _r = 633 \ nm = 633 *10^{-9} \ m\)

    The width of the slit is  \(d = 0.40 mm = 0.40 *10^{-3} \ m\)

    The distance of the screen from the point of diffraction is \(D = 2.9 \ m\)

Generally the width of the central bright fringe is mathematically represented as

       \(y_1 = \frac{\lambda * D}{d}\)

=>    \(y_1 = \frac{633 *10^{-9} * 2.90 }{0.40 *10^{-3}}\)

=>    \(y_1 = 0.004589 \ m\)

Generally the width of the first bright fringe on either side of the central one is mathematically represented as

     \(y_2 = 2 * y_1\)

=>   \(y_2 = 2 * 0.004589\)

=>   \(y_2 =0.009179 \ m\)

Answer:

9m/s^2

Explanation:

F=ma

a=F/m

a=63/7

a=9m/s^2

Answer:

b

Explanation: