A parachutist is falling with terminal velocity. Which of the following statement is not correct?

a) Gravitational potential energy is converted into kinetic energy of the air

b) G.P.E is converted into K.E of the parachutist

c) G.P.E is converted into thermal energy of the air

d) G.P.E is converted into thermal energy of the parachutist

The ISS do not fall to Earth because it is moving forward at exactly the right speed that if it is  combined with the rate it is falling, due to gravity, produces a curved path that matches the curvature of the Earth.

Yes the same concept can be used for the  Earth orbiting the Sun and the Moon orbiting the Earth.

What is the International Space Station (ISS)?

The International Space Station is described as the largest modular space station in low Earth orbit and a  project that involves five space agencies: NASA, Roscosmos, JAXA, ESA, and CSA.

Therefore we can conclude that the gravity pulling satellites, the moon and all planetary objects towards the center of Earth is balanced by the centrifugal force pushing it out.

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Matching the government activities to the different fiscal policies.

Contractionary Fiscal Policy:

budget indicates a surplus

government is spending less than what it earns

Expansionary Fiscal Policy:

government is spending more on infrastructure development

budget indicates a deficit

government is spending more than what it earns

When the government is spending less than what it earns, it has a budget surplus. This indicates that the government is collecting more revenue than it is spending. This is an example of a contractionary fiscal policy because it reduces the amount of money circulating in the economy, which can help control inflation.

When the government is spending more than what it earns, it has a budget deficit. This indicates that the government is spending more money than it is collecting in revenue. This is an example of an expansionary fiscal policy because it injects more money into the economy, which can stimulate economic growth.

When the government is spending more on infrastructure development, it is an example of an expansionary fiscal policy because it increases government spending and stimulates economic growth.

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Answer:

a) v₃ = 19.54 km, b)  70.2º north-west

Explanation:

This is a vector exercise, the best way to solve it is finding the components of each vector and doing the addition

vector 1 moves 26 km northeast

let's use trigonometry to find its components

         cos 45 = x₁ / V₁

         sin 45 = y₁ / V₁

         x₁ = v₁ cos 45

         y₁ = v₁ sin 45

         x₁ = 26 cos 45

         y₁ = 26 sin 45

         x₁ = 18.38 km

         y₁ = 18.38 km

Vector 2 moves 45 km north

        y₂ = 45 km

Unknown 3 vector

          x3 =?

          y3 =?

Vector Resulting 70 km north of the starting point

           R_y = 70 km

we make the sum on each axis

X axis

      Rₓ = x₁ + x₃

       x₃ = Rₓ -x₁

       x₃ = 0 - 18.38

       x₃ = -18.38 km

Y Axis

      R_y = y₁ + y₂ + y₃

       y₃ = R_y - y₁ -y₂

       y₃ = 70 -18.38 - 45

       y₃ = 6.62 km

the vector of the third leg of the journey is

         v₃ = (-18.38 i ^ +6.62 j^ ) km

let's use the Pythagorean theorem to find the length

         v₃ = √ (18.38² + 6.62²)

         v₃ = 19.54 km

to find the angle let's use trigonometry

           tan θ = y₃ / x₃

           θ = tan⁻¹ (y₃ / x₃)

           θ = tan⁻¹ (6.62 / (- 18.38))

           θ = -19.8º

with respect to the x axis, if we measure this angle from the positive side of the x axis it is

          θ’= 180 -19.8

          θ’= 160.19º

I mean the address is

          θ’’ = 90-19.8

          θ = 70.2º

70.2º north-west

Answer: 6.08 m/s

Explanation:

w=mg---> (9.8)(0.3)=2.94

Fc=mv^2/r ---> Fc=r(FT+w)/m

V=sqrt(r(FT+w)/m)

sqrt(2(2.6+2.94)/0.3= 6.08 m/s  

hope this helps :>

Answer:

a) F_{net } = 5 i ^ N ,   b) F_{net } = 5 N,  θ = 0

Explanation:

Force is a vector magnitude, one of the easiest methods to work with it is to use its Cartesian components and perform the sum on each axis in scalar form.

Therefore we will create a coordinate system and sum on each axis

X axis

          \(F_{net x}\) = F₁ + F₂

where they indicate the value of each one

F₁ = 15 N i ^

F₂ = -10 N i ^

where on the x-axis the direction to the right is positive

           F_{net x} = 15 - 10

           F_{net x} = 5 N

Y Axis

          F_{net y}  = F₃ + F₄

the values ​​of this force are given and the upward direction is taken as positive

   F₃ = 20 N j ^

   F₄ = -20 N j ^

we calculate

           F_{net y} = 20 -20

           F_{net x} = 0

we can give the result in two ways

a) F_{net } = 5 i ^ N

b) in the form of module and angle.

Let's use the Pythagorean theorem

        F_{net }² = F_{net x}² + F_{net y}²

        F_{net }² = 5² + 0²

        F_{net } = 5 N

we use trigonometry for the angles

        tan θ = F_{net yy} / F_{net y}

        θ = tan⁻¹ (0/5)

         θ = 0

Answer:

10 N to the left.

Explanation:

Since the forces are acting in opposite directions, you need to calculate the difference.

20 N - 10 N = 10 N

More force is being exerted to the left. Therefore, the net force is 10 N to the left.

The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).

We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).

Using n=1 and λ=2L/n, we get:

λ = 2L/1

λ = 2L

Using n=3 and λ=2L/n, we get:

λ = 2L/3

Using n=5 and λ=2L/n, we get:

λ = 2L/5

We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:

v/λ1 = f1

v/λ2 = f2

Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:

λ1 = 2L/1 = 2L

λ2 = 2L/3

Substituting these values into the above equations and solving for v, we get:

v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s

To find the fundamental frequency, we use the formula f=v/λ1:

f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz

Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

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The speed of the puck is 3.67 m/s.

To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.

Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:

= m1 * v^2 / R

where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.

For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:

T = m2 * g

where g is the acceleration due to gravity.

Combining these two equations, we can solve for the speed of the puck:

v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)

Substituting the given values, we get:

v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s

Therefore, the speed of the puck is 3.67 m/s.

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Answer:

x=v.t

The answer: Distance= Speed x Time

And also

Time = Distance/Speed

Speed= Distance/Time

Answer:

C, slightly less than 243 N

Explanation:

Road friction and air resistance aren't that much on a force. Try pushing something and see how much friction there is. Not that much.

a car moving at a speed shows that the force applied to the car is greater than the frictional force and air resistance

c. Slightly less than 243 N.

Answer:

The frequency of the system can be found using the formula:

f = 1 / (2π) * sqrt(k / m)

where f is the frequency, k is the spring constant, and m is the mass.

For the given system, with a mass of 10 kg and a spring constant of 20 N/m, the frequency is:

f = 1 / (2π) * sqrt(20 N/m / 10 kg) = 0.79 Hz

If the system is held vertically, the force of gravity will act on the mass, which will change the equilibrium position of the spring. The new equilibrium position will be lower than the original position, so the mass will be displaced by a greater distance before the spring exerts a restoring force.

To find the new frequency, we can use the formula:

f = 1 / (2π) * sqrt((k/m) - (g/L))

where g is the acceleration due to gravity and L is the length of the spring when it is at rest.

Assuming that the length of the spring remains constant, the new frequency can be calculated as:

f = 1 / (2π) * sqrt((20 N/m / 10 kg) - (9.81 m/s^2 / 0.1 m)) = 0.70 Hz

So the frequency of the system is slightly lower when it is held vertically due to the effect of gravity on the equilibrium position of the spring.

Let \(a\) be the acceleration of the masses. By Newton's second law, we have

• for the masses on the left,

\(1.3mg - T = 1.3ma\)

where \(T\) is the magnitude of tension in the pulley cord, and

• for the mass on the right,

\(T - mg = ma\)

Eliminate \(T\) to get

\((1.3mg - T) + (T - mg) = 1.3ma + ma\)

\(0.3mg = 2.3ma\)

\(\implies a = \dfrac{0.3}{2.3}g \approx 0.13g \approx 1.3 \dfrac{\rm m}{\mathrm s^2}\)

Starting from rest and accelerating uniformly, the right-hand mass moves up 75 cm = 0.75 m and attains an upward velocity \(v\) such that

\(v^2 = 2a(0.75\,\mathrm m) \\\\ \implies v \approx \sqrt{2\left(1.3\frac{\rm m}{\mathrm s^2}\right)(0.75\,\mathrm m)} \approx 1.4\dfrac{\rm m}{\rm s}\)

When the 0.5m mass is released, the new net force equations change to

• for the mass on the right,

\(mg - T' = ma'\)

where \(T'\) and \(a'\) are still tension and acceleration, but not having the same magnitude as before the mass was removed; and

• for the mass on the left,

\(T' - 0.8mg = 0.8ma'\)

Eliminate \(T'\).

\((mg - T') + (T' - 0.8mg) = ma' + 0.8ma'\)

\(0.2mg = 1.8 ma'\)

\(\implies a' = \dfrac{0.2}{1.8}g = \dfrac19 g \approx 1.1\dfrac{\rm m}{\mathrm s^2}\)

Now, the right-hand mass has an initial upward velocity of \(v\), but we're now treating down as the positive direction. As it returns to its starting position, its speed \(v'\) at that point is such that

\({v'}^2 - v^2 = 2a'(0.75\,\mathrm m) \\\\ \implies v' \approx \sqrt{\left(1.4\dfrac{\rm m}{\rm s}\right)^2 + 2\left(1.1\dfrac{\rm m}{\mathrm s^2}\right)(0.75\,\mathrm m)} \approx \boxed{1.9\dfrac{\rm m}{\rm s}}\)

An acidic solution is indicated by values between 0 and 7. A basic answer is indicated by values between 7 and 14. A solution is neutral when its pH value is exactly 7, meaning it is neither acidic nor basic.

By taking into account the reactivity of both the cation and the anion with water, we may determine whether a salt solution will be acidic, basic, or neutral. Water will not react with either species, leaving a neutral solution.

Since phenolphthalein's colour change is easier to see, it is typically preferred. It would be wise to utilize phenolphthalein, which is used and undergoes a sharp change at the equivalency point.

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Values between 0 and 7 suggest an acidic solution. Values between 7 and 14 indicate a basic response. When a solution's pH is exactly 7, it is considered neutral and is neither acidic nor basic.

We can tell whether a salt solution will be acidic, basic, or neutral by considering how the cation and anion react with water. Both species will not interact with water, leaving a neutral solution.

It is often used because phenolphthalein's color change is simpler to see. It is advisable to use phenolphthalein, which has a strong change at the equivalence point and is widely utilized. When a solution's pH is exactly 7, it is considered neutral and is neither acidic nor basic.

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Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\ \)

From the question we have

\(volume = \frac{100}{50} \\ \)

We have the final answer as

Hope this helps you

Answer:

Larger tubines generate more electricity.

Explanation:

Larger blades allow the turbine to capture more of the kinetic energy of the wind by moving more air through the rotors. However, larger blades require more space and higher wind speeds to operate. This distance is necessary to avoid interference between turbines, which decreases the power output.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Group of answer choices.

a) the capacity to learn from experience, solve problems, and to adapt to new situations.

b) how behavior changes as a result of experience.

c) the factors directing behavior toward a goal.

d) the ability to generate novel

Answer:

a) the capacity to understand the world, think rationally, and use resources effectively.

Explanation:

Psychology can be defined as the scientific study of both the consciousness and unconsciousness of the human mind such as feelings, emotions and thoughts, so as to understand how it functions and affect human behaviors in contextual terms.

This ultimately implies that, psychology focuses on studying behaviors and the mind that controls it.

In this scenario, Ashley who is a psychology major, stated that she's interested in the study of intelligence.

Intelligence can be defined as a measure of the ability of an individual to think, learn, proffer solutions to day-to-day life problems and effectively make informed decisions.

In other words, Ashley is interested in the capacity of humans to understand the world, think rationally, and use resources effectively to produce goods and services that meet the unending requirements, needs or wants of the people (consumers or end users) living around the world.

In fact, the piston is the disk that separates the two chambers of the barrel. It is the one that is being pushed by the hydraulic fluid. The piston and cylinder rod are joined.

Hydraulic cylinders are used as linear actuators in various marine and offshore technical applications to produce unidirectional force or stroke. The force produced by the displacement in hydraulic liquid under pressure is transferred to the piston inside the cylinder shell by the piston rods of these cylinders.

The force and liquid pressure is used to drive the hydraulic process, a type of mechanical operation. In hydraulics-based systems, pistons are moved mechanically by restricted, pumped liquid that frequently passes through hydraulic cylinders.

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In terms of molar solubility, the Ksp Expression for the specified solid is Ksp = 4x3.

Ksp, which stands for solubility product constant, is the equation for the equilibrium dissolution of a solid.

The solid ab2 has now dissolved according to the formula;

a(aq) = ab2(s) + 2b (aq)

The equilibrium constant is therefore;

Ksp equals (a)(b)/(ab2)

Now, because the solids aren't included in the equation because there isn't enough concentration, it may be condensed to;

Ksp = [a][b]².

Now, molarity is also known as molar solubility, and as such, we shall say that x = a.

Due to the fact that b = 2x, there is twice as much b as there is a, therefore we may write a and b in

Ksp = [x][2x]

² = 4x³

Answer:

Explanation:

E d g e n u i t y 2020

Answer:

The answer is B. A CD

Explanation:

The amplitude is given by the coefficient of the sine function, which in this case is 7.00 mm. The wavelength is 0.280 m. The frequency is f = 1/0.0360 s = 27.78 Hz. The wave's speed of propagation is 7.77 m/s. the direction of propagation is +x.

To determine the amplitude of the wave, we can observe the equation y(x, t) = (7.00 mm) sin[2π(t/0.0360s - x/0.280m)].

To determine the wavelength of the wave, we look at the coefficient of x in the argument of the sine function. Here, the coefficient is 0.280 m. Since wavelength (λ) is the distance covered by one complete cycle of the wave, we have λ = 0.280 m.

The frequency (f) of the wave can be obtained using the formula f = 1/T, where T represents the time period. The time period is the time taken for one complete cycle of the wave.

From the equation, we can see that the coefficient of t in the argument of the sine function is 0.0360 s. Therefore, the time period T = 0.0360 s, and the frequency is f = 1/0.0360 s = 27.78 Hz.

The speed of propagation (v) of a wave is given by the formula v = λf. Substituting the values we found, we have v = (0.280 m)(27.78 Hz) = 7.77 m/s.

The direction of propagation can be determined by observing the argument of the sine function.

Since the term (t/0.0360s - x/0.280m) appears in the sine function, we can see that as x increases, the argument decreases, which means the wave is moving in the positive x direction. Therefore, the direction of propagation is +x.

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Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

Given,

Power, P = 136.65 watts

Force, F = 16.22 N

Time, t = 4.97 seconds

The work done is calculated by the given formula,

Now, the formula of power is given by

Thus, the vertical distance is

Answer: 321 J

Explanation:

Given

Mass of the box \(m=3\ kg\)

Force applied is \(F=25\ N\)

Displacement of the box is \(s=15\ m\)

Velocity acquired by the box is \(v=6\ m/s\)

acceleration associated with it is \(a=\dfrac{F}{m}\)

\(\Rightarrow a=\dfrac{25}{3}\ m/s^2\)

Work done by force is \(W=F\cdot s\)

\(W=25\times 15\\W=375\ J\)

change in kinetic energy is \(\Delta K\)

\(\Rightarrow \Delta K=\dfrac{1}{2}m(v^2-0)\\\\\Rightarrow \Delta K=\dfrac{1}{2}\times 3\times 6^2\\\\\Rightarrow \Delta K=\dfrac{1}{2}\times 3\times 36\\\\\Rightarrow \Delta K=54\ J\)

According to work-energy theorem, work done by all the forces is equal to the change in the kinetic energy

\(\Rightarrow W+W_f=\Delta K\quad [W_f=\text{Work done by friction}]\\\\\Rightarrow 375+W_f=54\\\Rightarrow W_f=-321\ J\)

Therefore, the magnitude of work done by friction is \(321\ J\)

The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:

F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².

Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.

The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.

Therefore, we have:

m₁ = 50 kg

m₂ = 7 × 10²² kg

r = 380,000,000 m

G = 6.7 × 10⁻¹¹ N m²/kg²

Substituting these values into the formula, we get:

F = (G × m₁ × m₂) / r²

F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²

F = 1.15 N

Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

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Answer:

Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

I would appreciate it!

Answer:

\(R\approx12.43 \,\, \Omega\)

Explanation:

We can use Ohm's Law to find the resistance R of a wire that carries a current I under a given potential difference:

\(V=I\,\,R\\R = \frac{V}{I} \\R=\frac{87}{7} \\R\approx12.43 \,\, \Omega\)

Answer:

electron shell

Explanation:

the proton and nucleus are inside the electron shell so the arrow is point on the outer shell which is the electron shell.

Answer:524 Hz

Explanation:

Approximate frequency, heard in other car, when two car approaches each other, before they cross each other is 524 Hz.

Frequency of wave is the number of waves, which is passed thorough a particular point at a unit time.

For the two cars approaching each other the Doppler formula to find the frequency of second car is given as,

\(f_2=\dfrac{V_s+V_2}{V_s-V_1}f_1\)

Here, \(V_s\) is the speed of the sound.

Two cars approach each other from opposite directions.The velocity of car one is 54 km/h and the velocity of the car two is also 54 km/h.

Convert the unit of velocity of the car as,

\(\rm 54km/s=54\times\dfrac{5}{18}m/s\\\rm 54km/s=15m/s\)

As we know that the speed of the sound is 340 m/s and one of the cars emits a note of frequency 480 Hz.

Thus, putting the values in the above formula to find out the frequency heard in the other car before they cross each other as,

\(f_2=\dfrac{340+15}{340-15}480\\f_2=524.3\rm Hz\)

The approximate frequency heard in the other car before they cross each other is 524 Hz.

Learn more about the frequency here;

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