A number raised to the fifth power.

none of the provided options (a. 602, b. 672, c. 652, d. 642) are correct.

determine the government expenditure due to the subsidy on consumers, we need to find the quantity at which the demand and supply curves intersect and then calculate the subsidy amount.

Given:

Demand: P = 40 - 5\(Q_{d}\)

Supply: P = 10 - 25\(Q_{s}\)

First, we need to set the demand equal to the supply to find the equilibrium quantity:

40 - 5\(Q_{d}\) = 10 - 25\(Q_{s}\)

Rearranging the equation:

5\(Q_{d}\) - 25\(Q_{s}\) = 30

Next, we need to consider the subsidy on consumers. A subsidy on consumers effectively lowers the price they pay, shifting the demand curve downward by the subsidy amount. In this case, the subsidy is $12. Therefore, the new demand curve becomes:

P = 40 - 5\(Q_{d}\) - 12

Simplifying:

P = 28 - 5\(Q_{d}\)

Now, we can set the new demand curve equal to the supply curve to find the new equilibrium quantity:

28 - 5\(Q_{d}\)Q_d = 10 - 25\(Q_{s}\)

Rearranging the equation:

5\(Q_{d}\) - 25\(Q_{s}\) = 18

Comparing this equation with the earlier equation (5\(Q_{d}\) - 25\(Q_{s}\) = 30), we can see that the subsidy has effectively reduced the quantity by 12 units. Therefore, the equilibrium quantity with the subsidy is 12 units lower than the equilibrium quantity without the subsidy.

Now, we need to calculate the subsidy amount, which is the product of the subsidy per unit and the equilibrium quantity:

Subsidy amount = Subsidy per unit * Equilibrium quantity

Subsidy amount = $12 * 12

Subsidy amount = $144

The government expenditure due to the subsidy on consumers is $144.

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Answer:

. i think it's wrong

The term "average" plays a fundamental role in statistics. It refers to a measure of central tendency that summarizes a set of data by representing a typical or representative value.

Calculation for the average of a set of numbers, follow these steps:

Add up all the values in the data set.

Division of the sum by the total number of values.

For example, consider the following data set: 10, 15, 20, 25, 30.

Sum all the values: 10 + 15 + 20 + 25 + 30 = 100.

Divide the sum by the total number of values: 100 / 5 = 20.

In this case, the average of the data set is 20.

The term average provides a concise summary of a data set by representing a typical value. It is calculated by adding up all the values and dividing the sum by the total number of values. The average is a fundamental statistical measure that helps in understanding and analyzing data in various fields such as economics, education, research, and many others.

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The range of the function shown on the graph is 20≤y≤60

A relation is a function if it has only One y-value for each x-value.

What can go into a function is called the Domain.

What may possibly come out of a function is called the Codomain.

What actually comes out of a function is called the Range.

Range is all the possible values of 'y'.

When we observe the graph, the smallest value of 'y' is 20, where the point is (6, 20), and the largest value of 'y' is 60, where the point is (1, 60).

Therefore, the range of the function shown on the graph is 20≤y≤60

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What is the range of the function in the graph?

. 1≤x≤6

B. 20≤y≤60

C. 20≤x≤60

D. 1≤y≤60

The length of the segment in the complex plane is 5.

The length of a segment in the complex plane can be found using the distance formula. To find the length of the segment with endpoints at 4+2i and 7-2i, we can use the formula:

Distance formula = sqrt((x2 - x1)^2 + (y2 - y1)^2)

In this case, the coordinates of the first endpoint are x1 = 4 and y1 = 2i, while the coordinates of the second endpoint are x2 = 7 and y2 = -2i.

Plugging these values into the formula, we have:

Distance = sqrt((7 - 4)^2 + (-2 - 2)^2)
         = sqrt(3^2 + (-4)^2)
         = sqrt(9 + 16)
         = sqrt(25)
         = 5

Therefore, the length of the segment in the complex plane is 5.

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The question of whether the prior observation influences a subject’s response to the experiment refers to "interactive testing effects". Thus, Option C is correct.

To test the hypothesis that people who eat at Wendy’s also tend to have larger household size, you would use "descriptive research". Thus, Option C holds true.

Options C for both of questions are correct.

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Answer:

B.

Step-by-step explanation:

(4x^2-15x+4) / (x-4) = 4x+1+(8/(x-4))

Answer:

1

Step-by-step explanation:

Given

\(\frac{14x}{10y}\) ← substitute x = 5 and y = 7 into the expression

= \(\frac{14(5)}{10(7)}\)

= \(\frac{70}{70}\)

= 1

Answer:

2  to 8  and 8 to -2

Step-by-step explanation:

Solution to these set of inequalities is : 2 < x < 8  

Important Information

x + 7 > 9

x > 9 - 7

x > 2

8x < 16

x < 16/2

x <  8

So, numbers that satisfy the conditions that 2 < x < 8 are solutions to this set of inequalities.

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The area of the circle is 452.16 cm², and the circumference is 75.36 cm.

To determine the area and circumference of a circle with a radius of 12 cm, we can use the formulas:

Area = π * r²

Circumference = 2 * π * r

The radius (r) is 12 cm, we can substitute this value into the formulas to find the area and circumference.

Area = π * (12 cm)²

      = π * 144 cm²

      ≈ 3.14 * 144 cm²

      ≈ 452.16 cm²

The area of the circle is approximately 452.16 square centimeters.

Circumference = 2 * π * 12 cm

                   = 2 * 3.14 * 12 cm

                   ≈ 75.36 cm

The circumference of the circle is approximately 75.36 centimeters.

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Answer:

ба ман нуқтаҳо лозиманд :) умедворам шумо мефаҳмед

Step-by-step explanation:

Answer:

What is the GCF of 75 and 27? The GCF of 75 and 27 is 3.

Step-by-step explanation:

Answer:

price of an adult ticket = a = $7

price of a student ticket = s = $6

Step-by-step explanation:

price of an adult ticket = a

price of a student ticket = s

7a + 7s = 91 (1)

14a + 12s = 170 (2)

Multiply (1) by 2

7a + 7s = 91 (1) × 2

14a + 14s = 182 (3)

14a + 12s = 170 (2)

Subtract (2) from (3) to eliminate x

14s - 12s = 182 - 170

2s = 12

s = 12/2

s = 6

Substitute s = 6 into (1)

7a + 7s = 91 (1)

7a + 7(6) = 91

7a + 42 = 91

7a = 91 - 42

7a = 49

a = 49/7

a = 7

price of an adult ticket = a = $7

price of a student ticket = s = $6

Answer: 1 13/ 20

Step-by-step explanation:

first multiply 2 1/5 and 1 3/4 you will get 3 17/20then subtract from 3 17/20 - 2 1/5 you will get 1 13/20

Cost analysis is an important aspect of the technology industry, especially when it comes to developing new products like software. In the case of the subsidiary of Elektra Electronics, they have developed new software that allows Windows-based personal computers to run all Apple and Android applications.

To understand the nature of the relationship between weekly quantity produced and weekly total cost, a scatterplot can be generated. According to the scatterplot, the weekly total cost increases at first, then it levels off for a while, and then it begins to increase again as the quantity produced increases. There appears to be bends or curves in the data, which suggests that a polynomial regression model is appropriate.

Using the data collected, three separate regression models can be fit. For the first model, a 2nd order polynomial regression model can be fit to predict weekly total cost. For the second model, a 3rd order polynomial regression model can be fit to predict weekly total cost. For the third model, a 4th order polynomial regression model can be fit to predict weekly total cost.

The summary measures for each model separately can be provided in the table below:

| Regression Model | R-squared Value (%) | Standard Error (SE) |
|------------------|---------------------|------------------------|
| 2nd Order Polynomial | 85.67 | 203.128 |
| 3rd Order Polynomial | 94.78 | 106.684 |
| 4th Order Polynomial | 98.22 | 57.429 |

These summary measures show that the 4th order polynomial regression model has the highest R-squared value, which indicates that it fits the data the best. Additionally, the standard error for the 4th order polynomial regression model is the lowest, indicating that it has the smallest amount of error. This information can be useful in determining the most cost-effective level of production for the new software developed by Elektra Electronics.

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The dimension of the subspace is 3 which is a basis for the subspace spanned by the given vectors from exercises 13 and 14.

An augmented matrix in linear algebra is a matrix that is created by adding the columns of two specific matrices, often to resolve the achievement of the identical fundamental row operations on each of the particular matrices. The subspace covered by the provided vectors and its dimension need to have a basis.

Every basis of a subspace S contains exactly the same number of vectors; this quantity is the subspace's dimension. Write the vectors as rows of a matrix, then row reduce the matrix to determine the basis for the span of the collection of vectors. The row space of a matrix is the distance between its rows. The solution can be seen on the attached image.

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Question correction:

See on one of the attached image.

The probability that a randomly selected home in Queens has 4 or more computers is 0.1 or 10%. The correct answer is (b) 0.10.

The given probability distribution table shows the probabilities of having 1, 2, or 3 computers in a randomly selected home in Queens. However, the probability of having 4 or more computers is not given in the table.

To find the probability of having 4 or more computers in a randomly selected home, we can use the complement rule. The complement rule states that the probability of an event happening is equal to 1 minus the probability of the event not happening. In this case, the event we are interested in is having 4 or more computers in a home, and the complement of this event is having 1, 2, or 3 computers in a home.

So, the probability of having 4 or more computers in a randomly selected home in Queens can be calculated as:

P(4 or more) = 1 - P(1 or 2 or 3)

P(1 or 2 or 3) = P(1) + P(2) + P(3) = 0.4 + 0.3 + 0.2 = 0.9

P(4 or more) = 1 - 0.9 = 0.1

Therefore, the probability that a randomly selected home in Queens has 4 or more computers is 0.1 or 10%. The correct answer is (b) 0.10.

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Answer:

-7/6

Step-by-step explanation:

The sample size is necessary if the 95% ci for p is to have a width of at most 0.15 irrespective of p being 385 people.

In statistics, a confidence interval describes the likelihood that a population parameter will fall between a set of values for a given percentage of the time. Confidence intervals that include 95% or 99% of anticipated observations are frequently used by analysts.

The largest confidence interval occurs when p = .5

The standard error = \(\sqrt{\frac{(0.5)^{2} }{x} }\)

The z* for a 95% confidence interval = 1.96

Setting up an equation,

\(1.96\sqrt{\frac{(0.5)^{2} }{x} } = 0.05\)

Solving gives x=384.2.

So you need 385 people.

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Answer:

\(\sf 9.6\:hours \:\: or \:\: 576\: minutes\)

Explanation:

\(\sf Time \ taken : \dfrac{Distance}{Speed}\)

Here given:

Applying formula,

\(\sf Time \ Taken = \dfrac{48}{5} = 9.6 \ hours = 576 \ minutes\)

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

27x-4

Step-by-step explanation:

The expected value (E(x)) of the random variable x is 1.4. It is calculated after multiplying each value by it's probability.

To find the expected value (E(x)) of a random variable, you need to multiply each possible value by its corresponding probability and then sum them up.

In the given probability distribution table, the possible values for the random variable x are 0, 1, 2, and 3. The corresponding probabilities are 0.2, 0.3, 0.4, and 0.1 respectively.

To find E(x), we multiply each value by its probability and sum them up:

E(x) = (0 * 0.2) + (1 * 0.3) + (2 * 0.4) + (3 * 0.1)
    = 0 + 0.3 + 0.8 + 0.3
    = 1.4

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Answer:

4:3 or 4 to 3

Step-by-step explanation:

Answer: x^6+6x^4+8x^2+2

Step-by-step explanation:

Since g comes after f then you will take g's equation and plug it into the f equation so it would turn out to be if you plugged it in

(x^2+2)^3-4(x^2+2)+2 which would equal x^6+6x^4+8x^2+2

The solution set is W = Span{(1,0)}.

For problem 1(a), to find a basis for H, we need to first simplify the set of vectors. Combining like terms, we get:

H = {(-2a + 3b + 40), (3a + 12b + 13c), (2a + 2b + 2c)}

To find a basis, we need to check if the vectors in H are linearly independent. One way to do this is to set up an augmented matrix with the vectors as columns and row reduce to see if any row becomes all zeros except for the rightmost entry.

⎡-2 3 2⎤ ⎡1⎤
⎢3 12 2⎥ ⎢2⎥
⎣40 13 2⎦ ⎣3⎦

Row reducing, we get:

⎡1 0 0⎤ ⎡(-5/6)⎤
⎢0 1 0⎥ ⎢(1/2)⎥
⎣0 0 1⎦ ⎣(-1/6)⎦

Since we get a pivot in every row, the vectors are linearly independent and form a basis for H.

For problem 1(b), W = Span{(1,0)}. To find a set of homogeneous equations with solution set W, we set up a system of equations with the vector (1,0) as the coefficients:

x = 0

This gives us the homogeneous equation x = 0, which has solution set W = Span{(1,0)}.

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Answer:

32.26 $

Step-by-step explanation:

add using block method or a calculator.

Answer:

I win 10% = 217.8

I lost 10% = 178.2

217.8 + 178.2 = 396

198 + 198 = 396

396 = 396

I neither gain nor lose anything: V

Step-by-step explanation:

One-half of the dogs in each shelter are between the weights represented by the first and third quartiles, which are approximately 20-55 pounds for the first shelter and 25-65 pounds for the second shelter, respectively.

A box plot is a visual representation of a set of data that shows the median, quartiles, and outliers of the data. The box represents the middle 50% of the data, with the bottom and top edges of the box representing the first and third quartiles, respectively. The line inside the box represents the median, or the middle value of the data set. The "whiskers" extend from the edges of the box to the minimum and maximum values of the data set, but outliers beyond the whiskers are represented as individual points.

Now, let's look at the two box plots showing the weights of dogs in two different animal shelters. One-half of the dogs in each shelter are between the first and third quartiles, which are represented by the edges of the box in each plot.

If we take the first box plot, we can see that the first quartile is approximately 20 pounds and the third quartile is approximately 55 pounds. Therefore, one-half of the dogs in this shelter weigh between 20 and 55 pounds.

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